Answer:
How Can You Earn Your GED?
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. ...You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass).>Rules
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. You should also meet state eligibility requirements for the amount of time you've been out of high school. In some states, you have to be out of high school for at least 60 consecutive days before you're allowed to take the test. Contact the program administrator in your state for more details.
You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass). Scores range from 100 to 200 on the 2014 version). A score of 165 on each test is the benchmark for college and career readiness, and you will receive an Honors distinction if you reach this score. The four tests take seven and a half hours total and are administered by computer. You don't have to take them all on the same day, but some states enforce specific time frames for completing the tests. Most questions are multiple choice, although there is also a mix of fill-in-the-blank, drag and drop, and select-an-area questions, as well as an essay question on the Reasoning Through Language Arts section.
If you don't pass a test the first time around, you can retake it, although different states have different requirements for people who need to retake GED tests (such as additional fees or proof of attending a preparation class). Testing accommodations are available for those with disabilities; you can sign up for them through your online account after you register. You usually have to pay to sign up for the tests, but the cost varies from state to state. After you take each test, you will receive your scores within 24 hours. Here are some more details about the score report.
Explanation:
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A scientist uses electricity to break down water into hydrogen gas and oxygen
gas. Which statement best explains what happens?
A. A chemical change occurs.
B. A base neutralizes an acid.
C. An acid neutralizes a base.
D. A physical change occurs.
Answer: A chemical change occurs.
Explanation:
A. A chemical change occurs.
B. A base neutralizes an acid.
C. An acid neutralizes a base.
D. A physical change occurs.
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision. What is the final velocity of the two combined vehicles?
Answer:
v₃ = 3.33 [m/s]
Explanation:
This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.
In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.
[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]
where:
m₁ = mass of the car = 1000 [kg]
v₁ = velocity of the car = 10 [m/s]
m₂ = mass of the truck = 2000 [kg]
v₂ = velocity of the truck = 0 (stationary)
v₃ = velocity of the two vehicles after the collision [m/s].
Now replacing:
[tex](1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s][/tex]
What is the least number of forces required to stretch a spring?
Answer:
The least number of forces required to stretch a spring is one.
Explanation:
Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:
[tex]F \propto x[/tex] (1)
[tex]F = k\cdot x[/tex] (2)
Where:
[tex]F[/tex] - Net external force, measured in newtons.
[tex]k[/tex] - Spring constant, measured in newtons per meter.
[tex]x[/tex] - Deformation of spring, measured in meters.
Hence, the least number of forces required to stretch a spring is one.
An ant is following a circular pheromone trail. The ant takes 14 s to complete one ‘lap’ and is moving at a speed of 8.5 cm s−1.
What is the radius of the pheromone trail?
What is the angular velocity of the ant?
Explanation:
hold I will tell u the answer 1 sec
If you sprain an ankle your most likely to injure a *
A) patella
B) ligament
C) ACL
D) cardiac muscle
A uniform ladder whose length is 5.2 m and whose weight is 400 N leans against a frictionless vertical wall. The coefficient of static friction between the level ground and the foot of the ladder is 0.35. What is the greatest distance the foot of the ladder can be placed from the base of the wall without the ladder immediately slipping
Answer:
the greatest distance the foot of the ladder can be placed from the base of the wall without the ladder immediately slipping is 3.3424 m
Explanation:
Given the data in the question and as illustrated in the images below;
without the ladder immediately slipping, the net torque and the net force mus all balance out.
