She walked 3 1/4 miles per day.
Given,
Jane walked 9 3/4 miles in the course of 3 days.
If we calculate this mixed number into a fraction,
We get:
9 3/4 miles = {(9×4)+3} / 4 miles
=39/4 miles.
So, Jane walks 39/4 miles in 3 days.
Therefore, in one day she walked:
(39/4 ÷ 3) miles
= 13/4 miles per day
Let's now convert this fraction into a mixed number:
when 13 is divided by 4 we get the remainder as 1 and the quotient as 3.
So, a mixed number is given by:
quotient remainder/divisor
Hence 13/4 = 3 1/4.
So, Jane walked 3 1/4 miles per day.
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Which set of ordered pairs does not show y as a function of x? A. {(3,-2); (5,-3); (7,-4); (9,-5)} B. O {(3,-2); (6,-2); (9,-2); (12,-2)} c.{(4, -2); (5,-3); (6,-4); (7,-5)} D.O{(4, -2); (5,-3); (4,-8); (5,-9)}
Find the first three terms of this sequence Un=5n-2n3.
The first three terms of the sequence defined by the formula; Un=5n-2n³ as in the task content are; 3, -6 and -39 respectively.
What are the first three terms of the sequence given by the formula; Un=5n-2n³?It follows from the task content that the first three terms of the sequence defined by the formula be determined.
On this note, it follows that the first three terms are at; n = 1, n = 2 and n = 3 respectively.
Hence we have;
1st term; U(1) = 5(1) - 2(1)³ = 3.2nd term; U(2) = 5(2) - 2(2)³ = -6.3rd term; U(3) = 5(3) - 2(3)³ = -39.Hence, the first three terms are; 3, -6 and -39.
The first three terms of the sequence are as listed above.
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What is the value of the trig ratio sin A?
The sine relation is given by the length of the opposite leg to the angle over the length of the hypotenuse.
So, for the given triangle, we have:
[tex]\begin{gathered} \sin A=\frac{BC}{AC}\\ \\ \sin A=\frac{20}{29} \end{gathered}[/tex]Therefore the value of sin A is 20/29.
I'm confused about this problem can someone explain?
Answer:
32.50x + 7.50 < 235
Step-by-step explanation:
All the cost have to be less than 325. x stands for the number of people buying tickets.
3: A Bunch of SystemsSolve each system of equations without graphing and show your reasoning. Then, check yoursolutions,
Use the elimination method to solve the given system of equations.
To do so, multiply the first equation by -3 so that the coefficient of x in the first equation becomes the additive inverse of the coefficient of x in the second equation:
[tex]\begin{gathered} -3(2x+3y)=-3(16) \\ \Rightarrow-6x-9y=-48 \end{gathered}[/tex]Then, the system is equivalent to:
[tex]\begin{gathered} -6x-9y=-48 \\ 6x-5y=20 \end{gathered}[/tex]Add both equations to eliminate the variable x and to obtain an equation in terms of the variable y only:
[tex]\begin{gathered} (-6x-9y)+(6x-5y)=-48+20 \\ \Rightarrow-6x-9y+6x-5y=-28 \\ \Rightarrow-14y=-28 \\ \Rightarrow y=\frac{-28}{-14} \\ \therefore y=2 \end{gathered}[/tex]Replace y=2 into the first equation to find the value of x:
[tex]\begin{gathered} 2x+3y=16 \\ \Rightarrow2x+3(2)=16 \\ \Rightarrow2x+6=16 \\ \Rightarrow2x=16-6 \\ \Rightarrow2x=10 \\ \Rightarrow x=\frac{10}{2} \\ \therefore x=5 \end{gathered}[/tex]Replace y=2 and x=5 into the second equation to confirm the answer:
[tex]\begin{gathered} 6x-5y=20 \\ \Rightarrow6(5)-5(2)=20 \\ \Rightarrow30-10=20 \\ \Rightarrow20=20 \end{gathered}[/tex]Therefore, the solution to the system of equations is x=5, y=2.
The pro shop at the Hidden Oaks Country Club ordered two brands of golf balls. Swinger balls cost$2.10 each and the Supra balls cost $1.00 each. The total cost of Swinger balls exceeded the total costof the Supra balls by $330.00. If an equal number of each brand was ordered, how many dozens ofeach brand were ordered?AnswerHow to enter your answer (opens in new window)KeypadKeyboard Shortcutdozen
The Solution:
Given that equal number of each brand of golf ball was ordered.
Let the number of each brand ordered be represented with n
Each swinger ball cost $2.10
So, the total cost of the swinger ball ordered is:
[tex]2.10n[/tex]Each Supra ball cost $1.00
So, the total cost of the supra ball ordered is:
[tex]\begin{gathered} 1.00\times n \\ \text{which becomes}\colon \\ n \end{gathered}[/tex]Given that the total cost of the Swinger balls exceeded the total cost of the Supra balls by $330.00. We have the linear equation below:
[tex]2.1n=n+330[/tex]We are required to find the number of dozens of each brand of golf balls that were ordered.
So, we shall solve for n and then divide the value by 12.
[tex]\begin{gathered} 2.1n=n+330 \\ \text{collecting the like terms, we get} \\ 2.1n-n=330 \\ 1.1n=330 \end{gathered}[/tex]Dividing both sides by 1.1, we get
[tex]\begin{gathered} \frac{1.1n}{1.1}=\frac{330}{1.1} \\ \\ n=300\text{ balls} \end{gathered}[/tex]Dividing 300 by 12 (since 1 dozen = 12 balls), we get
[tex]\frac{300}{12}=25\text{ dozens of each brand of golf balls were ordered.}[/tex]Therefore, the correct answer is 25 dozens.
Simplify the problem and use the chart to find the answer.
When an exponent is a fraction, the number of the numerator is the exponent and the number of the denominator is the radical number:
Then, in this case:
Since
[tex]\sqrt[2]{x^3}=\sqrt[]{x^3}[/tex](when the number of the radical is 2 we can write it without the 2), then
[tex]\sqrt[2]{x^3}=\sqrt[]{x^3}[/tex]Then
Answer: III
A translation is a type of transformation in which a figure is flipped,TrueFalse
Translate the following word phrases to an algebraic expression and simplify: “8 times the difference of 6 times a number and 3”
SOLUTION:
Step 1:
In this question, we are meant to:
Translate the following word phrases to an algebraic expression and simplify:
“8 times the difference of 6 times a number and 3”
Step 2:
Assuming the unknown number be y, we have that:
[tex]\begin{gathered} 8\text{ ( 6y - 3 )} \\ =\text{ 48 y - 24} \end{gathered}[/tex]CONCLUSION:
The final answer is:
[tex]48y\text{ - 24}[/tex]
Mark noticed the probability that a certain player hits a home run in a single game is 0.175. Mark interested in the variability of the number of home runs if this player plays 200 games. If Mark uses the normal approximation of the binomial distribution to model the number of home runs, what is the standard deviation for a total of 200 games?
The standard deviation for a total of 200 games is 5.3735.
How to calculate the standard deviation?Let X = number of home runs of this player in 200 games played by him.
p = probability that a this player hits a home run in a single game and this is given to be 0.175.
Where np = Mean of X and √{np(1 - p)} is the standard deviation of X.
Here n = 200 and p = 0.175. So, the standard deviation for a total of 200 games is the standard deviation for a total of X
= √(200 x 0.175 x 0.825) / 2
= 5.3735
The value is 5.3735.
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In a circle with radius 8, an angle measuring radians intercepts an arc. Find thelength of the arc in simplest form.
s = 28π/3
Explanation:The radius, r = 8
The angle, θ = 7π/6 radian
The length of the arc, s = rθ
s = 8 x 7π/6
s = 28π/3
A rectangular vegetable garden will have a width that is 3 feet less than the length, and an area of 54 square feet. If x
represents the length, then the length can be found by solving the equation:
x(x-3) = 54
What is the length, x, of the garden?
The length is
feet.
The solution is?
To determine the length of the rectangular flower garden, we need to derive equations from the given measurements and relations. The given measurements are the area, and the relation of the width and the length. From these, we generate the equation needed. We do as follows:
Area = Length x Width
where length = x ft
width = x - 3 ft
area = 54 ft^2
54 ft^2 = x ft (x -3) ft
54 ft^2 = x^2 - 3x ft^2
Solving for the value of x, we will have two values which are
x = -6 ft ( NOTE: this value can't be the answer since we cannot have a negative value for the length)
x = 9 ft = length
in the figure shown MN is parallel to segment YZ what is the length of segment YZ
We will solve this question using the similar angle theorem
The shape consist of two triangles which i am going to draw out,
One is a big triangle while the other is a small triangle
Let NZ = a
To find NZ We will equate the ratio of the big triangle to that of the small triangle
[tex]\frac{7.5\operatorname{cm}}{3\operatorname{cm}}=\frac{(a+5)cm}{5\operatorname{cm}}[/tex]We then cross multiply to get,
[tex]\begin{gathered} 3(a+5)=7.5\times5 \\ 3a+15=37.5 \\ by\text{ collecting like terms we will have that} \\ 3a=37.5-15 \\ 3a=22.5 \\ \frac{3a}{3}=\frac{22.5}{3} \\ a=7.5\operatorname{cm} \end{gathered}[/tex]Therefore XZ=XN+NZ
[tex]XZ=5+7.5=12.5\operatorname{cm}[/tex]To calculate YZ ,
We will use the pythagorean theorem,
[tex]\begin{gathered} XZ^2=YZ^2+XY^2 \\ 12.5^2=YZ^2+7.5^2 \\ 156.25=YZ^2+56.25 \\ YZ^2=156.25-56.25 \\ YZ^2=100 \\ YZ=\sqrt[]{100} \\ \vec{YZ}=10.0cm \end{gathered}[/tex]Therefore ,
The value of YZ is
[tex]\vec{YZ}=10.0\operatorname{cm}[/tex]Hence ,
The correct answer is OPTION B
Use the Law of Sines to solve the triangle. Round your answers to two decimal places. (Let b = 5.1.)
