inding Total CostsStore AStore BWhat is the cost of the repair and sales tax combinedat Store B?ComputerRepair$1,200$1,350Sales Tax6%7%Gratuity15%15%ShippingFree2% of totalprice
Answers
Store B :
Computer repair : $1,350
Sale tax = 7%
To obtain the sale tax amount, multiply the price by the percentage in decimal form (divided by 100);
$1,350 x (7/100) = 1,350 x 0.07 = $94.5
Add both:
1,350+94.5=$1,444.5
Related Questions
Find the equation of the line. Use exortumbers. st V = 2+ 9 8- 6+ 5+ -4 3+ 2+ 1+ T + -9-8-7-65 2 3 5 6 7 8 9 4 -3 -2 -2 + -3+ -4+ -5* -6+ -7+ -8+
Answers
We can see that the line passes by the points (0, -5) & (5, 0), using this information we proceed as follows:
1st: We find the slope(m):
[tex]m=\frac{0+5}{5-0}\Rightarrow m=1[/tex]2nd: We use one of the points from the line and the slope to replace in the following expression:
[tex]y-y_1=m(x-x_1)[/tex]That is (Using point (0, -5):
[tex]y+5=1(x-0)[/tex]Now, we solve for y:
[tex]\Rightarrow y=x-5[/tex]And that is the equation of the line shown.
Which expression is equivalent to 4 * 4 * 4 * 5 * 5?34 x 2543 x 5244 x 501224 x 102
Answers
Any of those expressions are equivalent to 4*4*4*5*5
The number of algae in a tub in a labratory increases by 10% each hour. The initial population, i.e. the population at t = 0, is 500 algae.(a) Determine a function f(t), which describes the number of algae at a given time t, t in hours.(b) What is the population at t = 2 hours?(c) What is the population at t = 4 hours?
Answers
a) Let's say initial population is po and p = p(t) is the function that describes that population at time t. If it increases 10% each hour then we can write:
t = 0
p = po
t = 1
p = po + 0.1 . po
p = (1.1)¹ . po
t = 2
p = 1.1 . (1.1 . po)
p = (1.1)² . po
t = 3
p = (1.1)³ . po
and so on
So it has an exponential growth and we can write the function as follows:
p(t) = po . (1.1)^t
p(t) = 500 . (1.1)^t
Answer: p(t) = 500 . (1.1)^t
b)
We want the population for t = 2 hours, then:
p(t) = 500 . (1.1)^t
p(2) = 500 . (1.1)^2
p(2) = 500 . (1.21)
p(2) = 605
Answer: the population at t = 2 hours is 605 algae.
c)
Let's plug t = 4 in our function again:
p(t) = 500 . (1.1)^t
p(4) = 500 . (1.1)^4
p(4) = 500 . (1.1)² . (1.1)²
p(4) = 500 . (1.21) . (1.21)
p(4) = 500 . (1.21)²
p(4) = 732.05
Answer: the population at t = 4 hours is 732 algae.
3)A space shuttle achieves orbit at 9:23am. At 9:31am it has traveled an additional 2309.6 miles in orbit. Find the rate of change in miles per minutes.
Answers
Answer: 288.7 miles per minute.
Step-by-step explanation:
Considering:
Distance = Rate / Time
We are given the distance as 2309.6 miles in orbit.
We can calculate the time required to travel 2309.6 miles by doing:
End time - Start time.
In this case it would be 9:31 - 9:23 = 8 minutes.
Therefore it takes 8 minutes to travel 2309.6 miles.
Now we need to find the Rate of Change in miles per minutes.
In other words we need how many miles the shuttle traveled every minute.
Right now we have the shuttle traveled 2309.6 miles in 8 minutes. To find how many traveled in 1 minute, we need to divide.
2309.6 / 8 = 288.7 miles per minute.
What is the equation of the line that passes through the point (-5, -2) and has aslope of -6/5
Answers
Answer:
The equation of the line is;
[tex]y=-\frac{6}{5}x-8[/tex]Explanation:
Given the slope of the line as;
[tex]m=-\frac{6}{5}[/tex]And passes through point;
[tex](-5,-2)[/tex]Using the Point-slope equation to derive the equation of the line;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=-\frac{6}{5}(x-(-5)) \\ y+2=-\frac{6}{5}(x+5) \end{gathered}[/tex]Simplifying;
[tex]\begin{gathered} y+2=-\frac{6}{5}x-\frac{6}{5}(5) \\ y+2=-\frac{6}{5}x-6 \\ y=-\frac{6}{5}x-6-2 \\ y=-\frac{6}{5}x-8 \end{gathered}[/tex]Therefore, the equation of the line is;
[tex]y=-\frac{6}{5}x-8[/tex]
A is the incenter of Triangle FHG Find the length of AT. Explain your thinking.
Answers
we have that
The incenter is the center of the triangle's incircle, the largest circle that will fit
AR=AT=AS -----> radius of the inscribed circle in the triangle
therefore
AT=3 units
What is the slope of the line passing through the points (−1, 7) and (4, −1)? −5/62−8/5−2
Answers
Given the points:
(−1, 7) and (4, −1)
The slope of the line passing through the points is given by:
[tex]slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-7}{4-(-1)}=\frac{-8}{5}[/tex]So, the answer will be Slope = -8/5
Help meeeeeeeee
ASAP
Deena works at a customer service call center. She fields an average of 7 calls per hour. Employees are encouraged to field more than 280 calls per week. Deena has already fielded 112 calls this week.
How many more hours, x, does Deena need to work this week to reach the weekly goal of fielded calls if she continutes to field an average of 7 calls per hour? Select the inequality that includes the fewest number of hours Deena can work this week and still reach the weekly goal.
A.
x > 24
B.
x > 40
C.
x > 3
D.
x > 31
Answers
Examine this lable of points, which are all on a certain line. 8 What is the slope of this line? Enter your answer as a number, like this 42 Or, if the slope is undefined. enter a lowercase letter "u. like this. u
Answers
The formula for determining slope, m is expressed as
slope, m = (y2 - y1)/(x2 - x1)
y1 represents initial value of y
y2 represents final value of y
x1 represents initial value of x
x2 represents final value of x
From the table,
y2 = - 8
y1 = 0
x2 = - 1
x1 = - 5
Slope, m = (0 - - 8)/(- 1 - - 5)
Slope, m = (0 + 8)/(- 1 + 5)
Slope, m = 8/4
Slope = 2
1.5 part 1 question 36 determine whether the graph represent a function explain your answer
Answers
Recall that for a graph to correspond to a graph it must pass the vertical line test. The vertical line test consists of drawing vertical lines and if two points of the graph are on the same vertical line then the graph does not represent a function.
Notice the following:
From the above graph, we get that points A B, and C are on the same vertical line, and the same happens for e and f, and m and n. Therefore the graph fails the vertical line test.
Answer: The graph does not represent a function.
The frequency distribution of blood groups of a sample of patients was found to be as follows:A 14B 6AB 3O 17The relative frequency of AB in this data is:Group of answer choices7.5%30.033%
Answers
we have that
the number of patients is (14+6+3+17)=40
patients AB=3
so
40 -----> 100%
applying proportion
100/40=x/3
x=3*100/40
x=7.5%•is this function linear? •what’s the pattern in the table•what would be a equation that represents the function
Answers
Given data:
The given table.
The given function can be express as,
[tex]\begin{gathered} y-0=\frac{2-0}{1-0}(x-0) \\ y=2x \end{gathered}[/tex]As the equation of the above function is in the form of y=2x, it is linear function because for single value of x we got single value of y.
Thus, the function can be express as y=2x form which is linear function.
In the circle below, if the measure of arc ACB = 260 °, find the measure of < B.
Answers
Given:
There is a figure given in the question as below
Required:
If
[tex]arcACB=260\degree[/tex]than find the value of angle B
Explanation:
Value of arcADB is
[tex]arcADB=360\degree-arcACB=360\degree-260\degree=100\degree[/tex]Now to find the angle B
[tex]\angle B=\frac{1}{2}arcADB=\frac{1}{2}*100=50\degree[/tex]Final answer:
a
which example would be likely to give a valid conclusion?
Answers
Given: Different statement
To Determine: Which of the statement would give a valid conclusion
Solution
Please note that the statement must be a true representation of the population
Priya is mixing drops of food coloring to create purple frosting for a cake. She uses 24 drops of red dye and 16 drops of blue dye. Find the ratio of drops of red dye to total drops of dye. Express as a simplified ratio.
Answers
Priya uses 24 drops of red dye,
She also uses 16 drops of blue dye,
[tex]\begin{gathered} \text{Total drops of dye=}24+16 \\ =40\text{drops of dye} \end{gathered}[/tex]We are told to find the ratio of drops of red dye to the total drops dye.
[tex]=\frac{\text{red drops of dye}}{\text{total drops of dye}}[/tex][tex]\begin{gathered} =\frac{24}{40}=\frac{3}{5} \\ =3\colon5 \end{gathered}[/tex]Hence, the ratio of drops of red die to the total drops of die to the simplest rato is
3 : 5.
Which of the following sets does the number 12 over five belong to
Answers
The given figure is
12/5 = 2.4
Firstly, let us define the terms.
whole numbers are set of natural number including zero. It does not include decimals. Thus, 12/5 is not a whole number
Integers are are the set of whole numbers including all the negative natural numbers. It does not include fractions. Thus, 12/5 is not a whole number
Rational numbers is a set of fractions where the denominators and numerators are integers. Since 5 and 12 are integers, 12/5 is a rational number
Irrational numbers are numbers that numbers that cannot be written on the number line. They include square root of 2, pi. etc. Thus, 12/5 is not an irrational number
Real numbers is the set of all rational and irrational numbers. Thus, 12/5 is a real number
Therefore, the correct options are
Describe the association in the scatter plot below.----------------The scatter plot shows (positive linear, positive linear with one outlier, negative linear, negative linear with one outlier, nonlinear, or no) association because as the plotted values of x increase, the values of y generally (decrease, increase, show no pattern or follow a nonlinear pattern).
Answers
From the given figure
The given point can form a line with a negative slope, because when
the values of x increase the values of y decrease
Then the scatter plot shows a negative linear association because
as the values of x increase, the values of y generally decrease
Find the interest odf the loan using banker's ruleP - $350,- = 4.8%, t = 150 days
Answers
i = P r T
interest: i
Principal = $350
Interest rate : 4.8% (in decimal form, 4.8/100 = 0.048)
time = t = days/365 = 150/360
Replacing:
i= 350 (0.048) (150/360) = 7
what is the x intercepts or zeros for y = x^2 - 6x + 5
Answers
Solution:
Given;
[tex]y=x^2-6x+5[/tex]The x-intercepts are the points where y=0.
Thus;
[tex]x^2-6x+5=0[/tex]Thus;
[tex]\begin{gathered} x^2-x-5x+5=0 \\ \\ x(x-1)-5(x-1)=0 \\ \\ x-1=0,x-5=0 \\ \\ x=1,x=5 \end{gathered}[/tex]ANSWER:
[tex]x=1,x=5[/tex]what must be a factor if the polynomial function f(x) graphed ib the coordinate plane below ?
Answers
Solution
The question gives us a graph that crosses the x-axis at 3 points: x = 1, x = 2, and x = -3. We are asked to find which of the factors on the graph is in the options given.
- Whenever a graph crosses the x-axis at a point "a", it implies that x = a is a root of the graph and as a result, (x - a) must be a factor of the graph.
- We can apply this to the question and derive the factors of the graph as follows:
[tex]\begin{gathered} \text{ When }x=-3\colon \\ x=-3 \\ \text{Add 3 to both sides} \\ x+3=0 \\ \\ \text{Thus, }(x+3)\text{ is a factor of the graph.} \\ \\ \\ \text{When }x=1\colon \\ x=1 \\ \text{Subtract 1 from both sides} \\ x-1=0 \\ \\ \text{Thus, }(x-1)\text{ is a factor of the graph} \\ \\ \\ \text{When }x=2\colon \\ x=2 \\ \text{Subtract 2 from both sides} \\ x-2=0 \\ \\ \text{Thus, (}x-2)\text{ is a factor of the graph.} \\ \\ \\ \text{Thus, we can conclude that the 3 factors of the graph are:} \\ (x+3),(x+1),\text{ and }(x-2) \end{gathered}[/tex]- Going through the options, we can see that only (x - 1) is present in the options.
- Thus, (x - 1) is the answer
Final Answer
(x - 1) is the answer (OPTION B)
In the figure below, BAC~QPR. Use this information and the diagram below to name the corresponding parts of the similar triangles
Answers
a.
∠A is the right angle of the triangle ABC, so the corresponding angle is ∠P, which is the right angle of the triangle PQR.
b.
BC is the hypotenuse of the triangle ABC, so the corresponding side is QR, which is the hypotenuse of the triangle PQR.
c.
∠C is the smaller angle of the triangle ABC, so the corresponding angle is ∠R.
d.
∠Q is the bigger angle of the triangle PQR, so the corresponding angle is ∠B.
e.
PQ is the smaller leg of the triangle PQR, so the corresponding side is AB.
Which tree is growing faster?Tree 2*Tree 1 is growing1.5 inches everyweek.weeks 1|2|3|4|5inches 45678tallTree ?Tree 1
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the growing rate of the first tree
Tree 1 is growing 1.5 inches every week
STEP 2: Calculate the growing rate of the second tree
This implies the slope and is calculated using the formula;
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]By substitution,
[tex]m=\frac{5-4}{2-1}=\frac{1}{1}=1[/tex]The slope of 1 means that Tree 2 is growing at a rate of 1 inch per week
Hence, the tree that is growing faster is Tree 1 with a rate of 1.5 inches per week
ANSWER:
Tree 1
Suppose you open a bank account and deposit $50. Then, every month you deposit $20. Write anequation that relates the total number of dollars deposited, T, and the month, m.Which equation below relates the total number of dollars deposited, T, and the month, m?
Answers
Let:
T = Total number of dollars deposited
m = Number of months
b = Initial deposit
So:
[tex]\begin{gathered} T(m)=20m+b \\ where \\ b=50 \\ so\colon \\ T(m)=20m+50 \end{gathered}[/tex]6. Write a quadratic function whose graph has a vertex of (-4,-2) and passes through the point (-3,1).
Answers
(h,k) are the coordinates of the vertex.
Use the given point (x,y) and the vertex (h,k) in the equation above to find the value of a:
Point: (-3 ,1) x = -3 y=1
Vertex: (-4 , -2) h= -4 k=-2
[tex]\begin{gathered} 1=a(-3-(-4))^2+(-2) \\ 1=a(-3+4)^2-2 \\ 1=a(1)^2_{}-2 \\ 1=a-2 \\ 1+2=a \\ 3=a \end{gathered}[/tex]Use the vertex and a to write the equation:
[tex]\begin{gathered} y=3(x-(-4))^2+(-2) \\ \\ \\ y=3(x+4)^2-2 \end{gathered}[/tex]Find the slope of the line that contains the two points.ROUND YOUR ANSWER TO TWO DECIMAL PLACES.
Answers
The slope of a line is given by the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where (x1,y1) and (x2,y2) are the coordinates of the given points. Replace the given values and solve for m:
[tex]m=\frac{8-(-4)}{-6-0}=\frac{8+4}{-6}=\frac{12}{-6}=-2[/tex]The slope of the line that contains the two given points is -2.
The length of time (T) in seconds it takes the pendulum of a clock to swing through one compete cycle is givenby the formulaT= 2T✔️L/32 Where L is the length, in feet, of the pendulum, and is pie approximately 22/7. How long must the pendulum be of one complete cycle takes 2 seconds? Answer as a fraction or round to at least 2 decimal places.The pendulum must be__ feet.
Answers
we have the formula
[tex]T=2\pi\sqrt{\frac{L}{32}}[/tex]For T=2 seconds
substitute in the given formula
[tex]\begin{gathered} 2=2\pi\sqrt{\frac{L}{32}} \\ \\ 1=\frac{22}{7}\sqrt{\frac{L}{32}} \\ \\ squared\text{ both sides} \\ \\ (\frac{7}{22})^2=\frac{L}{32} \\ \\ L=\frac{7^2*32}{22^2} \\ \\ L=3.24\text{ ft} \end{gathered}[/tex]1) f(x) = 60.73(0.95)x2) f(x) = 0.93(60.73)x3) f(x) = 60.04 – 8.25 ln x4) f(x) = 8.25 – 60.04 ln x
Answers
A logarithmic function is expressed as
y = a + blnx
We would substitute corresponding values of x and y into the function. This will give us two equations. We would solve the equations for a and b. We have
From the table, when x = 1, y = 60
Thus,
60 = a + b * ln1
60 = a + b * 0
60 = a
when x = 2, y = 54
Thus,
54 = a + bln2
54 = a + 0.693b
Substituting a = 60 into 54 = a + 0.693b, we have
54 = 60 + 0.693b
0.693b = 54 - 60 = - 6
b = - 6/0.693
b = - 8.65
The function would be
f(x) = 60 - 8.65lnx
13(10+2) could be used to simplify which of the following problems?A 013/20)B O13(12)C 0130(26)
Answers
Explanation:
The expression is given below as
a test has 20 Questions worth 100 points the test consists of true or false questions worth 3 points each and multiple choice questions worth 11 points each how many multiple choice questions are on the test
Answers
A test is to be conducted with certain types of questions and each type of question weighs certain number of points.
A test would consist of two types of questions. These two types will be assigned variables that will denote the number of questions respectively as follows:
[tex]\begin{gathered} \text{True and False: x} \\ \text{MCQS : y} \end{gathered}[/tex]We are given that the entire test will consits of 20 questions. We can express the total number of questions on the test in terms of number of True and False questions ( x ) and number of MCQS ( y ) as follows:
[tex]\begin{gathered} \text{Total number of Questions = True and False + MCQS} \\ \textcolor{#FF7968}{20}\text{\textcolor{#FF7968}{ = x + y }}\textcolor{#FF7968}{\ldots Eq1} \end{gathered}[/tex]Further information is given to us in the questions regarding the number of points aloted to each type. The total weightage of each type of question on the test can be expressed as a product of ( number of each type * point weight of each type ).
The point weights for each type of questions are:
[tex]\begin{gathered} \text{True and False ( x ) : 3 points each} \\ \text{MCQs ( y ) : 11 points each} \end{gathered}[/tex]The total weights of each types of questions are:
[tex]\begin{gathered} \text{True and False ( points ) = 3}\cdot x \\ \text{MCQS ( points ) = 11}\cdot x \end{gathered}[/tex]We are given that the entire test is worth ( 100 points ). We express the total number of points of the test in terms of total weight of each type of question as follows:
[tex]\begin{gathered} test\text{ points = True and False ( points ) + MCQS ( points )} \\ \textcolor{#FF7968}{100}\text{\textcolor{#FF7968}{ = 3}}\textcolor{#FF7968}{\cdot x}\text{\textcolor{#FF7968}{ + 11}}\textcolor{#FF7968}{\cdot y\ldots}\text{\textcolor{#FF7968}{ Eq2}} \end{gathered}[/tex]We have two equations that express the total number of questions ( Eq 1 ) and total points ( Eq2 ) of the test in terms of number of True and False questions ( x ) and number of MCQs on the test ( y ).
[tex]\begin{gathered} \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ + y = 20 }}\textcolor{#FF7968}{\ldots Eq1} \\ \textcolor{#FF7968}{3x}\text{\textcolor{#FF7968}{ + 11y = 100 }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq2}} \end{gathered}[/tex]We will solve the above two equations simultaneously using Elimination method.
Step1: Multiply Eq1 with ( -3 )
[tex]\begin{gathered} -3\cdot\text{ ( x + y ) = -3}\cdot20 \\ \textcolor{#FF7968}{-3x}\text{\textcolor{#FF7968}{ - 3y = -60 }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq3}} \end{gathered}[/tex]Step2: Add Eq 3 into Eq 2
[tex]\begin{gathered} -3x\text{ - 3y = -60 } \\ 3x\text{ + 11y = 100} \\ =========== \\ 8y\text{ = 40 } \\ \textcolor{#FF7968}{y}\text{\textcolor{#FF7968}{ = 5}} \\ =========== \end{gathered}[/tex]Step3: Back susbtitue the value of ( y ) into ( Eq1 )
[tex]\begin{gathered} x\text{ + ( 5 ) = 20 } \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ = 15 }} \end{gathered}[/tex]Therefore, the number of each type of questions that must be put on the test should be.
[tex]\begin{gathered} \text{\textcolor{#FF7968}{True and False ( x ) = 15}} \\ \text{\textcolor{#FF7968}{MCQs ( y ) = 5}} \end{gathered}[/tex]Find the length of the missing side. Round answers to the nearest tenth if necessary. * S sva Your answer
Answers
Question:
Solution:
Notice that the angle between the sides of the square is 90 degrees:
Therefore, the angle of the vertex of the triangle measures 45 degrees:
thus, we obtain the following right triangle:
Now, apply the following trigonometric identity:
[tex]\cos \text{ (45) = }\frac{s}{5\sqrt[]{2}}[/tex]solving for s, we get:
[tex]s\text{ = cos(45) . 5 }\sqrt[]{2}\text{ = 5}[/tex]then, we can conclude that the correct answer is:
[tex]s\text{ = 5}[/tex]