from the first image;
In the x, the force is;
[tex]F_{f}[/tex] = N₂
mg = N₁
the torque about the ground contact point gives the following equation
N₂Lsin∅ = mgcos∅[tex]\frac{L}{2}[/tex]
solving for ∅
tan∅ = mg / 2N₂ 55
∅ = tan⁻¹ ( mg / 2N₂ )
we already know that N₂ = [tex]F_{f}[/tex] = μN₁ = μmg
so,
∅ = tan⁻¹ ( mg / 2μmg )
∅ = tan⁻¹ ( 1 / 2μ )
given that; The coefficient of static friction between the level ground and the foot of the ladder μ = 0.35
we substitute
∅ = tan⁻¹ ( 1 / (2×0.35 ) )
∅ = tan⁻¹ ( 1.42857 )
∅ = 55°
now to get the required distance;
from the second image; cos∅ = d / L
d = Lcos∅
given that; length of the ladder = 5.2 m
we substitute
d = 5.2cos(50)
d = 3.3424 m
Therefore, the greatest distance the foot of the ladder can be placed from the base of the wall without the ladder immediately slipping is 3.3424 m
A soccer ball, mass 3 kg, is kicked straight up with a velocity of 25 m/s. How high will the ball travel?
Answer:
h = 31.9 m
Explanation:
When the ball travels from the ground to the highest point, its kinetic energy is converted into potential energy. So by the law of conservation of energy:
[tex]Kinetic\ Energy\ Lost\ by\ ball = Potential\ Energy\ gained\ by\ ball\\\frac{1}{2}mv^{2} = mgh\\\\h = \frac{v^{2}}{2g}[/tex]
where,
h = height gained by ball = ?
v = speed of ball = 25 m/s
g = acceleration due to gravity = 9.8 m/s²
Therefore,
[tex]h = \frac{(25\ m/s)^{2}}{2(9.8\ m/s^{2})}[/tex]
h = 31.9 m
How long has a victim been dead if his body temperature was 89.2°F?
Please help me......
U
going o pri
7.) True or False: "Courtney is traveled 5 miles in 3 hours" is an example of
acceleration.
True
False
Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger D has a mass 4m and a speed v/2. Rank the joggers in order of increasing kinetic energy. Indicate ties when appropriate. Show your work.
Answer: B>A=D>C
Explanation:
Kinetic Energy is the product of mass and square of the velocity
For Jogger A
[tex]K.E._a=\frac{1}{2}mv^2[/tex]
For Jogger B
[tex]K.E._b=\frac{1}{2}\times\frac{m}{2}\times(3v)^2=\frac{9}{4}mv^2\\K.E._b=2.25mv^2[/tex]
For Jogger C
[tex]K.E._c=\frac{1}{2}\times3m\times(\frac{v}{2})^2=\frac{3}{8}mv^2\\K.E._c=0.375mv^2[/tex]
For Jogger D
[tex]K.E._d=\frac{1}{2}\times4m\times(\frac{v}{2})^2=\frac{1}{2}mv^2[/tex]
Kinetic Energy of Joggers in increasing order
B>A=D>C
What are two reasons digital storage of data is more secure than analog storage?
A.
A computer program can be used to encode digital data.
B.
A fingerprint can be used to control access to digital data.
C.
A computer program can easily change digital data.
D.
A stronger password is needed to access digital data.
Digital storage of data is more secure than analog storage because a stronger password is needed to access digital data and fingerprint can be used to control access to digital data.
What is analog device storage?Content that employs a technique in which data is represented by continuously varying physical quantities is known as analog device storage
In paper,cave,microfilm is the best example of analog data storage.
Digital storage of data is more secure than analog storage;
B. A fingerprint can be used to control access to digital data.
D. A stronger password is needed to access digital data.
To learn more about analog device storage, refer to the link;
brainly.com/question/11599772
#SPJ2
Answer: A, B
Explanation: did the test
A small block of mass m slides on a horizontal surface where friction between the block and the surface is negligible as it travels around the inside wall of a hoop of radius R. The coefficient of friction between the block and the wall is μk. The block is given an initial speed vo tangent to the hoop and allowed to travel along the inside edge. The velocity of the block at time is:_____
Answer:
v = v_o/(1 + (tv_o(μ_k)/R))
Explanation:
We are told that the coefficient of friction between the block and the wall is μ_k.
Now, formula for the frictional force will be;
F_fric = -μ_k × mv²/R
mv²/r is used because it is a centripetal motion.
Now, we know that F = ma = m(dv/dt)
Thus;
m(dv/dt) = -μ_k × mv²/R
m will cancel out to give;
dv/dt = -μ_k × v²/R
Rearranging to get;
dv/v² = -μ_k × (1/r)dt
We are told the initial velocity is v_o.
