Answers
To write the numbers with the specific number of significant figures, we need to remember that zeros to the left don't count as a significant figure and also that we can add zeros to the right to add significant figures to the numbers.
1) 1.5408 to 3 significant figures, we start counting from left to right, so we will maintain the numbers until the second decimal place, the "8". Since the next is "0", the rounding is "8", so the number is 1.54.
2) Here is similar, but since we don't have decimal places, we need to put the zeros in place of the numbers we are rounding. Since we want 2 significant figures, we will maintain only the first two. However, since the third is greater than 5, we need to round up, so the number is 4400.
3) To get this, we will maintain the zeros to the elft, but they don't count, so we start counting from the "1". Since the third number is less than 5, we round down, so the number is 0.019.
4) Now, here we have an example we need to add zeros. The way it is, 0.5 has only 1 significant figure, so we need to add 3 more zeros to the right to get to 4 significant figures. The number is 0.5000.
5) Here, is the same as item 3, but we want 3 significant figures and since the fourth is greater than 5 we round it up. So, the number is 0.066.
Related Questions
Use the balanced equation to solve the problem.Na₂CO3 +CaCl2 → 2NaCl + CaCO3115g of CaCl₂ react.How many moles of NaCl are made?mol
Answers
2.0724moles
Explanations:Given the balanced chemical reaction between Na2CO3 and CaCl2 expressed as:
[tex]Na_2CO_3+CaCl_2\rightarrow2NaCl+CaCO_3[/tex]Given the following parameters
Mass of CaCl₂ = 115g
Determine the moles of CaCl₂
[tex]\begin{gathered} moles\text{ of CaCl}_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CaCl}_2=\frac{115}{110.98} \\ moles\text{ of CaCl}_2=1.0362moles \end{gathered}[/tex]According to stochiometry, 1 mole of CaCl2 prodcues 2 moles of NaCl. The moles of NaCl requred is given as:
[tex]\begin{gathered} moles\text{ of NaCl}=2\times1.0362 \\ moles\text{ of NaCl}=2.0724moles \end{gathered}[/tex]Therefore moles of NaCl made is 2.0724moles
Find the molecular formula for a compound that contains 4.90 % N and 11.2 % O. The molecular mass of the compound is 92.0 g/mol.
Answers
The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄
How to determine molecular formulaWe'll begin by obtaining the empirical formula for the compound. This is illustrated below:
Nitrogen (N) = 4.90 gOxygen (O) = 11.2 gEmpirical formula =?Divide by their molar mass
N = 4.9 / 14 = 0.35
O = 11.2 / 16 = 0.7
Divide by the smallest
N = 0.35 / 0.35 = 1
O = 0.7 / 0.35 = 2
Thus, the empirical formula of the compound is NO₂
Finally, we shall determine the molecula formula. Details below
Molar mass of compound = 92 g/molEmpirical formula = NO₂Molecular formula =?Molecular formula = empirical × n = molar mass
[NO₂]ₙ = 92
[14 + (16×2)]ₙ = 92
46n = 92
Divide both side by 46
n = 92 / 46
n = 2
Molecular formula = [NO₂]ₙ
Molecular formula = [NO₂]₂
Molecular formula = N₂O₄
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Complete question:
Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.
Read each question carefully and choose the letter of the best answer.
Answers
This element is nonmetal and appears in the periodic table.
The number that represents the position of the elements is called, the atomic number, it also represents the number of protons = numbers of electrons an atom has.
Answer: D. the atomic number
I dont understand how to find the one with smallest atomic radiusa. Calciumb. Cobaltc. potassiumd NickelI think its last one but why
Answers
Answer:
d. Nickel
Explanation:
The atomic radius is a periodic property, that is, we can see how it varies in the Periodic Table of Elements.
Atomic radius increases by a column (group) from top to bottom, and increases by a row (period) from right to left.
We can see the variation of atomic radius and the location of the given atoms in the following drawing:
Since K (potassium), Ca (calcium), Co (cobalt) and Ni (nickel) are located in the same row (period), to identify which one has the smallest atomic radius, we have to analyze the increase in horizontal atomic radius.
So, the Ni atom has the smallest atomic radius (because it is located more to the right compared to the other atoms in the same row) and K atom has the largest atomic radius.
