I need help cause I’m lazy to do it myself it’s 4 in the morning

Answer:

I need help w this question to answer it plz!

Answer:

Step-by-step explanation:

You will need to add a picture

Answer:

D.6

Step-by-step explanation:

Answer:

$2720

Step-by-step explanation:

Interest = P×R×T /100

= 2000×12×3 /100

=72000/100 = $720

Amount = Principal + Interest

= $2000+$720 =$2720

Answer:

8.25

Step-by-step explanation:

(-10,-7) (-8,1) find the distance between the two points show work.

The formula for calculating the distance between the two points is expresses as;

D = √(x2-x1)²+(y2-y1)²

D = √(-8+10)²+(1+7)²

D = √(2)²+8²

D = √4+64

D = √68

D = 8.25

Hence the distance between the two points is 8.25

Answer:

It's B because If you cover the blue you will see space that looks like a triangle. Do the same to A. You see how in B the Triangle looking thing is lower than A because A triangle thing is like more up and wider so it has space. Also B has a little space than A

Step-by-step explanation:

Answer:

A water taxi travels around an island in a path that can be modeled by the equation y =0.5(x - 16). A water skier is skiing along a path that begins at the point (6,6) and ends at the point (8. - 4).

a. Write a system of equations to model the problem.

b. Is it possible that the water skier could collide with the taxi? Explain

Step-by-step explanation:

Answer:

tooth A

Step-by-step explanation:

0.23 = 0.230

0.230 > 0.195

Answer:

a

Step-by-step explanation:

Answer:

a) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{6}[/tex] of area A.

b) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{18}[/tex] of area B.

c) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{3}[/tex] of area C.

d) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{4}[/tex] of area D.

e) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{2}[/tex] of area E.

Step-by-step explanation:

According to stament, the area A is 6 square centimeters, the area B is 18 square centimeters, the area C is 3 square centimeters, the area D is 4 square centimeters and the area E is 2 square centimeters.

The purpose of this exercise is determine all ratios associated with each area, defined as a given area divided by the total area. Then, we proceed to determine each result:

([tex]A_{given} = 1\,cm^{2}[/tex], [tex]A_{A} = 6\,cm^{2}[/tex], [tex]A_{B} = 18\,cm^{2}[/tex], [tex]A_{C} = 3\,cm^{2}[/tex], [tex]A_{D} = 4\,cm^{2}[/tex], [tex]A_{E} = 2\,cm^{2}[/tex])

[tex]r_{A} = \frac{1\,cm^{2}}{6\,cm^{2}}[/tex]

[tex]r_{A} = \frac{1}{6}[/tex]

[tex]r_{B} = \frac{1\,cm^{2}}{18\,cm^{2}}[/tex]

[tex]r_{B} = \frac{1}{18}[/tex]

[tex]r_{C} = \frac{1\,cm^{2}}{3\,cm^{2}}[/tex]

[tex]r_{C} = \frac{1}{3}[/tex]

[tex]r_{D} = \frac{1\,cm^{2}}{4\,cm^{2}}[/tex]

[tex]r_{D} = \frac{1}{4}[/tex]

[tex]r_{E} = \frac{1\,cm^{2}}{2\,cm^{2}}[/tex]

[tex]r_{E} = \frac{1}{2}[/tex]

a) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{6}[/tex] of area A.

b) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{18}[/tex] of area B.

c) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{3}[/tex] of area C.

d) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{4}[/tex] of area D.

e) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{2}[/tex] of area E.

Answer:

[tex]\boxed {\boxed {\sf 1. \ 20 }}[/tex]

Step-by-step explanation:

An equilateral triangle has 3 equal sides and angles. Remember that equilateral sounds like equal.

The interior angles of a triangle must equal 180 degrees.

The question tells us the angle is equal to (4x-20).

So, by substitution, we can set 60 and (4x-20) equal to each other.

[tex]60=4x-20[/tex]

Now, solve for x by isolating the variable on one side of the equation.

20 is being subtracted from 4x and the inverse operation of subtraction is addition. Add 20 to both sides of the equation.

[tex]20+60=4x-20+20 \\ 20+60=4x\\80=4x[/tex]

x is being multiplied by 4. The inverse operation of multiplication is division. Divide both sides of the equation by 4.

[tex]\frac{80}{4}=\frac{4x}{4}[/tex]

[tex]\frac{80}{4}=x \\\ 20=x[/tex]

x is equal to 20 and choice 1 is correct.

Answer:

B

Step-by-step explanation:

Becuase 1 divide 1/2

You make the division sign a multiplication sign

1 time 1/2

get the recipricol of 1/2 wich is 2

1 times 2/1

is 2

Answer:

(5, 1) is the answer.

Step-by-step explanation:

This is because the point (5, 1) is NOT in the shaded area of the inequality. All the other points are either in the shaded area of the inequality, or on the line of the inequality equation.

Hope this helps!! :)

#teamtrees #WAP (Water And Plant)

Answer:

(5,1)

Step-by-step explanation:

Answer:

14 years

Step-by-step explanation:

£280 is 7% of 4000 so £4000 euro more would be 4000/280 = 14

Answer:

A.v

V for volume

I hope this helps:

Answer:

he is right v

Step-by-step explanation:

v is the common variable for volume

Answer:

n + 10

Step-by-step explanation:

We can substitute unknown number with any variable, such as n, and substitute increased by ten with + 10, because we are adding 10. Therefore, the answer is n + 10.

Answer:

Given AABC with coordinates A(2, 3), B(0, 6) and C(2, 6) b) Graph and ... c) Graph and label AA``B``C`` the image of AABC after D1/2. T2,4. R 180. D1/2.

Step-by-step explanation:

Given AABC with coordinates A(2, 3), B(0, 6) and C(2, 6) b) Graph and ... c) Graph and label AA``B``C`` the image of AABC after D1/2. T2,4. R 180. D1/2.

Answer: Location A: 6.04, since a negative and a negative is a positive. 6.04--1.08=7.12

Location C: 6.9

7.34-0.44=6.9

Step-by-step explanation:

Difference between high tide and low tide at location C is equal to 6.9 and high tide at location A is equal to 6.04

Tides originate in the oceans and progress toward the coastlines where they appear as the regular rise and fall of the sea surface. When the highest part, or crest of the wave reaches a particular location, high tide occurs; low tide corresponds to the lowest part of the wave, or its trough.

Given here Difference between high tides and low tides                                = high tide - low tide

= HT - LT    . . . . . . . (1)

thus, Difference between high tide and low tide at location C is = 7.34 -0.44    

                                                                                                          =  6.9

And high tide at location A is = (Difference between HT & LT) +  LT  (from  eqn 1)

                                                = 7.12 + ( -1.08)

                                                = 6.04

Hence, Difference between high tide and low tide at location C is equal to 6.9 and high tide at location A is equal to 6.04

Learn more about high tide and low tide here:

https://brainly.com/question/14683300

#SPJ2

9514 1404 393

Answer:

  log₁₂(4)

Step-by-step explanation:

The applicable rule of logarithms (to the same base) is ...

  log(a^b) = b·log(a)

__

Then the expression simplifies as follows:

  [tex]3\log_{12}(2)+\dfrac{1}{3}\log_{12}(2^3)-\log_{12}(2^2)\\\\=3\log_{12}(2)+\dfrac{3}{3}\log_{12}(2)-2\log_{12}(2)=(3+1-2)\log_{12}(2)\\\\=2\log_{12}(2)=\log_{12}(2^2)=\boxed{\log_{12}(4)}[/tex]

Answer:

y=3x+3

Step-by-step explanation:

9=3(2)+c

9=6+c

c=3

Answer:

-18

Step-by-step explanation:

-8 + 70/-7

-8 - 10

-18

Answer:

sorry i will answer if you make me branlyist

Step-by-step explanation:

Answer:

5^2=25 and 0.8^2= 0.64

Step-by-step explanation:

soo 25+0.64 equals..... 25.64!!!

Answer:

It will take 50 minutes.

Step-by-step explanation:

Because if you are trying to get 45.5 to 15.5 you need to drain 30 gallons of water, and to do that it will take 50 minutes because 0.6*50=30.

Hope this helps!

Pls mark brainliest if it is correct

Answer:

less - than is the answer

hope it helps you

Answer:

a

Step-by-step explanation:

-edge 2021

Answer:

dont cheat

Step-by-step explanation: