The reaction is exothermic as it involves a bond-forming process
when the liquids are mixed temperature of the reaction between the mixture increases.
There are small and large clusters in the mixture
The exothermic reaction involves the formation of new bonds which involves a combination of the bonds to form a new compound in our case water has hydroxy ions that bond with those of ethanol.
Mixing ethanol and water in volumetric glassware reduces the volume and increases the temperature.
The numerical example
Fill two 250 mL graduated cylinders to the line with water and ethanol pure temperature sensor shows both at room temperature. Next, move the temperature probe to an empty 500 mL graduated cylinder and pour the contents of the two smaller cylinders simultaneously and mix well.
The temperature of the mixture will rise by about 8 °C and the volume will decrease to 480 this indicates that the reaction is exothermic as the temperature rises and volume reduces
yes, clusters are present as ethanol falls between the spaces left by water as it has small molecules than that of water.
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Distillation is a process used to separate a mixture of liquids based on different
a. boiling points
b.
densities
freezing points
d. solubilities
Answer:
freezing points hope it helps u
Distillation is a process used to separate a mixture of liquids based on different freezing points. Therefore, option C is correct.
What is distillation ?Distillation is the process of turning a liquid into a vapor, which is then condensed back into a liquid state. The simplest illustration of it is when steam from a kettle condenses into drops of distilled water that are left on a cold surface.
In general, distillation is the process of vaporizing a liquid to its boiling point, then condensing it back into a liquid to separate it from impurities or other solutes.
Among the many industrial uses of distillation are the production of alcoholic drinks, water purification, and oil refining. Distillation is a physical procedure that removes desired pure compounds from an initial source using heat and other techniques.
Thus, option C is correct.
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I need to determine electron configuration of rubidium and rubidium ion.
The atomic number of rubidium is 37, it means that its electron configuration is as follows:
[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1[/tex]Rubidium is an alkali metal. Its ion is formed when it loses an electron. It means that the rubidium ion has 36 electrons instead of 37, and its configuration is as follows:
[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^6[/tex]why does bread grow mold more quickly at room temperature than in the refrigerator? why does bread grow mold more quickly at room temperature than in the refrigerator? the formation of mold is an endothermic process, and low temperatures favor endothermic processes. because of the absence of sunlight, the potential energy of the reactants is lower in the refrigerator. more reactants will have the energy necessary to proceed to products at room temperature than at refrigerator temperatures. the formation of mold is an example of a photochemical process, and it cannot occur in a dark place such as a refrigerator.
Bread grows mold more quickly at room temperature than in the refrigerator because more reactants will have the energy necessary to proceed to products at room temperature than at refrigerator temperatures.
Molds are formed on bread due to various reactions that facilitate the living of the molds on the bread and allow them to reproduce on the bread.
However, as molds are living organisms characterized as fungi, they need enzymes for function.
The enzymes and proteins normally function best at room temperature. On the other hand, when the temperatures are low, such as that of a refrigerator the molds will not have enough energy because the proteins and enzymes will be inactivated. Hence, molds grow on bread quickly at room temperature as compared to bread in a refrigerator.
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help me please!
What pressure will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm?
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.
What is ideal gas equation?
Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.
Mathematically the relation between Pressure and temperature can be given as
P₁M₁=DRT₁
P₂M₂=DRT₂
Rearranging the two equation we get
P₁M₁÷T₁=P₂M₂÷T₂
where,
P = pressure
M= Molarity
D=density
T =temperature
R = Gas constant = 0.0821 L.atm/K.mol
Substituting all the given values, we get
(P₁×M₁)÷T₁=(P₂×M₂)÷T₂
(P₁×20)÷303=(1.0 ×28)÷293
P₁=1.44atm
Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.
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two mole of ideal gas is compressed isothermal from 10 to 10,000 atmospheric pressure at 500 degree kelvin. calculate the entropy change in the process.
Two mole of ideal gas is compressed isothermal from 10 to 10,000 atmospheric pressure at 500 degree kelvin then the entropy change in the process is -114.86 J/K
Ideal gas is the hypothetical gas composed of molecule which follow a some rules in that ideal molecule do not attract or repel to each other and here given data is
Ideal gas = 2 mole
Pressure = P₁ = 10
Pressure = P₂ = 10,000
Temprature = 500 degree kelvin
We have to calculate entropy change in the process =?
We know the entropy change
ΔS = cv ln(T₂/T₁) +nR ln (P₂/P₁)
For isothermal compression temprature constant,
ΔS = nR ln (P₂/P₁)
ΔS = 2×8.314×ln(10/10,000)
ΔS = -114.86 J K⁻
ΔS = -114.86 J/K
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What is the boiling point of a solution of 0.250g of glycerol, C3H8O3, in 40g of H2O? Glycerol is a molecular compound, i = 1
Explanation
Given:
mass of glycol = 0.250g
mass of solvent (water) = 40g = 0.04 Kg
i = 1
Required: The boiling point of the solution
Solution
[tex]\Delta T\text{ = Kbm}[/tex]where Kb is the boiling point elevation constant
m is the molal concentration (molality) of all species
Step 1: Find the moles of glycerol
n = m/M
n = 0.250g/92,09382 g/mol
n = 2.71x10^-3 mol
Step 2: Find the molality
molality (m) = moles of solute/Kg of solvent
molality = 2.71x10^-3/0.04Kg
molality = 0.068 m
Step 3: Find the change in temperature
[tex]\Delta T\text{ = Kbm}[/tex]Kb of water = 0.512 cm^-1
DT = 0.512 x 0.068
DT = 0.035 'C
Step 4: Find the boiling point
Boiling point of water = 100 'C
DT = 0.035 'C
New boiling point =100 + 0.035 = 100.035 'C
Answer
100.035 'C
Which set of numbers will balance the following equations? 1's have been included for clarity.__Mn3N4 + __NaF --> __MnF4 + __Na3N a 1; 4; 1; 4 b 1; 4; 3; 2 c 1; 12; 3; 4 d 3; 2; 3; 2
ANSWER
Option C
EXPLANATION
Given that;
[tex]\text{ ----- Mn}_3N_4\text{ }+\text{ ---- NaF }\rightarrow\text{ ---- MnF}_4\text{ }+\text{ ---Na}_3N[/tex]In the reaction above, we have the following data
At the reactants side;
3 atoms of manganese
4 atoms of nitrogen
1 atom of sodium
1 atom of fluorine
At the products side
1 atom of manganese
4 atoms of fluorine
3 atoms of sodium
1 atom of nitrogen
To balance the above equation, apply the law of conservation mass
Law of conservation of mass states that matter can neither be created nor destroyed but can e transformed from one formato another.
To balance the equation, 1 mole of Mn3N4 reacts with 12 moles of Na Tto give 3 moles of MnF4 and 4 moles of Na3N
So, the new equation becomes
[tex]\text{ Mn}_3N_4\text{ }+\text{ 12NaF }\rightarrow\text{ 3MnF}_4\text{ }+\text{ 4Na}_3N[/tex]The following data can be deduced in the above equation
At the reactants side
3 atoms of Mn
4 atoms of N
12 atoms of Na
12 atoms of F
At the products side
3 atoms of Mn
12 atoms of F
12 atoms of Na
4 atoms of N
Looking atthe vabove data, the number of atoms of each element at the reactants side is equal to the number of atoms of same elements at the products side.
Hence, the correct answer is option Ce
u
in a beaker, 0.57 mol of potassium iodide and 0.52 mol of lead (ii) nitrate are dissolved in water. a reaction occurs, and a white precipitate is observed. calculate the mass (in grams) of the precipitate formed
The white precipitate formed is lead iodide (PbI₂) of mass 131.38g
What is a precipitate reaction?The term "precipitation reaction" may be described as "a chemical response taking place in aqueous solution wherein ionic bonds integrate to shape an insoluble salt". These insoluble salts fashioned in the course of precipitation reactions are referred to as precipitates. Precipitation reactions are normally double displacement reactions with the formation of stable residues referred to as precipitates.
One of the first-class examples of precipitation reactions is the chemical response among potassium chloride and silver nitrate, which precipitates stable silver chloride. This is an insoluble salt fashioned as a made from precipitation reactions. The chemical components for this precipitation response is proven below.
AgNO3(aqueous) + KCl(aqueous) —–AgCl(precipitate) + KNO3(aqueous)
For the given case,
The balanced reaction is as follows:
Pb(NO₃)₂ (aq) + 2KI (aq) → 2KNO₃ (aq) + PbI₂ (s)
This tells us that for every mole of lead iodide (PbI₂) produced, it requires 2 moles of potassium iodide (KI).
If you have 0.57 mole of KI, they will produce: 0.57/2 = 0.285 mol of PbI₂
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
mass of lead iodide (PbI₂) = Number of moles × molar mass
Mass of lead iodide = 0.285 × 461.01
Mass of lead iodide = 131.38g
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calculate the vapor pressure of a solution of 0.300 mol fraction of toluene and 0.700 mol fraction of cyclohexane at 32oc and determine whether the solution will boil. the vapor pressure of pure toluene is 40.2 torr and that of cyclohexane is 125 torr at 32oc
The Vapour pressure of the solution is 99.56 torr
The saturated vapour pressure of the solution maybe lower then the pressure of pure solvent in solution. It is equal to the vapour pressure of the pure solvent at the same temperature scaled by mole fraction of solvent stated by Rault's Law.
P(solution) = mol fraction of solvent × P° ( solvent)
given, pressure of pure toulene = 40.2 torr
pressure of pure cyclohexane = 125 torr
∴ P (solution) = 0.3 × 40.2 + 0.7 × 125
P (solution) = 99.56 torr
hence, vapour pressure is calculated to be 99.56 torr.
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Which of the following is not a factor that affects temperature?
Longitude
Altitude
Ocean currents
Latitude
What are different types of forces and how do they act on objects?
Why is reactivity with oxygen a chemical property?
The reactivity of a substance with oxygen is a chemical, not a physical property. The reason it is called a chemical property is that it relies on its electron configuration to determine how it behaves around other substances.
What is a chemical property?A chemical property is a property of any material that becomes apparent during or after a chemical reaction; that is, any quality that can only be determined by changing the chemical properties of a substance.
Oxygen is a very reactive element, is highly paramagnetic and readily combines with other elements. One of the most important chemical properties of oxygen is that it promotes combustion. Even at room temperature, oxygen binds to elements and forms e.g. rust.
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selective analysis of an analyte and internal standard yielded detector responses of 3.47 and 5.23 respectively when each had a concentration of 1.00 ppm. five ml of an unknown analyte solution were mixed with 1 ml of 5.00 ppm internal standard and then diluted to a total of 10 ml. the detector responses for analyte and internal standard for this mixture were 4.26 and 2.43. calculate the concentration of the analyte in the unknown solution. report your answer in ppm.
By calculating the response factor for the internal standard first, we can calculate that the concentration of the unknown analyte sample is 2.64 ppm.
When solving problems like this, we need to calculate the appropriate response factor:
A(X) / C(X) = F * A(S) / C(S)
A(X) - response for the analyte (3.47)
C(X) - concentration of the analyte (1 ppm)
F - response factor
A(S) - response for the internal standard (5.23)
C(S) - concentration of the internal standard (1 ppm)
F = A(X) * C(S) / (C(X) * A(S)
F = 3.47 * 1 ppm / (5.23 * 1 ppm)
F = 0.663
Now we can use this in the second calculation to obtain the concentration of the analyte in the sample. One thing to note is that in second measurement 1 mL of a 5.00 ppm internal standard was diluted to 10 mL, so the concentration of the internal standard is actually 5.00 ppm / 10 = 0.500 ppm.
4.26 / C(X) = 0.663 * 2.43 / 0.500 ppm
C(X) = 4.26 * 0.500 ppm / (0.663 * 2.43)
C(X) = 1.32 ppm
Because 5 mL of the analyte solution were diluted to 10 mL, the concentration is actually 2 * 1.32 ppm = 2.64 ppm.
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as a result of the sigmoidal shape of the o2-hb dissociation curve, there is very little change in hb saturation across a range of po2 values when po2 is high (e.g. between 80 and 100 mm hg in the text book figures). according to the reading, what is an advantage of the relatively flat shape of the curve here?
Red blood cells contain hemoglobin. When carbonic acid, which is found in tissues, is present, hemoglobin releases the bound oxygen. The oxygen that is attached to hemoglobin is released into the blood's plasma and taken up by the tissues in the capillaries, which are also where carbon dioxide is created.
Throughout each of these deep breathing cycles, how do the partial pressures change?If more air is exchanged, the partial pressures of the outside atmosphere will approach but never reach them due to the remaining volume.
Combustible Oxide : The dissociation curve shifts to the left as a result of one CO molecule binding to hemoglobin increasing the affinity of the other binding locations for oxygen.
Lower CO2, greater pH, and lower temperature all move oxygen dissociation to the left.
The pCO2 is significantly influenced by two variables. The person's breathing rate and depth are the first thing to consider. Someone who is hyperventilating will "blow out" more CO2, which will lower pCO2 levels. Holding one's breath causes CO2 to be retained, which raises pCO2 levels.
Limited pressures : There are two reasons why the alveolar oxygen partial pressure is lower than the ambient O2 partial pressure. First, the upper airway humidifies the air as it reaches the lungs, lowering the partial pressure of oxygen to around 150 mmHg while increasing the partial pressure of water vapour (47 mmHg).
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Identify the element symbol
1s22s22p63s23p64s23d104p65s24d5
Answer:
Tc
Explanation:
You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!
Explain how to make one liter of a 1.25 N sodium hydroxide solution.
Answer:
1.25 moles(N) of NaOH are present in 1000 gm of water.
and 1000gm = 1L
hence we need to put 1.25 Moles (N) of NaOH in 1L H2ONow read the question sooner passes an electric current through a sample of clear odorless colorless liquid as the experiment continues bubbles form and the volume of liquid and decreases soon eclectic samples of two colorless odorless gases that bubble out of the liquid one of these gases burn neither of neither the original nor the other gas burns which is the best explanation of her results
The best explanation will be that the sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound.
The utilization of the electric current to break down substances is called electrolysis.
The case displayed is the same as the electrolysis of water: the electrical current breaks down the water (a compound) into the components that frame it: hydrogen (a gas that burns) and oxygen (a gas that does not burn).
The test was broken down by the electric current and shaped into an unused substance that seems to burn. Hence the initial fluid may be a compound.
Bypassing an electric current through a test of clear, colorless, and odorless fluid. As the trial proceeds, bubbles shape, and the volume of fluid diminishes.
As the test proceeds, bubbles shape, and the volume of fluid diminishes. Suna collects tests of two colorless, odorless gasses that bubble out of the fluid. One of the gasses burns. Not one or the other the first fluid nor the other gas burns.
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To find the order of a reaction with respect to one reactant, you will monitor the __________ as the _________of ________ is changed.
To find the order of a reaction with respect to one reactant, you will monitor the Percentage as the reactant of product is changed.
To determine the reaction order from experimental data, either the differential rate law or the integrated rate law can be used. In the rate law, the exponents are frequently positive integers: 1 and 2 or even 0. As a result, the reactions in each reactant are of zeroth, first, or second order. Changes in the concentration of the reactants or products can be used to calculate the rate. changes in reactant or product mass or volume If the reaction is the result of multiple reaction steps with different orders, the order of the reaction can be changed by adjusting the reagent concentration. Because the order is often ruled by the slowest reaction, you can manipulate the relative reaction speed by varying the concentrations.
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Answer:
Explanation:
You will watch the Percentage when the reactant of the product is changed in order to determine the sequence of a reaction with respect to one reactant.
Either the differential rate law or the integrated rate law can be used to infer the reaction order from experimental data.
The exponents of the rate law are frequently positive numbers, such as 1 and 2 or even 0.
Because of this, each reactant undergoes reactions of the zeroth, first, or second order.
The rate can be calculated using changes in the concentration of the reactants or products.
A change in the reactant, product, or reactant's volume by changing the reagent concentration, the reaction order can be modified if it involves several steps that have been performed in a different sequence.
You can also control the relative reaction speed by changing the concentrations because the order is frequently determined by the slowest reaction.
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the number of atoms in 0.009567 mole of HBrO3 is
Avogadro's Number:
Avogadro's number, which is equal to 6.02214076 x [tex]10^{23}[/tex], is the quantity of units in one mole of any material. Hence, 1 mole of HBrO3 will contain
6.02214076 x [tex]10^{23}[/tex] atoms.
Then, 0.009567 mole of HBrO3 will contain
= 0.009567 moles x 6.02214076 x [tex]10^{23}[/tex] atoms
= 0.0576138 x [tex]10^{23}[/tex] atoms = 5.761 x [tex]10^{21}[/tex] atoms.
Hence, 0.009567 mole of HBrO3 will contain 5.761 x [tex]10^{21}[/tex] atoms.
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a sample of gas occupies a volume of 70.3 ml . as it expands, it does 140.6 j of work on its surroundings at a constant pressure of 783 torr . what is the final volume of the gas?
A sample of gas occupies a volume of 70.3 ml as it expands, it does 140.6 j of work on its surroundings at a constant pressure of 783 torr and the final volume of the gas is 11.12L
A gas is a sample of matter that conforms to the shape of a container in which it is held and acquires a uniform density inside the container and even in the presence of gravity and regardless of the amount of substance in the container
Here given data is 11.12L
V₁ = Initial volume = 70.3 ml = 0.0703ml = (1L=1000ml)
w = 140.6 J = 1.387 J = (1Latm=101.3J)
Pressure = 783 torr = 1.03 atm = (1atm=760 torr)
V₂ = final volume = ?
1.387Latm = 1.03 atm × (V₂ - 0.0703ml)
(V₂ - 0.0703ml) = 11.05
V₂ = 11.12L
The final volume of the gas is 11.12L
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Question 5(Multiple Choice Worth 2 points)
(14.01 LC)
What is the function of the outer covering in fish?
Answer:
Protects the fish from their environment.
Explanation:
Fish have a mucus on their outer covering that is very slimy and slippery; this serves as a benefit for the fish that will allow it to swim more easily in water.
It also works as a little suit of armor for the fish to protect themselves against predators.
Which element has 2 valence electrons and 5 energy levels?
Answer:
its Boron i hope this helped.
Explanation:
you need to prepare 1 l of the acetic acid/acetate buffer. you decided to mix 300 ml of 0.45 m acetic acid acid and 100 ml of 0.65 m naoh plus water to a final volume of one liter. the pka of acetic acid is 4.75. 1. calculate the ph of your buffer solution. 2. naoh is not the conjugate base to acetic acid. explain why you can use naoh to make an effective acetate buffer.
The pH of buffer solution is 4.72.
1) Molarity of acetic acid = 0.45 M
The volume of acetic acid = 300 ml
Molarity of NaOH = 0.65 M
Volume of NaOH = 100 ml
An acidic buffer solution is calculated by using Henderson's equation:
pH = pKa + ㏒[salt] / [acid]
where pKa = 4.75
pH = 4.75 + ㏒[0.065M] / [0.07M]
pH = 4.75 + ㏒(0.929)
pH = 4.75 - 0.03
pH = 4.72
Therefore, the pH of the buffer solution is 4.72.
2) NaOH is not the conjugate base to acetic acid. As we know NaOH is a strong base and acetic acid is a weak acid. Thus, an acid-base reaction occurs between acetic acid and NaOH, thus forming CH₃COONa, which is the conjugate base of acetic acid.
Acidic buffer solution is formed by mixing of weak acid and its conjugate salt of strong base. Thus, NaOH acts as limiting reactant and only CH₃COOH and CH₃COONa is present in solution. Thus, CH₃COOH is weak acid and CH₃COONa is its conjugate salt of strong base forms buffer solution. In the reaction of NaOH and CH₃COOH, NaOH gets completely reacted and forms CH₃COONa. Thus, NaOH is added to make an effective acetate buffer.
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Facts for Globalization?
Answer:
Globalization has many benefits, such as the increased flow of goods, services, capital, and people across borders. This has resulted in increased trade and investment, which has led to higher economic growth rates and improved standards of living around the world.
Explanation:
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A chemical reaction combines the metal sodium (NA) and the gas chlorine (cl2) to form sodium chloride, commonly known as table salt (nacl) why does this produce have different properties from the reactants
When a chemical reaction happens, the atoms in the reactants are rearranged to create compounds with various chemical characteristics. Although identical atoms are present in both the reactants and the products, sodium chloride was produced by rearranging the atoms in the reactants. The reactants lacked sodium chloride.
Sodium is a soft, silver-colored metal that may be sliced with a knife. With water, pure sodium metal reacts violently (and even explosively), creating sodium hydroxide, hydrogen gas, and heat.
2Na(s) + 2H₂O(l) ⟶ 2NaOH(aq) + H₂(g)
Chlorine is a poisonous yellow-green gas with a pungent smell.
But when sodium and chlorine combine, they create sodium chloride, or table salt, which is known to practically everyone in the world.
2Na(s) + Cl₂(g) ⟶ 2NaCl(s)
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what elements does KOH contain
Answer:
K- Potassium
O- Oxygen
H- Hydrogen
KOH is called as Potassium Hydroxide and it contains K (Potassium), O (Oxygen) and H (Hydrogen) elements.
Caustic potash is a common name for potassium hydroxide, an inorganic compound with the formula KOH. The majority of its industrial and niche applications capitalize on its caustic nature and acid reactivity. It important because it is the starting point for most liquid and soft soaps, as well as many chemicals that contain potassium.
It is a dangerously corrosive white solid. KOH has a high level of thermal stability. Melt-casting it into pellets or rods with low surface areas and easy handling properties is common due to its high stability and low melting point. Because KOH is hygroscopic, these pellets become tacky when exposed to air.
Its dissolution in water is strongly exothermic, with water and carbonates accounting for the remaining 90% purity. A common name for concentrated aqueous solutions is potassium lye. Solid KOH does not easily dehydrate even at high temperatures.
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Help me to balance this equation please
Answer:
H202(aq)+2Fe2+(aq)+2H+=>2fe3+(aq)+2H20(l)
Explanation:
H202(aq)+2Fe2+(aq)+2H+=>2fe3+(aq)+2H20(l)
H202(aq)+2Fe2+(aq)+2H+=>2fe3+(aq)+2H20(l)
during a phase change, even though heat is entering or leaving the system, the overall temperature of the system does not change. a good example of this is the freezing of liquid water to form ice cubes (an exothermic reaction) or the melting of an ice cube to liquid water (an endothermic reaction). if the temperature of the system does not change, what happens to the heat (energy) that is being released from (exothermic) or put into the system (endothermic)?
There is no temperature increase during a phase change because the heat supplied to the substance is used to give the molecules in the substance energy to break free from the forces holding them together.
What is a phase change in a substance?A phase change in a substance refers to the process by which a substance changes from one physical state to another when heat is added or removed from it.
A phase change is also called a change of state.
The various types of phase changes are as follows;
melting - this is the process whereby a substance changes from solid to liquidvaporization - this is the process whereby a substance changes from liquid to gassolidification - this is the process whereby a substance changes from liquid to solidcondensation - this is the process whereby a substance changes from gas to liquidDuring a phase change, even though heat is entering or leaving the system, the overall temperature of the system does not change. This is because the heat energy supplied is used to overcome the forces between the molecules of the substance.
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which is a difference between butyne and cyclobutyne? group of answer choices cyclobutyne does not exist. butyne's multiple bond is interior, cyclobutyne is not between interior carbons. cyclobutyne burns much hotter than butyne because of the greater unsaturation. both b and c are differences between the molecules.
Cyclobutyne does not exist. A hydrocarbon molecule called cyclobutyne has a triple bond inside of a ring with four carbon atoms.
Due to its high ring strain, this cycloalkyne is extremely unstable and hasn't been isolated in its purest form.
What is butyne ?Organic compound butyne has the chemical formula HC2CH2CH3. It is a flammable, colourless gas. 1-Butyne takes part in processes that are common for terminal alkynes, such as hydrogenation, condensation with formaldehyde, and alkyne metathesis.
Due of its extremely low torsional barrier and the difficulty in identifying it using high-resolution infrared spectroscopy, 2-butyne is of interest to physical chemists.
Cycloalkenes include cyclobutene. It offers potential for research but no immediate applications. It is an effortlessly condensible colourless gas. In a contemporary synthesis, cyclobutanol is dehydrated twice. The ammonium salt OH was first thermolyzed to create the chemical.
Cycloalkanes are monocyclic saturated hydrocarbons in organic chemistry. To put it another way, all of the carbon-carbon bonds in a cycloalkane's structure are single and it only contains hydrogen and carbon atoms grouped in a configuration with a single ring.
When a cycloalkane has more than 20 carbon atoms, it is often referred to as a cycloparaffin. The isomers of alkenes make up all cycloalkanes.
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Nothing like cyclobutyne exists. Cyclobutyne, a hydrocarbon molecule, features a triple bond inside of a ring made up of four carbon atoms. This cycloalkyne hasn't been isolated in its purest form because of its high ring strain, which makes it very unstable.
Describe butyne.?Butyne is an organic molecule with the formula HC2CH2CH3, according to chemistry. It is a flammable, colorless gas. 1-Butyne takes part in processes that are typical for terminal alkynes, such as hydrogenation, condensation with formaldehyde, and alkyne metathesis.
Because of its very low torsional barrier and the difficulty in locating it using high-resolution infrared spectroscopy, 2-butyne is of interest to physical chemists.
One of the cycloalkenes is cyclobutene. Although it might be studied, there are currently no applications in real life. It is an easily condensable colorless gas. In a contemporary synthesis, cyclobutanol passes through two stages of dehydration. The ammonium salt OH was first thermolyzed to create the chemical.
In organic chemistry, cycloalkanes are monocyclic saturated hydrocarbons. To put it another way, a cycloalkane has single carbon-carbon bonds throughout its whole structure.
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a gas expands against a constant external pressure of 1.15 atm: the initial volume of the gas is 0.150 l and the final volume is 1.65 l. calculate wgas.
The work done by the gas that expands at constant external pressure ( isobaric expansion) is 174.8 J
What is the work done by the gas that expands at constant external pressure?The work done by the gas that expands at constant external pressure is work done under isobaric conditions.
The work done by an isobaric expansion is calculated with the formula below:
Work done = P (Vf − Vi)
where;
P is pressureVf is final volume of gasVi is initial volume of gasP = 1.15 atm
P is converted to N/m² and volume is converted to m³
1.15 atm = 1.15 * 101325 N/m²
P = 116523.75 N/m²
Vf = 1.65 * 10⁻³ m³
Vi = 0.15 * 10⁻³ m³
W = 116523.75 N/m² ( 1.65 * 10⁻³ m³ - 0.15 * 10⁻³ m³)
Work done = 174.8 J
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