identify point in region of inequalities

Answers

Answer 1

We want to picture the inequalities

[tex]y<\text{ - x -3}[/tex]

and

[tex]y>\frac{4}{5}x\text{ +5}[/tex]

First, we consider the lines y= -x -3 and and y=(4/5) x +5 . Since the first line has a negative slope, this means that its graph should go downwards as x increases and since the other line has a positive slope, this means that its graph should go upwards as x increases. This leads to the following picture

Now, the expression

[tex]y<\text{ -x -3}[/tex]

means that the y coordinate of the line should be below the red line. Also, the expression

[tex]y>\frac{4}{5}x+5[/tex]

means tha the y coordinate should be above the blue line. If we combine both conditions, we find the following region

so we should look for a point that lies in this region

We are given the points (-1,9), (-6,2), (9,-9) and (-8,-5).

We see that the yellow region is located where the x coordinate is always negative. So, this means that we discard (9,-9).

so we should test the other points. Since -8 is the furthest to the left, let us calculate the value of each line at x=-8.

[tex]\text{ -(-8) -3 = 8 -3 = 5}[/tex]

so, in this case the first expression is accomplished since -5 < 5. And

[tex]\frac{4}{5}\cdot(\text{ -8)+5= =}\frac{\text{ -7}}{5}=\text{ -1.4}[/tex]

However note that -5 < 1.4, and it should be greater than -1.4 to be in the yellow region. So we discard the point (-8,-5) .

We can check , iusing the graph, that the lines cross at the point (-40/9, 13/9) which is about (-4.44, 1.44). This means that for the point to be on the yellow region, it should be on the left of -4.44. Since the only point that we are given that fulfills this condition is (-6, 2), this should be our answer. We check that

[tex]\text{ -(-6)-3=3>2}[/tex]

and

[tex]\frac{4}{5}\cdot(\text{ -6)+5 = }\frac{1}{5}=0.2<2[/tex]

so, the point (-6,2) is in the yellow region

Identify Point In Region Of Inequalities
Identify Point In Region Of Inequalities

Related Questions

Compute P(7,4)
From probability and statistics

Answers

The resultant answer from computing P(7,4) from probability and statistics is 840.

What is probability?The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.The probability is computed by dividing the total number of possible outcomes by the number of possible ways the event could occur.

So, P(7,4):

This is a permutation and can be calculated as:

ₙPₓ= n! / (n - x)!Here, n = 7 and x = 4

Put the values in the given formula:

P(7, 4) = 7! / (7 - 4)!P(7, 4) = 7! / 3!P(7, 4) = 840

Therefore, the resultant answer from computing P(7,4) from probability and statistics is 840.

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when graphed on a coordinate plane,Bumby Avenue can be represented by the equation y=-4x-7. primrose can be represented by the equation 8x+2y=17. Are these streets parallel ?

Answers

Answer:

The lines are not parallel because their slopes are opposite reciprocals.

Explanation:

The lines:

[tex]\begin{gathered} y=-4x-7 \\ \text{and} \\ 8x+2y=17 \end{gathered}[/tex]

are not parallel because their slopes are not the same

Note:

Two straight lines are said to be parallel when their slopes are the same, and have different y-intercepts.

2×+22=2(x+11)whats the property

Answers

Distributive property

In this property, multiplying the sum of two or more terms in that add up in a bracket by a number outside the bracket will be equal to multiplying each term in the bracket individually and then followed by sum of the product. In this question:

2x + 22 = 2(x + 11 ) in that when you perform product on the right side of the equation, the result is the same i.e 2x + 2*11 = 2x + 22

2.) On the first night of a concert, Fish Ticket Outlet collected $67,200 on the sale of 1600 lawn
seats and 2400 reserved seats. On the second night, the outlet collected $73,200 by selling
2000 lawn seats and 2400 reserved seats. Solve the system of equations to determine the cost
of each type of seat.

Answers

Answer:

L=$15

R=$18

Step-by-step explanation:

i cant really explain the work

Charlene and Gary want to make perfume. In order to get the right balance of ingredients for their tastes they bought 2ounces of rose oil at $4.36 per ounce, 5 ounces of ginger essence for $2.15 per ounce, and 4 ounces of black currant essence for $2.27 per ounce. Determine the cost per ounce of the perfume.

