If two cars meet on a narrow grade and they cannot pass, the right-of-way should be yielded to:A. Neither car.B. The car going uphill.C. The car going downhill.

The torque applied by the person if he applies 12N force 1 metre away form the pivot point is 12 Nm.

The torque will be calculated by the formula -

Torque = force applied × perpendicular distance to which the torque is applied

Keep the values in formula to find the value of torque

Torque = 12 × 1

Performing multiplication on Right Hand Side of the equation to find the value of applied torque

Torque = 12 Nm

Thus, the applied torque by the person on application of 12 N force perpendicular to the level arm, is 12 Nm.

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The acceleration of the ball which experiences an initial velocity of 4m/s and a final velocity of 16m/s and covers a distance of 25 m is 4.80 m/s².

Acceleration can be defined as the change in the velocity of an object. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second square (m/s²).

The acceleration of the ball can be calculated through initial velocity, final velocity and distance through the equation:

2as = v² - u²

where, a = acceleration of the object,

s = distance covered by the object,

v = final velocity of the object,

u = initial velocity of the object

2 × a × 25 = (16)² - (4)²

50a = 256 - 16

50 a = 240

a = 240/ 50

a = 4.80 m/s²

Therefore, the acceleration of the ball is 4.80 m/s².

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The final speed of the truck is  6.92 m/s.

The motion takes 0.866 second.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

Mass of the toy truck: m = 0.25 kg.

Force acting on it  = 5.0 N.

Frictional force acting on it = 3.0 N.

Hence, net force acting on the toy truck = 5.0 N -3.0 N = 2.0 N.

Acceleration of the it = force/mass = 2.0 N /0.25 kg = 8.0 m/s².

After moving 3.0 m, the final speed of it = √(2×8.0×3.0) m/s = 6.92 m/s.

Hence, time taken = final speed/time taken = 6.92 /8.0 = 0.866 second.

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The relative speed of a two bodies moving in the same direction is the difference between the speed of two bodies. Here, the  speed of Bolt relative to the train is 27 miles /hr

The speed of an object can be related to the speed of another moving object which can be of same direction or opposite direction. The speed of a body calculated with respect to the speed  another body is called the relative speed.

Speed is the measure of distance covered per unit time. The units of speed can be m/s, kilometer/hour, miles/hour etc.

Given that speed of the train = 150 miles/h

speed of Usain Bolt = 177 miles/h

Both the train and bolt are moving in the left to right direction. Then the relative speed of bolt with respect to the train is:

177 - 150 = 27 miles/h

Therefore, Bolt runs with a speed of 27 mils/h relative to the train.

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The force that is exerted by the racket is greater than the force that is exerted by the ball. Option C

We have to note that the momentum of the object as we know it is the product of the mass and the velocity of the body. The principle of the conservation of the linear momentum states that the momentum before collision is equal to the momentum after collision.

We can see that the masses of the racket and the ball are not the same and we know hat the object that has the greater mass would surely exert more force as we can see from the image that has been attached to the question that we have in this case here. The collision here is an elastic Collison as is clear from the image.

The racket would then be able to exerted a force  that is exerted by the ball.

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A force of 10N raises a 1-kg balloon in the air at equilibrium. Since every force has an equal and equal response. Therefore, C. 10 newtons is the correct solution.

A force is said to be applied when an item pushes or pulls. The items' contact results in push and pull. To convey pressure, you may also use terms like squeeze or stretch.

An agent with the power to alter a body's resting or mobile condition is known as an external force. It possesses a magnitude and a direction. The place where force is exerted is called the application, as well as the direction in which it is applied is called the direction of a pressure.

A source. The Force may be evaluated using balance. The Newton is the Si derived unit of force (N).

Weight of blimp: 1 kilogram

Using the equation W = m g

Think that g=10m/s2.

Weight is then computed as W = 1 kg * 10 m/s2 W = 10N.

According to Newton's law, the balloon in the air is lifted up by 10N since it is in balance.

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Answer:

0.215seconds

Explanation:

m = 745kg, Fe = 38900N, Fr = 34000, v = 21m/s, t = ?

