HELP PLS LAST QUESTION I WILL MARK BRAIN :D

Answer:

D

Step-by-step explanation:

Answer:

It's true...

Step-by-step explanation:

hope it helps...m

Answer:

189.27 in.

Step-by-step explanation:

15 x 10 = 150

10/2= 5 x 5= 25 x 3.14= 78.54/2= 39.27

Answer:

150

Step-by-step explanation:

Step-by-step explanation:

first term

degree 1

coefficient 4

second term

degree. 2

coefficient 8

third term

degree 3

coefficient -5

fourth term

degree 4

coefficient -5

fifth term

degree 0

coefficient -5

Answer:

A=2πr(r+h)= surface area

so your equation would be 2π8(8+12)=  D.  1004.80

The surface area of the cylinder is 1004.80 square centimeters

The given parameters are:

Radius = 8 cm.; Height = 12 cm.

The surface area of a cylinder is:

[tex]S = 2\pi r(h + r)[/tex]

So, we have:

S = 2 * 3.14 * 8 * (12 + 8)

Evaluate

S = 1004.80

Hence, the surface area of the cylinder is 1004.80 square centimeters

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Answer:

4) [tex]\frac{x}{7\cdot x +x^{2}}[/tex] is equivalent to [tex]\frac{1}{7+x}[/tex] for all [tex]x \ne -7[/tex]. (Answer: A)

5) [tex]\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}[/tex] is equivalent to [tex]-\frac{14}{1-5\cdot x}[/tex] for all [tex]x \ne \frac{1}{5}[/tex]. (Answer: B)

6) [tex]\frac{x+7}{x^{2}+4\cdot x - 21}[/tex] is equivalent to [tex]\frac{1}{x-3}[/tex] for all [tex]x \ne 3[/tex]. (Answer: None)

7) [tex]\frac{x^{2}+3\cdot x -4}{x+4}[/tex] is equivalent to [tex]x - 1[/tex]. (Answer: None)

8)  [tex]\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}[/tex] is equivalent to [tex]\frac{4}{3\cdot a^{3}}[/tex] for all [tex]a\ne 0[/tex]. (Answer: A)

Step-by-step explanation:

We proceed to simplify each expression below:

4) [tex]\frac{x}{7\cdot x +x^{2}}[/tex]

(i) [tex]\frac{x}{7\cdot x +x^{2}}[/tex] Given

(ii) [tex]\frac{x}{x\cdot (7+x)}[/tex] Distributive property

(iii) [tex]\frac{1}{7+x} \cdot \frac{x}{x}[/tex] Distributive property

(iv) [tex]\frac{1}{7+x}[/tex] Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

[tex]7+x = 0[/tex]

[tex]x = -7[/tex]

Hence, we conclude that [tex]\frac{x}{7\cdot x +x^{2}}[/tex] is equivalent to [tex]\frac{1}{7+x}[/tex] for all [tex]x \ne -7[/tex]. (Answer: A)

5) [tex]\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}[/tex]

(i) [tex]\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}[/tex] Given

(ii) [tex]\frac{x^{3}\cdot (-14)}{x^{3}\cdot (1-5\cdot x)}[/tex] Distributive property

(iii) [tex]\frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right)[/tex] Distributive property

(iv) [tex]-\frac{14}{1-5\cdot x}[/tex] Commutative property/Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

[tex]1-5\cdot x = 0[/tex]

[tex]5\cdot x = 1[/tex]

[tex]x = \frac{1}{5}[/tex]

Hence, we conclude that [tex]\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}[/tex] is equivalent to [tex]-\frac{14}{1-5\cdot x}[/tex] for all [tex]x \ne \frac{1}{5}[/tex]. (Answer: B)

6) [tex]\frac{x+7}{x^{2}+4\cdot x - 21}[/tex]

(i) [tex]\frac{x+7}{x^{2}+4\cdot x - 21}[/tex] Given

(ii) [tex]\frac{x+7}{(x+7)\cdot (x-3)}[/tex] [tex]x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})[/tex]

(iii) [tex]\frac{1}{x-3}\cdot \frac{x+7}{x+7}[/tex] Commutative and distributive properties.

(iv) [tex]\frac{1}{x-3}[/tex] Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

[tex]x-3 = 0[/tex]

[tex]x = 3[/tex]

Hence, we conclude that [tex]\frac{x+7}{x^{2}+4\cdot x - 21}[/tex] is equivalent to [tex]\frac{1}{x-3}[/tex] for all [tex]x \ne 3[/tex]. (Answer: None)

7) [tex]\frac{x^{2}+3\cdot x -4}{x+4}[/tex]

(i) [tex]\frac{x^{2}+3\cdot x -4}{x+4}[/tex] Given

(ii) [tex]\frac{(x+4)\cdot (x-1)}{x+4}[/tex]  [tex]x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})[/tex]

(iii) [tex](x-1)\cdot \left(\frac{x+4}{x+4} \right)[/tex] Commutative and distributive properties.

