Answer
0.9166 g CO
Procedure
Considering the conditions and parameters given ideal gas law will be assumed.
[tex]PV=nRT[/tex]The gas constant is 8.3144 L⋅kPa⋅ K⁻¹⋅mol⁻¹
Converting the current data to the required units
710 mL = 0.710 L
37 °C = 310.15 °K
Solving for moles and substituting the variables with the available data
[tex]n=\frac{PV}{RT}=\frac{119\text{ }kPa(0.710)L}{8.3144\text{ L. kPa\cdot}\degree\text{K^^^^207b^^b9\cdot mol^^^^207b^^b9 \lparen310.15\rparen }\degree K}=0.0327\text{ }moles\text{ CO}[/tex]Transforming from moles to grams using the molecular weight
[tex]0.0327\text{ }moles\text{ }CO\frac{28.01\text{ }g}{1\text{ }mole}=0.9166\text{ }g\text{ }CO[/tex]what are terms used for solubility or concentration expression ?
Answer:
The correct expression used for solubility is a. grams per 100 grams of solvent. One of the most commonly used methods for expressing the concentrations is molarity.
balanced chemical equation for .1 M barium nitrate and .1 m sodium sulfate
The balanced chemical equation for 0.1 M barium nitrate and 0.1 M sodium sulfate is -
2 Ba(NO₃)₂ + 2 Na₂SO₄ → 2 Ba(SO₄) + 2 NaNO₃
Balanced chemical equation are the equations having equal amount of reactants and the products formed. The reactants are placed on the left and products are placed on right forming a balanced chemical equation.
When 0.1 M barium nitrate reacts with the 0.1 M sodium sulfate, it gives an insoluble salt of barium sulfate and soluble salt of sodium nitrate as the product. This reaction is a type of precipitation reaction as precipitate is formed in the reaction. It is a double displacement reaction because the sulfate ions replace the nitrate ions to give the product.
Barium sulfate is known to be the most insoluble compound. It is formed as a precipitate.
To learn more about chemical equations,
brainly.com/question/28820839
#SPJ1
why is presence of nitrogen essential in the atmosphere?Explain in simple words.
Explanation:
Calcium like to lose how many electron/s to form an ion?Group of answer choices123cannot determine
Answer: the best option to answer the question is the second one (or letter B), "2"
Explanation:
The question requires us to identify how many electrons a calcium (Ca) atom would lose to form an ion.
We can analyze the electron configuration of Ca to understand how many electrons it would lose.
The atomic number of Ca is 20, thus its electron configuration is as it follows:
[tex]1s^2\text{ 2}s^2\text{ 2}p^6\text{ 3}s^2\text{ 3}p^6\text{ 4}s^2[/tex]From the electron configuration, we can see that Ca presents 2 electrons in its valence shell (4s2). To achieve stability, it is easier for Ca to lose these two electrons and form a Ca2+ ion.
Therefore, the best option to answer the question is the second one (or letter B), "2".
9 mol of A how many moles of C are formed upon complete reaction of
Answer:
C = 9 mol
Explanation:
Reaction: A + 2B ---> C
We want to find the moles of C.
Given: moles of A = 9 mol.
To solve this problem we will need to use stoichiometry.
A is the limiting reagent because it has a coefficient of 1 and B has a coefficient of 2.
The molar ratio between A and C is 1:1 therefore for every 9 moles of A that react, 9 moles of C will be produced.
What is the sum of the coefficients when the following equation is properly balanced? __Ca(OH)2 + __H3PO4 —> Ca3(PO4)2 + __H2O
The sum of coefficients when the above-mentioned equation is balanced is 12.
How to balance a chemical equation?A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation is the same.
According to this question, calcium hydroxide reacts with phosphoric acid as follows:
3Ca(OH)₂ + 2H₃PO4 → Ca₃(PO4)₂ + 6H₂O
The sum of the coefficients of the above balanced chemical equation is 3 + 2 + 1 + 6 = 12.
Learn more about coefficients at: https://brainly.com/question/28294176
#SPJ1
Which of the following does NOT happen during a chemical reaction?A. Bonds are brokenB. Bonds are formedC. Energy is createdD. Mass is conserved
ANSWER
Energy is created ------ (option C)
EXPLANATION
During the chemical reaction process, reactants need to be converted to form products. To balance such chemical reaction equation, we need to apply the law of conservation of mass
Law of conservation of mass states that matter can neither be created nor destroyed but can be transformed from one form to another.
In the process ofa chemical reaction, bonds are broken are the reactants side, bonds are formed on the products side and mass is conserved
Therefore, the correct answer is Energy is created
What is the [ OH -1 ] in a 0.01 M KOH solution? a. 1 X 10^-2 M b. 1 X 10^-14M c. 1 X 10^-7Md. 1X10^-12M
Answer
Explanation
Given:
[KOH] = 0.01 M
What to find:
The hydroxyl concentration, [OH⁻¹].
Step-by-step solution:
pH or pOH is the measure of acidity or alkalinity of a solution.
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14. Neutral substances have a pH of 7.
The dissociation of KOH in aqueous medium is:T
[tex]undefined[/tex]Explain the difference between a cation and an anion. Give hints for remembering each.
Some atoms are neutral and others have positive or negative charges.
The charged atoms are called "ions".
- If the ion has positive charge, it is called cation.
- If the ion has negative charge, it is called anion.
Ions can be identified by their charge, for example:
- Cations: Na^+1, K^+1, Mg^+2
- Anions: Cl^-1, Br^-1
8.In the equation 2 NH3 + H2O + CO2 ---> (NH4)2CO3, which of the following is a product?Select one:a. CO2 b. H2O c. NH3 d. (NH4)2CO3
According to the explanation given in a previous session, the compounds that comes after the arrow are classified as product, and the compounds that comes before are classified as reactant, therefore in this reaction, (NH4)2CO3 is the product of the reaction, letter D
Calculate the frequency and the energy of blue light that has a wavelength of 423 nm (Note => 423 nm = 4.23 * 10^7 m)
According to the Planck's equation,the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.
What is Planck's equation?Max Planck discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.
The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.
In the given problem, energy is calculated as,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.23×10[tex]^-7[/tex]=4.699×10[tex]^-19[/tex] J.
The frequency of light is calculated as follows,4.699×10[tex]^-19[/tex]/19.878×10[tex]^-26[/tex]=2.363×10⁶ m[tex]^-1[/tex].
Thus , the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.
Learn more about Planck's equation,here:
https://brainly.com/question/5528489
#SPJ1
7.Explain the bonding in carbon tetrachloride, CCl4—specifically, explain whether it’s covalent or ionic.
• The bond that exist between the CCl4 compound ,forms a covalent bond ,, this can be illustrated in the diagram below:
• We can see that it contains four non-polar covalent bond between carbon and chloride
If 3.8 moles of P4 are used, how many moles of O2 are needed?
1) Write the chemical equation.
[tex]P_4+O_2\rightarrow P_4O_{10}[/tex]2) List the elements in the reactants and in the products.
Reactants.
P: 4
O: 2
Products
P: 4
O: 10
Balance O.
[tex]P_4+5O_2\rightarrow P_4O_{10}[/tex]3) Moles of O2 needed.
The molar ratio between P4 and O2 is 1 mol P4: 5 mol O2.
[tex]mol\text{ }O_2=3.8\text{ }mol\text{ }P4*\frac{5\text{ }mol\text{ }O_2}{1\text{ }mol\text{ }P_4}=19\text{ }mol\text{ }O_2[/tex]If 3.8 mol P4 are used, 19 mol O2 are needed.
.
Write down a specific step by step procedure of the titration process which the goal is to determine the unknown concentration of a basic solution.
Explanation:
Titration is a technique used to determine the amount of matter in a sample using a solution of known concentration. In other words, titration is a quantitative chemical analysis. In this process, the sample has its concentration determined through a chemical reaction when it is mixed with another substance. The use of pH indicators in this process is useful to determine the endpoint of the titration, indicating that the entire sample has reacted. Titration is used to accurately determine the amount of a substance, confirm that the concentration described on the label is true or that the amount of a chemical compound is indicated on the package.
Sample weighing: With the solid sample on a watch glass, weigh it on the balance.
Sample dissolution: The sample is transferred to an Erlenmeyer flask with water, where dissolution takes place.
Problem solution: The solution is transferred to a volumetric flask and the volume is made up with water, creating the problem solution.
Aliquot transfer: Remove an aliquot of the problem solution with the aid of a pipette and transfer it to an Erlenmeyer flask.
Titration: To the Erlenmeyer flask, the problem solution (titrated) is added and the solution of known concentration (titrant) is inserted into the burette.
An acid-base indicator is also added to the titrator to indicate when the titration should be stopped due to the color change. The color change indicates the end point or turning point of the titration.
After that, when the color change persists, the volume of titrant used is verified and stoichiometric calculations will help us to discover the concentration of the titrated solution.
