I need help with this!

I Need Help With This!

Answers

Answer 1

Answer:

3. 8÷ x² is the correct answer.


Related Questions

Triangle DEF is shown below.

How many degrees GREATER is the sum of the measures of angle D and E than the measure of angle f?

Answers

The sum of the measures of angles D and E and the measure of angle F will be 3x + 35. Then the correct option is C.

What is the triangle?

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180°.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The information is given below.

∠D = 3(x + 10)

∠E = (2x + 15)

∠F = 2(x + 10)

The sum of the measures of angle D and E than the measure of angle F is calculated as,

⇒ ∠D + ∠E - ∠F

⇒ 3(x + 10) + 2(x + 10) - (2x + 15)

Simplify the expression, then we have

⇒ 3(x + 10) + 2(x + 10) - (2x + 15)

⇒ 3x + 30 + 2x + 20 - 2x - 15

⇒ 3x + 30 + 5

⇒ 3x + 35

The sum of the measures of angles D and E and the measure of angle F will be 3x + 35. Then the correct option is C.

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a belt is drawn tightly around three circles of radius 10 cm each, as shown. the length of the belt, in cm, can be written in the form a + b\pi for rational numbers a and b. what is the value of a + b?

Answers

Answer:

  80 cm

Step-by-step explanation:

You want a function of the length of the perimeter belt around three packed circles of radius 10 cm.

Perimeter

Examination of the attached figure shows the length of the belt is the sum of the lengths of the sides of an equilateral triangle with sides 20 cm, and the circumference of a circle with diameter 20 cm.

  triangle perimeter = 3s = 3(20 cm) = 60 cm

  circle circumference = πd = π(20 cm) = 20π cm

The length of the belt is the sum of these, or

  60 cm +20π cm = (60 +20π) cm

Function

Compared to (a +bπ) cm, we find a=60, and b=20. The desired sum is ...

  a +b = 60 +20 = 80

__

Additional comment

You will notice that equilateral triangle PQR in the attached figure has side lengths that are twice the radius of the circle. The straight segments AB, A'B', A"B" are parallel to the triangle sides, and are the same length. (ABPR is a rectangle.)

Each circular arc, BA', for example, is 1/3 of the circumference of the circle, so the total length of all the arcs is the circumference of one 20 cm circle.

The Quasi JX is a new car model. Under ideal driving conditions, the Quasi Jx’s fuel economy is E kilometers per liter (E*km/L) when its driving speed is constant at S kilometers per hour (S*km/h).
In terms of the variables S and E, select the expression that represents the number of liters of fuel used in 1 hour of driving under ideal driving conditions at a constant speed S, and select the expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed S. Make only two selections, one in each column.

Answers

Liters of fuel in 1 hr is S/E and Liters of fuel in 60 km is 60/E

Liters of fuel in 1 hr: The Quasi JX travels E kilometers per liter of fuel (EkmL)(EkmL) at S kilometers per hour (Skmhr)(Skmhr). Therefore the Quasi JX requires 1E1E liters of fuel to travel 1 km. Since the Quasi JX travels S kilometers per hour, it requires 1E1E LkmLkm × S km/hr, or SELhrSELhr

Thus, Liters of fuel in 1 hr is S/E.

Liters of fuel in 60 km: The Quasi JX travels E kilometers per liter of fuel (EkmL). Therefore the Quasi JX requires 1E1E liters of fuel to travel 1 km. Given this, the Quasi JX uses 1/E L/km × 60 km, or 60/E L of fuel to travel 60 km.

Thus, Liters of fuel in 60 km is 60/E.

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The expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed S is written as 60/E

Here we have given that RO1, Liters of fuel in 1 hour

Here we also know that the Quasi JX travels E kilometers per liter of fuel (E km/L) at S kilometers per hour (S km/hr)

Now, we have to know that the Quasi JX requires 1/E liters of fuel to travel 1 km.

Here the JX travels S kilometers per hour, and here it requires

=> (1/E x L/km) × (S km/hr)

Then it can be written as when we apply the value of Ro1 is 60, then we get

=> 60/E

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Test this for x-axis symmetry y=-x^2-0.1

Answers

The axis of symmetry of the function is x = 0

How to determine the axis of symmetry

From the question, we have the following parameters that can be used in our computation:

y = -x^2 - 0.1

Differentiate the function

So, we have the following representation

y' = -2x

Set the differentiated function to 0

This gives

-2x =0

Divide both sides by -2

x = 0

Hence, the axis of symmetry is x = 0

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A number divided by 4 has a remainder. What numbers. Might the remainder be?Explain.

