SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given equations
[tex]\begin{gathered} y=-\frac{4}{3}x \\ y=\frac{3}{2}x \end{gathered}[/tex]STEP 2: Define the point that is the solution for the given functions on the graph
The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect.
STEP 3: Determine the solution for the system of equations
It can be seen from the image below that the two lines intersect at the origin and hence they are given as the solutions to the given system of equations.
Hence, the solutions are:
[tex]x=0,y=0[/tex]what angle is Supplementary to angle 2 and what are the Verticle angles in this picture?
Suplementary angle = 180° - angle 2
is Angle 1,
because Angle 2 + Angle 1 = 180°
Part 2. Vertical angles are
Angles 2 and 5
Solve the system of two linear inequalities graphically. Graph the solution set of the first linear inequality? Type of boundary line? Two points on boundary line? Region to be shaded?
Answer:
Explanation:
Given the below system of linear inequality;
[tex]\begin{gathered} y<3 \\ y\ge-5 \end{gathered}[/tex]The graph of the linear inequality y < 3 will be a graph with a dashed line with a y-intercept of 3 since the inequality is not with an equal sign as seen below;
The graph of the 2nd linear inequality y >= -5 will be a graph with a solid line with a y-intercept of -5 since it has both the inequality sign and an equality sign as seen below;
Find the y-intercept and slope of the line below. Then write the equation is slope intercept form (y=mx+b).
The y-intercept is the value of y when x = 0
To identify y-intercept on a graph, we will check for the the value of y when the line crosses the y axis
From the graph, the line crosses the y axis at y = 6
Hence, the y-intercept is 6
To get the slope, we will pick any two points on the line.
Using points (0, 6) and (4, 0)
Applying the slope formula:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} x_1=0,y_1=6,x_2=4,y_2\text{ = }0 \\ m\text{ = }\frac{0\text{ - 6}}{4\text{ - 0}} \\ m\text{ = }\frac{-6}{4} \\ m\text{ = slope = -3/2} \end{gathered}[/tex]NOTE: the slope is negative because it is going from up to down (moving downwards)
The equation of slope in intercept form: y = mx + b
m = slope = -3/2
b = y-intercept = 6
The equation in y-intercept becomes:
[tex]y\text{ = }\frac{-3}{2}x\text{ + 6}[/tex]one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours. how long will it take the pipe to fill the pool if the drains left open
The time that it will take the pipe to fill the pool if the drains left open is 10 hours.
How to calculate the value?From the information, one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours.
The information illustrated that the input pipe gills 1/6 if the pool and the drain empties 1/15 in the pool every hour
The required time taken will be:
= 1/6 - 1/15
= 5/30 - 2/30
= 3/30
= 1/10
Therefore, the time taken is 10 hours.
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Please help me i have been struggling for two days
we have the equation
[tex]\log _5(x+1)-\log _2(x-2)=1[/tex]using a graphing tool
see the attached figure
The solution is x=2.90Consider function f, where B is a real number.
f(z) = tan (Bz)
Complete the statement describing the transformations to function f as the value of B is changed.
As the value of B increases, the period of the function
When the value of B is negative, the graph of the function
shy
and the frequency of the function
If the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B is negative, the graph of the function reflects over the y-axis.
How to estimate the graph and the frequency of the function?Let the tangent function be f(z) = tan (Bz)
The period exists [tex]$P=\frac{\pi}{|B|}$[/tex]
The frequency exists [tex]$F=\frac{1}{P}=\frac{|B|}{\pi}$[/tex].
The period exists inversely proportional to B, therefore, as B increases, the period decreases.
Frequency exists inversely proportional to the period, therefore, as the period decreases, the frequency increases.
When B is negative, we get f(z) = tan -Bz = f(-z), therefore, the function exists reflected over the y-axis, as the graph at the end of the answer shows, with f(z) exists red(B positive) and f(-z) exists blue(B negative).
As the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B exists negative, the graph of the function reflects over the y-axis.
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Identify the function rule from the values in the table.
we are given a table of inputs and ouputs of a function. We notice that each output is obtained by multiplying the input by -4:
[tex]\begin{gathered} (-2)(-4)=8 \\ (0)(-4)=0 \\ (1)(-4)=-4 \\ (3)(-4)=-12 \end{gathered}[/tex]Therefore, the right answer is A.
