Based on the fact that Home Liquidators marked up their merchandise by 35% on cost, the company equivalent markup on selling price is 26%.
How to find the equivalent markup?The equivalent markup by Home Liquidators on the selling price can be found by the formula:
= Percentage markup / Percentage selling price x 100%
The percentage markup = 35%
Percentage selling price = (100% + 35%) = 135%
The equivalent markup by Home Liquidators is therefore:
= 35% / 135% x 100%
= 26%
In conclusion, the Home Liquidators has an equivalent markup of 26% on selling price.
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Multiply. Write your answer in decimal form: (8 x 10^2)(4 x 10^2)
Answer:
32×10⁴
Step-by-step explanation:
open the bracket
8×4×10^(2+2)
32×10⁴
hope it helps
please mark brainliest
6 eggs weigh 3/4 of a pound. How much does each egg weigh? 1/4 pounds1/6 pounds1/8 pounds2/3 pounds
A hiker on the Appalachian Trail planned to increase the distance covered by 10% each day. After 7 days, the total distance traveled is 75.897 miles.
part A. We are given that a hiker will increase the distance covered by 10% each day. Let "S" be the distance, then on the first day the distance is:
[tex]S_1[/tex]On the second day, we must add 10% of the first day, we get:
[tex]S_1=S_1+\frac{10}{100}S_1[/tex]Simplifying we get:
[tex]S_2=S_1+0.1S_1=1.1S_1[/tex]On the third day, we add 10% of the second day, we get:
[tex]S_3=S_2+0.1S_2=1.1S_2=(1.1)(1.1)S_1=(1.1)^2S_1[/tex]On the fourth day, we add 10% of the third day, we get:
[tex]S_4=S_3+0.1S_3=1.1S_3=(1.1)^3S_1[/tex]If we continue this pattern and we set "n" as the number of days, then a formula for the distance after "n" days is:
[tex]S_n=(1.1)^{n-1}S_1[/tex]Now, we are given that for n = 7 the distance is 75897, therefore, we substitute n = 7 in the formula:
[tex]S_7=(1.1)^{7-1}S_1[/tex]Substituting the value of the distance:
[tex]75897=(1.1)^{7-1}S_1[/tex]Now we can solve for S1, we do that by dividing both sides by 1.1 together with its
exponent:
[tex]\frac{75897}{(1.1)^{7-1}}=S_1[/tex]Now we solve the operations:
[tex]\frac{75897}{(1.1)^6}=S_1[/tex]Solving the operations:
[tex]42842=S_1[/tex]Therefore, the distance the first day was 42842 miles.
part B. The formula for Sn is the given previously but we replace the known value of S1:
[tex]S_n=42842(1.1)^{n-1}[/tex]Part C. To determine the distance after 10 days, we substitute the value n = 10 in the formula, we get:
[tex]S_{10}=42842(1.1)^{10-1}[/tex]Solving the operations we get:
[tex]S_{10}=101019.19[/tex]Therefore, the distance after 10 days is 101019.19 miles.
Suppose that there are two types of tickets to a show: advance and same day. Advance tickets cost 30 and the same day tickets cost 20. For one performance there were 60 tickets sold in all and the total amount paid for them was $1600. How many tickets of each type were sold
Let A be the number of advance tickets sold and S be the total number of same-day tickets sold. The total amount of tickets is A+S, then:
[tex]A+S=60[/tex]The total earnings for A advanced tickets is 30A, while the total earnings for selling S same-day tickets is 20S. Then, the total amount of money for selling A advanced tickets and S same-day tickets, is 30A+20S, then:
[tex]30A+20S=1600[/tex]Solve the system of equations to find the total amount of tickets of each type that were sold. To do so, isolate A from the first equation and then substitute the resulting expression in the second one:
[tex]\begin{gathered} A+S=60 \\ \Rightarrow A=60-S \end{gathered}[/tex][tex]\begin{gathered} 30A+20S=1600 \\ \Rightarrow30(60-S)+20S=1600 \end{gathered}[/tex]Solve for S:
[tex]\begin{gathered} \Rightarrow1800-30S+20S=1600 \\ \Rightarrow1800-10S=1600 \\ \Rightarrow-10S=1600-1800 \\ \Rightarrow-10S=-200 \\ \Rightarrow S=-\frac{200}{-10} \\ \therefore S=20 \end{gathered}[/tex]Substitute S=20 into the expression for A:
[tex]\begin{gathered} A=60-S \\ =60-20 \\ =40 \end{gathered}[/tex]Then, the solution for this system is:
[tex]\begin{gathered} A=40 \\ S=20 \end{gathered}[/tex]If it costs $1.50 for a pack of Starbursts at ShopRite, how much will 5 packs cost?
