How many different lineups can Coach Lay create using 10 girls to fill 5 spots on the basketball court. Positions do not matter.

Answers

Answer 1

This is the formula for combinations

In this case, n = 10 and k = 5

C = 10!/(10-5)!(5)! = 3628800/(120)(120) = 3628800/14400 = 252

Answer:

252 different line u

How Many Different Lineups Can Coach Lay Create Using 10 Girls To Fill 5 Spots On The Basketball Court.

Related Questions

What is the value of x? Enter your answer in the box. x =

Answers

Step-by-step explanation:

it is an equilateral triangle : all 3 sides are if equal length (indicated by the same symbol on each side).

automatically with that comes the conclusion that all 3 angles have the same size.

and since the sum of all angles in a triangle is always 180°, this means every angle is 180/3 = 60°.

therefore,

2x - 4 = 60

2x = 64

x = 32

and FYI

5y = 60

y = 12

L Pretest: Unit 2Question 5 of 21Which of the following represents the factorization of the polynomial functiongraphed below? (Assume it has no constant factor.)55

Answers

[tex]B)\:y=(x-1)(x-3)[/tex]

1) The best way to tackle questions like this is to locate the x-intercepts. Since according to the options the leading coefficient is 1, we just need to locate the zeroes and plug them into the quadratic equation form, in its factored form.

2) So now, let's write out the factored form and plug the zeroes into them:

[tex]\begin{gathered} y=a(x-x_1)(x-x_2) \\ y=1(x-1)(x-3) \\ y=(x-1)(x-3) \end{gathered}[/tex]

Eliana drove her car 81 km and used 9 liters of fuel. She wants to know how many kilometres she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate. How far can Eliana drive on 22 liters of fuel? What if Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km? How many liters of fuel does she need?

Answers

Eliana can drive 198 km with 22 liters of fuel.

If Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km then she would need 15.5 liters of fuel

In this question, we have been given Eliana drove her car 81 km and used 9 liters of fuel.

81 km=9 liters

9 km= 1 liter

She wants to know the distance she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate.

By unitary method,

22 liters = 22 × 9 km

              = 198 km

Also, given that  if Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km.

We need to find the amount of fuel she would need.

Let 139.4 km = x liters

By unitary method,

x = 139.4 / 9

x = 15.5 liters

Therefore, Eliana can drive 198 km with 22 liters of fuel.

If Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km then she would need 15.5 liters of fuel

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Draw the angle 0=-pi/2 in standard position find the sin and cos

Answers

An angle in standard position has the vertex at the origin and the initial side is on the positive x-axis.

Thus, the initial side of the angle is:

Now, half the circumference measures pi, thus, pi/2 is a quarte of the circumference. As we want to find the angle -pi/2, then we need to rotate the terminal side clockwise:

Find the sine and the cosine.

The sine and the cosine in the unit circle are given by the coordinates as follows:

[tex](\cos\theta,\sin\theta)[/tex]

As can be seen in the given unit circle, the terminal side is located at:

[tex](0,-1)[/tex]

Thus, the values of cosine and sine are:

[tex]\begin{gathered} \cos\theta=0 \\ \sin\theta=-1 \end{gathered}[/tex]

Conner plans to plow a field in one day. Before lunch he plows 15 acres, which is 30% of the field. Howmany acres will he have to plow after lunch in order to finish the field?

Answers

Solution:

Let the total field to plow be 100 %

According to the question,

The field plowed before lunch is shown below:

15 acres field = 30%

30 % field = 15 acres

1 % field = 15/30 acres

The field plow after lunch is 70%.

[tex]\begin{gathered} 70\text{ \% of field = }\frac{15}{30}\times70 \\ =35\text{ acres} \end{gathered}[/tex]

Final Answer:

Therefore, the field to plow after lunch in order to finish the field is 35 acres.

Dianne is 23 years older than her daughter Amy. In 5 years, the sum of their ages will be 91. How old are they now?Amy is ? years old, and Dianne is ? years old.