(iv) [tex]x - 1[/tex] Existence of additive inverse/Modulative property/Result

Polynomic function are defined for all value of [tex]x[/tex].

[tex]\frac{x^{2}+3\cdot x -4}{x+4}[/tex] is equivalent to [tex]x - 1[/tex]. (Answer: None)

8) [tex]\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}[/tex]

(i) [tex]\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}[/tex]

(ii) [tex]\frac{4}{3\cdot a^{3}}[/tex] [tex]\frac{a}{b}\cdot \frac{c}{d} = \frac{a\cdot b}{c\cdot d}[/tex]/Result

Rational functions are undefined when denominator equals 0. That is:

[tex]3\cdot a^{3} = 0[/tex]

[tex]a = 0[/tex]

Hence, [tex]\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}[/tex] is equivalent to [tex]\frac{4}{3\cdot a^{3}}[/tex] for all [tex]a\ne 0[/tex]. (Answer: A)

9514 1404 393

Answer:

  L = 882/121 feet

Step-by-step explanation:

Set the appropriate variables in the equation to the given values and solve for the unknown.

  [tex]T=2\pi\sqrt{\dfrac{L}{32}}\\\\3=2\left(\dfrac{22}{7}\right)\sqrt{\dfrac{L}{32}} \qquad\text{fill in given values}\\\\ \dfrac{3\cdot7}{44}=\sqrt{\dfrac{L}{32}} \qquad\text{multiply by $\dfrac{7}{44}$}\\\\ \left(\dfrac{21}{44}\right)^2=\dfrac{L}{32}\qquad\text{square both sides}\\\\ \dfrac{32\cdot441}{1936}=L \qquad\text{multiply by 32}\\\\ \boxed{L=\dfrac{882}{121}}\qquad\text{reduce the fraction}[/tex]

_____

Additional comment

That's about 7.3 feet. (You can compare this to what you know about the time it takes for a cycle when swinging on a swing set.)

Answer:

Less than because it would equal 16035.75

Step-by-step explanation:

Answer:

Point-slope equation for the line is

[tex]y-2= -\frac {3}{2} (x -0)[/tex]

Step-by-step explanation:

Equation of straight line in slope intercept form is given as

[tex]y-y_1=m(x-x_1)[/tex]  ---------- (1)

Here

Slope            [tex]m=-\frac{3}{2}[/tex]  

Any Passing Point     [tex](x_1, y_1) = (0, 2)[/tex]

Substituting values in equation (1)

[tex]y-2= -\frac {3}{2} (x -0)[/tex]

Answer:

x= 4

y= 116°

Step-by-step explanation:

In a parallelogram, opposite sides are congruent

This means :

(y-60) ° = 56°

y= 56°+60°

y= 116°

And , parallel sides of a parallelogram are equal so;

16 = 3x + 4

16-4 = 3x

12 = 3x

12/3 = x

4 = x

Answer:

Step-by-step explanation:

Price:

Equations:

Multiply the first equation by 5 and the second equation by 2 and subtract to eliminate x:

Use the first equation to find x:

Iced tea costs $4.50 per gallon

Lemonade costs $4.75 per gallon

Answer:

x + 15

Step-by-step explanation:

N/A

Step-by-step explanation:

first you have to do the subtraction in the parentheses so it's 8+3(4) and then you multiply the 3 by 4 (only the 3 because the 8 isn't next to the multiply) and then you have 12, add 8 and it's 20

Answer:

a. H0: u ≠33 against Ha : u= 33

b. Z= x`- u / s/ √n, z= 1.85

c. The P-Value is 0.071075.

The result is not significant at p < .05.

d. Option A is correct.

A. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the mean age of actresses when they win an acting award is 33 years.

Step-by-step explanation:

Part a:

The null and alternate hypotheses are

H0: u ≠33  That is the mean age of actresses when they win an acting award is not equal to  33 years.

against the claim

Ha : u= 33 That is  the mean age of actresses when they win an acting award is 33 years.

The central limit theorem allows us to assume that the sampling distribution of  x`  is approximately normal with the mean u and  a standard deviation S/ √n.

Part b.

The test statistic would be

Z= x`- u / s/ √n

So we have

n= 77 , x= 35.4, s= 11.7

Z= 35.4- 33/ 11.7/√77

z= 2.4/1.333

z= 1.805

Now z α/2 =  ± 1.96 for two tailed test.

Part  d.

The rejection region will be

z< - z ∝/2 and z > z ∝/2

1.805 < 1.96

Since the calculated value of z lies in the rejection region we fail to reject H0 and conclude there is insufficient evidence to warrant rejection of the claim that the mean age of actresses when they win an acting award is 33 years.

