Help please due by 3:00

Answer:

The answer is "Option b"

Explanation:

[tex]\to \bold{y(t) = y_0e^{-a t} cos(\omega t)}[/tex]

           [tex]= y_0 e^{-\alpha t} cos(\omega t)[/tex]

and

[tex]\bold{y(t) =f(t) \cdot g(t)}[/tex]

where  

[tex]\to f(t) = y_{0}\ e^{- at} \ \ \ \ \ \\\\\ \to g(t) = cos {(\omega t)}[/tex]

Answer:7.5. 10^4 J

Explanation:

Answer:

The Kinetic Energy of the car at that instant will be 123,210 Joules.

Explanation:

Given:

Mass=500 Kg

[tex]Speed= 80 km/h=\frac{80*1000}{3600}\ m/s =22.2 m/s[/tex]

Required:

Kinetic energy (K.E)=?

Formula:

[tex]K.E=\frac{1}{2}mv^{2}[/tex]

Where:

m is the mass.

v is the speed.

Solution:

[tex]K.E=\frac{1}{2}mv^{2}\\K.E=\frac{1}{2} *500* (22.2)^{2} \\K.E=123,210 J[/tex]

The Kinetic Energy of the car at that instant will be 123,210 Joules.

Answer:

Based on the scientific notation ,

4.372896 x10^-7 is the answer.

Answer:

c and d

Explanation:

I got your back bro ;)

Answer:

C and D

Explanation:

Explanation:

If your reaction time is 1 second, then the new reaction time for each is:

Alcohol: 0.30 × 1 + 1 = 1.30

Drugs: 0.50 × 1 + 1 = 1.50

Cell phone: 0.20 × 1 + 1 = 1.20

Answer:

Explanation:

Volume of bottle filled = 2/3 x π R²h , R = radius = 2.5cm  , h = height = 6 cm

= 2/3 x 3.14 x 2.5² x 6 = 78.5 cm³

volume of one squirt =  π R² x .025 = 3.14 x 2.5² x .025 = .49 cm³

No of squirt required = 78.5 / .49 = 160.2 = 160

b )

mass of extract  = volume x density = 78.5 x 1.135 = 89 gm

c ) mass of one squirt = volume of one squirt x density = .49 x 1.135 = .57 gm

Answer:

Mass and distance

Explanation:

Answer:

Mass and distance

Explanation:

the larger the mass the faster it falls or more gravity is applied same goes for the distance the farther it is from the ground its heavier however if its to far gravity then does not apply

hope this helps :)

can have brainlist please

Answer:

The position at t=11 seconds is -96 m or 96 m to the left of the origin

Explanation:

Constant speed and constant acceleration motion

If a body travels the same distance per unit of time, the body has a constant speed. The equation for the distance x is:

[tex]x=v.t[/tex]

Where v is the constant speed and t is the time.

At time t=0 the body is moving at a constant speed of v=24 m/s in the positive x-direction. It keeps that condition for t=1 sec. The distance traveled is:

[tex]x=24m/s\cdot 1\ s=24\ m[/tex]

Now the body is given a constant acceleration of 6 m/s^2 in the negative x-direction, that is, a=-6 m/s^2

The distance traveled by a body at constant acceleration is given by:

[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]

Where vo is the initial speed and t is the time.

We need to find the position at t=11 sec, but we must subtract the one second already passed, thus t=10 s

[tex]\displaystyle x=24m/s\cdot 10s+\frac{-6m/s^2.(10)^2}{2}[/tex]

[tex]\displaystyle x=240\ m-360\ m=-120\ m[/tex]

This distance must be added to the actual position of the body, that is:

-120 m + 24 m = -96 m

The position at t=11 seconds is -96 m or 96 m to the left of the origin

Answer:

C₁ = 34.8 μF

C₂ = 0.2 μF

Explanation:

When the capacitors are connected in series their resultant capacitance is given by the formula:

Cs = 1/C₁ + 1/C₂

where,

Cs = Series equivalent capacitance = 4.8 μF

C₁ = Capacitance of 1st Capacitor

C₂ = Capacitance of 2nd Capacitor

Therefore,

4.8 μF = 1/C₁ + 1/C₂

(4.8 μF)(C₁ C₂) = C₁ + C₂   --------------- equation 1

When the capacitors are connected in parallel their resultant capacitance is given by the formula:

Cp = C₁ + C₂

where,

Cp = Parallel equivalent capacitance = 35 μF

Therefore,

35 μF = C₁ + C₂   -------------- equation 2

solving equation 1 and equation 2 simultaneously, we get:

C₁ = 34.8 μF

C₂ = 0.2 μF

Answer: High voltage transmission minimizes energy losses during electricity transmission.