Answer : $7.5
1 pack of starbursts cost $1.50 at shoprite.
How much will 5 packs cost
Let the cost in dollars of 5 packs of starbursts be x
1 pack will cost $1.50
5 packs will cost $x
Mathematically,
1 pack ---------------- $1.50
5 packs -------------= $x
Cross multiply
1 * x = 5 x 1.50
x = $7.5
Hence, 5 packs of starbursts would cost $7.5
Junior's brother is 1 1/2 meters tall. Junior is 1 2/5 of his brother's height. How tall is Junior? meters
To determine Junior's height you have to multiply Juniors height by multiplying 3/2 by 7/5his brother's height by 1 2/5.
To divide both fractions, first, you have to express the mixed numbers as improper fractions.
Brother's height: 1 1/2
-Divide the whole number by 1 to express it as a fraction and add 1/2
[tex]1\frac{1}{2}=\frac{1}{1}\cdot\frac{1}{2}[/tex]-Multiply the first fraction by 2 to express it using denominator 2, that way you will be able to add both fractions
[tex]\frac{1\cdot2}{1\cdot2}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}=\frac{2+1}{2}=\frac{3}{2}[/tex]Junior's fraction 1 2/5
-Divide the whole number by 1 to express it as a fraction and add 2/5
[tex]1\frac{2}{5}=\frac{1}{1}+\frac{2}{5}[/tex]-Multiply the first fraction by 5 to express it using the same denominator as 2/5, that way you will be able to add both fractions:
[tex]\frac{1\cdot5}{1\cdot5}+\frac{2}{5}=\frac{5}{5}+\frac{2}{5}=\frac{5+2}{5}=\frac{7}{5}[/tex]Now you can determine Junior's height by multiplying 3/2 by 7/5
[tex]\frac{3}{2}\cdot\frac{7}{5}=\frac{3\cdot7}{2\cdot5}=\frac{21}{10}[/tex]Junior's eight is 21/10 meters, you can express it as a mixed number:
[tex]\frac{21}{10}=2\frac{1}{10}[/tex]can you help me on the part 2 Heads in a Row:
Given:
Flipping a coin twice.
Required:
We need to find the likelihood of flipping heads twice in a row.
Explanation:
The sample space = All possible outcomes.
The sample space, S= {TT,TH,HT,HH}
[tex]n(S)=4[/tex]Let A be the event of flipping heads twice..
The favorable outcomes = flipping heads twice.
The favorable outcomes ={HH}
[tex]n(A)=1[/tex]Consider the probability formula.
[tex]P(A)=\frac{n(A)}{n(S)}[/tex][tex]P(A)=\frac{1}{4}[/tex][tex]P(A)=0.25[/tex]The probability of flipping heads twice in a row is 0.25 which is a close value to the number 0.
This event happens least likely.
Final answer:
Flipping heads twice in a row is the least likely.
The probability of flipping heads twice in a row is 0.25.
use the figure at the right . if JK=5x+23 and NO=29, what is the value of x?
From the triangle midpoint theroem,
[tex]\begin{gathered} NO=\frac{1}{2}JK \\ 29=\frac{1}{2}(5x+23) \\ 58=5x+23 \\ 58-23=5x \\ 35=5x \\ x=7 \end{gathered}[/tex]Which function has the greatest average rate of change on the interval [1,5]
Answer:
Explanation:
Given: interval [1,5]
Based on the given functions, we start by computing the function values at each endpoint of the interval.
For:
[tex]\begin{gathered} y=4x^2 \\ f(1)=4(1)^2 \\ =4 \\ f(5)=4(5)^2 \\ =100 \\ \end{gathered}[/tex]Now we compute the average rate of change.
[tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{100-4}{5-1} \\ \text{Calculate} \\ =24 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4x^3 \\ f(1)=4(1)^3 \\ =4 \\ f(5)=4(5)^3 \\ =500 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{500-4}{5-1} \\ =124 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4^x \\ f(1)=4^1 \\ =4 \\ f(5)=4^5 \\ =1024 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{1024-4}{5-1} \\ =255 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4\sqrt[]{x} \\ f(1)=4\sqrt[]{1} \\ =4 \\ f(5)\text{ = 4}\sqrt[]{5} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{(4\sqrt[]{5\text{ }})\text{ -4}}{5-1}\text{ } \\ =1.24 \end{gathered}[/tex]Therefore, the function that has the greatest average rate is
[tex]y=4^x[/tex]The area (in square inches) of a rectangle is given by the polynomial function A(b)=b^2 +9b+18. If the width of the rectangle is (b+3) inches what is the length?
As given by the question
There are given that area of rectangle and width of a rectangle
[tex]\begin{gathered} \text{Area}=A(b)=b^2+9b+18 \\ \text{Width}=(b+3) \end{gathered}[/tex]Now,
From the formula of area of a rectangle:
[tex]\text{Area}=\text{length}\times width[/tex]Then,
Put the value of an area and width into the above formula
So,
[tex]\begin{gathered} \text{Area}=\text{length}\times width \\ b^2+9b+18=length\times(b+3) \end{gathered}[/tex]Then,
[tex]\begin{gathered} b^2+9b+18=length\times(b+3) \\ (b+3)(b+6)=\text{length}\times(b+3) \\ \text{length}=\frac{(b+3)(b+6)}{(b+3)} \\ \text{length}=(b+6) \end{gathered}[/tex]Hence, the value of length is ( b + 6 ).
choose which group of sets the following number belongs to. Be sure to account for ALL sets. 2/7
A. Real numbers, rational numbers
Explanations:Note:
Real numbers are numbers that can be found on the number line. They include all rational and irrational numbers
Natural numbers are counting numbers. They include 0 and all whole numbers (1, 2, 3, ....)
Rational numbers are numbers that can be expressed as fractions of two integers. eg 2/3, 5/4, etc
Irrational numbers are numbers that cannot be expressed a s fractions of two integers. eg √7, π, etc
2/7 is a real number because it can be found on the number line, and is continuous
Also, 2/7 is a rational number because it is expressed as a fraction of two integers (2 and 7)
A triangular banner has an area 2000 square yards. Find the measures of the base and height of the triangle if the base is five-eighths of the height. What are the units of measurement.
ANSWER:
Height = 80 yds
Base = 50 yds
STEP-BY-STEP EXPLANATION:
Given:
Area = 2000 square yards
Height = h
Base = 5/8h
We can calculate the value of the height using the triangle area formula, just like this:
[tex]\begin{gathered} A=\frac{b\cdot h}{2} \\ \text{ We replacing} \\ 2000=\frac{h\cdot \frac{5}{8}h}{2} \\ h^2=\frac{2000\cdot2\cdot8}{5} \\ h=\sqrt{6400} \\ h=80\text{ yd} \\ \text{ therefore, the base is:} \\ b=\frac{5}{8}\cdot80 \\ b=50\text{ yd} \end{gathered}[/tex]Height = 80 yds
Base = 50 yds
The distance from the ground of a person riding on a Ferris wheel can be modeled by the equation d equals 20 times the sine of the quantity pi over 30 times t end quantity plus 10 comma where d represents the distance, in feet, of the person above the ground after t seconds. How long will it take for the Ferris wheel to make one revolution?
We have the function d, representing the distance from the ground of a person riding on a Ferris wheel:
[tex]d(t)=20\sin (\frac{\pi}{30}t)+10[/tex]If we consider the position of the person at t = 0, which is:
[tex]d(0)=20\sin (\frac{\pi}{30}\cdot0)+10=20\cdot0+10=10[/tex]This position, for t = 0, will be the same position as when the argument of the sine function is equal to 2π, which is equivalent to one cycle of the wheel. Then, we can find the value of t:
[tex]\begin{gathered} \sin (\frac{\pi}{30}t)=\sin (2\pi) \\ \frac{\pi}{30}\cdot t=2\pi \\ t=2\pi\cdot\frac{30}{\pi} \\ t=60 \end{gathered}[/tex]Then, the wheel will repeat its position after t = 60 seconds.