Write a sine function that has a midline of 4 , an amplitude of 3 and a period of 2/3
Given a midline of 4, an amplitude of 3 and a period of 2/3 we are asked to write a sine function.
Explanation
The equation of a sine function is given as
[tex]y=Asin(\frac{2\pi x}{T})+B[/tex]Where A is the amplitude, T is the period and B is the midline of the sine function.
Therefore, we will have;
[tex]\begin{gathered} y=3sin(2\pi x\div\frac{2}{3})+4 \\ y=3sin(2\pi x\times\frac{3}{2}_)+4 \\ y=3s\imaginaryI n(3\pi x)+4 \end{gathered}[/tex]Answer:
[tex]y=3s\imaginaryI n(3\pi x)+4[/tex]Simplify (v2 + 10v + 11)(v2 + 3v – 4) using the distributive property of multiplication ove addition(DPMA)
Given:
[tex](v^2+10v+11)(v^2+3v-4)[/tex]To find- the simplification.
Explanation-
We know that the distribution property of multiplication over addition says
[tex]a(b+c)=ab+ac[/tex]Use this property to simplify, and we get
[tex]\begin{gathered} =(v^2+10v+11)(v^2+3v-4) \\ =v^2(v^2+3v-4)+10v(v^2+3v-4)+11(v^2+3v-4) \end{gathered}[/tex]Multiply by opening the bracket, and we get
[tex]=(v^4+3v^3-4v^2)+(10v^3+30v^2-40v)+(11v^2+33v-44)[/tex]Now, open the bracket and combine the like terms.
[tex]\begin{gathered} =v^4+3v^3-4v^2+10v^3+30v^2-40v+11v^2+33v-44 \\ =v^4+(3v^3+10v^3)+(11v^2-4v^2+30v^2)-40v+33v-44 \end{gathered}[/tex]On further solving, we get
[tex]=v^4+13v^3+37v^2-7v-44[/tex]Thus, from the distributive property of multiplication over addition, we get v⁴+13v³+37v²-7v-44.
The answer is v⁴ + 13v³ + 37v² - 7v - 44.
g(x)=2x-2f(x)=4x-1Find (g*f) (-9)
Given:
[tex]\begin{gathered} g(x)=2x-2 \\ f(x)=4x-1 \end{gathered}[/tex]The expression for g(f(x)) is,
[tex]\begin{gathered} g(f(x))=2(f(x))-2 \\ =2(4x-1)-2 \\ =8x-2-2 \\ =8x \end{gathered}[/tex]Substitute x=-9 in the above expression.
[tex]\begin{gathered} g(f(-9))=8\times-9 \\ =-72 \end{gathered}[/tex]Thus, the final value of the expression is -72.
coupon A 45% off of a $73 jacket coupon B $30 rebate on a $73 Jacket
To be able to determine which among the coupon gives a lower price, let's determine what is 45% of $73 so that we could compare it with the $30 rebate. The highest amount among the two coupons will give you a lower price.
Let's determinte the 45% of 73:
[tex]\text{73 x }\frac{45\text{\%}}{100\text{\%}}\text{ }\rightarrow\text{ 73 x 0.45}[/tex][tex]\text{ = \$32.85}[/tex]Coupon A gives you $32.85 dollar off of a $73 Jacket.
Coupon A will give you a lower price compared to Coupon B. The price of the jacket will be $2.85 lesser than using Coupon B.
Imagine you are four years old. A rich aunt wants to provide for your future. She hasoffered to do one of two things.Option 1: She would give you $1000.50 a year until you are twenty-one.Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amounteach year until you were 21.If you only received money for ten years, which option would give you the most money?
Given the situation to model the arithmetic and the geometric sequences.
Imagine you are four years old. A rich aunt wants to provide for your future. She has offered to do one of two things.
Option 1: She would give you $1000.50 a year until you are twenty-one.
This option represents the arithmetic sequence
The first term = a = 1000.50
The common difference = d = 1000.50
The general formula will be as follows:
[tex]\begin{gathered} a_n=a+d(n-1) \\ a_n=1000.50+1000.50(n-1) \\ \end{gathered}[/tex]Simplify the expression:
[tex]a_n=1000.50n[/tex]Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amount each year until you were 21.
This option represents the geometric sequence
The first term = a = 1
The common ratio = r = 2/1 = 2
The general formula will be as follows:
[tex]\begin{gathered} a_n=a\cdot r^{n-1} \\ a_n=1\cdot2^{n-1} \end{gathered}[/tex]Now, we will compare the options:
The first term of both options is when you are four years old that n = 1
you only received money for ten years so, n = 10
So, substitute with n = 10 into both formulas:
[tex]\begin{gathered} Option1\rightarrow a_{10}=1000.50(10)=10005 \\ Option2\rightarrow a_{10}=1\cdot2^{10-1}=2^9=512 \end{gathered}[/tex]So, the answer will be:
For ten years, the option that gives the most money = Option 1
tim wants to order pizza for 22 employees.Each employee should get 1/4 of a pizza.How many pizzas should tim order ?
Tim should order approximately 6 pizza.
Define division.Division in mathematics is the process of dividing an amount into equal parts. For instance, we may split a group of 20 people into four groups of 5, five groups of 4, and so on. One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division. The other operations are multiplication, addition, and subtraction. Mathematicians use addition, subtraction, multiplication, and division as their four fundamental arithmetic operations. The division is one of these four operations that we employ most frequently in our daily work. It involves dividing a huge group into equally sized smaller units. Divide 25, for instance, by 5.
Given Data
Number of employees = 22
Slice of pizza one should get = 1/4
Dividing 22 by 1/4
[tex]\frac{22}{4}[/tex]
5 and [tex]\frac{1}{2}[/tex]
Tim should order approximately 6 pizza.
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G(x) = 1/x^10 g’(x)=
Differentiation - The value of g'(x) = [tex]\frac{1}{10}x^{-9}[/tex].
Apart from integration, differentiation is among the two key ideas in calculus. A technique for determining a function's derivative is differentiation. Mathematicians use a process called differentiation to determine a function's instantaneous rate of change predicated on one of its variables. The most typical illustration is velocity, which is the rate at which a distance changes in relation to time. Finding an antiderivative is the opposite of differentiation. The rate of change of signal with respect to y has been given by dy/dx if x and y are two variables. The general representation of a function's derivative is given by the equation f'(x) = dy/dx, where y = f(x) is any function.
Given that,
G(x) = [tex]\frac{1}{x^{10} }[/tex]
g’(x)=?
g’(x) is the derivative of g(x).
The derivative of [tex]x^{n} = nx^(n-1)[/tex]
[tex]x^{10} = 10x^(10-1)[/tex]
[tex]x^{10}= 10x^9[/tex]
Then,
[tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex]
Hence, The derivative of g(x) is [tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex].
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find the missing values in the figure below ( I need help as soon as possible only have 5 minutes available)
You can see in the figure attached that there are two Right triangles.
By definition, Right triangles are those triangles that have an angle that measures 90 degrees.
The larger triangle is the triangle ABC, but you only know the lenght of the side BC, which is:
[tex]BC=15m+2.5m=17.5m[/tex]And for the smaller triangle you only know the side whose lenght is 2.5 meters.
Therefore, since the exercise does not provide any other lenght and it does not provide another angle, you can conclude that the missing values cannot be determine with the given information.
So, the answer is OPTION D.
ABC is dilated by a factor of 5 produce A'B'C.What is A'C, the length of AC after the dilation? What is the measure of angle A?
We have that the scale factor is 5, then, the dilation is an enlargement.
Then, the new lengths are:
[tex]\begin{gathered} A^{\prime}C^{\prime}=5AC=5\cdot5=25 \\ A^{\prime}B^{\prime}=5AB=5\cdot4=20 \\ B^{\prime}C^{\prime}=5BC=5\cdot3=15 \end{gathered}[/tex]therefore, A'C' =25.
Finally, the dilations don't affect the angles, therefore, angle A remains with the measure of 37°
Write the expression as a sum and/or difference of logarithms. Express powers as factors
We will have the following:
[tex]\begin{gathered} ln(x^3\sqrt{6-x})=ln(x^3)+ln(\sqrt{6-x}) \\ \\ =3ln(x)+\frac{1}{2}ln(6-x) \end{gathered}[/tex]Find (and classify) the critical points of the following function and determine if they are local max, local min, or neither: f(x) =2x^3 + 3x^2 - 120x
As given by the question
There are given that the function:
[tex]f(x)=2x^3+3x^2-120x[/tex]Now,
To find the critical point, differentiate the given function with respect to x and put the result of function equal to zero
So,
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f^{\prime}(x)=6x^2+6x-120 \end{gathered}[/tex]Then,
[tex]\begin{gathered} f^{\prime}(x)=0 \\ 6x^2+6x-120=0 \\ x^2+x-20=0 \\ x^2+5x-4x-20=0 \\ x(x+5)-4(x+5) \\ (x-4)(x+5) \\ x=4,\text{ -5} \end{gathered}[/tex]Now,
To find the y-coordinate, we need to substitute the above value, x = 4, -5, into the function f(x)
So,
First put x = 4 into the given function:
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(4)=2(4)^3+3(4)^2-120(4) \\ =128+48-480 \\ =-304 \end{gathered}[/tex]And,
Put x = -5 into the function f(x):
[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(-5)=2(-5)^3+3(-5)^2-120(-5) \\ =-250+75+600 \\ =425 \end{gathered}[/tex]Hence, the critical point is, (4, -304) and (-5, 425).
Now,
To find the local maxima and local minima, we need to find the second derivative of the given function:;
So,
[tex]\begin{gathered} f^{\prime}(x)=6x^2+6x-120 \\ f^{\doubleprime}(x)=12x+6 \end{gathered}[/tex]Now,
The put the value from critical point into the above function to check whether it is maxima or minima.
So,
First put x = 4 into above function:
[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(4)=12(4)+6 \\ f^{\doubleprime}(4)=48+6 \\ f^{\doubleprime}(4)=54 \\ f^{\doubleprime}(4)>0 \end{gathered}[/tex]And,
Put x = -5 into the above function
[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(-5)=12(-5)+6 \\ f^{\doubleprime}(-5)=-60+6 \\ f^{\doubleprime}(-5)=-54 \\ f^{\doubleprime}(-5)<0 \end{gathered}[/tex]Then,
According to the concept, if f''(x)>0 then it is local minima function and if f''(x)<0, then it is local maxima function
Hence, the given function is local maxima at (-5, 425) and the value is -54 and the given function is local minima at point (4, -304) and the value is 54.
A rectangle is bounded by the x-axis and the semicircle
y = 49 − x2 What length and width should the rectangle have so that its area is a maximum?
The length and width of the rectangle are 4.04 and 32.67 respectively for which the area is a maximum.
What is mean by Rectangle?
A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.
Given that;
The rectangle is bounded by the x - axis and the semicircle y = 49 - x².
Since,
The area of rectangle with sides x and y is,
Area = x × y
A = xy
Since, The equation of the semicircle is;
y = 49 - x².
Substitute the values of y in equation (i), we get;
A = x (49 - x²)
A = 49x - x³
Now, Find the derivative and equate into zero,
A' = 49 - 3x²
A' = 0
49 - 3x² = 0
49 = 3x²
x² = 49/3
x = 7/√3
x = 7/1.73
x = 4.04
Hence, y = 49 - x²
y = 49 - (4.04)²
y = 49 - 16.3
y = 32.67
Since, The area is maximum when we can multiply x by y as;
Maximum area = 4.04 x 32.67
Maximum area = 132
Hence, The length and width of the rectangle are 4.04 and 32.67 respectively for which the area is a maximum.
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Company A has a monthly budget of 2 x 10^4 dollars. Company B has
a monthly budget of 5 x 10^8 dollars. How many times greater is the
monthly budget for company B than for company A?
The budget is 20000 times greater.
What are basic arithmetic?Mathematics' fundamentals are arithmetic operations. Addition, subtraction, multiplication, and division are the main operations that make up this concept. The phrase "mathematical operations" also refers to these.
The math operation of subtracting two integers reveals the difference between them. The '-' sign is used to indicate it. In math, subtraction is the process of taking one number away from another to determine what is left over after something has been taken away. Rational number operations are equivalent to those performed on whole numbers. The main distinction is that rational numbers take the form p/q, where p and q are integers and q is not equal to 0. It is necessary to take the LCM of the numerators when adding or subtracting two rational integers.
Here we are discussing the four basic rules of arithmetic operations for all real numbers.
Addition (sum; ‘+’)Subtraction (difference; ‘-’)Multiplication (product; ‘×’ )Division (÷)Company A = $2 × [tex]10^{4}[/tex]e
Company B = $ 5 × [tex]10^{8}[/tex]
The difference = $2 × [tex]10^{4}[/tex]
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The width of a rectangle is 6x + 8 and the length of the rectangle is 12x + 16 determine the ratio of the width to the perimeter.Supply the following:Perimeter = 21 + 2w = Ratio= w/p Final answer in simplest form:
Solution:
For this case we know that the width is given by:
w = 6x +8
The lenght is given by:
l= 12x +16
And the perimeter would be given by:
P= 2l +2w = 2(12x+16)+ 2(6x+8)= 24x+32 +12x+16=36x + 48
And then the ratio would be:
[tex]\text{ratio}=\frac{6x+8}{36x+48}=\frac{3x+4}{18x+24}[/tex]In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 4 boys and 5 girls are competing, how many different ways could the six medals possibly be given out?
ANSWER
1,440
EXPLANATION
We have that 4 boys are competing and also 5 girls are competing. 3 medals are given to the boys and 3 medals are given to the girls.
For the boys, the gold medal can be awarded to one of 4 boys, then the silver medal can be awarded to 3 boys because 1 of them already got the gold medal. Finally, the bronze medal can be awarded to one of 2 boys, since the gold and silver medals are already taken. The number of ways the medals can be given to the boys is,
[tex]permutations_{boys}=4\cdot3\cdot2=24[/tex]This situation is similar for the girls, but in this case, there are 5 girls in total,
[tex]permutations_{girls}=5\times4\times3=60[/tex]The total ways the six medals can be given is,
[tex]permutations_{boys}\times permutations_{girls}=24\times60=1,440[/tex]Hence, there are 1,440 ways to give the six medals to the 4 boys and 5 girls.
Find all the zeros of the following function.
f(x)=x^4+8x²-9
The zeros of the function are
(Use a comma to separate answers as needed. Express complex numbers in terms of i.)
All the zeros of following function f(x)=x4−8x2−9 are 3, -3, i, -i
What do you mean by the roots of function?A number x that reduces the value of a function f to 0 is known as its root in mathematics: f(x) = 0.
Roots are actual objects since polynomials are functions as well.
Every polynomial with complex coefficients has at least one (complex) root, according to the fundamental theorem of algebra.
f(x)=x4−8x2−9
You should set (x4 - 8x2 - 9) to 0.
x4−8x2−9=0
Learn what x's value is.
Put u=x2 in the equation's place.
As a result, applying the quadratic formula will be straightforward.
u2−8u−9=0
Consider the equation x2+bx+c.
Write out the factored form (u-9)(u+1) = 0.
The answer is the set of all numbers that add up to (u9)(u+1)=0.
u=9,−1
If u=x2 has a genuine value, change it to x2=9, x2= -1
In the case of these equations, x = +3, -3, and -i, +i .
The whole solution is made of of the solution's positive and negative components.
x4- 8x2- 9 = 0 has a solution.
is x=3,−3, i,−i
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write the equation of the line passing through the given points write your awnser in slope intercept form Y=mx+b (5 1) and (-3 17)
The given points are (5, 1) and (-3, 17).
First, we have to find the slope using the following formula.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]\begin{gathered} x_1=5 \\ x_2=-3 \\ y_1=1 \\ y_2=17 \end{gathered}[/tex]Let's use the coordinates above to find the slope.
[tex]m=\frac{17-1}{-3-5}=\frac{16}{-8}\Rightarrow m=-2[/tex]The slope is -2.
Now, we use the point-slope formula to find the equation.
[tex]y-y_1=m(x-x_1)[/tex]Let's use the same coordinates x_1 and y_1, and the slope m = -2.
[tex]y-1=-2(x-5)[/tex]Now, we solve for y to express the equation in slope-intercept form.
[tex]y-1=-2x+10\Rightarrow y=-2x+10+1\Rightarrow y=-2x+11[/tex]Therefore, the slope-intercept form of the equation is[tex]y=-2x+11[/tex]decide wether the following sides are acute obtuse or a right triangle.
The acute triangle is defined by the condition,
[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]Here, we have,
[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]Thus, the triangle is an obtuse triangle.
Write each ratio using the given figure. If necessary, find the missing side.Tan P = ___________Answer?
Hello!
First, let's analyze the figure and write each side:
Analyzing it, we don't have enough information yet to calculate the tangent (because we don't know the measurement of P).
So, let's calculate the opposite side (by Pithagoras):
[tex]\begin{gathered} a^2=b^2+c^2 \\ 41^2=40^2+c^2 \\ 1681=1600+c^2 \\ 1681-1600=c^2 \\ c^2=81 \\ c=\sqrt{81} \\ c=9 \end{gathered}[/tex]As we know the opposite side, we can calculate the tangent of P, look:
[tex]\begin{gathered} \tan(P)=\frac{\text{ opposite}}{\text{ adjacent}} \\ \\ \tan(P)=\frac{9}{40} \\ \\ \tan(P)=0.225 \end{gathered}[/tex]Curiosity: using the trigonometric table, this value corresponds to approximately 13º.
Answer:The tangent of P is 0.225.
You borrow 200 from a friend you repay the loan in two weeks and agreed to pay eight dollars for interest what is the annual percentage rate? Round your answer to the nearest 10th of a percent
suppose g(x) = f(x - 3) - 4. I need the graph of g(x) with the graph of f(x)
In order to graph g(x) with the graph of f(x), first we need a translation of 3 units to the right, because of the term f(x - 3)
Then, we need a translation of 4 units down, because of the term -4.
So the movements are: translations of 3 units right and 4 units down.
pls help fast I have to submit this soon!! :)
Since the rectangles are similar, that means their sides are proportional.
Since the bigger rectangle has a base of 24cm and the smaller one's base is 20cm, the proportion the sides hold is
[tex]\frac{24}{20}=1.2[/tex]This means the sides of the larger rectangle are 1.2 times larger than those of the smaller one.
The area of the small rectangle is 80cm². Since
[tex]A=b\mathrm{}h[/tex]where b is the lenght of the base and h is the lenght of the height, then
[tex]80=20\cdot h_1[/tex][tex]\frac{80}{20}=h_1=4[/tex]So the height of the small rectangle will be 4cm. But as we previously deduced, the height of the larger rectangle will be 1.2 times larger than that of the smaller one, so it's height will be
[tex]h_2=4\cdot1.2=4.8[/tex]And so, its are is
[tex]A_2=24\cdot4.8=115.2[/tex]We can confirm this because
[tex]\frac{115.2}{80}=1.44=1.2^2[/tex]which is the proportion the areas of the rectangles hold.
While at college orientation, Kate is buying some cans of juice and some cans of soda for the dorm. The juice is $0.60 per can while the soda is $0.75. Kate has $24 of dorm funds all to be spent. What is an equation that represents all the different combinations of juice and soda Kate can buy for $24 and how many different combinations of drinks are possible?
From the question the following can be derived:
(a)
Let x cans of juice and y cans of soda be purchased for the dorm. Then the cost of the juice and soda is 0.60x + 0.75y. The equation of all the combinations of juice and soda is 0.60x + 0.75y = 24.
(b)
The cost of exactly 24 cans of juice is $24 * 0.60 = $14.40. After this purchase, the remaining sum of money available is $24 - $14.40 = $9.60. This will suffice to buy 12 cans of soda, leaving a balance of $0.80. Thus. the entire money cannot be spent if exactly 24 cans of juice are purchased.
(c)
Below is a graph of the line 0.6x + 0.75y = 24 or 4x + 5y = 160 is plotted. All possible cimbinations of juice and soda will lie on this line. The x-intercept is 40 and the y-intercept is 32. Since neither of x and y can be negative, hence the lower and upper bounds for x are 0 and 40 and the lower ad upper bounds for y are 0 and 32. Also , x has to be multiple of 5 and y has to be a multiple of 4. As may be observed from the graph, only 9 combinations are possible which are (x, y):
(0, 32), (5, 28), (10, 24), (15, 20), (20, 16), (25, 12), (30, 8), (35, 4), (40, 0).
Graph: