Answer:
[tex]0.75623\ \text{kN/m}[/tex]
[tex]55.6\ \text{cm}[/tex]
Explanation:
m = Mass of object = 7.94 kg
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
x = Change in length of the spring = [tex](42.4-32.1)\ \text{cm}[/tex]
F = Force on the spring
Force of gravity on the object and the force on the spring will be equal
[tex]mg=kx\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{7.94\times 9.81}{0.424-0.321}\\\Rightarrow k=756.23\ \text{N/m}[/tex]
The spring constant is [tex]756.23\ \text{N/m}=0.75623\ \text{kN/m}[/tex]
F = 178 N
Force on spring is given by
[tex]F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{178}{756.23}\\\Rightarrow x=0.235\ \text{m}=23.5\ \text{cm}[/tex]
The length of the spring will be [tex]32.1+23.5=55.6\ \text{cm}[/tex].
Help me and get points
What is the correct answer
Consider a bowl shapes like a cycloid. Show that the oscillation period of a marble released at any point in the bowl is always the same, irrespectively from how far the release point is from the bottom of the bowl. In particular prove that the oscillation period is:________.
What is the rms current flowing through a light bulb that uses an average power of 30.0 W when it is plugged into a wall receptacle supplying an rms voltage of 240.0 V
Answer:
0.125 A
Explanation:
From the question given above, the following data were obtained:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
The power in an electric circuit is given by the following equation:
Power (P) = current (I) × voltage (V)
With the above formula, we can obtain the rms current flowing through the bulb as shown below:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
P = Irms × Vrms
30 = Irms × 240
Divide both side by 240
Irms = 30 / 240
Irms = 0.125 A
Thus, the rms current flowing through the light bulb is 0.125 A
Which example is most likely made from both metals and gemstones?
Answer:
A Necklace is most likely made from both metals and gemstones
Explanation:
Brainliest?
Fix this problem, please.
Answer:
The correct option is (a).
Explanation:
Given that,
Radius of a horizontal circle, r = 80 cm = 0.8 m
Angular velocity, ω = 5 rev/minute = 0.523 rad/s
We need to find the magnitude of its centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :
[tex]a=\omega^2 r\\\\a=(0.523)^2\times 0.8\\\\a=0.218\ m/s^2[/tex]
or
[tex]a=0.22\ m/s^2[/tex]
So, the magnitude of its acceleration is [tex]0.22\ m/s^2[/tex].
What is the wavelength of a wave traveling at 300 m/s if the frequency is 10 Hz?
Answer:
30 m
Explanation:
The wavelength of a wave is found by the velocity divided by the frequency. Therefore, the wavelength is (300 m/s)/(10 Hz) = 30 m
I hope this helps! :)
A sports car accelerates from 0 to 25 meters per second in 4 seconds. What is its acceleration?
Question 1 options:
10ms2
6.25 ms2
25ms
0ms
20pts
Answer:
6.25 ms²
Explanation:
..................
Help! Don’t say the wrong answer please!!
Jamal is playing with magnetic toy vehicles. He has two identical magnetic vehicles (purple and green) on different sides of a center magnet that cannot move. His friend Simone challenges him to move one vehicle one space to the left or the right in order to get the largest increase in potential energy. That means Jamal can move the purple car to point A or point B, or he can move the green car to point C or point D.Explain which movement Jamal should make (which car and which point), and why that movement will result in the largest increase in potential energy. Describe the magnetic force that will act on the vehicle he moves.
Answer:
I think he should move the purple car to the right. good luck
A car is being driven down a level track with no net force on it. This motion is best described as
A)Linear motion
B)circular motion
C) periodic motion
D) projectile motion
A)Linear motion
If there is not net force on the car, then by the Newton Second Law, the acceleration is zero, and the only valid option for zero acceleration is A).
turns into _____ energy (when plants convert into food)
Answer:
the answer is PHOTOSYNTHESIS..
