3.01×10²³molecules.
Explanations:
The formula for the number of molecules of a compound given the number of moles is expressed as:
[tex]nu\text{mber of molecules=moles}\times6.02\times10^{23}[/tex]Get the moles of ethane gas using the formula:
[tex]\begin{gathered} \text{moles of ethane=}\frac{Mass\text{ of ethane}}{Molar\text{ mass of ethane}} \\ \text{Moles of ethane=}\frac{15}{2(12)+1(6)} \\ \text{Moles of ethane}=\frac{15}{30}\text{moles} \\ \text{Moles of ethane}=0.5\text{moles} \end{gathered}[/tex]Determine the required number of molecules of ethane
[tex]\begin{gathered} nu\text{mber of mol}ecules=0.5\times6.02\times10^{23} \\ nu\text{mber of mol}ecules=3.01\times10^{23} \end{gathered}[/tex]Hence the molecule of ethane gas that is in 15 grams of the compound is 3.01×10²³molecules.
PLEASE HELP!!
For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.
One of the main components of an airbag is the gas that fills it. As part of the design process, you need to determine the exact amount of nitrogen that should be produced. Calculate the number of moles of nitrogen required to fill the airbag. Show your work. Assume that the nitrogen produced by the chemical reaction is at a temperature of 495°C and that nitrogen gas behaves like an ideal gas.
Part C
Recall the balanced chemical equation from part B of task 1:
2NaN3 → 2Na + 3N2.
Calculate the mass of sodium azide required to decompose and produce the number of moles of nitrogen you calculated in part B of this task. Refer to the periodic table to get the atomic weights.
Part D
What would happen if the amount of sodium azide used was far greater or far less than what you calculated in part C? Describe both cases.
The number of moles of nitrogen required to fill the airbag is 1.197 moles.
The mass of sodium azide required to decompose and produce 1.197 moles of nitrogen is 51.87 g.
If the mass used was greater, the airbag could burst, but if the mass used was smaller, the airbag would not inflate properly.
What amount in moles of nitrogen is required to fill the bag?The number of moles of nitrogen required to fill the airbag is calculated from the equation of reaction as follows:
Using the ideal gas equation; PV = nRT
where;
P = pressureV = volumen = number of molesR = molar gas constantT = temperatureFrom the data provided:
P = 1.30 atm
V = 58 Liters
n = ?
R = 0.082 atm.L.mol⁻¹K⁻¹
T = 495 °C or ( 273.15 + 495) K = 768.15 K
solving for n;
n = PV/RT
n = (1.3 * 58) / (0.082 * 768.15)
n = 1.197 moles
Equation of reaction: 2 NaN₃ → 2 Na + 3 N₂
moles ratio = 2 moles of sodium azide produce 3 moles of N₂
Moles of azide required = 1.197 * 2/3 = 0.798 moles
molar mass of sodium azide = 65 g/mol
mass of sodium azide = 0.798 * 65
mass of sodium azide required = 51.87 g
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What kind of energy transfer happens when you hang Christmas lights?
Answer: For example, Christmas lights transform electrical energy into thermal energy and light energy.
Explanation: so it either thermal or light, most likely light.
What is the percent yield if 15.5 g SO2 is obtained from the reaction of 42.5 g of O2 with excess ZNS according to the following equation 2ZnS (s) + 3O2 -> 2ZnO (s) + 2 SO2(g)
Answer:
Percent yield = 27.3%.
Explanation:
First, let's write the chemical equation:
[tex]2ZnS+3O_2\rightarrow2ZnO+2SO_2.[/tex]The limiting reactant, in this case, would be O2 because we have an excess of ZnS. So, we have to convert 42.5 g of O2 to moles. Remember that the molar mass of O2 is 32 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will be:
[tex]42.5\text{ g O}_2\cdot\frac{1\text{ mol O}_2}{32\text{ g O}_2}=1.33\text{ moles O}_2.[/tex]With this value, we're going to find the number of moles of SO2 produced by 1.33 moles of O2. You can see in the chemical equation that 3 moles of O2 reacted produces 2 moles of SO2, so the calculation would look like this:
[tex]1.33\text{ moles O}_2\cdot\frac{2\text{ moles SO}_2}{3\text{ moles O}_2}=0.887\text{ moles SO}_2.[/tex]The next step is to find the mass of SO2 based on its number of moles and the molar mass of SO2 which is 64 g/mol, like this:
[tex]0.887\text{ moles SO}_2\cdot\frac{64\text{ g SO}_2}{1\text{ mol SO}_2}=56.8\text{ g SO}_2.[/tex]And finally, we replace the values that we have in the formula of percent yield:
[tex]\%\text{ yield }=\frac{experimental\text{ yield}}{theoretic\text{al yield}}\cdot100\%.[/tex]Our experimental yield is the mass that we obtained of SO2 which is 15.5 g and the theoretical yield is the mass that we found through stoichiometry which is 56.8g:
[tex]\%\text{ yield}=\frac{15.5\text{ g}}{56.8\text{ g}}\cdot100\%\approx27.3\%.[/tex]The percent yield of this reaction would be 27.3%
I need to understand how to do problem number 5
Answer:
[tex]\begin{gathered} \text{ - molecule of H}_2SO_4=2.408\times10^{24} \\ -4\text{ atoms of Oxygen} \end{gathered}[/tex]Explanations:
Given the following parameters
Moles of sulfuric acid = 14 moles
According to the Avogadro's constant;
[tex]1\text{mole}=6.02\times10^{23}molecules[/tex]The number of molecules of 14 moles of sulfuric acid is calculated as:
[tex]\begin{gathered} \text{ molecule of H}_2SO_4=14\times6.02\times10^{23} \\ \text{ molecule of H}_2SO_4=24.08\times10^{23} \\ \text{ molecule of H}_2SO_4=2.408\times10^{24} \end{gathered}[/tex]Hence the molecule of sulfuric acid that is contained in 14moles if sulfuric acid is 2.408 * 10^24 molecules
Since the chemical formula of sulfuric acid is expressed as H₂SO₄. This shows that the compound has 2 atoms of Hydrogen, 1 atom of sulfur, and 4 atoms of oxygen.
Hence the number of atoms of oxygen contained in this sample is 4 atoms
Which of the following is used to find the mass of 3.2 moles of calcium carbonate?
1) Converting grams to moles or moles to grams
In order to do this kind of conversion, we need the molar mass (in grams) of the compound to use it as a conversion factor as follows:
[tex]\frac{molarmassofthecompound_{}}{1molofthecompound_{}}[/tex]-
How many joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C
Joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C is 450 J.
Given that :
The specific heat capacity expression is given as :
Q = m cΔT
Q = heat energy
m = mass = 100 g
c = specific heat = 0.45 J/g °C
ΔT = change in temperature = 33 °C - 23 °C = 10 °C
substituting the values in the formula:
Q = m cΔT
Q = 100 g × 0.45 J/g °C × 10 °C
Q = 450 J
Thus, Joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C is 450 J.
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identify an element that has similar chemical properties as those of the element krypton (K).
The table below gives the equilibrium concentrations for this reaction at acertain temperature:N₂(g) + O₂(g) →→→→2NO(g)0.69 M[N₂]0.98 MOA. 20OB. 1.7 x 10-3OC. 5.0 × 10-2OD. 9.9[0₂]What is the equilibrium constant for the reaction?0.034 M[NO]
Option B is correct
[tex]1.7\times10^{-3}[/tex]Explanations:Given the chemical reaction below;
[tex]N_2(g)+O_2(g)\rightarrow2NO(g)[/tex]The equilibrium constant for the reaction is given as;
[tex]k=\frac{[NO]^2}{[O_2][N_2]}[/tex]Given the following parameters
[tex]\begin{gathered} [NO]=0.034M \\ [N_2]=0.69M \\ [O_2]=0.98M \end{gathered}[/tex]Substitute
[tex]\begin{gathered} k=\frac{(0.034)^2}{(0.69)(0.98)} \\ k=\frac{0.001156}{0.6762} \\ k=0.001709=1.7\times10^{-3} \end{gathered}[/tex]Therefore the equilibrium constant for the reaction is 1.7 * 10^-3
12. What is a resonance structure?A. Alternate structures of similar compoundsb. Alternate structures of the same compoundC. Similar compounds with electrons added to themd. Similar compounds with electrons removed from them
There are some compounds in which the electrons move from one side to anothe, and it is a continous movement. For that reason, the resonance structure is created. It works as a theorical structure which is not exact, but it helps us to approach to the real structure.
For example, for the bencene, there are 3 different resonance structures:
And they are the same compound. It means that the answer is B. Alternate structures of the same compound.
how do you determine what the product of a chemical reaction would be
Answer and explanation
To predict the product, you need to first have or know your reactans, for example, if you have magnesium (Mg) + oxygen (O2), the product should include both reactants. Oxidation numbers also play a role of the final charge of the product, magnesium has a charge of 2+ and O has a charge of 2-, therefore the product will be MgO
Example 2
Na2CO3 + HCl
When sodium carbonate (Na2CO3) reacts with HCl, Na+, O^-2 and CO2 dissociates in the solution, H+ and Cl- also dissociates, what happens is that the oppositely charges ions attract and form compounds, Na is positive and Cl is negative, they will combine to form NaCl, the hydrogen has a positive charge (+1), it will combine with excess oxygen (O^-2) forming water (H2O) and the CO2 will not combine with anything since it is not an ion
Final equation:
Na2CO3 + HCl = NaCl + H2O + CO2
Now we can balance the equation:
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
What is the correct formula that wouldresult from the combination of the twoionic species?Na¹+ and CIO ¹-1-4BNa₂(CIO4)2NaCIO4
To determine how the formula will be when combining two ionic species, we must look at the oxidation states of the ions. The Na ion has an oxidation state of +1 and the ClO4 ion has an oxidation state of -1.
The number of ions must be such that the total sum of the oxidation states is zero. If we have a Na+1 ion and a ClO4(-1) ion, the sum will be equal to zero. So there must be one ion of each species in the molecule.
[tex]Na^{+1}ClO_4^{-1}\rightarrow NaClO_4[/tex]Therefore, the answer will be: NaCIO4
What is the concentration in molarity of a solution which is 2.91 %m/v benzene (C₆H₆, MM =78.11 g/mol ) in CCl₄ (MM = 153.81 g/mol)?
According to molar concentration,concentration in molarity of the solution is 3.77×10[tex]^-7[/tex] M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
In the given problem,mass of benzene =2.91 g and molar mass of benzene=78.11 g/mole and volume=100-2.91=97.09 ml or 97.09×10[tex]^-3[/tex] L.
Substituting in the formula,molarity=2.91/78.11×1/97.09×10[tex]^-3[/tex]=3.77×10[tex]^-7[/tex] M.
Hence, the molarity of solution is 3.77×10[tex]^-7[/tex] M.
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Please select the correct answer for each question!
Answer:1=X
2=Y
3=X
Explanation:
If you have 4 cups of flour, 2 sticks of butter, 8 eggs, 4 cups of sugar, 2 cups of milk, and 4 tsp of baking powder, how many cakes can you make?
Based on the mole ratio of the reactants, 2 cakes can be made.
What are limiting reactants?Limiting reactants are the reactants in a chemical reaction that are used up in a reaction.
Limiting reactants are the reactants upon which the reaction depends. Once the limiting reactant is used up, the reaction will stop.
Hence, the amount of product that can be formed from a reaction depends on the limiting reactant.
The limiting reactant of a reaction is obtained from the mole ratio of the reactants in the reaction.
Considering the equation of the reaction of the baking of cake:
2 cups flour + 1 stick butter + 4 eggs + 2 cups sugar + 1 cup milk + 2 tsp. baking powder = 1 cake
The amount of reactants present:
4 cups of flour,2 sticks of butter,8 eggs,4 cups of sugar,2 cups of milk, and4 tsp of baking powderThe amount of the reactants available is twice their mole ratio, hence two cakes can be made.
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-8- A student conducted a number of tests on a solid mixture, X. The inferences made are recorded in Table 2. Complete Table 2 by filling in the observations based on the inferences made. TABLE 2: TESTS ON MIXTURE X Test Observation Inferences (a) Distilled water was added to a portion of X and the resulting mixture stirred and filtered. (The residue was set aside for use later.) The filtrate was divided into 3 equal portions and tests (b) to (d) done on separate portions. Clions are present. (b) Dilute nitric acid followed by a few drops of silver nitrate solution was added. Ammonium hydroxide solution was added to the resulting mixture. An oxidizing agent is present. (c) A few drops of potassium iodide solution were added. Iron(III) ions are present. Aqueous sodium hydroxide was added until in excess. Carbonate ions are present. (e) Dilute nitric acid was added to the residue from test (a) and the gas produced passed through lime water. Total 1 •Pet (3 marks) (2 marks) (2 marks) (3 marks)
Answer:
There would be a change in the color of the potassium iodide from yellowish-brown to colorless
Explanation:
Here, we want to test for the presence of oxidizing agent by the use of potassium iodide
Since we already have the inference, we need to state what would be observed
Potassium iodide itself is a reducing agent
Thus, it becomes oxidized
In the process of being oxidized, there would be a color change
The color change observed will be from yellowish-brown to colorless
Which subatomic particle is positively charged?ProtonNeutronElectronNone
Explanation:
A proton is a positively charged subatomic particle.
A neutron is a neutrally charged subatomic particle.
An electron is a negatively charged subatomic particle.
Answer:
The first option is correct.
Consider this reaction:3Ca(s)+2H3PO4(aq)=Ca3(PO4)2(s)+3H2(g)How many grams of calcium are required to produce 50.500 g of calcium phosphate (MW = 310.19g/mol) assuming an excess of Phosphoric acid?
Answer
19.6 grams
Explanation
Given:
Mass of calcium phosphate produced = 50.500 g
Equation: 3Ca(s) + 2H3PO4(aq) ---> Ca3(PO4)2(s) + 3H2(g)
What to find:
The grams of calcium required to produce 50.500 g of calcium phosphate.
Step-by-step solution:
From the equation, 3 mol Ca produce 1 mol Ca3(PO4)2
1 mole Ca3(PO4)2 = 310.19 grams
1 mole Ca = 40.078 grams
This means, (3 x 40.078 g) = 120.234 g Ca produce 310.19 g Ca3(PO4)2
So x grams Ca will be required to produce 50.500 grams Ca3(PO4)2
x grams Ca will be equal
[tex]\frac{50.500\text{ }g}{310.19\text{ }g}\times120.234g\text{ }Ca=19.6\text{ }grams\text{ }Ca[/tex]The grams of calcium required to produce 50.500 g of calcium phosphate = 19.6 grams
If an acid dissosciates, what is happening?A. It is combining with a base in a neutralization reactionB. it is involved in a chemical reactionC. the concentration is decreasingD. it is being pulled apart by solvent molecules
In a solution, when we have an acid being dissociated, what is actually happening is that the acid is being pulled apart by solvent molecules, becoming two ions, the proton H+ and the conjugated base, this is what causes the solution to be acidic, and this is also how the strength of the acid is measured. Therefore the best answer is letter D
A patient turns in a sample of urine for specific gravity test. The lab results record a value of1.024. What is the density of this patient's urine?
Specific gravity is the same concept for relative density. This measure indicates the density with respect to the density of water at standard temperature. The formula is:
[tex]\text{Specific gravity = }\frac{density\text{ of substance}}{density\text{ of water}},[/tex]If we are comparing pure water, the density of this would be 1.00 g/mL, so clearing the formula and replacing, we're going to have:
[tex]\begin{gathered} \text{density of substance (urine) = specific gravity }\cdot\text{ density of water,} \\ \text{density of urine = 1.024 }\cdot\text{ 1.00}\frac{g}{mL}, \\ \text{density of urine = 1.024 }\frac{g}{mL}. \end{gathered}[/tex]The density of the patient's urine is 1.024 g/mL if the specific gravity is 1.024.
How many moles of atoms are in 7 g of 13C
Answer:
Explanation:
molar mass of 13c = 13 grams
number of moles = mass / molar mass
therefore,
number of moles = 7 / 13
To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:
number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms
A chicken egg has mass 60g. It's shell makes up 10% of the whole egg. The shell is made of Calcium Carbonate; CaCO3. What is the mass of the Ca/ Calcium in the egg shell?
Calculate the enthalpy of combustion (kJ/mol) of methyl linoleate (C₁₉H₃₄O₂), an important component of many biodiesel fuels made from corn oil and methanol, given the following standard enthalpies of formation: CO₂(g) = -393.5 kJ/mol H₂O(l) = -285.8 kJ/mol C₁₉H₃₄O₂(l) = -645.7 kJ/mol
Answer:
Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation
∆Hcombustion
∆H = ∑∆Hf products - ∑∆Hf reactants
∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)
∆H = -24,670 + 1291
∆H = 25,961 kJ
(be sure to check the math)
How many grams of H2 are required to completely convert 80g of Fe2O3?
Answer
3.0 grams H₂ is required.Explanation
Given:
Mass of Fe2O3 = 80 g
Equation:
What to find:
The grams of H2 required to completely convert 80g of Fe2O3.
Step-by-step solution:
From the equation of reaction;
3 moles of H2 completely react with 1 mole of Fe2O3
Note: Molar mass of H2 is 2.016 grams per mole and Molar mass of Fe2O3 is 159.69 g/mol
This implies; (3 x 2.016 g) = 6.048 grams H2 completely react with 159.69 grams Fe2O3.
Therefore, x grams H2 will completely convert 80 grams Fe2O3.
Cross multiply and divide both sides by 159.69 grams Fe2O3.
x grams H2 is now equal to
[tex]x=\frac{80\text{ }g\text{ }Fe_2O_3}{159.69\text{ }g\text{ }Fe_2O_3}\times6.048\text{ }g\text{ }H_2=3.0298\approx3.0\text{ }grams\text{ }H_2[/tex]Therefore the grams of H2 required to completely convert 80g of Fe2O3 is 3.0 grams
1. How would an element be classified?a. homogeneous mixtureb. pure substancec. solutiond. heterogeneous mixture
Hello
To solve this question, we should understand that an element is is the base form in which a particule exit. However, it can either be in a molecule, atom or in a compound. Elements are pure substance which form up the molecule, atom or compounds. An element can said to be an identity of a substance. Elements are generally classified using the periodic table into metals, non-metals, metalliods.
In this question, the most possibe defination is that an element is a pure substance
A homogenous mixture is a mixture that is said to have one phase of substance throughout. I.e the comprising substance are all in a single phase.
A solution is the mixture of a solute that is completely dissolved in a solvent.
A heterogeneous mixture is a solution that the substance are not in a single phase.
The answer to this question is option B
What is Kb for the conjugate base of HF (Ka = 6.8 × 10⁻⁴)?
The Kb for the conjugate base of HF, Fluoride ion is 1.470588 * 10^-11
The conjugate base of HF (hydrofluoric acid) is fluoride ion, F-
Ka of HF or hydrofluoric acid is given as 6.8 × 10⁻⁴
Kw = Ka * Kb
Where,
Kb = Base dissociation constant
Kw = Water dissociation constant or equilibrium constant
Ka = Acid dissociation constant
Kw = [H+] [OH-] = 1.0 X 10-14 at room temperature
The formula can be rewritten as,
Kb = (Kw / Ka)
= (10^-14) / (6.8 * 10^-4)
= 1.470588 * 10^-11
Therefore, the kb for the conjugate base of HF, Fluoride ion is 1.470588 * 10^-11
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Patricia wants to examine the morphology of a hair sample. What is the BEST way for her to accomplish this task?
A.
Send the sample away to a lab for DNA testing.
B.
Observe the sample under a high-powered microscope.
C.
Add a solution to the hair to see if it reacts.
D.
Use a Hemastix strip to perform A-B-O testing.
The best way for her to accomplish the task of evaluating a hair strip is DNA testing. Hence, option A is correct.
What is DNA testing?The DNA testing in forensic laboratories include extract the DNA strands from the sample and strictly evaluate it some reagents and color indicators.
Hair analysis involves examining the DNA of cells linked to the hair's root as well as the hair's structure. It can be used to determine a person's family relationship. It is possible to use forensic hair analysis to identify a person who may have been at a crime scene. Hair samples are examined under a microscope and evaluated using particular chemicals.
Additionally, metal poisoning from lead or mercury can be detected through hair analysis. However, this form of testing often does not involve hair analysis alone.
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In the reaction below, if a total of 10.0 g of zinc and hydrochloric acid react completely, what is the total mass of zinc chloride and hydrogen produced?Zn(s) + 2HCl(aq) to ZnCl2(aq) + H2(g)Exactly 10.0 gLess than 10.0 gNot enough information to tellGreater than 10.0 g
Answer:
Not enough information to tell.
Explanation:
What is given?
Mass of Zn = 10.0 g,
Mass of HCl = 10.0 g,
Molar mass of Zn = 65.4 g/mol,
Molar mass of HCl = 36.4 g/mol,
Molar mass of ZnCl2 = 136.2 g/mol,
Molar mass of H2 = 2 g/mol.
Step-by-step solution:
First, let's convert 10.0 g of each reactant to moles using their respective molar mass:
[tex]\begin{gathered} 10.0\text{ g Zn}\cdot\frac{1\text{ mol Zn}}{65.4\text{ g Zn}}=0.153\text{ moles Zn,} \\ \\ 10.0\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=0.275\text{ moles HCl.} \end{gathered}[/tex]Now, let's identify what is the limiting reactant. Let's see how many moles of ZnCl2 can be produced by 0.153 moles of Zn if 1 mol of Zn reacted produces 1 mol of ZnCl2, and how many moles of ZnCl2 can be produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of ZnCl2:
[tex]\begin{gathered} 0.153\text{ moles Zn}\cdot\frac{1\text{ mol ZnCl}_2}{1\text{ mol Zn}}=0.153\text{ moles ZnCl}_2, \\ \\ 0.275\text{ moles HCl}\cdot\frac{1\text{ mol ZnCl}_2}{2\text{ moles HCl}}=0.138\text{ moles ZnCl}_2. \end{gathered}[/tex]You can realize that the limiting reactant, in this case, is HCl because is the first reactant consumed first and this reactant 'impose' the limit to produce the products.
So now, let's find how many moles of H2 are being produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of H2:
[tex]0.275\text{ moles HCl}\cdot\frac{1\text{ mol H}_2}{2\text{ moles HCl}}=0.138\text{ moles H}_2.[/tex]The final step is to convert each number of moles of each product to grams using their respective molar mass, as follows:
[tex]\begin{gathered} 0.138\text{ moles ZnCl}_2\cdot\frac{136.2\text{ g ZnCl}_2}{1\text{ mol ZnCl}_2}=18.8\text{ g ZnCl}_2, \\ \\ 0.138\text{ moles H}_2\cdot\frac{2\text{ g H}_2}{1\text{ mol H}_2}=0.276\text{ g H}_2. \end{gathered}[/tex]We're producing 18.8 g of zinc chloride (ZnCl2), and 0.276 g of hydrogen (H2), so based on this logic the answer would be not enough information to tell.
Balance each of these reactions and indicate the type of reaction each equation represents: a) NH3 → N2 + H2 b) Ba(C2H3O2)2 + Na3PO4 → Ba3(PO4)2 + NaC2H3O2 c) Zn + HCl → ZnCl2 + H2 d) Hg + O2 → HgO
Answer:
Explanation:
Here, we want to balance the chemical equation and state the type of chemical reaction
In balancing the chemical equation, we have to ensure that the number of atoms we have on the left hand side is same as what we have on the right hand side
We have this as:
[tex]3Ba(C_2H_3O_2)_2+2Na_3PO_4\text{ }\rightarrow Ba_3(PO_4)_2+6NaC_2H_3O_2[/tex]To get the type of reaction, we can see that there is an exchange of ionic groups between the individual metallic ions
This type of reaction is called a double displacement reaction
How many grams of carbon monoxide gas would be contained in 710 mL at 119 kPa and 37 C
Answer
0.9166 g CO
Procedure
Considering the conditions and parameters given ideal gas law will be assumed.
[tex]PV=nRT[/tex]The gas constant is 8.3144 L⋅kPa⋅ K⁻¹⋅mol⁻¹
Converting the current data to the required units
710 mL = 0.710 L
37 °C = 310.15 °K
Solving for moles and substituting the variables with the available data
[tex]n=\frac{PV}{RT}=\frac{119\text{ }kPa(0.710)L}{8.3144\text{ L. kPa\cdot}\degree\text{K^^^^207b^^b9\cdot mol^^^^207b^^b9 \lparen310.15\rparen }\degree K}=0.0327\text{ }moles\text{ CO}[/tex]Transforming from moles to grams using the molecular weight
[tex]0.0327\text{ }moles\text{ }CO\frac{28.01\text{ }g}{1\text{ }mole}=0.9166\text{ }g\text{ }CO[/tex]can someone please help me with question 27 B please!
Answer:
Sodium carbonate + Nitric acid → sodium nitrate + water + carbon dioxide. - To write the balanced chemical reaction between sodium carbonate and nitric acid we should know the chemical formula of them. - The chemical formula of sodium carbonate is Na2CO3 and the chemical formula of nitric acid is HNO3
Explanation:
hope it help
