Answers
Given the following equation:
[tex]\frac{x}{x-4}-\frac{4}{x}=\frac{3}{x-4}[/tex]First, we will identify the zeros of the denominator
So, the zeros are: x = {0,4}
Second, multiply the equation by x(x-4) to eliminate the denominators
[tex]x(x-4)*(\frac{x}{x-4}-\frac{4}{x})=x(x-4)*\frac{3}{x-4}[/tex]Simplify the equation:
[tex]x^2-4(x-4)=3x[/tex]Expand the equation and combine the like terms:
[tex]\begin{gathered} x^2-4x+16=3x \\ x^2-7x+16=0 \end{gathered}[/tex]The last quadratic equation will be solved using the quadratic rule:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Substitute a = 1, b = -7, c = 16
[tex]\begin{gathered} x=\frac{7\pm\sqrt{(-7)^2-4(1)(16)}}{2(1)} \\ \\ x=\frac{7\pm\sqrt{-15}}{2}=\frac{7\pm i\sqrt{15}}{2} \\ \\ x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace \end{gathered}[/tex]So, the answer will be:
[tex]x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace[/tex]Related Questions
Consider the two polynomials p(x), q(x) in Z[x] by p(x) = 1+2x+3x2, q(x) = 4+5x+7x3. Then p(x) + q(x) is
Answers
The solution for polynomials p(x) + q(x) is 7x³ + 3x² + 7x + 5
Given,
The polynomials
p(x) = 1 + 2x + 3x²
q(x) = 4 + 5x + 7x³
We have to find the solution for p(x) + q(x)
Then,
p(x) + q(x) = (1 + 2x + 3x²) + ( 4 + 5x + 7x³)
p(x) + q(x) = 7x³ + 3x² + 2x + 5x + 1 + 5
p(x) + q(x) = 7x³ + 3x² + 7x + 5
That is,
The solution for polynomials p(x) + q(x) is 7x³ + 3x² + 7x + 5
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I wills send you a picture
Answers
Draw the tank
we can use the formula of the volume of a cylinder
[tex]V=\pi\times r^2\times h[/tex]we can repalce the value of the volume (320pi) and the height
[tex]\begin{gathered} 320\pi=\pi\times r^2\times20 \\ 320\pi=20r^2\pi \end{gathered}[/tex]now solve for r^2 dividing 20pi on both sides
[tex]\begin{gathered} \frac{320\pi}{20\pi}=r^2 \\ \\ r^2=16 \\ \end{gathered}[/tex]and solve for r using roots
[tex]\begin{gathered} r=\sqrt[]{16} \\ \\ r=4 \end{gathered}[/tex]the value of the radious is 4ft and the diameter double, then
[tex]\begin{gathered} d=2\times4 \\ d=8 \end{gathered}[/tex]diameter of the cylinder is 8 ft then rigth option is C
You start driving north for 5 miles, turn right, and drive east for another 12 miles. At the end of driving, what is your straight line dissonance from you r starting point?
Answers
You start driving north for 5 miles, turn right, and drive east for another 12 miles
The angle between north and east = 90
So, x is the hypotenuse of the triangle
[tex]x=\sqrt[]{5^2+12^2}=\sqrt[]{25+144}=\sqrt[]{169}=13[/tex]so, the length = 13 miles
Hey I need help with my homework help me find the points on the graph too please Thankyouu
Answers
Given the function:
g(x) = 3^x + 1
we are asked to plot the graph of the function.
Using the table:
x y
-2 10/9
-1 4/3
0 2
1 4
2 10
The graph:
The expomential functions have a horizontal asymptote.
The equation of the horizontal asymptote is y = 1
Horizontal Asymptote: y = 1
To find the domain is finding where the question is defined.
The range is the set of values that correspond with the domain.
Domain: (-infinity, infinity), {x|x E R}
Range: (1, infinity0, {y|y > 1}.
Kepler's third law of planetary motion states that the square of the time required for a planet to make one revolution about the sun varies directly as the cube of the average distance of the planet from the sun. If you assume that Jupiter is 5.2 times as far from the sun as is the earth, find the approximate revolution time for Jupiter in years.
Show work pls ;-;
Answers
By applying Kepler's third law of planetary motion, the approximate revolution time for Jupiter is equal to 12 years.
What is Kepler's third law?Mathematically, Kepler's third law of planetary motion is given by this mathematical expression:
T² = a³
Where:
T represents the orbital period.a represents the semi-major axis.Note: Earth has 1 astronomical unit (AU) in 1 year of time.
For this direct variation, the value of the constant of proportionality (k) is given by:
T² = ka³
k = T²/a³
k = 1²/1³
k = 1.
When the semi-major axis or the distance of Jupiter from Sun is 5.2, we have;
T² = ka³
T² = 1 × 5.2³
T² = 140.608
T = √140.608
T = 11.858 ≈ 12 years.
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A ball is thrown from an initial height of 6 feet with an initial upward velocity of 21 ft/s. The ball's heighth (in feet) after t seconds is given by the following,6+21 167Find all values of t for which the ball's height is 12 feet.Round your answer(s) to the hearest hundredth(If there is more than one answer, use the "or" button.)
Answers
The given expression in the question is
[tex]h=6+21t-16t^2[/tex]with the value of h given as
[tex]h=12ft[/tex]By equating both equations, we will have
[tex]\begin{gathered} 12=6+21t-16t^2 \\ 12-6-21t+16t^2=0 \\ 6-21t+16t^2=0 \\ 16t^2-21t+6=0 \end{gathered}[/tex]To find the value of t we will use the quadratic formula of
[tex]ax^2+bx+c=0[/tex]which is
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where} \\ a=16 \\ b=-21 \\ c=6 \end{gathered}[/tex]By substitution, we will have
[tex]\begin{gathered} t=\frac{-(-21)\pm\sqrt[]{(-21)^2-4\times16\times6}}{2\times16} \\ t=\frac{21\pm\sqrt[]{441-384}}{32} \\ t=\frac{21\pm\sqrt[]{57}}{32} \\ t=\frac{21\pm7.5498}{32} \\ t=\frac{21+7.5498}{32}\text{ or t=}\frac{21-7.5498}{32} \\ t=\frac{28.5498}{32\text{ }}\text{ or }t=\frac{13.4502}{32\text{ }} \\ t=0.89\text{ or t=0.42} \end{gathered}[/tex]Alternatively, Solving the equation graphically we will have
Therefore,
The values of t( to the nearest hundredth) t= 0.89sec or 0.42sec
4) Using the number line to help you, decide which fraction is larger or if they are equal: one/twos or three/fifths. Label each fraction on the number line.
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Explanation:
The number line is between 0 to 1. There are 10 smaller lines in between
Each of the small lines represent 1/10 or 0.1
one/twos is the same as 1/2 = 0.5
three/fifths is the same as 3/5 = 0.6
From the above, 0.6 is greater than 0.5
Showing both numbers on the number line:
Hi there, I need help with this question. Thank you in advance!
Answers
For the data given, we have 24 entries in all.
They are :
75, 36, 80, 49, 24, 61, 34, 39, 30, 76, 44, 44, 40, 35, 21, 89, 34, 70, 79, 65, 66, 53, 99, 11
(1) Minimum refers to the lowest data in the table. we can see out of all the data in the table, the lowest is 11. Therefore,
Min = 11
(2) Maximum refers to the highest data in the table.
The highest is 99.
Therefore,
Max = 99
(3) Range is defined as highest data minus lowest data
Range = 99 - 11
Range = 88
(4) Mean:
[tex]\begin{gathered} \text{ Mean =}\frac{\text{ sum of the data}}{total\text{ count}} \\ \operatorname{mean}\text{ = }\frac{75+36+80+49+24+61+34+39+30+76+44+44+40+35+21+89+34+70+79+65+66+53+99+11}{24} \\ \\ \text{Mean = }\frac{1254}{24} \\ =52.25 \end{gathered}[/tex]Therefore,
Mean = 52.25
(5) Standard deviation:
The steps to calculate the standard deviation in shown in the picture below.
The standard deviation = 22.8386..
To 2 decimal places, we have 22.84
Therefore,
Standard deviation = 22.84
Today's previewYou can solve this by rearranging to create asituation to use the method from the previouslesson, or you can solve this by thinking a littledifferently about how the variables below mightalso be described.... so solve it.y = 2x + 4x + y = 7
Answers
What are the domain and range of y = cot x? Select onechoice for domain and one for range.
Answers
ANSWER:
A. Domain: x ≠ n
D. Range: All real numbers
STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]y=\cot\left(x\right)[/tex]The domain of a function is the interval of input values, that is, the interval of x while the range is the interval of output values, that is, the interval of y.
In the cotangent function, x cannot take the value of radians (nor its multiples), since it is not defined, while the range is continuous on all real numbers.
That means the correct options are:
A. Domain: x ≠ n
D. Range: All real numbers
Choose SSS, SAS, or neither to comparethese two triangles.A) SSSB) SASC) neither
Answers
Answer:
C. Neither
Explanation:
The SSS Congruence Rule states that if the three sides of a triangle are equal to the three sides of another triangle, then the two triangles are congruent.
The SAS Congruence Rule states that if the two sides and the included angle of one triangle are equal to the two sides and the included angle of another triangle, then the two triangles are congruent.
Notice that in the given triangles, there are two congruent sides and a non-included angle, since this does not satisfy any of the rules stated above, SSS Congruence rule or SAS Congruence rule, we'll choose "neither" as the correct answer.
Nov 28,Quadrilateral ABCD is dilated by a scale factor of to form quadrilateral A'B'C'D'.What is the measure of side DA?Dal1515301B2162А
Answers
The quadrilateral ABCD was dilated by a scale factor of 3/4 to form the quadrilateral A'B'C'D'
This means that each side of the quadrilateral was multiplied by 3/4 to make the dilation.
You know that the scale factor is 3/4 and the length of D'A' is equal to 30 units, then:
[tex]\begin{gathered} D^{\prime}A^{\prime}=\frac{3}{4}DA \\ 30=\frac{3}{4}DA \end{gathered}[/tex]Multiply both sides by the reciprocal of 3/4
[tex]\begin{gathered} 30\cdot\frac{4}{3}=(\frac{4}{3}\cdot\frac{3}{4})DA \\ 40=DA \end{gathered}[/tex]The length of side DA is 40 units.
find the first term when the 31st 32nd and 33rd are 1.40, 1.55, and 1.70
Answers
jadeymae06, this is the solution:
This is an arithmetic sequence, where d (common difference) = 0.15
(1.70 - 1.55) or (1.55 - 1.40)
•
,• a + 30d = 1.40
,• a + 30(0.15) = 1.4
,• a + 4.5 = 1.4
,• a = 1.4 - 4.5
,• a = -3.1
Jade, the first term is -3.1
11. Jarrod's favorite movie is now on video at 15% off the originalprice. If he pays $17, what was the original price?
Answers
original price = x
discount = 15%
price after discount = $17
Write an equation:
x (1-15/100) = 17
x (1-0.15 ) = 17
0.85x = 17
Solve for x:
x = 17/0.85
x = $20
Greg is ordering tile for a floor he is installing. The owner picks out tile that is 16in by 16in including the grout . The floor is 350 sq ft . (part 1) How many tile must Greg order for the floor ( assume no waste)(part 2) Each tile cost $ 1.75 plus 8% sales tax . How will the tile cost ?
Answers
ANSWER
(part 1) 196 tiles
(part 2) $ 1.89
EXPLANATION
(part 1)
First we have to find the area of each tile, that is the product of the dimensions because it is a rectangle,
[tex]A_{\text{tile}}=16in\cdot16in=256in^2[/tex]To compare it to the floor's area, we have to transform it into square feet. Knowing that 1 ft² = 144 in²,
[tex]256in^2\cdot\frac{1ft^2}{144in^2}=\frac{16}{9}ft^2[/tex]This is a partial result, so it is best if we leave it as a fraction so we don't miss any decimals.
Now, the area of the floor is 350 ft². To find how many tiles Greg has to order, we have to divide the area of the floor by the area of each tile,
[tex]\#tiles=\frac{A_{\text{floor}}}{A_{\text{tile}}}=\frac{350ft^2}{\frac{16}{9}ft^2}=196.875[/tex]But the number of tiles has to be an integer. If Greg buys 197 tiles they will have to cut some (waste). If he buys 196 there will be some of the floor not covered. However we were asked to assume no waste, so Greg will have to order 196 tiles.
(part 2)
To answer this question we have to add 8% to the cost of the tile. The 8% of 1.75 is,
[tex]1.75\cdot\frac{8}{100}=0.14[/tex]So the cost of each tile is,
[tex]1.75+0.14=1.89[/tex]are f(x) and g(x) inverse functions across the domain (5, + infinity)
Answers
Given:
[tex]\begin{gathered} F(x)=\sqrt{x-5}+4 \\ G(x)=(x-4)^2+5 \end{gathered}[/tex]Required:
Find F(x) and G(x) are inverse functions or not.
Explanation:
Given that
[tex]\begin{gathered} F(x)=\sqrt{x-5}+4 \\ G(x)=(x-4)^{2}+5 \end{gathered}[/tex]Let
[tex]F(x)=y[/tex][tex]\begin{gathered} y=\sqrt{x-5}+4 \\ y-4=\sqrt{x-5} \end{gathered}[/tex]Take the square on both sides.
[tex](y-4)^2=x-5[/tex]Interchange x and y as:
[tex]\begin{gathered} (x-4)^2=y-5 \\ y=(x-4)^2+5 \end{gathered}[/tex]Substitute y = G(x)
[tex]G(x)=(x-4)^2+5[/tex]This is the G(x) function.
So F(x) and G(x) are inverse functions.
[tex]\begin{gathered} G(x)-5=(x-4)^2 \\ \sqrt{G(x)-5}=x-4 \\ x=\sqrt{G(x)-5}+4 \end{gathered}[/tex]Final Answer:
Option A is the correct answer.
The graphs of the functions g and h are shown below. For each graph, find the absolute maximum and absolute minimum. If no such value exists, click on "None".
Assume that the dashed line shown is a vertical asymptote that the graph does not cross.
Answers
For the graph g, the absolute maximum is 2 and the absolute minimum is -4.
Similarly, for graph h, the absolute maximum is 3 and the absolute minimum is -5.
Absolute Maximum of a Graph:
The absolute maximum of a graph is the point on the graph with the highest y-value. There can only be one absolute maximum of a graph.
Absolute Minimum of a Graph:
The absolute minimum of a graph is the point on the graph with the lowest y-value. There can only be one absolute minimum of a graph.
Given,
Here we have the two graph called g and h.
Now, we need to find the absolute maximum and minimum from it.
AS per the given definition, we know that,
For graph g,
The absolute maximum is 2 and the absolute minimum is -4.
Similarly, for graph h, the absolute maximum is 3 and the absolute minimum is -5.
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PLEASE ITS URGENT I NEED HELP!!! I BEG YOU GUYS PLEEAASEEE THANKS..
Answers
Explanation
remember some properties of the exponents
[tex]\begin{gathered} a^m\cdot a^n=a^{m+n} \\ (a^m)^n=a^{m\cdot n} \\ a^{-m}=\frac{1}{a^m} \end{gathered}[/tex]then, to solve this solve each option and compare
Step 1
[tex]6^{-5}\cdot6^2[/tex]solve
[tex]\begin{gathered} 6^{-5}\cdot6^2=6^{-5+2}=6^{-3} \\ \end{gathered}[/tex]so, this is not an answer
Step 2
[tex](\frac{1}{6^2})^5[/tex]solve
[tex]\begin{gathered} (\frac{1}{6^2})^5=(6^{-2})^5=6^{(-2\cdot5)}=6^{-10} \\ \end{gathered}[/tex]so, this is an answer
Step 3
[tex]\begin{gathered} (6^{-5})^2 \\ \text{solve} \\ (6^{-5})^2=6^{-5\cdot2}=6^{-10} \end{gathered}[/tex]so, this is an answer
Step 4
[tex]\begin{gathered} \frac{6^{-3}}{6^7} \\ \text{solve} \\ \frac{6^{-3}}{6^7}=\frac{1}{6^3\cdot6^7}=\frac{1}{6^{3+7}}=\frac{1}{6^{10}}=6^{-10} \end{gathered}[/tex]so, this is an answer
Step 5
[tex]\begin{gathered} \frac{6^5\cdot6^{-3}}{6^{-8}} \\ \text{solve} \\ \frac{6^5\cdot6^{-3}}{6^{-8}}=\frac{6^{5-3}}{6^{-8}}=\frac{6^2}{6^{-8}}=6^2\cdot\frac{1}{6^{-8}}=6^2\cdot6^8=6^{10} \end{gathered}[/tex]so, this is not an answer
I hope this helps you
How do I find the selling price if a store pays 3$ for a magazine. The markup is 5%
Answers
We need to find the selling price of a magazine. We know that the store pays $3 for it, and the markup is 5%.
So, we need to add 5% of the initial price to that initial price.
First, let's find:
[tex]5\%\text{ of }\$3=5\%\cdot\$3=\frac{5}{100}\cdot\$3=\frac{\$15}{100}=\$0.15[/tex]Now, adding the previous result to the initial price, we obtain:
[tex]\$3+\$0.15=\$3.15[/tex]Therefore, the selling price is $3.15.
Function g is a transformation of the parent function exponential function. Which statements are true about function g?
Answers
For the given function, The following are true statements:
Four units separate function g from function f.There is a y-intercept for function g. (0,4)Function g has a range of (3,∞ ).Over the range (-, ∞), function g is positive.It may be seen from the graph below that
The g function's graph is 4 units higher than the parent exponential function's graph.
All of the input values for which the function is defined are referred to as the function's domain. The domain of the function is (-, ∞ ) according to the graph of function g.
The location where a function's graph crosses the y-axis is known as the y-intercept. G's graph crosses the y-axis at (0, 4). As a result, the Function g's y-intercept is (0,4).
growing function g across the range (- ∞, 0).
Function output values are referred to as the function's range. It can be seen from the graph that the range of function g is (3, ∞ ).
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2) A seat has a speed of 15 mph in seicher travels downstream from Greentown to Glenevon in 2/5 of an hour. It then goes back upstream from Glenevon to Colombia, which is 2 miles downstream, in 3/5 of an hour. Find the rate of the current.
Answers
Rate of the current = 5 mph
Explanations:The time taken to travel downstream from Greentown to Glenevon = 2/5 hours
The time taken to travel upstream from Glenevon to Columbia = 3/5 hours
Rate = Distance /time
Let the distance traveled = y miles
Rate of the downstream travel:
Rate = y ÷ 2/5
Rate = y x 5/2
Rate = 5y / 2
Rate of the upstream travel
Since the travel upstream from Glenevon to Columbia is 2 meters downstream:
Distance = y - 2
Rate = (y-2) ÷ 3/5
Rate = (y-2) x 5/3
Rate = 5(y-2)/3
Let the current rate be represented by k
The rate of the downstream travel will be:
15 + k = 5y/2...........(1)
The rate of the upstream movement will be:
15 - k = 5(y-2)/3............(2)
Add equations (1) and (2)
(15 + k) + (15 - k) = [5y/3] + [5(y-2)/3]
[tex]\begin{gathered} 30\text{ = }\frac{5y}{2}+\text{ }\frac{5y-10}{3} \\ 30\text{ = }\frac{15y+10y-20}{6} \\ 30(6)\text{ = 15y + 10y - 20} \\ 180\text{ = 25y - 20} \\ 180\text{ + 20 = 25y} \\ 25y\text{ = 200} \\ y\text{ = 200/25} \\ y\text{ = 8} \end{gathered}[/tex]Substitute the value of y into equation (1)
[tex]\begin{gathered} 15\text{ + k = }\frac{5y}{2} \\ 15\text{ + k = }\frac{5(8)}{2} \\ 15\text{ + k = }\frac{40}{2} \\ 15\text{ + k = 20} \\ k\text{ = 20 - 15} \\ k\text{ = 5} \end{gathered}[/tex]The rate of the current = 5 mph
Evaluate theexpression belowwhen x = = 3.<54 : 2.3 - 22Enter your answer inthe box below.
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The given expression is
[tex]54\frac{.}{.}2\times3-x^2[/tex]where x=3
the dot in the expression means multiplication
substitute into the expression above we have
[tex]\begin{gathered} 54\frac{.}{.}2\times3-3^2 \\ \end{gathered}[/tex]Applying BODMAS
[tex]27\times3-3^2[/tex][tex]\begin{gathered} 81-3^2 \\ 81-9 \\ 72 \end{gathered}[/tex]Therefore the value of the expression is 72
what number is divisible by 5 ? 86,764,670,or27
Answers
The number divisible by 5 is 670.
Numbers divisible by 5 have their last digits as 0 or 5
Answer : 670
What is the answer to 3/8 + 7 5/8
Answers
Given the Addition:
[tex]\frac{3}{8}+7\frac{5}{8}[/tex]You can find the sum as follows:
1. Covert the Mixed Number to an Improper Fraction:
- Multiply the Whole Number part by the denominator of the fraction.
- Add the result to the numerator.
- The denominator does not change.
Then:
[tex]7\frac{5}{8}=\frac{5+(7\cdot8)}{8}=\frac{5+56}{8}=\frac{61}{8}[/tex]2. Rewrite the Addition:
[tex]=\frac{3}{8}+\frac{61}{8}[/tex]3. Since the denominators are equal, you only need to add the numerators:
[tex]=\frac{3+61}{8}=\frac{64}{8}[/tex]4. Simplifying the fraction, you get:
[tex]=8[/tex]Hence, the answer is:
[tex]=8[/tex]What is the distance from 7 to 0? O A. 7, because 171 = 7 Jurid O B. 7, because 171 = 7 O c. 7, because |-71 = -7 O D. -7, because [7] = -7
Answers
The distance from 7 to 0 is 7 because the absolute value of 7 is 7.
Correct Answer: A
The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?
Answers
The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?
we have that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube.
so
Find the scale factor
ratio volumes=40.5/12=3.375
3.375=(scale factor)^3
[tex]\text{scale factor=}\sqrt[3]{3.375}[/tex]scale factor=1.5
To find out the diameter of the larger balloon multiply the scale factor by the diameter of the smaller balloon
so
1.5*(10)=15 inches
the answer is 15 inchesCan you please help me out with a question
Answers
right. the lateral area of a hemisfere is the curved area, wich is half the area of a complete sphere
area of a sphere:
4πr²
So, half the area is 1/2(4πr²)= 2πr²
Now, the total surface is the lateral area plus the area of the base. the base is a circle, so the area is equal to πr²
And the volume of a hemisfere is equal to half the volume of a sphere:
[tex](\frac{4}{3}\pi r^3)\cdot\frac{1}{2}\text{ =}\frac{2}{3}\pi r^3[/tex]So, the anwsers are:
[tex]2\pi r^{2}\text{ = }2\pi(24ft)^{2}\text{ = 1152}\pi ft^2[/tex][tex]\pi r^{2}\text{ = }\pi(24ft)^2\text{ = 576}\pi ft^2[/tex][tex]\frac{2}{3}\pi r^3\text{ = }\frac{2}{3}\pi(24ft)^3\text{ = 9216}\pi ft^3[/tex]The answers are in order
i need help with this question
Answers
Answer:
8%.
Step-by-step explanation:
The perimeter = 2(20 + 30)
= 100 cm.
The new perimeter = 2(20 + 0.05*20 + 30 + 30*0.10)
= 2(21 + 33)
= 2*54
= 108 cm.
Percent increases = 8%.
andrews family spent 410 on 2 adult tickets to go to the concert. maxs family spent 375 on 3 tickets and 2 child tickets 3 how much is the adult ticket how much is a child ticket
Answers
Let 'x' represents the cost of the ticket for an adult, and 'y' be the cost of a child's ticket.
Andrew's family spend 410 on two adult tickets.
[tex]2x=410[/tex]From the above expression,
[tex]\begin{gathered} x=\frac{410}{2} \\ =205 \end{gathered}[/tex]Thus, the cost of an adult ticket is 205.
Given that the Max's family spend 375 for 3 tickes, and two of them is for childrens.
[tex]\begin{gathered} x+2y=375 \\ 205+2y=375 \\ 2y=375-205 \\ 2y=170 \\ y=\frac{170}{2} \\ y=85 \end{gathered}[/tex]Thus, the cost for tickets for the childrens is 85.
what is the simplified ratio of 32:24
Answers
Answer:
4/3
Step-by-step explanation:
The simplest form of
32: 24
is 43
Steps to simplifying fractions
Find the GCD (or HCF) of numerator and denominator
GCD of 32 and 24 is 8
Divide both the numerator and denominator by the GCD
32 ÷ 8
24 ÷ 8
Reduced fraction:
4/3
Therefore, 32/24 simplified to lowest terms is 4/3.
