How can we distinguish between ethylene and acetylene chemically?​

Answer:

true

Explanation:

Answer:

On the basis of this explanation, if the rate of lactate production is high enough, the cellular proton buffering capacity can be exceeded, resulting in a decrease in cellular pH. These biochemical events have been termed lactic acidosis. ... Every time ATP is broken down to ADP and Pi, a proton is released

Explanation:

[tex]2C_2H_6 + 7O_2[/tex] → [tex]4CO_2 + 6H_2O[/tex] is the balanced equation for the complete combustion of ethane.

The chemical equation in which the number of atoms of each element is equal in the reactant and the product of the reaction is called a balanced chemical equation.

[tex]2C_2H_6 + 7O_2[/tex] → [tex]4CO_2 + 6H_2O[/tex] is the balanced equation for the complete combustion of ethane.

Reactants contain 4 carbon atoms, 12 hydrogen atoms and 14 oxygen atoms. The same is true for products too.

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The equation for the combustion of ethane is 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O .

Combustion, or burning, is a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.

Balanced equation for the combustion of ethane :

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O .

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[tex]\huge\fbox{Answer ☘}[/tex]

It is given in the question that 200.0 grams of sodium hydroxide reacts with excess of sulphuric acid.

The given reaction is shown below

[tex]\bold\blue{2NAOH + H _{2}SO _{4} \: - > 2H _{2} O+ NA _{2}SO_{4} }\\ [/tex]

In this reaction, two mole of sodium hydroxide react with one mole of sulphuric acid to give two mole of water and one mole of sodium sulfate.

To determine the mass of sodium sulfate, first calculate the moles of sodium hydroxide as the value of mass is provided.

The molecular weight of NaOH is 40 g/mol.

The formula is shown below.

[tex]\pink{n = \frac{m}{ M}}\\[/tex]

Where,

✫ n is the number of moles

✫ m is the mass

✫ M is the molecular weight

To calculate the number of moles, substitute the values in the above equation.

[tex]\pink{n = \frac{200.0}{40g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢n = 5}[/tex]

In the equation it is given that 2 mole of sodium hydroxide gives 1 mole of sodium sulphate.

So, to determine the actual mole of sodium sulfate divide the calculated moles of NaOH by 2.

[tex] \pink{⇢ \frac{5}{2}} \\ \\ \pink{⇢ 2.5 \: mol}[/tex]

So 2.5 mol sodium sulfate is formed from 5 mol NaOH.

The molecular weight of sodium sulfate is 142.1 g/mol.

To calculate the mass of sodium sulfate, substitute the values in the formula.

[tex] \pink{⇢2.5 = \frac{m}{142.1g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢ m = 2.5 \times 142.1 }\\ \\ \pink{⇢ m = 355.25}[/tex]

Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.

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Answer:

You need two potassium atom to form an ionic bond with one sulfur atom. Pottassium ions are formed by donating losing their electrons in the outermost shell, thr lost electrons are gained by sulphur atom to form 2K+ and S2-, respectively. The attraction between the positive ions and negative ions gives rise to the ionic bond and the molecular formula is K2S

Explanation:

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

Half-life can be given as the time required by the substance to reduce to half of its original concentration. The original mass of Uranium was 11.2 grams.

The half-life for the reaction can be expressed as;

[tex]A_t=A_0(\dfrac{1}{2})^\dfrac{t}{t1/2}[/tex]

Where the final mass of the product is, [tex]A_t=1.40\;\rm g[/tex]

The time for the reduction is given as, [tex]t=206.7\;\rm years[/tex]

The half-life of the compound is given as, [tex]t1/2=68.9\;\rm years[/tex]

The original concentration ([tex]A_0[/tex]) of the Uranium is given as,

[tex]\rm 1.40\;g=\textit A_0(\dfrac{1}{2} )^{\dfrac{206.7}{68.9}}\\\\1.40\;g= \textit A_0(\dfrac{1}{2} )^3\\\\\textit A_0=11.2\;\rm grams[/tex]

The original mass of uranium-232 has been 11.2 grams.

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Explanation:

magnesium Hydroxide + Hydrochloric react together and give us magnesium chloride + water

The IUPAC name of the given compound is 4-methylene-1,7-heptadiene

Organic chemistry is the chemistry of carbon together with other elements such as oxygen, nitrogen, sulfur, hydrogen and phosphorus.

Organic compounds forms the core of organic chemistry.

In naming organic compounds, the IUPAC nomenclature is used.

The IUPAC name of the given compound is 4-methylene-1,7-heptadiene.

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Answer:

Aluminium Can not rust (Can't rust also meaning Corrode)

Because it's surface is protected by aluminium Oxide which stops the metal below from coming in contact with the air (which contains Oxygen) Unlike rust, which can flake off the surface of iron and steel objects, the layer of aluminium oxide does not flake off.

Corrode

destroy or damage (metal, stone, or other materials) slowly by chemical action.

Answer:

120

Explanation:

atomic number of Mercury is 80; therefore, each atom has 80 each of protons and electrons. The number of neutrons depends on the isotope, but for Hg-200, the number of neutrons is 200 - 80 = 120.

Answer:

Theoretical yield

Explanation:

hope this helps :)

Answer : B) theoretical yield

percent yield = Actual yield : theoretical yield x 100%

actual yield = actual product

theoretical yield = the product that should be produced (from the calculation of the reaction coefficient)

Answer:State the number of valence electrons for a hydrogen atom and a bromine atom in a covalent bond.

Explanation:

Explanation:

both reduction and oxidation are occurring simultaneously, this is known as a redox reaction. An oxidizing agent is substance which oxidizes something else. In the above example, the iron(III) oxide is the oxidizing agent. A reducing agent reduces something else

The oxygen atoms undergo reduction, formally gaining electrons, while the carbon atoms undergo oxidation, losing electrons. Thus oxygen is the oxidizing agent and carbon is the reducing agent in this reaction.

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Answer:

a. Change of state

Explanation:

Because you will see that the state has changed

Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas [tex](\rm N_{2})[/tex] in the cylinder is 1.63 moles.

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

[tex]\rm PV = nRT[/tex]

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

Gas constant (R)=  0.08206

Substituting values  in the equation:

[tex]\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}[/tex]

Therefore, 1.63 moles are produced.

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Answer:

1.63 moles.

Explanation:

The procedural steps in order to get iodinate salicylamide are as follows:

The Electrophilic aromatic substitution is known to be a kind of an organic reaction where an atom is said to be added or attached to a kind of aromatic structure (that is made up of hydrogen) is said to be replaced by an electrophile.

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Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=13mol × 1mol

2mol

x= 13mol

2mol

x= 6.5mol of oxygen

Answer:

The car has an acceleration of 9.5m/s²

Explanation:

Since:

a= change in velocity / change in time

a= 95m/s / 10s = 9.5 m/s²

[tex]\tt \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

T₁=40+273=313

T₂=60+273=333

P₁.820/313 = 1.4.1250/333

P₁=2.006 atm

After understanding the food chain, we realize that how one organism is dependent upon another organism for survival. Here among the given organisms, seagulls receives the energy last. The correct option is D.

A food chain refers to the order of events in an ecosystem, where one living organism eats another organism, and later that organism is consumed by another larger organism. The flow of nutrients and energy from one organism to another occurs at different trophic levels.

The food chain consists of sequential stages which are called the trophic levels. A food chain starts with the producers which utilize large amount of energy from the sun and the decomposers which are the last part needs less energy.

Decomposers get energy from dead materials. Here Seagulls comes last, so it receives less amount of energy.

Thus the correct option is D.

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Rubidium sulfide( Rb2S)

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Answer:

500 m/s

Explanation:

Wave Speed=Frequency x Wavelength

=50x10

=500

Answer:

4

Explanation:

hope it helps you in the long run

it is c because canivores eat only meat while herbivores eat only plants so it is most likely a herbivore because it knows flavours that are good for it

A carnivore is more likely to have taste buds for umami flavors so it can taste the flavors of meat, while a herbivore is less likely because plants do not generally have umami flavors. Hence, option B is correct.

One of the five fundamental flavors is umami. It has been characterized as savory and is present in cooked meats and broths. Glutamates and nucleotides, which are plentiful in meat broths and fermented foods, trigger the taste receptors that allow us to detect umami.

Meats, shellfish, fish (including fish sauce and preserved fish like maldive fish, Katsuobushi, sardines, and anchovies), tomatoes, mushrooms, hydrolyzed vegetable protein, meat extract, yeast extract, and cheeses are examples of foods with a strong umami flavor.

Carnivores are eating meat while herbivores are plant eaters. Hence, slight chance for herbivores to taste the umami flavor. Therefore, option B is correct.

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This problem is asking for the solubility of CO2 at both 25. °C and 60. °C in different masses of water and that of KNO3 in 40. g of water at 80 °C. At the end, the answers are 0.14 g, 0.348 g and 68. g respectively.

In chemistry, solubility is defined as the maximum amount of a solute one can perfectly dissolve without getting any precipitate or undissolved amount.

In this case, for CO2, one can start seeing that at 25. °C its solubility in 1000 g of water is approximately 1.4 g, which means that in 100. g it turns out to be:

[tex]\frac{1.4gCO_2*100.gH_2O}{1000gH_2O} =0.14 gCO_2[/tex]

However, at 60. °C it is approximately 0.6 g in 1000 g of water, which means that in 580. g it turns out to be:

[tex]\frac{0.6gCO_2*580.gH_2O}{1000gH_2O} =0.348gCO_2[/tex]

Finally, since the solubility of KNO3 at 80 °C is about 170 g in 100 g of water, one can see that in 40. of water it turns out to be:

[tex]\frac{170 gKNO_3*40.gH_2O}{100gH_2O} =68 gKNO_3[/tex]

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Answer:

My Understanding:

Explanation:

2 Carbon, 7 Hydrogen, 1 Oxygen, 1 Hydrogen plus 2 Oxygen is the reactants of 1 Carbon, 2 Oxygen plus 2 Hydrogen, and 1 Oxygen.