At 12,000 feet above sea level, the temperature is 38°F if the air temperatures at sea level is 80°F.
What does °F refer to in terms of temperature?Daniel Gabriel Fahrenheit, a scientist, initially suggested the temperature measure known as the Fahrenheit scale in 1724. (1686–1736).
The sign for the unit is indeed the letter °F, which stands for degrees Fahrenheit. There are several stories about how he first developed his scale, but according to the first publication, the lower defining point, 0 °F, was chosen as the freezing point of a brine solution that was formed by mixing water, snow, and ammonium chloride (a salt).
His best guess for the normal temperature of a person, which was initially put at 90 °F and later adjusted to 96 °F (around 2.6 °F),The other limit established was lower than the actual value (due to a subsequent revision of the scale).
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at the university of florida, we can remember the spectral type of the sun by thinking the sun is
The surface temperature of our Sun, a class G star, is 5800 K. Since it is hotter than a type M star, we can infer that it is cooler than a type O star. Williamina Fleming developed a system to categorize stars in the 1880s based on the potency of hydrogen absorption lines.
The stars with the strongest hydrogen lines were designated as "A" stars, followed by "B" stars with the second-strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.
However, as we saw above, hydrogen lines by themselves are not a very reliable indicator for classifying stars since they vanish from the visible light spectrum when stars get too hot or too cool.
A, B, F, G, K, M, and O were the only letters from the old system that Annie Jump Cannon focused on when she redesigned this classification system in the 1890s.
Instead of beginning over, Cannon also rearranged the existing classes into the order we are familiar with: O, B, A, F, G, K, M, in decreasing order of temperature.
In her lifetime, she classified over 500,000 stars, classifying up to three stars each minute by examining the stellar spectra, as you can read in the piece on Annie Cannon: Classifier of the Stars later in this section.
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Our Sun is a class G star with a surface temperature of 5800 K. We may conclude that it is colder than a type O star since it is hotter than a type M star.
In the 1880s, Williamina Fleming created a classification system for stars based on the strength of hydrogen absorption lines.
The stars were categorized as "A" stars, "B" stars with the second-strongest hydrogen lines, "C" stars with the strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.
Since they disappear from the visible light spectrum when stars get too hot or too cold, hydrogen lines by themselves are not a particularly accurate signal for categorizing stars, as we have shown above.
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According to Dutch scientist Christiaan Huygens, what was light made of?
•
atoms
• particles
• waves
• electrons
Answer: C) waves
Explanation: According to Dutch scientist Christiaan Huygens, light is made of waves. Huygens proposed the wave theory of light in the 17th century, which stated that light travels as a wave through a medium, such as air or water.
Huygens observed that light waves can be diffracted, refracted, and reflected, which supported his theory. He believed that these wave phenomena could be explained by the interaction of tiny, spherical wavelets emitted by light sources.
Huygens' wave theory of light was later supported and further developed by other scientists, including Thomas Young and Augustin-Jean Fresnel. It provided a basis for understanding various optical phenomena, such as interference and diffraction patterns.
While Huygens' wave theory of light was significant, it was later superseded by the electromagnetic theory of light proposed by James Clerk Maxwell. This theory unified the understanding of light as both a wave and an electromagnetic wave, and it is widely accepted today.
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An ideal gas is placed in an expandable container of volume V at pressure P. If the volume of the container is doubled to 2V at constant temperature, what is the resulting gas pressure
If the volume of the container is doubled to 2V at a constant temperature, then the resulting gas pressure will be halved.
The ideal gas law states that the product of the pressure and volume of an ideal gas is equal to the product of the number of moles of the gas and the ideal gas constant multiplied by the temperature of the gas.
PV=nRT
This means that if the volume of the container is doubled to 2V at a constant temperature, the resulting gas pressure will be halved to P/2.
This is because the number of moles of gas and the temperature remains constant, so the only variable that can change is the pressure, which is inversely proportional to the volume.
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Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart
at a speed of 2 meters per second each way. Which is the best prediction? (1 point)
When it was full, the cart had less kinetic energy.
The cart had the same kinetic energy going each way.
The cart's kinetic energy depends on Mr. Starr's mass.
When it was empty, the cart had less kinetic energy.
The best prediction, in this case, is - When it was empty, the cart had less kinetic energy.
On which variables Kinetic Energy of a particle depends?Kinetic energy is expressed by the following formula
[tex]K.E. = \frac{1}{2} mv^{2}[/tex]
where m and v represent the mass and the velocity of the particle respectively.
As the cart was moved at a constant rate of 2 meters per second in both directions, we can safely consider velocity to be constant.
Hence, the only variable element is the mass of the cart. Initially, the cart was full of groceries, hence it had more mass compared to the later scene when the cart was empty.
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Answer:
(Question) A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?
(Answer) Potential energy in the water becomes kinetic energy as it moves through turbines, which turn kinetic energy into mechanical energy that spins a generator, which changes mechanical energy into electricity.
(Question) An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?
(Answer) The acorn’s potential energy decreases as its kinetic energy increases.
(Question) An airplane carries 320 passengers from Phoenix to Los Angeles flying at an average speed of 490 miles per hour. On the return flight, the plane carries 164 passengers and travels at the same average speed. What happens to the plane’s kinetic energy?
(Answer) On the return flight, the plane has less kinetic energy.
(Question) A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?
(Answer) 90,480.6 J
(Question) Which object has kinetic energy?
(Answer) balloon rising in the sky
(Question) Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart at a speed of 2 meters per second each way. Which is the best prediction?
(Answer) When it was empty, the cart had less kinetic energy.
(Question) A student fires a toy rocket into the sky. When does the rocket have the most potential energy?
(Answer) when the rocket reaches its highest point
(Question) What is the best description of one billiard ball hitting a second billiard ball?
(Answer) Most of the kinetic energy in the first ball is transferred to the second ball.
(Question) A roller-coaster car is at the top of a hill. The car and its passengers have a combined mass of 1,088 kilograms. If the hill is 62 meters tall, how much potential energy does the car have?
(Answer) 661,068.8 J
(Question) A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?
(Answer) 592,416 J
(Question) A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?
(Answer) when the swing is pulled back prior to release
(Question) essay
(Answer) good luck
(Question) essay
(Answer) good luck
Explanation:
I just completed the assignment. UwU
A very light small ball (with a speed of 5m/s) collides with a bowling ball that is at rest. The small ball bounces back, and the bowling ball moves very slowly. Which one, small ball or bowlling ball experiences the greater magnitude impulse during the collision
The bowling ball experiences the greater magnitude impulse during the collision since it is initially at rest and is given the momentum of the small ball which has a speed of 5m/s.
The impulse of the bowling ball can be calculated using the equation impulse = change in momentum = mvf - mvi, where m is the mass of the bowling ball, vf is its final velocity, and vi is its initial velocity.
Since the bowling ball is initially at rest (vi = 0), the impulse can be calculated as mvf = m(5m/s) = 5m^2/s. The impulse of the small ball can be calculated in the same way, giving an impulse of 5m^2/s. Therefore, the bowling ball experiences a greater magnitude impulse during the collision.
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find all the second partial derivatives. f(x, y) = (sin(mx + ny))2
The second partial derivatives of f(x, y) = (sin(mx + ny))² are:
∂²f/∂x² = -m²(sin(mx + ny))²∂²f/∂y² = -n²(sin(mx + ny))²∂²f/∂x∂y = ∂²f/∂y∂x = mn(sin(mx + ny))²Second Derivatives PartialThe reason these are the second partial derivatives is because we are taking the derivative of the function twice with respect to x and y.