Answers

First, lets calculate how much the expended in the perfume:

[tex]2\times(4.36)+5\times(2.15)_{}+4\times(2.27)=28.55[/tex]

So, for 11 ounces of perfume, they need $28.55, so the minimum that the perfume need to cost per ounce is:

[tex]\frac{28.55}{11}=2.5954\cong2.6[/tex]

So, about $2.6 per ounce of perfume.

Two cyclists, 108 miles apart, start riding toward each other at the same time. One cycles 2 times asfast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?

Answers

Initial distance: 108 miles

We know that they start riding toward each other, and one of them is 2 times as fast as the other. Then, if the speed of the slowest is v, the speed of the faster cyclist is 2v. The combined speed is:

[tex]v_T=v+2v=3v[/tex]

The speed and the distance are related by the equation:

[tex]V=\frac{D}{t}[/tex]

They meet 4 hours later, thus:

[tex]\begin{gathered} D=108 \\ t=4 \end{gathered}[/tex]

Finally, using the previous equation:

[tex]\begin{gathered} 3v=\frac{108}{4} \\ \Rightarrow v=9\text{ mi/h} \end{gathered}[/tex]

The speed of the faster cyclist (2v) is 18 mi/h.

Shaun deposits $3,000 into an account that has an rate of 2.9% compounded continuously. How much is in the account after 2 years and 9 months?

Answers

The formula for finding amount in an investment that involves compound interest is

[tex]A=Pe^{it}[/tex]

Where

A is the future value

P is the present value

i is the interest rate

t is the time in years

e is a constant for natural value

From the question, it can be found that

[tex]\begin{gathered} P=\text{ \$3000} \\ i=2\frac{9}{12}years=2\frac{3}{4}years=2.75years \end{gathered}[/tex][tex]\begin{gathered} e=2.7183 \\ i=2.9\text{ \%=}\frac{2.9}{100}=0.029 \end{gathered}[/tex]

Let us substitute all the given into the formula as below

[tex]A=3000\times e^{0.29\times2.75}[/tex][tex]\begin{gathered} A=3000\times2.21999586 \\ A=6659.987581 \end{gathered}[/tex]

Hence, the amount in the account after 2 years and 9 months is $6659.99

3.2 Similar FiguresIf ASRT - ACBD, find the value of x.Show all work.Hint: Don't let your eyes deceive you pay attention tothe similarity statement.

Answers

Find the ratio of corresponding sides:

SRT to CBD =

70/50 = 1.4

SR / 60 = 1.4

SR = 60 x 1.4

SR = 84

84= 11x-4

Solve for x:

84+4 = 11x

88= 11x

88/11 = x

8=x

The number of bacteria in a culture increased from 27,000 to 105,000 in five hours. When is the number of bacteria one million if:a) Does the number increase linearly with time?b) The number increases exponentially with time?

Answers

We have the following situation regarding the growth of bacteria in a culture:

• The given initial population of bacteria is 27,000

,

• After 5 hours, the population increases to 105,000.

Now, we need to find the moment when that population is one million if:

• The population increases linearly with time

,

• The population increases exponentially with time

To find the time in both situations, we can proceed as follows:

Finding the moment when the population is one million if it increases linearly with time

1. We need to find the equation of the line that passes the following two points:

• t = 0, population = 27,000

,

• t = 5, population = 105,000

2. Then the points are:

[tex]\begin{gathered} (0,27000)\rightarrow x_1=0,y_1=27000 \\ (5,105000)\rightarrow x_2=5,y_2=105000 \\ \end{gathered}[/tex]

3. Now, we can use the two-point form of the line equation:

[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \\ y-27000=\frac{105000-27000}{5-0}(x-0) \\ \\ y-27000=\frac{78000}{5}x=15600x \\ \\ y=15600x+27000\rightarrow\text{ This is the line equation we were finding.} \end{gathered}[/tex]

4. We can see that the population is given by y. Then if y = 1,000,000, then we need to solve the equation for x as follows:

[tex]\begin{gathered} 1000000=15600x+27000 \\ \\ 1000000-27000=15600x \\ \\ \frac{(1000000-27000)}{15600}=x \\ \\ x=62.3717948718\text{ hours} \\ \\ x\approx62.3718\text{ hours} \end{gathered}[/tex]

Therefore, if the population increases linearly with time, the number of bacteria will be one million around 62.3718 hours.

