Answer:
Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.Answer:
because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.
Explanation:
please mark as brainlest
I would like to know why this is the correct answer
-The harder a gas pedal in a car is pressed, the faster the car’s velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?
*There is both a positive correlation and causation
Answer:
see below
Explanation:
First, the obvious, as you press the gas pedal harder the acceleration goes up as well. Conversely, is you do not press the pedal, you will not accelerate. This determines that is I press the gas pedal, it will CAUSE the car to accelerate. This proves causation.
Now, correlation. The definition of correlation in statistics is any statistical relationship between two random variables or data. This simply means that these two events are connected to one another. A POSITIVE correlation is when two correlated events move in the same direction as one another. I have added a graph to help visualize this. In this problem as the gas is pressed harder, the acceleration increases. If the pressure on the pedal was decreased, then the acceleration also decreases. If the pressure on the pedal is constant, the the acceleration is constant.
I hope this helps!
A heater is rated to dissipate 1440 W when connected to a 120 V source. The current drawn by the device is
Answer:
The current drawn by the heater is 12 A.
Explanation:
Given;
power dissipated by heater, P = 1440 W
Source voltage, V = 120 V
The electric power of the heater is given by;
P = IV
Where;
I is the current drawn by the heater
Make I the subject of the formular;
I = P / V
Substitute the given values and solve for the current "I";
I = 1440 / 120
I = 12 A
Therefore, the current drawn by the heater is 12 A.
If the original experiment is repeated with a 1.0 kg aluminum block, what is the final temperature of the water and block
Answer:
T₂ = 36.36°C
Explanation:
The complete question is:
A 0.5 kg block of aluminum (Caluminum = 900J/kg*C)is heated to 200 C. The block is then quickly placed in an insulated tub of cold water at 0C (Cwater=4186J/kg*C) and sealed. At equilibrium, the temperature of the water and block are measured to be 20C.
A) If the original experiment is repeated with a 1.0 kg {kg} aluminum block, what is the final temperature of the water and block?
Answer: We will apply the law of conservation of energy here:
Heat Loss by Aluminum Block = Heat Gained by Water
m₁C₁ΔT₁ = m₂C₂ΔT₂
where,
m₁ = mass of aluminum block
C₁ = Specific Heat Capacity of Aluminum Block = 900 J/kg °C
ΔT₁ = Change in Temperature of Aluminum Block
m₂ = mass of water
C₂ = Specific Heat Capacity of Water = 4186 J/kg °C
ΔT₂ = Change in Temperature of water
Therefore, for initial given condition:
m₁ = 0.5 kg
ΔT₁ = 200°C - 20°C = 180°C
m₂ = ?
ΔT₂ = 20°C - 0°C = 20°C
Therefore,
(0.5 kg)(900 J/kg °C)(180°C) = m₂(4186 J/kg °C)(20°C)
m₂ = 81000 J/(83720 J/kg)
m₂ = 0.97 kg
Now, we have the mass of water. So, we can solve for the final equilibrium temperature if the mass of block is changed to 1 kg. So, for the new state:
m₁ = 1 kg
m₂ = 0.97 kg
ΔT₁ = 200°C - T₂
ΔT₂ = T₂ - 0°C
T₂ = Final Equilibrium Temperature = ?
Therefore,
(1 kg)(900 J/kg °C)(200°C - T₂) = (0.97 kg)(4186 J/kg °C)(T₂ - 0°C)
180000 J - (900 J/°C)(T₂) = (4050 J/°C)(T₂)
180000 J = (900 J/°C)(T₂) + (4050 J/°C)(T₂)
T₂ = (180000 J)/(4950 J/°C)
T₂ = 36.36°C
So basically there is this chart and all you just to name what energy will transform into what energy so like here is just an example like solar to mechanical or something like sorry the arrows are a bit scuffed
Answer:
free points let's gooo
An experimental electrical generator collects sunlight with mirrors and generates heat at a rate of 1.2 megawatts. The generator is mounted on the roof of an environmentally friendly building and is used to operate an elevator. The elevator has a maximum operating load of 8000 kg and a maximum velocity of 6 m/s.
A. Determine the power that the generator must supply to operate the elevator at its maximum operating
B. What is the efficiency of this system?
Answer:
a) 0.47MW
b) 39.24%
Explanation:
In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:
P=Fv
where P is the power, F is the force and v is the velocity.
The force the elevator must carry can be calculated with the following formula:
F=mg
where m is the mass of the elevator and g is the acceleration of gravity, so:
[tex]F=(8000 kg)(9.81 m/s^{2})[/tex]
F=78 480 N
so now we can make use of the power formula:
P=Fv
P=(78 480N)(6 m/s)
P=470 880W
P=0.47W
b)
In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:
[tex]efficiency = \frac{P_{in}}{P_{out}}*100\%[/tex]
[tex]efficiency=\frac{0.470880}{1.2}*100\%[/tex]
efficiency=39.24%
A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mouse?