Explanation:
photosynthesis is the process when plants make their food from taking energy from the sun creating sugar.
How does an electric motor use magnetic force to produce motion?
The north pole of a permanent magnet placed in the center of an electromagnet attracts the north pole of the electromagnet.
The north pole of an electromagnet placed in the center of a permanent magnet attracts the north pole of the permanent magnet.
The north pole of a permanent magnet placed in the center of an electromagnet repels the north pole of the electromagnet.
The north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet.
Answer:
The north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet.
Explanation:
The commutator of the electric motor reverses the current in each half revolution to keep the torque, turning the coil in the same direction. This occurs as the north pole of the electromagnet nears the south pole of the permanent magnet, and the current reverses, which causes the poles of the magnets to repel.
Thus, the correct answer is "the north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet".
Answer:
The answer is D
Explanation:
Just took the test on Edge :)
A 0.950 kg block is attached to a spring with spring constant 16 N/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 49 cm/s. What are:________
a. The amplitude of the subsequent oscillations?
b. The block's speed at the point where x=1/2A
Answer:
A)0.1m
B)vf= 35cm/s
Explanation:
A gasoline engine absorbs 2 500 J of heat and performs 1 000 J of mechanical work in each cycle. The efficiency of the engine is:
Answer:
The efficiency of the engine is 40 %
Explanation:
Given;
input energy, = 2500 J
output energy, = 1000 J
The efficiency of the engine is given as;
Efficiency = output energy / input energy
Efficiency = 1000 / 2500
Efficiency = 0.4
Efficiency(%) = 0.4 x 100%
Efficiency = 40 %
Therefore, the efficiency of the engine is 40 %
The efficiency of Engine is 40%.
Given data:
The amount of heat absorbed by gasoline engine is, Q = 2500 J.
The mechanical work performed by Engine is, W = 1000 J.
The tendency to do work is often rated and measured using the concept of efficiency of Engine. It is expressed as the ratio of work obtained and amount of heat supply. So, the expression for the efficiency of Engine is given as,
[tex]\eta = \dfrac{W}{Q}[/tex]
Solving as,
[tex]\eta = \dfrac{1000}{2500}\\\\\eta =0.4\\\\\eta = 0.4 \times 100\\\\\eta =40 \%[/tex]
Thus, we can conclude that the efficiency of Engine is 40%.
Learn more about the Efficiency of Engine here:
https://brainly.com/question/24244446
PLEASE ANSWER! A sound Wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with a speed of 340 m/s. Approximately how many times larger is the wavelength in water than in air?
Answer:
ok
Explanation:
12345-7543
If mass increases, how does force need to change in order to achieve the
same change in motion?
Explanation:
states that the acceleration of an object increases with increased force and decreases with increased mass. The law also states that the direction in which an object accelerates is the same as the direction of the force.
An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of 2.70 x 10^-3 V/m and is parallel to the x axis. What are the frequency and the magnetic-field amplitude of this wave? In calculating the amplitude of the magnetic field, you divide the electric-field amplitude by the speed of light, which requires you to convert some units. Which of the following is equivalent to 1 T?
a. 1 (N/A.m)
b. 1 (N/c.m)
c. 1 (N.s/C.m)
d. 1 (V.s/m^2)
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
Given that
The wavelength of the wave, λ = 435 nm
Amplitude of the electric field, E(max) = 2.7*10^-3 V/m
a)
The frequency of the wave can be found by using the formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b)
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c)
1T = 1 (V.s/m^2)
I would like to know why this is the correct answer.
-The same net force is applied to two bodies. The first body acquires half of the acceleration of the second body. What is the relationship between the masses of the bodies?
*The mass of the first body is double the mass of the second body
Answer:
The mass of first body is double, since mass is double.
This is due to momentum
The same net force is applied to two bodies. The first body acquires half of the acceleration of the second body. The mass of first body is double, since mass is double.
What is momentum?In Newtonian physics, an object's mass and velocity are combined to form momentum, more precisely linear momentum and translational momentum. It has both a magnitude as well as a trajectory, making it a vector quantity. If an item has a mass of m and a velocity of v (also a vector quantity).
The kilogram metre per second (kg m/s), or newton-second inside the International System of Units (SI), is the unit used to measure momentum. The same net force is applied to two bodies. The first body acquires half of the acceleration of the second body. The mass of first body is double, since mass is double.
Therefore, the mass of first body is double, since mass is double.
To know more about momentum, here:
https://brainly.com/question/29598011
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A proton is confined within an atomic nucleus of diameter 3.80 fm (1fm=10^−15m). Estimate the smallest range of speeds you might find for a proton in the nucleus.
Answer:
0m/s to 8.29×20^6m/s
Explanation:
The proton is confined in 3.80 fm
then the maximum uncertainty is
Δx=3.810^−15m
Uncertainty principle can be expressed as
Δp. Δx ⩾ h/4π ...........eqn(1)
Δp ⩾ h/4π.Δx
p= mv which is the uncertainty in momentum
m.Δv ⩾ h/4π.Δx
We can also express it in term of velocity as
Δv= h/4πmΔx .............eqn(2)
m=Mass of proton= 1.673 × 10^-27 kilograms
h= Plank's constant= 6.626 × 10^-34kilograms
Δv= uncertainty in speed
If we input the values into eqn(2) we have
Δv=6.626 × 10^-34/(4π× 1.673 × 10^-27 × 3.8×10^−15)
Δv=8.29×20^6m/s
Hence, the smallest range of speeds you might find for a proton in the nucleus is 0<v<8.29×20^6m/s
BRAINLEST TO SOMEONE WHO ACTUALLY ANSWERS AND FREE 100 POINTS TO REAL ANSWER 2. Using the average time, calculate the oscillation period, or the time it took for one oscillation. Fill the averages into the orange cells in the data table. (2 points)
a. Reminder: the times in the data table are for five oscillations. The period of a pendulum is equal to one oscillation (one back and forth). So, divide the average time by five to get the time for
one oscillation.
Answer:
IM SO SORRY :((
Explanation:
A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy potential store
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Suppose a square wave signal has a 65 percent duty cycle and an on-state voltage of 40 volts DC. What is the average DC voltage
Answer:
The voltage is [tex]\= DC _v = 2.6 \ V[/tex]
Explanation:
From the question we are told that
The duty cycle is p = 65% = 0.65
The on - state voltage is [tex]V = 40 \ volt[/tex]
Generally the average DC voltage is mathematically represented as
[tex]\= DC _v = p * V[/tex]
=> [tex]\= DC _v = 40 * 0.65[/tex]
=> [tex]\= DC _v = 2.6 \ V[/tex]
PLEASE HELP its due today
On a flat field, a ball is kicked and given an initial velocity of 28 m/s at an angle of 20 degrees above the horizontal.
a) What are the x and y components of the ball’s initial velocity?
b)From the moment it is kicked, how long will it take for the ball to reach its maximum height?
c)What is the maximum height of the ball?
d) Find the horizontal distance between the point at which the ball was kicked and the point where it lands.
Answer:
1. far
2. a couple of seconds
3. a mile or so
Explanation:
How might a location's altitude influence it's climate?
Answer:
You will discover that at high altitude, there is cold and the opposite is experienced when you go deep down the sea. However, the reason elevation affects climate and temperature gets colder is this. As you go higher up, the atmosphere experiences less pressure.
Explanation:
2. Which biome has many grasses and few trees due to fires, drought, and grazing?
(6 Points)
a. Temperate deciduous forest
b. Tropical rainforest.
c Temperate grasslands
d. Tundra
Answer:
C. Temperate grasslands
I would like to know why this is the correct answer
-Two rockets with the same mass are accelerated. Rocket A accelerates twice as quickly as rocket B. Which statement is correct?
*The motor in rocket A is twice as powerful as the motor in rocket B.
Answer:
Yah, the powerful the motor is, the greater the velocity.
Since velocity is directly proportional to momentum, rocket A will have a greater magnitude of momentum than rocket B.
In accordance to Newton's second law of motion, momentum accounts for acceleration force hence rocket A will have a greater force of acceleration than rocket B
How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water
Answer:
the velocity of the water flow is 7.92 m/s
Explanation:
The computation of the velocity of the water flow is as follows
Here we use the Bernouli equation
As we know that
[tex]V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)} \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}[/tex]
= 7.92 m/s
Hence, the velocity of the water flow is 7.92 m/s
We simply applied the above formula so that the correct value could come
And, the same is to be considered
how do magnetic keepers stop demagnetization
Answer:
Keepers also have a useful safety function, as they stop external metal being attracted to the magnet. ... A keeper for low-coercivity magnets is just a strong permanent magnet that keeps all the domains pointing the same way and realigns those that may have gone astray.
An object of volume 7.50×10−4m3 and density 1.15×103kg/m3 is completely submerged in a fluid. Calculate the weight of this object.
Answer:
The weight of this object is 8.45 N.
Explanation:
Given;
volume of the object, V = 7.5 x 10⁻⁴ m³
density of the object, ρ = 1.15 x 10³ kg/m³
The mass of the object is given as;
mass = density x volume
m = ρV
m = (1.15 x 10³)(7.5 x 10⁻⁴ )
m = 0.8625 kg
The weight of the object is given as;
w = mg
where;
g is acceleration due to gravity = 9.8 m/s²
w = 0.8625 x 9.8
w = 8.45 N
Therefore, the weight of this object is 8.45 N.
It takes 10 lb of force to stretch a spring 2 in. What is the stiffness (spring constant) of the spring
Answer:
875.59 N/m
Explanation:
From the question given above, the following data were obtained:
Force (F) = 10 lb
Extention (e) = 2 in
Spring constant (K) =?
Next, we shall convert 10 lb to Newton (N). This can be obtained as follow:
1 lb = 4.448 N
Therefore,
10 lb = 10 lb × 4.448 N / 1 lb
10 lb = 44.48 N
Thus, 10 lb is equivalent to 44.48 N
Next, we shall convert 2 in to metre (m). This can be obtained as follow:
1 in = 0.0254 m
Therefore,
2 in = 2 in × 0.0254 m / 1 in
2 in = 0.0508 m
Thus, 2 in is equivalent to 0.0508 m.
Finally, we shall determine the spring constant i.e the stiffness of the spring as follow:
Force (F) = 44.48 N
Extention (e) = 0.0508 m.
Spring constant (K) =?
F = Ke
44.48 = K × 0.0508
Divide both side by 0.0508
K = 44.48 / 0.0508
K = 875.59 N/m
Therefore the spring constant i.e the stiffness of the spring is 875.59 N/m
A horizontal clothesline is tied between 2 poles, 20 meters apart. When a mass of 2 kilograms is tied to the middle of the clothesline, it sags a distance of 5 meters. What is the magnitude of the tension on the ends of the clothesline
Answer:
[tex]T =99.94[/tex]
Explanation:
From the question we are told that
The distance between the poles is [tex]d = 20 \ m[/tex]
The mass is [tex]m = 2 \ kg[/tex]
The sag distance [tex]=5m[/tex]
Generally the tension in the rope is mathematically represented as as
[tex]T =\frac{mg}{2sin(\theta)}[/tex]
where [tex]\theta =arctan(\frac{1}{5})[/tex]
[tex]T =\frac{m*9.8}{2sin(tan^-1(\frac{1}{5})}\\[/tex]
[tex]T =99.94[/tex]
the tension on the line is 99.94
