hello,Can you please help me with question # 25 in the picture?Thank you

Hello,Can You Please Help Me With Question # 25 In The Picture?Thank You

Answers

Answer 1

To find the sum of an arithmetic sequence up to the nth term, we use the sum formula, which is

[tex]S_n=n(\frac{a_1+a_n}{2})[/tex]

where a1 represents the first term, and an the nth term.

The general term of our sequence is

[tex]a_n=3n+2[/tex]

We want to sum up to the 16th term. Evaluanting n = 16 and n = 1 on this expression, we get the terms to plug in our formula

[tex]\begin{gathered} a_1=3(1)+2=3+2=5 \\ a_{16}=3(16)+2=48+2=50 \end{gathered}[/tex]

Then, the sum is equal to

[tex]\sum_{i\mathop{=}1}^{16}(3i+2)=16(\frac{50+5}{2})=8\cdot55=440[/tex]

The result of this sum is 440.


Related Questions

points E,D and H are the midpoints of the sides of TUV, UV=100,TV=126,and HD=100, find HE.

Answers

Since the triangles are similar there exists correspondance in the angles, so in order to solve this you just have to clear the function:

[tex]\begin{gathered} \frac{VD}{VU}=\frac{HD}{TU} \\ \end{gathered}[/tex]

Since D is the midpoint of VU, VD=50

[tex]\begin{gathered} \frac{50}{100}=\frac{100}{TU} \\ 50\times TU=100\times100 \\ TU=200 \end{gathered}[/tex]

then

[tex]\begin{gathered} \frac{HE}{UV}=\frac{HD}{TU} \\ \frac{HE}{100}=\frac{100}{200} \\ HE=\frac{100}{200}\times100 \\ HE=50 \end{gathered}[/tex]

The population of the state of Colorado was about 5,846,000 people in 2020.
Which number best approximates the population as a single digit times a
power of 10?
OA. 6x 10-6
OB. 6 x 106
C. 5 × 105
D. 5 x 106

Answers

The answer is B. 6 x 10^6

Answer:  [tex]6 \times 10^6[/tex] which is choice B

==========================================

Method 1

5,846,000 rounds to 6,000,000 aka "6 million".

This converts to the scientific notation [tex]6 \times 10^6[/tex]

The first 6 is from "6 million", while the 6 as the exponent tells us to move the decimal point that many places to the right to go from 6.0 to 6,000,000

---------------

Method 2

Place a decimal point between the first two digits of 5,846,000 and erase the zeros at the end.

So we get 5.846

We must move the decimal point 6 spaces to the right to go from 5.846 back to 5,846,000 again

Therefore, [tex]5,846,000 = 5.846 \times 10^6[/tex]

Then the 5.846 rounds to 6.0 or simply 6 when rounding to the nearest whole number. This leads to [tex]6 \times 10^6[/tex]

A dilation with a scale factor of 4 is applied to the 3 line segment show on the resulting image are P'Q', A'B', And M'N'. Drag and drop the measures to correctly match the lengths of The images

Answers

Given:

Scale factor = 4 (Dilation)

PQ = 2 cm

AB = 1.5 cm

MN = 3 cm

Find-:

[tex]P^{\prime}Q^{\prime},A^{\prime}B^{\prime}\text{ and }M^{\prime}N^{\prime}[/tex]

Explanation-:

Scale factor = 4

So,

[tex]\begin{gathered} P^{\prime}Q^{\prime}=4PQ \\ \\ A^{\prime}B^{\prime}=4AB \\ \\ M^{\prime}N^{\prime}=4MN \end{gathered}[/tex]

So the value is:

[tex]\begin{gathered} P^{\prime}Q^{\prime}=4PQ \\ \\ P^{\prime}Q^{\prime}=4\times2 \\ \\ P^{\prime}Q^{\prime}=8\text{ cm} \end{gathered}[/tex][tex]\begin{gathered} A^{\prime}B^{\prime}=4AB \\ \\ A^{\prime}B^{\prime}=4\times1.5 \\ \\ A^{\prime}B^{\prime}=6\text{ cm} \end{gathered}[/tex][tex]\begin{gathered} M^{\prime}N^{\prime}=4MN \\ \\ M^{\prime}N^{\prime}=4\times3 \\ \\ M^{\prime}N^{\prime}=12\text{ cm} \end{gathered}[/tex]

Which relation is a function? choose all the correct answers.[1] (1, 0), (3, 0), (1, 1), (3, 1) (1, 3) [2] (1, 1), (2, 2), (3, 3), (4, 4), (5, 8)[3] (2, 7), (6, 5), (4, 4), (3, 3), (2, 1)[4] (9, −3), (9, 3), (4, −2), (4, 2), (0, 0)

Answers

A relation is a function if an input value has only one output value. This means that a value of x must have only one value of y. Looking at the options,

1) for x = 1, there are different values of y. They include y = 0, 1, 3

for x = 3, y = 0, 1

This means that it is not a function

2) No value of x has more than one value of y. Thus, no input has more than one output. This means that it is a function

3) for x = 2, there are different values of y. They include y = 7, 1

This means that it is not a function

4) for x = 9, there are different values of y. They include y = - 3, 3

for x = 2, there are different values of y. They include y = - 2, 2

This means that it is not a function

Thus, the correct option is

[2] (1, 1), (2, 2), (3, 3), (4, 4), (5, 8)

Which inequality is represented by the graph?

Answers

Answer:

it's option c ............

List all real values of x such that f(x) = 0, if there are no such real x, type DNE in the answer blank. If there is more than one real x, give a comma separated list (i.e: 1, 2) X =

Answers

Answer:[tex]x=\frac{34}{7}[/tex]

Explanations:

Given the function defined as:

[tex]\begin{gathered} f(x)=-7+\frac{-8}{x-6} \\ \end{gathered}[/tex]

The function can further be expressed as:

[tex]f(x)=-7-\frac{8}{x-6}[/tex]

Find the LCM of the function;

[tex]\begin{gathered} f(x)=\frac{-7(x-6)-8}{x-6} \\ f(x)=\frac{-7x+42-8}{x-6} \\ f(x)=\frac{-7x+34}{x-6} \\ \end{gathered}[/tex]

If f(x) = 0, then the value of x is calculated as:

[tex]\begin{gathered} \frac{-7x+34}{x-6}=0 \\ -7x+34=0 \\ -7x=0-34 \\ -7x=-34 \end{gathered}[/tex]

Divide both sides of the equation by -7:

[tex]\begin{gathered} \frac{\cancel{-7}x}{\cancel{-7}}=\frac{\cancel{-}34}{\cancel{\square}7} \\ x=\frac{34}{7} \end{gathered}[/tex]

Therefore the value of x if f(x) = 0 is 34/7

Mai works as a tutor for $12 an hour and as a waitress for $7 an hour. This month,she worked a combined total of 85 hours at her two jobs. Let t be the number of hours Mai worked as a tutor this month. Write an expression for the combined total dollar amount she earned this month.total earned (in dollars) = ?

Answers

Solution:

Let t be the number of hours Mai works as a tutor.

Given that She earns $12 a hour as a tutor, this implies that for t number of hours, she will earn

[tex]\begin{gathered} \$12\times t \\ =\$\text{ 12t} \end{gathered}[/tex]

For the month, she worked a combined total of 85 hours. This implies that

[tex]\begin{gathered} 85=t\text{ + (number of hours worked as a waitress) } \\ \Rightarrow nu\text{mber of hours worked as a waitress = (85-t) hours} \end{gathered}[/tex]

Her total eranings for the month is expressed as

[tex]\text{Total earnings = 12(number of hours worked as a tutor)+7(number of hours worked as a waitress)}[/tex]

Recall that she earnes $7 an hour while working as a waitress.

Thus, we have her combined total amount in dollars expressed as

[tex]\text{Total earned (in dollars)=12t+7(85-t)}[/tex]

Hence, the expression is

[tex]\begin{gathered} \text{12t+7(85-t) } \\ \text{open parentheses} \\ \Rightarrow12t+595-7t \\ \text{collect like terms.} \\ \text{thus, the expression is simplied to be} \\ 5t+595 \end{gathered}[/tex]

if the population of a city is 158,000 and isdecreasing by 8% every year, what will thepopulation be in 5 years?