Thus, let the final velocity be v.
The initial time is 0 and thus the final time will be represented by t.
Thus;
(v,v_o)∫dv/v² = (t, 0)∫-μ_k × (1/R)dt
Integrating this we have;
-1/v - (-1/v_o) = -((μ_k)/R) × (t - 0)
-(1/v) + (1/v_o) = -t(μ_k)/R
Rearranging to get;
1/v = (1/v_o) + t(μ_k)/R
Simplifying the right hand side gives;
[R + tv_o(μ_k)]/Rv_o
Thus;
1/v = [R + tv_o(μ_k)]/Rv_o
v = Rv_o/[R + tv_o(μ_k)]
Simplifying further gives;
v = v_o/(1 + (tv_o(μ_k)/R))
A boy is looking into a plane mirror. His nose is 30 cm in front of the mirror.
How far is his nose from where its image appears to be?
HELP I NEED TO SUBMIT MY SCIENCE HW IN LIKE 30 MINS!!!
Answer:
Hug g g fed gvgcgcgcg
Explanation:
G gcgvhcvkgj
The acceleration of a particle is constant. At t = 0, the particle is at the origin and the velocity of the particle is vo = vji+ v2j. At time t = T, the velocity of the particle is v = v3j. Here v1, v2, and v3 are constants with dimensions of length divided by time. All answers should be written in terms of vj, v2, V3, T, and the unit vectors i and j.
Part (a) What is the particle's acceleration vector?
Part (b) What is the particle's position vector at t= 2T?
Part (c) What is the particle's velocity vector at t =2T?
Answer:
a) a = [tex]- \frac{v_1}{T}[/tex] i ^ +[tex]\frac{v_3 - v_2}{T}[/tex] j^, b) r = 2 v₃ T j ^, c) v = -v₁ i ^ + (2 v₃ - v₂) j ^
Explanation:
This is a two-dimensional kinematics problem
a) Let's find the acceleration of the body, for this let's use a Cartesian coordinate system
X axis
initial velocity v₀ₓ = v₁ for t = 0, velocity reaches vₓ = 0 for t = T, let's use
vₓ = v₀ₓ + aₓ t
we substitute
for t = T
0 = v₁ + aₓ T
aₓ = - v₁ / T
y axis
the initial velocity is [tex]v_{oy}[/tex] = v₂ at t = 0 s, for time t = T s the velocity is v_{y} = v₃
v₃ = v₂ + a_{y} T
a_{y} = [tex]\frac{v_3 - v_2}{T}[/tex]
therefore the acceleration vector is
a = [tex]- \frac{v_1}{T}[/tex] i ^ +[tex]\frac{v_3 - v_2}{T}[/tex] j^
b) the position vector at t = 2T, we work on each axis
X axis
x = v₀ₓ t + ½ aₓ t²
we substitute
x = v₁ 2T + ½ (-v₁ / T) (2T)²
x = 2v₁ T - 2 v₁ T
x = 0
Y axis
y = [tex]v_{oy}[/tex] t + ½ a_{y} t²
y = v₂ 2T + ½ [tex]\frac{v_3 - v_2}{T}[/tex] 4T²
y = 2 v₂ T + 2 (v₃ -v₂) T
y = 2 v₃ T
the position vector is
r = 2 v₃ T j ^
c) the velocity vector for t = 2T
X axis
vₓ = v₀ₓ + aₓ t
we substitute
vₓ = v₁ - [tex]\frac{v_1}{T}[/tex] 2T = v₁ - 2 v₁
vₓ = -v₁
Y axis
[tex]v_{y}[/tex] = v_{oy} + a_{y} t
v_{y} = v₂ + [tex]\frac{ v_3 - v_2}{T}[/tex] 2T
v_{y} = v₂ + 2 v₃ - 2v₂
v_{y} = 2 v₃ - v₂
the velocity vector is
v = -v₁ i ^ + (2 v₃ - v₂) j ^
what is the relationship between the dipole moment and bond moment? explain it with examples ,how it possible for a molecule to have bond moment and yet be nonpolar?
