how many atoms are in the glucose chemical formula C6, H12, O6 ?

Answer: I think the answer is C. NaCl and H2O

Explanation: I’m not sure tho

Answer:

C) - Water and a Salt

Explanation:

Because Water and a Salt are the products of a neutralization reaction between an acid and a hydroxide base.

Answer:

$17

Explanation:

$4.75 is equal to 0.75 * x value, where x is the weekly allowance

$4.75=0.75x

$17=x

Answer:

it is the seed being planted into the soil

Explanation:

Answer:

C. It is the seed being planted into the soil.

Explanation:

Answer:

[tex] \frac{0.200 \times 320}{57} = .112[/tex]

Hope this helps

The concentration of 25 ml barium hydroxide required to neutralize 32 ml of 0.200 M nitric acid is 0.256 M.

Neutralization is the reaction of acid with base to form a salt of neutrality. The salt formed is not acidic or basic.

In the given reaction, barium hydroxide is a base and nitric acid is the acid and they forms barium nitrate and water.

If the volume and molarity of a solution is given and the molarity or volume either one of the second solution is given, then the unknown quantity of the second solution can be calculated as follows:

M₁V₁ = M₂V₂

Where, M₁ and V₁ is the molarity and volume respectively of first solution and   M₂ and V₂ be that of second solution.

The molarity and volume of nitric acid is 0.200 M and 32.0 ml. Volume of nitric acid is given 25 ml. Thus the molarity of nitric acid is calculated as follows:

Volume of nitric acid = (32 ml × 0.200 M) /25 ml

                                   = 0.256 M

Therefore, the concentration of barium hydroxide required to neutralize 0.200 M nitric acid 0.256 M.

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Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition  for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

Answer:

The empirical formula is C3H4O which would have a formula mass of 56 g/mol (numerically the same as 56 amu/molecule). With a molar mass of 112.

The rate of reaction would change by a factor of 1  if [C] is tripled.

We know that the rate law is a relationship that shows the connection that exists between the reactants and the products in a given reaction. Now we know that species that appear in the rate law are the species who actually participate in the reaction. If there is any specie that does not participate in the rate determining step of the reaction then it does not in any way appear in the rate determining step of the reaction.

We have the reaction equation as;  A + 2B + C → Products

The we have the rate law for the reaction as;  Rate = k[A]²[B]

We can see that C dos not appear in the rate law thus the formation of the product is independent of the concentration of C.

Thus, the rate of reaction would change by a factor of 1  if [C] is tripled.

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Concentration of H+ ions in HNO3 solution is 10⁻¹ which is equal to 0.1 M

[tex] \bf \: pH \: = - log[{h}^{ + }][/tex]

putting the value we get

[tex] \sf \dashrightarrow \: pH \: = - log \: [ \frac{1}{10}] \\ \\ \sf \dashrightarrow \: pH \: = - log \: {10}^{ - 1} \\ \\ \sf \dashrightarrow \: pH \: = 1[/tex]

So, the required option is A) 1

Answer: 2N2H4 + (CH3)2N2H2 + 3N204 → 6N2 + 2CO2 + 8H20.

Explanation:

As per the balanced reaction,  3 moles of N₂O₄ is needed one mole of dimethyl hydrazine and  2 moles of hydrazine. Thus, it is the limiting reactant. The amount of water produced by this reaction will be 2021.73 Kg.

The reactant which is has fewer number of moles in a reaction and thus, it determines the yields of products is called the limiting reactant. In the given reaction, 2 moles of hydrazine requires 3 moles of nitrogen oxide.

Molar mass of hydrazine = 32 g/mol.

2 moles = 64 g.

Molar mass of N₂O₄ = 60 g/mol

3 moles = 276 g.

64 g needs 276 g. Thus mass of N₂O₄ needed for 1200 Kg is

= (1200000 g × 276 g)/ 64 g

= 5175 Kg

But we have only 4500 Kg N₂O₄ . Thus it is the limiting reactant.  276 g of N₂O₄  produces 8 moles or 124 g of water. Thus mass  of water produced by 4500 kg of N₂O₄  is  calculated as follows:

mass of water =  (4500000 g × 124 g) / 276

                        = 2021.73 Kg.

Therefore, there will be 2021.7 g of water left in the lunar atmosphere through this reaction.

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Petrified fossils are made of minerals that have replaced the original matter from wood. Petrified fossils are really rock.

These are the fossils that are obtained when there is porous wooden material present and wood from that material is replaced by organic material from minerals.

It is very much similar to creating a mold or statue of what was once there. Very common example is of trees or wood that become petrified fossils, the trees or wood generally turn to stone.

Petrified Wood gets its name from the Greek word “petro” that says the phrase “wood turned to stone” because Petrified Wood is nothing but a stone. When organic material is overrun with minerals such as quartz or silicate, the preservation of the fossil is made possible.

Therefore, Petrified fossils are made of minerals that have replaced the original matter from wood. Petrified fossils are really rock.