Answer:
Step 1 - Sample weighing: With the solid sample on a watch glass, weigh it on the balance.
Step 2 - Sample dissolution: The sample is transferred to an Erlenmeyer flask with water, where dissolution takes place.
Step 3 - Problem solution: The solution is transferred to a volumetric flask and the volume is made up with water, creating the problem solution.
Step 4 - Aliquot transfer: Remove an aliquot of the problem solution with the aid of a pipette and transfer it to an Erlenmeyer flask.
Step 5 - Titration: To the Erlenmeyer flask, the problem solution (titrated - basic solution) is added and the solution of known concentration (titrant - acidic solution) is inserted into the burette.
Step 6 - An acid-base indicator is also added to the titrator to indicate when the titration should be stopped due to the color change. The color change indicates the endpoint or turning point of the titration.
Step 7 - After that, when the color change persists, the volume of titrant used is verified and stoichiometric calculations will help us to discover the concentration of the titrated solution.
Abed found fingerprints at a crime scene that match fingerprints that were taken from the suspect. What does this MOST likely mean?
A.
The suspect’s fingerprints match someone else’s.
B.
All 150 ridge characteristics are identical.
C.
The suspect touched something at the crime scene.
D.
At least three different points were a perfect match.
Answer:
C
Explanation:
Because the suspect touched something at the crime scene and thus he's fingerprint are matching
How many moles are in 95 grams of aluminum (AI)?
ANSWER
3.52 moles are in 95 grams of aluminum
STEP-BY-STEP EXPLANATION:
As you can see from the question provided, you are asked to find the moles of aluminum
Given data
Mass of aluminum = 95 grams
To find the moles of aluminum, we will need to apply the below formula
[tex]\text{ Mole }=\text{ }\frac{\text{ reacting mass}}{\text{molar mass}}[/tex]From the question provided, you can see that the molar mass of aluminum was given
From your periodic table, you will see that the molar mass of aluminum is 27 g/mol
Molar mass of aluminum = 27g/mol
The next thing is to substitute the data given in the above formula
[tex]\begin{gathered} \text{ Mole = }\frac{95}{27} \\ \text{mole = }3.52\text{ g/mol} \end{gathered}[/tex]Therefore, we have 3.52 moles are in 95 grams of aluminum
Calculate the percent nitrogen in NH4NO3.Group of answer choices17.5%8%60%28%35%
In order to find the percent composition for Nitrogen in NH4NO3, we will need to work with all the masses from this compound, so let's list them below:
NH4NO3 = 80.04 g/mol
N = 14 grams, but we have 2 nitrogens, therefore = 28 grams
H = 1 gram, 4 Hydrogens = 4 grams
O = 16 grams, 3 Oxygens = 48 grams
Now we take the total mass of the compound as 100% and check how much it will be made by Nitrogen:
80.04 g = 100%
28 g = x %
x = 34.98%, which we can round up to 35% therefore the answer will be letter E
54000 mL isO 54 m3O 5400 cm3O 0.054m3O 540 m3
mL and cm³ have a 1 to 1 conversion, so we have:
[tex]54000mL=54000cm^{3}[/tex]But we don't have this option, so we will need to find another.
The other are in m³, so we can use the conversion from cm to m to get this:
[tex]\begin{gathered} 1m=100cm \\ (1m)^{3}=(100cm)^{3} \\ 1m^{3}=1000000cm^{3} \\ 1cm^{3}=\frac{1}{1000000}m^{3} \end{gathered}[/tex]So, we can apply this to what we have:
[tex]54000cm^3=54000\cdot\frac{1}{1000000}m^3=0.054m^{3}[/tex]We have an option with 0.054m³, so the correc alternative is 0.054 m³.
Select the structure that correspondsto the molecule name:ethylmethylamineA.NHB. CH3CH₂NHCH3C. both
Ethylmethylamine is a secondary amine, that has one ethyl group attached to the amine group and one methyl group, which is a also attached to the amine group.
It is represented by:
Nevertheless it can be represented by CH3CH2NHCH3.
It means that the correct answer is c. Both.
Consider the hypothetical thermochemical equation 3 A + B → 2 C for which ΔH = 65.5 kJ/mol.What would ∆H, in kJ/mol, be for the reaction 2 C → 3 A + B?
Given the hypothetical thermochemical equation, expressed as:
[tex]3A+B\rightarrow2C;\triangle H=65.5\text{kJ/mol}[/tex]We are to find the enthalpy change (ΔH ) for the reaction 2C → 3 A + B.
• You can see that the, given reaction, 2C → 3 A + B is the, reverse ,of the thermochemical equation 3 A + B → 2 C.
• Since the ,reverse reaction is possible,, the reaction enthalpy has the ,same numerical value, but with the, ,opposite sign
Therefore, the enthalpy change ∆H, in kJ/mol, be for the reaction 2 C → 3 A + B is -65.5kJ/mol
Write the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions.
Answer:
Explanation:
As the cell has a copper strip like the anode and a coin or nail (we can consider this like it is nickel) like the cathode, we can write both half-reactions:
• Copper half-reaction,:
[tex]Cu_{(s)}\leftrightarrows Cu_{(aq)}^{2+}+2e^-[/tex]In the copper anode, the oxidation reaction takes place. This is the positive terminal.
• Nickel half-reaction,:
[tex]Ni_{(aq)}^{2+}+2e^-\leftrightarrows Ni_{(s)}[/tex]In the nickel cathode, the reduction reaction takes place. This is the negative terminal.
The direction of the electron flow always go from the anode to the cathode.
when the solute particles mixed with water what do they become
Answer:
the water becomes solvent, and the mixture becomes the solution.
Explanation:
Answer:
a solution
Explanation:
solute and solvent(water) put together would produce a solution
Could anyone please help me balance this equation?
K⁺(aq) + 2Al(s) +H⁺(aq) +SO₄²-(aq)+H2O(l)⭢KAl(SO4)2·12H2O(s)+3H2(g)
To see the total number of atoms we need to multiply coefficient which is written in foot of the molecule or element to the number that is written on the foot of that element
The balanced reaction is
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
What is Balanced equation?
Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side
The unbalanced equation is
Al(s) + KOH(aq) + H₂SO₄(aq)→ KAl(SO₄)₂·12H₂O(s)
sulfur atoms on reactant side is 1 while on the product side it is 2 so multiply H₂SO₄ by 2
Al(s) + KOH(aq) + 2H₂SO₄(aq) → KAl(SO₄)₂·12H₂O(s)
Now add H₂O(l) and H₂(g) to balance oxygen and hydrogen. The balanced equation becomes
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
Thus the balanced equation is
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
Learn more about the balanced equation, here:
https://brainly.com/question/7181548
#SPJ1
70.0 mL of water was added to 100.0 mL of 0.250 M CaCl₂ solution. Assuming the volumes are additive, what is the CaCl₂ concentration in the diluted solution?
70.0 mL of water was added to 100.0 mL of 0.250 M CaCl₂ solution. Assuming the volumes are additive, The CaCl₂ concentration in the diluted solution is 0.147 M.
given that :
volume V1 = 100 mL
volume V2 = 100 + 70 = 170 mL
Molarity M1 = 0.250 M
Molarity M2 = ?
using dilution equation we get :
M1 V1 = M2 V2
M2 = ( M1 V1) / V2
M2 = ( 0.250 × 100 ) / 170
M2 = 0.147 M
Therefore , the dilution solution will have 0.147 M
Thus, 70.0 mL of water was added to 100.0 mL of 0.250 M CaCl₂ solution. Assuming the volumes are additive, what is the CaCl₂ concentration in the diluted solution is 0.147 M.
To learn more about molarity here
https://brainly.com/question/8732513
#SPJ1
Potential Molecular TheoryThere are 500 grams of Kl in a volumetric flask. It is dissolved in 1 liter of water. What is the molarity?3.141 M3.012 M0.500 M500.000 M20A precipitate is formed when two solutions are mixed. This would only occur if
Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:
M = n/V
Where:
n = number of moles
V = volume in Liters, 1 Liter
But we need to find the number of moles, we will do so by using its molar mass, KI = 166g/mol and the given mass in the question, 500g grams
166g = 1 mol
500g = x moles
x = 3.012 moles
Now we can use the Molarity formula
M = 3.012/1
M = 3.012 M, this is the molar concentration of the solution, 2
calculating formal charge
The carbonate ion has the simplest oxo carbon anion structure. One carbon atom is surrounded by three oxygen atoms in a trigonal planar arrangement, giving it D3h molecular symmetry. Its molecular mass is 60.01 g/ mol and its formal charge overall is HCO3.
Explain about the structure of carbonate ion?
Carbonate Organization its structure is a trigonal planar arrangement of three oxygen atoms surrounding a carbon atom. Two single bonds to the negative oxygen atom and two double bonds to the neutral oxygen atom make up the carbonate ion's Lewis structure.
The carbonate ion, a salt of carbonic acid, is the most basic form of the oxo carbon anion. A polyatomic ion, it has the chemical formula CO32-. The term "carbonate" can also refer to a carbonate ester, an organic molecule with the carbonate group C(=O)(O-)2.
The carbonate has a valency of two because it may combine with two hydrogen atoms.
To learn more about structure of carbonate ion refer to:
https://brainly.com/question/4680313
#SPJ13
Determine the [H3O+] of a 0.150 M solution of benzoic acid.
The [H₃O⁺] of a 0.150 M solution of benzoic acid is 0.00515 M.
Benzoic acid is classified as a weak acid and it dissociates partially when it is dissolved in water. Benzoic acid has chemical formula as C₆H₅COOH and it produce the benzoate anion which is [C₆H₅COO⁻] with a hydronium cation which is [H₃O⁻].
We know that constant Ka = 1.77 x 10⁻⁴
We will write the equilibrium reaction as -
C₆H₅COOH + H₂O → H₃O⁺ + C₆H₅COO⁻
0.150 M x x x
Ka = [H₃O⁺] [C₆H₅COO⁻]
C₆H₅COOH
1.77 x 10⁻⁴ = x₂
0.150
We will solve to get the value of x -
x = [H₃O⁺] = 0.00515 M
Therefore, [H₃O⁺] is 0.00515 M.
To learn more about benzoic acid,
brainly.com/question/11004927
#SPJ1
The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required to completely react with 0.025 g C3H8?"Determine the mass of each of the following compounds, rounding molar masses of elements to the gram before adding up the total: C3H8 (propane)"
The molar mass of oxygen gas (O2) is 32.00 g/mol.
The molar mass of C3H8 is 44.1 g/mol.
This kind of reaction is a combustion:
C3H8 + 5O2 → 3CO2 + 4H2O (In a combustion we obtain CO2 and H2O. Don't forget to balance this equation)
Procedure:
Let's use stoichiometry to solve this
44.1 g C3H8 --------- 5 x 32.00 g O2
0.025 g C3H8 --------- X
X = 0.091 g O2
Answer: mass of O2 required = 0.091 g
Select the answer that correctly describes the masses the subatomic particles from lightest to having.
1) Subatomic particles. Atoms are made up of smaller parts called subatomic particles. Proton, neutron, and electron are some of them.
Electron: 9.11*10^-31 kg.
Proton: 1.672 18*10^-27 kg.
Neutron: 1.674 93*10^27 kg.
The lightest subatomic particle is the electron, then comes the protons, and finally the electron.
Part II Dilution Problems: 17. 350.0 mL of water was added to a 2.3 L solution of NaCl. If the final concentration of the solution was 0.967 M, what was the original concentration of the solution?
ANSWER
The original concentration of the solution is 0.147 mol
EXPLANATION
Given that;
The volume of water is 350.0mL
The volume of NaCl solution is 2.3L
The final concentration of the solution is 0.967M
To find the original concentration of the solution, follow the steps below
Step1: Write the dilution formula
[tex]\text{ M1V1}=M2V2[/tex]Where
• M1 is the original concentration of the solution
,• V1 is the original volume of the of the solution
,• M2 is the final concentration of the solution
,• V2 is the final volume of the solution
Step 2: Convert the volume of water to L
Recall, that 1mL is equivalent to 0.001L
[tex]\begin{gathered} \text{ The volume can be converted below as} \\ \text{ 1mL }\rightarrow\text{ 0.001L} \\ \text{ 350mL }\rightarrow\text{ vL} \\ \text{ Cross multiply} \\ \text{ vL}\times\text{ 1mL }=\text{ 350mL}\times0.001L \\ \text{ Isolate v} \\ \text{ v }=\text{ }\frac{350\cancel{mL}\times\text{ 0.001L}}{1\cancel{mL}} \\ \text{ v }=\text{ 350}\times\text{ 0.001} \\ \text{ v }=\text{ 0.35L} \end{gathered}[/tex]Step 3; Find the original concentration of the solution by substituting by the given data into the formula in step 1
[tex]\begin{gathered} \text{ M1}\times2.3\text{ }=\text{ 0.35}\times\text{ 0.967} \\ \text{ 2.3M1 }=\text{ 0.33845} \\ \text{ Divide both sides by 2.3} \\ \text{ }\frac{2.3M1}{2.3}\text{ }=\text{ }\frac{0.33845}{2.3} \\ \text{ M1}=\text{ 0.147 mol} \end{gathered}[/tex]Hence, the original concentration of the solution is 0.147 mol