Answer:
Explained below
Explanation:
The relationship between dipole moment and bind moment is that Dipole moment of a molecule is defined as the resultant of all the bond moments and moments that are due to any existing lone pair.
For example, If a covalent bond is formed between two different elements that have different electronegativity, it means that the bond will become polar. Now, thee shared electron pair existing in the covalent bond gets more attracted to the more electronegative atom. As a result of that, the negative pole will now develop on that atom and thereby making positive pole to develop on the other atom.
If a molecule has a symmetrical shape and as a result all of its bond moments are equal, it means that the molecule will be non-polar. Examples that exhibit this are: CO2, CH4, BF3, etc.
3N
3 N
What is the net force of the box?
What type of stimulus do we tend to be particularly aware of ?
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Give an example of newtons 1st, 2nd and 3rd law of motion?
What is unusual about the material that Emily invented?
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
Hope it helps! Please mark brainliest.
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
The distance between a loudspeaker and the left ear of a listener is 2.70 m. (a) Calculate the time required for sound to travel this distance if the air temperature is 20 oc. (b) Assuming that the sound frequency is 523 Hz, how many wavelengths of sound are contained in this distance
Answer:
Explanation:
Distance covered by sound = 2.7 m
speed of sound at 20⁰C = 343 m /s
time take by sound to cover the distance = distance / speed
= 2.7 / 343
= 7.87 ms . ( millisecond )
b )
Wavelength of sound = speed / frequency
= 343 / 523 m
= .6558 m
= 65.58 cm
Distance = 2.70 m = 270 cm
No of wavelengths contained in the distance
= 270 / 65.58
= 4.11 or 4 wavelengths ( by rounding off to digit )
The time taken by sound and the wavelengths of sound is required.
Time taken is [tex]0.00787\ \text{s}[/tex]
The number of wavelenghts is 4.
s = Distance = 2.7 m
v = Speed of sound at [tex]20^{\circ}\text{C}[/tex] = 343 m/s
Time is given by
[tex]t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{2.7}{343}\\\Rightarrow t=0.00787\ \text{s}[/tex]
f = Frequency = 523 Hz
Wavelength is given by
[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{523}\\\Rightarrow \lambda=0.66\ \text{m}[/tex]
The wavelength is 0.66 m.
n = Number of wavelengths
[tex]n\lambda=s\\\Rightarrow n=\dfrac{s}{\lambda}\\\Rightarrow n=\dfrac{2.7}{0.66}\\\Rightarrow n\approx 4[/tex]
The number of wavelenghts is 4.
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A 1500 kg truck is acted upon by a force that decreases its speed from 25 m/s to 15 m/s in 8 s. What is the magnitude of the force acting on the truck?
Answer:
F = 1,875 N
Explanation:
force=
[tex] \frac{change \: in \: momentum}{time \: taken} [/tex]
∆H = m∆V
where ∆H ----> change in momentum.
( final momentum - initial momentum )
and ∆V ----> change in velocity
( final velocity - initial velocity )
and m ----> is mass
then f =
[tex] \frac{1500 \times (25 - 15)}{8} [/tex]
= 1,875 N
34000×0.4
----------------
0.02×200
In scientific notation
Answer:
the simplified expression is written as 3.4 x 10³
Explanation:
Given expression;
[tex]\frac{34000\times 0.4}{0.02 \times 200}[/tex]
in scientific notation, the expression is simplified as;
[tex]\frac{34000\times 0.4}{0.02 \times 200} = \frac{13600}{4} = 3400 = 3.4 \times 10^3[/tex]
Therefore, in scientific notation, the simplified expression is written as 3.4 x 10³
A mass is hung from a vertical spring and allowed to come to rest or its equilibrium position. The mass is then pulled down an additional 0.25 meters and released. As the mass oscillates it completes one full cycle in 3.0 seconds. Place the numbers below to correctly identify the mass's amplitude, full range of vertical motion, frequency, and period. The full range of vertical motion is the distance between the maximum and minimum heights of the mass.
e amplitude of the spring is______ m.
