if the evaporator oulet temperature on an r-410A system is 50f and the evaporator superheat is 10f, what is the evaporating pressure of the refrigerant in the system

Answer:

it traveled 1350 kilometers or 839 miles

Explanation:

You just have to do 450 times three because its 3 HOURS and 450 kilometers per HOUR.

A circuit is complete when there is a continuous path for electricity to travel from one end of the energy source to the other end.

Electric circuit: a way for current to travel. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

Several categories are used to categorise electric circuits. One-way current only flows through a direct-current circuit. As in most residential circuits, an alternating-current circuit transports current that pulses back and forth repeatedly every second.

Learn more about electric circuit here:

https://brainly.com/question/29032441

#SPJ5

Answer:

heathy, people, apple, motivational, together  

Explanation:

Answer:

She fell out of a tree

Explanation:

Answer:

bbx

Explanation:

xbb

Answer:

The answer is A) River delta

Explanation:

River deltas are formed by the deposition of sediment carried by rivers.

Explanation:

Fnet = ma = (20kg)(2.5m/s²) = 50N to the left.

Hence Ff = 30N to the right. (Ff is frictional force)

Coefficient of kinetic friction

= Ff / Normal force

= 30N / (mg)

= 30N / [(20kg)(9.81N/kg)]

= 0.15.

Answer:

Happy now?

Explanation:

Correct answer:

Sound waves are longitudinal waves, meaning that the waves propagate by compression and rarefaction of their medium. They are termed longitudinal waves because the particles in the medium through which the wave travels (air molecules in our case) oscillate parallel to the direction of motion.

Answer:

Storing it at a temperature greater than its Curie temperature will demagnetize it. The Curie temperature--named after the French scientist Pierre Curie--is the temperature at which magnets lose their permanent magnetism. ... Samarium cobalt, neodymium, and ceramic/ferrite magnets are brittle.

Answer:

A. the same speed as the first trip

Explanation:

there's no friction

pls mark as brainliest

Answer:

b. 40 ms

Explanation:

A wave travels at a speed of 20 m/s

the wavelength is 0.800 m

Required

the period

The expression for the velocity of a wave is given as

[tex]v=f \lambda\\\\f= v/ \lambda\\[/tex]

substituting our data

[tex]f= 20/0.8\\\\f=25Hz[/tex]

But T=1/f

T=1/25

T=0.04s

T=40ms

the answer is B

i jus took the assement

Answer:

B

Explanation:

Answer:

a)  F_total = -648 10⁻⁴ N

,  b)   F_total = - 312 N,  c)   F_total = (38.6 i ^ + 883.4 j ^) 10⁻⁴ N

Explanation:

To solve this exercise we will use Coulomb's law

         F = k q₁ q₂ / r²

and that forces are vectors

They indicate that the charge q₁ = 3 10⁻⁴ C and the charge q₂ = 12 10⁻⁴ C being separated d = 1 m

Let's place the reference system on the charge q₁

a) we place a third charge q₃ = 2 10⁻⁹ C at the midpoint

        r = d / 2

        r = ½ m

Since all charges have the same sign, the forces are repulsive, so the total force is

        F_total = F₁₃ - F₂₃

let's develop this expression

        F_total = k q₁ q₃ / r² - k q₂ q₃ / r²

        F_total = [tex]k \frac{q_{3} }{r^{2} } ( q_{1} - q_{2} )[/tex]

let's calculate

         F_total = 9 10⁹  (3- 12) 10⁻⁴

         F_total = -648 10⁻⁴ N

b)  place the charge q₃ at a distance r = -0.5 m to the left of the charge q₁  

        F_total = -F₁₃ -F₂₃  

       F_total = -k q₁ q₃/ r₁₃² - k q₂ q₃ / r₂₃²  

      F_total = - [tex]k q_{3} ( \frac{q_{1} }{r_{13}^{2}} + \frac{q_{2} }{r_{23}^{2} } )[/tex] 

the distances  

      r₁₃ = 0.5 m  

     r₂₃ = 0.5 +1 = 1.5 m  

calculate  

    F_total = - 9 10⁹ 2 10⁻⁹ (3 /0.5² + 12 /1.5²) 10⁻⁴  

    F_total = - 18 (12 + 5.33) 10⁻⁴  

    F_total = - 312 N

c) the charged q₃ is placed on the charge q₂ on the y axis.  

