How do I Graph the line with the given slope m and y-intercept b.
M=-4/3,b=2

How Do I Graph The Line With The Given Slope M And Y-intercept B. M=-4/3,b=2

Answers

Answer 1
So first start at the y-intercept which is also “b”
Then look at your slope “m” and the top is the vertical movement and the denominator is the horizontal movement. So to solve this, you start at (0,2) and you have two choices, to go down 4 and right three OR up 4 left 3.
Remember: if the slope a integer, the denominator is one so you can move left or right one according

Related Questions

explain why there are two zeros in the product of 5 x 40

Answers

EXPLANATION

There are two zeros in the product of 5x40 because multiplying the number 40 5 times give us the number 200 wich is a hundred type number.

relation and functionFunction OperationComposition of functionsymmetryfunction Inversesrate of change scartterplots

Answers

The answer is

[tex]m\text{ }\ne\text{ 0}[/tex]

So the first one is the answer.

Because if m = 0 then the function would be a constant function that does not have inverse. and we don't care if b= 0 or not because even if b= 0 or no we just need to know about m.

Consider 0.6 X 0.2.How many digits after the decimal point will the product have?Number of digits =

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given expression

[tex]0.6\times0.2[/tex]

STEP 2: Evaluate the expression

It can be seen that the result of the expression is 0.12

Hence, there are 2 digits after the decimal point for the product

Picture explains it all

Answers

Answer: .1$ so 10cents

Step-by-step explanation:

Answer is $0.10 for 10 pieces

Step by step

$10/1000 pieces = $0.01 per piece of candy

Multiply your rate x 10 pieces = $0.10

Complete the following proof
Given: = 3(5x + 1) = 13x + 5
Prove: x = 1

Answers

Key ConceptsProving algebraic expressions

Solving the Question

[tex]3(5x + 1) = 13x + 5[/tex]

Plug in x=1:

[tex]3(5(1) + 1) = 13(1) + 5\\3(5 + 1) = 13 + 5\\3(6) = 18\\18=18[/tex]

This statement is true.

A chemist needs to strengthen a 34% alcohol solution with a 50% solution to obtain a 44% solution. How much of the 50% solution should be added to 285 millilitres of the 34% solution? Round your final answer to 1 decimal place.

Answers

Answer: 475 ml of 50% solution is needed

Explanation:

Let x represent the volume of the 50% solution needed.

From the information given,

volume of 34% alcohol solution = 285

Volume of the mixture of 34% solution and 50% solution = x + 285

Concentration of 44% mixture = 44/100 * (x + 285) = 0.44(x + 285)

Concentration of 34% alcohol solution = 34/100 * 285 = 96.9

Concentration of 50% solution = 50/100 * x = 0.5x

Thus,

96.9 + 0.5x = 0.44(x + 285)

By multiplying the terms inside the parentheses with the term outside, we have

96.9 + 0.5x = 0.44x + 125.4

0.5x - 0.44x = 125.4 - 96.9

0.06x = 28.5

x = 28.5/0.06

x = 475

In a third day of randomly selected subjects, the mean age of the 36 respondents is 40 years and the standard deviation of ages is 10 years. Use the sample results to construct a 95% confidence interval estimate of the mean age of the population from which the sample was selected. Repeat the previous problem assuming that the population standard deviation is known to be six years.

Answers

a. Given that:

- The mean age of the 36 respondents is 40 years.

- The standard deviation of ages is 10 years.

You need to construct a 95% confidence interval estimate of the mean age of the population from which the sample was selected.

Then, you need to use this formula:

[tex]x\pm z\cdot\frac{\sigma}{\sqrt{n}}[/tex]

Where "x" is the sample mean, "z" is the confidence level value, "n" is the sample size, and σ is the standard deviation.

In this case:

[tex]\begin{gathered} x=40 \\ \sigma=10 \\ n=36 \end{gathered}[/tex]

Therefore, by substituting values into the formula:

[tex]40\pm\frac{10}{\sqrt{36}}[/tex]

You get these two values:

[tex]40+\frac{10}{\sqrt{36}}\approx41.67\text{ }[/tex][tex]40-\frac{10}{\sqrt{36}}\approx38.33[/tex]

b. If you assume that:

[tex]\sigma=6[/tex]

You get the following values by substituting them into the formula:

[tex]40+\frac{6}{\sqrt{36}}=41[/tex][tex]40-\frac{6}{\sqrt{36}}=39[/tex]

Hence, the answers are:

a.

[tex](38.33,41.67)[/tex]

b.

[tex](39,41)[/tex]

Which points sre vertices of the pre-image, rectangle ABCD?Makes no sense

Answers

Given rectangle A'B'C'D', you know that it was obtained after translating rectangle ABCD using this rule:

[tex]T_{-4,3}(x,y)[/tex]

That indicates that each point of rectangle ABCD was translating 4 units to the left and 3 units up, in order to obtain rectangle A'B'C'D'.

Notice that the coordinates of the vertices of rectangle A'B'C'D' are:

[tex]\begin{gathered} A^{\prime}(-5,4) \\ B^{\prime}(3,4) \\ C^{\prime}(3,1) \\ D^{\prime}(-5,1) \end{gathered}[/tex]

Therefore, in order to find the coordinates of ABCD, you can add 4 units to the x-coordinate of each point and subtract 3 units to each y-coordinate of each point. You get:

[tex]\begin{gathered} A=(-5+4,4-3)=(-1,1) \\ B=^(3+4,4-3)=(7,1) \\ C=(3+4,1-3)=(7,-2) \\ D=(-5+4,1-3)=(-1,-2) \end{gathered}[/tex]

Hence, the answers are:

- First option.

- Second option.

- Fourth option.

- Fifth option.

absolute value of v-5>3

Answers

Answer: v=8

Step-by-step explanation:

-5+5=0

3+5=8

v=8

A positive integer is 38 more than 27 times another their product is 5057. Find the two integers.

Answers

Answer:

13 and 389

Explanation:

Let the two positive integers be x and y

If a positive integer is 38 more than 27 times another, then;

x = 27y+ 38 ...1

If their product is 5057, then;

xy = 5057 .....2

Substitute equation 1 into 2

(27y + 38)y = 5057

Expand the bracket

27y^2 + 38y = 5057

27y^2 + 38y - 5057 = 0

Factorize

27y^2 -351y + 389y - 5057 = 0

27y(y-13) + 389(y-13) =0

(27y+389)(y−13) = 0

27y + 389 = 0 and y - 13 = 0

27y = -389 and y = 13

Since y is a positive integer, hence y = 13

Substiute y = 13 into equation 1;

x = 27y+ 38 ...1

x = 27(13)+ 38

x = 351 + 38

x= 389

Hencethe two positive integers are 13 and 389

2x -1/4y = 1 Solve the equation for y.

Answers

Given:

Given the equation

[tex]2x-\frac{1}{4}y=1[/tex]

Required: Solve for y.

Explanation:

Subtract 2x on both sides.

[tex]\begin{gathered} 2x-\frac{1}{4}y-2x=1-2x \\ -\frac{1}{4}y=1-2x \end{gathered}[/tex]

Multiply both sides by -4.

[tex]\begin{gathered} y=-4(1-2x) \\ =4(2x-1) \end{gathered}[/tex]

Final Answer: y = 4(2x - 1)

Explain how you know 437,160 is greater than 43,716.4 grade student

Answers

437,160 is read as four hundred thirty-seven thousand one hundred sixty and 43,716 is read as fourty-three thousand seven hundred sixteen.

The first number has hundreds of thousand and the second one only has tens of thousand. It means that the first number is greater than the second one.

Another way to know this is because of the number of figures before the decimal point. The first number has 6 figures before the decimal point and the second one only has 5.

That way, we know that 437,160 is greater than 43,716.

Which measurement is closest to the area of the triangle in square centimeters? A 63 cm2 B 42.75 cm2 С 35.5 cm2 D 31.5 cm2

Answers

The measurement shows that the base of the triangle is approximately 7 cm

while the height is approximately 9cm

The area of the triangle is given by

[tex]\text{Area = }\frac{1}{2}\text{ x base x height}[/tex][tex]\begin{gathered} \text{Area =}\frac{1}{2}\text{ x 7 x 9} \\ \text{Area = }\frac{63}{2}cm^2 \\ \\ \text{Area = 31.5cm}^2 \end{gathered}[/tex]

Option D is the closest to the answer

solving rational equations 1[tex] \frac{9x}{x - 2} = 6[/tex]2[tex] \frac{7}{x + 2} + \frac{5}{x - 2} = \frac{10x - 2}{x {}^2{ - 4} } [/tex]3[tex] \frac{ x - 1}{2x - 4} = \frac{2x - 2}{3x} [/tex]step by step instructions please thank you

Answers

the given expression is.,

[tex]\frac{9x}{x-2}=6[/tex][tex]\begin{gathered} 9x=6x-12 \\ 9x-6x=-12 \\ 3x=-12 \\ x=-\frac{12}{3} \\ x=-4 \end{gathered}[/tex]

also, the given expression is,

[tex]\frac{7}{x+2}+\frac{5}{x-2}=\frac{10x-2}{x^2-4}[/tex][tex]\begin{gathered} \frac{7x-14+5x+10}{x^2-4}=\frac{10x-2}{x^2-4} \\ 12x-4=10x-2 \\ 12x-10x=4-2 \\ 2x=2 \\ x=\frac{2}{2}=1 \\ x=1 \end{gathered}[/tex]

How do you determine a relation is function on a GRAPH?

Answers

To Determine: How to determine a relation is function on a GRAPH

In other to achieve this, we will use the vertical test

If a vertical line is moved across the graph and, at any time, touches the graph at only one point, then the graph is a function. If the vertical line touches the graph at more than one point, then the graph is not a function

Check the image below for a better clarification

With the use of the vertical line test, the graph in OPTION C and OPTION D are functions and the graph in OPTION A and B are not functions

In summary, you determine a relation is a function on a graph by using a vertical line test

The parent function y = |x| is reflected across the x-axis to obtain ________________.y = -|x|y = -|x + 1|y = |-x|y = -|x + 5|

Answers

The given function is:

[tex]y=|x|[/tex]

It is reflected across the x-axis to obtain a new function. This transformation follows the rule:

[tex]g(x)=-f(x)\rightarrow reflection\text{ }across\text{ }x-axis[/tex]

If we apply this rule, we obtain:

[tex]y=-|x|[/tex]

The answer is y=-|x|

10. Determine if the following sequence is arithmetic or geometric. Then, find the 67th term. 36, 30, 24, 18, ... a. arithmetic, -360 b. arithmetic, 12 c. geometric, -360 d. geometric, 12

Answers

hello

to determine if the sequence is arthimetic or a geometric progression, we check if a common difference or common ratio exists between the two sequence

the sequence is 36, 30, 24, 18,......

from careful observation, this is an arthimetic progression because a common difference exists between them

d = 30 - 36 = -6

or

d = 24 - 30 = -6

to find the 67th term, let's apply the formula

[tex]\begin{gathered} T_n=a+(n-1)d \\ T_{67}=a+(67-1)d \\ a=\text{first term = 36} \\ d=common\text{ difference = }-6 \\ T_{67}=36+(67-1)\times-6 \\ T_{67}=36+66\times-6 \\ T_{67}=36-396 \\ T_{67}=-360 \end{gathered}[/tex]

Text-to-Speech 11. Diva wants to make a flower arrangement for her aunt's birthday. She wants 1/3 of the arrangement to be roses. She has 12 roses. How many other flowers does she need to finish the arrangement?

Answers

[tex]\begin{gathered} \text{We have} \\ \frac{1}{3}x=12 \\ x=12\cdot3 \\ x=36 \\ \\ \text{ The need in total 36 flowers, but she have 12 roses} \\ \\ \text{ thus she only needs 24 flowers!} \end{gathered}[/tex]

Compute the percent of profit or loss on shares of stock purchased at8.625 and sold at 10.75.

Answers

ANSWER:

24.63%

STEP-BY-STEP EXPLANATION:

The first thing is to mention that it is a profit because it was bought at a lower amount than it was sold, therefore

We take 100% as the lowest value, and thus we calculate the profit percentage

[tex]10.75\cdot\frac{100}{8.625}=124.63[/tex]

Then the difference between both percentages is the profit percentage

[tex]124.63-100=24.63[/tex]

Show your work Round to the nearest whole number if needed

Answers

Given:

Radius, r = 6

Let's find the chance of hitting the shaded area by finding the ratio.

Since the radius of the cirlce is 6, the length of one side of the square is the diameter:

s = 6 x 2 = 12

To find the ratio divide the area of the circle by area of the square. The area of the circle is the shaded area while the area of the square is the total possible area.

Thus,we have:

[tex]\text{ Area of circle = }\pi r^2=3.1416\ast6^2=3.1416\ast36=113.0976\text{ square units}[/tex][tex]\text{ Area of square = }s^2=12^2=12\ast12=144\text{ square units}[/tex][tex]\text{ Ratio=}\frac{shaded\text{ area}}{total\text{ possible area}}=\frac{area\text{ of circle}}{area\text{ of square}}=\frac{113.0976}{144}=0.7854\approx0.79[/tex][tex]\text{ Percentage ratio = 0.7854 }\ast\text{ 100=}78.54\text{ \%}[/tex]

Therefore, the chance of hitting the shaded region is 78.54%

ANSWER:

78.54%

What are all of the answers for these questions? Use 3 for pi. Please do not use a file to answer, I cannot read it.

Answers

The company's sign has two(2) congruent trapezoids and two(2) congruent right angled triangle.

The area of the figure is:

[tex]A_{\text{figure}}=2A_{\text{trapezoid}}+2A_{\text{triangle}}[/tex]

The area of a trapezoid is given by the formula:

[tex]\begin{gathered} A_{\text{trapezoid}}=\frac{1}{2}(a+b)h \\ \text{where a and b are opposite sides of the trapezoid} \\ h\text{ is the height} \end{gathered}[/tex]

Thus, we have:

[tex]\begin{gathered} A_{\text{trapezoid}}=\frac{1}{2}(1\frac{1}{2}+3)2 \\ A_{\text{trapezoid}}=\frac{1}{2}(1.5+3)2 \\ A_{\text{trapezoid}}=\frac{1}{2}\times4.5\times2=4.5m^2 \end{gathered}[/tex]

Area of a triangle is given by the formula:

[tex]A_{\text{triangle}}=\frac{1}{2}\times base\times height[/tex]

Thus, we have:

[tex]\begin{gathered} A_{\text{triangle}}=\frac{1}{2}\times2\times1\frac{1}{2} \\ A_{\text{triangle}}=\frac{1}{2}\times2\times1.5=1.5m^2 \end{gathered}[/tex]

Hence, the area of the company's sign is:

[tex]\begin{gathered} A=(2\times4.5)+(2\times1.5) \\ A=9+3=12m^2 \end{gathered}[/tex]

determine the volume of each rectangular or triangular prism round to the nearest tenth if necessary

Answers

Determine the volume of each rectangular or triangular prism round to the nearest tenth if necessary ​

____________________

volume = base (B)* height (H)

_____________________

Base area

Triangle

B = b*h/2

Rectangle

B= L1*L2

__________________

volume = base (B)* height (H)

H= 15

Triangle case

B = 4.8 *9.6 /2

B = 46.08 / 2

B= 23.04

V= 23. 04* 15

V= 345.6 in ^3

2. The area of the arena is 2160 in.2 a) Will the arena fit on the rug? Show your work and explain your answer below. b) If the length of the arena is 60 inches, what is the width? c) If the arena fits, and is placed exactly in the middle of the rug, how much standing room on the rug could a drive have? Use your measurements from above to help you. ? 3. If 15 robots can fit on the arena floor at one time, how much space does each robot take up?

Answers

Answers:

2a. The arena will fit on the rug

b. Width = 36 in

c. Standing room: 4 in

3. 144 in²

Explanation:

2. Part a.

First, we need to convert the measures of the rug to inches, so taking into account that 1 ft = 12 in, we get

Length = 6 ft x 12 in/ 1ft = 72 in

Width = 4 ft x 12 in/ 1 ft = 48 in

Then, the area of the rug will be

Area = Length x Width

Area = 72 in x 48 in

Area = 3456 in²

Therefore, the area of the arena, which is 2160 in² is lower than the area of the rug. It means that the area will fit on the rug.

Part b.

The area of the arena is equal to

Area = Length x Width

To find the width of the area, we need to solve the equation for the width, so

Width = Area/Length

So, replacing Area = 2160 in² and Length = 60 in, we get

Width = 2160 in² / 60 in

Width = 36 in

Therefore, the width of the area is 36 in.

Part c.

The measures that we get from parts a and b can be represented as

Therefore, the missing length can be calculated as:

(48 in - 36 in)/2 = 12 in/ 2 = 6 in

Therefore, a drive will have 6 in of standing room.

3.

Finally, to know how much space each robot take up, we need to divide the area of the arena by 15, so

2160 in²/ 15 = 144 in²

Therefore, each robot take 144 in²

I have a practice problem in the calculus subject, I’m having trouble solving it properly

Answers

The limit of a function is the value that a function approaches as that function's inputs get closer and closer to some number.

The question asks us to estimate from the table:

[tex]\lim _{x\to-2}g(x)[/tex]

To find the limit of g(x) as x tends to -2, we need to check the trend of the function as we head towards -2 from both negative and positive infinity.

From negative infinity, the closest value we can get to before -2 is -2.001 according to the values given in the table. The value of g(x) from the table is:

[tex]\lim _{x\to-2^+}g(x)=8.02[/tex]

From positive infinity, the closest value we can get to before -2 is -1.999 according to the values given in the table. The value of g(x) from the table is:

[tex]\lim _{x\to-2^-}g(x)=8.03[/tex]

From the options, the closest estimate for the limit is 8.03.

The correct option is the SECOND OPTION.

The baker has 305 cakes to send to the farmers market. If he can pack up to 20cakes in a crate for shipping, what is the minimum number of boxes required toship all of the cakes. Explain your reasoning.

Answers

We have 305 cakes. As we know

Which expression is equivalent to (m−5n−3)−3?

m−15n−9
m15n9
m−8n−6
1 over the quantity m raised to the eighth power times n raised to the sixth power end quantity

Answers

The expression (m⁻⁵n⁻³)⁻³ has an equivaent of m⁻¹⁵n⁹

How to determine the equivalent expression

From the question, the expression is represented as

(m−5n−3)−3

Rewrite the expression properly

This is done as follows;

(m⁻⁵n⁻³)⁻³

Open the brackets

So, we have the following equation

(m⁻⁵n⁻³)⁻³ = (m⁻⁵)⁻³ x (n⁻³)⁻³

Evaluate the products

So, we have the following equation

(m⁻⁵n⁻³)⁻³ = (m⁻¹⁵) x n⁹

This gives

So, we have the following equation

(m⁻⁵n⁻³)⁻³ = m⁻¹⁵n⁹

Hence, the solution is (m⁻⁵n⁻³)⁻³ = m⁻¹⁵n⁹

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The given expression (m⁻⁵n⁻³)⁻³ has an equivalent to the m⁻¹⁵n⁹

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The expression is represented as (m−5n−3)−3

Rewrite the expression as follows;

(m⁻⁵n⁻³)⁻³

Open the brackets , we have

(m⁻⁵n⁻³)⁻³ = (m⁻⁵)⁻³ x (n⁻³)⁻³

Evaluate the products, we have;

(m⁻⁵n⁻³)⁻³ = (m⁻¹⁵) x n⁹

(m⁻⁵n⁻³)⁻³ = m⁻¹⁵n⁹

Hence, the solution will be; (m⁻⁵n⁻³)⁻³ = m⁻¹⁵n⁹

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Find the present value that will grow to $6000 if the annual interest rate is 9.5% compounded quarterly for 9 yr.The present value is $(Round to the nearest cent as needed)

Answers

We need to know how to calculate compound interest to solve this problem. The present value is $2577.32

Compound interest is the interest that is earned on interest. Inorder to calculate the compound interest we need to know the principal amount, the rate of interest, the time period and how many times the interest is applied in per time period. In this question we know the amount after 9 years and the rate of interest is 9.5% and the interest is compounded quarterly. We will use the formula for compound interest get the principal value.

A=P[tex](1+\frac{r}{n}) ^{nt}[/tex]

where A= amount, P= principal, t=time period, n= number of times interest applied per time period, r=rate of interest

A=$6000

r=9.5%

t=9 yrs

n=4

6000=P[tex](1+\frac{9.5}{400} )^{36}[/tex]

6000= P x 2.328

P=6000/2.328=2577.32

Therefore the present value that will grow to $6000 in 9 years is $2577.32

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PLEASE HELP! *not a test, just a math practice that I don't understand.

Answers

1) Let's analyze those statements according to the Parallelism Postulates/Theorems.

8) If m∠4 = 50º then m∠6 =50º

Angles ∠4 and ∠6 are Alternate Interior angles and Alternate Interior angles are always congruent

So m∠4 ≅ m∠6

9) If m∠4 = 50, then m∠8 =50º

Angles ∠4 and ∠8 are Corresponding angles and Corresponding angles are always congruent

10) If m∠4 = 50º, then m∠5 =130º

Angles ∠4 and ∠5 are Collateral angles and Collateral angles are always supplementary. So

need help asap look at attachmen

Answers

The rectangle has a width of 7 yards and a length of 42 yards.

How to find the length and width?

For a rectangle of length L and width W, the perimeter is:

P  = 2*(L + W)

Here we know that:

L = 6*W

P = 98yd =  2*(L + W)

Then we have the system of equations:

L = 6*W

98yd =  2*(L + W)

If we substitute the first equation into the second one, we get:

98yd = 2*(6*W + W)

98yd = 14*W

98yd/14 = W = 7yd

So the width is 7 yards, and the length is 6 times that, so:

L = 6*7yd = 42yd

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help meeeeeeeeee pleaseee !!!!!

Answers

The composite functions are evaluated and simplified as:

(f o g)(x) = 9x² + 5

(g o f)(x) = 3x² + 15

How to Evaluate a Composite Function?

To evaluate a composite function, the inner function is evaluated first using the given input. After then, the output of the inner function is used as the input to evaluate the outer function.

Given the following:

f(x) = x² + 5g(x) = 3x

Therefore:

a. (f o g)(x) = f(g(x))

Substitute g(x) for x into f(x) = x² + 5

f(g(x)) = (3x)² + 5

Simplify the function

f(g(x)) = 9x² + 5

b. (g o f)(x) = g(f(x))

Substitute f(x) for x into g(x) = 3x:

g(f(x)) = 3(x² + 5)

Simplify the function

g(f(x)) = 3x² + 15

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The number of friends who donate $ 5 to Daylyn is 3 times the number who pays him for correct answers. Write and solve an equation to find the number of friends who must pay him $0.25 for each correct answer in order for Daylyn to meet his goal 4. A stone nudged off the Royal Gorge Bridge near Caon City, Colorado, falls 1053 feet before hitting water. Because its speed increases as it falls, the distance ittravels each second increases. During the first second, it drops 16 feet. During the next second, it drops an additional 48 feet. During the third second, it drops another80 feet. The distances traveled each second form an arithmetic sequence:16, 48, 80,...Part 1: How far does the stone fall during the 5th second? Find and use the explicitformula.a. What is the first term of the sequence?b. What is d, the common difference?c. Write the explicit formula in function notation. Use f(n) = f(1) + (n - 1)d, wheref(1) represents the first term.d. Use the explicit formula to find the distance the stone travels in the 5th second.Part II: The table below shows the values in the sequence you already know. Use the explicit formula or the common difference to complete the table for the first 7 seconds. Time (s) 1 2 3 4 5 6 7 Distance (ft) 16 48 80 | | 144 | | | | Part ||| : Use the table from part 2 to answer the questions a. The values in the table form a(n)___ sequence and the term numbers are shownb. The term values are shown in the in the____row, and the term numbers are shown in the ___ row. c. This sequence is associated with a(n)___function d. The domain of the function is the set of time values:___ for 2020, lydia had adjusted gross income of $60,000 and made the following charitable contributions: cash contribution to her synagogue: $ 1,500 tuition to a private school paid directly to her niece: $ 1,200 contribution to the salvation army: $ 350 cash contribution to a man begging on a freeway off ramp: $ 150 what is the maximum amount that she can deduct as a charitable contribution for 2020? Select all ratios equivalent to 13.1452:56. 39:42. 3:4 You deposit $200 each month into an account earning 4% interest compounded monthly.a) How much will you have in the account in 25 years?$b) How much total money will you put into the account?$c) How much total interest will you earn?$ In an all boys school, the heights of the student body are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. What is the probability that a randomly selected student will be taller than 71 inches tall, to the nearest thousandth? when the protein gramicidin is integrated into a membrane, an h channel forms and the membrane becomes very permeable to protons ( h ions). if gramicidin is added to an actively respiring muscle cell, how would it affect the various processes involved in cellular respiration and oxidative phosphorylation? (assume that gramicidin does not affect the production of nadh and fadh2 during the early stages of cellular respiration.) A circle has a circumference of 10 inches. Find its approximate radius, diameter and area AWhich of the following is a reasonable claim the researchers can make based on the data in the graphs?BC2Crabs are more abundant in areas with high salinity than in areas with low salinity.Crab populations are most limited where salinity range between 10 and 15 psu.3Salinity does not influence crab populations because the number of crabs fluctuates across the five sites.D Crab populations are larger in areas with low salinity than in areas with high salinity.5 Instead of cultural and marketing influences, what factors should determine a households saving rate?. Two students measured a box in class. They used a digital scale and found that the mass was 400 grams. They then measured the box found the length is 2cm, the width is 2cm, and the height is 1cm. What is the density of the object