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To avoid being spotted, some deep-sea animals use bioluminescence as a cloaking device. Hatchet fish have light-producing organs in rows along their bellies that allow them to avoid detection — a strategy called counter illumination. These organs shine a pale blue light that matches daylight filtering down from above.

Bioluminescence is light produced by a chemical reaction within a living organism.

Bioluminescence is therefore a certain type of chemiluminescence, which is the term used for a chemical reaction where light is produced, but we use bioluminescence because this reaction is taking place inside a living organism.

Most bioluminescent organisms are found in the ocean. These bioluminescent marine species include fish, bacteria, and jellies.

Therefore, To avoid being spotted, some deep-sea animals use bioluminescence as a cloaking device. Hatchet fish have light-producing organs in rows along their bellies that allow them to avoid detection — a strategy called counter illumination. These organs shine a pale blue light that matches daylight filtering down from above.

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Answer:

An increase in the carbon dioxide concentration increases the rate at which carbon is incorporated into carbohydrate in the light-independent reaction, and so the rate of photosynthesis generally increases until limited by another factor.

Explanation:

After one half life initial amounts gets half so :-

so at last of third half life amount left = 43.75 grams

each time amount get half

ask ure doubt freely in comments

Answer:Biopolymer: the monomeric amino acids are linked through an

amide bond (the carboxylic acids of one AA with the α-amino

group of a second)

Explanation:

In this reaction, elimination of water molecule takes place, therefore this reaction is elimination reaction. So, option C is correct.

In a one- or two-step method, two substituents are removed from a molecule in an organic reaction known as an elimination reaction. The E2 reaction is the name given to the one-step mechanism, and the E1 reaction to the two-step mechanism.

Dehydration and oxidation are the two basic techniques used in this kind of process. Dehydrohalogenation. Because it allows us to remove one of the variables and answer a more straightforward equation.

The halogenoalkane and either sodium or potassium hydroxide solution are the same chemicals you use for replacement or elimination.

Thus, option C is correct.

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Answer:

Most of the food energy that enters a trophic level is "lost" as heat when it is used by organisms to power the normal activities of life. Thus, the higher the trophic level on the pyramid, the lower the amount of available energy.

Explanation:

Answer:

NaS2 it is the most stable

The losses in the pipe increases the power requirement of the pipe to

maintain a given flowrate.

Responses (approximate value);

(a) 2.598 m/s

(b) 181,058.58

(c) 0.025

(d) 227:1000

(e) 1,216.67 W

The given parameters are;

Pump efficiency, η = 80%

Length of the pipe, L = 15 m

Cross-sectional diameter, d = 7 cm

Reservoir temperature, T = 20°C = 293.15 K

[tex]\mathbf{K_{entrance}}[/tex] ≈ [tex]\mathbf{K_{exit}}[/tex] ≈ 1.0, [tex]\mathbf{K_{elbow}}[/tex] ≈ 0.4

Volumetric flow rate, Q = 10 Liters/s = 0.01 m³/s

Surface roughness, ∈ = 0.15 mm

(a) The cross sectional area of the pipe, A = π·r²

Where;

[tex]r = \mathbf{\dfrac{d}{2}}[/tex]

Which gives;

[tex]r = \dfrac{0.07 \, cm}{2} = \mathbf{0.035 \, cm}[/tex]

[tex]Average \ water \ velocity, \ v =\mathbf{ \dfrac{Q}{A}}[/tex]

Therefore;

[tex]v = \dfrac{0.01}{ \pi \times 0.035^2} \approx 2.598[/tex]

(b) The viscosity of water at 20°C is 0.001003 kg/(m·s) given as follows;

Density of water at 20°C, ρ = 998.23 kg/m³

Reynolds' number, Re, is found as follows;

[tex]Re = \mathbf{\dfrac{\rho \cdot V \cdot D}{\mu}}[/tex]

Which gives;

(c) The friction factor is given by the following formula;

[tex]\dfrac{1}{\sqrt{f} } = \mathbf{-2.0 \cdot log \left(\dfrac{\epsilon/D}{3.7} + \dfrac{5.74}{Re^{0.9}} } \right)}[/tex]

Which gives;

(d) Friction head loss is given as follows;

[tex]h_f = \mathbf{f \times \dfrac{L}{D} \times \dfrac{V^2}{2 \cdot g}}[/tex]

Which gives;

[tex]h_f = 0.025 \times \dfrac{15}{0.07} \times \dfrac{2.598^2}{2 \times 9.81} \approx \mathbf{1.84}[/tex]

[tex]Other \ head \ losses, \ h_l= \sum K \cdot \dfrac{V^2}{2}[/tex]

Which gives;

[tex]h_l=(1 + 1+0.4) \times \dfrac{ 2.598^2}{2} \approx \mathbf{8.0995}[/tex]

Ratio between friction head loss and other head loss is therefore;

(e) The power required P is found as follows;

[tex]P= \mathbf{ \dfrac{\rho \cdot g \cdot Q \cdot H}{\eta}}[/tex]

Which gives;

[tex]P= \dfrac{998.23 \times 9.81 \times 0.01 \times (1.84 + 8.0995)}{0.8} \approx \mathbf{ 1216.67}[/tex]

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Answer:

La masa de 2,23×10²³ átomos de azufre es 11,85 g

A partir de una comprensión detallada de la hipótesis de Avogadro, entendimos que 1 mol de cualquier sustancia contiene 6,02 × 10²³ átomos.