The first partial derivative with respect to x is:∂f/∂x = ∂/∂x (sin(mx + ny))² = ∂/∂x (sin²(mx + ny)) = 2sin(mx + ny)cos(mx + ny) * ∂/∂x (mx + ny) = m cos(mx + ny)sin(mx + ny)
The second partial derivative with respect to x is:∂²f/∂x² = ∂/∂x (m cos(mx + ny)sin(mx + ny)) = -m²sin²(mx + ny)
Similarly, the second partial derivative with respect to y is :∂²f/∂y² = ∂/∂y (n cos(mx + ny)sin(mx + ny)) = -n²sin²(mx + ny)
And lastly, the partial derivative with respect to x and y is :∂²f/∂x∂y = ∂/∂y(m cos(mx + ny)sin(mx + ny)) = mn cos(mx + ny)sin(mx + ny)
So, all these second derivatives are the result of applying the chain rule and the product rule several times.
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The pressure of a gas is reduced from 1200. 0 mmhg to 850. 0 mmhg as the volume of its container is increased by moving a piston from 85. 0 ml to 350. 0 ml. What would the final temperature be if the original temperature was 90 deg celcius?.
The final temperature would be 46.9 deg Celsius
To determine the final temperature of the gas after the pressure has been reduced, we can use the ideal gas law:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature.
Since the number of moles of gas and the universal gas constant are constants, we can rearrange the equation to solve for temperature:
T = (PV)/(nR)
We know the initial pressure, volume, and temperature of the gas, so we can plug in these values to solve for the final temperature:
Tfinal = (850.0 mmhg * 350.0 ml)/(nR)
To solve for the final temperature, we need to know the value of nR. We can use the initial pressure, volume, and temperature to calculate this value:
nR = (1200.0 mmhg * 85.0 ml)/(90 deg C)
Plugging this value into the equation for Tfinal, we get:
Tfinal = (850.0 mmhg * 350.0 ml)/((1200.0 mmhg * 85.0 ml)/(90 deg C))
Solving this equation, we find that the final temperature of the gas is approximately 46.9 degrees Celsius.
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you are taking a bath in a 1.5 m tub during a small earthquake. the water sloshes up and down at the ends of the tub but remains still in the center. you observe that the water goes through 10 oscillations in 22 s. what is the wavelength of the surface wave in m?
The wavelength of the surface wave in 1.2 m
Calculation-(a)since there are two antinodes and one node(where water is motionless), This is the first mode of a pipe open at both ends
so \lambda= 2L
\lambda=2(1.3)
\lambda=2.6m
(c)frequency= 10/22=0.455 Hz
v= f\lambda
v=0.455(2.6)
\lambda=1.2 m/s
What does the term "surface wave" mean?Surface waves are typically lower frequency than body waves and move through Earth's surface material more slowly. On a seismogram, they may be easily differentiated. Deeper earthquakes result in weaker surface waves, which are stronger as the earthquake depth increases.
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The magnetic field in the figure is decreasing at the rate 0.6 T/s . (Figure 1) Part A What is the magnitude of the acceleration of a proton at rest at point a? Part C What is the magnitude of the acceleration of a proton at rest at point b? Part E What is the magnitude of the acceleration of a proton at rest at point c? Part G What is the magnitude of the acceleration of a proton at rest at point d?
0.0080 ×10 8 m/s² is the magnitude of the acceleration of a proton at rest at point c
0.016×10 8 m/s² is the magnitude of the acceleration of a proton at rest at point d
We apply here faraday, law,
∮C→E⋅d→l=dϕmdt
For a uniform electric field;
∮C→E⋅d→l=E(2πr)∮
Here,
r = radius of the circle
Since we see that the magnetic field is perpendicular to the area of the circle, then the magnetic flux will be,
ϕm=2πrB (B= magnetic field)
E=r/2 dB/dt
Now, the force on the proton will be at distance r from the center of the circle ,
F=qE=ma
Written as,
a=qEm
Here,
q=1.6×10−19 C ( charge of the proton)
m=1.67×10−27 kg ( mass of the proton)
Thus,
a=qr/2m dB/dt
to find at point C,
we know that
r=1 cm=0.01 m
a=1.6×10−19 C X 0.01 m X 0.6 T/s / 2 ×1.67×10−27 kg
=0.0080 ×10⁸ m/s2
At the point D,
We know that,
r=2 cm = 0.02 m
Then,
a=1.6×10−19 C×0.02 m×0.6 T/s / 2×1.67×10−27 kg
=0.016×10⁸ m/s2
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How many light years in diameter have scientists estimated that our milky way galaxy is?
Milky way galaxy is about 100,000 light-years in diameter.
Milky way galaxy is the galaxy where our solar system is included is formed approximately 14 billion years ago. It got the name because of its appearance while viewed from Earth.
Ancient astronomers believed that all stars and planets of the universe is in milky way galaxy.
The number of stars in milky way galaxy is estimated at around 100-400 billion in number.
Sagittarius A is the blackhole that situated in the centre of Milky way galaxy.
It is approximated that Milky way galaxy moves at a velocity of 600 km/s and it is expanding at a rate of 500 m/s.
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A frog leaps 2 feet horizontally. The highest point in the jump is 12 foot. Assume the frog starts at (0, 0). What quadratic function models the path of the jump?.
The quadratic function that models the path of the jump is [tex]f(x)=-\frac{1}{8} (x-2)^{2}+\frac{1}{2}[/tex]
It is discovered that, given the vertex, the quadratic model is provided by different equations and the condition given is the parabolic so, the equation that we will use will be the parabolic equation that will derive into quadratic equation.
The following is the equation for a parabola with vertex (h,k):
[tex]f(x)=a (x-h)^{2}+k[/tex]
In this issue:
Leaps 2 feet horizontally, therefore the vertex's x-coordinate is 2, or
it is given by h=2.
The vertex's y-coordinate is because the highest point is half a foot high, or it is given by k=[tex]\frac{1}{2}[/tex]
Then:
[tex]f(x)=a (x-2)^{2}+\frac{1}{2}[/tex]
begins at (0,0), or the moment when x=0 and y=0, and this is utilized to find a.
[tex]0=a (0-2)^{2}+\frac{1}{2}[/tex]
[tex]4a=-\frac{1}{2}[/tex]
[tex]a=-\frac{1}{8}[/tex]
The equation is then:
[tex]f(x)=-\frac{1}{8} (x-2)^{2}+\frac{1}{2}[/tex]
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The quadratic function models the path of the jump as f(x) = -1/8(x-2)² + 1/2
The parabola's general equation is given as,
f(x) = a ( x - h )² + k
Given that,
Leaps horizontally 2 ft, means that, x-coordinate of the vertex is 2, h = 2.
The highest point is half a foot, y- coordinate of the vertex is 1/2, k = 1/2.
Then, f (x) = a(x-2)² + 1/2
By placing, x(0,0), we can find a.
0 = a(0-2)² + 1/2
4a = -1/2
a = -1/8
Thus, the equation is, f(x) = -1/8 (x-2)² + 1/2
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The heating curve shows temperature verses energy gain. Which parts of the curve represent a gain in potential energy?.
The two parts which are along x axis and have some constant value along the y axis i.e. horizontal parts represents a gain in potential energy.
In the heating curve shown in the question, these are gain in potential energy because they have constant temperature referred to the gain.he work done by a force on an object between two points does depend on the path taken by the object between the two points. For the special case of conservative forces, we have seen that the work does not depend on the path.
Therefore, we can define, for conservative forces, an associated potential energy that, for a given object, depends only on its location. In particular, when a conservative force acts on an object as it moves between two points, we define the define the change in potential energy associated with that force as minus the work done by that force between those two points.
Whatever kinetic energy the ball gains is exactly equal to the potential energy that the ball loses. If we define the total mechanical energy of an object as the sum of its kinetic and potential energy, then, in this case, we see that the total mechanical energy of the ball was conserved.
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Potential energy is increased by the two horizontal components that are along the x axis and have some constant value along the y axis.
These are a gain in potential energy in the heating curve depicted in the question since they have constant temperature. The work that a force performs on an object between two points depends on the path that the thing takes there. We have demonstrated that, in the exceptional case of conservative forces, the work is independent of the path.
As a result, we can define a potential energy associated with conservative forces that, for a given item, depends only on its location. In particular, we define the change in potential energy associated with a conservative force as the work done by that force between the two points when it acts on an item as it moves between them.
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A 2 kg block is at rest on the top of a 20 m long rough ramp inclined at 20° with a
coefficient of kinetic friction of 0.6. If an albino Alabaman accordion player does 40 J of
work on the block down the ramp over 12 nm, how far down the ramp does the block
slide?
The block slides 2.37 meters down the ramp.
What is friction?The force preventing solid surfaces, fluid layers, and material components from sliding past one another is known as friction.
The mass of the block: m = 2 kg.
Height of the ramp: h = 20 meter.
Angle of the ramp: α = 20°
coefficient of kinetic friction: μ = 0.6
Hence, frictional force f= μmg cosα = 0.6 × 2 × 9.8 × cos20° N = 10.18 N.
Total work done in sliding a distance l is = mglsinα + fl
= ( 2 × 9.8 × sin20° + 10.18) l
= 16.88 l joule.
But work done is 40 J.
Hence, the distance slides by the ramp = 40/16.88 meter = 2.37 meters.
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The proportion between the friction force and the normal force that a body travelling on a dry, uneven surface experiences is known as the kinetic friction coefficient (k). A very clever process may be used to determine k with a high degree of accuracy.
What role of coefficient of kinetic friction?We may use the equation for work to determine how far the block travels down the ramp. Which is W = Fd, where W is the amount of work completed, F is the amount of force used, and d is the length of time the force was used.
The equation can be used to determine the force in this situation, which is the force of kinetic friction. The formula for kinetic friction is kinetic friction = uk * N, where N is the normal force and uk is the coefficient of kinetic friction.
The normal force is equal to the weight of the block, which is mg, where m is the mass of the block and g is the acceleration due to gravity.
Substituting these values into the equation for work and rearranging to solve for d, we get:
d = W / (kinetic friction× cos(θ))
= 40 J / [(0.6 × 2 kg * 9.8 m/s^2) * cos(20°)]
= 40 J / [(11.76 N) * cos(20°)]
= 40 J / 10.45 N
= 3.84 m
Therefore, the block slides a distance of approximately 3.84 meters down the ramp.
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what is the displacement of the elevator between 8-20 seconds
This is an application of Newton's second law to the forces felt in an elevator.
What law of motion is an elevator?
The use of elevators in public places is a sample of rectilinear motion. If you are accelerating uphill you feel heavier, and if you are accelerating downward you feel lighter. In free fall mode, the elevator's acceleration is the same as the acceleration due to gravity. The enormity of the acceleration due to gravity is 9,8 m/s2,
Since your true weight remains the same, the net force appears because the elevator exerts a smaller normal force on you which is complemented by Newton's Third Law by an equal force downwards on the elevator
So we can conclude that an elevator going up shows constant linear motion, as the elevator will move in a linear line with a constant speed.
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How much work must be done to accelerate a 704.15 kg car from 15.28 m/s to 32.48 m/s?
Answer:
To calculate the amount of work required to accelerate a car from 15.28 m/s to 32.48 m/s, you can use the following formula:
Work = Force * Distance
In this case, the force is the accelerating force on the car, and the distance is the change in velocity of the car. The accelerating force can be calculated using the formula:
Force = Mass * Acceleration
To find the acceleration of the car, you can use the formula:
Acceleration = Change in Velocity / Time
The time it takes for the car to accelerate can be calculated using the formula:
Time = Distance / Velocity
Substituting these formulas into the original equation, we get:
Work = Mass * (Change in Velocity / Time) * (Time)
Plugging in the given values, we get:
Work = 704.15 kg * (32.48 m/s - 15.28 m/s) / (32.48 m/s - 15.28 m/s) * (32.48 m/s - 15.28 m/s / 32.48 m/s)
Simplifying this equation, we get:
Work = 704.15 kg * (17.2 m/s)^2
Work = 704.15 kg * 295.04 m^2/s^2
Work = 207,764.79 kg*m^2/s^2
So the total amount of work required to accelerate the car from 15.28 m/s to 32.48 m/s is 207,764.79 kg*m^2/s^2.
Explanation:
What are the two steps required to charge an object without any physical contact between charged objects
There are two main methods for charging an object without any physical contact between charged objects namely induction and Coulombic attraction/repulsion.
Induction is a process by which a charged object can influence the distribution of charges in a nearby conductor without actually touching it. When a charged object is brought near a conductor, it causes the electrons in the conductor to rearrange themselves in an effort to balance out the overall charge distribution. This can result in one end of the conductor becoming positively charged and the other end becoming negatively charged.
Coulombic attraction/repulsion is a phenomenon that occurs when two charged objects are brought close together. According to Coulomb's Law, if the two objects have opposite charges (e.g. one is positive and the other is negative), they will experience a force of attraction. If the two objects have the same charge (e.g. both are positive or both are negative), they will experience a force of repulsion.
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Your question seems incorrect, but I assume the correct question was:
"What are the two main methods to charge an object without any physical contact between charged objects?"
a 2.0 kg block travels with an angular velocity of 12 rad/s around a 0.50 m radius circle. what is the angular momentum of the block?
The terms velocity and angular momentum are relevant to this query.The The size of angular momentum is "6 J.s".
What is the simple definition of velocity?The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. The displacement change rate is the issue.
What does velocity vs. acceleration mean?Velocity is the term for the rate at which a displacement changes. Acceleration is the measure of a change in velocity. Velocity is a vector quantity because it comprises both magnitude and direction. Acceleration is a vector quantity because it is the speed at which velocity varies.
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A ball of mass m is dropped from rest from a height h and collides elastically with the floor, rebounding to its original height. What is the magnitude of the average force applied by the floor on the ball during the time the ball is in contact with the floor?.
A horizontal floor receives a ball of mass m that is dropped upon it from height h, colliding with it at speed u. If the floor's coefficient of restitution is, the ball will get an impulse on its second rebound off the floor.
How do you tell whether an impulse is good or bad?A negative impulse indicates that the net force is moving in the opposite direction since impulse is a vector. Similar to this, a positive impulse denotes a positive net force.
The centre of mass of the ball experiences translational (rectilinear) motion when it rolls on the ground, whereas the ball itself experiences rotating motion in the centre of mass frame. Thus, rectilinear motion is demonstrated by a ball rolling on the ground.
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A car speedometer has a 3% uncertainty. What is the range of possible speeds (in km/h) when it reads 120 km/h
Answer:
The range of possible real speeds is:
[tex]x\ -\ the\ actual\ speed \\116.4 < x < 123.6[/tex]
Explanation:
If we know that the certainty of a measurement is 3% - we refer that to the measured value - we calculate how much is 3% of 120:
[tex]120 * 3\% = 3.6[/tex]
To calculate the lower limit - we subtract the given value from the measurement value and to calculate the upper limit - we have to add.
Three boxes, A, B, and C, are placed on a frictionless surface as shown in the diagram below. If you push on box A with a force of 8.25 N, find the contact force (in N) between each pair of boxes. Here mA -5.50 kg, Mg = 4.40 kg, and mc-1.50 kg. contact force between A and B 4.26 contact force between B and C 7.45 - X How much force does box B apply to Box C? N
The contact force (in N) between each pair of boxes is mathematically:
F_{ab} = 3.56 N
F_{bc} = 1.2 N
The net force gives you the system acceleration, and then each box's acceleration gives you the pushing force.
8.25 N = (5.5 + 4.4 + 1.5)kg * a → a = 0.724 m/s²
Therefore the B&C force is
Fab = (1.5 + 4.4)kg * 0.724m/s² = 4.27 N
and
Fbc = 1.5kg * 0.724m/s² = 1.09 N
Five instances of contact force:
Contact force is a force that, when applied to an item, can initiate or modify the motion of the object. For instance, the force exerted by muscles, friction, springs, tension, air resistance, etc.
What do contact force examples mean?(a) A contact force is precisely what it sounds like: it is the force that one body exerts on another when they are in close proximity. For instance, you are exerting a contact force on a box when you pull it off the ground.
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32) You are at the stern of a paddle boat and observe that the paddle wheel has a radius of 10ft and makes 15
revolutions per minute. What is the speed of the paddle boat with respect to the water?
The linear speed of the paddle boat is 15.7 ft/s.
What is the speed of the paddle boat?
The speed of the paddle boat is calculated by applying the following formula as shown below.
v = ωr
where;
ω is the angular speed of the paddle boatr is the radius of the circular pathThe angular speed of the paddle boat = 15 rev / min
= 15 rev/min x 2π rad/rev x 1 min / 60 s
= 1.57 rad/s
The linear speed of the paddle boat is calculated as follows;
v = 1.57 rad/s x 10 ft
v = 15.7 ft/s
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A 560-g squirrel with a surface area of 144cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a drag coefficient for a horizontal skydiver.) What will be the velocity of a 56-kg person hitting the ground, assuming no drag contribution in such a short distance
Answer:
To estimate the terminal velocity of the squirrel, we need to consider the forces acting on it: its weight, the force of gravity, and the drag force. The terminal velocity is the velocity at which the sum of these forces is zero, meaning that the squirrel is no longer accelerating.
The weight of the squirrel is given by:
W = m * g
where m is the mass of the squirrel and g is the acceleration due to gravity (9.8 m/s^2).
The force of gravity is given by:
F_g = W
The drag force is given by:
F_d = (1/2) * C * rho * A * v^2
where C is the drag coefficient, rho is the density of air, A is the surface area of the squirrel, and v is its velocity.
The equation for terminal velocity can be written as:
0 = W - F_d
= m * g - (1/2) * C * rho * A * v^2
Solving for v, we get:
v = sqrt((2 * m * g) / (C * rho * A))
Plugging in the values for the squirrel, we get:
v = sqrt((2 * 560 g * 9.8 m/s^2) / (1.28 * 1.225 kg/m^3 * 144 cm^2))
= 15.4 m/s
Therefore, the terminal velocity of the squirrel is approximately 15.4 m/s.
To calculate the velocity of a person hitting the ground, we can use the same formula as above, but with the mass and surface area of the person.
Plugging in the values for the person, we get:
v = sqrt((2 * 56 kg * 9.8 m/s^2) / (1.28 * 1.225 kg/m^3 * 5000 cm^2))
= 51.5 m/s
Therefore, the velocity of the person hitting the ground would be approximately 51.5 m/s, assuming no drag contribution in such a short distance.
a uniform ladder weighing 480 n rests against a frictionless wall. the ladder makes a angle with the horizontal. find the horizontal force the ground exerts on the base of the ladder when an 800 n firefighter is from the bottom.
Given that static friction is defined as F equal to the sum of a coeffficient for static friction as well as the normal response N, we obtain the following value: 0.297
Is the wind an horizontal force?Because different sections of the Earth are heated differently by the sun, resulting in pressure differences, solar sun is the primary source of pressure differences that cause winds to occur.
Why does horizontal pressure exist?After being projected onto a nearby horizontal plane, the pressure gradient results in a two-dimensional vector known as the horizontal pressure gradient. This force of the horizontal pressure gradient is directed from higher pressure toward lower pressure very close to the Earth's surface.
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A substance having low specific heat capacity on with equal. gets heated faster than another mass and having high specific head capacity? why?
Heat capacity of a substance is the amount of heat energy required to raise the temperature of that substance by one degree celcius. Specific heat capacity of a substance is the amount of heat energy required to raise the temperature of a unit mass by one degree celcius.
We can look into the question by using the examples of water and oil.Specific heat capacity of water is 4184 JKg⁻¹K⁻¹.This means the amount of heat energy required to raise the temperature of 1 Kg water by 1 degree celcius is 4184K.Whereas,specific heat capacity of oil is 2100 JKg⁻¹K⁻¹.Hence oil needs only 2100 J to increase its temperature by one degree celcius which is half than that of water.
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A car accelerates uniformly from rest and
reaches a speed of 17.3 m/s in 6 s. The
diameter of a tire is 66.5 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev.
Describe the energy of a car driving up a hill. a. entirely kinetic b. entirely potential c. both kinetic and potential d. gravitational e. elastic Explain why
The kinetic energy of the moving car is converted from potential energy.
What type of energy does a car have when it is being driven up a hill?An easy illustration is a car that is parked at the top of a hill. The car gains more kinetic energy and loses more potential energy as it goes down the slope, increasing its kinetic energy. The car transforms kinetic energy into potential energy as it ascends the hill back to the top.
When climbing a hill, what happens to kinetic energy?The marble moves from kinetic energy to gravitational potential energy as it ascends the small hill, then backwards as it descends the hill on the opposite side.
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What does atmospheric mean in art?
Atmospheric or it is also called as atmospheric perspective is an art that creates the illusion of space in the two dimension artwork. Atmospheric emphasizes spatial intervals, the range between an object with other objects where as objects recede into the distance, the object become less detailed, lower in contrast, and getting more blurry.
What is art?Art is any activity or product that human do in purpose to create something aesthetic. There are some of category in art such as painting, sculpture, architecture, literature, music, dance, cinema, etc. The value of a certain is different for every people because of every person perspective is unique.
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A human being can be electrocuted if a current as small as 50 mA passes near the heart. An electrician working with sweaty hands makes good contact with the two conductors he is holding. If his resistance is 2200 , what might the fatal voltage be
If his resistance is 2200 Ohm , the fatal voltage is 110 Volt.
The relation between resistance, voltage, and current is given by the Ohm law:
V = I R
Where:
V = voltage
I = current
R = resistance
Parameters from the problem are:
I = current = 50 mA = 0.05 A
R = resistance = 2200 Ohm
Hence,
V = IR
= 0.05 x 2200 = 110 Volt
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two small plastic spheres are given positive electric charges. when they are apart, the repulsive force between them has magnitude what is the charge on each sphere (a) if the two charges are equal and (b) if one sphere has four times the charge of the other?
We apply positive electric charges to two little plastic spheres. The amount of the repelling force between them when they are separated depends on how charged each sphere is. In light of this, total value of all of the two was 7.4 x 10-7 C.
How does physics define an electric charge?Charge, often referred to as electric control, electrical charge, and electrostatic charge, and denoted by the symbol q, is a property of a unit unit matter that expresses that degree to which it has much more and fewer protons than electrons.
Which 3 types of fees are there?Subatomic particles or matter particles serve as examples of different types of charges: The charge on a proton is positive. Negative charge is a property of electrons. Null charge exists in neutrons.
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An object is shot vertically upward into the air with a positive initial velocity.
According to the vector study, the upward direction is taken as positive, and the downward direction is taken as negative.
in the same manner, the rightward direction is taken as positive span the leftward direction is taken as negative.
As the object is hot vertically upwards so now the direction of velocity is taken as positive as given in the question.
(Because it is direction is in the direction of the center of the Earth). until the object reaches its maximum height where the speed is zero and then it begins to fall until it hits the ground.
At the maximum height, the velocity is zero.
The acceleration acting on the object is acceleration due to gravity which is always acting downwards so it is taken as negative.
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