Explanation:

When electricity is to be transmitted over a long distance, high voltage transmission is preferred to minimize energy losses due to heat.

The higher the transmission voltage, the lower the current and the lesser the resitance in the wire and the lesser the energy lost due to heat during transmission.

High voltage transmission in kilowatts enables light weight cables to be used for long distance electricity transmission.

This explains why, even though only 110 V may be required at home by some appliances, but electricity is transmitted in kilovolts and often require a stepdown transformer

Answer:

The mass flowrate of the cooling water needed to meet the regulation is 560 kg/s

Explanation:

The given information are;

The mass flow rate of the water = 562.0 kg/s

The temperature of the exit water = 330.0 K

The allowable temperature of the of released water into nearby river = 310.00 K

The temperature of the cool water with which the temperature of the exit water is cooled = 290.00 K

Therefore, we have;

Heat gained by the mixture = The heat of the final mixture exited to the river

Q = m×c×ΔT

[tex]m_w[/tex] = 562.0 kg/s

The mass of the cooling water = x

The final temperature = 310 K

4.2×562×(330 - 310) = x×4.2×(310 - 290)

47208 = 84×x

x = 47208/84 = 560 kg

Therefore, the mass flowrate of the cooling water needed to meet the regulation = 560 kg/s.

Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

Answer:

A measure of the ability of a material to transfer heat.

Explanation:

Please mark me as brainliest please

Answer:

GPE = mgh = 5.00 kg .

 2.20 + 0.30 m = 122.5 J

Explanation:

Answer:

In the statement of Newton's first law, the unbalanced force refers to that force that does not become completely balanced (or canceled) by the other individual forces. If either all the vertical forces (up and down) do not cancel each other and/or all horizontal forces do not cancel each other, then an unbalanced force exists. The existence of an unbalanced force for a given situation can be quickly realized by looking at the free-body diagram for that situation. Free-body diagrams for three situations are shown below. Note that the actual magnitudes of the individual forces are indicated on the diagram.

In each of the above situations, there is an unbalanced force. It is commonly said that in each situation there is a net force acting upon the object. The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out. At this point, the rules for summing vectors (such as force vectors) will be kept relatively simple. Observe the following examples of summing two forces:

Observe in the diagram above that a downward vector will provide a partial or full cancellation of an upward vector. And a leftward vector will provide a partial or full cancellation of a rightward vector. The addition of force vectors can be done in the same manner in order to determine the net force (i.e., the vector sum of all the individual forces). Consider the three situations below in which the net force is determined by summing the individual force vectors that are acting upon the objects.

Answer:

For proton:

A. The proton is released from Vb (highest potential)

B. v = 2.9x10⁴ m/s

For electron:

A. The electron is released from Va (lowest potential)

B. v = 1.2x10⁶ m/s    

Explanation:

For a proton we have:

A. To find the origin from which the proton was released we need to remember that in a potential difference, a proton moves from the highest potential to the lowest potential.                

Having that:

Va = 1.51 V and Vb = 5.81 V

We can see that the proton moves from Vb to Va, hence the proton was released from Vb.

B. We now that the work done by an electric field is given by:

[tex]W = \Delta Vq[/tex]    (1)                                        

Where:

q: is the proton's charge = 1.6x10⁻¹⁹ C    

V: is the potential    

Also, the work is equal to:

[tex] W = \Delta K = (K_{a} - K_{b}) = \frac{1}{2}mv_{a}^{2} - \frac{1}{2}mv_{b}^{2} [/tex]     (2)      

Where:

K: is the kinetic energy

m: is the proton's mass = 1.67x10⁻²⁷ kg

[tex]v_{a}[/tex]: is the velocity in the point a

[tex]v_{b}[/tex]: is the velocity in the point b = 0 (starts from rest)

Matching equation (1) with (2) we have:

[tex]\Delta Vq = \frac{1}{2}mv_{a}^{2}[/tex]

[tex](5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}1.67 \cdot 10^{-27} kg*v_{a}^{2}[/tex]

[tex] v_{a} = 2.9 \cdot 10^{4} m/s [/tex]

For an electron we have:

A. For an electron we know that it moves from the lowest potential (Va) to the highest potential (Vb), so it is released from Va.

B. The speed is:

[tex]\Delta Vq = \frac{1}{2}mv_{b}^{2} - \frac{1}{2}mv_{a}^{2}[/tex]

Since [tex]v_{a}[/tex] = 0 (starts from rest) and [tex]m_{e}[/tex] = 9.1x10⁻³¹ kg (electron's mass), we have:

[tex](5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}9.1 \cdot 10^{-31} kg*v_{b}^{2}[/tex]    

[tex]v_{b} = 1.2 \cdot 10^{6} m/s[/tex]

I hope it helps you!

Answer:

1. Force is a push or a pull that usually causes distortion and/or acceleration.

2. force of friction holding nails and screws in desks, cabinets, walls, etc.

3. weight (force of gravity) pulling down on everything.

4. force of friction between you and your seat

Explanation:

A force can be defined as a push or a pull that usually causes distortion and/or acceleration. A force is a vector quantity because it has both magnitude and direction. Also, force typically causes an interaction (push or a pull) between two objects such as frictional force, gravitational force, tension force, electric force, normal force, magnetic force etc.

Mathematically, a force is given by the equation;

[tex]F = ma[/tex]

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Thus, the acceleration (a) of an object of constant mass (m) is directly proportional to the amount of force acting on it or the degree of force exerted on it.

Additionally, the standard unit of measurement for a force is Newton (N).

Some examples of forces found around us are;

1. Force of friction holding nails and screws in desks, cabinets, walls, etc.

2. Weight (force of gravity) pulling down on everything.

3. Force of friction between you and your seat.

Answer:

Let there be vectors A and B  where B = -A

Then A + B = 0

Answer:

Explanation:

Voltage = 12 (the two batteries are in series and the voltage adds).

Resistance = 3 ohms

I = V / R

I = 12/3

I = 4 amperes.

None of the answers are the right ones. If there is a fifth one that reads 4 amperes then it is the correct answer.

Answer:

The minimum acceleration his partner will need in order to catch Bond before he hits the water is 25.688 meters per square second.

Explanation:

Let be the initial position of the sppedboat the reference location, James Bond jumps horizontally and experiments a parabolic motion, which consists in a horizontal motion at constant velocity and an vertical uniform accelerated motion due to gravity.

Speedboat must accelerate from rest and get Bond at right location and instant. Now we describe the appropriate equations of motion for James Bond and for the speedboat:

James Bond

[tex]x_{B} = x_{B,o} + v_{B,o,x} \cdot t[/tex]

[tex]y_{B} = y_{B,o} + v_{B, o, y}\cdot t + \frac{1}{2}\cdot g \cdot t^{2}[/tex]

Speedboat

[tex]x_{S} = x_{S,o}+v_{S,o}\cdot t + \frac{1}{2}\cdot a_{S}\cdot t^{2}[/tex]

Where:

[tex]x_{B,o}[/tex], [tex]x_{S,o}[/tex] - Initial horizontal positions for James Bond and the speedboat, measured in meters.

[tex]x_{B}[/tex], [tex]x_{S}[/tex] - Current horizontal positions for James Bond and the speedboat, measured in meters.

[tex]v_{B,o,x}[/tex], [tex]v_{S,o}[/tex] - Initial horizontal velocities of James Bond and the speedboat, measured in meters per second.

[tex]v_{B,o, y}[/tex] - Initial vertical velocity of James Bond, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a_{S}[/tex] - Acceleration of the speedboat, measured in meters per square second.

We must observe the following conditions such as we may calculate the minimum acceleration of the speedboat:

1) [tex]x_{B} = x_{S}[/tex]

2) [tex]y_{B} = 0\,m[/tex]

Now, if we know that [tex]x_{B,o} = 60\,m[/tex], [tex]x_{S,o} = 0\,m[/tex], [tex]y_{B, o} = 18\,m[/tex], [tex]y_{B} = 0\,m[/tex], [tex]v_{B,o, x} = -6.7\,\frac{m}{s}[/tex], [tex]v_{S,o} = 0\,\frac{m}{s}[/tex], [tex]v_{B,o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the resulting system of equations is:

[tex]60\,m +\left(-6.7\,\frac{m}{s} \right)\cdot t = 0\,m +\left(0\,\frac{m}{s} \right)\cdot t +\frac{1}{2}\cdot a_{S}\cdot t^{2}[/tex]

[tex]\frac{1}{2}\cdot a_{S}\cdot t^{2} +\left(6.7\,\frac{m}{s} \right)\cdot t -60\,m = 0[/tex] (Eq. 1)

[tex]0\,m = 18\,m +\left(0\,\frac{m}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]

[tex]\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}+18\,m = 0[/tex] (Eq. 2)

At first we get the time from (Eq. 2) by using the Quadratic Formula:

[tex]t_{1} \approx 1.916\,s[/tex] and [tex]t_{2}\approx -1.916\,s[/tex]

Only the first root is physically reasonable. ([tex]t\approx 1.916\,s[/tex])

Then, we substitute time in (Eq. 1) and clear the acceleration of the speedboat:

[tex]\frac{1}{2}\cdot a_{S}\cdot (1.916\,s)^{2} +\left(6.7\,\frac{m}{s} \right)\cdot (1.916\,s) -60\,m = 0[/tex]

[tex]1.836\cdot a_{S}-47.163\,m = 0[/tex]

[tex]a_{S} = 25.688\,\frac{m}{s^{2}}[/tex]

The minimum acceleration his partner will need in order to catch Bond before he hits the water is 25.688 meters per square second.

Answer and Explanation:

A. We have temperature t = 32

Speed of sound, s = 1087.5

As t increases by 1⁰f speed increases by 1.2

So that

S = 1088.6

T= 33⁰f

We have 2 equations

1087.5 = k(32) + c

1088.6 = k(33) + c

Subtracting both equations

(33-32)k = 1088.6-1087.5

K = 1.1

b.). S = kT + c

1087.5 = 32(1.1) + c

Such that

C = 1052.3

Therefore

S = 1.1(t) + 1052.3

C.). S = 1.1t + 1052.3

We make t subject of the formula

T = s/1.1 - 1052.3/1.1

T = 0.90(s) - 956.3

D. This means that We have temperature to rise by 0.90 whenever speed is increased

Answer:

1.76 m/s^2

Explanation:

The formula to find the force is F = ma (reference from 2nd law of Newton's Laws of Motion). Since you need to find the acceleration of the box, you need to use the formula a = f/m

a = 9.7 n divided by 5.5 kg = 1.76 m/s^2

Car B travels a distance x after time t (measured in seconds) of

x = (80 m/s) t

so that at 6:40 AM (which is 40 min = 2400 s after the starting time of 6:00 AM), it will have moved

(80 m/s) * (2400 s) = 192,000 m

If we take t = 0 to refer to 6:40 AM, the cars' respective positions x at time t are given by

A: x = (280 m/s) t

B: x = 192,000 m + (80 m/s) t

(i) After 1 h = 3600 s, their positions are

A: (280 m/s) * (3600 s) = 1,008,000 m

B: 192,000 m + (80 m/s) * (3600 s) = 480,000 m

away from the point X, so the distance between the two cars is

1,008,000 m - 480,000 m = 528,000 m = 582 km

(ii) Car A moves faster than car B, so A overtakes B as soon as their positions are equal, which happens for

(280 m/s) t = 192,000 m + (80 m/s) t

(200 m/s) t = 192,000 m

t = (192,000 m) / (200 m/s)

t = 960 s = 16 min

So after 16 min, both cars have a position of

(280 m/s) * (960 s) = 268,800 m = 268.8 km

beyond point X.

Answer:

No. If the moon did not rotate at all we would still see the same visible "fraction" of the moon's surface.

At the full moon  phase we would still the entire surface of  1/2 of the moon regardless of which side of the moon we were observing.

Actually the moon does not make one rotation for each revolution of the earth, but rather, one rotation for each complete revolution of the moon around the the earth. That's why we always see the same side of the moon from earth. The back side of the moon is never visible from earth.