Answers

Solution:

From the question, we use the population decay formula expressed as

[tex]\begin{gathered} P(t)=P(1-r)^t \\ where \\ P\Rightarrow initial\text{ population} \\ r\Rightarrow decay\text{ rate} \\ t\Rightarrow time \\ P(t)\Rightarrow population\text{ at time t} \end{gathered}[/tex]

Given that:

[tex]\begin{gathered} P=158000 \\ r=8\%=\frac{8}{100}=0.08 \\ t=5 \end{gathered}[/tex]

By substituting these values into the population decay formula, we have

[tex]\begin{gathered} P(t)=158000(1-0.08)^5 \\ =104134.88066 \end{gathered}[/tex]

Hence, the population in 5 years will be

[tex]104134.88066[/tex]

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

The correct representations of the inequality -3(2x-5)<5(2-x) are -6x + 15 < 10 - 5x  and  "an open circle is at 5 and a bold line that starts at 5 and is pointing to the right" , the correct option is (c) and (d) .

In the question ;

it is given that

the inequality -3(2x-5)<5(2-x)

on solving this inequality further , we get

-3(2x-5)<5(2-x)

-6x+15<10-5x

which is option (c) .

Further solving

Subtracting 15 from both the sides of the inequality  , we get

-6x + 15 -15 < 10 -5x -15

-6x < -5 -5x

-6x +5x < -5

-x < -5

multiplying both sides by (-1) ,

we get

x > 5 .

x> 5 on number line means  an open circle is at 5 and a bold line starts at 5 and is pointing to the right .

Therefore , the correct representations of the inequality -3(2x-5)<5(2-x) are -6x + 15 < 10 - 5x  and  "an open circle is at 5 and a bold line that starts at 5 and is pointing to the right" , the correct option is (c) and (d) .

The given question is incomplete , the complete question is

Which are correct representations of the inequality -3(2x - 5) < 5(2 - x)? Select two options.

(a) x < 5

(b) –6x – 5 < 10 – x

(c) –6x + 15 < 10 – 5x

(d) A number line from negative 3 to 7 in increments of 1 , An open circle is at 5 and a bold line that starts at 5 and is pointing to the right.

(e) A number line from negative 7 to 3 in increments of 1,  An open circle is at negative 5 and a bold line that starts at negative 5 and is pointing to the left.

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PLS HELP!!! Ill give 20 points!!!

Answers

Answer:

Step-by-step explanation:

22.57 cm inches are the net weight of the slope

suppose that z varies jointly with x and y. When x=2, y=2, z=7 write the equation that models the relationship

Answers

[tex]\begin{gathered} z=\text{ x + y + b} \\ 7\text{ = 2+2+b} \\ 7\text{ = 4+b} \\ 7-4=b \\ b=\text{ 3} \\ z=\text{ x + y +3} \end{gathered}[/tex]

what is the value of the q that makes the equation true? 3(q+4)-10q=2q+3

Answers

3(q+4)-10q = 2q + 3

Distribute:
3q + 12 - 10q = 2q + 3

Combine like terms:
-7q + 12 = 2q + 3

Inverse operation (subtract 3 on both sides):

-7q + 9 = 2q

Inverse operation; Add -7q on both sides:
9 = 9q

Solve: Divide 9 on both sides to single out the variable
[ q=1 ]



In boot camp, a cadet must use a rope swing to cross an obstacle withoutfalling into the water hazard below. Unfortunately, they miss the platform onthe other side and swing back to where they started. If it takes the cadet 3.5seconds to swing from one side of the obstacle to the other and back, howlong is the rope swing? Use the formula:

Answers

Answer:

Choice C: 3.0 m

Explanation:

We are basically asked to solve for L using

how do you find the x intercept for -(x-3)^2+12

Answers

[tex]y=mx+b[/tex]

This is the equation for the line.

Here the given equation is,

[tex]-(x-3)^2+12[/tex]

We can calculate x intercept by substituting 0 for y, as there is no value of y,

the x intercept is none here. The graph is as follows,

How much should be invested now at an interest rate of 7% per year, compounded continuously, to have 2000 dollars in three years? Do not round intermediate computations, and round your answer to the nearest cent

Answers

Answer:

The amount that should be invested is $1621.16

Explanation:

The formula for continuous compound interest is:

[tex]A=Pe^{rt}[/tex]

Where:

A is the amount of money after t years

P is the invested amount (what we want to find, in this case)

r is the rate of compounding in decimal

t i the amount of time compounding, in years

Then, in this case:

A = $2000

r = 0.07 (to convert percentage to decimal, we divide by 100: 7% / 100 = 0.07)

t = 3 years

Then:

[tex]2000=Pe^{0.07\cdot3}[/tex][tex]2000=Pe^{0.21}[/tex]

[tex]P=\frac{2000}{e^{0.21}}\approx1621.16849[/tex]

To the nearest cent, P = $1621.16

What is the equation for this? I don't understand which piece of information is irrelevant.

Answers

It is given that she produce print of her photos at a cost of 4 dollar per print and a setup cost of 45 dollar per run.

Let the number of photos produced be x.

Then the equation formed is

[tex]C(x)=4x+45[/tex]

The sellling cost given is the unnecessary data given in the question.

The total cost is determined by only the setup cost and cost produce per prints.

The graph formed for the total cost and number of photos produced is

X-axis represent the number of photos produced and Y-axis represent the total cost.

match the function rule with the graph of the function (number 24)

Answers

It is given that the function is:

[tex]y=\frac{3}{4}\times4^x[/tex]

Therefore y=0 then the value of x will be:

[tex]\begin{gathered} 0=4^x \\ x=-\infty \end{gathered}[/tex]

Now at x=0, y will be:

[tex]y=\frac{3}{4}[/tex]

at x=1, y will be:

[tex]y=\frac{3}{4}\times4=3[/tex]

These 3 points that is (-inf,0),(0,3/4),(1,3) are on graph D.

Hence option D is coreect.

The table shows the numbers of ships that visited a port in the past 5 years. Identify a polynomial function for thenumber of ships in thousands that visited the port in a given year.

Answers

The function is f(x) = 1.3x^2 + 0.1X

Rewrite 20 - 4x³ using a common factor.
O 4x(5-x²)
O4(5 - 4x³)
02x(10-2x²)
02(10-2x³)

Answers

Answer:

[tex]20 - 4 {x}^{3} = 4(5 - {x}^{3} )[/tex]

Rewrite 4x + 16 using a common factor.

Answer 4(x + 4)

Which of the following is equal to the rational expression below when x+112x² – 121x +11A. +11B.X+ 11c. -11XD. X-11

Answers

SOLUTION

From the question we have

[tex]\frac{x^2-121}{x+11}[/tex]

from difference of two squares, we have

[tex]\begin{gathered} \frac{(x-11)(x+11)}{x+11} \\ x+11\text{ above cancels the one below, we have } \\ x-11 \end{gathered}[/tex]

Hence the answer is option D

help meeeeeeeeee pleaseee !!!!!

Answers

The values of the functions are determined as:

a. (f + g)(x) = 3x² + 2x

b. (f - g)(x) = -3x² + 2x

c. (f * g)(x) =  6x³

d. (f/g)(x) = 2/3x

How to Determine the Value of a Given Function?

To evaluate a given function, substitute the equation for each of the functions given in the expression that needs to be evaluated.

Thus, we are given the following functions as shown above:

f(x) = 2x

g(x) = 3x²

a. To find the value of the function (f + g)(x), add the equations for the functions f(x) and g(x) together:

(f + g)(x) = 2x + 3x²

(f + g)(x) = 3x² + 2x

b. To find the value of the function (f - g)(x), find the difference of the equations of the functions f(x) and g(x):

(f - g)(x) = 2x - 3x²

(f - g)(x) = -3x² + 2x

c. To find the value of the function (f * g)(x), multiply the equations of the functions f(x) and g(x) together:

(f * g)(x) =  2x * 3x²

(f * g)(x) =  6x³

d. To find the value of the function (f/g)(x), find the quotient of the equations of the functions f(x) and g(x):

(f/g)(x) = 2x/3x²

(f/g)(x) = 2/3x.

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when doing right triangle trigonometry how do you determine which sine you use like sin, cos etc?

Answers

Let's draw a right triangle to guide us:

Every right triangle will have one hypotenuse side and two leg sides. The hypotenuse is always the bigger one and it is always opposite to the right angle, so in this triangle the hypotenuse is a (the letter can change from exercise to exercise, but it is always the opposite to the rignt angle).

The legs can be classified as adjancent or opposite legs, but this is with respect to the angle we are using.

So, if we are using angle C, the opposite leg is the leg that is opposite to angle C, that is, c.

Thus, the adjancent leg is the leg that is touching the angle C, that is, b.

So, with respect to angle C, we have:

Hypotenuse - a

Opposite leg - c

Adjacent leg - b

The sine is the ratio between the opposite leg and the hypotenuse, always.

The cosine is the ratio between the adjacent leg and the hypotenuse, always.

The tangent is the ratio between the opposite leg and the adjacent leg, always.

For, for angle C, we have:

[tex]\begin{gathered} \sin C=\frac{c}{a} \\ \cos C=\frac{b}{a} \\ \tan C=\frac{c}{b} \end{gathered}[/tex]

For angle B, we do the same, however now, the legs are switched, because the leg that is opposite to angle B is b and the leg that is adjance to angle B is c, so, for angle B:

Hypotenuse - a

Opposite leg - b

Adjacent leg - c

And we follow the same for sine, cosine and tangent but now for angle B and with the legs switched:

[tex]\begin{gathered} \sin B=\frac{b}{a} \\ \cos B=\frac{c}{a} \\ \tan B=\frac{b}{c} \end{gathered}[/tex]

Questions regaring these ratios normally will present 2 values and ask for a third value. One of the values will be an angle, the other will be side (usually). So, we need to identify which angle are we working with and which sides are the hypotenuse, the opposite leg and adjancent leg with respect to the angle we will work with. Then we identify which of the side we will use and pick the ratio thet relates the sides we will use.

Solve the equation by working backward through the number trick.

Answers

Answer:

x = 3

Explanations:

The given equation is:

[tex]\frac{4(x+3)-6}{2}=\text{ 9}[/tex]

Step 1: Cross multiply

4 ( x + 3) - 6 = 9(2)

Step 2: Remove the brackets by expanding the equation

4x + 12 - 6 = 18

4x + 6 = 18

Step 3: Collect like terms

4x = 18 - 6

4x = 12

Step 4: Divide both sides by 4

4x / 4 = 12 / 4

x = 3

A business could not collect $5,000 that it was owed. The total owed to the business was $100,000. What fraction of the total was not collected? (Express As Fraction)

Answers

Total owed to the business = $100,000

amount that could not be collected = $5000

Fraction of total not collected

[tex]\text{fraction not collected=}\frac{5000}{100000}=\frac{5}{100}=\frac{1}{20}[/tex]

If the revenue function for a certain item is R(x)=20x−0.25x2, what is the marginal revenue for the 8th item? Do not include the dollar sign in your answer.

Answers

The marginal revenue of the 8th item from the revenue function is 16

How to determine the marginal revenue?

From the question, the revenue function is given as

R(x) = 20x - 0.25x^2

To calculate the marginal revenue, we start by differentiating the revenue function

This is calculated as follows

R(x) = 20x - 0.25x^2

Differentiate the function

R'(x) = 20 - 0.5x

The above represents the marginal revenue function

So, we have

M(x) = 20 - 0.5x

For the 8th item, we have

M(8) = 20 - 0.5 x 8

Evaluate

M(8) = 20 - 4

Evaluate

M(8) = 16

Hence, the marginal revenue is 16

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How many 7 digit phone numbers can be created if the first digit cannot be a zero, and the lastnumber must be an odd number?

Answers

Given:

Number of digits = 7

The first digit cannot be zero

Last number = odd number

The possible numbers between other than zero is 9

and there are 5 odd numbers.

Hence, the number of possible combinations is:

[tex]\begin{gathered} =\text{ 9 }\times\text{ 10 }\times\text{ 10 }\times\text{ 10 }\times\text{ 10 }\times\text{ 10 }\times\text{ 5} \\ =\text{ 4500000} \end{gathered}[/tex]

Answer: Option A

Identify the rate, base, and portion.
21% of what number is 57?

Question content area bottom

Which values are given? Select the correct choice below and fill in any answer boxes in your choice. (Type an integer or a decimal. Do not perform the calculation.)
A.The base is (enter your response here) and the portion is (enter your response here). The rate is not given.

B.The rate is (enter your response here % ) and the portion is (enter your response here). The base is not given.

C. The rate is (enter your response here %) and the base is (enter your response here).

Answers

Given:

21​% of what number is 57

Let the number = x

So, 21% of x = 57

so, the rate = 21%

and the base = x

and the portion = 57

So, the base is not given

so, the answer will be option B

B) the rate is 21% and the portion is 57. the base is not given.

Solve for y: 5 left parenthesis 3 y plus 4 right parenthesis equals 6 open parentheses 2 y minus 2 over 3 close parentheses The solution is Y = _______

Answers

ANSWER:

-8

STEP-BY-STEP EXPLANATION:

We have the following equation:

[tex]5\cdot\mleft(3y+4\mright)=6\cdot\mleft(2y-\frac{2}{3}\mright)[/tex]

Solving for y:

[tex]\begin{gathered} 15y+20=12y-4 \\ 15y-12y=-4-20 \\ 3y=-24 \\ y=-\frac{24}{3} \\ y=-8 \end{gathered}[/tex]

The solution of y is equal to -8

Sally wishes to purchase an IPhone 12. the price of the item is $849. the amount of money she save's per month is $70. The amount of money Sally already have's is $17. , , , : write your function and define your variables. your function should be in a slope-intercept form. what is ()input = number of months. and ()output = amount of money you need :: complete your input/output tabel. select 6 values for your input (). They can be consistent (, , , , , , ) Whatever the case, it should match your function. Substitute those values into your function to solve for your output () : create your graph. Clearly label your - and - axis and use an appropriation scale. Use the ordered pair from your input/output table to place on the graph. Connect your points with a straight line. : 1. how long will it take you to reach your goal and purchase your item? 2. looking at your data (table and graph) what is one observation you can make? 3. if you double your savings each month, how does this affect the time it takes to reach your goal amount? 4. how do you know your equation is a function?

Answers

[tex]\begin{gathered} \text{PART A} \\ y=70x+17 \\ \text{PART B} \\ \text{The part B is on the pic} \\ \text{PART C } \\ \text{The part C is on the pic} \\ \text{PART D} \\ 1.\text{ } \\ 849=70x+17 \\ 70x=849-17 \\ 70x=832 \\ x=\frac{832}{70} \\ x=11,885\approx12 \\ In\text{ 12 months she will reach her goal} \\ 2. \\ These\text{ values have a direct positive relationship} \\ 3. \\ \text{new equation} \\ y=140x+17 \\ 849=140x+17 \\ 140x=849-17 \\ 140x=832 \\ x=\frac{832}{140} \\ x=5.9\approx6 \\ \text{Doubling the savings each month makes reach the goal } \\ \text{in a half time.} \\ 4.\text{ } \\ \text{The equation is a function because for each value of x it has only} \\ \text{ one value }In\text{ y} \end{gathered}[/tex]

Make a tree diagram, Please complete number 18.Please be quick, I am in a hurry.

Answers

Explanation:

The question wants us to list out all the possible outcomes in question 18

From the question

We have a spinner that has 5 possible outcomes

[tex]\mleft\lbrace\text{Red, Orange, Green, Purple, Yellow}\mright\rbrace[/tex]

The outcomes of flipping a coin are

[tex]\begin{gathered} \mleft\lbrace\text{Head, Tail}\mright\rbrace\text{ } \\ \text{which can be written as} \\ \mleft\lbrace H,T\mright\rbrace \end{gathered}[/tex]

Thus, to get the possible outcomes, we will have

Other Questions
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