Isopropyl alcohol is mixed with water to produce 32.0% (v/v) alcohol solution.How many milliliters of each component are present in 655 mL of this solution? Assume the volumes are additive.Alcohol: _____________ mL Water: __________ mL
Answers
Isopropyl alcohol + water = Solution
Solute = Isopropyl alcohol
Solvent = water
% V/V = mL of solute / 100 ml of solution
Now we have 655 mL of solution.
32.0 % V/V means 32 mL of Isopropyl alcohol dissolved in 100 mL of solution.
So,
32 mL Isopropyl alcohol ------------------- 100 mL Solution
x ------------------- 655 mL Solution
x represents the volume of Isopropyl alcohol in 655 mL of solution
[tex]x\text{ = }\frac{655\text{ mL solution x 32 mL }Isopropylalcohol\text{ }}{100\text{ mL solution}}=\text{ 209.6 mL of }Isopropylalcohol[/tex]Now
Alcohol: 209.6 mL
Water: 655 mL (solution = Alcohol + Water) - 209.6 mL (alcohol) = 445.4 mL of water
3. 135 g of ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water = 334 J/g. Specific heat of water = 4.184 J/g °C. T2-T1 = 47.3 °C.Note there are a couple different ways to solve this problems to sove this por(a) Determine the initial volume of water in the beaker (before the ice was added).(b) Determine the final volume of water in the beaker (after all the ice has melted).
Answers
Answer:
Explanation:
Answer to the 1st one. I have my doubts for the second one so didn't post :)
17. Which of the following represents a formula for a chemical compound?A. CB. KOHC. O
Answers
KOH. Option B is correct
Explanations:A chemical compound are made up of more than one element combined together. According to the question, we need to determine the formula that represents a compound.
The compound there is KOH since it contains three elements (Potassium, Oxygen and Hydrogen)
During the chlorination of silicon, chlorine gas is reacted with solid silicon to form silicon tetrachloride.Si(s) + 2Cl2(g) + heat - SiC|4(g)Which will not cause the reaction to shift towards the products?A) adding a catalystB) increasing the pressureC increasing the temperatureD) increasing the concentration of CL2(g)
Answers
Let's analyze each option to find what best fit as an answer:
A - the function of a catalyst is to lower the energy of activation in a reaction, causing it to occur in a faster way. Since this question is not much about energy or kinetics, this would be the best fit, adding a catalyst or not adding it would not be too influential in the shift of the reaction.
B - Increasing the pressure in a reaction containing gases will mostly favor the side with a lower value of moles, smaller amount of moles = less pressure, so if we add more pressure, the reaction will shift towards the side of the products
C - If we treat heat as a reactant, if we add more temperature, it will shift towards the products, to counteract this increase of temperature
D - Adding reactants will favor the reaction to shift towards the products
Therefore the answer is letter A
The designations for the first four electron energy sublevels with the maximum number of electrons that can be accommodated in each sublevel ares:2, p:6, d:10, and f:14s:2, p:8, d:10, and f:14s:1, p:2, d:3, and f:4s:2, p:8, d:18, and f:32
Answers
So,
The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max.
Therefore, the correct answer is:
s:2, p:6, d:10, and f:14
In a lab experiment, 7.97 g of phosphorus reacts with bromine to form 69.65 g of phosphorus tribromide. How much phosphorus tribromide would be formed if 12.05 g of phosphorus reacted with 61.68 g of bromine? answer:______gi put what i got in the image and it is wrong sorry
Answers
1) List the known and unknown quantities.
First experiment:
Reactants
Phosphorus: 7.97 g.
Bromine: excess.
Product
Phosphorus tribromide: 69.65 g.
Second experiment
Reactants
Phosphorus: 12.05 g.
Bromine: 61.68 g.
Product
Phosphorus tribromide: unknown.
2) Write and balance the chemical equation.
[tex]2P+3Br_2\rightarrow2PBr_3[/tex]3) Convert the masses.
3.1-Convert the mass of P to moles of P.
The molar mass of P is 30.97 g/mol.
[tex]mol\text{ }P=12.05\text{ }g\text{ }P*\frac{1\text{ }mol\text{ }P}{30.97\text{ }g\text{ }P}=0.38909\text{ }mol\text{ }P[/tex]3.2-Convert the mass of Br to moles of Br.
The molar mass of Br2 is 159.8080 g/mol.
[tex]mol\text{ }Br_2=61.68\text{ }g\text{ }Br_2*\frac{1\text{ }mol\text{ }Br_2}{159.8080\text{ }g\text{ }Br_2}=0.38596\text{ }mol\text{ }Br_2[/tex]4) Which is the limiting reactant?
4.1-How many moles of Br2 do we need to use all of the P?
The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.
[tex]mol\text{ }Br_2=0.38909\text{ }mol\text{ }P*\frac{3\text{ }mol\text{ }Br_2}{2\text{ }mol\text{ }P}=0.583635\text{ }mol\text{ }Br_2[/tex]We need 0.583635 mol Br2 and we have 0.38596 mol Br2. We do not have enough Br2. This is the limiting reactant.
4.2-How many moles of P do we need to use all of the Br2?
The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.
[tex]mol\text{ }P=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }P}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }P[/tex]We need 0.25731 mol P and we have 0.38909 mol P. We have enough P. This is the excess reactant.
5) Moles of phosphorus tribromide produced from the limiting reactant.
Limiting reactant: 0.38596 mol Br2.
The molar ratio between Br2 and PBr3 is 3 mol Br2: 2 mol PBr2.
[tex]mol\text{ }PBr_2=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }PBr_3}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }PBr_3[/tex]6) Conver the moles of Pbr3 to mass of PBr3.
The molar mass of PBr3 is 270.6858 g/mol.
[tex]g\text{ }PBr_3=0.25731\text{ }PBr_3*\frac{270.6858\text{ }g\text{ }PBr_3}{1\text{ }mol\text{ }PBr_3}=69.6502\text{ }g\text{ }PBr_3[/tex]The mass of PBr3 produced in the reaction is 69.65 g PBr3.
.
The following lists consists of ionic compounds EXCEPT
barium hydroxide, zinc carbonate, ammonium sulfate
calcium chloride, carbon disulfide, magnesium nitrate
sodium sulfate, copper(II) oxide, potassium nitride
aluminium sulfide, sodium sulfite, calcium fluoride
Answers
Except for NACLE, the is made up of ionic compounds. Carbon disulfide bonds are not ionic due to their weak and trivial polarity. Carbon disulfide bonds are covalent due to the small difference in electronegativities of carbon and sulfur.
What makes an ionic bond?Ionic bond, also known as electrovalent bond, is a type of linkage formed in a chemical compound by the electrostatic attraction of oppositely charged ions. When the valence (outermost) electrons of one atom are permanently transferred to another, a bond is formed.After two or more atoms lose or gain electrons to form an ion, an ionic bond can form. Ionic bonds form when metals lose electrons and nonmetals gain electrons. Ions with opposite charges attract each other, forming an ionic bond.To learn more about Ionic Bond, refer to:
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The chemical reaction of hydrogen with oxygen produces water.
2H₂(g) + O₂(g) → 2H₂0 (g)
a. How many moles of O₂ are required to react with 2.6 moles of H₂?
b. How many moles of H₂ are needed to react with 5.0 moles of O₂?
Answers
Answer: a
explanation: Make a ratio of the number of moles and do the calculations. Do you get it?
A 45 mL sample of calcium chloride stock solution produces a 0.182 M diluted solution by adding 50. mL of water. What is the molarity of the stock solution?
Answers
A solution of Calcium Chloride was made, we are asked to find the concentration of the initial solution.
We will apply the following equation to find it:
[tex]C_1V_1=C_2V_2[/tex]Where,
C1 is the initial concentration we have to find
V1 is the initial volume, 45mL
C2 is the final concentration, 0.182M
V2 is the final volume, 50. mL
We clear C1 and replace the known data;
[tex]C_1=\frac{C_2V_2}{V_1}[/tex][tex]\begin{gathered} C_1=\frac{0.182M\times50.mL}{45mL} \\ C_1=0.202M \end{gathered}[/tex]The molarity of the stock solution is 0.202M
Answer: 0.202M
Which process is not reversible?Dissolving sugar in water Burning butane in a candle lighterMelting waxExtracting iron metal from iron (III) oxide
Answers
Answer
The process that is NOT reversible is Burning butane in a candle lighter
Explanation
All other processes can be reversed
What makes water a polar molecule? options:A) The equal forces between oxygen and hydrogenB) The liquid nature of waterC) The uneven bend in the bond between oxygen and hydrogenD) The ionic bond between oxygen and hydrogen
Answers
The polarity of a molecule is given by the difference in charges, hydrogen has a slightly positive charge and oxygen has a negative charge. Its electronegativity difference between hydrogen and oxygen is less than 1.7 making the bond a covalent bond.
That said, we can rule out options A and D. Now, the state of matter does not affect the polarity of the molecule, so option B will also be incorrect.
The correct option will be C, since there is a difference in charges that makes water polar.
Answer: C) The uneven bend in the bond between oxygen and hydrogen
3. A 5.00 mole sample of oxygen gas has a pressure of 1.25 atm at 22℃. What is the volume of the gas?
Answers
The volume of a gas that has a pressure of 1.25 atm at 22℃ is 96.88L.
How to calculate volume?The volume of a gas can be calculated by using the following formula:
PV = nRT
Where;
P = pressure of the gas V = volume of the gasn = number of moles of the gasT = temperatureR = gas law constantAccording to this question, 5.00 mole sample of oxygen gas has a pressure of 1.25 atm at 22℃. The volume can be calculated as follows:
1.25 × V = 5 × 0.0821 × 295
1.25V = 121.0975
V = 96.88L
Therefore, 96.88L is the volume of the gas
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How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.
Answers
10.7 grams
Explanations:The formula for calculating the molarity of a solution is given as:
[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]Given the following parameters
molarity of NaOH = 1.11M
volume of solution = 241.0mL = 0.241L
Find the moles of NaOH
[tex]\begin{gathered} moles\text{ of Na}OH=\frac{1.11mol}{L}\times0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}[/tex]Determine the mass of solute (NaOH)
[tex]\begin{gathered} Mass\text{ of NaOH}=mole\times molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675\times40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}[/tex]Hence the grams of solute that would be used to prepare the solution is 10.7grams
predict the product of this combination reaction. Include thephysical state of the product and balance the reaction. Hint: You have aluminumand sulfide ions in your product. What are the charges of those ions? How wouldyou write the formula so that the charges cancel?
Answers
We are asked to predict a reaction having two solids as reactants. The reaction occurs in the solid phase. Initially the elements are in their natural state, so they will have an oxidation state equal to 0.
This is a combination reaction, so the product will be a combination of aluminum and sulfur.
When combined, aluminum has an oxidation state of +3, this means that it gives up its electrons. Sulfur has an oxidation state of -2. The resulting product will be aluminum sulfide (Al2O3). so, the reaction will be:
[tex]Al_{(s)}+S_{8(s)}\rightarrow Al_2^{+3}S_3^{-2}[/tex]We must balance the equation.
Let's start with sulfur. We multiply each sulfur-containing molecule by its opposite. In other words, we multiply the S8 molecule by 3 and we multiply the S3 molecule by 8.
And to balance the aluminum we must multiply the aluminum molecule by 16. So, the balanced equation will be:
[tex]16Al_{(s)}+3S_{8(s)}\rightarrow8Al_2^{+3}S_{3(s)}^2[/tex]So, the answer, in summary, will be:
We obtain a product with the formula Al2O3. Al is an ion with a charge of +3, and S is an ion with a charge of -2.
4) Mixtures of He and oxygen are used in scuba diving to help prevent “TheBends". For a particular dive the total pressure in the tank is 15 atm. If thepartial pressure of oxygen is 6.0 atm, what is the partial pressure of He ?A
Answers
By following Daltons laws of partial pressure .
" the pressure that eachgaswould have exerted ,Add up to the total pressure" .
• Therefore :
,• Total Pressure = P.Pressure (oxygen) + P.Pressure of (He)
15 atm = 6atm + Pressure of He
P.Pressure ofHe = 15atm-6atm
= 9 atm
This means that the partial pressure of He = 9atm +
General nucleus and electron attraction explained
Answers
General nucleus and electron attraction explained
We can say this:
The net positive charge from the nucleus (remember that protons are in the nucleus) that an electron can feel attraction from, is the effective nuclear charge. The core electrons (electrons are on shells around the nucleus) are said to shield the valence electrons from the full attractive forces of the pro
Write formulas or names as appropriate for each of the following hydrates. 1. Magnesium sulfate heptahydrate 6. CoSO4•H2O 2. Copper(I) sulfate pentahydrate 7. Na2CrO4•4H2O 3. Potassium phosphate decahydrate 8. CuF2•2H2O 4. Calcium chloride hexahydrate 9. Sr(NO3)2•6H2O 5. Iron(III) nitrate nonahydrate 10. ZnSO4•7H2O
Answers
Answer:
Explanation:
Here, we want to give the names or formulas of the given hydrates
1) Magnesium sulfate heptahydrate
The first thing we have to do here is write the formula for magnesium sulfate.
Hepta means 7, which is pointing to the fact that there are 7 water molecules
We can have this as:
[tex]\text{MgSO}_4\cdot7H_2O[/tex]6) Here, we can see that the element involved is cobalt with an oxideation number of 2. We also have just one water of crystallization
So, we have the name of the compound as:
[tex]\text{Cobalt (II) Sulphate hydrate}[/tex]5
Select the correct answer from each drop-down menu.
Complete the following statements to describe solids, liquids, and gases. Select the correct answer from each drop-down
A solid
A liquid
Agas
a definite volume and
a definite volume and
V a definite volume and
a definite shape.
a definite shape.
a definite shape.
Reset
Next
Answers
A solid has an identifiable shape and volume. A liquid has a fixed volume and an ill-defined shape. A gas has an undefined shape and a fixed volume.
Which statement regarding solids, liquids, and gases is accurate?A solid is something that has a specific shape and volume. The definition of a liquid is something that has a fixed volume but no fixed shape. A gas is described as something that has neither a fixed shape nor a fixed volume.
What are the solid, liquid, and gas elements' four characteristics?A solid has a distinct volume and shape, a liquid has a distinct volume but no distinct shape, and a gas lacks both.
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calculate the theoretical and % yield of copper when 0.500 g of Cu was used and 0.350 g were recovered at the end of the experiment. complete solution
Answers
The theoretical percentage yield of copper is 70%
This is further explained below.
What is a yield?Generally, the equation for yield is mathematically given as
[tex]yield =\frac{\text { mote no. of product }}{\text { mote no. of reactant }} \times 100$[/tex]
Here, Based on Theoretical Yield
[tex]\begin{aligned} \text { mole rio. of reactant } &=-\frac{0.5}{63.546} \text { mole } \\ \end{aligned}$[/tex]
Based on the Actual yield
mole rio. of Product=0.35/63.546 mole
(Here atomic man of Cu=63.546g/mol )
Therefore, we apply the initially stated equation for %yield
So, %yield =[tex]\frac{\frac{0.35}{63.546}}{\frac{0.5}{(63.546}} \times 100 \%$[/tex]
=[tex]\frac{0.35}{0.5} \times 100 \%\\[/tex]
=0.7 *100%
=70%
In conclusion, the percentage yield is 70%
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Which of the following describes a physical property?Corrosiveness of sodiumToxcity of cadmiumWater when heated forms steamFlammability of hydrogen
Answers
Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.
In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.
The correct answer is Water when heated forms steams.
Calculate the percent by volume of 75 mL of concentrated juice if the juice is diluted with 200 mL of water.
Answers
The percent by volume is 27.27%
A gas mixture contains 1.26 g N2 and 0.76 g O2 in a 1.51 L container at 11 C. Calculate the partial pressure of N2?
Answers
When we have a mixture of gases, the pressure exerted by each depends on the number of moles present in the mixture, this contribution is called partial pressure. The sum of the partial pressures will be equal to the total pressure, this is called Dalton's law.
Partial pressure can be described by the following equation:
[tex]P_i=X_iP_T[/tex]Where,
Pi is the partial pressure
Xi is the molar fraction
Pt is the total pressure
The molar fraction is calculated by the following equation:
[tex]X_i=\frac{n_i}{n_T}[/tex]Where,
ni is the number of moles of the substance
nT is the total number of moles.
So, we have to find first the number of moles of each gas. We are given the grams of gases, to get the equivalent moles we must divide the mass by the molar mass.
Molar Mass N2=28.0134g/mol
Molar Mass O2=31.9988g/mol
[tex]\begin{gathered} molN_2=1.26g\times\frac{1molN_2}{28.0134gN_2}=0.045molN_2 \\ molO_2=0.76gO_2\times\frac{1molO_2}{31.9988gO_2}=0.024molO_2 \end{gathered}[/tex]Now, the partial pressure of N2 will be:
[tex]P_{N2}=\frac{0.045molN_2}{0.045molN_2+0.024molO_2}\times P_T[/tex][tex]P_{N2}=\frac{0.045molN_2}{0.069mol}\times P_T[/tex][tex]P_{N2}=0.652\times P_T[/tex]If we assume that the gas behavior is like an ideal gas, we can find the total pressure with the following equation:
[tex]\begin{gathered} PV=nRT \\ P_T=\frac{nRT}{V_T} \end{gathered}[/tex]Where,
n is the total number of moles, 0.069mol
R is a constant, 0.08206atm.L/mol.K
V is the volume of the gas, 1.51L
T is the temperature of the gas, K.284.15K
We replace the known data:
[tex]P_T=\frac{0.069mol\times0.08206\frac{atm.L}{mol.K}\times284.15K}{1.51L}=1.06atm[/tex]Now, the partial pressure of nitrogen will be:
[tex]P_{N2}=0.652*1.06atm=0.69atm[/tex]Answer: The partial pressure of N2 is 0.69atm
How many significant figures (SF) are in each of the following measured quantities? Drag the appropriate measurement to the respectable bins
Answers
Chemistry => Measurements => Significant Figures
Significant figures correspond to the number of digits in a number. We have to take into account the following:
• Zeros at the beginning of a number or at the end are not counted as digits, but zeros in between the number should be counted.
,• When we write a number in scientific notation, the 10 that accompanies the number should not be counted.
Following these indications, let's count the significant figures of each given number:
In summary, we have the answer will be:
1SFs
3.00 m
4.0x10^3 mL
3SFs
50 100 00g
80.10 mL
60.4 °C
6SFs
9018.17 kg
A 3.00 L sample of paint that has a density of 4.65 g/mL is found to contain 33.1 g lead (II) nitride. what is mass percentage of lead in the paint and what is the ppm?
Answers
Density relates the mass of a compound to its volume. We will first find the mass of the solution using the density and volume given. We have the following equation:
[tex]\rho=\text{ density = }\frac{Mass}{Volume}[/tex]We clear the mass,
[tex]\begin{gathered} Mass\text{ = }\rho\times Volume \\ Mass\text{ =}4.65\frac{g}{mL}\times3000mL \\ Mass\text{ =}13950\text{ g} \end{gathered}[/tex]So, the mass of paint is 13950 g. Now the mass percentage of the lead in the paint will be calculated as follows:
[tex]\begin{gathered} \%mass=\frac{\text{ Mass of lead (II) nitride}}{Mass\text{ of paint}}\times100 \\ \%mass=\frac{33.1\text{ g}}{13950\text{ g}}\times100 \\ \%mass=0.24\% \end{gathered}[/tex]The mass percentage of lead in the paint is 0.24%.
ppm concentration means the quantity of solute in milligrams (mg) is in a liter (L) of a solution. So, to calculate ppm concentration we will divide the milligrams of lead (II) nitride between the liters of paint:
[tex]\begin{gathered} \text{ppm = }\frac{\text{33.1g of lead}\times\frac{1000mg}{1g}}{3L} \\ \text{ppm =11033ppm of lead} \end{gathered}[/tex]The ppm of lead in the paint is 11033ppm.
1. 60.0 mL of 0.322 M lithium chloride, LICI (aq) are combined with 20.0 mL of 0.530 M Tin (II) nitrate,
Sn(NO₂)2 (aq), 0.632 g of precipitate are recovered.
a. Write a balanced chemical equation for the reaction.
b. Write a balanced net-ionic equation for the reaction.
c. Calculate the moles of precipitate that are actually produced in the reaction.
d. Calculate the moles of precipitate that should be produced if the reaction went to completion.
e. Calculate the percent yield of the reaction.
Answers
Answer:
60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.
How many grams of lead (II) iodide will precipitate? (you must write your own reaction)
Explanation:
Assuming that each double-displacement reaction occurs, predict the products and write each balanced chemical equation.
a.
Sn(OH)2 + FeBry -*?
b. CsNO3 + KCI -* ?
Answers
The products of the double displacement reactions are given in the equations of the reaction below:
a. 3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
What are double displacement reactions?Double displacement reactions are reactions in which there is an exchange of radicals by two compounds when solutions of the compounds are added together.
In a double displacement reaction, an insoluble precipitate is obtained since one of the products of the double displacement reaction is insoluble in aqueous solutions.
The products of the double displacement reactions are given in the equations of the reaction below:
a. Reaction between Sn(OH)₂ and FeBr₃
3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. Reaction between CsNO₃ and KCI
CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
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