Answers

7

it could be 7 because if you think about it, 4 can't go into 7 evenly.

so the proper way to solve this would be by finding how many times 4 can go into 7 evenly

4 can go into 7 once evenly

3 times 1 is 3

so you would have 4 left over

1 r4

1. A particle moves along a straight line. The graph of the particle's position x(t) at time t is shown below over the interval [0,10]. The function has horizontal tangents at t=1.7 and t=6.9, and a point of inflection at t=4.3. Determine the values of t where the velocity of the particle is increasing. Justify your answers.

Answers

The particle increases its velocity in the following three subintervals:

0 < t < 2 4 < t < 7 9 < t < 10

How to determine the interval of times where the velocity is increasing

In this question we find the case of the position of a particle (x) in versus time (t), whose graph is shown below. The velocity associated to a given time t is represented by the slope of the line tangent to that point. The velocity of a particle increases when the signs of function position and function velocity are the same.

By secant line formula, velocity can be approximated by this formula:

v ≈ Δx / Δt

Since time is a non-negative real number, the sign of velocity is derived by the following rules:

Velocity is negative for Δx < 0.Velocity is zero for Δx = 0.Velocity is positive for Δx > 0.

Then, the velocity of the particle increases in the following two cases:

v(t) > 0, x(t) > 0.v(t) < 0, x(t) < 0.

The velocity is increasing in the following subinterval 0 < t < 2, 4 < t < 7 and 9 < t < 10.

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Can someone help me with this question?

Answers

Answer:

A

Step-by-step explanation:

The Expression Above Gives The Amount Of Money, In Dollars, Generated In A Year By A $1,000 Deposit In A Bank Account That Pays An Annual Interest Rate Of R %, Compounded Monthly. Which Of The Following Expressions Shows How Much Additional Money Is Generated At An Interest Rate Of 5% Than At An Interest Rate Of 3% ?
a. 1000 (1=5-3/1200)12
b. 1000 (1=5/3/1200)12
c. 1000 (1=5/1200)12
d. 1000 (1=5/1200)12-(1=3/1200)12

Answers

The expression which shows how much additional money generated at an interest rate of 5% than at an interest rate of 3% is: (1,000 (1 + 5 / 1,200) ^12) – (1,000 (1 + 3 / 1,200) ^12). The correct answer is option D.

The amount of money generated at the interest rate of 5% is shown by A₅ :

1,000 (1 + 5 / 1,200) ^12

And similarly, the amount of money generated at the interest rate of 3% is shown by A₃ :

1,000 (1 + 3 / 1,200) ^12

Hence, the additional amount of money will be shown by A₅ – A₃  :

(1,000 (1 + 5 / 1,200) ^12) – (1,000 (1 + 3 / 1,200) ^12)

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Although part of your question is missing, you might be referring to this full question: 1,000 (1 + r/1,200) ^12. The expression above gives the amount of money, in dollars, generated in a year by a $1,000 deposit in a bank account that pays an annual interest rate of r%, compounded monthly. Which of the following expressions shows how much additional money is generated at an interest rate of 5% than at an interest rate of 3%?

A. 1,000 (1 + (5 – 3) / 1,200) ^12

B. 1,000 (1 + (5 / 3) / 1,200) ^12

C. (1,000 (1 + 5 / 1,200) ^12) / (1,000 (1 + 3 / 1,200) ^12)

D. (1,000 (1 + 5 / 1,200) ^12) – (1,000 (1 + 3 / 1,200) ^12)

Mike has jelly beans worth $5 per pound that he wants to mix with 10 pounds of jelly beans worth $2 per pound to get a mixture that he can sell for $4.25 per pound. How many pounds of the expensive jelly beans should he use?

Answers

The pounds of expensive jelly beans that Mike should use, given the amount he wants to sell the mixture, is 30 pounds.

How to find the pounds of jelly beans ?