In this case the charge q₂ exerts a force on the y-axis on the charge q₃  

F₂₃ = k q₂ q₃ / r² j ^

where r = 0.5 m  

let's calculate  

F₂₃ = 9 10⁹ 12 10⁻⁴ 2 10⁻⁹ / 0.5²  

F₂₃ = 864 10⁻⁴ j ^  

Charge q1 exerts a repulsive force on the axis that joins them  

F₁₃ = k q₁ q₃ / r₁₃²

let's look for the distance  

r₁₃ =  

r₁₃ = 1,118 m  

Let's use trigonometry to find the direction of this distance  

tan θ = y / x  

θ = tan⁻¹ (y / x)  

θ = tan⁻¹ (0.5 / 1)  

θ = 26.6º

let's write this force in its components  

F₁₃ = k q₁  

(cos 26.6 i ^ + sin 26.6 j ^)  

let's calculate  

F₁₃ = 9 10⁹ 3 10⁻⁴  

(cos 26.6 i ^ + sin 26.6 j ^)  

F₁₃ = 43.2 (0.894 i ^ + 0.448 j ^) 10⁻⁴  

F₁₃ = (38.6 i ^ + 19.4 j⁾ 10⁻⁴ N  

Let's write the total force  

F_total = F₁₃ i ^ +  

j ^ + F₂₃ j ^  

let's substitute  

F_total = 38.6 10⁻⁴ i ^ + (19.4 + 864) 10⁻⁴ j ^  

F_total = (38.6 i ^ + 883.4 j ^) 10⁻⁴ N

Answer:

The distance the car traveled during the given time is 94.44 m.

Explanation:

Given;

time of motion t = 8 seconds

initial velocity, u = 15 km/hr = 4.167 m/s

final velocity, v = 70 km/hr = 19.444 m/s

The distance traveled by the car during this time is given by;

[tex]s = (\frac{u+v}{2} )t\\\\s = (\frac{4.167+19.444}{2} )*8\\\\s = 94.44 \ m[/tex]

Therefore, the distance the car traveled during the given time is 94.44 m.

Answer:

[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]

Explanation:

From the given information concerning the spring-mass system:

Let us apply Hooke law.

Then, we have:

mg = ks

8 = k4

k = 8/4

k = 2

Provided that the mass weighing 8 lbs is attached to a spring.

Then, we can divide it by gravity 32 ft/s².

∴

m = 8/32

m = 1/4 slugs

The medium that offers the damping force [tex]\beta = \sqrt{2}[/tex]

Now, let us set up a differential equation that explains the motion of the spring-mass system.

The general equation is:

[tex]mx '' + \beta x' + kx = 0[/tex]

where;

[tex]m = \dfrac{1}{4}[/tex]

k = 2,  and

[tex]\beta = \sqrt{2}[/tex]

Then;

[tex]\dfrac{1}{4}x'' + \sqrt{2} x' + 2x = 0[/tex]

By solving the above equation, the auxiliary equation is:

[tex]m^2 + 4 \sqrt{2} m + 8n = 0[/tex]

Using quadratic formula:

[tex]\dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{(4 \sqrt{2})^2 -4(1)(8) }}{2}[/tex]

[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{32 -32 }}{2}[/tex]

[tex]m = -2 \sqrt{2}[/tex]

Since this is a repeated root, the solution to their differential equation took the form.

[tex]x_c = c_1 e^{mt} + c_2 t e^{mt}[/tex]

[tex]x_c = c_1 e^{-2\sqrt{2} t} + c_2 t e^{-2\sqrt{2} t}[/tex]

From the initial condition.

At equilibrium position where the mass is being from:

x(0) = 0

Also, at the downward velocity of 3 ft/s

x'(0) = 3

Then, at the first initial condition:

[tex]x_c (0) = c_1 e^{-2\sqrt{2} *0} + c_2 (0) e^{-2\sqrt{2} *0}[/tex]

[tex]0= c_1 e^{0} + 0[/tex]

[tex]0= c_1[/tex]

At the second initial condition;

[tex]x' = -2 \sqrt{2} c_1 e^{-2 \sqrt{2} t } -2 \sqrt{2} c_2 t e^{-2 \sqrt{2} t } + c_2 e^{-2 \sqrt{2} t}[/tex]

where;

x'(0) = 3

[tex]x' (0) = -2 \sqrt{2} c_1 e^{-2 \sqrt{2}* 0 } -2 \sqrt{2} c_2 (0) e^{-2 \sqrt{2} *0 } + c_2 e^{-2 \sqrt{2} *0}[/tex]

[tex]3 = -2 \sqrt{2} * 0 *e^0 - 0 + c_2 e^0[/tex]

[tex]3 = 0 + c_2[/tex]

[tex]3 = c_2[/tex]

Replacing in the constraints, the equation of the motion is:

[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]

Answer:

the potential energy stored in two bands is 15J

Explanation:

The computation of the potential energy stored in two bands is as follows:

Given that

F = 15N

x = -1.00 m = -0.01m

F = -kx

k = -F ÷ x

= 15N ÷ 0.01m

= 1,500 N/m

Now the potential energy would be

= 1,500N/m × (-0.10m)^2

= 15J

hence, the potential energy stored in two bands is 15J

The same is to be considered

Answer: 600 feet

Explanation:

Answer:

Energy

A medium

Explanation:

A wave is a disturbance that travels through a medium, transferring energy from one point to another in the medium.

Mechanical waves are waves that require a medium for their propagation.

Answer:

THE ANSWER FOR THE FIRST SENTENCE IS ENERGY WHILE THE ANSWER FOR THE SECOND SENTENCE IS MATTER.

Explanation:

HOPE THIS HELPS

Answer:

to turn red litmus blue and react with acid to form salt

Answer:

an acceleration on the y-axis, on the x-axis she has no acceleration.

y-axis the speed increases linearly,  speed of the ball is constant on the x-axis

Explanation:

When the girl throws the ball, she is subjected to an acceleration on the y-axis called a relationship of gravity that is constant, on the x-axis she has no acceleration.

The speed of the ball is constant on the x-axis since there are no acceleration relationships and on the y-axis the speed increases linearly, daring the relationship constant.

Answer:

Granite

Explanation:

The best choice would be granite.

This is because granite has the highest specific heat capacity of 0.79 J/(g.K) and would thus store more heat in it for the same mass and same temperature change as the other materials.

Since it contains more heat, it would be able to heat up the room to a higher temperature than the other materials.

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

From the question, we know that

435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m

a)

To find the frequency of the wave, we would be applying this formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b) again, to find the amplitude of the magnetic field, we would use this relation

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c) and lastly,

1T = 1 (V.s/m^2)

First of all, weight is a force typically measured in Newtons. So right away, you can eliminate 35 kg and 343 kg from the given choices.

The object's weight F on Venus as given by the universal law of gravitation is

F = G (35 kg) (4.87 x 10²⁴ kg) / (6.05 x 10⁶ m)²

where G = 6.67 x 10⁻¹¹ N•m²/kg² is the gravitational constant. You would find the weight of the object to be

F ≈ 310.8 N

so the closest answer is 311 N.

Answer:

69

Explanation:

Perform addition first as;

(0.210 + 0.41) = 0.62 -------{2 significant figures}

Perform product

(1.10 x 102) = 112 -------------- {3 significant figures}

The combined product

0.62 x 112 =69.44

                 = 69 ----------2 significant figures

Rule

The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.

Answer:

Wavelength in water, [tex]\lambda=1.12\times 10^6\ m[/tex]

Explanation:

Given that,

A submarine uses sub-radio communication at 200 Hz.

The index of refraction, n = 1.333

The refractive index of a medium is given by :

[tex]\mu=\dfrac{c}{v}\\\\\mu=\dfrac{c}{\lambda_m f}\\\\\lambda_m=\dfrac{c}{\mu f}\\\\\lambda_m=\dfrac{3\times 10^8}{1.333\times 200}\\\\=1.12\times 10^6\ m[/tex]

So, the wavelength of the electromagnetic waves in water is [tex]1.12\times 10^6\ m[/tex].

Answer:

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

[tex]Cos^2 \theta = \frac{I}{I_o} \\\\Cos^2 \theta =\frac{121}{300} \\\\Cos^2 \theta =0.4033\\\\Cos \theta = \sqrt{0.4033} \\\\Cos \theta = 0.6351\\\\\theta = Cos^{-1} (0.6351)\\\\\theta = 50.57 ^0[/tex]

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Answer:

D. the same as force. the applied force per cross-sectional area.

Explanation:

Tensile stress of a material is defined as the ratio of the applied force on the material to its cross sectional area. this is expressed mathematically as;

Tensile stress = Force/cross sectional area

Tensile stress = F/A

Force is measured in newton while cross sectional area is measured in m

Hence the unit of Tensile stress is N/m²

The tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

The given problem is based on the concept of stress and strain. The force applied on a material per unit area is known as Stress. It is denoted by the symbol [tex]\sigma[/tex] .

And due to the applied force, the ratio of change in length to the original length is known as Strain. It is denoted by the symbol [tex]\epsilon[/tex].

And the ratio of Stress and Strain is known as Elastic modulus. That is,

[tex]E = \dfrac{stress}{strain}\\\\E = \dfrac{\sigma }{\epsilon}[/tex]

So, the tensile stress is obtained as,

[tex]E = \dfrac{\sigma}{\epsilon}\\\\\sigma = E \times \epsilon[/tex]

So, clearly stress is nothing but the force applied per unit cross sectional area. That is,

[tex]\sigma = \dfrac{F}{A}[/tex]

Thus, we can conclude that the tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

Learn more about the tensile stress here:

https://brainly.com/question/17077464

Answer:

Explanation:

The distance covered can be found by using the formula

[tex]d = \frac{w}{f} \\ [/tex]

f is the force

w is the workdone

From the question we have

[tex]a = \frac{12000}{800} = \frac{120}{8} \\ [/tex]

We have the final answer as

Hope this helps you