__ is the rate at which an object changes position

The substance added to gasoline and found in the wells of people who live miles from a gas station is an example of non-point source of pollution.

Point source pollution are sources of pollution, radiation, waves, fluid or other substance that has one specific location.

On the other hand, non-point source pollution is a combination of pollutants from a large area rather than from specific identifiable sources such as discharge pipes.

According to this question, a substance added to gasoline is found in the wells of people who live miles from a gas station. This suggests that the pollutants enter from a wide array of sources.

Therefore, it can be said that the source of pollution is a non-point source.

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Given,  

weight of a piece of rock, W = mg = 5N

So, mass of a piece of rock is m = W ÷ g = 5N ÷ 9.8 m/[tex]s^{2}[/tex] = 0.51 kg.

When a force F is applied, it produces an acceleration 'a'. From Newton's second law of motion, F = ma = 0.51 a.

⇒a = F / 0.51.

Acceleration produced by 2nd piece of the rock is a' = 8a.

Assuming the mass of 2nd piece of rock to be same as the 1st piece, force to be applied on 2nd piece is F' = m'a'.

⇒ F' = m' × 8a = 8m'a

If the mass of both pieces of rock are equal, then m' = m = 0.51 kg.

⇒ F' = 0.51kg × 8a

⇒  F' = 0.51kg × 8 (F / 0.51)

⇒  F' = 8F.

Thus, a force equal to 8 times the force applied on 1st piece should be applied on the 2nd piece of the rock to produce an acceleration of 8a (if their masses are equal.

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The horizontal force required for an acceleration of 2.0 m/s² is equal to 54.3 N.

The force of kinetic friction is a type of frictions that acts on a moving object on a surface. In order to calculate the force of kinetic friction, we use the formula F = μN where F is the force of kinetic friction, μ is the coefficient of the kinetic friction, and N is the normal force. However, we need to take into account the force along the x-axis. Therefore, the formula ∑F = μN + ma will help us find the horizontal force.

Let ∑F represent the net force, N represent the normal force, m represent the mass of the box, g represent the acceleration of gravity, µ represent the kinetic friction, and a represent an acceleration of 2 m/s².

∑F = µN + ma

∑F = µmg + ma

∑F = m (µg + a)

∑F = 10 kg (0.35 × 9.8 m/s² + 2 m/s²)

∑F = 10 kg (3.43 m/s² + 2 m/s²)

∑F = 10 kg (5.43 m/s²)

∑F = 54.3 kg × m/s²

∑F = 54.3 N

The net force is equal to 54.3 N. That is the horizontal force required!

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Given data

*The given initial volume of water is V_1 = 2 L

*The given initial temperature of the water is T_i = 20 °C

*The given final temperature of the water is T_f = 40 °C

*The coefficient of volumetric expansion of water is

The formula for the volumetric expansion is given as

Substitute the known values in the above expression as

Logarithmic decrement is the ratio of successive amplitudes in a time series.

The logarithmic decrement δ is equal to the natural logarithm of the ratio of two successive maximum deflections x of oscillating quantity in the same direction:

δ = log( [tex]x_{1} /x_{2}[/tex])

Logarithmic decrement is used to find the damping ratio of an underdamped system in the time domain. It is defined as the natural logarithm of the ratio of any two successive amplitude on the same side of the mean line.

Therefore we get that logarithmic decrement is the ratio of successive amplitudes in a time series.

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The scale reading of a man standing on a scale in an elevator that is accelerating upward at 2.00 m/s2 is 788 N.

Acceleration is the price of change in the velocity of an object with the recognition of time. Accelerations are vector portions. The orientation of an item's acceleration is given by way of the orientation of the internet pressure acting on that item.

