If I have 3 liters of solute, and 4 liters of solvent how many liters in solution do I have?

Answer:

Its B

Explanation:

Answer:

I think the answer is polar covalent as there will be an unequal amount of electrons shared/available. An ionic bond will not take place because the valance shell of the larger atom contains more than 1 electron.

Answer:

V₂ = 107.84 L

Explanation:

Given data:

Initial volume = 100 L

Initial pressure = 80 KPa (80/101 =0.79 atm)

Initial temperature = 200 K

Final temperature =273 K

Final volume = ?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁T₂  /T₁P₂

V₂ = 0.79 atm × 100 L × 273 K / 200 K × 1 atm

V₂ =21567 atm.L.K /200 K.atm

V₂ = 107.84 L

Answer:

a) Q₁ = 58.82 KJ

b) Q₂ = 42.48 KJ

c) Q₃ = 29.22 KJ

d) Q = 130.52 KJ  

Explanation:

a)

In order to find the energy absorbed to heat the solid, we will use:

[tex]Q_{1} = mC_{1}\Delta T_{1}[/tex]

where,

Q₁ = Heat absorbed for heating solid = ?

m = mass of solid = 488.3 g = 0.4883 kg

C₁ = Specific Heat Capacity of Solid = 2.96 J/g °C

ΔT₁ =  Change in temperature of Solid = Melting Temperature - Initial Temp.

ΔT₁ = 17.6°C - (-23.1°C) = 40.7°C

Therefore,

[tex]Q_{1} = (488.3\ g)(2.96\ J/g\ ^{0}C)(40.7\ ^{0}C)[/tex]

Q₁ = 58.82 KJ

b)

In order to find the absorbed to melt the solid at 17.6°C, we will use:

[tex]Q_{2} = nH_{fus}[/tex]

where,

Q₂ = Heat absorbed for melting solid = ?

H_fus = Heat of Fusion = 8.04 KJ/mol

n = no. of moles = [tex]\frac{m}{MM} = \frac{488.3\ g}{92.41\ g/mol} = 5.28 mol[/tex]

Therefore,

[tex]Q_{2} = (5.28\ mol)(8.04\ KJ/mol)[/tex]

Q₂ = 42.48 KJ

c)

In order to find the energy absorbed to heat the liquid, we will use:

[tex]Q_{3} = m C_{3}\Delta T_{3}[/tex]

where,

Q₃ = Heat absorbed for heating Liquid = ?

m = mass of solid = 488.3 g = 0.4883 kg

C₃ = Specific Heat Capacity of Liquid = 1.75 J/g °C

ΔT₃ =  Change in temperature of Liquid = Final Temp. - Melting Temp.

ΔT₃ = 51.8°C - 17.6°C = 34.2°C

Therefore,

[tex]Q_{3} = (488.3\ g)(1.75\ J/g\ ^{0}C)(34.2\ ^{0}C)[/tex]

Q₃ = 29.22 KJ

d)

Total amount of energy absorbed during entire process is:

[tex]Q = Q_{1} + Q_{2} + Q_{3}[/tex]

[tex]Q = 58.82\ KJ + 42.48\ KJ + 29.22\ KJ[/tex]

Q = 130.52 KJ

In order to heat a 488.3 g solid, 58.8 kJ are required. To melt the solid, 42.5 kJ are required. To heat the liquid, 29.2 kJ are required. The total amount of energy absorbed is 130.5 kJ.

Initially, a 488.3 g solid at -23.1 °C is heated up to 17.6 °C (melting point). We can calculate the heat required (Q₁) using the following expression.

[tex]Q_1 = c \times m \times \Delta T = \frac{2.96J}{g.\° C } \times 488.3g \times (17.6\° C-(-23.1\° C)) \times \frac{1kJ}{1000J} = 58.8 kJ[/tex]

where,

At 17.6 °C, we can calculate the heat (Q₂) required to melt the solid using the following expression.

[tex]Q_2 = \Delta H_{fus} \times \frac{m}{MM} = 8.04 kJ/mol \times \frac{488.3 g}{92.41g/mol} = 42.5kJ[/tex]

where,

The liquid is heated from 17.6 °C to 51.8 °C. We can calculate the heat required (Q₃) using the following expression.

[tex]Q_3 = c \times m \times \Delta T = \frac{1.75J}{g.\° C } \times 488.3g \times (51.8\° C-17.6\° C)) \times \frac{1kJ}{1000J} = 29.2 kJ[/tex]

The total amount of energy absorbed (Q) is the sum of the energy absorbed in each step.

