The net force acting on the car is equal to -12000 Newton.
Given the following data:
Mass = 1,200 kgInitial velocity = 30 m/s.Final velocity = 0 m/s (since the car came to a stop).Time = 3 seconds.To determine the net force acting on the car:
How to calculate the net force.Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:
[tex]F = \frac{m(v\;-\;u)}{t}[/tex]
Where:
m is the mass.t is the time.u is the initial velocity.u is the final velocity.Substituting the given parameters into the formula, we have;
[tex]F = \frac{1200 \times (0\;-\;30)}{3}\\\\F = \frac{1200 \times (-30)}{3}\\\\F = \frac{-36000 }{3}[/tex]
Net force = -12000 Newton.
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In the simulation, there are three balls on the floor. Drag each of them up off the floor, and then let go. See what happens to the balls. In what way do the balls behave the same? In what way do they behave differently?
Answer:
I hope this helps and I'm not to late
A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.
Explanation:
you also can use paraphrase to help you reword bye bye!!
My Answer:
Starting with how they acted the same. All three balls fell at the same rate since they are of the same mass; gravity has equal force on all three. Next to the differences, all three balls bounce differently. The blue ball had an average of four bounces before it stopped. The red ball bounced twice before stopping, and lastly, the green ball didn't bounce.
My Explanation:
This is how I answered the question, and I'm on edmentem aswell.
Which property describes the rate at which waves pass by?
O A. Wavelength
B. Speed
O c. Period
C.
O D. Frequency
Option D is correct. Frequency is the property describes the rate at which waves pass by.
What is wave frequency?Wave frequency is the number of waves that travel through a specified location in a given amount of time.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
Frequency is the property describes the rate at which waves pass by.
Hence,frequency is the right answer.
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A person pushes a box across a horizontal surface at a constant speed of 0.5 meter per second The box has
a mass of 40 kilograms, and the coefficient of sliding friction is 0.25. The power supplied to the box by the
person is
a. 0.2 W
c. 50 W
b. 5W
d. 100 W
Answer:
The correct option
(C) 50W
-
Hope it help's u :))!
relation between linear and cubical expansion?
cubic expansion is 3 times the linear expansion. expressed mathematically as
[tex] \gamma = 3 \alpha [/tex]
A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant, what is its final pressure?
Answer:
0.013atm
Explanation:
every gas contains 22.4 GameCube at atmospheric pressure
A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant, then its final pressure would be 3 atm
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one, the real gases approach the behaviors of an ideal gas at a very high temperature and very low pressure.
As given in the problem A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant
By using the Boyle's law equation for the given problem
P₁V₁=P₂V₂
By substituting the values in the above equation
P₁ = 1 atmospheric pressure
V₁= V
P₂ =?
V₂= V/3
1×V=P₂×V/3
P₂ = 3V/V
P₂ = 3 atm
Thus, then its final pressure would be 3 atm
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Given that the solar spectrum corresponds to a temperature of T=5800K and peaks at a wavelength of λ =500nm, use Wien’s law to determine the wavelength ( λ ') corresponding to the peak of the blackbody curve (a) in the core of the Sun, where the temperature is T'=107 K, (b) in the solar convection zone (105 K), and (c) just below the solar photosphere (104 K). [Hint: =′′ λ T = λ ′ T ′ (why?)] What form (visible, infrared, X ray, etc.) does the radiation take in each case?
Explanation:
Given that the solar spectrum corresponds to a temperature of T=5800K and peaks at a wavelength of λ =500nm, use Wien’s law to determine the wavelength ( λ ') corresponding to the peak of the blackbody curve (a) in the core of the Sun, where the temperature is T'=107 K, (b) in the solar convection zone (105 K), and (c) just below the solar photosphere (104 K). [Hint: =′′ λ T = λ ′ T ′ (why?)] What form (visible, infrared, X ray, etc.) does the radiation take in each case?
A wheel is turning at 55 rad/s, and is slowing due to friction at a rate of -1.7 rad/s?. How long will the
wheel turn before coming to rest?(in seconds) How far will the wheel turn before coming to rest?( in
radians)
Answer:
32.4 s, 890 rad
Explanation:
ω₀ = 55 rad/s, α = -1.7 rad/s², ω = 0
α = (ω - ω₀)/t, so
t = -ω₀/α = -55/(-1.7) = 32.4 s
Δθ = ω₀t + αt²/2 = 55*32.4 + (-1.7)*32.4²/2 = 890 rad
Potential energy is the energy an object has because of its position; it is energy waiting to be released. What conclusion is BEST supported by the selection above? A All still objects have potential energy. B Some objects have more energy than others. C Most still objects do not have potential energy. D Potential energy makes objects move.
Answer:
Explanation:
An object can store energy as the result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position. This stored energy of position is referred to as potential energy. Similarly, a drawn bow is able to store energy as the result of its position. When assuming its usual position (i.e., when not drawn), there is no energy stored in the bow. Yet when its position is altered from its usual equilibrium position, the bow is able to store energy by virtue of its position. This stored energy of position is referred to as potential energy. Potential energy is the stored energy of position possessed by an object.
You are working in the field to assess the stability of various slopes in the area of a new housing development. You conclude that the ratio of resisting forces to driving forces is 0.73 in an area where many houses are slated to be built. What do you recommend to the builder
The stability of the slope to vehicles moving on it is high, thus the builder can use materials that improves or maintains the given stability of the slope so that vehicles won't skid on the slope.
Stability of the slopeThe stability of the slopes comes with the availability of the static frictional forces.
Ff/F = 0.73
where;
Ff is the frictional forceF is the driving forceThe stability of the slope to vehicles moving on it is high, thus the builder can use materials that improves or maintains the given stability of the slope so that vehicles won't skid on the slope.
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The slope's stability to vehicles traveling on it is high, thus the builder can employ materials that strengthen or preserve the slope's provided stability so that cars do not slide on the slope.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration in the different components and balancing the equation gets.Components in the x-direction.
The given data in the problem is
the ratio of resisting forces to driving forces is 0.73
f is the resisting force
F is the driving force
[tex]\rm \frac{f}{F} = 0.73[/tex]
The slope's stability to vehicles traveling on it is high.
Hence the builder can employ materials that strengthen or preserve the slope's provided stability so that cars do not slide on the slope.
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Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin, and the positive x-axis is directed from the negative charge to the positive. At what points along the x axis is the potential zero? Let V=0 at r=∞ .
The electric field is zero at x = -16.45cm
Data;
q1 = 3.4 μC q2 = -2.0 μC distance = 5cmThe Electric Field at point 0As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.
Let the point be at x.
For an electric field to be equal to zero;
[tex]k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\[/tex]
Let's solve for x using mathematical methods.
[tex]\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0[/tex]
Solving the above quadratic equation;
[tex]x = -16.45cm[/tex]
The electric field is zero at x = -16.45cm
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What is the kinetic energy of a moving toy car if the car has a mass of 15.0 kg and the velocity is 7.2 m/s ? ______ J
Answer:
389 J
Explanation:
m = 15.0 kg, v = 7.2 m/s
Kinetic energy = mv²/2 = 15.0 * 7.2²/2 = 389 J
How fast does light travels the earth?
Answer:
Light travels at a constant, finite speed of 186,000 mi/sec.
Explanation:
Light travels at a constant, finite speed of 186,000 mi/sec.
the ball is accelerating at a rate of 10 m/s squared. the balls mass if 5 kg. what is the net force on the ball? help me men plez
Answer:
50N
Explanation:
[tex]F=ma\\F=(5kg)*(10m/s^{2})\\F=50N[/tex]
Two charged particles with opposite signs but the same magnitude of charge enter a magnetic field that is perpendicular to their direction of motion. How will the motion of the two particles differ when they enter the magnetic field?
Answer:
the two particles will go opposite directions, along clockwise circle and counter-clockwise circle, respectively.
Explanation:
charge = ±q, velocity = v, magnetic field = B
force F = q v x B
opposite q will give opposite force, so the two particles will go opposite directions, along clockwise circle and counter-clockwise circle, respectively.
If the voltage in a circuit is 12V and is connected to a single 3Ohm resistor, what is the current flowing through the circuit?
Answer:
12/30
Explanation:
v=ir
i=v/r
12/30=i
A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second point charge from infinity to the position x=+4.00cm, y=0, z=0. What is the value of the second charge?
The value of the second charge is 1.2 nC.
Electric potential
The work done in moving the charge from infinity to the given position is calculated as follows;
W = Eq₂
E = W/q₂
Magnitude of second chargeThe magnitude of the second charge is determined by applying Coulomb's law.
[tex]E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC[/tex]
Thus, the value of the second charge is 1.2 nC.
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The importance of physics to mining engineering
Answer:
The process of mining is complicated and involves physics. Two main components of mine cycle are Drilling and Blasting. Some important factors in mining are the pillars, rock elasticity, and the slope stability of the ground being mined.
A box of weight 100 N is at rest on a floor where μs = 0.4. A rope is attached to the box and pulled horizontally with tension T = 30 N. Which way does the box move?
∑F = F-fs
∑F = F - μs.N
∑F = 30 - 0.4 x 100
ΣF = 30 - 40 = -10
the box doesn't move
Due to the fact that the tension of 30 N that is given to the rope is less than the maximum static friction force of 40 N, the box remains in its current position.
We need to make a comparison between the force of static friction and the force that was applied in order to figure out which way the box is going to move. The static friction force (F[tex]_friction[/tex]) works in the opposite direction to the applied force, and it keeps the box from moving so long as the applied force does not exceed the maximum static friction force. This is true provided that the applied force does not exceed the maximum static friction force.
The following equation can be used to derive the greatest static friction force (F[tex]_friction_max[/tex]) that exists between the box and the floor:
F[tex]_friction_max[/tex] = s multiplied by N
where s is the coefficient of static friction and N is the normal force. Because the box is sitting still on the floor, the normal force is equal to the weight of the box, which is 100 N in this example.
F[tex]_friction_max[/tex] equals 0.4 times 100 N, which equals 40 N.
The tension in the rope, measured in newtons (N), is thirty. Due to the fact that T (30 N) is less than the maximum force of static friction (40 N), the box will not be able to overcome the static friction, and it will not move in the direction where the applied force is exerting its force.
Therefore, there is no movement of the box when a strain of 30 N is applied to the rope and it is pulled.
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You are driving on a rural road and see a person on the shoulder ahead, riding or leading an
animal. You should
A: Use reasonable care, and don't make any loud noises when approaching them, to avoid
frightening the animal.
B: Speed up, to get past them quickly.
C: Honk your horn to wam them that you are approaching.
Answer:
A
Explanation:
Any sort of honk can frighten the animal, drive slow enough that the person would know you're coming/you're there and make sure you are taking a lot of care.
The thing that should be done when driving is A. Use reasonable care, and don't make any loud noises when approaching them, to avoid frightening the animal.
How to illustrate the information?It should be noted that the person is driving on a rural road and see a person on the shoulder ahead, riding or leading an animal.
In this case, the person should reasonable care, and don't make any loud noises when approaching them, to avoid frightening the animal.
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A 100 kg block slides down a frictionless ramp which is at an angle of 26.6 ∘ with the horizontal. Find the magnitude of the velocity of the block when it gets to the bottom of the ramp if the length of the incline is 50 meters. V=_____m/s
The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude
(100 kg) g sin(26.6°) ≈ 438 N
(Note that the positive sign here means we take "down the ramp" to be the positive direction.)
Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that
438 N ≈ (100 kg) a ⇒ a ≈ 4.38 m/s²
The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that
v² = 2a (50 m)
Solve for v :
v = √(2a (50 m)) ≈ 20.9 m/s
Brainliest if correct
Answer:
B is the correct answer of the question
Hello, I'm struggling with this physics worksheet.
A flywheel (disk) initially spinning at 1850 rpm counterclockwise is brought to rest in 3.00 minutes
a. What is the wheel's average angular acceleration?
b. What is the angular displacement of the flywheel during this acceleration?
c. If the flywheel has a mass of 155 kg and a radius of 0.650 m, what torque was required to accelerate it?
Thank you in advance.
(a) The wheel's average angular acceleration is 1.076 rad/s².
(b) The angular displacement of the flywheel during this acceleration is 17,455.6 rad.
(c) The torque required to accelerate the flywheel is 35.23 Nm.
Average angular acceleration of the flywheelThe average angular acceleration of the flywheel is calculated as follows;
[tex]\alpha = \frac{\Delta \omega}{t} \\\\\omega_f = 1850\frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 \ s} = 193.76 \ rad/s\\\\\alpha = \frac{\omega _f - \omega_i}{t} \\\\\alpha = \frac{193.76 -0}{3\min\times 60 \ s} \\\\\alpha = 1.076 \ rad/s^2[/tex]
Angular displacementThe angular displacement of the flywheel during this acceleration is calculated as follows;
[tex]\omega_f^2 = \omega_i ^2 + 2\alpha \theta\\\\\omega_f^2 = 0 + 2\alpha \theta\\\\\theta = \frac{\omega_f^2}{2\alpha} \\\\\theta = \frac{(193.76)^2}{2(1.076)} \\\\\theta = 17,445.6 \ rad[/tex]
Moment of inertia of the flywheel[tex]I = \frac{1}{2} mr^2\\\\I = \frac{1}{2} \times 155 \times 0.65^2\\\\I = 32.74 \ kgm^2[/tex]
TorqueThe torque required to accelerate the flywheel is calculated as follows;
[tex]\tau = I \alpha\\\\\tau = 32.74 \times 1.076\\\\\tau = 35.23 \ Nm[/tex]
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In an electrical storm, an electric field builds up in the space between a cloud and the ground. Lightning occurs when the magnitude of the electric field reaches a critical value EC, at which air is ionized.
Required:
a. Treat the cloud as a flat square with sides of length L. If it is at a height h above the ground, find the amount of energy released in the lightning strike.
b. Based on your answer from part a, which is more dangerous, a lightning strike from a high-altitude cloud or a low-altitude one
This answer was deleted by a Brainly Staff Member for violating our Terms of Service.
How many atoms of oxygen in the chemical formula 2 Ca(CIO2)2?
O 2
O 4
O 6
O 8
Answer:
I believe it's 8
Explanation:
Which of the following is not a power of congress?
A: ratifying presidential appointments
B: advising the president on a peace treaty?
C: commanding the armed forces
D: declaring war
Answer:
declaring war,
These include the power to declare war, coin money, raise an army and navy, regulate commerce, establish rules of immigration and naturalization, and establish the federal courts and their jurisdictions.
Explanation:
hope it helps
Answer:option no.D:declaring war
When light traveling in straight lines passes through an object that is curved like a lens, the light is ________ at different angles.
Answer:
You are right. It is reflected
Explanation:
if it is concave then the light is reflected at one direction.
if it is convex the light is reflected outwards and they will travel away from the focal point and the light scatters or will be reflected to different directions
When light traveling in straight lines passes through an object that is curved like a lens, the light is refracted at different angles. Thus, the correct option is B.
What is refraction of light?Refraction is the phenomena of bending of light, it also happens with sound, water and other waves as it passes from one transparent substance into another substance. This bending of light by refraction makes it possible for us to have lenses, such as magnifying glasses, prisms, and rainbows.
When a ray of light travels in straight line, it passes through an object that is curved like a lens, the light is refracted at various different angles, depending upon the angle of incidence of light on the lens.
Therefore, the correct option is B.
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A solar system has the five planets shown below. The mass of each planet is proportional to its size. Planet X is at equal distance from Planet A, Planet B, Planet C and Planet D Planet A Planet B Planet X Planet D Planet C O Which planet exerts the greatest gravitational force on Planet X? Planet A Planet B Planet C Planet D
Please help me i will mark Brainlast
Answer:
Explanation:
The gravitational force is equal to the equation [tex]\frac{Gm_{x} m_{p} }{r^{2} }[/tex]
r: distance between the planet and planet xm[tex]_{x}[/tex] : mass of planet x[tex]m_{p}[/tex]: mass of any planetSince we know that the distance between the planets to planet x is equal, thus the value 'r' is of no use to use to increase the gravitational force.
The only way to increase gravitational force is by increasing the mass of the planet. Thus planet C which has the greatest mass has the greatest gravitational force
Hope that helps!
A gas at 110atm and 303K filled a container of 2L. If the temperature is raised to 353 K and the pressure is increased to 440atm, what is the new volume
Question 4 options:
5.8 L
0.58 L
58 L
10.6 L
Answer:
0.58 L
Explanation:
For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.
(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2
Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.
(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
Consider our givens:
P_1 = 110atm
T_1 = 303K
V_1 = 2L
P_2 = 440atm
T_2 = 353K
Now we simply plug in these values to the equation to find the new volume, V_2.
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
(110atm * 2L) * 353K / (303K * 440atm) = V_2
77660 atm*L*K / 133320 K*atm = V_2
0.583 L = V_2
Hence, the new volume is 0.583 L.
Cheers.
Artists can create emphasis in a competition using
Answer:
Microphone and speaker
Calculate: the charge flow in 60 seconds in a wire when the current in the wire is 3.0 A.
Answer:
180 C
Explanation:
t = 60 sec, I = 3.0 A
Q = I*t = 3.0 * 60 = 180 C
