help meeeeeeeeee pleaseee !!!!!

Answer:

Down Here

Step-by-step explanation:

Hello!

Area is measured in units². Here, the units are feet, so the area would be written as feet² (ft²).

Simplifying the expression:

You can't simplify this because the units are not the same, and this can't measure area because all units of the area have to be squared. The term 6ft has non-squared units.

The common ratio = 0.750 (3 decimal places)

Explanation:

Initial drop height = 72 inches

Height after the first bounce = 54 inches

common ratio = r = height on first bounce/initial height

r = 54/72

r = 0.75

The common ratio = 0.750 (3 decimal places)

Solution:

According to the problem, a regular work week consists of 5 work days with 8 hours a day. This is equivalent to say:

5 x 8 hours every regular work week.

That is:

40 hours every regular work week

then, the money earned per hour is:

then we can conclude that the correct answer is:

$7.5

A)140 adults and 72 children

Explanation

Step 1

Let x represents the number of childrend attending

Let y represents the number of adults attending

then

total cost for the children=4x

total cost for the adults=6y

if you raise 1128,

Now, 212 people attend,Hence

Step 2

solve for x and y

a)isolate x in equation (2), then replace in equation (1)

it means 140 adults are attending

b)replace y=140 in equatin (2) to find x

so, the number of children is 72 and 72 children

Use the distributive property to expand the parenthesis:

Then:

Answer:

Lower limit: 11.7 cm

Upper limit: 16.263

Explanation:

The formula to find the lower and upper limits of the confidence interval (given the data is normally distributed) is :

Where:

• μ = sample mean

• σ = sample standard deviation

• Z* = critical value of the z-distribution

• n = is the sample size

In this case:

• μ = 14cm

• σ = 4cm

• n = 12

The critical value of the z-distribution for a confidence interval of 95% is Z* = 1.96

Now, we can use the formula above to find the upper and lower limit:

Thus:

Rounded to one decimal:

Lower limit: 11.7cm

Upper limit: 16.3cm

Solution:

Case: Area

Given: A house to be painted

Method/ Final answers

a) Find the area of the garage to be painted.

(i) Front.

A = l X w - Garage door area

l= 15 ft, b= 10-4 gives 6ft

A= 15 X 6 - (10 X 7)

A= 90 - 70

A= 20 square feet

ii) Side

A= l X w

A= 6 X 5

A= 30 square feet

iii) The sum of areas

A= 20 + 30

A= 50 square feet

b) Area of the painted region around windows 5 and 6.

Since 12 in = 1 ft

Area of front door converted to feet is (20/3) ft by 3 ft

Areas of windows 5 and 6 converted to feet is 3 ft by (5/3) ft each

A= Area of space - (Area of front door + window 5 + window 6)

A= (30 X 10) - [(20/3) X 3 + 3 X (5/3) + 3 X (5/3)]

A= 300 - [20 + 5 + 5]

A= 300 - 30

A= 270 square feet.

c) Area of the painted region around windows 3

A= Total face - Area of window 3

A= (Rectangle + Parallelogram + Triangle) - Area of window 3

A= [(10 X 4) + (5 X 4) + (0.5 X 4 X 3)] - [1 X (5/3)]

A= [40+20+6] - [5/3]

A= 66 - (5/3)

A= 193/3 square feet

A= 63.33 square feet

d) Area of the region on the second floor with 2 rectangles and the region around window 4

i) region with rectangle 1 from left to right

A= 10 X (15- 6)

A= 10 X 9

A = 90

ii) region with rectangle 2 from left to right

A= 10 X (15- 6)

A= 10 X 9

A = 90

iii) Area of region around window 4

Area of space - area of window

A= 10 X (30-9-12) - [3 X (5/2)]

A= 10 X 9 - (15/2)

A= 82.5.

Total area= 90 + 90 + 82.5

= 262.5 square feet

e) Total area of the painted region (white)

262.5 + 63.33+ 270 + 50

= 645.83 square feet.

f) Additional question

The total cost if it cost $8 per sq ft

645.83 square feet X $8 per sq ft

=$5166.64

We have a one-dimensional horizontal line segment. Three points are indicated on the line as follows:

In the above sketch we have first denoted a reference point at the extreme left hand as ( Ref = 0 ). This is classified as the origin. The point ( A ) is located on the same line and is at a distance of ( 21 units ) from Reference ( Ref ). The point ( B ) is located on the same line and is at a distance of ( 66 units ) from Reference ( Ref ).

The point is located on the line segment ( AB ) in such a way that it given as ratio of length of line segment ( AB ). The ratio of point ( P ) from point ( A ) and from ( P ) to ( B ) is given as:

The length of line segment ( AB ) can be calculated as follows:

We can form a relation for the line segment ( AB ) in terms of segments related to point ( P ) as follows:

We were given a ratio of line segments as ( Eq1 ) and we developed an equation relating the entire line segment ( AB ) in terms two smaller line segments as ( Eq2 ).

We have two equation that we can solve simultaneously:

Step 1: Use Eq1 and express AP in terms of PB.

Step 2: Substitute ( AP ) in terms of ( PB ) into Eq2

We already determined the length of the line segment ( AB ). Substitute the value in the above expression and solve for ( PB ).

Step 3: Solve for PB

Step 4: Solve for AP

Step 5: Locate the point ( P )

All the points on the line segment are located with respect to the Reference of origin ( Ref = 0 ). We will also express the position of point ( P ).

Taking a look at point ( P ) in the diagram given initially we can augment two line segments ( OA and AP ) as follows:

The point ( P ) is located at.

Answer:

The median of the given data set will be 35.

So, The variability metrics for each class are listed below:

The further classifications: Class A; Class B;

Greater variability in the data set is suggested by class B's wider interquartile range and mean absolute deviations.

Set A's median will be:

Therefore, the median of the given data set will be 35.

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EXPLANATION

Let's see the facts:

rate ---> 3.6 miles / 30 minutes

The unit rate is:

Unit rate = 0.12 miles/minute

Now, dividing the needed 4.8 miles by the unit rate will give us our desired number:

Time= 4.8 miles/ 0.12miles/minute = 40 minutes

The answer is 40 minutes.

We have the next given equation:

Now, we can subtract both sides by 3p:

Then, divide both sides by 6:

Hence, the answer is p=3

The expression that is useful to determine the total amount of credit cards opened at the two locations is (A + B)(t) = 40 + 2t so option (B) is correct.

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

A statement expressing the equality of two mathematical expressions is known as an equation.

As per the given,

The amount in location A is given as

A(t) = 15 + 3t

The amount in location B is given as

B(t) = 25 − t

The total amount combined between A and B is given as,

(A + B)(t) = 15 + 3t + 25 - t

(A + B)(t) = 15 + 25 + 3t - t

(A + B)(t) = 40 + 2t

Hence "The expression that is useful to determine the total amount of credit cards opened at the two locations is (A + B)(t) = 40 + 2t".

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Answer; Meg's account is < - $15

Meg is owing the bank more than -$15

This implies that, the amount she is owing is more that -$15

The amount she is owing the bank could be -$16, -$17

Therefore, her current back account is less than -$15

Meg's account value is < -$15

Explanation

For the first question

We are asked to write the equation of the circle given that

The equation of a circle is of the form

In our case

Substituting the values

For the second question

Given that

We will have to get the midpoints (center) first

Next, we will find the radius

Using the points (4,-3) and (11,-8)

The question wants us to solve the following system of equations by elimination:

Solution

Answer

The answer to the system of equations is:

x = -8

y = 1

We have the next information

100 mg of menthol

every minute the amount of menthol in your body is cut in half

we have the next variables

x= minutes

y= amount of menthol in mg remaining in your body

so the equation that can we model is

then we have that It is safe to take a new cough drop after the level of menthol in your body is less than 5 mg

y= 5mg

in order to know the time we need to solve the equation above

then we isolate the x

after 5 minutes you can take another cough drop

Step-by-step explanation:

A nonagon has 9 sides, so a regular nonagon will have vertices that are 40° apart as measured from the center. It has 9-fold rotational symmetry,

so the figure will be identical to the original when rotated multiples of 360°/9 = 40°.

Therefore the degrees will a nonagon have rotational symmetry

Hene the correct answer is Option B

For the given situation:

In the first part of this problem, we must compute some statistic variables of two distributions:

0. the mean value,

1. the median,

2. the standard deviation.

3. the interquartile range.

1. The mean of a data set is the sum of all the data divided by the count n:

2. The median is the data value separating the upper half of a data set from the lower half, it is computed following these steps:

• arrange data values from lowest to the highest value,

• the median is the data value in the middle of the set

• if there are 2 data values in the middle the median is the mean of those 2 values.

3. The standard deviation for a sample data set is given by the following formula:

4. The interquartile range (IQR) is given by:

Where Q_1 and Q_3 are the first and third quartiles. The lowest quartile (Q1) covers the smallest quarter of values in your dataset.

--------------

Using the definitions above, we compute the mean, the median and the standard deviation for the samples taken by Manuel and Gretchen.

Manuel's sample

• Sample = {3, 6, 8, 11, 12, 8, 6, 3, 10, 5, 14, 9, 7, 10, 8}

• Count = 15

1. Mean

Using the formula above, we get:

2. Median

We order the data set:

From the ordered data set, we see that the central number 8 divides the data set into two equal parts.

So the median of this sample is:

3. Standard deviation

Using the formula above, we get:

4. Interquartile range

Dividing the data sample into quartiles, we have:

We have:

• Q_1 = 6,

• Q_3 = 10.

So the interquartile range is:

Gretchen's sample

• Sample = {22, 4, 7, 8, 12, 15, 10, 7, 9, 6, 13, 3, 8, 10, 10}

• Count = 15

1. Mean

2. Median

We order the data set:

From the ordered data set, we see that the central number 8 divides the data set into two equal parts.

So the median of this sample is:

3. Standard deviation

4. Interquartile range

Dividing the data sample into quartiles, we have:

We have:

• Q_1 = 7,

• Q_3 = 12.

So the interquartile range is:

Answers

Manuel's sample

0. Mean = 8

1. Median = 8

2. Standard deviation ≅ 3.14

3. Interquartile range = 4

Gretchen's sample

0. Mean = 9.6

1. Median = 9

2. Standard deviation ≅ 4.69

3. Interquartile range = 5

The given quadratic equation is

y = - x^2 + 25

a) The leading coeffiecient is the coefficient of the term with the highest exponent. Thus, the leading coefficient is the coefficient of x^2.

Leading coefficient = - 1

Since the leading coefficient is negative, the graph would open downwards. Thus, the correct option is

Down

b) The standard form of a quadratic equation is

y = ax^2 + bx + c

By comparing both equations,

a = - 1

b = 0

c = 25

The formula for calculating the x coordinate of the vertex of the graph is

x = - b/2a

By substituting the given values,

x = - 0/2 * - 1 = 0

We would calculate the y coordinate of the vertex by substituting x = 0 into the original equation. We have

y = - 0^2 + 25

y = 25

The coordinate of the vertex is (0, 25)

c) To find the x intercepts, we would equate the original equation to zero and solve for x. We have

- x^2 + 25 = 0

x^2 = 25

Taking the square root of both sides,

x = square root of 25

x = ± 5

Thus, the x intercepts are

(5, - 5)

d) The y intercept is the value of y when x = 0

Substituting x = 0 into the orignal equation,

y = - 0^2 + 25

y = 25

y intercept = (0, 25)

e) We would find another point on the graph. Let us substitute x = 6 into the equation. We have

y = - (6)^2 + 25 = - 36 + 25

y = - 11

We would plot (6, - 11) and (0, 25) on the graph. The graph is shown below

Express the fraction in terms of decimal.

The numbers are,

2.3, 2.4, 2.5, 2.2, 2.1.

Now we arrange the number from least to greatest.

So answer is,

We write as an inverse proportion first then make an equation by multiplying by k:

Find the value of k:

Then, when x = 2, y is:

Answer: y = 42

Given:

K is the mid-point of FG and L is the mid-point FH.

To find:

The measure of Angle H

Step-by-step solution:

As we are given that K and L are the midpoints of FG and FH respectively.

According to the mid-point theoram,

The segment that connects the mid-point of two sides, is parallel to the third side of that triangle.

Thus,

KL||GH and ∠KLF = ∠GHL

As both of these angles are corresponding angles.

So we can say that m∠H = 85 degrees.

EXPLANATION:

Given;

We are given a cone with the following dimensions;

Required;

We are required to calculate the volume of the cone with the given dimensions.

Step-by-step solution;

To solve this problem, we would take note of the formula of the volume of a cone;

We can now substitute and we'll have;

Therefore, the volume of the cone is,

ANSWER:

Solution

- The solution is given below:

- Thus, we have:

- Thus, the plot is:

(a) To find the area of the kitchen floor, we just have to multiply

(b) To find the number of tiles needed, we have to find the area of each tile, which is

Then, we divide the total area of the kitchen floor by the area of each tile.

Hence, David will need 80 tiles to cover the floor.

The value of the composite function is determined as: (g o f)(5) = 6.

To determine the value of a composite function, first evaluate the inner function by plugging in the value of x given, then use the output of the inner function as an input to evaluate the outer function.

Given the following:

f(x) = x² - 6x + 2

g(x) = -2x

Therefore:

(g o f)(5) = g(f(5))

Find f(5):

f(5) = (5)² - 6(5) + 2

f(5) = 25 - 30 + 2

f(5) = -3

Find g(f(5)) by substituting x = -3 into g(x) = -2x:

g(f(5)) = -2(-3)

g(f(5)) = 6

Therefore, (g o f)(5) = 6.

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The quadratic equation that gives the height of the rocket, h = 156·t - 16·t² is evaluated at h = 60 feet to give the two times the rocket's height is 60 feet as 0.40 seconds and 9.35 seconds.

A quadratic equation is an equation of the second degree that can be expressed in the form; a·x² + b·x + c = 0, where the letters, a, and b represents the coefficients of x and c is a constant.

The initial velocity of the rocket = 156 ft./s upwards

The given equation of the rocket is: h = 156·t - 16·t²

The times when the rocket height is 60 feet are found by plugging in the value h = 60, in the equation of the vertical height of the rocket as follows:  

h = 60 = 156·t - 16·t²

156·t - 16·t² - 60 = 0

4·(39·t - 4·t² - 15) = 0

Therefore: [tex]39\cdot t - 4\cdot t^2 - 15 = \dfrac{0}{4} =0[/tex]

39·t - 4·t² - 15 = 0

-4·t² + 39·t - 15 = 0

From the quadratic formula which is used to solve the quadratic equation of the form; f(x) = a·x² + b·x + c, is presented as follows;

[tex]x = \dfrac{-b\pm\sqrt{b^2-4\cdot a \cdot c} }{2\cdot a}[/tex]

The solution of the equation, -4·t² + 39·t - 15 = 0, is therefore:

[tex]t = \dfrac{-39\pm\sqrt{(39)^2-4\times (-4) \times (-15)} }{2\times (-4)}= \dfrac{-39\pm\sqrt{1281} }{-8}[/tex]

Therefore, when the height of the rocket is 60 feet, the times are: [tex]t = \dfrac{-39-\sqrt{1281} }{-8}\approx 9.35[/tex] and [tex]t = \dfrac{-39+\sqrt{1281} }{-8}\approx 0.40[/tex]

The times when the height of the rocket is 60 feet, the times are:

t ≈ 9.35 s, and t ≈ 0.40 s

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