Answer:
0.40
Explanation:
From the question, we're given that;
* 8% of the members run only long-distance, so the probability that a member of the team will run only long-distance, P(A) = 8/100 = 0.08
* 12% compete only in non-running events, so the probability that a member will compete only in non-running events, P(B) = 12/100 = 0.12
* 32% are sprinters only, so the probability that a member is a sprinter only P(C) = 32/100 = 0.32
We're asked in the question to determine the probability that a randomly chosen team member runs only long-distance or competes only in sprint events, since these events cannot occur at the same time, we can use the below formula to solve as shown below;
[tex]P(\text{A or C) = P(A) + P(C)}[/tex]P(A or C) = 0.08 + 0.32 = 0.40
the table below shows changes in the population densities of the zebra and you knew I'd muscles from 1991 to 2015, in six-year intervals.1. based on the data shown in the table calculate the percent change in the population density of zebra mussels from 1997 to 2003
The table below shows changes in the population densities of the zebra and you knew I'd muscles from 1991 to 2015, in six-year intervals.
1. Based on the data shown in the table calculate the percent change in the population density of zebra mussels from 1997 to 2003
_____________________
1997 (3 250)
2003 (2 500)
Percentage change= 100 *(new value- old value)/old value
Percentage change = 100 *(2500- 3250)/ 3250 = 100* (-0.2308)
Percentage change = -23.08%
__________________________________
Answer
The percent change in the population density of zebra mussels from 1997 to 2003 is -23.08%
There was a decrease of 23. 08%
Which probem situation can be represented by the equation below?3x +3 <11F Joe and Hannah together got less than 11 questions correct on their quizzes. Joe got 3 more questions correct than Hannah. What is x, the number of quiz questions Hannah got 3 correct?G A coin collection of dimes and quarters has less than 11 coins. The collection has more than 3 times as many quarters as dimes. How many dimes, x, is in the collection?H Two numbers have a sum that is less than 11. The larger number is 3 more than twice he smaller number. What s the smaller number, x?J The length of a rectangle is 3 inches more than the width, x. Three times the length is less than 11. What is the width of the rectangle?
Let x be correct questions of Joe and y be correct quiz question of Joe. The in equality for Joe and Hannah together questions is,
[tex]x+y<11[/tex]Joe got 3 more questions correct than Hannah, means equaltion is,
[tex]y=x+3[/tex]So inequality obtained is,
[tex]\begin{gathered} x+x+3<11 \\ 2x+3<11 \end{gathered}[/tex]Thus option F is incorrect.
Let x be number of dimes and y be number of quarters. So inequality for collection of coins is,
[tex]x+y<11[/tex]The number of quarters are,
[tex]y=3x[/tex]So resultant inequality is,
[tex]\begin{gathered} x+3x<11 \\ 4x<11 \end{gathered}[/tex]Thus option G is incorrect.
Let larger number be y. So sum of numbers is less than 11, means
[tex]x+y<11[/tex]The equation of larger number in terms of smaller number is,
[tex]y=2x+3[/tex]Substitute the value of y in the inequality to obtain the desired inequality.
[tex]\begin{gathered} x+2x+3<11 \\ 3x+3<11 \end{gathered}[/tex]Thus inequality obtained is 3x + 3 < 11.
Thus option H is correct.
Correct option : Two numbers have a sum that is less than 11. The larger number is 3 more than twice he smaller number. What s the smaller number, x?
Write 5^-15 with a positive exponent
Given:
[tex]5^{-15}[/tex]To change a negative exponent to a positive exponent, the variable will change from numerator to denominator and vice versa.
For example:
[tex]\begin{gathered} P^{-1}\text{ = }\frac{1}{P} \\ \\ We\text{ know that:} \\ 5^{-15}=5^{(15)-1} \\ \\ 5^{(15)-1}\text{ = }\frac{1}{5^{15}} \end{gathered}[/tex]Therefore, we have:
[tex]5^{-15}\text{ = }\frac{1}{5^{15}}[/tex]ANSWER:
[tex]\frac{1}{5^{15}}[/tex]5. a) Look at the number grid below. Shade the Multiples of 4, 1 2 3 4 5 6 7 00 8 9 10 11 12 13 14 15 16 17 17 18 19 20
We need to find the multiples of 4 using the next given set:
The multiples of 4 are given by
4*1 =4
4*2 = 8
4*3= 12
4*4=16
4 *5 =20
Then:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20.
Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of this function:h(x) = (x − 1)^2− 9.
The function is
[tex]h(x)=(x-1)^2-9[/tex]1) x-intercept(s)
The x-intercepts refer to the points on which the function intercepts with the x-axis, in other words, when y=h(x)=0
So, given that condition, we get
[tex]\begin{gathered} h(x)=0 \\ \Rightarrow(x-1)^2-9=0 \\ \Rightarrow x^2-2x+1^{}-9=0 \\ \Rightarrow x^2-2x-8=0 \\ \Rightarrow(x-4)(x+2)=0 \end{gathered}[/tex]Therefore, there are two x-intercepts, and those are the points
[tex](4,0),(-2,0)[/tex]2) y-intercepts
The y-intercepts happen when x=0. So,
[tex]\begin{gathered} x=0 \\ \Rightarrow h(0)=(0-1)^2-9=1-9=-8 \end{gathered}[/tex]So, there is only one y-intercept and it's on the point (0,-8)
3) Vertex
The general equation of a parabola is
[tex]y=f(x)=a^{}x^2+bx+c[/tex]There is another way to express the same function, which is called the 'vertex form':
[tex]\begin{gathered} y=f(x)=a(x-h)^2+k \\ \Rightarrow y=ax^2-2ahx+ah^2+k \end{gathered}[/tex]What is particularly useful of this vertex form is that the vertex is the point (h,k)
So, transforming h(x) into vertex form:
[tex]\begin{gathered} h(x)=(x-1)^2-9=a(x-h)^2+k \\ \Rightarrow\begin{cases}a=1 \\ h=1 \\ k=-9\end{cases} \end{gathered}[/tex]Therefore, the vertex is the point (h,k)=(1,-9)
4) Axis of symmetry
In general, the equation of the axis of symmetry is given by
[tex]x=-\frac{b}{2a};y=f(x)=ax^2+bx+c[/tex]Therefore, in our particular problem,
[tex]\begin{gathered} h(x)=x^2-2x-8=ax^2+bx+c \\ \Rightarrow\begin{cases}a=1 \\ b=-2 \\ c=-8\end{cases} \\ \end{gathered}[/tex]Thus, the equation of the line that is the axis of symmetry is
[tex]x=-\frac{b}{2a}=-\frac{(-2)}{2\cdot1}=-\frac{(-2)}{2}=1[/tex]Then, the axis of symmetry is the line x=1.
Summing up the information in the four previous steps, we get
how do I graph the line with the given slope m and y-intercept b.
m=5/3,b=-4
y=(5/3)x+4
I am aware that the slope is "big," m = - 5 /3, and that the yy-intercept is "left(0, 4), right" (0,4). The final graph of the line should be declining when viewed from left to right because the slope is negative.
y = mx+c
how to draw this graph?
step 1: Plot the given equation's yy-intercept, which is left(0,4right), first (0,4).
On the xy axis, the position (0,4) .
step2: Use the slope largem = -5 /3
m= 5/3
to locate a different point using the y-intercept b as a guide. The slope instructs us to move 3 units to the right after dropping down 5 units.
To find the opposite spot, start at (0,4) and go 5 units down and 3 units to the right.
Step 3: Make a line that goes through all of the points.
Create a line that joins the coordinates (0,4) and (3,5)
To learn more about y-intercept b refer to:
https://brainly.com/question/26231013
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Write the ordered pair with no spaces (x,y) of point C for j(x).
This problem is about functions.
In this case, we don't have function j(x) defined in order to find its ordered pairs.
However, assuming that function j(x) is a function of f(x), we can deduct that points C is
[tex]C(0,0)[/tex]Use compatible numbers.4,921 ÷ 63
Given:
The objective is to divide the 4921÷ 63 using compatible numbers.
Explanation:
First, the compatible numbers are,
[tex]\begin{gathered} 4921=4920 \\ 63=60 \end{gathered}[/tex]To calculate division:
Now, the division can be performed as,
Hence, the value of the division is 82.
4. Identify the properties that are always true for the given quadrilateral by placing an X in the appropriate box. Property Parallelogram Rectangle Rhombus Square Isosceles Trapezoid Kite a. Opposite sides are parallel. b. Only one pair of opposite sides is parallel C. Opposite sides are congruent Side Relationships d. Only one pair of opposite sides is congruent e. All sides are congruent. f. 2 pairs of consecutive sides are congruent.
There is quadrilateral, means it has 4 lines
Is a rhombus
An inverted pyramid is being filled with water at a constant rate of 30 cubic centimeters per second . The pyramíd , at the top, has the shape of a square with sides of length 7cm and the height is 14 cm.
ANSWER :
The answer is 30 cm/sec
EXPLANATION :
We have an inverted square pyramid with a square side of 7 cm and a height is 14 cm.
We need to find the area of the square at 2 cm from below.
Using similar triangles, we will express the side view as 2D :
We need to find the side of the square at 2 cm level.
The ratio of the sides of the smaller triangle and bigger triangle must be the same :
[tex]\begin{gathered} \frac{\text{ smaller}}{\text{ bigger}}=\frac{x}{7}=\frac{2}{14} \\ \\ \text{ Solve for x :} \\ \text{ Cross multiply :} \\ 14x=7(2) \\ 14x=14 \\ x=\frac{14}{14}=1 \end{gathered}[/tex]So the value of x is 1, then the side of the square at 2 cm level is 1 cm
The area of that square is :
A = 1 x 1 = 1 cm^2
The inverted pyramid is filled with water at a constant rate of Q = 30 cm^3 per second.
And we are asked to find the rate when the water level is 2 cm or when the area of the square is 1 cm^2 from the result we calculated above.
Recall the formula of rate :
[tex]\begin{gathered} Q=AV \\ \text{ where :} \\ Q\text{ = constant rate in }\frac{cm^3}{sec} \\ \\ A\text{ = Area of the section in }cm^2 \\ \\ V\text{ = Velocity or rate in }\frac{cm}{sec} \end{gathered}[/tex]We have the following :
[tex]\begin{gathered} Q=30\text{ }\frac{cm^3}{sec} \\ \\ A=1\text{ }cm^2 \end{gathered}[/tex]Using the formula above, the rate is :
[tex]\begin{gathered} Q=AV \\ V=\frac{Q}{A} \\ \\ V=\frac{30\text{ }\frac{cm^{\cancel{3}}}{sec}}{1\text{ }\cancel{cm^2}} \\ \\ V=30\text{ }\frac{cm}{sec} \end{gathered}[/tex]6. ΔABC is mapped onto ΔA'B'C' by a dilation at D. Complete the statement: The dilation of 4/3 is _____. a. a reduction b. an enlargement
Dilation involves adjusting the size of an object or a figure, without altering its shape.
The object can be increased or decreased depending on its scale factor.
A scale factor less than 1 results in a figure of reduced dimensions whereas, a scale factor greater than 1 results in a figure or an object of enlarged dimensions.
In the ΔABC, a dilation of 4/3, which is greater than 1, will thus result into an enlargement.
The correct option is B.
find the value of x so that the function has the given value
j(x) = -4/3x + 7; j (x) = -5
Answer:
x = 13 [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
j(x) = [tex]\frac{-4}{3}[/tex] x + 7 Substitute -5 for x
j(-5) = [tex]\frac{-4}{3 }[/tex] ( -5) + 7
or
j(-5) =[tex](\frac{-4}{3})[/tex] [tex](\frac{-5}{1})[/tex] + 7 A negative times a negative is a positive
j(-5) = [tex]\frac{20}{3}[/tex] + 7
j(-5) = [tex]\frac{20}{3}[/tex] + [tex]\frac{21}{3}[/tex] [tex]\frac{21}{3}[/tex] means the same thing as 7
j(-5) = [tex]\frac{41}{3}[/tex] = 13 [tex]\frac{2}{3}[/tex]
solve for x in the parallelogram below
Square ABCD is inscribed in a circle with radius 20 m . What is the area of the part of the circle outside of the square
ANSWER:
456 square meters
STEP-BY-STEP EXPLANATION:
The first thing is to represent the problem in the following figure:
To calculate the area of the part of the circle outside of the square, we must calculate the area of the circle and subtract the area of the inscribed square.