Netforce{Fn} = Fe + Fr

Fn = 38900 + 34000

Fn = 72900N

Fn = mv/t

Making time subject of the formula

We have;

t = mv/Fn

t = (745 × 21)/72900

t = 0.215s

The work done by the brakes to stop the car will be 56.25 kN-m.

If the amount of force is applied to the body and the body gets displaced from its original place. Then it is said to work is done on the system. The work done is given as,

WD = Force x Displacement

A vehicle is going along a street when the driver detects a hedgehog crossing ahead. The driver applies a slowing down the power of 2500 N and figures out how to stop the vehicle after 7.5 meters to stay away from the hedgehog.

The work done is calculated as,

WD = 7500 x 7.5

WD = 56,250 N-m

WD = 56.25 kN-m

The work done by the brakes to stop the car will be 56.25 kN-m.

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Saturn cannot transit (i.e. pass in front of) the Sun as seen from Jupiter.

The planet Saturn is the celestial object that, when viewed from Jupiter, cannot transit or pass in front of the Sun. Mercury, Venus, Earth, and Mars are the planets with the smallest orbits, whereas Jupiter is the fifth planet from the Sun. This indicates that occasionally, the orbits of the aforementioned planets pass between Jupiter and the Sun. Saturn, the sixth planet from the Sun, usually travels in an orbit that is greater than Jupiter because of its larger orbit. Saturn's orbit does not intersect Jupiter's orbit and will never be between Jupiter and the Sun, in contrast to Pluto, whose extremely elliptical orbit occasionally places it inside Neptune's orbit.

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Utilizing its metal radius of 186 pm, one sodium atom's volume, or v, is equal to 26965110.857pm3.

Sodium seems to be an element in the periodic table with the atomic number 11 and the symbol Na (derived from the Latin natrium). It is a delicate, silvery-white metal that is exceedingly reactive. Due to its placement in group one of the periodic table, sodium is very much an alkali metal. 23Na is the only stable isotope of it.

Alkali metal subgroup (Group 1 [Indeed is]) of the element element sodium (Na). The element sodium has a very delicate silvery-white.

volume of spherical sodium atoms,

V=4/3 πr³

Here,

volume = V

radius = r

The value of r is 186pm.

= (4/3) × (22/7) × (186pm)³

= (88/21)×6434856pm³

= 26965110.857pm³

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Along either side of such an 80 m wide road, two equal-height poles are positioned in opposition to one another. Angles of height of their tops are 30° and 60° from a point on the route between them. The poles are 20 m and 3 m in height, respectively, and the point is 20 m & 60 m away from the poles.

A scale height, typically represented by the punctuation mark H, is a vertical or radial distance across where a physical quantity drops by the a factor of e this same base for natural or roughly 2.718.

h(t) = -16t2+256t, in which t is time in seconds, yields this same height of the object, h(t). Determine the object's highest point and the moment it touches the ground. The goal of  summertime business plan is to mow lawns.

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Answer:

The work done during the expansion is -608J .

as the details stated in the question

the work done in the expansion from

4 [tex]dm^3[/tex] to 6 [tex]dm^3[/tex] is

work done is the negative of pressure times the change in the volumes of the gases

W = - P [tex]\triangle[/tex] V

where

W is said to be the work done

P is said to be the pressure

Δ V is the change in final and initial volumes of the gases

to calculate the work done

the pressure given is 3 atm

Now ,

W = - (3)x( 6-4)

W = - 3 x (2)

W = -6 L- atm

to convert  atm into joules

-6 x 101.32

=> - 608J

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The complete question is

The work done during the expansion of a gas from a volume of 4 [tex]dm^3[/tex] to 6 [tex]dm^3[/tex] against a constant external pressure of 3 atm is ?

The work done during the expansion of a gas from 4dm³ is -608J.

The work done in the expansion from 4dm³ is -608J. Work done is the negative of pressure times the change in the volumes of the gases

W = - P  V

where

W is the work done

P is the pressure

Δ V is the change in final and initial volumes of the gases

W = - (3)x( 6-4)

W = - 3 x (2)

W = -6 L-atm

In order to convert atmospheric into joules, we multiply

-6 x 101.32 = - 608J.

Work done in case is the force multiplied by distance in the mechanics case. Work done is nothing but the measure of movement or the change of anything with respect to the other measurable quantity. We can just calculate it by the help of physics. like wise we can see the work done in many aspects like in electricity and magnetism, we can find out about work done in cell potential, moving of a charge from one place to another and we can also calculate the work done in many other fields of mechanics like in momentum and energy of any object.

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Answer:

6 types of energy and their transfers are noted:  nuclear, light, chemical synthesis, chemical decomposition, mechanical , potential, and kinetic, along with an explanation.

Explanation:

Each energy transition is noted with a "*#."

1.  Lets start with the solar system's sun.  It is comprised of hydrogen and helium atoms that collide with enough force to join and become different elements.  The nucleus is broken apart and particles rearrange to form a new atom, perhaps berylium.  Some of the energy holding the nucleus together is released in the form of heat and light.  The energy in the nucleus is relesased in a nuclear reaction  *1.

*1  Nucleus of an atom releases energy as heat and light.

----------------

The light from the sun goes all directions.  A portion hits the Earth during the daylight hours.  Life has evolved on Earth to to the point that certain plants and some other organisms can capture the light energy.  Trees are a good example.  The chlorophyll in trees is able to capture the light energy and use it to synthesize compounds such as sugars (photosynthesis).  The energy is used to create the bonds of the elements in a sugar molecule.  *2 The process of photosynthesis makes structural compounds as well as sugars.  The sugars carry the stored chemical energy to other parts of the plant involved with metabolism.  When energy is required, the sugars are metabolized into smaller compounds, releasing the energy from the former chemical bonds.

  *2  Chemical energy contained in chemical bonds

---------

Trees also contain complex polymeric celluloses that are made of of complex molecules with many high-energy bonds.That energy may be released if the wood is burned. *3 A small amount of heat, known as the activation energy (e.g., a match), can cause the bonds to break and release even more heat.  This results in fires, which is the conversion of chemical energy into heat and light.

*3.  Decomposition (sometimes combustion)  is the release of chemical energy as heat and light.

----

The heat from a fire may be used to boil water and make steam.  The ability of steam to create pressure on a piston to create movement is the foundation of the industrial revolution.  This is the conversion of chemical energy to heat and then heat to mechanical motion.  

*4.  Conversion of heat to mechanical motion energy.

Stem engines do many tasks.  One is to raise materials such as structural beams to heights above ground for the construction of building.  The mechanical energy is tranferred into potential energy.  *5 This is the energy contained in an object above Earth's surface.  It can be recovered with the object comes back to Earth, if it were attached to a pulley that is used to lift something.

  *5.  Conversion of Mechanical energy to potential energy

An object above Earth has a potential energy that can be coverted to kinetic energy.  If the object is allowed to drop, the potential energy is conveted into kinetic energy.  *6 Physics and Chemistry have formulas that can precisely predict the speed and trajectory of such objects.  They are based on the value for potential energy being converted to kinetic energy which is the speed of the object.

  *6 Conversion of Potential energy to kinetic energy

Fire (Chemical energy → Heat and Light) Electric lamp (Electrical energy → Heat and Light) Microphone (Sound → Electrical energy) Wave power (Mechanical energy → Electrical energy)

Energy is characterised as having the "ability to accomplish work, which is the capacity to apply a force sufficient to move an object." Despite this unclear definition, the concept is actually quite straightforward energy is just the force that moves objects. Potential and kinetic energy are the two different categories.

It is possible to change the form of energy. Examples Our cars are filled with gasoline (chemical), which, with the aid of electrical energy from a battery, produces mechanical (kinetic) energy. Our TVs are powered by purchased electricity, which is then transformed into light and music.

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4.19 J of heat are transferred to the skin by 25.0 g of water. 2. Because the skin's temperature is unaffected, the total heat transmitted is 4.19 J plus 4.19 J, for a total of 10.39 J.

In general, heat transfer refers to the movement of heat (thermal energy) brought on by temperature differences as well as the following distribution and alterations in temperature. The exchange of momentum, energy, and mass through conduction, convection, and radiation is the focus of the study of transport phenomena.

Conduction: When you hold a hot cup of coffee, heat is transferred into your hands. Convection: When the barista "steams" cold milk to make hot cocoa, heat is transferred. Radiation: Microwave-heating a cold cup of coffee.

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Answer:

Density of water = 1   (1 g / ml)

.25 L = 250 ml   (milleters)

mass of flask = 250 ml * 1 g / ml = 250 g     (water to fill flask)

Equivalent mass of Hg = 13.5 * 250 g = 3375 g = 3.375 kg

The block, because there is no Force of Friction (Ffr) to slow it down.

-Normal Force (Fn) is perpendicular to ramp

- Force of Friction (Ffr) is going up the ramp

- Force of Gravity (Fg=w=mg) is going straight down

Force of Friction (Ffr) because it causes a rotation, therefore making the acceleration different if friction were negligible and it were slipping down the slope.

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The force exerted by the wagon on the girl is 30 N.

The Newton second law of motion states that:

∑F = m . a

Where:

∑F = net force applied on the object

m = mass of the object

a = resulted acceleration

Hence, the object is accelerated if the net force applied on it is not zero.

In the given problem, the object is the 20-kg wagon.

Since the wagon is accelerated at 2 m/s², the net force acted on the wagon is not zero, or the force exerted by the girl on the wagon is not the same as the force exerted by the wagon on the girl.

Let

Fw = force exerted by the wagon on the girl.

∑F = m . a

10 + Fw = 20 x 2

Fw = 40 - 10 = 30 N

Hence,

The force exerted by the wagon on the girl is 30 N

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The ascent of a low-mass main-sequence star to the red giant branch is stopped by the beginning of helium fusion in the core.

The star starts to compress and heat up, just like when a red giant forms. In the shell, helium starts to fuse with carbon. In a shell around the helium, hydrogen fuses. The star expands once again and turns redder as a result of the burning in the shell. The aforementioned image contrasts the various evolutionary routes that low-mass stars, such as the Sun, and high-mass stars take following the red giant phase. After the helium has fused into carbon in low-mass stars (left side), the core again collapses. The star's outer layers are ejected as the core disintegrates.

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The angular resolution of the 100 m Green Bank Telescope when it operates at a wavelength of 20 cm is approximately 1.6 arcseconds.

1. Calculate the telescope's diameter in meters:

100 m

2. Calculate the wavelength in meters:

20 cm = 0.2 m

3. Calculate the resolving power of the telescope:

Resolving power = D / λ

Resolving power = 100 m / 0.2 m

Resolving power = 500

4. Calculate the angular resolution:

Angular resolution = 1 / Resolving power

Angular resolution = 1 / 500

Angular resolution = 0.002 radians

5. Convert the angular resolution to arcseconds:

Angular resolution = 0.002 radians * (180/π) * (3600/1)

6. Calculate the telescope's diameter in meters:

100 m

7. Calculate the wavelength in meters:

20 cm = 0.2 m

8. Calculate the resolving power of the telescope:

Resolving power = D / λ

Resolving power = 100 m / 0.2 m

Resolving power = 500

9. Calculate the angular resolution:

Angular resolution = 1 / Resolving power

Angular resolution = 1 / 500

Angular resolution = 0.002 radians

10. Convert the angular resolution to arcseconds:

Angular resolution = 0.002 radians * (180/π) * (3600/1)

Angular resolution = 1.6 arcseconds

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If air resistance is included, then part b will give higher is speed because the path of the ball in the first part, a is longer so more negative work is done by the air resistance on the ball in part a so. This is the final answer.

Here on Earth, we tend to take air resistance (aka. “drag”) for granted. We just assume that when we throw a ball, launch an aircraft, deorbit a spacecraft, or fire a bullet from a gun, that the act of it traveling through our atmosphere will naturally slow it down. But what is the reason for this. Just how is air able to slow an object down, whether it is in free-fall or in flight.

Because of our reliance on air travel, our enthusiasm for space exploration, and our love of sports and making things airborne (including ourselves), understanding air resistance is key to understanding physics, and an integral part of many scientific disciplines. As part of the subdiscipline known as fluid dynamics, it applies to fields of aerodynamics, hydrodynamics, astrophysics, and nuclear physics (to name a few).

By definition, air resistance describes the forces that are in opposition to the relative motion of an object as it passes through the air. These drag forces act opposite to the oncoming flow velocity, thus slowing the object down. Unlike other resistance forces, drag depends directly on velocity, since it is the component of the net aerodynamic force acting opposite to the direction of the movement.

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In general, the higher the initial speed of the car and the lower the slope, the farther the car will be able to coast up, but it is impossible to give a definitive answer without variables such as the slope and mass of the car.

If the work done by friction is negligible and the car is coasting with the engine disengaged, then the only force acting on the car will be gravity. This means that the car will slow down as it goes up the hill due to the force of gravity acting against its motion. The height of the hill that the car can coast up will depend on the slope of the hill and the mass of the car, as well as the initial speed of the car and the coefficient of rolling resistance. However, it is difficult to give a precise answer without knowing the specific values of these variables.

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(a) The speed at the bottom of the hill is 11.53 m/s.

(b) The maximum vertical height to which the box will rise on the opposite hill is 6.78 m.

The speed of the box at the bottom of the hill is calculated by applying the following kinematic equation as shown below.

v² = u² + 2gh

where;

v² = ( 9.87² ) + 2( 9.8 )( 1.81 )

v² = 132.89

v = √ ( 132.89 )

v = 11.53 m/s

The maximum vertical height to which the box will rise on the opposite hill is calculated by applying the principle of conservation of energy.

mgh = ¹/₂mv²

h = ( v² ) / ( 2g )

h = ( 11.53² ) / ( 2 x 9.8 )

h = 6.78 m

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Answer:

Explanation:

F = ma = (2 kg)(9.8 m/s²) = 19.6 N

a = F/m = 25 N / 2 kg = 12.5 m/s²

One year is about 3.16 x 10^7 seconds while one day is exactly 86,400 seconds.

In one hour, there are 60 minutes and in each minute, there are 60 seconds. While in one day there are 24 hours.

So

60 . 60 . 24 =  86, 400

giving 86, 400  seconds in a day.

In one year there exist 365 days.

Now multiply the number of days by the number of seconds of each day.

So,

86,400.  365  =  31,563,000 =  3.16 x 10^7 seconds

giving 3.16 x 10^7 seconds in a year.

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An O-star has a hotter surface temperature than the Sun, so compared to the Sun, its emission peaks in the blue part of the spectrum.

An O-star is a hot, blue star of spectral type O in the Yerkes classification system. O-stars have temperatures of over 30,000 kelvin. They have strong lines of other ionized elements, strong absorption lines of ioniszed helium, and hydrogen and neutral helium lines that are weaker than spectral type B.

O-stars are very rare, but they can be seen at great distances because they are very bright. Because of their high mass, O-stars end their lives rather quickly in violent supernova explosions, which results in neutron stars or black holes.

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Following the collision, the two carts' combined momentum is zero in magnitude.

Momentum can be defined as the force behind a body's motion. Momentum is measured by "mass velocity" since it depends on both the airspeed or the orientations of the body's motion. Energy is the result since work rate is a vector if mass is a scalar.

Momentum serves as the connection among a direction of motion, momentum, and direction. The result of any momentum change is force. Therefore, a difference in momentum is used to compute the force applying on the item.

Momentum of ball 1:

p1 = mv

=(2.0 kg) + (4.0 m/s)

= + 8.0kgm/s

Momentum of ball 2:

p2 = mv

= (1.0 kg) (-8.0" " m/s)

= - 8.0kgm/s

total momentum,

p = p1 + p2

=+8.0kgm/s + (-8.0kgm/s)

P =0

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An atom in the ground state that requires the least amount of energy to remove its most loosely held electron is Bi (Bismuth).

Bismuth atom has 83 electrons and the shell structure is as 2.8.18.32.18.5.  An atom in which total energy of the electrons can not be lowered by transferring one or more electrons to different orbitals is called as ground-state atom. We can say that, in this case all electrons are in the lowest possible energy levels.

Ground state electron configuration of ground state gaseous neutral Bismuth is as shown here : [Xe].4f^14.5d^10.6s^2.6p^3.

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