How does light from a headlamp use a lens and a mirror to produce a narrow beam?

Answers

Answer 1

Answer:

AnSwEr iS BeLoW

Explanation:

Well according to https://van.physics.

The headlamp's concave mirror is open on one end, and the light bulb's filament is placed at or near the focus. Parallel ight rays, if they were coming into the headlamp from outside (say, the driver is driving his car in the direction of the setting sun), would converge near the filament of the light bulb

Hopes this helps :)

Answer 2

When a light bulb is placed at focus , the head lamp as a concave mirror will produce a narrow beam.

What is concave mirror?

Concave mirror is the spherical part of mirror which is painted from outside and the ray falling on this mirror forms a real image.

The concave mirror of headlamp is open on one end, and the bulb filament is placed at the focus. Parallel ight rays from outside will converge to form a narrow beam near the filament of the light bulb.

Thus, When a light bulb is placed at focus , the head lamp as a concave mirror will produce a narrow beam.

Learn more about concave mirror.

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Related Questions

As an object falls the gravitational potential energy of the object is converted into ?

Answers

Answer:

the gravitational potential energy is converted to kinetic energy

Explanation:

Because the conversation of the energy as a tool permits the calculation of the velocity just before it hits the surface

How many neutrons are in He

Answers

There are 2 neutrons in helium.

A proton high above the equator approaches the
Earth moving straight downward with a speed of
365 m/s.
Find the acceleration of the proton, given that the magnetic field at its altitude is 4.10*10^-5 T.

Answers

We can see from the calculations that the acceleration of the proton is 1.43 * 10^7 ms-2.

What is acceleration?

Acceleration is the rate of change of velocity with time. We know that the magnetic force is obtained by;

F = qvB

q= 1.6 * 10^-19 C

v = 365 m/s

B =  4.10*10^-5 T

F = 1.6 * 10^-19 C * 365 m/s *  4.10*10^-5 T

F = 2.39 * 10^-20 N

Recall that the mass of the proton is 1.67 × 10−27 kg hence

a = F/m = 2.39 * 10^-20 N/1.67 × 10−27 kg  = 1.43 * 10^7 ms-2

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what force is required to acceleration a body with a mass of 32 kilograms at a rate of 12 m/s

Answers

Answer:

384 N

Explanation:

F=m×a

F= ?

m= 32kg

a= 12m/s

32×12 = 384 N

N is newton's

hope this helps

Is it possible to hold friendships outside of your designated group Why or Why not?

Answers

Answer: Yes it is possible.

Explanation: The reason is being because, people tend to like to see different stuff. Like in the movie Pocahontas she was a totally different person. And John Smith was a different person too. SO it is possible.

A car starts from rest and travels for 5.0 s with a constant acceleration of
-1.5 m/s. What is the final velocity of the car? How far does the car travel
in this time interval?

Answers

Explanation:

Explanation:

If an object having initial velocity

uExplanation:

If an object having initial velocity

u

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

1.5

m

sec

2

.

Hence final velocity

v

=

1.5

×

5

=

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

1.5

)

×

5

2

=

18.75

m

.

Minus sign indicates that acceleration is in reverse direction.

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

1.5

m

sec

2

.

Hence final velocity

v

=

1.5

×

5

=

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

1.5

)

×

If an object having initial velocity

u

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

1.5

m

sec

2

.

Hence final velocity

v

=

1.5

×

5

=

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

1.5

)

×

5

2

=

18.75

m

.

Minus sign indicates that acceleration is in reverse direction

5

2

=

18.75

m

.

Minus sign indicates that acceleration is in reverse direction.

what is the kinetic energy of an object that has a mass of 12 kg and moves with a velocity of 10 m/s

Answers

Answer:

600 J

Explanation:

The formula to find the kinetic energy of an object is [tex]\frac{1}{2}mV^2[/tex]

m = mass in kgV = velocity in m/sKE is measured in Joules just as all other forms of energy.

Now, let's plug in the variables we're given and simplify.

[tex]\frac{1}{2}(12)(10)^2[/tex] [tex]\frac{1}{2}(12)(100)[/tex] [tex](6)(100)[/tex] [tex](600)[/tex]

Thus, the answer is 600 Joules.

The two rods are now firmly attached together as in Figure 2.
Sketch and explain what would happen they are heated [2 marks) Fixed and Figure 2​

Answers

Thermal equilibrium is attained and the both rods are now at the same temperature.

What is thermal equilibrium?

Two bodies are said to have attained thermal equilibrium when the two bodies at the same temperature. It should be known that when two rods are firmly attached to each other heat flows from one rod to another.

As such, after some time, thermal equilibrium is attained and the both rods are now at the same temperature.

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In scientific terms, anything that represents something else is called a
O theory
O model
O hypotnesis
O chemical bond

Answers

The answer is a model
Please mark brainliest!

The pressure on a volume of liquid V = 1.0 mº at the surface is approximately equal to the atmospheric pressure Patm = 1.00 x 105 N/m2. If this volume of liquid is now
placed at a depth where the pressure is P = 2.30 x 10' N/m², what will be the change in volume of the liquid (in mº)? The bulk modulus of the liquid is 8.0 x 100 N/m².
(Include the appropriate sign with your answer.)
m
Additional Materials

Answers

Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

ΔP = P₂-P₁  ----> ΔP = 2.30*10⁷ - 1.00*10⁵ = 2.29*10⁷

Which of the following states that energy cannot be created or destroyed?

Answers

Answer:

germany

Explanation:

Calculate: a student lifts an apple to a height of 1 m. The apple weighs 1 N. How much work does the student do on the apple? Type out your calculations

Answers

Answer:

1J

Explanation:

Work done = force × distance

1 × 1 = 1

Work done = 1J

J = Joules

What kind of force draws certain types of metal together?
O A. Friction
O B. Nuclear
O C. Magnetic
O D. Weight

Answers

C. Magnetic draws certain types of metal together.

A magnetic force is the answer

Devon is riding his bicycle at 15 m/s. How far will he travel in 12 s?

Answers

Devon will travel 180m in 12 seconds. All you have to do is multiply 15 by 12. Hope this helps

i need help on a english book report

Answers

Answer:

I can help, but

Explanation:

Where is the question?

How does the evolutionary process contradict the second law of thermodynamics?

Answers

Evolution, the argument goes, is a decrease of entropy, because it involves things getting more organized over time, while the second law says that things get more disordered over time. So evolution violates the second law.

why is electromagnet are called temporary magnet
pls its urgent

Answers

Answer: because when you remove the battery, the the magnet no longer has electricity flowing through it, therefore the magnetic field disappears. Thats why its called a temporary magnet

Explanation:

Help me pls, ASAP..
____1. These are motion graphs that show a change in an object’s location over time.

____2. It can show us if an object is going backwards or forwards (direction).

____3. These are useful and effective tools in visually presenting the motion of objects.

____4. It is the line of dots on the tape that is created when a long tape is attached to

an object that is moving.

____5. It is a periodic disturbance that moves away from a source and carries energy with it.

____6. It is the maximum displacement of a particle of the medium on either side of its

normal position when the wave passes.

____7. It is a measurement of how fast the sound wave vibrates.

A. Amplitude
B. Displacement-time graph
C. Frequency
D. Motion graphs
E. Position-time graphs
F. Ticker tape diagram
G. Wave​

Answers

[tex] \qquad \huge \underline{ \boxed{\sf Answer}}[/tex]

Here's the correct choices for the blank questions~

# 1 : position - time graph

#2 : Displacement - time graph

#3 : Motion graphs

#4 : Ticker tape diagram

#5 : Wave

#6 : Amplitude

#7 : Frequency

The answers to the questions are as follows :

Position time graphs ( E ) Displacement time graph ( B )Motion graphs ( D )Ticker tape diagram ( F ) Wave ( G ) Amplitude ( A ) Frequency ( C )

The different types of motion graphs

Position time graphs are motion graphs that show the change in an object position in relation to time traveled, while a displacement time graph shows if an object is going backwards or forward and unlike distance, she does not consider the direction of movement of an object.

Motion graphs are used for the presentation of the motion of objects visually.

Hence we can conclude that the answers to your questions are as listed above.

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right answer gets brainliest, wrong answer gets ignored
The star Sirius has a temperature of 10,700 degrees Celsius and has a luminosity of 23 solar luminosity units. At which letter on the HR Diagram would you place Sirius?

Answers

Answer:

A

Explanation:

Because A looks like it's in the 10,700 degree area and also in the 23 luminosity area.

How does the nature of heat explain the occurrence of high temperature in a human body that has a fever?

Answers

Explanation:

THE BODY INCREASES THE RATE OF HEAT LOSS TO BALANCE THE HEAT BURDEN.

A 2kg rock is at the edge of a cliff 20m above the surface of a lake. It comes loose and falls. Half
way down it is falling at 14 m/s. What is its Kinetic Energy at the moment it hits the water?

Please show work!

Answers

Awesome to see a chainsaw man fan! Here's your answer!

Answer:
Follow:

The potential energy (P.E) at the top is 392 J.The kinetic energy (K.E) at the top is 0 J.The potential energy (P.E) at the halfway point is 196 J.The kinetic energy (K.E) at the halfway point is 196 J.

Explanation:

Facts  - Key Details Given:

mass of the rock: m = 2 kgheight of the cliff: h = 20 mspeed of the rock at the halfway point: v = 14 m/s---------------------------------------------------------------------------------------------------Calculations: #1: The potential energy (P.E) and kinetic energy (K.E) when its at the top;

P.E = mgh

P.E = (2)(9.8)(20)

P.E= 392 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the top of the cliff = 0

K.E = ¹/₂(2)(0)²

K.E = 0

#2: The potential energy (P.E) and kinetic energy (K.E) at the halfway point;

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the halfway point = 14 m/s

K.E = ¹/₂(2)(14)²

K.E = 196 J.

A projectile is launched with an initial speed of 40 mys from the foor of a tunnel whose height is 30 m. What angle of elevation should be used to achieve the maximum possible horizontal range of the projectile?

Answers

Answer:

We are given the trajectory of a projectile:

y=H+xtan(θ)−g2u2x2(1+tan2(θ)),

where H is the initial height, g is the (positive) gravitational constant and u is the initial speed. Since we are looking for the maximum range we set y=0 (i.e. the projectile is on the ground). If we let L=u2/g, then

H+xtan(θ)−12Lx2(1+tan2(θ))=0

Differentiate both sides with respect to θ.

dxdθtan(θ)+xsec2(θ)−[1Lxdxdθ(1+tan2(θ))+12Lx2(2tan(θ)sec2(θ))]=0

Solving for dxdθ yields

dxdθ=xsec2(θ)[xLtan(θ)−1]tan(θ)−xL(1+tan2(θ))

This derivative is 0 when tan(θ)=Lx and hence this corresponds to a critical number θ for the range of the projectile. We should now show that the x value it corresponds to is a maximum, but I'll just assume that's the case. It pretty obvious in the setting of the problem. Finally, we replace tan(θ) with Lx in the second equation from the top and solve for x.

H+L−12Lx2−L2=0.

This leads immediately to x=L2+2LH−−−−−−−−√. The angle θ can now be found easily.

)Which will likely produce a greater amount of static charge: a wool sweater worn under a cotton jacket, or a wool sweater worn under a rubber rain coat? Why?

Answers

A wool sweater worn under a cotton jacket produces more static charges.

What is static charge?

Static charge is an imbalance of electric charges within or on the surface of a material or between materials.

Static charges can be produced by two materials together (friction method).

A wool sweater worn under a cotton jacket (in the absence of lubricant like water) creates friction which enables more static charge to be produced.

Thus, a wool sweater worn under a cotton jacket produces more static charges.

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The mass of an empty density bottle is 2 g. Its mass when filled with water is 4.0 g and 6.0 g when filled with liquid X. Calculate the density of liquid X if the density of water is 1,000 kgm-3.​

Answers

Answer:

density of liquid x = 2000kg/m3

Explanation:

mass of water = mass of bottle with water - mass of bottle

mass of water = 4g - 2g

mass of water = 2g

mass of liquid x = mass of bottle with liquid x - mass of bottle

mass of liquid x = 6g - 2g

mass of liquid x = 4g

since the mass of liquid x is double the mass of the water and the volume of the bottle is the same, the density is doubled

density of liquid x = 1000kg/m3 • 2

density of liquid x = 2000kg/m3

i need help question confuseing

Answers

Answer:

could you tell me what the question is pls, that way I can help you

Explanation:

A rotating lens mechanism blocks the view of the object as the new lenses are rotated. Be sure to click each lense firmly into place. If you do not the field will be only partially visible. What kind of mechanism is on your microscope?

Answers

I think that mechanism is called a "lens turret".

Assuming that (1) the solar luminosity has been constant since the Sun formed, and (2) the Sun was initially of uniform composition throughout, as described by Table 9.2, estimate how long it would take the Sun to convert all of its original hydrogen into helium. [Hint: Calculate the mass of hydrogen in the sun and then divide it by the rate of hydrogen fusion]

Answers

Based on the mass and luminosity of the Sun, the time required to convert of its original hydrogen into helium is 7.505 × 10^10 years.

What is nuclear fusion?

Nuclear fusion is the process whereby nucleus of lighter atoms are fused together to produce heavier atoms with the release of large amounts of energy.

Nuclear fusion occurs at the core of the sun where four hydrogen atoms are fused to form one helium atom with the release considerable energy, and this is known as hydrogen fusion.

The mass of the Sun = 2.0 × 10^30 kg

The Sun’s hydrogen mass is 0.71 × 2.0 × 10^30 kg = 1.42 × 10^30 kg.

The Sun converts 6 × 10^11 kg of hydrogen into helium per second.

Time required to convert all of the Sun's hydrogen to helium = 1.42 × 10^30 kg/6 × 10^11 kg/s

Time required = 2.367 × 10^18 seconds

Converting to years:

3.154 × 10^7 seconds = 1 year

2.367 × 10^18 seconds = 2.367 × 10^18 seconds * 1 year/3.154 × 10^7 seconds

Time required = 7.505 × 10^8 years

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A 10^3 kg load is placed on top of a lead bar of length 3.0 m. If the bar is compressed by 2.0
mm, calculate the cross-sectional area of the bar.

Answers

The cross-sectional area of the lead bar is [tex]9.188 \times 10^{-4} \ m^2[/tex].

Young's modulus of lead bar

The Young's modulus (E)of lead bar is given as 1.6 x 10¹⁰ Pa.

Cross-sectional area of the bar

The cross-sectional area of the bar is calculated as follows;

[tex]E = \frac{stress}{strain} = \frac{F/A}{e/l} = \frac{Fl}{Ae} \\\\A = \frac{Fl}{Ee}[/tex]

where;

A is cross-sectional areaF is applied force due to its weightE is Young's moduluse is compressionl is length

[tex]A = \frac{(mg) l}{Ee} \\\\A = \frac{(10^3 \times 9.8) \times 3}{1.6 \times 10^{10} \times 2 \times 10^{-3}} \\\\A = 9.188 \times 10^{-4} \ m^2[/tex]

Thus, the cross-sectional area of the lead bar is [tex]9.188 \times 10^{-4} \ m^2[/tex].

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Is this an example of outline??And why?​

Answers

Answer:

Yes

Explanation:

You included all the stages of matter and described each of them. You're outlining their properties and you've created a clear diagram (and by diagram I mean chart) of solids, liquids, and gas.

Brainliest if correct

Answers

Answer:

the answer is C. rocket 4.

Explanation:

[tex]a = \frac{f}{m} \\ \\ c) a = \frac{120}{3.25} = 36.923...[/tex]

it's the biggest amongst the four.

rocket one has an acceleration of 34.782...

rocket two has an acceleration of 22.429...

rocket three has an acceleration of 26.666...

rocket four has an acceleration of 36.923

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