Answers

Currently

Let Amy's current age be x. Since Dianne is 23 years older than her daughter, then she is (x + 23) years old.

In 5 years

Amy's age will be (x + 5) years.

Dianne's age will be:

[tex]x+23+5=(x+28)\text{ years}[/tex]

The sum of their ages in 5 years is 91. Therefore, we have:

[tex](x+5)+(x+28)=91[/tex]

Solving, we have:

[tex]\begin{gathered} x+5+x+28=91 \\ 2x=91-5-28 \\ 2x=58 \\ x=\frac{58}{2} \\ x=29 \end{gathered}[/tex]

Amy is 29 years old. Therefore, Dianne will be:

[tex]29+23=52\text{ years old}[/tex]

ANSWER:

Amy is 29 years old, and Dianne is 52 years old.

x + y = 5 y - 2x = -4

Answers

Answer:

x = 3, y = 2

Explanations:

The equations are:

x + y = 5......................(1)

y - 2x = -4...................(2)

Make x the subject of the the formula

x = 5 - y...............(3)

Substitute equation (3) into equation (2)

y - 2(5 - y) = -4

y - 10 + 2y = -4

3y = -4 + 10

3y = 6

y = 6 / 3

y = 2

Substitute the value of y into equation (3)

x = 5 - 2

x = 3

The function used to compute the probability of x successes in n trials, when the trials are dependent, is the _____. a.binomial probability functionb.Poisson probability functionc.hypergeometric probability functiond.exponential probability function

Answers

Given:

The function used to compute the probability of x successes in n trials, when the trials are dependent.

Required:

To choose the correct option for the given statement.

Explanation:

The hypergeometric distribution is a discrete probability distribution. It is used when you want to determine the probability of obtaining a certain number of successes without replacement from a specific sample size.

Therefore the option c is correct.

Final Answer:

c ) hypergeometric probability function.

Use the change of base formula and a calculator to evaluate the logarithm

Answers

The change of base formula states that:

[tex]\log _bx=\frac{\ln x}{\ln b}[/tex]

this means that we can caculate any logarithm using the natural logarithm if we make the quotient of the natural logarithm of the original value and the natural logarithm of the original base.

In this case we have:

[tex]\begin{gathered} x=14 \\ b=\sqrt[]{3} \end{gathered}[/tex]

Then, using the change of base formula, we have:

[tex]\log _{\sqrt[]{3}}14=\frac{\ln 14}{\ln \sqrt[]{3}}[/tex]

Once we have the expression we just evaluate the expression on the right to get the appoximation we need:

[tex]\log _{\sqrt[]{3}}14=\frac{\ln14}{\ln\sqrt[]{3}}\approx4.804[/tex]

16. Eric is deciding how many trees to plant.
Here are his estimates of the time it will take.
Number of trees
1 tree
2 trees
3 trees
4 trees
5 trees
Time
30 minutes
40 minutes
50 minutes
60 minutes
70 minutes

Answers

With each additional tree , the estimated time increases by 10 minutes .

in the question ,

a table with number of trees and time required to plant them is given .

For planting 1 tree 30 minutes is required to plant them .

for planting 2 trees 40 minutes is required to plant them .

increase in number of tree = 2 tree - 1 tree = 1 tree

change in time required = 40 min - 30 min = 10 min

for planting 3 trees , 50 minutes is required to plant them .

increase in number of tree = 3 trees - 2 trees = 1 tree

change in time required = 50 min - 40 min = 10 min

So, we can see that for every additional tree planted the time increases by 10 minutes .

Therefore , with each additional tree , the estimated time increases by 10 minutes .

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a wall in marcus bedroom is 8 2/5 feet high and 16 2/3 feet long. of he paints 1/2 of the wall blue, how many square feet will be blue?140128 2/157064 2/15

Answers

Answer:

[tex]70[/tex]

Explanation:

What we want to answer in this question is simply, the area of the room that will be painted blue if he decides he would paint exactly have the room blue

So, we need to simply get the area of the room and divide this by half

Mathematically, the area of a rectangle is the product of its two sides

Thus, we have it that the area of the room is:

[tex]\begin{gathered} 8\frac{2}{5}\times16\frac{2}{3} \\ \frac{42}{5}\times\frac{50}{3}\text{ = 14}\times10=140ft^2 \end{gathered}[/tex]

Now, to get the area painted blue, we divide this by 2 as follows or multiply by 1/2

We have this as:

[tex]140\times\frac{1}{2}=70ft^2[/tex]

80% of _ = 20?4-4-4-

Answers

Let

x -----> the missing number

we know that

80%=80/100=0.80

so

0.80x=20

solve the linear equation for x

Divide by 0.80 both sides

x=20/0.80

x=25

the answer is 25

diameter = 10.5in.we are learning something about area of circle.

Answers

Use the formula for the area of a circle:

[tex]A=\pi\cdot r^2[/tex]

First, we need to find the radius r. Since the radius is half the diameter, then:

[tex]\begin{gathered} r=\frac{10.5\text{ in}}{2} \\ \therefore r=5.25in \end{gathered}[/tex]

Substitute the value for r in the formula for the area of the circle:

[tex]\begin{gathered} A=\pi\cdot(5.25in)^2 \\ \approx86.6in^2 \end{gathered}[/tex]

Therefore, the area of a circle of diameter 10.5 in is approximately 86.6 squared inches.

A window washer drops a tool from their platform 155ft high. The polynomial -16t^2+155 tells us the height, in feet, of the tool t seconds after it was dropped. Find the height, in feet, after t= 1.5 seconds.

Answers

The answer is is pie

Write a relation consisting of five ordered pairs that satisfies the following conditions. The relation is a function. Switching the x- and y-coordinates of each ordered pair results in a relation that is not a function.

Answers

Answer:

Step-by-step explanation:

If each value of x only has one corresponding value of y, it is a function. You can test this just by eye or by graphing and doing the vertical line test by rolling a pencil or other straight object across to make sure only one point is on the line at a time

find the slope of #1 y = 2x - 3#2 (-2,-4) (-1,-2)#3 y = 1/3x - 4# 4 (4,0) (4,1)

Answers

1. slope= 2

2. slope=2

3. slope= 1/3

4. slope indefinite, vertical line

Explanation

Step 1

[tex]\begin{gathered} y=\text{ 2x-3} \\ \end{gathered}[/tex]

the equation is given in slope(m) - intercept(b)

[tex]\begin{gathered} y=\text{ mx+b} \\ \text{then} \\ mx+b=2x-3 \\ m=2 \\ \text{slope}=2 \end{gathered}[/tex]

Step 2

when you have two points of a line, P1 and P2 the slope is given by:

[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1)andP2(x_2,y_2) \end{gathered}[/tex]

Let

P1(-2,-4) P2(-1,-2)

replace

[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-2-(-4)}{-1-(-2)} \\ \text{slope}=\frac{-2+4}{-1+2}=\frac{2}{1}=2 \\ \text{slope}=2 \end{gathered}[/tex]

Step 3

[tex]y=\frac{1}{3}x-4[/tex]

similar to the #1. ,the equation is given in slope(m) - intercept(b)

[tex]\text{the slope = }\frac{1}{3}[/tex]

Step 4

let

[tex]P1(4,0)\text{ and P2(4,1)}[/tex][tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{1-0}{4-4}=\frac{1}{0}=\text{indefined} \\ it\text{ means the line is vertical} \end{gathered}[/tex]

Help on math question precalculus ChoicesVertical shift Period DomainRange Phase shift Amplitude

Answers

All the x-values that satisfy the function - Domain

Translating the sine or cosine curve up or down - Vertical shift

How long a given function takes to repeat itself - Period.

A horizontal shift of a sine or cosine function- Phase shift

All the y-values that satisfy the function- Range

Distance from the horizontal axis or midline to the maximum and minimum points - Amplitude

I need help for problem number 9. On the right side of the paper.

Answers

Constant of variation ( k ):

• y = 2/3

,

• x = 1/4

[tex]k=\frac{y}{x}=\frac{\frac{2}{3}}{\frac{1}{4}}=\frac{8}{3}[/tex]

k = 8/3

Based on k we can find the value of y when x =3/4 as follows:

[tex]\begin{gathered} k=\frac{y}{x} \\ y=k\cdot x \\ y=\frac{8}{3}\cdot\frac{3}{4}=2 \end{gathered}[/tex]

Answer:

• k = 8/3

,

• When ,x, = ,3/4,,, y = 2

Sara spent 35 minutes on math homework and 20 minutes on reading homework. Mia spent a total of 40
minutes on reading and math homework. How much longer did Sara spend on her homework than Mia?

Answers

Sara spent 15 minutes longer than (the difference is 15 min) Mia in her homework.

According to the question,

We have the following information:

Sara spent 35 minutes on math homework and 20 minutes on reading homework. Mia spent a total of 40 minutes on reading and math homework.

So, it means that the total time spent by Sara in her homework is:

35+20 minutes

55 minutes

So, the differences between their time spent in her homework (will give us the more time taken by Sara) is:

Time spent by Sara in her homework-time spent by Mia in her homework

(55-40) minutes

15 minutes

Hence, Sara spent 15 more minutes than Mia.

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What is 175% of 48? Show work.

Answers

Let 175% of 48 be y.

This implies that

[tex]\frac{175}{100}\times48=y[/tex]

To evaluate y,

[tex]\begin{gathered} \frac{175}{100}\times48=y \\ \Rightarrow\frac{175\times48}{100}=y \\ \frac{8400}{100}=y \\ \Rightarrow y=84 \end{gathered}[/tex]

Hence, 175% of 48 is 84.

Point M is the midpoint of AB. If AM = b² + 5b and
MB = 3b + 35, what is the length of AM?

Answers

Step-by-step explanation:

since M is the midpoint, it means that AM = MB.

so,

b² + 5b = 3b + 35

b² + 2b - 35 = 0

the general solution to such a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case (x is called b, don't get confused, as this is not the factor of x) this gives us

b = (-2 ± sqrt(2² - 4×1×-35))/(2×1) =

= (-2 ± sqrt(4 + 140))/2 = (-2 ± sqrt(144))/2 =

= (-2 ± 12)/2 = -1 ± 6

b1 = -1 + 6 = 5

b2 = -1 - 6 = -7

therefore, we have 2 solutions

b = 5

AM = 5² + 5×5 = 25 + 25 = 50

b = -7

AM = (-7)² + 5×-7 = 49 - 35 = 14

control, as AM = MB

MB = 3×5 + 35 = 15 + 35 = 50

or

MB = 3×-7 + 35 = -21 + 35 = 14

AM = MB in both cases, so, all is correct.

17. 19yd. 28in.- 16yd. 31in.18. 61wk. 4da.- 18wk. 6da.21. 8tbsp. 2tsp. * 15

Answers

We need to solve the next expressions:

17. 19yd. 28in.- 16yd. 31in

We need to solve subtract each expression.

Then:

19yd. 28in.- 16yd. 31in =

19yd - 16yd and 28in-31in

3yd -3in

Then, we have the next equivalent.

1 yard = 36 in

So:

36 in - 3 in = 33 in

Therefore

19yd. 28in.- 16yd. 31in = 2 yard 33

18 61wk. 4da.- 18wk. 6da.

We need to subtract both expression:

Then

61wk - 18wk = 43kw

4da-6da = -2da

Where 1 week = 7 days

Then

7 da - 2da = 5 da

Hence, 43kw -1 wk = 42 wk.

The result is:

42 wk 5 da

21. 8tbsp. 2tsp. * 15

We need to convert 2ts into tbsp and then multiply the result by 15.

If

1 tsp ------- 0.333tbsp

Then

2tp ------ 2(0.333tbsp)= 0.66666 tbsp

Now

(8tbsp + 0.6666 ) * 15 = 130 tbsp

Im confused on what you have to do in order to find the answer

Answers

Given:

The ship is moved from (-10,9) to (-1,-5) in the coordinate plane.

To find:

The transformation rule

Explanation:

The initial point can be written to obtain the terminal point as follow,

[tex](-10+9,9-14)\rightarrow(-1,-5)[/tex]

In general,

We write,

[tex](x,y)\rightarrow(x+9,y-14)[/tex]

Final answer: Option C.

[tex](x,y)\operatorname{\rightarrow}(x+9,y-14)[/tex]

If f (x)- VX-3, complete the following statement:x + 219) =

Answers

Given that;

[tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]

To get f(19), let's substitute 19 for x in the function f(x);

[tex]\begin{gathered} f(x)=\frac{3}{x+2}-\sqrt{x-3} \\ f(19)=\frac{3}{19+2}-\sqrt{19-3} \\ f(19)=\frac{3}{21}-\sqrt{16} \\ f(19)=\frac{1}{7}-4 \\ f(19)=-3\frac{6}{7} \end{gathered}[/tex]

Therefore, the value of f(19) is;

[tex]f(19)=-3\frac{6}{7}[/tex]

3. Trapezoid JKLM with vertices J(-4, 3), K(-2, 7),L(2,7), and M(3, 3) in the line y = 1.what would the reflection coordinates be

Answers

First, we graph the trapezoid and the line

If we reflect the figure across the line y = 1, then we get the following figure

As you can observe in the graph, the vertices would be J'(-4,-1), K'(-2,-5), L'(2,-5), and M'(3,-1).

A gumball machine contains 5 blue gumballs and 4 red gumballs. Two gumballs are purchased, one after the other, without replacement.

Find the probability that the second gumball is red.

Answers

Answer:   4/9

===================================================

Work Shown:

5 blue + 4 red = 9 total

A = P(1st is red, 2nd is red)

A = P(1st is red)*P(2nd is red, given 1st is red)

A = (4/9)*(3/8)

A = 12/72

B = P(1st is blue, 2nd is red)

B = P(1st is blue)*P(2nd is red, given 1st is blue)

B = (5/9)*(4/8)

B = 20/72

C = P(2nd is red)

C = A+B

C = 12/72 + 20/72

C = 32/72

C = 4/9

From the given proportional relationship, which of the following points lie on the same line?

Answers

As per given by the question,

There are given that a graph of line.

Now,

h

2625÷32 long division way​

Answers

Answer: 82 R1 or decimal form 82.031

Step-by-step explanation:

0082

. --------

-0

26

. - 0

. 262

. -256

65

-64

. 1

draw a right triangle with a leg that as a length of 10 and the angle opposite to that side is 55 degrees. find the length of the hypotenuse. round your answer to nearest tenth.

Answers

Question:

Draw a right triangle with a leg that has a length of 10 and the angle opposite to that side is 55 degrees. find the length of the hypotenuse. round your answer to the nearest tenth.​

Solution:

A right triangle with a leg that has a length of 10 and the angle opposite to that side is 55 degrees is given by the following picture:

In this case, the appropriate trigonometric identity is:

[tex]\sin (55^{\circ})\text{ = }\frac{y}{h}[/tex]

where y is the opposite side, and h is the hypotenuse. Now, replacing the given data in the previous equation we obtain:

[tex]\sin (55^{\circ})\text{ = }\frac{10}{h}[/tex]

and solving for h, we get:

[tex]h\text{ = }\frac{10}{\sin (55^{\circ})}\text{ = 12.207}\approx12.21[/tex]

then, the correct answer is:

[tex]h\text{ =}12.21[/tex]

For which pair of triangles would you use ASA to prove the congruence of the two triangles?

Answers

Solution:

Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. According to this, the correct answer is:

C.

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