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Answer:The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°

Explanation:

Answer:

A) 7kg

B) 0.044

Explanation:

a) Accordimg to Newton's second law

\sum F = ma

Fm - Ff = ma

Fm is moving force =15-5 = 10N

Ff is fictional force = 3N

m is the mass = ?

a Is the acceleration = 1m/s²

Substitute

10-3 = 1m

7 = m

Hence the mass of the body is 7kg

b) coefficient of friction is expressed as;

n = Ff/R

R is the reaction = mg

n =Ff/mg

Substitute

n = 3/7(9.8)

n = 3/68.6

n = 0.044

Hence the coefficient of friction is 0.044

Answer:    

Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.

Hope that helps!

Answer:

A. The core makes up the majority of Earth's volume.

Explanation:

Although the core and mantle are about equal in thickness, the core actually forms only 15% of earth's volume whereas the mantle takes up 84%

Answer:

Canva. Although Canva's free storyboard app for iOS and Android is targeted more at video production, it still provides animators and UX designers everything they need.

Explanation:

Answer:

what is 30 + 40 add

Answer:

A). 2.3 s

Explanation:

Given that,

Length of the string = 130cm or 1.3 m

g near Earth's surface = 9.8 [tex]ms^{-2}[/tex]

To determine the period of a pendulum near Earth’s surface;

T = 2 π [tex]\sqrt{\frac{L}{g} }[/tex]

T = 2π[tex]\sqrt{\frac{1.3}{9.8} }[/tex]

T = 2.3 sec

Therefore, the period of the pendulum near the earth's surface is 2.3 sec.

Answer:A road sign gives drivers informaton about traffic on busy highways. One sign shows 15 miles in 20 minutes. What is this speed in miles per hour?

Explanation:

Answer:

Muscular energy

Explanation:

Hope it helps!!!!

Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields. They are also perpendicular to the direction of the EM

Explanation:

Answer:

0.3 seconds

Explanation:

When we walk, our legs alternatively swing forward about the hip joint as a pivot. In this motion the leg is acting approximately as a physical pendulum. Treating the leg as a thin uniform rod of length 0.80 m,

To find the time it takes for the leg to swing forward, where g = 9.8 m/s^2

Let's use the simple pendulum formula which says that:

T = 2π( sqrt ( L/g))

T = 2π[sqrt (0.8/9.8)]

T = 2π × 0.082

T = 0.5129

For the leg to swing forward only, the number of complete oscillations will be half.

Period T = time t ÷ number of complete oscillations. That is,

T = t ÷ 1/2

0.5129 = t ÷ 1/2

t = 0.5129 × 1/2

Time t = 0.256 seconds.

Therefore, the time it takes for the leg to swing forward is 0.3 seconds approximately

Answer:

-929.5Joules

Explanation:

To get the work done by sam, we will calculate the kinetic energy of sam expressed as;

KE = 1/2mv²

m is the mass = 1100kg

v is the velocity = 1.3m/s

KE = 1/2(1100)(1.3)²

KE = 550(1.69)

KE = 929.5Joules

Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules

Answer:

500Hertz

Explanation:

Given the fundamental frequency of the string given as  1.25x10²Hz

Harmonics are integral multiples of the fundamental frequency.

In strings, the third harmonic F3 is expressed in terms of the fundamental frequency expressed as;

F3 = 4F0

F0 is the fundamental frequency;

Given

F0 = 1.25x10²Hz

F3 = 4(1.25x10²)

F3 = 4(125)

F3 = 500Hz

Hence the  frequency of the third harmonic is 500Hertz

Complete question is;

You are looking at a module specification

sheet that has the table of information

below. What is the maximum power of this

module in Watts to the nearest whole Watt?

Value

Polycrystalline si

Characteristic

Cell Type

Cell

Configuration

Voc

160 in series

137.2 V

V_imp: 29.3 V

Ilsc: 8.60 A

I_Imp: 8.02 A

Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"

Weight: 10 kg / 22 lbs​

Answer:

P ≈ 235 Watts

Explanation:

Formula for power is;

P = IV

Now, for maximum power, we will make use of I_imp and V_imp given

Thus, P = I_imp × V_imp

We are given;

V_imp: 29.3 V

I_Imp: 8.02 A

Thus: P = 8.02 × 29.3 = 234.986 Watts

We are to approximate to the nearest whole watt.

Thus: P ≈ 235 Watts

Answer:

Explanation:

The solution of the question has been put in attachment.

Answer:

B.

Explanation:

Answer:

a) 7.2*10^55

b) 1.2*10^29 kg

c) 3.2*10^11 m/s

Explanation:

Given a diameter of 10 km, that's a radius of 5 km.

