Answer:
it is of brainlee
I'd and also a password
I want to save it because my phone battery is low so don't delete my answer
Sound waves move the fastest through which medium?
water at high temperatures
water at low temperatures
air at high temperatures
air at low temperatures
Answer:
Water at high temperatures
Explanation:
When heated, molecules move faster which results in the sound waves being transmitted faster.
Also sound waves travel fastest in solids. Fast in liquids, and slowest in the air.
Answer:
Sound waves will move faster in water at high temperature.
Explanation:
Sound waves are longitudinal waves.These waves travel in bilk medium.The speed of sound increases with the increase in temperature.Speed of sound increases by 4.57 meter for every 1.5 degree Fahrenheit rise in temperature.What is longitudinal wave?The waves in which particles of the medium vibrate in the direction of propagation, is called longitudinal wave.
Hence sound waves will move faster in the water at high temperature.
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To make them gas, you have to give liquids yes or no?
Answer:
Yes
Explanation:
16. Explain the following observations:
i. Water wets glass surface but does not wet the waxed glass surface.
Answer:
because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.
Answer:
the adhesive forces between the drops are stronger than cohesive force between the liquid
An industrious beaver manages to chew through the base of a wooden tree trunk 18 m tall, causing it to fall over. If the base of the trunk does not slide while it falls over, how fast is the other end of the trunk moving right before it hits the ground
Answer:
Vf = 18.78 m/s
Explanation:
As, the block does not trunk does not slide while falling. hence, we can use third equation of motion to find its velocity before it hits the ground:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = Height of Trunk = 18 m
Vf = Velocity of trunk just before it hits the ground = ?
Vi = Initial Velocity of the trunk = 0 m/s
Therefore, using these values in the equation, we get:
(2)(9.8 m/s²)(18 m) = Vf² - (0 m/s)²
Vf = √(352.8 m²/s²)
Vf = 18.78 m/s
Ganymede is a moon of Jupiter (mass = 1.90 x 1027 kg). It orbits Jupiter in a circle of radius 1.07 x 109 m. What is Ganymede's period in hours)?
Answer:
T = 171.59 hours
Explanation:
Mass of Ganymede, [tex]M=1.9\times 10^{27}\ kg[/tex]
Radius of the orbit, [tex]R=1.07\times 10^9\ m[/tex]
We need to find Ganymede's period. Let time is T. Using Kepler's third law of motion.
[tex]T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.9\times 10^{27}}\times (1.07\times 10^9)^3\\\\T=617754.35\ s[/tex]
or
T = 171.59 hours
Hence, Ganymede's period is 171.59 hours.
A motorcycle moves from rest and accelerates uniformly on a straight road, reaching a speed of 25 ms in 20 s and then moves at a constant speed of 25 ms1 for a distance of 300 m. Determine the total displacement for the entire trip.
Answer:total displacement is 550m.
Explanation:
A thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with the horizontal. How long does it take it to travel the first 3.1 m?A) 1.4 sB) 1.1 sC) 2.1 sD) 1.6 sE) 1.8 s
Answer:
B ( 1.1 s )
Explanation:
Given that a thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with the horizontal.
Let the height = h
Sin 30 = h / 3.1
h = 3.1 Sin 30
The P.E at the top = mgh
P.E = 9.8 × 3.1 Sin 30 × m
P.E = 15.19m
The K.E = P.E
K.E = 1/2mv^2
1/2 × V^2 × m = 15.19m
The mass m will cancel out.
V^2 = 30.38
V = 5.51 m/s
Using third equation of motion to find acceleration
V^2 = U^2 + 2as
Since it starts from rest, initial velocity u = 0
30.38 = 2 × 3.1 × a
30.38 = 6.2a
a = 30.38 / 6.2
a = 4.9 m/s^2
Using equation one of linear motion to calculate time t
V = U + at
5.51 = 4.9t
t = 5.51 / 4.9
t = 1.12 s
Therefore, it will take approximately 1.1 s to travel the first 3.1 m
The correct option is B
What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor
Complete Question
A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?