La afirmación anterior implica que:

6,02×10²³ átomos = 1 mol de azufre

Recordar :

1 mol de azufre = 32 g

Así, podemos decir que:

6,02×10²³ átomos = 32 g de azufre

Con la información anterior , podemos obtener la masa de 2,23×10²³ átomos de azufre. Esto se puede obtener de la siguiente manera:

6,02×10²³ átomos = 32 g de azufre

Por lo tanto,

2,23×10²³ átomos = *la imagen*

2,23×10²³ átomos = 11,85 g de azufre

Así, la masa de 2,23×10²³ átomos de azufre es 11,85 g

Explanation:

The mass of 2.23×10²³ sulfur atoms is 11.85 g

From a detailed understanding of Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02 × 10²³ atoms.

The above statement implies that:

6.02×10²³ atoms = 1 mole of sulfur

Remember :

1 mole of sulfur = 32 g

Thus, we can say that:

6.02×10²³ atoms = 32 g of sulfur

With the above information, we can obtain the mass of 2.23×10²³ sulfur atoms. This can be obtained as follows:

6.02×10²³ atoms = 32 g of sulfur

Therefore,

2.23×10²³ atoms =*the picture*

2.23×10²³ atoms = 11.85 g of sulfur

Thus, the mass of 2.23×10²³ sulfur atoms is 11.85 g

Taking into account the definition of Avogadro's number, 0.116 moles of acetic acid are in the sample.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of carbon, then 1.40×10²³ atoms are contained in how many moles of carbon?

amount of moles of carbon= (1.40×10²³ atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of carbon= 0.232 moles

So, the amount of moles of carbon in acetic acid that contains 1.40×10²³ carbon atoms is 0.232 moles.

On the other side, the small subscripts placed to the right of some symbol indicate the number of moles of the element that are found in the compound.

So, in pure acetic acid, CH₃COOH, are present 2 moles of carbon in 1 mole of acetic acid.

Then you can apply the following rule of three: if 2 moles of carbon are present in 1 mole of acetic acid, then 0.232 moles of carbon are contained in how many moles of acetic acid?

[tex]amount of moles of acetic acid=\frac{0.232 moles of carbonx1 mole of acetic acid}{2 moles of carbon}[/tex]

amount of moles of acetic acid= 0.116 moles

In summary, 0.116 moles of acetic acid are in the sample.

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The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

The moles of reactant and product in a chemical reaction to the whole number ratio is given by the stoichiometric coefficient of the balanced chemical equation.

Answer:

1.1C3H8 + 5.5O2 --> 3.3CO2  + 4.4H2O

Explanation:

You insert the 3.3 next to CO2. The easiest now is to calculate the carbon on the reactant side.

You already have 3 carbon but need 3.3 so if you calculate 3.3/3=1.1

Carbons are now equal on both sides.

Now look at hydrogen. At the reactant side, you have 1.1*8= 8.8 of H.

You need to make equal on product side. do 8.8/2 =4.4 so you put the 4.4 in front of h2o.

last bit is oxygen. on the product side you have (3.3*2) +(4.4*1) = 11 oxygen.

You just need to make that equal on the reactant side now. you already have 2 oxygen so you times it by 5.5.

voila. hope you follow.

Answer:

At the nucleus point of a substance, the particles have enough kinetic energy to break free from their fixed positions.

Answer : nucleus

Based on the mass given, the value of P in the N - P - K designation is 32.

The percentage mass composition of an element is the mass percent ofbthe element in the the total mass of the compound.

Since the fertilizer contains 1.2 g of phosphorus as P2O5.

Molar mass of P2O5 = 142 g

mass percent of P in P2O5 = 2 × 31/142 = 43.6%

mass of P2O5 in 8.6 g fertilizer = 100/43.6 × 1.2 = 2.75 g

Mass percent of P2O5 = 2.75/8.6 × 100% = 32.0%

Therefore, the value of P in the N - P - K designation is 32.

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Answer:

1. Label Each Compound With a Variable

  aLi3N + bNH4NO3 = cLiNO3 + d(NH4)3N

2. Create a System of Equations, One Per Element

  Li: 3a + 0b = 1c + 0d

  N: 1a + 2b = 1c + 4d

  H: 0a + 4b = 0c + 12d

  O: 0a + 3b = 3c + 0d

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 3

  c = 3

  d = 1

Explanation:

In order to make a buffer that was 2 pH away from the pka, what you have to do is to dilute the buffer.

If the buffer was made using a base and an acid, then there can be an adjustment through the use of hydrochloric acid.

It can also be adjusted to the value that you want through the use of base such as sodium hydroxide

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Answer:

Explanation: