How does an image from a CT scan differ from a regular X-ray image?
A.
An X-ray image requires a computer to create it, and a CT scan does not.
B.
The CT scan uses many X-ray images in thin slices to make a 3D image.
C.
The CT scan makes a 2D image, and regular X-ray images are 3D.
D.
The CT scan uses lower amounts of radiation.

Answers

Answer 1

Answer:

The Answer is B

Explanation:

I just took the test

Answer 2

An image from a CT scan differ from a regular X-ray image in such a way that B)The CT scan uses many X-ray images in thin slices to make a 3D image.

What is a CT scan ?

A CT scan also stands for Computed tomography scan is a medical technique to obtain detail of internal images of the body .

x ray image are in 2D while CT Scan image are in 3D (hence option c) is wrong ). Also CT scans have a doughnut shaped tube that rotated the x ray 360° degree around the body . The data provides a detailed 3D view of the inside of the body

hence , option B

The CT scan uses many X-ray images in thin slices to make a 3D image.

is correct

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Related Questions

What type of metals are known as ferromagnetic metals

Answers

Answer:

those who are attracted to magnets. ex: iron, cobalt and nickel

kinda easy but too lazy

Answers

Do it your self then

Answer:

We don't promote laziness here, my dear child. :)

The latent heat of vaporization for water at room temperature is 2430 J/g.

1. How much kinetic energy does each water molecule that evaporates possess before it evaporates?
2. Find the pre-evaporation rms speed of a water molecule that is evaporating.
3. What is the effective temperature of these molecules (modeled as if they were already in a thin gas)?

4. Why do these molecules not burn you

a. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy decreases.
b. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy is unaffected.
c. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy is unaffected.
d. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy increases.

Answers

Answer:

1)   [tex]kinectic energy=7.26*10^-^2^0J[/tex]

2)  [tex]V= 2.0m/s[/tex]

3)  [tex]T=3.5*10^3K[/tex]

4)  The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

   

  [tex]M=\frac{18.02}{6.02*10^-^2^6}[/tex]

  [tex]M=3*10^-^2^3g[/tex]

Therefore

  [tex]kinectic energy=2430J/g*3*10^-^2^3g[/tex]

 [tex]kinectic energy=7.26*10^-^2^0J[/tex]

b)Generally the evaporation speed V is given as[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]

Mathematically derived from the equation

[tex]\frac{1}{2} mv^2 =K.E[/tex]

To Give

[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]

[tex]V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }[/tex]

[tex]V= 2.0m/s[/tex]

c)Generally the equation for velocity   [tex]Vrms=\sqrt{\frac{3RT}{M} }[/tex]

Therefore

Effective temperature T is given by

      [tex]T=\frac{\sqrt{v}*m}{R}[/tex]

where

     [tex]T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}[/tex]

     [tex]T=3.5*10^3K[/tex]

4) The Molecules do not burn because of the presences of hydrogen bond in place

An object accelerates uniformly from rest. If the final velocity of the object after 6.0 s is
18 m/s east, how far did the object travel?

Answers

Answer:

54m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time taken  = 6s

Final velocity  = 18m/s east

Unknow:

How far did the object travel  = ?

Solution:

To solve this problem, we use one of the kinematics equation:

 We first find the acceleration which is the change in velocity

   

So;

        S  = [tex](\frac{v - u}{2} ) t[/tex]    

    S is the distance  

    v is the final velocity

    u is the initial velocity

    t is the time taken

  Therefore;

       S = [tex]\frac{18 - 0}{2}[/tex]  x 6  = 54m

A woman on a bridge 82.2 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 5.04 m more to travel before passing under the bridge. The stone hits the water 2.13 m in front of the raft. Find the speed of the raft.

Answers

Answer:

0.71 m/s

Explanation:

We find the time it takes the stone to hit the water.

Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.

So, substituting the values of the variables into the equation, we have

y = ut - 1/2gt²

82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²

82.2 m = 0 + (4.9 m/s²)t²

82.2 m =  (4.9 m/s²)t²

t²  = 82.2 m/4.9 m/s²

t² = 16.78 s²

t = √16.78 s²

t = 4.1 s

This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.

Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s

Roots spreading far and wide

Answers

Answer:

₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₣5₣ đ₮ɽ ₮₣ ₮ɽ

how is space Technology different from space exploration​

Answers

Answer:

Space technology is technology developed by space science for use in astronautics, for purposes such as spaceflight or space exploration. Space technology includes spacecraft, satellites, space stations, and support infrastructure equipment, and procedures and space warfare.

Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system

Answers

Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

what is physical quantity​

Answers

Answer:

a physical quantity is any physical property that can be quantified, that is, be measured using numbers.

Answer: A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.

Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be treated as particles and are fixed with a certain separation. (a) For what value of q/Q will the electrostatic force between the two spheres be maximized? What are the (b) smaller and (c) larger values of q/Q that give a force magnitude that is 75% of that maximum?

Answers

Answer:

2. Smaller value of q = 1/4Q

3. Larger value of q = 3/4Q

Explanation:

1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.

2. The smaller value is

F = 75% = 75/100

= 3/4 * Q²/16piEod² ---3

When we equate 1 and 3

We get 3Q²/16 = Qq - q² from here we cross multiply to get

3Q² = 16(Qq-q²)

3Q² = 16Qq-16q²

16q² - 16Qq + 3Q² = 0

When solve this out using the quadratic equation formula, we have:

Q/2 +- 2Q/8

We can get the smaller value of q as

Q/2-2Q/8

Solve using LCM we get

2Q/8 = 1/4Q = Q/4

C. The larger value of q

Q/2+2Q/8

= 6Q/8

= 3Q/4

Please use the attachment it will guide you to understand this better.

Use one of the following formulas to solve distance:
speed=d/t
*Hint: You will have to manipulate the formula
At dinner you got mad and threw your burrito at a speed of 4 m/s. It flies for 18 seconds through the air. How much distance did the burrito
cover?

Answers

Answer:

72m

Explanation:

Given parameters:

Speed of the Burrito  = 4m/s

Time  = 18s

Unknown:

Distance covered by the flying Burrito = ?

Solution:

Speed is the rate of distance covered per unit of time.

        Speed  = [tex]\frac{distance}{time}[/tex]  

 Distance  = Speed x time

So;

 Distance  = 18 x 4  = 72m

A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 68.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 21.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.

Answers

Answer:

0.74 m/s

Explanation:

From the question,

We apply the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0

0 = Total momentum after collision

(m+M)V + m'v = 0

Where m = mass of the  skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v =  velocity of the brick

make V the subject of the equation above

V = -m'v/(m+M)................... Equation 1

Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.

Substitute these values into equation 1

V = -(2.5×21)/(68+2.5)

V = 52.50/70.5

V = 0.74 m/s

Which of the following statements is true?
1)Efficiency is calculated by multiplying work input and work output.
2)a few machines are 100 percent efficient.
3) Some machines are frictionless.
4)The ratio of work output to work input is always less than one.

Answers

Answer:

4)

Explanation:

Efficiency is calculated by dividing the energy out by energy in, not multiplying

No machines are 100% Efficient

No machines are frictionless

4) is true

Please help I will mark brainlest .

Answers

Answer:

lithium atom

Explanation:

If you search up lithium atom the same atom will come out.

Sorry if it's wrong.

If you are givin force and time, you can determine power if you can know.

A. Watts
B. Energy
C. Joules
D. Distance

Answers

Answer:

D. Distance

Explanation:

Power is work divided by time. Work is force times distance, therefore you need distance in order to find power.

If you are givin force and time, you can determine power if you can know.

C. Joules

A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m

Answers

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

What is force?

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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A dog walks 15 meters to the east and then 20 meters back to the west​

Answers

the dig would -5 from where he first started.

The dog would be -5 that’s where he started from

4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle that A makes with the x axis​

Answers

Answer:

A = 4.49

α = 57.72°

Explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

[tex]A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49[/tex]

The angle tangent can be used to determine the angle.

[tex]tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)[/tex]

Two equal in magnitude, positive charges Q are fixed at distance 2d from each other. The third charge, of magnitude q and unknown sign is positioned very carefully into the midpoint on the line connecting the first two charges. Pick the statement which is correct:

a. The third charge will accelerate towards one of the charges.
b. The third charge will be in equilibrium and this equilibrium is stable.
c. The third charge will be in equilibrium and this equilibrium is unstable.
d. The third charge will be in equilibrium. This equilibrium is stable if charge is positive and unstable if charge is negative.
e. All these statements are wrong.

Answers

Answer:

the correct one is d

Explanation:

To answer which statement is correct, let's look for the force on the third charge

                F = F₁₃ + F₂₃

force is electric force

                F = [tex]k \frac{q_1 q_2}{r^2}[/tex]

In the exercise we are told that the distance between the two charges is 2d, therefore the distance of each charge to the third is x = d and the two falls have a car Q

               F₁₃ = k q Q / d²

               F₂₃ = k q Q / d²

suppose that charge 3 is positive for which the forces are repulsive

                F = k q Q / d₂ - k q Q / d₂

                F = 0

suppose that the charge 3 is negative for which the forces are of attraction

                  F = -k q Q / d₂ + k q Q / d₂

                  F = 0

We can see that regardless of the sign of charge 3 the forces on it are zero, so it has no acceleration, it is in equilibrium.

Let's analyze the type of equilibrium, for this we move the charge 3 towards one of the sides

charge 3 positive

the force towards the approaching side increases and the other decreases, therefore the load has a net force towards the center, in that case the equilibrium is stable

negative charge 3

The force towards the approaching side is stronger and more attractive and the other decreases, therefore it has an attractive net force that carries it towards the charge, it is closer, in this case the balance is unstable

To review the different answers, the correct one is d

What is the loudness, in decibels, of a sound 1 trillion times as loud as the softest audible sound?
The loudness of this sound in decibels is _________ dB. (Type an integer or a decimal.)

Answers

Answer:

What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)

Why do the snakes only get one unit of energy?

Answers

Answer: Snakes are reptiles

Explanation: All reptiles are ectothermic (they obtain body heat from their environment).

As snake belongs to secondary consumer, it get  less amount of energy in food cycle. If producer (grass) get 100 unit of energy, according to food chain snakes only gets one unit of energy.

What is food chain?

The sequence of events in an ecosystem known as a "food chain" occurs when one live organism eats another organism, which is then eaten by a larger organism. A food chain is created by the transfer of nutrients and energy from one creature to another at various trophic levels.

The feeding habits or connections between living things are also explained by the food chain. Trophic level is the term used to describe the orderly phases in a food chain, from producers at the bottom through primary, secondary, and tertiary consumers. A trophic level is any position along a food chain.

A food chain demonstrates the interdependence of all living things on one another. The direction of energy flow within an ecosystem is described by the food chain.

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How can pressure impact the alignment of minerals within the rock

Answers

Metamorphism occurs because some minerals are stable only under certain conditions of pressure and temperature. When pressure and temperature change, chemical reactions occur to cause the minerals in the rock to change to an assemblage that is stable at the new pressure and temperature conditions.

16.An astronaut, visiting a newly discovered planet, finds the acceleration due to gravity by dropping an objectfrom a height of 1.0 meter and measuring how long it takes the object to hit the ground. If it takes the object0.8 seconds to hit the ground, what is the acceleration due to gravity on th

Answers

Answer:

g = 3.125 m/s²

Explanation:

To find the acceleration due to gravity we will use the second equation of motion:

[tex]h = V_{i}t + \frac{1}{2}gt^{2}\\[/tex]

where,

h = height = 1 m

Vi = initial speed object = 0 m/s (object is initially at rest)

t = time taken = 0.8 s

g = acceleration due to gravity = ?

Therefore,

[tex]1\ m = (0\ m/s)(0.8\ s)+\frac{1}{2}g(0.8\ s)^{2}\\\\\frac{2\ m}{0.64\ s^{2}} = g\\\\[/tex]

g = 3.125 m/s²

Truck pull the car 2350 KG a distance of 25 m. If they car accelerates from 3M/S to 6M/S, what’s the average force exerted on the car

Answers

Answer: 7

Explanation: 7 is the superior number

Answer:

1,269 N

Explanation:

I guessed and got the question right on CK-12's work practice.

It has been suggested that rotating cylinders about 10 mi long and 5.9 mi in diameter be placed in space and used as colonies. The acceleration of gravity is 9.8 m/s 2 . What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on

Answers

Answer:

ω = 0.05 rad/s

Explanation:

We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,

[tex]Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\[/tex]

where,

ω = angular velocity of cylinder = ?

g = required acceleration = 9.8 m/s²

r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m

Therefore,

[tex]\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\[/tex]

ω = 0.05 rad/s

What are the applications of diodes and rectifiers?

Answers

Answer:

The most common and important application of a diode is the rectification of AC power to DC power. Using the diodes, we can construct different types of rectifier circuits. The basic types of these rectifier circuits are half wave, full wave center tapped and full bridge rectifiers.

Explanation:

Here ya go <3

In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number presented in statement B.
1. Statement A: 2.567 km, to two significant figures.
Statement B: 2.567 km, to three significant figures.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
2. Statement A: (2.567 km+ 3.146 km), to two significant figures.
Statement B: (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
3. Statement A: Area of a rectangle with measured length = 2.536 m and width = 1.4 m.
Statement B: Area of a rectangle with measured length = 2.536 m and width = 1.41 m.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.

Answers

Answer:

1)   A> B, 2)  A = B,  3)    A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

        A> B

2) decalration A

         2,567 + 3,146 = 5,713

with two figures it remains

             5.7

statement B

         2.6 + 3.1 = 5.7

 A = B

3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

   2.536 * 1.4 = 3.6

  statement B

    2.536 * 1.41 = 3.58

          A> B

Which of the following is an example of exothermic reaction?

Answers

Explanation:

Exothermic reaction are those in which heat releases during a reaction

what happens to the orbit time as the distance increases.

Answers

The orbital period increases if the orbital distance is increased.

(b) Which statement about beta radiation is true?
Tick one box
It is the fastest moving type of radiation.
It is the type of radiation with a negative charge.
It is the type of radiation with the greatest mass.
It is the type of radiation with the greatest range in air.

Answers

Answer:

is the fastest moving type of radiationhe

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