Finding the moment when the population is one million if it increases exponentially with time

1. In this case, we also need to find the equation that will give us the time when the number of bacteria is one million. However, since the equation will be exponential, we have:

[tex]\begin{gathered} y=a(1+r)^x \\ \\ a\rightarrow\text{ initial value} \\ \\ x\rightarrow\text{ number of time intervals that have passed.} \\ \\ (1+r)=b\text{ }\rightarrow\text{the growth ratio, and }r\rightarrow\text{ the growth rate.} \end{gathered}[/tex]

2. Now, we can write it as follows:

[tex]\begin{gathered} a=27000 \\ \\ x=5\rightarrow y=105000 \\ \\ \text{ Then we have:} \\ \\ 105000=27000(b)^5 \\ \end{gathered}[/tex]

3. We can find b as follows (the growth factor):

[tex]\begin{gathered} \frac{105000}{27000}=b^5 \\ \\ \text{ We can use the 5th root to obtain the growth factor. Then we have:} \\ \\ \sqrt[5]{\frac{105000}{27000}}=\sqrt[5]{b^5} \\ \\ b=1.31209447568 \end{gathered}[/tex]

4. Then the exponential equation will be of the form:

[tex]\begin{gathered} y=27000(1.31209447568)^x \\ \\ \text{ To check the equation, we have that when x = 5, then we have:} \\ \\ y=27000(1.31209447568)^5=105000 \end{gathered}[/tex]

5. Now, to find the time when the number of bacteria is one million, we can proceed as follows:

[tex]\begin{gathered} 1000000=27000(1.31209447568)^x \\ \\ \frac{1000000}{27000}=1.31209447568^x \end{gathered}[/tex]

6. Finally, we need to apply the logarithm to both sides of the equation as follows:

[tex]\begin{gathered} ln(\frac{1000000}{27000})=ln(1.31209447568)^x=xln(1.31209447568) \\ \\ \frac{ln(\frac{1000000}{27000})}{ln(1.31209447568)}=x \\ \\ x=13.2974595282\text{ hours} \end{gathered}[/tex]

Therefore, if the population increases exponentially with time, the number of bacteria will be one million around 13.2975 hours.

Therefore, in summary, we have:

When is the number of bacteria one million if:

a) Does the number increase linearly with time?

It will be 62.3718 hours

b) The number increases exponentially with time?

It will be around 13.2975 hours

Subtract. Write fractions in simplest form. 12/7 - (-2/9) =

Answers

You have to subtract the fractions:

[tex]\frac{12}{7}-(-\frac{2}{9})[/tex]

You have to subtract a negative number, as you can see in the expression, both negatives values are together. This situation is called a "double negative" when you subtract a negative value, both minus signs cancel each other and turn into a plus sign:

[tex]\frac{12}{7}+\frac{2}{9}[/tex]

Now to add both fractions you have to find a common denominator for both of them. The fractions have denominators 7 and 9, the least common dneominator between these two numbers is the product of their multiplication:

7*9=63

Using this value you have to convert both fractions so that they have the same denominator 63,

For the first fraction 12/7 multiply both values by 9:

[tex]\frac{12\cdot9}{7\cdot9}=\frac{108}{63}[/tex]

For the second fraction 2/9 multiply both values by 7:

[tex]\frac{2\cdot7}{9\cdot7}=\frac{14}{63}[/tex]

Now you can add both fractions:

[tex]\frac{108}{63}+\frac{14}{63}=\frac{108+14}{63}=\frac{122}{63}[/tex]

. In a 30°-60-90° triangle, the hypotenuse is 7 yards long.Find the exact lengths of the legs?

Answers

ANSWER

The lengths of the legs of the triangle are 6.06 yards and 3.6 yards.

EXPLANATION

First, let us make a sketch of the problem:

To find the length of the legs, we have to apply trigonometric ratios SOHCAHTOA.

We have that:

[tex]\sin (60)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

From the diagram:

[tex]\begin{gathered} \sin (60)=\frac{x}{7} \\ \Rightarrow x=7\cdot\sin (60) \\ x\approx6.06\text{ yds} \end{gathered}[/tex]

We also have that:

[tex]\sin (30)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

From the diagram:

[tex]\begin{gathered} \sin (30)=\frac{y}{7} \\ \Rightarrow y=7\cdot\sin (30) \\ y=3.5\text{ yds} \end{gathered}[/tex]

The lengths of the legs of the triangle are 6.06 yards and 3.5 yards.

Solve triangle EFG with the given parts.f = 17.78, F = 27.3°, G = 102.1°

Answers

STEP - BY - STEP EXPLANATION

What to find?

g, E and e

Given:

Step 1

Find the measure of side g using the sine ratio.

[tex]\begin{gathered} \frac{sinF}{f}=\frac{sinG}{g} \\ \\ \frac{sin27.3}{17.78}=\frac{sin102.1}{g} \\ \\ gsin27.3=17.78sin102.1 \\ \\ g=\frac{17.78sin102.1}{sin27.3} \\ \\ g\approx37.9 \end{gathered}[/tex]

Step 2

Find angle E.

[tex]E+F+G=180(sum\text{ of interior angle in a triangle\rparen}[/tex][tex]\begin{gathered} E+27.3+102.1=180 \\ \\ E=180-102.1-27.3 \\ \\ E=50.6° \end{gathered}[/tex]

Step 3

Find side e using the sine ratio.

[tex]\begin{gathered} \frac{sinE}{e}=\frac{sinF}{f} \\ \\ \frac{sin50.6}{e}=\frac{sin27.3}{17.78} \\ \\ esin27.3=17.78sin50.6 \\ \\ e=\frac{17.78sin50.6}{sin27.3} \\ \\ e\approx29.96 \end{gathered}[/tex]

ANSWER

g=37.9

E=50.6°

e = 29.96

there are 3 members on a hockey team (including all goalie) at the end of a hockey game each member if the team shakes hands with each member of the opposing team. how many handshakes occur?

Answers

[tex]\begin{gathered} \text{There are 2 teams, so:} \\ \text{Total of members=6} \\ C(n,k)=nCk=\frac{n!}{k!(n-k)!} \\ n=6 \\ k=2 \\ C(6,2)=6C2=\frac{6!}{2!(4)!}=\frac{720}{48}=15 \end{gathered}[/tex]

the vertex of the parabola below is at the point (3,2) and point (4,6) is on the parabola

Answers

By using the vertex and the given point, we conclude that the quadratic equation is:

y = 4*(x - 3)^2  + 2

How to find the equation of the parabola?

A quadratic equation with a vertex (h, k) and a leading coefficient A can be written as:

y = A*(x - h)^2 + k

In this case, we know that the vertex is (3, 2), replacing that in the general equation we get:

y = A*(x - 3)^2 + 2

We also know that the curve passes through (4, 6), so when x = 4, the value of y must be 6, replacing that in the quadratic equation we can find the value of A.

6 = A*(4 - 3)^2 + 2

6 = A*(1)^2 + 2

6 - 2 = A*1

4 = A

So we conclude that the quadratic equation is:

y = 4*(x - 3)^2  + 2

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Find the prime factorization of the following number write any repeated factors using exponents

Answers

Notice that 100=10*10, and 10=2*5. 2 and 5 are prime numbers; therefore,

[tex]\begin{gathered} 100=10\cdot10=(2\cdot5)(2\cdot5)=2\cdot2\cdot5\cdot5=2^2\cdot5^2 \\ \Rightarrow100=2^2\cdot5^2 \end{gathered}[/tex]

The answer is 100=2^2*5^2

Which quadrant has ordered pairs (-x,-y)?

Answers

ANSWER

Quadrant III

STEP-BY-STEP EXPLANATION:

Firstly, we need to draw the cardinal points and label each quadrant on it

Looking at the ordered pair (-x, -y), you will see that the x and y-values both fall on the negative side of the x-ais and y-axis

Hence, it falls on the quadrant III

Use the functions f(x) = 8x + 11 and g(x) = 4x² + 7x - 2 to evaluate the following:a. f(8) =b. f(-8)=c. g(6) =d. g(-7)=e. g(a) =

Answers

Given:

f(x) = 8x + 11

g(x) = 4x² + 7x - 2

We are asked to evaluate using the following:

(a) f(8)

f(8) = 8(8) + 11

f(8) = 64 + 11

f(8) = 75

(b) f(-8)

f(-8) = 8(-8) + 11

f(-8) = -64 + 11

f(-8) = -53

(c) g(6)

g(6) = 4(6)² + 7(6) - 2

g(6) = 4(36) + 42 - 2

g(6) = 144 + 42 - 2

g(6) = 184

(d) g(-7)

g(-7) = 4(-7)² + 7(-7) - 2

g(-7) = 4(49) - 49 - 2

g(-7) = 196 - 49 - 2

g(-7) = 145

(e) g(a)

g(a) = 4(a)² + 7(a) - 2

g(a) = 4a² + 7a - 2

in a hurry! have to finish the practice test in 30mins, so I can take the real one!(CHECKING AWNSERS, SO ONLY NEED AWNSERS TO I CAN COMPARE)

Answers

The expression can be simplified as,

[tex]\begin{gathered} \frac{3}{x+2}+\frac{2}{x-3}=\frac{3(x-3)+2(x+2)}{(x-3)(x+2)} \\ =\frac{3x-9+2x+4}{(x-3)(x+2)} \\ =\frac{5x-5}{(x-3)(x+2)} \end{gathered}[/tex]

Thus, option (D) is the correct option.

The confidence interval on estimating the heights of the students is given as (5.5, 6.5). Find the sample proportion of the confidence interval.

Answers

Answer:

Step-by-step explanation:

So ABC and DEF are the same triangle, this question is asking me to write an equation between the relationships of DEF. How do I write that?

Answers

Explanation

The first step is to draw a representation of the given parameters.

Since this is a right-angle triangle, the Pythagorean theorem applies. This can be seen below;

[tex]\text{Longest Leg}^2=sum\text{ of the square of the short legs}[/tex]

We can then apply it to the sides of the triangle.

DF is the longest side. Therefore,

Answer

[tex]DF^2=DE^2+EF^2[/tex]

A square has side length (2x+3). The perimeter is 60cm. Find the length of one side in centimetres

Answers

As given by the question

There are given that the side length is (2x+3) and perimeter is 60 cm.

Now,

From the formula of perimeter:

[tex]\text{Perimeter =4}\times side[/tex]

So,

[tex]\begin{gathered} \text{Perimeter =4}\times side \\ 60=4\times(2x+3) \\ 60=8x+12 \\ 8x=60-12 \\ 8x=48 \\ x=\frac{48}{8} \\ x=6 \end{gathered}[/tex]

Then,

Put the value of x into the given side length (2x+3)

So,

[tex]\begin{gathered} 2x+3=2\times6+3 \\ =12+3 \\ =15 \end{gathered}[/tex]

Hence, the one side of length is 15 cm.

Determine the system of inequalities that represents the shaded area .

Answers

For the upper line:

[tex]\begin{gathered} (x1,y1)=(0,2) \\ (x2,y2)=(2,3) \\ m=\frac{y2-y1}{x2-x1}=\frac{3-2}{2-0}=\frac{1}{2} \\ \text{ using the point-slope equation:} \\ y-y1=m(x-x1) \\ y-2=\frac{1}{2}(x-0) \\ y=\frac{1}{2}x+2 \end{gathered}[/tex]

For the lower line:

[tex]\begin{gathered} (x1,y1)=(0,-3) \\ (x2,y2)=(2,-2) \\ m=\frac{-2-(-3)}{2}=\frac{1}{2} \\ \text{ Using the point-slope equation:} \\ y-y1=m(x-x1) \\ y-(-3)=\frac{1}{2}(x-0) \\ y+3=\frac{1}{2}x \\ y=\frac{1}{2}x-3 \end{gathered}[/tex]

Therefore, the system of inequalities is given by:

[tex]\begin{gathered} y\le\frac{1}{2}x+2 \\ y\ge\frac{1}{2}x-3 \end{gathered}[/tex]


If two lines intersect to form a right angle, then they are
..(perpendicular, parallel, obtuse

Answers

the answer would be perpendicular.

(x - 5) (4x - 5) = 0 there are two answers

Answers

The solutions are the values of x that makes the expression equal to zero:

x-5 =0

Add 5 to both sides

x=5

4x-5=0

Add five to both sides

4x=5

Divide both sides by 4

x= 5/4

x=1.25

247474647447x4747474747

Answers

Answer:

1174879639277360520909 in exact form

or

in decimal form 1.17487963 x 10^21

Step-by-step explanation:

The first quartile of a data set is 32, and the third quartile is 52. Which of
these values in the data set is an outlier?

Answers

Answer: As we know that the formula of outlier is

IQR = Q3 - Q1

= 52 - 32

= 20

52 + 1.5(20) = 82...

so anything above 82 is an outlier

now

32 - 1.5(20) = 2.

..anything below 2 is an outlier

so...the 83 is outlier

so correct option is D

hope it helps

Step-by-step explanation:

What is the equation, in slope-intercept form, of a line that passes through the points(-8,5) and (6,5)?

Answers

Given the points (-8,5) and (6,5), we can find the equation of the line first by finding the slope with the following formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

in this case, we have the following:

[tex]\begin{gathered} (x_1,y_1)=(-8,5) \\ (x_2,y_2)=(6,5) \\ \Rightarrow m=\frac{5-5}{6-(-8)}=\frac{0}{6+8}=0 \\ m=0 \end{gathered}[/tex]

since the slope is m = 0, we have that the line is a horizontal line that goes through the points (-8,5) and (6,6), then, the equation of the line is:

[tex]y=5[/tex]

in slope-intercept form the equation would be:

[tex]y=0x+5[/tex]

A person standing 306 feet from the base of a church observed the angle of elevation to the church’s steeple to be 20°. How tall is the church. Give answer to the nearest whole number

Answers

Solution

- The solution steps are given below:

[tex]\begin{gathered} \text{ Applying SOHCAHTOA, we have:} \\ \frac{h}{306}=\tan20 \\ h=306\tan20 \\ \\ h=111.374...ft\approx111ft\text{ \lparen To the nearest whole number\rparen} \end{gathered}[/tex]

Final Answer

111 ft

Write the slope-intercept form of the equation of each line.4) -3+y=2/5x

Answers

[tex]y=\frac{2}{5}x+3[/tex]

where

[tex]\begin{gathered} \text{slope}=\frac{2}{5} \\ y-\text{intercept}=3 \end{gathered}[/tex]

Explanation

the equation of a line in slope-intercept form is given by:

[tex]\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]

Step 1

then, isolate y

[tex]-3+y=\frac{2}{5}x[/tex]

i) add 3 in both sides

[tex]\begin{gathered} -3+y=\frac{2}{5}x \\ -3+y+3=\frac{2}{5}x+3 \\ y=\frac{2}{5}x+3 \end{gathered}[/tex]

Hence, the answer is

[tex]y=\frac{2}{5}x+3[/tex]

where

slope=2/5

y-intercept=3

I hope this helps you

The volume of cylinder is 504 pi cm^(3) & height is 14cm Find the curved surface area 8 total surface area.

Answers

The Solution:

The correct answers are:

Curved surface area = 527.79 squared centimeters

Total surface area = 753.98 squared centimeters.

Given that the volume of a cylinder with height 14cm is

[tex]504\pi cm^3[/tex]

We are required to find the curved surface area and the total surface area of the cylinder.

Step 1:

We shall find the radius (r) of the cylinder by using the formula below:

[tex]V=\pi r^2h[/tex]

In this case,

[tex]\begin{gathered} V=\text{volume =504}\pi cm^3 \\ r=\text{ radius=?} \\ h=\text{ height =14cm} \end{gathered}[/tex]

Substituting these values in the above formula, we get

[tex]504\pi=\pi r^2\times14[/tex]

Finding the value of r by first dividing both sides, we get

[tex]\begin{gathered} \frac{504\pi}{14\pi}=r^2 \\ \\ r^2=36 \end{gathered}[/tex]

Taking the square root of both sides, we get

[tex]\begin{gathered} \sqrt[]{r^2}\text{ =}\sqrt[]{36} \\ \\ r=6\operatorname{cm} \end{gathered}[/tex]

Step 2:

We shall find the curved surface area by using the formula below:

[tex]\text{CSA}=2\pi rh[/tex]

Where

[tex]\begin{gathered} \text{ CSA=curved surface area=?} \\ h=14\operatorname{cm} \\ r=6\operatorname{cm} \end{gathered}[/tex]

Substituting these values in the formula above, we have

[tex]\text{CSA}=2\times6\times14\times\pi=168\pi=527.788\approx527.79cm^2[/tex]

Step 3:

We shall find the total surface area by using the formula below:

[tex]\text{TSA}=\pi r^2+\pi r^2+2\pi rh=2\pi r^2+2\pi rh[/tex]

Where

TSA= total surface area and all other parameters are as defined earlier on.

Substituting in the formula, we get

[tex]\text{TSA}=(2\pi\times6^2)+(2\pi\times6\times14)=72\pi+168\pi[/tex][tex]\text{TSA}=240\pi=753.982\approx753.98cm^2[/tex]

Therefore, the correct answers are:

Curved surface area = 527.79 squared centimeters

Total surface area = 753.98 squared centimeters.

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