Acceleration is the price at which pace adjustments with time, in phrases of both speed and course. A factor or an object shifting in an immediate line is elevated if it hurries up or slows down. movement on a circle is expanded despite the fact that the rate is constant, due to the fact the path is constantly changing.

f = mg - ma

   = 900 - 180

   = 788 N

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The work done on the force on the block is 23.516J

We are given that,

The mass of the block = m= 4.0 kg

The vertical component of the wall at an angle = sinθ = sin 30°

The horizontal component of the wall at an angle = cosθ = cos30°

The acceleration due to gravity = g = 9.81 m/s²

The coefficient of kinetic friction between the block and the wall= μ=0.40

So that to calculate the work done by the force on the block can be given by the expression, for vertical and horizontal component

Wf = Fycosθ

The Wf is the work done by the force Fy (on y-axis) on the block by the horizontal component,

Wf = Fxsinθ

The Wf is the work done by the force Fx (on x-axis) on the block by the vertical component,

Net Fy = sinθ N -mg =0

Net Fx = 0

Therefore, the work done by the force on the block can be assumed by above equations,

Wf = (mgdsinθ)/(sinθ -  μcosθ)

Wf = (4.0kg)(1.0m)(9.81m/s²)/sin30° -(0.40)cos30°

Wf = 33.981/1.445 J

Wf = 23.516J

Thus , the work done by the force on the block would be 23.516J

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The potential energy of the hiker at the first hut is mathematically given as

v = 548800J

Generally, the equation for potential energy is mathematically given as

v = mgh

where,

m = 80kg, g = 9.8, h = 700

therefore

v = 80 x 9.8 x 700

In conclusion, the potential energy of the hiker at the first hut

v = 548800J

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From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:

The kinetic energy is given by:

On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:

Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:

At the beggining of the movement, the value of r corresponds to the radius of the Earth:

At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:

Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:

Isolate the term GM/(R_E+h):

Divide both sides by the factor GM:

Take the reciprocal to both sides of the equation:

Isolate h:

Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:

Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:

The swan will travel 55.15 m during uniform motion before becoming airbone.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 5.8 m/s

a = 0.305 m/s²

By using the second equation, we can calculate the distance before becoming airbone

vt² = vo² + 2a . s

5.8² = 0² + 2 . 0.305 . s

0.61s = 33.64

s = 55.15 m

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The input work of a machine with an efficiency of 20% and an output work of 140 J is 28 J

Input work is the work done on a machine as the input force acts through the input distance.

To calculate the input work of the machine, we use the formula below.

Formula:

Where:

Make Wi the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the input work of the machine is 28 J.

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Since sound expands and loses intensity as it moves farther away, the echo is weaker than the initial sound and has a smaller amplitude. For instance, when a speaker's voice is heard and its echo is compared.

One kind of audio effect that involves gradually delaying a signal is an echo effect. In this instance, after some amount of time, listeners hear the same signal repeated audibly. When the time delay is relatively long (more than 30 milliseconds), listeners can distinguish between the echoes.

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Answer:

D: Availability

Explanation:

correct on edge 2023

The sphere has to be launched 4 times the initial height, h, to hit the same target.

The time taken for the first sphere to hit the target is calculated as follows;

d = V₀t₁

where;

t₁ = d/V₀

The height travelled by the ball;

h = ¹/₂gt₁²

t₁² = 2h/g

t₁ = √(2h/g)

The time of motion of the second sphere when it is launched at a speed of 2V₀.

t₂ = d/2V₀

t₂ = ¹/₂(d/V₀)

t₂ = ¹/₂(t₁)

The height of fall of the second sphere;

¹/₂(t₁) = √(2h/g)

[¹/₂(t₁)]² = 2h/g

t₁²/4 = 2h/g

t₁² = 4(2h/g)

Thus, the height the sphere need to be launched in order to hit the same target is determined by applying kinematic equation.

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The magnetic field in the solenoid due to current 1.2A  is 54.807 x 10⁻⁵ A/m

The No. of Loops in the solenoid, N = 200

Length of the solenoid, l = 55 cm

The current passing through the solenoid, I = 1.2 A

The magnetic field passing through the solenoid can be calculated using the Ampere's law which is

                      B = μ₀nI

where B is the magnetic field

          μ₀ is the permeability of free space

          n is the no. of turns per meter

          I is the current passing through the solenoid

Thus , we can re-write this formula a

                    [tex]B = \frac{\mu_0 N I}{l}[/tex]

Let us substitute the know values in the above equation , we get

                  B = (4 x 3.14 x 10⁻⁷ x 200 x 1.2 ) / (55 x 10⁻²)

    where μ₀ = 4π x 10⁻⁷

                 B = 3014.4 x 10⁻⁷ / 55 x 10⁻²

                 B = 54.807 x 10⁻⁷ x 10²

                 B = 54.807 x 10⁻⁵ A/m

Therefore , the magnetic field passing through the given solenoid is

54.807 x 10⁻⁵ A/m

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magnitude of the momentum of the combined mass immediately after the collision  p = 0. 478 (kg. m/sec)

Mass of bullet : m = 5. 25 (g) = 0. 00525 (kg)

Mass of block : M = 360 (g) = 0. 360 (kg)

Height : h = 8. 75 (m) = 0. 0875 (m)

Here we need to find the momentum :

Now,

As we know that,

The conservation of energy :

Now,

Kinetic energy = Potential energy

= 1/2( m + M)v² = (m+M)gh (m,M is mass of bullet and block)

Now,

v = [tex]\sqrt{2gh}[/tex]

Now,

Momentum can be defined as :

Here,

p = (m+ M) [tex]\sqrt{2gh}[/tex]. . . eqn 1

Putting the values in eqn 1 :

We get,

p = 0.478 (kg. m/sec)

Hence, the momentum : p = 0. 478 (kg. m/sec)

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Less than the angle of incidence, the angle of refraction will exist.

Angle of refraction refers to the angle formed by the refracted ray and the normal at the point of incident.

In a mirror, the angle of incidence and angle of reflection are the same. If the incident ray falls along the normal, the angle of incidence for a plane mirror is 0 degrees rather than 90 degrees.

The behavior of light is described by Fermat's principle, which states that a light ray always chooses the shortest route to its destination. On reflection, the exact same behavior is seen. The angle of incidence and the angle of reflection are equal when a ray is reflected from a plane.

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Due to air friction different mass configurations show the same physics of  non-conservation.

Momentum in an easy way is an amount of motion. right here quantity is measurable because if an item is transferring and has mass, then it has momentum. If an item no longer passes then it has no momentum. but, in normal lifestyles, it has significance but many humans did not understand it.

Momentum may be described as "mass in motion. All items have mass; so if an item is transferring, then it has momentum - it has its mass in motion. the quantity of momentum that an item has relies upon two variables.

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The average atomic mass of lanthanum that has an isotope with an atomic mass of 138.9 amu and an abundance of 99.9 1% and a second isotope with an atomic mass of 137.9 amu and an abundance of 0.09 % is

Average atomic m = Sum of product of atomic m and % abundance /  100

For isotope 1,

Atomic mass = 138.9 amu

% abundance = 99.91 %

For isotope 2,

Atomic mass = 137.9 amu

% abundance = 0.09 %

Average atomic mass = ( 138.9 * 99.91 ) + ( 137.9 * 0.09 ) / 100

Average atomic mass = 13877.5 + 12.41 / 100

Average atomic mass = 138.9 amu

The average atomic mass or average atomic weight of an element is the weighted average mass or weight of atoms in a naturally occurring sample ( i.e., isotopes ) of the element.

Therefore, the average atomic mass of lanthanum is 138.9 amu

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It is best to choose option B. When a star runs out of fuel, it can no longer undergo the merger process and dies. The primary elements of stars are helium and hydrogen.

A white dwarf star's maximum mass is determined by Chandrasekhar's limit, a sort of maximum restricted value. The Chandrasekhar limit is often valued at 1.44 times the mass of the sun, or around 2.765 1030 kg, on a global scale.

In other words, the Chandrasekhar limit is the highest figure that may possibly reach 1.44 times the mass of the sun.