We first attempt to find its mass number

A = (r/1.2*10^-15)³

A = (5/1.5*10^-15)³

A = 7.2*10^55

This gotten mass number is then multiplied by the mass of each neutron in the star. With each neutron being, 1.7*10^-27

M = 7.5*10^55 * 1.7*10^-27

M = 1.2*10^29 kg

And finally, using the formula

g = GM/r², we can find its acceleration due to gravity.

g = (6.67*10^-11 * 1.2*10^29) / 5000²

g = 8*10^18 / 2.5*10^7

g = 3.2*10^11 m/s

A blue "H" means a center of high pressure (usually calm, sunny weather). A red "L" means low pressure (which can mean storminess). Most fronts extend from low-pressure centers.

The weather symbol blue 'H' represents high pressure while red 'L' represents Low pressure.

Weather symbols can be described as symbols with which meteorologists indicate various atmospheric and natural conditions on special weather maps such as temperature, pressure, precipitation, wind, or the percentage of cloud coverage in the sky. These maps can be used to be paper maps or digital.

Warm fronts can be described as indicated by curved red lines with red semicircles. Cold fronts can be curved blue lines with blue triangles. Stationary fronts exhibit alternating red curves with semicircles and blue curves with triangles. There are 99 present weather symbols used in meteorology.

The eight elements observed by meteorologists for creating weather forecasts are air temperature, humidity, wind speed, wind direction, visibility, clouds, precipitation, and atmospheric pressure.

On weather maps, readings are represented as a red “L” for low pressure or a blue “H” for high pressure.

Learn more about  weather map symbols, here:

https://brainly.com/question/29362930

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Answer:

[tex]V_1= 3.4*10^7m/s[/tex]

Explanation:

From the question we are told that

Nucleus diameter [tex]d=5.50-fm[/tex]

a 12C nucleus

Required kinetic energy [tex]K=2.30 MeV[/tex]

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            [tex]K_2 +U_2=K_1+U_1[/tex]

where

[tex]K_1[/tex] =initial kinetic energy

[tex]K_2[/tex] =final kinetic energy

[tex]U_1[/tex] =initial electric potential

[tex]U_2[/tex] =final electric potential

mathematically

   [tex]U_2 = \frac{Kq_pq_c}{r_2}[/tex]

where

[tex]r_f[/tex]=distance b/w charges

[tex]q_c[/tex]=nucleus charge [tex]=6(1.6*10^-^1^9C)[/tex]

[tex]K[/tex]=constant

[tex]q_p[/tex]=proton charge

Generally kinetic energy is know as

         [tex]K=\frac{1}{2} mv^2[/tex]

Therefore

         [tex]U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2} mv_1^2 +U_1[/tex]

Generally equation for radius is [tex]d/2[/tex]

Mathematically solving for radius of nucleus

         [tex]R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})[/tex]

         [tex]R=2.75*10^-^1^5m[/tex]

Generally we can easily solving mathematically substitute into v_1

   [tex]q_p[/tex][tex]=6(1.6*10^-^1^9C)[/tex]

   [tex]K_1=9.0*10^9 N-m^2/C^2[/tex]

   [tex]U_1= 0[/tex]

   [tex]R=2.75*10^-^1^5m[/tex]

   [tex]K=2.30 MeV[/tex]

   [tex]m= 1.67*10^-^2^7kg[/tex]

   [tex]V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }[/tex]

    [tex]V_1= 3.4*10^7m/s[/tex]

Therefore the proton must be fired out with a speed of [tex]V_1= 3.4*10^7m/s[/tex]

Answer:

B. Q/2

Explanation:

Given;

charge of the two particles, = -Q

distance between the two charges, r = L

the net force experienced by each charge = F

Apply coulomb's force between two charged particles;

[tex]F = \frac{KQ^2}{r^2} = \frac{kQ^2}{L^2}[/tex]

when

+q is introduced midway between the charges, the net force is reduced by 2

[tex]\frac{F}{2} = \frac{kQq}{L^2} \\\\ \frac{1}{2}(\frac{kQ^2}{L^2} ) = \frac{kQq}{L^2}\\\\\frac{kQ^2}{2L^2} =\frac{kQq}{L^2} \\\\\frac{Q}{2} = q[/tex]

Thus, The value of q is Q/2

The value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.

Given here,  

-Q = charge of the two particles  

r = distance between the two charges = L  

F = net force on each charge  

From coulomb's force between two charged particles;

[tex]\bold{F = \dfrac {KQ^2}{r^2} =\dfrac {kQ^2}{L^2} }[/tex]

If +q is bring at mid point between the charges, the net force is reduced by 2

Thus, q = Q/2

Therefore,   the value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.

Answer:

Explanation:t

The Inertial is the resistance of a body at rest to be in motion

Given the following  item

1. 4kg shot put ball  

2. 2,000 kg boulder

The body of greater mass has greater inertia, hence would be harder to accelerate.

An object with a small inertial mass will accelerate more than an object with a large inertial mass when acted upon by the same force.

Of the 2 items in the list, the 2,000 kg boulder has the largest mass, hence it also has the greater inertial  and more difficult to accelerate.

Answer:

Planets that are close to the sun have shorter years, and planets that are farther have longer years, because of how fast/slow it orbits the sun.

Explanation:

Answer:

[tex]0.542*10^{23}\ Aluminum\ Atoms[/tex]

Explanation:

[tex]We\ are\ given:\\Density\ of\ aluminum=2.7\ g/cm^3\\Volume\ of\ aluminum-cube=0.9\ cm^3\\Hence,\\As\ we\ know\ that,\\Density=\frac{Mass}{Volume}\\Mass=Density*Volume\\Hence,\ here,\\Mass\ of\ the\ solid\ iron\ cube=2.7*0.9=2.43\ g\\Now,\\We\ also\ know\ that,\\Gram\ Atomic\ mass\ of\ Aluminum = 26.98 \approx 27\ g\\Hence,\\No.\ of\ particles=\frac{Mass}{GAM}*Avagadro's Constant\\Hence,\ here\\No.\ of\ Aluminum\ atoms=\frac{2.43}{27}*6.022*10^{23} \approx 0.542*10^{23}\ Aluminum\ Atoms[/tex]

Answer:

83.168 Nm

Explanation:

I=mass of bat* ( length )^2 /3

Moment of inertia from one end = 2.2 * (0.96)^2 / 3.

Ang. acc. = 2.2×2 pi / 0.2 = 22pi

Torque =  2.3 * (0.96)^2 / 3 * 22 pi = 83.168 Nm SI units

Answer: Ain't its because how light the feather is ? It's not as heavy.

Explanation: With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down. ... Usually, resistance is not very high at low speed or for small or sharp objects (Google Source if needed to prove yours answer)

Answer:

The correct option is C: 0.31 s.

Explanation:

When the mass is then suddenly released we have:

[tex] F = k\Delta y [/tex]

Where:

F is the force

k: is the spring constant

Δy: is the spring displacement

Since the tension in the spring is zero, the force is the weight:

[tex] F = mg [/tex]

Where:

m is the mass of the object

g is the gravity

[tex] mg = k\Delta y [/tex]    (1)

The oscillation period of the spring is given by:

[tex] T = 2\pi \sqrt{\frac{m}{k}} [/tex]    (2)

By solving equation (1) for "k" and entering into equation (2) we have:

[tex] T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}} [/tex]

[tex]T = 2\pi \sqrt{\frac{\Delta y}{g}}[/tex]

Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:

[tex] T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s [/tex]                   

Hence, the oscillation period is 0.31 s.

The correct option is C: 0.31s.

I hope it helps you!                                                                                                      

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 9 × 11

We have the final answer as

Hope this helps you

Complete Question

What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaries are to be installed?The  lamps to be installed are rated 75 watts at 277 volts. This is NOT a continuous load so each circuit can carry 20 amps maximum

Answer:

The number is  [tex]k = 11[/tex]

Explanation:

From the question we are told that

     The current is  [tex]I = 20 \ A[/tex]

     The voltage is  [tex]V = 277 \ volt[/tex]

     The power rating of each bulb is  [tex]P = 75 \ W[/tex]

      The total number of  incandescent luminaries is [tex]n = 810[/tex]

Generally the amount of current each lamp takes is mathematically represented as

       [tex]I_e = \frac{P}{ V}[/tex]

=>    [tex]I_e = \frac{75}{ 277}[/tex]

=>    [tex]I_e = 0.270 \ A[/tex]

Generally the number of bulb fitting(i.e bulbs )  a  20 A current can supply (i.e the bulbs the branch ) to is

                    [tex]N = \frac{I}{I_e}[/tex]

=>                 [tex]N = \frac{20 }{ 0.270 }[/tex]

=>                 [tex]N = 73.86[/tex]

Generally the number of 20-amp 277-volt branch circuits required is mathematically represented as

          [tex]k = \frac{n}{N}[/tex]

=>       [tex]k = \frac{810}{73.86}[/tex]

=>       [tex]k = 11[/tex]