Answer:

The value is [tex]t_t =41.12 \ s [/tex]

Explanation:

From the question we are told that

The maximum acceleration is [tex]a_m = 2.10 \ m/s^2[/tex]

The maximum velocity is [tex]v_m = 10.3 \ m/s[/tex]

The height of the observatory floor is [tex]H = 373 \ m[/tex]

Generally at the initial state of the motion the elevator accelerates from rest with a maximum acceleration [tex]a_m = 2.10 \ m/s^2[/tex] to attain a maximum velocity [tex]a_m = 2.10 \ m/s^2[/tex] at a time period of [tex]t_a[/tex]

Then it continues with the maximum velocity for a time period of [tex]t_b[/tex]

and finally decelerates with a maximum deceleration [tex] a_m = -2.10 \ m/s^2[/tex] to come to rest at a time period of [tex]t_c[/tex]

Generally the velocity of the elevator for the first part of the motion is

[tex]v = u + at_a[/tex]

given that it started from rest u = 0 m/s

=> [tex]10.3 = 2.10t_a[/tex]

=> [tex]t_a = 4.90 \ s [/tex]

Generally from kinematic equations the distance covered during the first part of the motion is

[tex]S_1 = ut_a + \frac{1}{2} at_a^2[/tex]

=> [tex]S_1 = 0 + \frac{1}{2} (2.10 ) (4.90)^2[/tex]

=> [tex]S_1 = 25.21 \ m [/tex]

Generally the distance covered during the second part of the elevators motion is mathematically represented as

[tex]S_2 = v_m * t_2[/tex]

[tex]S_2 = 10.3 t_b[/tex]

Generally given that the first part of the elevator motion is similar to the third part of the elevator motion it implies that the distance covered is similar

i.e [tex]S_1 = S_3 = 25.21 \ m[/tex]

The total distance covered is mathematically repented as

[tex]H = S_1 + S_2 + S_3[/tex]

=> [tex]373 = 25.21 + 10.3 t_b + 25.21 [/tex]

=> [tex]t_2 = 31.32 \ s [/tex]

Generally the minimum total time taken is

[tex]t_t = t_a + t_b + t_c[/tex]

Generally [tex]t_a = t_c = 4.90 \ s[/tex]

So

     [tex]t_t  =4.90+ 31.32 +4.90[/tex]

=> [tex]t_t =41.12 \ s [/tex]

Answer:D:

Laboratory experiments involve the identification and control of variables.

Explanation:

Its D

Laboraty Expirements inolve the Identification and control of variables

Answer:

No, although the thoughts, hopes, dreams and aspirations entirely the results of physiological processes: Love, hate, anger and memories are not only at the synaptic level because some or part of human behavior and reaction are due to nature and nurture rather than totally dependent on the external stimuli or nurture

Explanation:

The physiological process can be described as a part of a system that plays a role on how the brain works and in inventory management, a part of a product are items that can be counted in inventory and can then be sold or used internally while a product is an item only meant to be sold.

Therefore, a product consist of all the integral parts required to complete a given function

A product such as what determines emotions, aspirations, thoughts, hopes and dreams has only one predetermined purpose or a process which it fits into even before if was sold or made, just like a bus bought to carry future employees of a company that is having a new site office.

While a part such as the fan belt can be changes and used on other vehicles without altering the journey of the bus.

A system is more than just its integral part as the system was desirable even before it was made while a part is made because of the system.

Answer:

P1 = 2680 pa            P2  = 4870pa

T1 = 273k                  T2 = T

From the ideal gas equation,

P1 / T1 = P2 / T2

2680 / 273 = 4870 / T

T = 4870 * 273 / 2860

T  = 496.38 k

Kindly Mark Brainliest, Thanks

Answer:

223.38 C

Explanation:

according to gay lussacs law

p1/t1=p2/t2

so 2680/273.16=4870/t2

or t2=496.38 K

in celsius= 496.38-273=223.38 C

Answer:

mathematical model

Explanation:

A computer model is a very complex type of mathematical model.

These complex mathematical models involves series of equations or algorithms known as set of instructions for the computer to perform difficult computations. These mathematical models include dynamical systems, statistical models, or differential equations.