Answer:
3.39 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
3.39 JHope this helps you
Answer:
im not sure
Explanation:
I just need the answer to number 1 (with work please)
(Newton’s Second Law)
Answer:
wish I could help
Explanation:
I been rereading this and I can't solve it lemme go ask people in ma house real quick
A car is moving with a speed of 32.0 m/s. The driver sees an accident ahead and slams on the brakes, causing the car to slow down with a uniform acceleration of magnitude 3.50 m/s2. How far does the car travel after the driver put on the brakes until it comes to a stop?
Answer:
292 m
Explanation:
Step one:
given data
initial velocity velocity v= 32 m/s
final velocity u= 0 m/s
acceleration a= 3.5m/s^2
Required
The distance covered upon the application of the brake
Step two:
we know that acceleration
a= v-u/t
t= v-u/a
t= (0-32)/3.5
t=32/3.5
t=9.14seconds
also, to find distance, we use s=d/t,
rearrange as d=s*t
d=32*9.14 s
d=292 m
A 0.2-kg stone attached to a string is swung in a circle with a radius 0.6 m on a horizontal frictionless surface. What is the tension in the string if the stone makes 150 revolutions per minute?
Answer:
The value is [tex]T = 29.58 \ N[/tex]
Explanation:
From the question we are told that
The mass of the stone is [tex]m = 0.2 \ kg[/tex]
The radius of the circle is [tex]r = 0.6 \ m[/tex]
The angular speed is [tex]w = 150 \ rpm = \frac{ 2 * \pi * 150 }{ 60 } = 15.7 \ rad/s[/tex]
Generally the tension in the string is mathematically represented as
[tex]T = m * r * w ^2[/tex]
=> [tex]T = 0.2 * 0.6 * 15.7 ^2[/tex]
=> [tex]T = 29.58 \ N[/tex]
A typical road bike wheel has a diameter of 70 cm including the tire. In a time trial, when a cyclist is racing along at 12 m/s how fast is a point at the top of the tire moving?
Answer:
24 m/s
Explanation:
Given that,
A typical road bike wheel has a diameter of 70 cm including the tire.
Speed of the cyclist = 12 m/s
We need to find the speed at the top of the tire moving. The velocity of the topmost point is twice that of the velocity of the object.
v = 2 × 12
= 24 m/s
Hence, the required velocity is 24 m/s.
The speed at which the point at the top of the tire moves is 24 m/s.
Given that,
A typical road bike wheel has a diameter of 70 cm including the tire.In a time trial, when a cyclist is racing along at 12 m/s.Based on the above information, the calculation is as follows:
We know that the velocity of the point should be the twice of the object velocity.
So,
= 2 (12)
= 24 m/s
Therefore we can conclude that the speed at which the point at the top of the tire moves is 24 m/s.
Learn more: brainly.com/question/23334479
What is the only bone of the skull that moves?
Answer:
Mandible.
Explanation:
The mandible in the bone that allows you to open and close your mouth, otherwise known ad the jawbone.
Answer:
mandible
Explanation:
which is also the lower jaw and it allows the mouth to open and close
hope i helped
A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate the magnitude of the magnetic field inside the solenoid.
Answer:
The value is [tex]B = 0.0643 \ T[/tex]
Explanation:
From the question we are told that
The length of the solenoid is [tex]L = 133 \ cm = 1.33 \ m[/tex]
The radius is [tex]r = 2.99 \ cm = 0.0299 \ m[/tex]
The number of turns is [tex]N = 1740 \ turns[/tex]
The current it carries is [tex]I = 3.91 \ A[/tex]
Generally the magnitude of the magnetic field is mathematically represented as
[tex]B = \frac{\mu_o * N * I}{L}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi *10^{-7} \ N/A^2[/tex]
=> [tex]B = \frac{ 4\pi * 10^{-7} * 1740 * 3.91}{0.133}[/tex]
=> [tex]B = 0.0643 \ T[/tex]
Can someone help me with this question please picture is above
Answer:
It should be B.
Explanation:
Because expansionary monetary policy works by expanding the money supply faster than usual or lowering short-term interest rates. It is enacted by central banks and comes about through open market operations, reserve requirements, and setting interest rates.
I hope this helped!!!
The crowd at a concert lifts a singer to a height of 2.2 m. The crowd uses a total of force of 600 N. How much work has the crowd done?
Answer:
1320 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 600 × 2.2
We have the final answer as
1320 JHope this helps you
An upright spring with a 96g mass on it is compressed 2 cm. When
released it travels 60 cm upwards. A) Calculate the spring constant. B)
Calculate its beginning speed when it takes off.
Answer:
I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5
Explanation:
Use the m*g*h=1/2*k*x^2 equation
96*9.81*60=1/2*k*2^2
5650.56=2k
5650.56/2=2825.28N/m
HEre now can somebody help!!
Pic is what i need help with
Answer:
which of the cars are speeding up: c
which of the cars or slowing down: a
which of the cars are maintaning a constant speed: b
Explanation:
Answer:
Explanation:
I gave a good enough explanation in your other posting. I'm sorry that I'm eating up your points.
The orange line is speeding up
The blue line is neither speeding up nor slowing down. It's speed is constant.
The green line is starting from 4 m/s and is slowing down to 0.
The diagram helps a lot. Thank you for that.
A laser emits a beam of light whose photons all have the same frequency. When the beam strikes the surface of a metal, photoelectrons are ejected from the surface. What happens if the laser emits twice the number of photons per second
Answer:
the no. of ejected electrons per second will increase.
Explanation:
In photoelectric effect, when a light is incident on a metal surface it ejects some electrons from the metal surface. The energy of photon of light must be equal to or greater than the work function of that metal. All the extra energy above the work potential appears as the kinetic energy of the ejected electrons. So, greater he energy of photon greater will be the kinetic energy of the ejected electrons.
A single photon interacts with a single electron and ejects it only if its energy is greater than work function. So, the increase in no. of photons per second means an increase in the intensity of laser beam. And greater no. of photons, will interact with greater no. of electrons. So, the no. of ejected electrons per second will increase.
A student claimed that thermometers are useless because a thermometer always registers its own
temperature. How would you respond?
Answer:
I wud respond no, actually it registers ur temperature
Light is shone on a diffraction grating
with d = 1.00 x 10-6 m. The second
order (m = 2) maximum occurs at an
angle of 74.6º. What is the
wavelength of the light IN
NANOMETERS?
[?] nm
Hint: The answer will be between 400 and 700.
Answer:
λ = 482.05 nm
Explanation:
The diffraction phenomenon and the diffraction grating is described by the expression
d sin θ = m λ
where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction
in this case they indicate the distance between slits, the angle and the order of diffraction
λ = [tex]\frac{d sin \theta }{m}[/tex]d sin θ / m
let's calculate
λ = 1.00 10⁻⁶ sin 74.6 / 2
λ = 4.82048 10⁻⁷ m
Let's reduce to nm
λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)
λ = 482.05 nm
A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.
Answer:
b. transparent
Explanation:
Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.
Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by
a push when the support string is at an angle of 45° from the vertical direction. The initial
speed of the suspended mass at the release point is 3.0 m/s.
(a) The maximum angle that pendulum moves in the second half of its swing is
(b) The mechanical energy of pendulum (measured relative to its lowest point) is
Answer:
A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?
Explanation:
Calculate the time needed to accelerate a 50 kg object from 2 m/s to 12 m/s if a force of 10 N is
applied.
Hi there!
[tex]\large\boxed{\text{50 seconds.}}[/tex]
Begin by calculating the acceleration on the object by using the formula
F = m · a (Newton's Second Law) where:
F = Force (N)
m = Mass (kg)
a = acceleration (m/s²)
Plug in the given values:
10 = 50 · a
10 = 50a
10 / 50 = a
a = 1/5 = 0.20 m/s²
Solve for the time using the kinematic equation:
Δv / a = t, or (vf - vi) / a = t
Plug in the acceleration along with the initial and final velocites into the equation:
(12 - 2) / 0.20 = 10 / 0.20 = 50 seconds.
Which requires more work: lifting a 100 kg sack a vertical distance of 2 m or lifting a 50 kg sack a vertical distance of 4 m?Explain.
Answer:
They both require the same amount of work.
Explanation:
Work is said to be done if the force applied to a body cause the boody to move through a distance. Mathematically;
Workdone = Force * Distance
Workdone = mass * acceleration due to gravity * Distance
For the 100kg sack lifted through a distance of 2m:
Workdone = 100 * 9.8 * 2
Workdone = 980 * 2
Workdone = 1960Joules
For 50kg sack lifted through a distance of 4m;
Workdone = 50 * 9.8 * 4
Workdone = 200 * 9.8
Workdone = 1960Joules.
Since the workdone in carry both sack is the same, hence they both require the same amount of work.
What is the water pressure at the deepest part of the ocean in the Challenger Deep in the Mariana Trench at 10,994 m below the surface.
Answer:
The pressure is 107417976.4 N[tex]m^{-2}[/tex]
Explanation:
The pressure of water at a given height/ depth can be determined by:
Pressure = σhg
Where: σ is the density of water, h is the height/ depth, and g is the gravitational force.