To calculate the area of the square, we plant the following, taking into account that the diagonal of the square is equal to twice the radius and the sides equal to the radius times the root of two, like this:
Knowing the value of the side of the square, we can directly calculate the area of the part of the circle outside of the square, subtracting the corresponding areas like this:
[tex]\begin{gathered} A=A_C-A_S_{} \\ A=\pi\cdot r^2-\mleft(r\cdot\sqrt{2}\mright)^2 \\ \text{replacing} \\ A=3.14\cdot20^2-\mleft(20\cdot\sqrt{2}\mright)^2 \\ A=1256-800 \\ A=456 \end{gathered}[/tex]The area of the part of the circle outside of the square is equal to 456 square meters
Which graph represents the function over the interval [−3, 3]?f(x)=⌊x⌋−2
Given:
[tex]f(x)=x-2\text{ ,\lbrack-3,3\rbrack}[/tex]In ATUV, the measure of ZV=90°, TV = 28, UT = 53, and VU = 45. What ratiorepresents the cosecant of ZU?
cosecant = hypotenuse / opposite side
hypotenuse = 53
opposite side = 28
cosecant U = 53/28
You can use a calculator to approximate the logarithm. Round to four decimal place
This is a simple question to solve when we use the calculator (as the question allows us to use it).
For this problem when we have :
[tex]\log \pi[/tex]It can be read as "log base 10 of pi", and using a calculator we find:
And that is the final answer.
NOTE: this result means that:
.
Right Triangle ABC is pictured below.Which equation gives the correct value for BC?Option 1: sin(32) = BC/8.2Option 2: cos(32) = BC/10.6Option 3: tan(58) = 8.2/BCOption 4: sin(58) = BC/10.6
Given the image, we are asked which equation gives the correct value for BC?
Explanation
From the image;
[tex]\begin{gathered} A+B+C=180 \\ 32+B+90=180 \\ B=180-90-32 \\ B=58^0 \end{gathered}[/tex]Therefore,
[tex]tan58^0=\frac{opposite}{Adjacent}=\frac{8.2}{BC}[/tex]Answer: Option three
the product of 4 and the diference of 9 and 2 find the value of your expression
Answer:
28
Step-by-step explanation:
4(9-2)
4(7)
28
octavius wants to write the equation of a line perpendicular to y=-4x + 5 that passes through the point (8,-3). Describe the mistake octavius made and write the correct equation of the line.
The equation of line perpendicular to 4y = x-8 passing through (4,-1) is:
[tex]y = \frac{1}{4} x-5[/tex].
What is a equation of line?These lines are written in the form y = mx + b, where m is the slope and b is the y-intercept. We know from the question that our slope is 3 and our y-intercept is –5, so plugging these values in we get the equation of our line to be y = 3x – 5.
Given equation of line is:
y=-4x + 5
Let [tex]m_{1}[/tex] be the slope of given line
Then,
[tex]m_{1}[/tex] = -4
Let [tex]m_{2}[/tex] be the slope of line perpendicular to given line
As we know that product of slopes of two perpendicular lines is -1.
[tex]m_{1}*m_{2} = -1\\- 4*m_{2}=-1\\ m_{2} = \frac{1}{4}[/tex]
The slope intercept form of line is given by
[tex]y = m_{2}x+c[/tex]
[tex]y = \frac{1}{4} x+c[/tex]
to find the value of c, putting (4,-1) in equation
[tex]-3= \frac{1}{4} *8+c\\-3-2 = c\\c = -5[/tex]
Putting the value of c in the equation
[tex]y=\frac{1}{4} x-5[/tex]
Hence, The equation of line perpendicular to 4y = x-8 passing through (4,-1) is [tex]y=\frac{1}{4} x-5[/tex].
To learn more about equation of line from the given link:
https://brainly.com/question/14315919
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The volume of the right cone below is 36π units ^3. Find the value of x
The formula to find the volume of a cone is:
[tex]\begin{gathered} V=\frac{1}{3}\pi r{}{}^2h \\ \text{ Where} \\ V\text{ is the volume} \\ r\text{ is the radius} \\ h\text{ is the heigth} \end{gathered}[/tex]Then, we replace the know values in the above formula and solve for h.
[tex]\begin{gathered} V=36\pi \\ r=\frac{\text{ diameter}}{2}=\frac{6}{2}=3 \\ h=x \end{gathered}[/tex][tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ 36\pi=\frac{1}{3}\pi(3)^2x \\ 36\pi=\frac{9\pi x}{3} \\ 36\pi=3\pi x \\ \text{ Divide by }3\pi\text{ from both sides} \\ \frac{36\pi}{3\pi}=\frac{3\pi x}{3\pi} \\ 12=x \end{gathered}[/tex]AnswerThe value of x is 12 units.
helpppppppppppppppppppppppppppppppppppppp
Answer:
[tex]\large \text{$f^{-1}(x) = 3x -6$}[/tex]
Graphs attached
Step-by-step explanation:
Your inverse function is correct. So not sure what additional information you need
I am not familiar with the graphing tool you have been provided with. My graph is attached. I used a free online graphing tool
Express 80 as the product of its prime factors Write the prime factors in ascending order.
Answer:
2×2×2×2×5
Step-by-step explanation:
Express 80 as the product of its prime factors Write the prime factors in ascending order.
2 × 2 × 2 × 2 × 5
2×2×2×2×5 = 80
Please help, disregard the option I chose because I'm not sure it's right :)
Consider that the graph of f(x) is the graph of a cubic function, that is, the graph of a 3 degree polynomial. If you apply first derivative to such a polynomial, the result is another polynomial of degree 2.
Now, take into account that the graph of a polynomial of degree 2 is a parabola. The parabola can open up or down. It depends of the leadding coefficient of the polynomial. In this case, due to the graph of f(x), the leadding coefficient is positive, which means that the parabola of f'(x) opens up.
Hence, you can conclude that the graph of f'(x) is option C.
which calculation does not show the surface area of the cube?
Given: A cube with side 6.5 cm
Required: Which calculation does not show the surface area of the cube.
Explanation:
Surface area of cube with side a is 6a².
So here the surface area of cube is
[tex]6(6.5)^2[/tex]Oprion 2, 3 and 4 reflects the calculation correctly.
But option A is actually the volume of the cube, it is not a correct way to show surface area of the cube.
Final Answer: option A is correct.
A chemist has 30% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 570 liters of 31% acid solution? Work area number of liters | acid strength | Amount of acid 30% acid solution 60% acid solution 31% acid solution liters of 30% acid liters of 60% acid
Let the amount of 30% acid solution be a
Let the amount of 60% acid solution be b
Given, "a" and "b" mixed together gives 570 liters of 31% acid. We can write:
[tex]0.3a+0.6b=0.31(570)[/tex]Also, we know 30% acid and 60% acid amounts to 570 liters, thus:
[tex]a+b=570[/tex]The first equation becomes:
[tex]0.3a+0.6b=176.7[/tex]We can solve the second equation for a:
[tex]\begin{gathered} a+b=570 \\ a=570-b \end{gathered}[/tex]Putting this into the first equation, we can solve for b. The steps are shown below:
[tex]\begin{gathered} 0.3a+0.6b=176.7 \\ 0.3(570-b)+0.6b=176.7 \\ 171-0.3b+0.6b=176.7 \\ 0.3b=176.7-171 \\ 0.3b=5.7 \\ b=\frac{5.7}{0.3} \\ b=19 \end{gathered}[/tex]So, a will be:
a = 570 - b
a = 570 - 19
a = 551
Thus,
551 Liters of 30% acid solution and 19 Liters of 60% acid solution need to be mixed.
21/x=48/96. 70/b=20/80. 50/20=x/72
In summary, the respective values of the unknown variables in the equations are 42, 280, and 1800.
i need help with this asap please check work when done
Given the parent function
[tex]y=\cos x[/tex]From the graph,
The range of the function is best modelled by the interval
Comparing the function with general equation of the cosine function,
[tex]B=1[/tex]The formula for the period is,
[tex]T=\frac{2\pi}{B}[/tex]There
Factor the following expression using the GCF.5dr - 40rr(5 dr - 40)5 r( d - 8)r(5 d - 40)5( dr - 8 r)
The greatest common factor (GCF) is: 5r
You multiply 5r by d to get the first term and multiply 5r by -8 to get the second term, then the factors are:
[tex]5r(d-8)[/tex]Answer: 5r(d-8)1. Canada has the longest coastline of any country. It is 202,080 km. China has 22,147 km of borders - more than any other countries. What is the difference between the two lengths? Label your answer!!
Canada has a coastline if 202,080km and China has 22,147 of borders, so the difference between them can be writen like this:
[tex]202080-22147[/tex]And we can made this operation so the answer is:
[tex]202080-22147=179,933[/tex]This means that the coastline of canada is 179,933 longer than the border of china