Answer: 60 seconds.
Alexa claims that the product of 2.3 and 10^2 is 0.23. Do you agree or disagree? Explain why or why not?
Answer:
disagree
Step-by-step explanation:
product = 2.3 * 10²
= 2.3 * 100
= 230
thus, the answer is different from the one acclaimed by Alexa.
hello i am haveing some trouble with ineqalles and can you help with this create a word problem that leads to an inequality by filling in the blanks with your corresponding answer.Twenty subtracted from the product of seven and a number exceeds one hundred.
Step 1
To change word problem to an inequality, you must take the word problem step by step and translate it into an inequality.
Step 2
Take the word problem step by step
[tex]\begin{gathered} \text{Twenty refers to the number }^{\prime}20^{\prime} \\ \text{Twenty subtracted from means 20 was removed from something.} \\ i.e\text{ say x-20} \end{gathered}[/tex][tex]\begin{gathered} \text{Twenty subtract}ed\text{ from the product of seven and a number } \\ \text{Product of seven and a number first} \\ Let\text{ the number be x} \\ so\text{ it now} \\ \text{Product of seven and x=7x } \end{gathered}[/tex][tex]\text{Twenty subtract}ed\text{ from the product of seven and a number}=7x-20[/tex]22The value of the hypotenuse in the right triangle shown isinches.14 in48 inFigure not drawn to scale
SOL
Step 1 :
In this question, we are meant to find the value of
the hypotenuse in the right angle below:
Before, we proceed, we still need to remind ourselves of Pythagoras' theorem,
Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“.
Step 2 :
From the above theorem, we can see that that the two adjacent sides are :
14 inches and 48 inches.
From the principle of Pythagoras' Theorem,
[tex]\begin{gathered} c^2=a^2+b^2 \\ \text{where a = 14 inches} \\ b\text{ = 48 inches} \\ c^2=14^2+48^2 \\ c^2\text{ = ( 14 x 14 ) + ( 48 x 48 )} \\ c^2\text{ = 196 + 2304} \\ c^2\text{ = 2500} \\ \text{square root both sides, we have that :} \\ c\text{ = 50 inches} \end{gathered}[/tex]
CONCLUSION :
The value of the hypotenuse in the Right angle, c = 50 inches.
A cake is cut into 12 equal slices. After 3 days Jake has eaten 5 slices. What is his weekly rate of eating the cake?
5
36
35
36
cakes/week
cakes/week
1
1 cakes/week
35
01. cakes/week
4
Answer:
11.2 Slices / Week
Step-by-step explanation:
We know that Jake has eaten 5 slices of cake in 3 days. You can divide 5 / 3 to get an average of 1.6 slices of cake being eaten per day. The question asks what the weekly rate or eating the cake will be, do you need to multiple 1.6 x 7 for the total amount of cake eaten per week, which is 11.2 slices!
Answer:
11.6
explanation
we have 7 days.
7days-3days =4
in 3 days he has eaten 5 slices
again 4-3 days=1
so in 6 days he has eaten 10 slices
we have 1 day left.so if he eats 5 slices in 3 day,how many he eat slices in 1 day?5/3=1.6
10+1.6=11.6
Jenny borrowed $8000 at a rate of 9%, compounded semiannually. Assuming she makes no payments, how much will she owe after 10Do not round any intermediate computations, and round your answer to the nearest cent.
SOLUTION
We will use the formula
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ where\text{ } \\ A=amount\text{ after 10 years = ?} \\ P=money\text{ borrowed = \$8,000} \\ r=9\%=\frac{9}{100}=0.09 \\ t=time\text{ in years = 10} \\ n=compounding=semi-annualy=2 \end{gathered}[/tex]plugging in, we have
[tex]\begin{gathered} A=8,000(1+\frac{0.09}{2})^{2\times10} \\ A=8,000(1.045)^{20} \\ A=8,000\times2.4117140 \\ A=19,293.7121986 \end{gathered}[/tex]Hence the answer is $19,293.71
I would like to ask for Some help on this equation please?
ABC is a right triangle
AB is perpendicular to BC
If 2 lines are perpendicular, the product of slopes is -1
m1 x m2 = -1
mAB x mBC = -1
mAB = -1 / mBC
mAB = -1 / (1/2)
mAB = -2
many solutions can be found for the system of linear equations represented on the graph?A. no solution B. one solution C. two solution D. Infinity many solutions
The lines are not intersecting. The system of linear equations has a solution only if the lines corresponding to the equations intersect.
The general linear equation is,
y=mx+c, where m is the slope.
The slopes of lines m=2.
Since the graphs are parallel or have the same slope and will never intersect, the system of linear equations have no solution.
can you solve for x and y y=4x-11=x+13
x = 8, y = 21
Explanations:The given equation is:
y = 4x - 11 = x + 13
This can be splitted into two equations as:
y = 4x - 11..........(1)
y = x + 13..........(2)
Substitute equation (1) into equation (2)
4x - 11 = x + 13
4x - x = 13 + 11
3x = 24
x = 24/3
x = 8
Substitute the value of x into equation (1)
y = 4x - 11
y = 4(8) - 11
y = 32 - 11
y = 21
x = 8, y = 21
I have a calculus question about related rates, pic included
ANSWER
40807 cm³/min
EXPLANATION
The tank has the shape of a cone, with a total height of 9 meters and a diameter of 3.5 m - so the radius, which is half the diameter, is 1.75 m. As we can see, the relationship between the height of the cone and the radius is,
[tex]\frac{r}{h}=\frac{1.75m}{9m}=\frac{7}{36}\Rightarrow r=\frac{7}{36}h[/tex]So the volume of water will be given by,
[tex]V(h)=\frac{1}{3}(\pi r^2)h=\frac{1}{3}\cdot\pi\cdot\frac{7^2}{36^2}h^2\cdot h=\frac{49\pi}{3888}h^3[/tex]Where h is the height of the water (not the tank).
If we derive this equation, we will find the rate at which the volume of water is changing with time,
[tex]\frac{dV}{dt}=\frac{49\pi}{3888}\cdot3h^{3-1}=\frac{49\pi}{3888}\cdot3h^2=\frac{49\pi}{1296}h^2[/tex]We want to know what is the change of volume with respect to time, and this is,
[tex]\frac{dV}{dt}=\frac{dV}{dt}\cdot\frac{dh}{dt}[/tex]Because the height also changes with time. We know that this change is 24 cm per minute when the height of the water in the tank is 1 meter (or 100 cm), so we have,
[tex]\frac{dV}{dt}=\frac{49\pi}{1296}h^2\cdot\frac{dh}{dt}=\frac{49\pi}{1296}\cdot100^2cm^2\cdot\frac{24cm}{1min}\approx28507cm^3/min[/tex]This is the rate at which the water is increasing in the tank. However, we know that there is a leak at a rate of 12300 cm³/min, which means that in fact the water is being pumped into the tank at a rate of,
[tex]28507cm^3/min+12300cm^3/min=40807cm^3/min[/tex]Hence, the water is being pumped into the tank at a rate of 40807 cm³/min, rounded to the nearest whole cm³/min.
Miguel has 225 base ball cards. He plans to keep 75 cards and give the rest to his friends.Can Miguel give an equal number of cards to 6 friends? Explain.
We know what Miguel has 225 baseball cards, and he plans on keeping 75, while giving them the rest of them to his friends. We want to know if he can give an equal number to 6 of his friends.
For this objective, we know what he will have to give to his friends an amount of:
[tex]undefined[/tex]10. The graph shows the scores of an exam. About what percent of students scored above 86%?Distribution of Exam Scores20Percent1078808286889084Score11%18%6.5%
Answer
Option B is correct.
Percent of students that scored above 86% = 18%
Explanation
To find the percentage of students that scored above 86%, we will need to add the percent of the bars for all the scores greater than 86%.
For 87%, the bar is 8%
For 88%, the bar is 5.8%
For 89%, the bar is 2.2%
For 90%, the bar is 2%
So,
Percent of students that scored above 86% = 8 + 5.8 + 2.2 + 2 = 18%
Hope this Helps!!!
Which is a way to model 9485 with base ten blocks
The most appropriate way to model 9485 with the base ten blocks is
9 - thousand, 4 - hundred, 8- ten, and 5 - once.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,
Base ten block implies the number of blocks according to the digit representation,
For the given question,
The number represents there are 9485 cubes, which can be represented as 9 - thousand, 4 - hundred, 8- ten, and 5 - once.
Thus, the most appropriate way to model 9485 with the base ten blocks is 9 - thousand, 4 - hundred, 8- ten, and 5 - once.
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Prof. Glatt likes 2% milk (2% fat) for her cereal in the morning. Her parents only buy wholemilk (3.5% fat) and non-fat milk (0% fat). While she is visiting her parents, how much of eachtype of milk does she need to mix to get 3 cups of 2% milk. The answer can be rounded to thenearest tenth.linear systems solving algebraically
It is given that there are two types of milk.
One is 3.5% and one is 0%.
Let the number of cups of 3.5% milk be x and the number of cups of 0% milk used be y.
The total should be 3 cups so it follows:
[tex]x+y=3\ldots(i)[/tex]It is also known that the resulting milk is 2% so it follows:
[tex]\begin{gathered} \frac{3.5}{100}x+\frac{0}{100}y=\frac{2}{100}(x+y) \\ \frac{3.5}{100}x=\frac{2}{100}(x+y) \end{gathered}[/tex]Multiply by 100 on both sides to get:
[tex]\begin{gathered} 3.5x=2(x+y) \\ 3.5x=2x+2y \\ 1.5x=2y \\ x=\frac{2}{1.5}y \\ x=\frac{2\times2}{1.5\times2}y \\ x=\frac{4}{3}y \end{gathered}[/tex]Substitute the value of (ii) in (i) to get:
[tex]\begin{gathered} x+y=3 \\ \frac{4}{3}y+y=3 \\ \frac{4+3}{3}y=3 \\ \frac{7}{3}y=3 \\ \frac{3}{7}\times\frac{7}{3}y=\frac{3}{7}\times3 \\ y=\frac{9}{7} \end{gathered}[/tex]Hence the quantity of 0% milk is 9/7 cups.
The quantity of 3.5% milk is given by:
[tex]\begin{gathered} x=\frac{4}{3}y \\ x=\frac{4}{3}\times\frac{9}{7} \\ x=\frac{12}{7} \end{gathered}[/tex]Hence the quantity of 3.5% milk is 12/7 cups.
For a science project, Sammy observed a chipmunk and a squirrel stashing acorns in holes. The chipmunk hid 3 acorns in each of the holes it dug. The squirrel hid 4 acorns in each of the holes it dug. They each hid the same number of acorns, although the squirrel needed 4 fewer holes. How many acorns did the chumpkin hide
Let x and y be the number of holes dug by the chipmunk and the squirrel, respectively.
Therefore, the number of hidden acorns by each animal is given by the equations below
[tex]\begin{gathered} a_{chipmunk}=3x \\ a_{squirrel}=4y \end{gathered}[/tex]On the other hand, since the squirrel needed 4 fewer holes, and the number of hidden acorns is the same
[tex]\begin{gathered} y=x-4 \\ and \\ a_{chipmunk}=a_{squirrel} \end{gathered}[/tex]Thus,
[tex]\begin{gathered} \Rightarrow3x=4y \\ \Rightarrow3x=4(x-4) \\ \Rightarrow3x=4x-16 \\ \Rightarrow x=16 \end{gathered}[/tex]Hence,
[tex]\Rightarrow16*3=48[/tex]The chipmunk hid 48 acorns.write three things you used to do but don't do anymore
Answer:
Trusting peoples
Be happy
make friends
what are the reasons ? and is there anymore statements
The first reason is GIVEN
If angles ∠XWY and ∠RTU are supplemetary, it means they add up 180°. It demands that lines It demands that lines It demands that
What is the volume of a hemisphere with a radius of 6.5 in, rounded to the nearesttenth of a cubic inch?
To calculate the volum of a hemisphere
We use the formula;
V = (2/3)πr³
where r = radius
π is a constant equal 3.14
r= 6.5 in and π = 3.14
Substituting into the formula
V = (2/3) x 3.14 x (6.5)³
Evauluate
V = (2/3) x 3.14 x 274.625
V = (2/3) x 862.3225
V=574.8816666666667
V= 574.89 in³ to the nearest tenth of a cubic inch.