Given that; h = 10994 m, but σ = 997 kg/[tex]m^{3}[/tex] and g = 9.8 m/[tex]s^{2}[/tex]
Thus, the pressure of water at the deepest part of the ocean will be:
Pressure = 997 x 10994 x 9.8
= 997 x 107741.2
= 107417976.4
Pressure = 107 420 KN[tex]m^{-2}[/tex]
The pressure of water at 10994 m below the surface is 107417976.4 N[tex]m^{-2}[/tex]
If mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.
a. True
b. False
Answer:
False.
Explanation:
Given that if mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.
This statement is false. Because if mechanical energy is converted to thermal energy, there will be distortions in the solid pattern of the spring. And this will make the spring to compress.
Also, no matter what may happen to the spring, the spring constant remains constant. That is, unchanged.
Is it possible for the velocity of an object to be zero and its acceleration not zero?
Explanation:
Yes, it is possible to have zero speed while accelerating, but only for a moment. ... acceleration is the rate at which the speed and direction of an object changes over time, so whenever an object goes through zero speed while reversing directions, it has non-acceleration. zero but a speed of zero.
Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 248 Hz, while the other produces 288 Hz. When a tuning fork is sounded together with the 248-Hz tone, a beat frequency of 20.0 Hz is produced. When the same tuning fork is sounded together with the 288-Hz tone, a beat frequency of 20.0 Hz is produced. What is the frequency of the tuning fork
Answer:
F = 268 Hz
Explanation:
The beat frequency is given as:
[tex]Beat Frequency = |Frequency 1 - Frequency 2|\\[/tex]|
So, for the first flute and tuning fork:
[tex]20 Hz = |248 Hz - F|[/tex]
where,
F = Frequency of tuning fork
F = 248 Hz ± 20 Hz
F = 268 Hz (OR) 228 Hz
Now, for the second flute and tuning fork:
[tex]20 Hz = |288 Hz - F|[/tex]
where,
F = Frequency of tuning fork
F = 288 Hz ± 20 Hz
F = 268 Hz (OR) 308 Hz
Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.
F = 268 Hz
Janet jumps horizontally off a high diving platform with a velocity of 2.63 m/s and lands in the water 1.9 s later. How high is the platform
Answer:
The height of the platform is 22.686 m.
Explanation:
Given;
initial velocity of Janet, u = 2.63 m/s
time of her motion, t = 1.9 s
The height of the platform is given by;
h = ut + ¹/₂gt²
substitute the given values and solve for height "h"
h = (2.63 x 1.9) + ¹/₂(9.8)(1.9)²
h = 4.997 + 17.689
h = 22.686 m
Therefore, the height of the platform is 22.686 m.
Sandy soil has a relatively low thermal conductivity. Therefore, the surface layer over sandy soil will normally reach a lower temperature during the day than it would over soil that is moist or covered with vegetation.
a. True
b. False
Answer:
False
Explanation:
Granted, sandy soil has low conductivity, but the surface layer of sandy soil isn't low particularly during the day. Sandy soil reacts more to temperature when compared with other types of soil, and as such, during the day under a hot temperature, the texture of sandy soil is usually hot, and not low like the question suggested. Invariably, the inference the question is making is wrong and not correct, so false
A 1990 kg car moving at 20.0 m/s collides and locks together with a 1540 kg car at rest at a stop sign. Show that momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.
Answer:
The momentum before collision and momentum after collision is equal in a frame of reference moving at 10.0 m/s in the direction of the moving car.
Explanation:
[tex]m_1[/tex] = Mass of moving car = 1990 kg
[tex]u_1[/tex] = Velocity of moving car in stationary frame = 20 m/s
[tex]m_2[/tex] = Mass of stationary car = 1540 kg
[tex]u_2[/tex] = Velocity of stationary car in stationary frame = 0 m/s
v = Combined velocity in stationary frame
Momentum conservation for stationary frame
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{1990\times 20+0}{1990+1540}\\\Rightarrow v=\dfrac{3980}{353}\ \text{m/s}[/tex]
In frame moving at 10 m/s the velocities change in the following ways
[tex]u_1=20-10\\\Rightarrow u_1=10\ \text{m/s}[/tex]
[tex]u_2=0-10\\\Rightarrow u_1=-10\ \text{m/s}[/tex]
[tex]v=\dfrac{3980}{353}-10\\\Rightarrow v=\dfrac{450}{353}\ \text{m/s}[/tex]
Momentum before collision
[tex]m_1u_1+m_2u_2=1990\times 10+1540\times -10\\\Rightarrow m_1u_1+m_2u_2=4500\ \text{kg m/s}[/tex]
Momentum after collision
[tex](m_1+m_2)v=(1990+1540)\times \dfrac{450}{353}\\\Rightarrow (m_1+m_2)v=4500\ \text{kg m/s}[/tex]
The momentum before collision and momentum after collision is equal. So, the momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.