[tex]Q = Q_1 + Q_2 + Q_3 = 58.8kJ+42.5kJ+29.2kJ= 130.5kJ[/tex]

In order to heat a 488.3 g solid, 58.8 kJ are required. To melt the solid, 42.5 kJ are required. To heat the liquid, 29.2 kJ are required. The total amount of energy absorbed is 130.5 kJ.

Learn more: https://brainly.com/question/10481356

The volume of the bag would be in (L) upon arrival in Whistler : 0.66

Boyle's Law  

At constant temperature, the gas volume is inversely proportional to the pressure applied  

[tex]\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}[/tex]

V₁=0.51 L

P₁=1.01 atm

P₂=0.78 atm

[tex]\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1.01\times 0.51}{0.78}\\\\V_2=0.66[/tex]

Answer 15m

Explanation: Distance =  Speed x Time

3 x 5 =15

Answer:

two oxygen atoms

Explanation:

One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.

Answer:

2 * (6.02 * 10^23)

Explanation:

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Explanation:

Bohr's model of the hydrogen atom is based on three postulates: (1) an electron moves around the nucleus in a circular orbit, (2) an electron's angular momentum in the orbit is quantized, and (3) the change in an electron's energy 

Answer:

C!

Explanation:

only C

A: solid B: liquid : C: GAS

Answer:

C.

Explanation:

Gas molecules are always spread far apart, and have room to move freely, so the answer is C.

Answer:

Landslides

Explanation:

Answer:

Landslides

Explanation:

Correct on edge

Answer:

demos los

Explanation:

Answer: Renewable resources can be used again and again. Non-Renewable resources can be used once

Explanation: Sunlight, water, wind, are the renewable resources

Petrol, coal, natural gas are  examples of non-renewable resources.

The question is incomplete, the complete question is shown in the image attached.

Answer:

7.69%

Explanation:

The balanced equation of this reaction is shown in the image attached to this answer.

The reaction is redox because we can notice a change in the oxidation number of species from left to right in the reaction equation.

For instance, the oxidation number of oxygen was changed from -1 in H2O2 to zero in O2. Hence H2O2 was oxidized.

To calculate the percentage of H2O2 in the sample;

number of moles of KMnO4 =  137 ml/1000 * 0.230 M = 0.03151 moles of KMnO4

From the reaction equation;

2 moles of permanganate reacts with 5 moles of H2O2

0.03151 moles of permanganate reacts with  0.03151 moles * 5/2 = 0.079 moles of H202

Mass of H2O2 reacted = 0.079 moles of H202 * 34 gmol-1 = 2.69 g

Hence % by mass of H2O2 in the sample = 2.69 g/35 g * 100 = 7.69%

Answer:

0.5 moles of Pb(OH)₂ are produced.

Explanation:    

The reaction is:  

[tex]2NaOH + Pb(NO_{3})_{2} \rightarrow Pb(OH)_{2} + 2 NaNO_{3}[/tex]

If we have 1.0 liter of 1.0 M of sodium hydroxide and lead (II) nitrate, the number of moles are:  

[tex] n_{NaOH} = C*V = 1 M*1 L = 1 mol [/tex]

[tex] n_{Pb(NO_{3})_{2}} = C*V = 1 M*1 L = 1 mol [/tex]

Now, we need to find the limiting reactant knowing that 2 moles of sodium hydroxide react with 1 mol of lead (II) nitrate:

[tex] n_{NaOH} = \frac{2 moles_{NaOH}}{1 mol Pb(NO_{3})_{2}}* 1 mol Pb(NO_{3})_{2} = 2 moles [/tex]

Since we have 1 mol of sodium hydroxide and we need 2 moles to react with lead (II) nitrate, then the limiting reactant is sodium hydroxide.

We can find the number of moles of lead (II) hydroxide produced as follows:

[tex] n_{Pb(OH)_{2}} = \frac{1 mol Pb(OH)_{2}}{2 mol NaOH}*1 mol NaOH = 0.5 mol [/tex]

Therefore, 0.5 moles of Pb(OH)₂ are produced.

I hope it helps you!  

Answer:

C

Explanation:

Answer:

ganyan din ang alam ko

Explanation:

letter c

Explanation:

Where's the question?

Answer:

Na2SO4 + Bi(NO3)3 = Bi2(SO4)3 + NaNO3

Answer:

1-Chloropropane is likely the answer (attached a picture)

Explanation:

First off there are 3 peaks and 3 carbons which indicates to me that this will be a chain without any symmetry and that each carbon has hydrogens on it.  

Second the triplet at 1.0 that integrates to 3 likely correlates to a CH3 (methyl) group.  Peaks are very upfield triplets that integrate to three are almost always methyl peaks.

Third the triplet at 3.7 is indicative of being next to the halogen.  Hydrocarbons by themselves do not have peaks that far downfield meaning that its shift could only be explained by the chlorine being involved.  Also we know that this can't be next to the methyl group since its multiplicity is to low to be next to it.  

That leaves the multiplet at 1.75 being the hydrogens on the middle carbon which also makes sense since it is more downfield then the methyl group (due to being closer to the chlorine) but is not far enough downfield to say the chlorine is there.  It also makes sense that it is a multiple since it would be a hextet due to the adjacent 5 hydrogens which can't always be resolved.

I hope this helps and let me know if anything is unclear or needs further explanation.

Answer:

The gas and liquid are at equilibrium

Answer:

0.13 km/min west

Explanation:

I just did the test.

Answer:

Pressure is a stress. It is a scalar given by the magnitude of the force per unit area. In a gas, it is the force per unit area exerted by the change of momentum of the molecules impinging on the surface. ... It is this force, acting on the surface of the solid, that we call the force due to pressure.

Explanation:

I hope this helps

Answer:

1866.4 secs

Explanation:

The integrated rate law for first order kinetics is given by;

[A] = [Ao] ^-kt

Where;

[A] = concentration of cyclopropane at time = t

[Ao] = initial concentration of cyclopropane

k = rate constant

t = time taken

From the question, we are told that 99% of cyclopropane disappeared hence;

[A] = 0.290 - (0.99 * 0.290)

[A] = 0.290 - 0.2871

[A] = 0.0029 M

Hence

0.0029 = 0.290 e^-2.74 x 10^ - 3 * t

0.0029/0.290 = e^-2.74 x 10^ - 3 * t

0.01 = e^-2.74 x 10^ - 3 * t

ln(0.01) = -2.74 x 10^ - 3 * t

-4.61 = -2.74 x 10^ - 3 * t

t= -4.61/-2.74 x 10^ - 3

t = 1866.4 secs

Answer:

0.692

Explanation:

To solve this problem we can use Henderson-Hasselbach's (H-H) equation:

In which pOH can be calculated from the pH:

Then we use the H-H equation to calculate[tex]\frac{[NH_4Cl]}{[NH_3]}[/tex]:

As the problem asks for the ratio of ammonia to ammonium chloride, we invert [tex]\frac{[NH_4Cl]}{[NH_3]}[/tex]:

The mole ratio of ammonia to ammonium chloride in a buffer with a pH of 9.09 is 0.692.

Henderson Hasselbalch equation for the weak base (NH₃) and for their conjugate acid (NH₄Cl) will be written as:

pOH = pKb + log[NH₄Cl]/[NH₃], where

pKb = base dissociation constant = 4.75

pOH will be calculated from the given value of pH as:

pH + pOH = 14

pOH = 14 - 9.09 = 4.91

Now we these values in the above equation and we get,

4.91 = 4.75 + log[NH₄Cl]/[NH₃]

log[NH₄Cl]/[NH₃] = 0.16

[NH₄Cl]/[NH₃] = 10⁰°¹⁶

[NH₄Cl]/[NH₃] = 1.44

[NH₃]/[NH₄Cl] = 1/1.44

[NH₃]/[NH₄Cl] = 0.692

Hence, required mole ratio is 0.692.

To know more about Henderson Hasselbalch equation, visit the below link:

https://brainly.com/question/26746644

Answer:

You can fill 212 balloons.

Explanation:

First we calculate the helium moles in the small cylinder, using PV=nRT:

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

Then we calculate the number of moles that can fit in a single balloon:

Finally we divide the total number of available moles by the number of moles in a single balloon:

So the answer is that you can fill 212 balloons.

Answer:

Recessive and Dominant

Explanation:

Answer:

4 doughnut

Explanation:

Answer:

Charged ion

Explanation:

Answer:

Following are the solution to this question:

Explanation:

In this opinion, Tim Kane believed that its economy can not be badly affected by low manufacturing jobs in 1979, provided, in which an American industrial production had strong potential growth. Their view also opposes whatever Mr. Grove said of lower US employment particularly cos of increased production figures. Their opinion disputes as much as the American.

In Forbes, they wrote that All our industrial production is breaking records with increasing efficiency, despite a low number of industrial workers. Including Mr. grove, he favors beginning for small businesses. It was mainly due to the big advantage of smaller companies or the production of employment.

Answer:

the PH would be 12 the person was correct!

Explanation:

Answer:

yessirrrrrrrrrrrrrr

Explanation:lets get ma boa

Answer:

kinetic energy

Explanation:

Answer:

kenetic energy is the one