The total weight of the mixture is x + 10 pounds because Mike adding 10 pounds of the cheaper jelly beans while the cost of the expensive jelly beans would be:

= 5 x number of pounds

= 5x

The total cost of the cheaper jelly beans is :

= 10 pounds x 2

= $ 20

The total revenue from the mixture is therefore:

= 4.25x + 42.5

The total cost is :

= 5x + 20

Equating these would find the pounds of expensive jelly beans needed :

5x + 20 = 4.25x + 42.5

0.75x = 22.5

x = 30

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What is the opposite of 19(4/3) ?
A. 19(4/3)
B. -19(4/3)
C. 91(4/3)
D. -91(4/3)
E. 19(3/4)

Answers

The opposite of the number 19(4/3) is

B. -19(4/3)

What is additive inverse?

Additive inverse is the opposite of a number in terms of addition, this is the number that gives zero when added to the original number.

To get a result equal to 0, add the original number and the additive inverse or by simply changing the sign of the integer. On the basis of negation of the original number.

In the problem, the opposite of 19(4/3) is solved as follows

let x be the opposite

19(4/3) + x = 0

x = -19(4/3)

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Please help me!! I need help asap

Answers

Second and last boxes

Please helpppp!!!!!
Algebra 2

Answers

Answer:

1209067.550.625

Step-by-step explanation:

25% = 25/100 = 0.25

Then:

Bounce 1:

160 - (160*0.25) = 160 - 40 = 120

Bounce 2:

120 - (120*0.25) = 120 - 30 = 90

Bounce 3:

90 - (90*0.25) = 90 - 22.5 = 67.5

Bounce 4:

67.5 - (67.5*0.25) = 67.5 - 16.875 = 50.625

Part A: Given the function g(x) = |x − 5|, describe the graph of the function, including the vertex, domain, and range. (5 points)

Part B: If the parent function f(x) = |x| is transformed to h(x) = |x| + 3, what transformation occurs from f(x) to h(x)? How are the vertex and range of h(x) affected?

Answers

Part A: The vertex, domain, and range of the function are respectively; (5, 0), ( - ∞ , ∞ ),  [0, ∞ ]\

Part B: The function f(x) = |x| is vertically shifted by 3 units to get the function h(x) = |x| + 3. The y-coordinate of the vertex is shifted by 3 units.

How to find the domain and range of a function?

Part A: The given function is g(x) = | x - 5 |.

The x-coordinate of the vertex will be: x - 5 = 0

x = 5

Therefore, the y-coordinate of the vertex will be:

y = g(x) = |x - 5|

y = g(5) = |5 - 5|

y = 0

So, the absolute value vertex is (5, 0).

Now, all real numbers fall under the expression's domain, with the exception of cases where it is undefined. In this instance, the phrase is defined even if there is no real number. Thus;

Interval Notation: ( - ∞ , ∞ )

Set builder Notation: { x | x ∈ R }

The set of all legitimate y values is the range.

Interval Notation: [0, ∞ ]

Set builder Notation: { y | y ≥ 0}

Part B: h(x) = |x| + 3 is the transformed version of the parent function f(x) = |x|.

For the parent function f(x) = |x|, the vertex is ( 0, 0).

The range of an absolute function in the form c( | ax + b | ) + k is f(x) ≥ k.

Therefore, the range of the function f(x) = |x| is f(x) ≥ 0 and in interval notation is [ 0, ∞ ).

For the transformed function h(x) = |x| + 3.

The vertex of the function is ( 0, 3 ).

The range of function is h(x) ≥ 3 and in interval notation is [3, ∞ ).

Hence, the y coordinate of the vertex is transformed by 3.

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Suppose that you want to design a set of four congruent square pyramids whose combined volume is the same as the volume of a single rectangular pyramid. What values of l and h for the four square pyramids and what values of l, w, and h for the rectangular pyramid will produce identical volumes? There is more than one correct answer.

Answers

The values of l and h, along with w for the rectangular pyramid, that will produce identical volumes, are given by the following relation:

w = 4l.

(the value of the height is free).

How to calculate the volume of a pyramid?

The volume of a pyramid is calculated as the multiplication of the base area by the height, which is then divided by three.

Hence, the formula is given as follows:

V = Ab x h/3.

In which:

Ab is the base's area.h is the height.

The base areas are calculated as follows:

Square pyramid: Ab = l².Rectangular pyramid: Ab = lw.

Four congruent square pyramids whose combined volume is the same as the volume of a single rectangular pyramid, hence the relation is given as follows:

4l²h/3 = lwh/3.

w = 4l.

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What expression is equivalent to 3 squared 256x10y^7

Answers

The expression that is equivalent to 3 squared 256x10y^7 is  [tex]4x^3y^2\sqrt[3]{4xy}[/tex].

What is the expression?

Each term of the expression can be wriiten so as to find their prime factorization which can be done as

256 = 2^3.2^3.2^2

x^10 = x^3.x^3.x

y^7 = y^3.y^3.y

We can perform some simplification by bringing triples out  which will be outside the cube root : which are

2^3.2^3.x^3.x^3.y^3.y^3 = 2.2.3.3.y.y =[tex]4x^3y^2[/tex]

Then remaining terms will now be 2²(x)(y) will be in the cube root which = [tex]2^2xy[/tex]

Then we can write as [tex]4x^3y^2\sqrt[3]{4xy}[/tex]

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(Guys i need an expert verified)
Solve y3 = −216.

A: y = −72

B: y = ±72

C: y = −6

D: y = ±6

Answers

Answer: y = -6.

Step-by-step explanation: -6^3 is -216. Sorry if this isn't a clear explanation, but it seems like the correct choice.

Have a great day! :)

Ricardo wants to know when he got the best price for gas. He paid $43.08 for 12 gallons two weeks ago. Last week he paid $31.14 for 9 gallons, and this week he paid $52.70 for 15} gallons of gas.
In which week did Ricardo get the best price per gallon? Explain how you know.

Answers

The best price can be obtained by taking the ratio and it is given for the case of two weeks ago.

What is the ratio of two numbers?

The ratio of two numbers a and b can be written as a : b = a/b.

The ratio of two quantities is the unit rate of one quantity with respect to the other.

The price of gas per gallon for both the cases are calculated as below,

Two weeks ago it is given as,

Total price ÷ Number of gallons

⇒ 31.14 ÷ 9 = $3.46

And, for last week it is given as,

Total price ÷ Number of gallons

⇒ 52.70 ÷ 15 = 3.51

Thus, the price per gallon is cheaper two weeks ago.

Hence, the best price of gas is obtained for the case of two weeks ago.

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15. If the figures below are similar, give the scale
factor of Figure A to Figure B.



Answers

Answer:

The answer is 1.25.

Step-by-step explanation:

You can see what sides match up, and then you divide to find the scale factor.

17.5/14 = 1.25

20/16 = 1.25

find the volume of the solid whose base is bounded by the graphs of y= x+1 and y=(x2)+1, with the indicated cross sections taken perpendicular to the x-axis.
a) squares
b) rectangles of height 1

Answers

The volume of the solid is a) 1/30 and b) 1/6.

When the solid’s base is located in the xy plane and the cross-section is taken perpendicular to the x-axis with known cross sectional area given by A(x) for all the x in the interval [a,b], then the volume of the solid is given as the definite integral of these cross-sectional areas.

V = ∫_a^b▒A(x)dx

By graphing the given equations, we see that the area is bounded by the line y= x+1 and parabola y=x^2+1 on the interval on x-axis as [0,1].

a) The base of each square has length

f(x) – g(x) = (x + 1) – (x^2 + 1) = x – x^2

and the solid is square.

The area of cross section is

A(x) = (x – x^2)^2 = x^2 – 2x^3 + x^4

Hence, the volume is

∫_0^1▒A(x)dx

∫_0^1▒〖(x^2-2x^3+x^4)dx〗

[1/3 x^3-1/2 x^4+1/5 x^5]1¦0

[1/3 -1/2  +1/5]

1/30

b) The base of each rectangle has length

f(x) – g(x) = x – x^2

and the height of each rectangle is 1.

The area of cross section is

A(x) = (x – x^2)(1) = x - x^2

Hence, the volume is

∫_0^1▒A(x)dx

∫_0^1▒〖(〖x-x〗^2)dx〗

[1/2 x-1/3 x^3]1¦0

[1/2 -1/3]

1/6

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Solve 2/3x+2=4/3x-6 please help‼️

Answers

Answer:12

Step-by-step explanation:4/3x-2/3x=2/3x

6+2=8

2/3x=8

x=12

Answer:

X = 12

Step-by-step explanation:

2​x+2=34​x−6

Multiply both sides of the equation by LCM

(32​x+2)×3=(34​x−6)×3

CalculateMore Steps

 2x+6=(34​x−6)×3

CalculateMore Steps

 2x+6=4x−18

Move the variable to the left side

2x+6−4x=−18

Subtract the termsMore Steps 

−2x+6=−18

Move the constant to the right side

−2x=−18−6

Subtract the terms

−2x=−24

Multiply both sides

−2x(−21​)=−24×(−21​)

SimplifyMore Steps

 −2x(−21​)=12

Solution

x=12

please help me so love this problem?

Answers

Answer:

12.7  ==> distance of RS

24.2 ==> distance of RT

Step-by-step explanation:

Distance is always positive. So if you get a negative value, take the absolute value of the negative number:

For example, between point R and S:

-17.2 - (-4.5) =

-17.2 + 4.5 =  ==> subtracting a negative number is equivalent to adding a

                           positive number

-(17.2 - 4.5) = -12.7

-12.7 ==> |-12.7| = 12.7  ==> distance of RS

For RT:

-17.2 - 7 =

-(17.2 + 7) = -24.2

-24.2 ==> |-24.2| = 24.2 ==> distance of RT

Given the figure below, find the values of x and z .

Answers

Answer:

x = 19

z = 19

Step-by-step explanation:

8x - 88 + 5x + 21 = 180

13x - 67 = 180

13x = 247

x = 19

z = 19

A bait and tackle shop has fishing lures in the following weights. Write the weights of the lures in order from least to greatest. 5 BOZ 몸으 1 2-07 3 g-oz

Answers

Based on the information, it can be inferred that the order from lightest to heaviest lure would be: 0.25 (c), 0.372 (d), 0.5625 (b), and 0.625 (a).

How to calculate the weights of the lures?

To calculate the weights of the lures we must take into account that they are fractional, that is to say that to find an exact number of the weight of each one of the lures we can carry out the division of the fractional to have a decimal number that allows us to organize more easily the pesos.

According to the above information, the weights would be the following:

a. 5/8 = 0.625

b. 9/16 = 0.5625

c. 1/4 = 0.25

d, 3/8 = 0.372

Then, the weights organized from smallest to largest would look like this: 0.25 (c), 0.372 (d), 0.5625 (b), and 0.625 (a).

Note: This question is incomplete because there is some information missing. Here is the complete information:

Options:

a. 5/8OZ

b. 9/16 OZ

c. 1/4OZ

d. 3/8OZ

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2 objects without replacement from 3 objects pencil, eraser, and desk how many ways can this be done taken and not taken into consideration

Answers

The total number of ways in which the selection can be done are 3.

What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is to take out 2 objects without replacement from 3 objects, pencil, eraser, and desk.

Combination is an arrangement of objects where the order in which the objects are selected does not matter.Mathematically :  [tex]$_n C_r=\frac{n !}{r ! (n-r) !}[/tex]

The total number of ways in which the selection can be done is -

C(3, 2) = (3!)/(2!)(1!) = 3

C(3, 2) = 3

Therefore, the total number of ways in which the selection can be done are 3.

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Arnold is studying the prevalence of three health risk factors, denoted by A, B, and C, within a population of men. For each of the three factors, the probability that a randomly selected man in the population has only this risk factor (and none of the others) is 0.1. For any two of the three factors, the probability that a randomly selected man has exactly these two risk factors (but not the third) is 0.14. The probability that a randomly selected man has all three risk factors, given that he has A and B is 1/3. The probability that a man has none of the three risk factors given that he does not have risk factor A is p/q, where p and q are relatively prime positive integers. Find p+q.

Answers

The value of p + q is 17.

The probability that one of the three risk factors will be present in exactly the right amount for a randomly chosen individual can be calculated using the inclusion-exclusion principle. The probabilities that a man has risk factors A (but not B or C), B (but not A or C), and C (but not A or B) are, accordingly, denoted by the letters P(A), P(B), and P(C). Next, we have:

P(A or B or C) = P(A) + P(B) + P(C) - P(A and B) - P(A and C) - P(B and C) + P(A and B and C)

P(A) = P(B) = P(C) = 0.1 and P(A and B) = P(A and C) = P(B and C) = 0.14 are both supplied to us.

 Additionally, it is stated that if a guy possesses both A and B, there is a 1/3 chance that he possesses all three risk factors. Using this knowledge, we can calculate P. (A and B and C).

P(A, B, and C) = P(A, B | C) * P(C) = (1/3) * 0.1 = 1/30 is what we got.

These values are then reinserted into the equation above to produce the following result: P(A or B or C) = 0.1 + 0.1 + 0.1 - 0.14 - 0.14 - 0.14 + 1/30 = 0.44/30 = 11/75

None of the three risk factors are present in a guy in a likelihood of 1 - P(A or B or C) = 1 - 11/75 = 64/75. As a result of the reduction of the proportion 64/75 to 8/9, p = 8 and q = 9, and p + q = 8 + 9 = 17.

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24.
Events A and B
Events B and C
Events C and D
Events A and C
Events A and D

Answers

The pairs of events that are disjoint and cannot occur at the same time are; Option D: Events A and C

How to interpret disjoint events?

In mathematical set problems, we usually say that two sets are said to be disjointed sets if they have no elements in common.

Since the spinner has 10 sections numbered 1 to 10, then the sample space is;

S = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }

We are told that Event A is the event of the Spin of an odd number. Thus;

Event A = { 1, 3, 5, 7, 9 }

Event B: Spin a number greater than 1 Thus;

Event B = { 2, 3, 4, 5, 6, 7, 8, 9, 10}

Event C: Spin a 2. Thus;

Event C = { 2 }

Event D: Spin a multiple of 2. Thus;

Event D = { 2, 4, 6, 8, 10}

Therefore;

A ∩ B = { 3, 5, 7, 9}

B ∩ C = {2}

C ∩ D = { 2 }

A ∩ C = { }

Thus, A ∩ C does not contains any element. So A and C is a disjoint event.

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ASAP 20 points

For any real number c, \sqrt{c^2}
c
2


= .

A.
1

B.
|c|∣c∣

C.
c2

D.
c

Answers

For any real number c, it is calculated that √(c²) is; Option D: c

How to find the real numbers?

The set of real numbers is defined as the union of the set of Irrational numbers and the set of rational numbers.

Now, we are given the equation as;

√(c²)

Now, from definition of real numbers, it means that they are not imaginary and as such any value of c remains the same. Thus, we have;

√(c²) = c

Now, because c is not classified as an absolute value, and even if since it is square, will be surely positive and as such the final answer for every real number c in the square root will be c.

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4 + 2(5 + (-3)
Circle the terms and calculate the value of this expression

Answers

The terms of the expression are 4, 2(5) and -3 and the value of the expression is 11

How to determine the terms of this expression

From the question, we have the following parameters that can be used in our computation:

4 + 2(5 + (-3)

Rewrite properly

So, we have

4 + 2(5) + (-3)

For an expression ax + by

The terms are ax and by

This means that the terms of 4 + 2(5) + (-3) are 4, 2(5) and -3

How to calculate the value of this expression

Here, we have

4 + 2(5) + (-3)

Remove the brackets

4 + 2(5) + (-3) = 4 + 10 - 3

Evaluate the like terms

4 + 2(5) + (-3) = 11

Hence, the value is 11

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A high school has a population of 2,035 students and is increasing by 3% each year.
a) Write an exponential function to model the student population in terms of the number of years from now.
b) predict the number of students that will be in school after five years.

Answers

Answer:

a) y = 2,035(1.03)^t

b) 2,359

Step-by-step explanation:

a)

Exponential growth:

y = a(1 + r)^t

where

y = future vale

a = initial value

r = periodic rate of growth

t = number of periods

y = 2,035(1 + 0.03)^t

y = 2,035(1.03)^t

b)

Here we have a = 2,035; r = 3% = 0.03; t = 5

y = 2,035(1 + 0.03)^5

y = 2,359

2,359

The
graph of a quadratic function with vertex (0, 3) is shown in the figure below.
Find the domain and the range.
Write the domain and range using interval notation.

Answers

The domain of the quadratic function is (-∞,∞). The range of the quadratic function is (-∞,3].

What is interval notation?

Interval Notation is a method of representing a subset of real numbers by the numbers that connect them.

The vertex of the quadratic function is (0,3).

The function extended downward direction in a vertical. The function extended on both sides of the x-axis horizontally.

The x-coordinate of the points on the quadratic function is the domain.

The y-coordinate of the points on the quadratic function is the range.

The x-coordinate of the points on the quadratic function is from -∞ to ∞.

The y-coordinate of the points on the quadratic function is from -∞ to 3.

The domain of the function is (-∞,∞).

The range of the function is  (-∞,3].

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