The full range of vertical motion is _____m.
The frequency of the spring is______ Hz.
The period of the spring is_______ s.
Answer:
Explanation:
Time period of oscillation T = 3 s .
Frequency of oscillation = 1 / T = 1 / 3 = .333 per second .
The mass is pulled down an additional 0.25 meters so amplitude of oscillation A = .25 m .
Full range of vertical motion = .25 x 2 = 0.5 m .
The period of the spring = 3 s .
A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 193.0 km/h. The conditions at the airport are ideal, there is no wind. When the engine is running at its full power, the acceleration of the airplane is 2.80 m/s2. What is the minimum required length of the runway
Answer:
513 m
Explanation:
We have;
final speed of the airplane = 193.0 km/h * 1000/3600 = 53.6 m/s
acceleration of the air plane = 2.80 m/s2
initial velocity of the airplane = 0 m/s
length of the runway = distance covered
v^2 = u^2 + 2as
v^2 - u^2 = 2as
s = v^2 - u^2/2a
s = (53.6)^2 - 0^2/ 2 * 2.80
s = 2872.96/ 5.6
s = 513 m
1.
Atennis ball is shot straight up with an initial velocity of 34 m/s. What is its velocity two seconds after launch?
Answer:
The speed (magnitude of the velocity) is 14.4 m/s
Explanation:
Vertical Launch Upwards
It occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.
If vo is the initial speed and g is the acceleration of gravity, the speed vf at any time is calculated by:
[tex]v_f=v_o-g.t[/tex]
A tennis ball is launched vertically up with an initial speed of vo=34 m/s. At time t=2 s, its speed is:
[tex]v_f=34-9.8*2[/tex]
[tex]v_f=34-19.6[/tex]
[tex]v_f=14.4\ m/s[/tex]
The speed (magnitude of the velocity) is 14.4 m/s
A mimibus drives with a constant speed of 39 km/h. how far can it travel in 1.94 hours?
Answer:
The minibus traveled 75.66 km
Explanation:
Motion with Constant Speed
An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.
The formula to calculate the speed is:
[tex]\displaystyle v=\frac{d}{t}[/tex]
Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we solve for d:
d = v . t
The minibus has a constant speed of v=39 km/h and it's required to find the distance it travels in t=1.94 hours.
Calculating the distance:
d = 39 km/h * 1.94 h
d = 75.66 km
The minibus traveled 75.66 km
The Porsche 911 turbo S is one of the fastest production cars in the world. It can go from 0-60 mph (0-27.7 m/s) in 2.9 seconds. What is the acceleration of this car in m/s^2?
Answer:
Acceleration = 9.55m/s²
Explanation:
Given the following data;
Initial velocity = 0m/s
Final velocity = 27.7m/s
Time = 2.9 secs
To find the acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Substituting into the equation, we have;
[tex]a = \frac{27.7 - 0}{2.9}[/tex]
[tex]a = \frac{27.7}{2.9}[/tex]
Acceleration = 9.55m/s²
An RLC parallel circuit has an applied voltage of 240 volts. R= 60 ohms, XL = 20 ohms, and Xc =36 ohms. What is the capacitor current?
Answer:
6.67A
Explanation:
The voltage across the capacitor formula is expressed as;
VL = IXL
VL is the voltage across the capacitor = 240volts (since it is a parallel connection, all the elements will have the same voltage)
I is the capacitor current
XL is the capacitive reactance = 36 ohms
Recall from the formula:
VL = IXL
I = VL/XL
I = 240/36
I = 6.67A
Hence the capacitor current is 6.67A
A spring has a spring constant of 200 N/m. How much elastic potential energy is stored in the spring when it is stretched by 0.1 meters? A:2000 J B:20 J C:0 J D:1 J
Answer:
D, 1J
Explanation:
PE=1/2kx^2 and plug in the variables.
PE=1/2 x 200 x 0.1^2= 1J