When a high-mass star runs out of gas to burn, it enlarges and changes into a red supergiant. While the bulk of stars gradually fade away, the supergiant stars, often known as supernovae, demolish themselves in a massive explosion. New stars can develop as a result of massive stellar deaths.

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120N  is the force of gravity pulling on a 12kg block accelerating at 10m/s²

F = m × a

F = 10 ×12

F= 120N

The mass (m) and height (h) of the item determine how much gravitational potential energy is there. Based on an object's high position relative to a lower location, gravitational energy is potential energy that is stored in the object.

This energy can be utilised later to move an item since it can be stored and utilised at a later time. Three variables—mass, gravity, and height—determine the gravitational potential energy. Energy is directly inversely proportional to all three variables.

Because the highest amount of energy that may be converted into other forms is called potential energy. You need more energy to move the thing at a greater height.

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The phenomenon that occurs here is known as the snell's window, and the cone angle is 98 degrees.

To calculate the cone angle,

The cone angle is equal to two times the critical angle which is say, Ф

To calculate the critical angle Ф take the equation sinФ = n1÷n2 where

n1 is the refractive index of air, and n2 is the refractive index of water.

The refractive index of air, n1 = 1,

The refractive index of water, n2 = 1.33,

Substituting these values in the equation sinФ = n1÷n2, the equation becomes

sinФ = 1÷1.33

solving for Ф

Ф = [tex]sin^{-1}[/tex](1÷1.33)

Ф = 49°

Cone angle = 2×Ф

Cone angle = 2×49

Cone angle = 98°.

The phenomenon taking place here is known as snell's window. In this phenomenon, the person under the water sees everything above the surface through a cone of light whose width is about 96°-98°. Whatever is outside this cone appears dark to the person who is under the water. This is caused due to the refraction of light in different mediums.

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21.168 m/s velocity of the ball just prior to striking the ground.

Round to nearest hundreds is 21.17

The direction of the movement of the body or the object is defined by its velocity. Most of the time, speed is a scalar quantity. In its purest form, velocity is a vector quantity. It measures how quickly a distance changes. It is the rate at which displacement is changing.

“equations of motion”

How long does it take?

s = ut + ½ at²

23 m = 0 + ½ *9.81m/s² * t²

23 m = 4.905 t²

t² = 23 / 4.905

t² = 4.689

t =2.165s

What velocity will it hit the ground?

Take ↓ direction as +

v = u + at

v = 0 + 9.81 m/s² * 2.16 s

v =21.168 m/s

Velocity = 21.168 m/s downwards. ( have left you to decide on significant digits in the answer.

round to nearest hundreds is 21.17

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a) The magnitude of the impulse is 2.39 × [tex]10^{3}[/tex] N. b) Average force on the passenger during the collision is 4.78 × [tex]10^{5}[/tex] N. c) impulse is 1.6 × [tex]10^{3}[/tex] N.s d) The corresponding average force would be 3.52 × [tex]10^{5}[/tex] N.

a) By energy conservation, the speed of the passenger when the elevator hits the floor is

1/2 mv² = mgh

v = √2gh = [tex]\sqrt{2(9.8)(36)}[/tex]

  = 26.6 m/s

The magnitude of the impulse is

J = |Δp| = m|Δv| = mv = (90kg) (26.6m/s) ≈ 2.39 × 10³ N.s

b) With duration of Δt = 5.0 × [tex]10^{-3}[/tex] s for the collision, the average force is

[tex]F_{avg}[/tex] = J/ Δt = 2.39×10³ N.s / 5.0 × [tex]10^{-3}[/tex] s

       ≈ 4.78 × [tex]10^{5}[/tex] N

c) If the passenger were to jump upward with a speed of [tex]v^{'}[/tex]= 7.0 m/s, then the resulting downward velocity would be

[tex]v^{n}[/tex] = v- [tex]v^{'}[/tex]

    = 26.6m/s - 7.0 m/s

    = 19.6 m/s

The magnitude of the impulse becomes

[tex]J^{n}[/tex] = |Δ[tex]p^{n}[/tex]| = m|Δ[tex]v^{n}[/tex]| = m[tex]v^{n}[/tex] = (90kg) (19.6 m/s)

                                          ≈ 1.76 × 10³³N.s

d) The corresponding average force which is

[tex]F_{avg } ^{n}[/tex] = [tex]J^{n}[/tex]/ Δt = 1.76 × 10³ N.s/ 5.0 × [tex]10^{-3}[/tex] s

                     ≈ 3.52 × [tex]10^{5}[/tex]N

Therefore the magnitude of the impulse is 26.6 m/s, average force on the passenger during the collision is 4.78 × [tex]10^{5}[/tex]N, the magnitude of the impulse is 1.76×[tex]10^{3}[/tex]N.s, average force is 3.52 × [tex]10^{5}[/tex].

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Both gravitational potential energy (PE) and kinetic energy (KE) are present on a swinging pendulum bob. The KE is at its highest and the PE is zero when the bob is in its lowest position. The KE is zero and the PE is at its highest value when the bob is in its highest position on both sides.

The pendulum moves at its fastest while it is passing through the middle position. We could interpret this in terms of energy conservation. Bob is at his shortest height when he is in the average position. When Bob is positioned at an extreme, such as the right, it is slightly higher than when it is in the middle.

The bob's center of mass serves as the standard for determining the pendulum's "length." The center of gravity of the bob would fluctuate in a convoluted manner as the mercury drained out of a simple spherical bob with a small hole in the bottom. The center of gravity would be in the middle of the bob when it is totally full.

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The required speed is 15.35 m/s, if air resistance is ignored.

The magnitude of average force of air resistance is 1.0341N.

a) V = √2gh

The required speed is

V = √2(9.8)(12)

V = 15.35m/s

b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])

    W = (mg - f)h

 ( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))

(1.421 - f)12 = 4.64

Force of an air resistance  = 1.0341N

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Since the magnetic force and velocity are orthogonal, the velocity only changes in direction but not in magnitude . Circular motion is the end consequence. The force is in the opposite direction from the right-hand rule and has a negative charge.

Uniform In circular motion, an object moves in two dimensions with a constant speed in a fixed circular direction; however, because the object's direction changes at every point, the velocity also changes, and the direction at each point is always the tangent.

In physics, magnetic force is referred to as an object's maximal size and direction. Both vector and scalar values use magnetic force as a common factor. We understand that by definition

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Answer: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal.

Explanation: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal. The resultant motion is circular. The force has a negative charge and is directed in the opposite direction from the right-hand rule.

Uniform In a circular motion, an item moves in two dimensions with a constant speed in a fixed circular direction; yet, because the object's direction varies at each point, the velocity also alters, and the direction at each point is consistently the tangent.

As an object's maximum size and direction, the magnetic force is referred to in physics. Magnetic force is a factor that is present in both scalar and vector values. We comprehend that by nature.

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The work required to move the motorcycle from rest to a speed of v/4 is 1/16 times of the initial work w.

As we already know, from the work energy theorem,

That work done by all the conservative forces and all the none conservative forces on the body is equal to the change in kinetic energy of that body.

So, in formula form, it can be written as,

W = ∆K

Where w is work done on the body and ∆K is the change in kinetic energy of the body.

So, if now we assume, that the work done to increase the velocity of the body from zero to V is w, then we can write,

w = 1/2mv² ..... Equation 1

m is the mass of the body.

Now, as per the question,

Let us say the work done needed to increase the speed of the body from rest to v/4 is w', then we can write,

w' = 1/2m(v/4)² ..... Equation 2

Now,

Dividing equation 2 by 1,

We get,

w'/w = 1/16

So, the value of w' is w/16.

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If the additional mass is attached to the ball, it must be large enough to increase the downward acceleration by 35%.

What is acceleration?
An object is said to have been accelerated if its velocity changes. An object's velocity can change depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, or a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both. Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is either the first derivative of velocity in relation to time or even the second derivative of position in relation to time.

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