Answer:
The magnetic field is [tex]B = 6.4*10^{-4} \ T[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 8.0 \ A[/tex]
The diameter is [tex]d = \ cm = \frac{1}{100} = 0.01 m[/tex]
The position considered is [tex]d = 2.5 \ mm = 0.0025 \ m[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{\mu_o * I }{ 2 \pi d}[/tex]
Here [tex]\mu_o[/tex] is permeability of free space with value
[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }[/tex]
=> [tex]B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }[/tex]
=> [tex]B = 6.4*10^{-4} \ T[/tex]
A motor exerts a 280 N force and does 1220 J
of work while lifting a box. How far did the
motor lift the box?
We know that:
Work = Force × DistanceSolving for Distance:
Distance = Work / ForceDistance = 1220 J / 280 N Distance = 4.36 mThe coldest and hottest temperatures ever recorded in Switzerland are −43.2°F (231 K) and 106.7°F (315 K), respectively. What is the speed of sound in air at each temperature?
Answer:
v₂₃₁ = 304.4 m/s
v₃₅₁ = 355.5 m/s
Explanation:
The formula used to find the speed of sound in air, at different temperatures is given as follows:
v = v₀ √(T/273)
where,
v = speed of sound at given temperature
v₀ = speed of sound at 0°C = 331 m/s
T = temperature in K
For T = 231 K:
v₂₃₁ = (331 m/s)√(231 K/273 K)
v₂₃₁ = 304.4 m/s
For T = 315 K:
v₃₅₁ = (331 m/s)√(315 K/273 K)
v₃₅₁ = 355.5 m/s
Which of the remaining designs has the highest thermal efficiency? Which of the remaining designs has the highest thermal efficiency?
Answer:
DEVICE E
Explanation:
From my house to the store it takes 1 mile. The average a man can walk in a day is 3.1 miles. So why has it taken my dad 19 years to come back home with the milk?
Type your essay here.
Answer:
my essay
i typed my my essay like u said
The weight of a person can be represented by a vector that acts...
Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffrey is experiencing psychomotor________
Answer:
R.E.T.A.R.D.A.T.I.O.N
Explanation:
It won't let me spell it normal
Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all then it means that he is experiencing R.E.T.A.R.D.A.T.I.O.N .
What is acceleration?The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
R.E.T.A.R.D.A.T.I.O.N is the process of inhibiting something's growth. However, negative acceleration has a very different meaning in physics. The negative acceleration is just the opposite of acceleration. A shift in speed is meant by the phrase "acceleration." In general, acceleration signifies an increase in velocity; while, acceleration in the opposite denotes a reduction in velocity.
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What part of the atom is the arrow pointing to?
electron
electron shell
nucleus
proton
Answer:
electron shell
Explanation:
the proton and nucleus are inside the electron shell so the arrow is point on the outer shell which is the electron shell.
A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?
Answer:
The distance is [tex]R = 79.5 \ m[/tex]
Explanation:
From the question we are told that
The angle at which the ball is thrown is [tex]\theta = 60^o[/tex]
The initial speed is [tex]u = 30 \ m/s[/tex]
Generally the distance from the original position which the ball covered is mathematically evaluated as
[tex]R = \frac{ u^2 * sin 2\theta }{g}[/tex]
=> [tex]R = \frac{ 30^2 * sin (2* 60)}{9.8}[/tex]
=> [tex]R = 79.5 \ m[/tex]
Which type of change is freezing water an example of?
Answer:
For example, a physical change does not result in the formation of new substances. Physical changes alter only the size, shape, form or matter state of a material. Water boiling, melting ice, tearing paper, freezing water and crushing a can are all examples of physical changes.
Explanation:
Which combination of a wire coil and a core would make the strongest
electromagnet?
A. 200 coils of bare wire around a hollow cardboard core
B. 200 coils of insulated wire around a steel bolt
C. 50 coils of insulated wire around a hollow cardboard core
D. 50 coils of bare wire around a steel bolt
Answer:B
Explanation:Just took it.
200 coils of insulated wire around a steel bolt is the strongest electromagnet among them. Hence, option (A) is correct.
What is electromagnet?A wire coil is used to build electromagnets (wire curled in series). In comparison to a straight wire, this is more efficient in creating a magnetic field. A powerful magnetic core consisting of a magnetic substance, such as iron, can be tightly wound around a wire to enhance this effect.
In electromagnet, the core serves a great role in creating magnetic field. The core of ferromagnetic materials is far efficiency compared to hollow cardboard core. And the more number of turns means more amount of current passes through it and the strength of the electromagnet is more. That is why, 200 coils of insulated wire around a steel bolt is the strongest electromagnet among them.
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Two carts with masses 10.0kg and 2.5 kg move in opposite directions on a frictionless horizontal track with speeds of 6.0m/s and 3.0 m/a respectively. The carts stick together after colliding head on. Find the final speed.
Please help!!
Answer:
4.2
Explanation:
A teacher bangs his ruler on his desk with a force of 15 N breaking it into pieces. If the ruler has a mass of 0.25 kg, how much force did the desk apply back to the ruler when it broke into pieces?
Answer:
Well, this teacher is pretty dumb if you ask me.
Explanation:
5 N, i think this is right.
when a car is heated , say by taking it to a desert, it expands. Is the increase in length of the car greater than, less than, or equal to its increase in height?
Answer:
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion
Explanation:
This is an exercise in thermal expansion, which is described by the expression for one dimension
ΔL = α L₀ ΔT
For the analysis of this exercise we will assume that the sides are independent
Let's look for the condition of the length of the car
ΔL / L₀ = α ΔT
The height delay (h) is
Δh / h₀ = α ΔT
we can match the two expressions
ΔL / L₀ = Δh / h₀
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion
Describe a screw.
Pleaseeeeee
Explanation:
Short, Made with medal, and screws into places to hold things together.
Hope This Helps!!!
screws are one kind kd simple machine. They have a corkscrew-shaped ridge, know as a thread, wrapping around a cylinder. The head is specially shaped to allow a screwdriver or wrench to grip the screw driving it in.
What is the orbital velocity in km/s and period in hours of a ring particle at the outer edge of Saturn's A ring
Answer:
The orbital velocity [tex]v = 16.4 \ km/s[/tex]
The period is [tex]T = 14.8 \ hours[/tex]
Explanation:
Generally centripetal force acting ring particle is equal to the gravitational force between the ring particle and the planet , this is mathematically represented as
[tex]\frac{GM_s * m }{r^2 } = m w^2 r[/tex]
=> [tex]w = \sqrt{ \frac{GM}{r^3} }[/tex]
Here G is the gravitational constant with value [tex]G = 6.67*10^{-11}[/tex]
[tex]M_s[/tex] is the mass of with value [tex]M_s =5.683*10^{26} \ kg[/tex]
r is the is distance from the center of the to the outer edge of the A ring
i.e r = R + D
Here R is the radius of the planet with value [tex]R = 60300 \ km[/tex]
D is the distance from the equator to the outer edge of the A ring with value [tex]D = 80000 \ kg[/tex]
So
[tex]r =80000 + 60300[/tex]
=> [tex]r =140300 \ km = 1.4*10^{8} \ m[/tex]
So
=> [tex]w = \sqrt{ \frac{ 6.67*10^{-11}* 5.683*10^{26}}{[1.4*10^{8}]^3} }[/tex]
=> [tex]w = 1.175*10^{-4} \ rad/s[/tex]
Generally the orbital velocity is mathematically represented as
[tex]v = w * r[/tex]
=> [tex]v = 1.175*10^{-4} * 1.4*10^{8}[/tex]
=> [tex]v = 1.64*10^{4} \ m /s = 16.4 \ km/s[/tex]
Generally the period is mathematically represented as
[tex]T = \frac{2 \pi }{w }[/tex]
=> [tex]T = \frac{2 * 3.142 }{ 1.175 *10^{-4} }[/tex]
=> [tex]T = 53473 \ second = 14.8 \ hours[/tex]
Answer:
The orbital velocity [tex]v = 16.4 \ km/s[/tex]
The period is [tex]T = 14.8 \ hours[/tex]
Explanation:
Generally centripetal force acting ring particle is equal to the gravitational force between the ring particle and the , this is mathematically represented as
[tex]\frac{GM_s * m }{r^2 } = m w^2 r[/tex]
Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. how strong was his push off the ground?
Answer:
734.16 kg m/[tex]s^{2}[/tex]
Explanation:
The problem is asking for the Force of pushing off the ground.
The formula of Force is: F = mass x accelerationGiven = Mass: 600 newtons (N)
Acceleration: 12 m/[tex]s^{2}[/tex]
We have to convert the mass into kg first. Remember that 1 kg is equal to 9.80665 newtons.
Let x be the mass in newtons.
Let's convert: [tex]\frac{1 kg}{9.80665 N}[/tex] x [tex]\frac{x}{600 N}[/tex] = [tex]\frac{600}{9.80665}[/tex] = 61.18 kg
Phil's weight is 61.18 kg
Let's go back to finding the force.
F = m x a
F = 61.18 kg x 12 m/[tex]s^{2}[/tex]
F = 734.16 kg m/[tex]s^{2}[/tex]
A train is traveling away from you at 120 km/h. It blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound to be 340 m/s. What frequency does the whistle actually produce
Answer:
The actual frequency produced by the train whistle is 444 Hz.
Explanation:
Given;
speed of the train, Vs = 120 km/h = 33.33 m/s
observed frequency, Fo = 0.4 kHz = 400 Hz
speed of sound in air, V = 340 m/s
Note: as the train moves away, the observed frequency will be smaller than the source frequency. Thus, the source frequency which is frequency of the train whistle will be greater than 400 Hz.
The source frequency is given by Doppler effect formula;
[tex]F_s = F_o [\frac{V}{V-V_s} ]\\\\F_s = 400[\frac{340}{340-33.33} ]\\\\F_s = 400(1.109)\\\\F_s = 443.6 \ Hz[/tex]
Fs = 444 Hz
Therefore, the actual frequency produced by the train whistle is 444 Hz.
A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is low, the penny rides up and down without difficulty. If the frequency is steadily increased, there comes a point at which the penny leaves the surface. Part A At what point in the cycle does the penny first lose contact with the piston
Answer:
in the downward movement of the movement when the constant is lost
Explanation:
When the coin is on the piston it has a relationship given by
a = d²x / dt²
the piston position is
x = A cos wt
a = - A w² cos wt
the maximum acceleration is
a = - A w²
When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.
The point where you lose contact is
a = g
g = A w²
In short, in the downward movement of the movement when the constant is lost
what are the conditions under which the resultant of three coplanar forces is zero?
A force of magnitude 26 N stretches a spring .73 m from equilibrium. what is the value of the spring constant?
Answer:
third trust eh if not then here a cookie for my forgivness
Explanation:
A student measures the stiffness of a spring by observing how far it stretches with different masses hanging from it. She tries six different masses: 10, 20, 30, 40, 50, 60 grams; and she finds that the spring stretches: 3.1, 6.5, 10.2, 11.1, 16.2, 18.5 centimeters.
a. Based on these observations, what is the best estimate for the spring constant of this spring?
b. With the 60 gram mass attached, the student observes an oscillatory period of 0.886±0.003 seconds. Explain whether this observation is consistent with your answer from part (a).
Answer:
a) k = 3.2 N / m
b) T = 0.27 s
some problem measuring the time of the oscillation.
Explanation:
a) With the student's observations we can make a graph of elongation against applied weight, see attached, with this graph, Hooke's law must comply
F = -k x
where force is the applied weight
F = W = mg
substituting
W = k x
x = 1 / k W (1)
the linear regression of the graph gives
x = 31.2 w + 0.23
the slope of the graph is
m = 31.2 cm/N
if we relate this value with equation 1
1 / k = 131.2
k = 0.032 N / cm
Let's reduce to the SI system
k = 0.032 N / cm (100cm / 1m)
k = 3.2 N / m
This is the best value we can obtain from the spring constant with these experiential data
b) When the student oscillates the system, he has a simple harmonic motion whose angular velocity is
w =[tex]\sqrt\frac{k}{m} {}[/tex]
for the masses of m = 60 gr = 60 10-3 kg = 0.060 kg
w = √ (3.2 / 0.060)
w = 22.82 rad/s
angular velocity is related to frequency and period
w = 2π f = 2π / T
T = 2π / w
T = 2π / 22.82
T = 0.27 s
A great discrepancy is observed between the theoretical value and the experimental value, it is not common erorr so high it can be due to some problem measuring the time of the oscillation.