Part c.

The p- value is the probabilities between which the value of test statistic lies.

Using the calculator

The P-Value is 0.071075.

The result is not significant at p < .05

Answer:

they played 48 games

Step-by-step explanation:

let 'g' = total # of games

5/6g = 40

g = 48

40 wins, 8 losses

Answer:

$26

Step-by-step explanation:

78 divided by 3

Answer:

43.96

(i used 3.14 for pie)

Step-by-step explanation:

5/6 is less than 2 1/2

5/6 < 15/6

0.833333333333 < 2.5

5/6 <  2 1/2  

I think i'm not to good at math

Answer:

3

Step-by-step explanation:

divide 2 1/2 by 5/6

5/2 ÷ 5/6 = 5/2 · 6/5 = 30/10 or 3

Answer:

15

Step-by-step explanation:

10×10 =100

5×10= 50

100+50=150

Answer:

8.4 miles

Step-by-step explanation:

a mph in 45 min.

This means that she did 0.75 of a miles during that time.

When she bikes 4mph slower, she did 0.75a-4 which took her 70 minutes.

Now, V=d/t.

First equation: 0.75a=d/45

Second equation: (0.75a-4)=d/70

First equation: d=33.75a

Second equation: d=52.5a-280

Now, to put it all together: 52.5a-280=33.75a

18.75a=280

a= 14 14/15 mph

1 hour=60 min.

d=(0.75*14 14/15)/60

d=504/60

d=8.4 miles.

:)

Jasmine's grandma's home will be 504 miles away from her home.

The relation between distance[x] and time [t] is -

⇒ [x] = v [t]

where v is the velocity of body.

Given that;

Jasmine reached her grandma's house in 45 minutes. When she was biking back home in the evening it was foggy and she went 4 mph slower. The trip back took her 1 hour and 10 minutes.

Now, Let her grandma's home be [x] miles away form her house.

Assume that her velocity was [v] mph on her way to grandma's house.

So, We get;

⇒ 45 = x/v

⇒ x = 45v

And, Her velocity on her way back home would be [v - 4] mph

⇒ 70 = x/(v - 4)

⇒ x = 70(v - 4)

Equating both -

⇒ 45v = 70(v - 4)

⇒ 45v = 70v - 280

⇒ 70v - 45v = 280

⇒ 25v = 280

⇒ v = 11.2 mph

Hence, The value of [x] will be -

⇒ x = 45 x 11.2 = 504 miles

Thus, Jasmine's grandma's home will be 504 miles away from her home.

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Answer:

5-10g+20h

Step-by-step explanation:

Distribute the 5 to each number

Answer:

that's the right answer

Step-by-step explanation:

Answer:

36

please Mark as brainliest

Answer:

The average rate of change of the function from x=1 to x=2 will be: 10.5                

Step-by-step explanation:

Given the function

[tex]f\left(x\right)=-\frac{14}{x^2}[/tex]

at x₁ = 1,

f(x₁) = f(1) =  -14/(1)² = -14/1 = -14

at x₂ = 2,

f(x₂) = f(2) = -14/(2)² = -14/(4) = -3.5

Using the formula to determine the average rate of change at which the total cost increases will be:

Average rate of change = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                                        = [-3.5 - (-14)] / [2 - 1]

                                        = [-3.5 + 14] / [1]

                                        = 10.5 / 1

                                        = 10.5

Therefore, the average rate of change of the function from x=1 to x=2 will be: 10.5                      

Answer:

63/50 meters^2 or in mixed number: 1 13/50 meters^2

Step-by-step explanation:

Area= length * width

length = 4 1/5= 21/5 . Multiply the whole number with the denominator. 4*5= 20 . Add 20 with the numerator. 20+1=22

width= 3/10

21/5* 3/10 ( Multiply the denominators together). ( Multiply the numerators together).

21*3 / 5*10

The solution is Option A.

The area of rectangular garden is A = 1 13/50 meters

The area of the rectangle is given by the product of the length of the rectangle and the width of the rectangle

Area of Rectangle = Length x Width

Given data ,

Let the area of the rectangular garden be A

Now , the equation will be

The length of the rectangle = 4 1/5 meters

The length of the rectangle = 21/5 meters

The width of the rectangle = 3/10 meters

So , Area of Rectangle = Length x Width

The area of the rectangular garden A = ( 21/5 ) x ( 3/10 )

On simplifying the equation , we get

The area of the rectangular garden A = 63/50

The area of the rectangular garden A = 1 13/50 meters

Hence , the area of the rectangular garden is 1 13/50 meters

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Answer:

Step-by-step explanation:

37.4 is the correct answer.

Hope it helped you.

Answer:

20.3 + 17.1 = 37.4

B=37.4

Answer:

32n-16n

Step-by-step explanation: