ANSWER :
The answer is 20.3971 years
EXPLANATION :
The compounding interest formula is :
[tex]FV=PV(1+\frac{r}{n})^{nt}[/tex]where :
FV = future value ($6800)
PV = present value ($2900)
r = rate of interest (4.2% or 0.042)
n = number of compounding in a year (4 : compounded quarterly)
t = time in years
Using the formula above :
[tex]6800=2900(1+\frac{0.042}{4})^{4t}[/tex]Solve for t :
[tex]\begin{gathered} \frac{6800}{2900}=(1.0105)^{4t} \\ \text{ take ln of both sides :} \\ \ln(\frac{6800}{2900})=\ln(1.0105)^{4t} \\ \operatorname{\ln}(\frac{6800}{2900})=4t\operatorname{\ln}(1.0105) \\ 4t=\frac{\ln(\frac{6800}{2900})}{\ln(1.0105)} \\ t=\frac{\ln(\frac{6800}{2900})}{4\ln(1.0105)} \\ t=20.3971 \end{gathered}[/tex]how much must be deposited at the beginning of every six months in account that pays 6% compounded semi-annually so that account will contain 21,000 at the end of three years
The formula for Final Amount, A after compounding for n period of times is given by
[tex]A=p(1+\frac{r}{100})^n[/tex]Where A = amount
p= principal
r = rate (in %)
n = number of compounding periods
From the question.
A=21,000, p = ?, r=6, n = 3 x 2 = 6
[tex]\begin{gathered} 21000=p(1+\frac{6}{100})6 \\ \\ 21000=p(1+0.06)^6 \\ 21000=p(1.06)6 \\ 21000=p(1.41852) \\ 21000=1.41852p \\ p=\frac{21000}{1.41852} \\ p=14,804.17 \end{gathered}[/tex]The amount that must be deposited at the beginning is 14,804.17
Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent% markdown = 40Reduced price = $144$ markdown = ?
The given information:
% mark up = 40
Reduced = $144
Markdown = ?
The formula for percentage markup is given as
[tex]\text{ \%markup }=\frac{markup}{actual\text{ price}}\times100[/tex]Let the actual price be x
Hence,
Reduced price = 60% of actual price
[tex]60\text{\% of x = 144}[/tex]Solving for x
[tex]\begin{gathered} \frac{60x}{100}=144 \\ x=\frac{144\times100}{60} \\ x=240 \end{gathered}[/tex]Therefore, actual price = $240
Inserting these values into the %markup formula gives
[tex]40=\frac{\text{markup}}{240}\times100[/tex]Solve for markup
[tex]\begin{gathered} 40=\frac{100\times\text{markup}}{240} \\ 40\times240=100\times\text{markup} \\ \text{markup}=\frac{40\times240}{100} \\ \text{markup}=96 \end{gathered}[/tex]Threefore, markup = $96
Line segment AB is on square ABCD. Segment EF on equilateral triangle EFG is 12 units longer than AB. Square ABCD and triangle EFG have equal perimeters. What is the length of AB?
The length of segment AB when the line segment AB is on square ABCD is 36 units.
What is the length of segment AB?From the task content, the length of the line segment AB which is a side of the square ABCD is to be determined.
In this case, since the perimeters of triangle EFG and square ABCD are equal as given;
Let the length of segment AB = x.
Therefore, EF = x + 12.
Therefore, the perimeter of the equilateral triangle = 3(x +12).
While the perimeter of square ABCD is; 4x.
Therefore, since the perimeters are equal, we equate them and this will be:
3(x + 12) = 4x
3x + 36 = 4x
36 = x.
Therefore, the length is 36 units.
Read more on Perimeter of squares;
https://brainly.com/question/2437195
#SPJ1
5|x +1| + 7 = 38
Solve for x
Answer: No solutions
Step-by-step explanation:
[tex]5|x+1|+7=-38\\\\5|x+1|=-45\\\\|x+1|=-9[/tex]
However, as absolute value is non-negative, there are no solutions.
Transformations that preserve shape and size are called rigid motions. Find a definition of just the word rigid using the internet and write it below.
Simply put,
Rigid means not moving.
In transformations, rigid motions are transformations that preserve distance.
You choose a marble from the bag. What is the probability you will NOT choose blue?1/25/72/72
Given a sample and required to get the probability of a particular outcome, we make a couple of considerations including:
- Sample Space: The universal set
- Required Outcome
We can identify these variables as:
Sample space: total number of marbles = 7
Required outcome: Not blue = 7 - 2 = 5
Probability is given as:
[tex]\begin{gathered} P=\text{ }\frac{\text{number of required outcome}}{Sample\text{ space}}=\frac{5}{7} \\ P=\frac{5}{7} \end{gathered}[/tex]The table shows a function. Is the function linear or nonlinear?x y0 1918 1200
By plotting the points, we get a non-linear function
help in this question
A vertex is a point on a polygon where two rays or line segments meet, the sides, or the edges of the object come together. Vertex is the plural form of vertices.
A vertex example is what?f(x)=3(x−1)2
Find the given parabola's characteristics.
Lessen the steps you tap...
Vertex form is to be used, y=a(x−h)2+k,
to calculate the values of a, h, and k.
a=3
h=1
k=0
The parabola widens because the value of an is positive.
opens up
Find the (h,k) vertex. ( 1 , 0 )
Calculate p, the distance between the focus and the vertex.
To continue, tap...
1/ 12
Locate your focus.
To continue, tap... ( 1 , 1/ 12 )
By identifying the line that connects the vertex with the focus, you may determine the axis of symmetry.
x = 1
The horizontal line that results from deducting p from the vertex's y-coordinate k depends on whether the parabola opens up or down. This line is known as the directrix.
y = k − p
Simplify the formula after substituting the known p and k values.
y = − 1 /12
Analyze and graph the parabola using its characteristics.
Direction: opens up
vertices: ( 1, 0 )
Focus: ( 1 , 1 /12 )
x = 1 is the symmetry axis.
Direction: y = /1 12.
To Learn more About vertex ,Refer:
https://brainly.com/question/21185651
#SPJ13
A student entering a doctoral program in educational psychology is required to select two courses from the list provided as part of his or her program (a)List all possible two-course selections (b)Comment on the likelihood that you EPR 625 and EPR 686 will be selected The course list EPR 613, EPR 664, EPR 625, EPR 685, EPR 686(a)select all the possible two-course selections belowA. 613, 686B. 625,686C. 613,613,664D. 664,685E. 625,685F. 625,672G. 613,625H. 685,686I. 664,625J 686,686K. 613,613L. 613,685M. 664, 686N. 613,664
List of courses that the student entering a doctoral program in educational psychology can take:
EPR 613, EPR 664, EPR 625, EPR 685, EPR 686
Therefore, the possible two-course selections for the student are:
A. Both courses are on the list given: 613, 686
B. Both courses are on the list given: 625, 686
C. It's not possible. This option contains three courses.
D. Both courses are on the list given: 664, 685
E. Both courses are on the list given: 625, 685
F. It's not possible, Course 672 isn't available.
G. Both courses are on the list given: 613, 625
H. Both courses are on the list given: 685, 686
I. Both courses are on the list given: 664, 625
J. It's not possible. Just one course is given.
K. Same case than J. Just one course.
L. Both courses are on the list given: 613, 685
M. Both courses are on the list given: 664, 686
N. Both courses are on the list given: 613, 664
Caitlyn is 160 centimeters tall. How tall is she in feet and inches, rounded to the nearest inch?
Answer:
5 ft 3 in.
Explanation:
First, recall the standard conversion rates below.
• 1 foot = 30.48 cm
,• 1 foot = 12 inches
First, convert 160 cm to feet.
[tex]\begin{gathered} \frac{1ft}{30.48\operatorname{cm}}=\frac{x\text{ ft}}{160\text{ cm}} \\ 30.48x=160 \\ x=\frac{160}{30.48} \\ x=5.2493\text{ ft} \\ x=(5+0.2493)\text{ ft} \end{gathered}[/tex]Next, we convert the decimal part (0.2493 ft) of the result above to inches.
[tex]\begin{gathered} 1ft=12\text{ inches} \\ \frac{1\text{ ft}}{12\text{ inches}}=\frac{0.2493\text{ ft}}{y\text{ inches}} \\ y=0.2493\times12 \\ y=2.9916 \\ y\approx3\text{ inches (to the nearest inch)} \end{gathered}[/tex]Therefore, 160 centimeters in feet and inches is:
[tex]5\text{ feet 3 inches}[/tex]the vertices of ABC and the endpoints of DE have coordinates that are integers. Determine the coordinates of point F so That ABC≈DEFOPTIONS:(-7, 1)(-5, 3)(-7, -8)(-2, -8)
We want figure EDF≈ABC.
We can see that if we rotate figure ABC we will obtain the following:
If we rotate it we can see that the segment AB is exactly as the segment ED.
We can now find the answer if we look how far is the point C, we see it is three unities up from B and 5 unities to its left. Then F must be 3 unities up from E and 5 unities to its left.
Since E is located :
at y = -2 if we go up 3 unities
-2 + 3 = 1
at x = -2 if we go at its left 5 unities then
-2 - 5 = -7
Then, F must be at x = -7 and y = 1.
Answer: (-7, 1)1. A train moves at a constant speed and travels 6 miles in 4 minutes. What is its speed in miles per minute? d/t = r time distance t d 4 mins. 6 miles
Answer: 1.5 miles / minute
Given that:
Distance travelled = 6
Time = 4 minutes
Speed = Distance / time
Speed = 6 / 4
1.5 mile / minute
in a public opinion poll 624 people from a sample of 1100 indicated they would vote for specific candidate how many votes can the candidate expect to receive from a population of 40000
Hello!
In a sample of 1100 people, the specific candidate got 624 votes. So, we can write it as 624/1100.
And if the total of voters is 40,000, how many votes this specific candidate will receive? We can write it as x/40,000.
Now, let's equal both fractions look:
[tex]\begin{gathered} \frac{624}{1100}=\frac{x}{40000} \\ \\ 1100x=624\times40000 \\ 1100x=24960000 \\ x=\frac{24960000}{1100} \\ \\ x\cong22691 \end{gathered}[/tex]Answer:Approximately 22691 votes.
kenny has red marbles, 3 blue marbles,and 4 black marbes. Which ration compares a part to the whole? Please help me
A ratio comparing a part to the whole must then have 9 as the second number.
In this question, we have been given Kenny has red marbles, 3 blue marbles, and 4 black marbles.
We need to find the ratio that compares a part to the whole.
Here, the total number of marbles are:
2 red + 3 blue + 4 black = 9 marbles.
Let x be either number of marbles (either red marbles or blue marbles or black marbles)
Then the ratio that compares a part to the whole would be,
x : 9
Therefore, a ratio comparing a part to the whole must then have 9 as the second number.
Learn more about the ratio here:
https://brainly.com/question/25184743
#SPJ1
If TRAP is an isosceles trapezoid, what is the value of x?A. 1B. 22C. 12D. 23E. 11F. Cannot be determined
In an Isosceles trapezoid, it is known that the base angles have equal measures, and non-congruent angles are supplementary.
The non-congruent angles ∠RAP and ∠APTfrom the figure have measures 6x° and (2x+4)°, respectively.
Since they must be supplementary, it follows that their sum is 180°:
[tex]\begin{gathered} 6x+2x+4=180 \\ \Rightarrow8x+4=180\Rightarrow8x=180-4 \\ \Rightarrow8x=176\Rightarrow\frac{8x}{8}=\frac{176}{8} \\ \Rightarrow x=22 \end{gathered}[/tex]Hence, the value of x is 22. The correct option is B.
Answer:B
Step-by-step explanation:just took the test
The function is defined by h(x) = x - 2 . Find h(n + 1) .
SOLUTION:
Case: Functions
Method:
The function
[tex]\begin{gathered} h(x)=x-2 \\ Hence \\ h(n+1)=(n+1)-2 \\ h(n+1)=n+1-2 \\ h(n+1)=n-1 \end{gathered}[/tex]Final answer:
[tex]h(n+1)=n-1[/tex]Tommy paid $8.25 for three pounds of gummy candy.Tommy created a graph from the data on his chart. Is his graph correct? Why or Why not?
Notice that the relationship between the number of pounds of gummy candy and the number of dollars that that number of pounds costs is a function because there cannot be two prices for the same number of pounds.
Now, notice that the graph that Tommy creates does not represent a function because it fails the vertical line test at x=3.
Also, from the given table we get that (4,11) is a point of the graph.
Then the graph that Tommy creates is not correct.
Answer: No, because the graph does not represent a function and the point (4,11) is not part of the graph.
0.75 greater than 1/2
True
0.75 is greater than 0.5
Explanation
Step 1
remember
[tex]\frac{a}{b}=\text{ a divided by b}[/tex]then
[tex]\frac{1}{2}=\text{ 1 divided by 2 = 0.5}[/tex]Step 2
compare
0.75 and 0.5
[tex]0.75\text{ is greater than 0.5}[/tex]I hope this helps you
FOR GREATER THAN WE ADD THE TERMS.
MATHEMATICALLY THIS MEANS
[tex] = 0.75 + \frac{1}{2} \\ = 0.75 + 0.5 \\ = 1.25[/tex]
1.25 is the answer.
How many different committees can be formed from 12 teachers and 32 students if the committee consists of 3 teachers and 2 students?
Answer: 4 committees
Step-by-step explanation:
12 divided by 3 = 4 (this equation represents the teachers)
2 x 4 = 8 (this equation represents the students)
There can only be 4 committees because there are only 12 teachers. There are some students that will not be in a committee. 24 students will be committee-less to be exact.
Gary is saving money to buy a ticket to a New York Jets game that costs $225. Healready has saved $18. What is the least amount of money Gary must save each week, sothat at the end of 9 weeks he has enough money to buy the ticket? (Only an algebraic- solution will be accepted.)
lillyvong13, this is the solution:
Cost of the ticket to a New York Jets game = $ 225
Savings up to now = $ 18
Difference = 225-18 = 207
Number of weeks = 9
Let x to represent the amount of money Gary must save each week for buying the ticket, as follows:
x = 207/9
x = 23
Gary must save $ 23 at the end of 9 weeks to have enough money to buy the ticket
Find the mean: 16,12,15,10,7,916
You can calculate the mean by using the formula:
Mean=sum of values/number of values
Then,
[tex]undefined[/tex]determine the point and slope that were used to write each linear equation in point slope form
The slope-point form is:
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point in the line and m is the slope.
A) If the equation is written in slope-point form, we have:
[tex]y-0=2(x-5)[/tex]Then, the point is (5,0) and the slope is m=2.
Answer: Point = (5,0)
Slope = 2
B)
[tex]\begin{gathered} y+3=5x \\ y-(-3)=5(x-0) \end{gathered}[/tex]Answer: Point (0,-3)
Slope = 5
Z A I + 5 4x - 3 3r-1 2x + 1 What value of x makes ASTW - AXYZ? s 3 + 1 T 4r-5 x = 2 X = 3 X=4 X=1
Here, we have two congruent triangles.
Given:
ST = 3x - 1 XY = 4x - 5
SW = 3x + 1 XZ = 4x - 3
TW = 2x + 1 YZ = x + 5
Since triangle STW and triangle XYZ are congruent, they have exactly the same corresponding sides.
To find the value of x, equate the corresponding sides and evaluate.
ST = XY
SW = XZ
TW = YZ
Take one of the corresponding sides.
We have:
ST = XY
3x - 1 = 4x - 5
Subtract 4x from both sides:
3x - 4x - 1 = 4x - 4x - 5
-x - 1 = -5
Add 1 to both sides:
-x - 1 + 1 = -5 + 1
-x = -4
Divide both sides by -1:
[tex]\begin{gathered} \frac{-x}{-1}=\frac{-4}{-1} \\ \\ x=4 \end{gathered}[/tex]Therefore, the value of x that makes ΔSTW ≅ ΔXYZ is 4
ANSWER:
x = 4
Find the sum of the first 39 terms of the following series, to the nearest integer.2,7, 12,...
The sequence 2,7,12,... given is an arithmetic progression. This is because it has a common difference.
Given:
first term, a = 2
common difference, d = second term - first term = 7 - 2 = 5
d = 5
n = 38
The sum of an arithmetic progression is given by;
[tex]\begin{gathered} S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack \\ S_{38}=\frac{38}{2}\lbrack2(2)+(38-1)5\rbrack \\ S_{38}=19\lbrack4+37(5)\rbrack \\ S_{38}=19\lbrack4+185\rbrack \\ S_{38}=19(189) \\ S_{38}=3591 \end{gathered}[/tex]Therefore, the sum of the first 39 terms of the series is 3,591
1. Write a linear equation of the form y1 = mx + b for your first set of data.2. Write a linear equation of the form y2 = mx + b for the other equation in your system. 3. Graph and explain the solution.
Given:
Company A: transport 56 people in one hour for $40 per person in 30 minutes
Company B:
Solve radical∛x²-8=4
Let's determine the value of x on the given radical expression:
[tex]\text{ }\sqrt[3]{x^2-8}\text{ = 4}[/tex]Enter a rule for each function f and g, and then compare their domains, ranges, slopes, and y-intercepts.The function f(x) has a slope of -2 and has a y-intercept of 3. The graph shows the function g(x).
The rule of the function f(x) is : -2x + 3
To find the rule of the function g(x) let's calculate the slope of the line
[tex]m=\frac{y2-y1}{x2-x1}=\frac{-11-5}{4-0}=\frac{-16}{4}=-4[/tex]The slope of the line is -4 and the intercept is 5 ( from the graph).
The rule of the function g(x) is : -4x + 5
The domains of f(x) and g(x) is All real numbers, because there is not any number of x which doesn't have a corresponding y-coordinate.
The ranges of f(x) and g(x) is All real numbers, because there is not any number of y which doesn't have a corresponding x-coordinate.
The slope of f(x) is greater than g(x) (-2 is greater than -4)
The y-intercept of f(x) is less than the y-intercept of g(x).(3 is less than 5)
What is the sign of when x > 0 and y < 0 ?
The number line always goes from negative to positive :
It increases from left to right
SInce negative is always on the left side of the zero
Snumber greater than zero are always positive
i.e. x > o
Given the graph of f (x), determine the domain of f –1(x).
Radical function f of x that increases from the point negative 3 comma negative 2 and passes through the points 1 comma 0 and 6 comma 1
The domain of the function f(x) that has a range of [-2, ∞) is [-2, ∞)
What is the inverse of a function?The inverse of a function that maps x into y, maps y into x.
The given coordinates of the points on the radical function, f(x) are; (-3, -2), (1, 0), (6, 1)
To determine the domain of
[tex] {f}^{ - 1}( x)[/tex]
The graph of the inverse of a function is given by the reflection of the graph of the function across the line y = x
The reflection of the point (x, y) across the line y = x, gives the point (y, x)
The points on the graph of the inverse of the function, f(x), [tex] {f}^{ - 1} (x)[/tex] are therefore;
[tex]( - 3, \: - 2) \: \underrightarrow{R_{(y=x)}} \: ( - 2, \: - 3)[/tex]
[tex]( 1, \: 0) \: \underrightarrow{R_{(y=x)}} \: ( 0, \: 1)[/tex]
( 6, \: 1) \: \underrightarrow{R_{(y=x)}} \: ( 1, \: 6)
The coordinates of the points on the graph of the inverse of the function, f(x) are; (-2, -3), (1, 0), (1, 6)
Given that the coordinate of point (x, y) on the image of the inverse function is (y, x), and that the graph of the function, f(x) starts at the point (-3, -2) and is increasing to infinity, (∞, ∞), such that the range of y–values is [-2, ∞) the inverse function, [tex] {f}^{ - 1}( x)[/tex], which starts at the point (-2, -3) continues to infinity, has a domain that is the same as the range of f(x), which gives;
The domain of the inverse of the function, [tex] {f}^{ - 1}( x)[/tex], using interval notation is; [-2, ∞)
Learn more about the inverse of a function here:
https://brainly.com/question/3831584
#SPJ1
the inside diameter (I.D.) and outside diameter (O.D.) of a pope are shown in the figure. The wall thickness of the pope is the dimension labeled t. Calculate the wall thickness of the pipe if its I.D. is 0.599 in. and its O.D. is 1.315 in.
Given:
The inside diameter of the pope, I.D.=0.599 in.
The outside diameter of the pope, O.D.=1.315 in.
The inside radius of the pope is,
[tex]IR=\frac{ID}{2}=\frac{0.599}{2}=0.2995\text{ in}[/tex]The outside radius of the pope is,
[tex]OR=\frac{OD}{2}=\frac{1.315}{2}=0.6575\text{ in}[/tex]The wall thickness of the pope can be calculated as,
[tex]t=OR-IR=0.6575-0.2995=0.358\text{ in}[/tex]Therefore, the wall thickness of the pope is t=0.358 in.