Given:-
An image with triangle.
To find:-
The value of B,a,c.
So the laws of sines are,
[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]So now we substitute the known values. we get,
[tex]\frac{\sin16}{a}=\frac{\sin B}{5.1}=\frac{\sin125}{c}[/tex]Now we find the value of B,
Since the sum of angles of the triangle is 180. we get,
[tex]\begin{gathered} A+B+C=180 \\ 16+B+125=180 \\ B+141=180 \\ B=180-141 \\ B=39 \end{gathered}[/tex]So substituting the value we get,
[tex]\frac{\sin16}{a}=\frac{\sin 39}{5.1}=\frac{\sin125}{c}[/tex]Now we find the value of a. we get,
[tex]\begin{gathered} \frac{\sin16}{a}=\frac{\sin 39}{5.1} \\ \frac{0.2756}{a}=\frac{0.6293}{5.1} \\ a=\frac{0.2756\times5.1}{0.6293} \\ a=2.2335 \end{gathered}[/tex]Now we find c. we get,
[tex]\frac{0.2756}{2.2335}=\frac{\sin 125}{c}[/tex]So
The 250 m between Sam's house and the tennis court corresponds to 5 cm on a town
map. What is the actual distance between Sam's school and the library if they are 8.4
cm apart on the same map?
Sam's school and the library are actually 420m apart.
What is the Scale Drawing?A scale drawing is a more compact representation of the original image, structure, or object.
The town is depicted at scale on the town map.
Original dimensions divided by the scale drawing's dimensions gives the drawing's scale.
The first step is to establish the map's scale in order to calculate the precise distance between Sam's school and the library.
Map scale: 250 m / 5 cm = 50
In this scale, 1 cm equals 50 m.
Scale of the drawing times the distance on the map equals the actual distance between Sam's school and the library.
50 x 8.4 = 420m
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90 minutes for 3 typed pages; 60 minutes for a a typed pages write a proportion for each phrase and solve it
90 minutes for 3 typed pages; 60 minutes for a a typed pages write a proportion for each phrase and solve it
we have that
90/3=60/a
solve for a
a=(60*3)/90
a=2 pagesProfessor Ivy’s students have a Mean grade of 69.5 and a Standard Deviation of 6.5.3. If Johnny has an 82 in the class, what would the z-score for Johnny’s grade be? (round to the tenthsplace)4. What percentile does Johnny’s score put him in? (round to the nearest whole number)
Given:
Mean,ц = 69.5
Standard deviation, σ = 6.5
Let's solve for the following:
• 3. If Johnny has an 82 in the class, what would the z-score for Johnny’s grade be?
Apply the z-score formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]Where:
x = 82
ц = 69.5
σ = 6.5
Thus, we have:
[tex]\begin{gathered} z=\frac{82-69.5}{6.5} \\ \\ z=\frac{12.5}{6.5} \\ \\ x=1.9 \end{gathered}[/tex]Therefore, the z-score is 1.9
Question 4.
Here, we are to find P(Z<1.9).
Using the standard normal distribution table, we have:
NORMSDIST(1.9) = 0.9712
Now convert to percentage:
0.9712 x 100 = 97.12% = 97%
ANSWER:
3). 1.9
4.) 97%
Camden, a florist, is dividing 56 flowers equally into 8 bouquets. He uses division to find that he can put 7 flowers in each bouquet. Which subtraction equation could he use to check his answer?
The subtraction equation that Camden could use to check his answer is, x = 56 - 8 x 7.
What is a subtraction equation?A subtraction equation is an equation, which is a mathematical statement that two mathematical expressions share equality, which involves the use of the subtraction operation.
The result of a subtraction operation is known as the difference. The other parts of a subtraction operation are the minuend and the subtrahend.
The total number of flowers for the bouquets = 56
The number of bouquets = 8
The number of flowers for each bouquet = 7 (56/8)
Check:
x = 56 - 7 x 8
x = 56 - 56
x = 0
To check if the answer is correct, Camden should multiply 7 by 8 and then subtract the product from 56.
Thus, the difference in the subraction equation x = 56 - 8 x 7 that Camden used is zero, showing that his earlier division operation was correct.
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Solve the triangle with the given measures. More than one triangle may be possibletriangle ABCM
then
[tex]undefined[/tex]Find the equations (in terms of x) of the line through the points (-2,-3) and (3,-5)
The general equation of a line passing through two points (xb₁,y₁)Pxb₂,y₂) is expressed as
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{where} \\ m\Rightarrow slope\text{ of the line, expr}essed\text{ as }m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ (x_1,y_1)\Rightarrow coordinate_{}\text{ of point P} \\ (x_2,y_2)\Rightarrow coordinate_{}\text{ of point Q} \end{gathered}[/tex]Given that the coordinates of the two points are (-2, -3) and (3, -5), we have
[tex]\begin{gathered} (x_1,y_1)\Rightarrow(-2,\text{ -3)} \\ (x_2,y_2)\Rightarrow(3,\text{ -5)} \end{gathered}[/tex]Step 1:
Evaluate the slope o the line.
The slope is thus evaluated as
[tex]\begin{gathered} m\text{ = = }\frac{y_2-y_1}{x_2-x_1} \\ \text{ = }\frac{\text{-5-(-3)}}{3-(-2)} \\ =\frac{-5+3}{3+2} \\ \Rightarrow m\text{ = -}\frac{2}{5} \end{gathered}[/tex]Step 2:
Substitute the values of x₁,
Thus, we have
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ x_1=-2 \\ y_1=-3 \\ m\text{ =- }\frac{2}{5} \\ \text{thus,} \\ y-(-3)\text{ = -}\frac{2}{5}(x-(-2)) \\ y+3\text{ =- }\frac{2}{5}(x+2) \end{gathered}[/tex]Step 3:
Make .
[tex]\begin{gathered} y+3\text{ =- }\frac{2}{5}(x+2) \\ \text{Multiply both sides of the equation by 5 } \\ 5(y+3)\text{ = -2(x+2)} \\ \text{open brackets} \\ 5y\text{ + 15 =- 2x - 4} \\ \Rightarrow5y\text{ =- 2x - 4 -15} \\ 5y\text{ = -2x-1}9 \\ \text{divide both sides of the equation by the coefficient of y, which is 5.} \\ \text{thus,} \\ \frac{5y}{5}=\frac{-\text{2x-1}9}{5} \\ \Rightarrow y\text{ =- }\frac{2}{5}x\text{ - }\frac{19}{5} \end{gathered}[/tex]Hence, the equation of the line is
[tex]y\text{ = -}\frac{2}{5}x\text{ - }\frac{19}{5}[/tex]y₁ and m into the general equation of the line.
Given the definitions of f(a) and g(x) below, find the value of (19)( 1),f (x) = x2 + 3x – 11g(x) = 3a + 6
The given functions are,
[tex]\begin{gathered} f(x)=x^2+3x-11_{} \\ g(x)=3x+6 \end{gathered}[/tex]Fog can be determined as,
[tex]\begin{gathered} \text{fog}=f(g(x)) \\ =f(3x+6) \\ =(3x+6)^2+3(3x+6)-11 \\ =9x^2+36+36x+9x+18-11 \\ =9x^2+45x+43 \end{gathered}[/tex]The value of fog(-1) can be determined as,
[tex]\begin{gathered} \text{fog}(-1)=9(-1)^2+45(-1)+43 \\ =9-45+43 \\ =7 \end{gathered}[/tex]Thus, the requried value is 7.
I ONLY need help with the last question help me with special Angles in a circle..GEOMETRY
We want to know the measure of the angle BCD. In this case, we see that it is an inscribed angle, and then its measure is half of the arc it intercepts (in this case BD).
With this in mind,
[tex]m\measuredangle BCD=\frac{1}{2}m\hat{BD}=\frac{1}{2}(130^{\circ})=65^{\circ}[/tex]And then, the angle BCD has 65°.
The equation for the line of best fit is shown below.What does the y-intercept represent? A. the cost to upload an unlimited amount of files B. the cost to enroll in the file sharing service C. the cost per file uploaded D. the cost per Mb uploaded
Answer:
B. the cost to enroll in the file-sharing service
Explanation:
The y-intercept is the cost when x = 0. It means that it is the cost of the service when the customer uploads 0 Mb, so it should represent the cost to enroll in the file-sharing service.
A collection of dimes and quarters has a value of $1.35. List all possible combinations of dimes and quarters. Remember to write a let statement
3 combinations:
3 quarters and 6 dimes
5 quarters and 1 dime
1 quarter and 11 dimes
1) Remember that a dime corresponds to $0.10 and a quarter to $0.25. And the value we want to find is $1.35
2) As we can see the last digit on $1.35 is 5 then we can infer that we're going to need an odd number of quarters ($0.25). Also, notice that we need whole numbers for the quantities of each coin. In other words, multiples of 0.10 and 0.25 whose sum yields to $1.35. So let's do it step by step:
So, we can write out the following list of combinations:
q (quarter) 3 q = 3 x 0.25 = $ 0.75
d (dimes) 6 d = 6 x 0.10 = $ 0.60
0.60 + 0.75 = 1.35
2.2) Another possible combination:
q (quarter) 5 q = 5 x 0.25 = $ 1.25
d (dimes) 1 d = 1 x 0.10 = $ 0.10
0.10+1.25= 1.35
2.3)
q (quarter) 1 q = 1 x 0.25 = $ 0.25
d (dimes) 11 d = 11x 0.10 = $ 1.10
0.25+1.10 = 1.35
3) Hence, considering that we need to combine dimes and quarters and their sum must be lesser than $1.35 We have three combinations with whole numbers of dimes and quarters:
3 quarters and 6 dimes
5 quarters and 1 dime
1 quarter and 11 dimes
A manager recorded the performance review scores for each employee and placed the results in the bar chart below. All employees received a rating on each of the Evaluation Categories. If Person 6 obtained the highest score possible, what score did Person 3 receive? Use the graph and tables below.EVALUATION CATEGORIESRATINGGeneral Quality of WorkDependabilityJob KnowledgeCommunication SkillsPersonalityManagement AbilityContribution to GroupProductivityAchievement of GoalsRating ScaleSCOREDESCRIPTION5Excellent4Very Good3Good2Fair1Poor253530
SOLUTION
Comparing the graphs and the options, it follows that each line on the graph represents 5 points. This means the person 6 obtained a score of 45, comparing this to the person 3, it means the person 3 obtained a score of 35.
So the answer is 35.
For the rating since person 6 has the highest possible score, which is 45, person 3 score becomes
[tex]\begin{gathered} \frac{35}{45}\times5 \\ =3.88888888 \\ which\text{ is approximately 4} \end{gathered}[/tex]so we can classify person 3 as very good
Katherine bought à sandwich for 5 1/2 dollar and a adrink for $2.60.If she paid for her meal with a $ 10 bill how much money did she have left?
To find out how much Katherin have left we need to substrac the amount she spent:
[tex]10-5\frac{1}{2}-2.6=10-5.5-2.6=1.9[/tex]Therefore she has $1.9 left.
To do this same problem in fraction form we need to convert the 2.6 in fraction, to do this we multiply the number by 10 and divided by ten. Then:
[tex]2.6\cdot\frac{10}{10}=\frac{26}{10}=\frac{13}{5}[/tex]then we have:
[tex]\begin{gathered} 10-5\frac{1}{2}-\frac{13}{5}=10-\frac{11}{2}-\frac{13}{5} \\ =\frac{100-55-26}{10} \\ =\frac{19}{10} \end{gathered}[/tex]Therefore, the answer in decimal form is 19/10 dollars.
I need help with this practice problem I’m having trouble solving it
A generic cosecant function is
[tex]f(x)=A\csc (kx+\theta)+C[/tex]We must find A, k, θ, and C using the information that we have.
Finding A:
To find A we can use the range of the function, we know there is a gap between -9 and 5, that's the crucial information, the value of A will be the mean of |-9| and |5| (in modulus!), therefore
[tex]A=\frac{|-9|+|5|}{2}=\frac{9+5}{2}=\frac{14}{2}=7[/tex]Therefore
[tex]f(x)=7\csc (kx+\theta)+C[/tex]Finding C:
We can use the fact that we know A and find C, let's suppose that
[tex]\csc (kx+\theta)=1[/tex]For an unknown value of x, it doesn't matter, using the range again we can use the fact that 5 is a local minimum of the function, therefore, when the csc(kx + θ) is equal to 1 we have that the function is equal to 5
[tex]\begin{gathered} 5=7\cdot1+C \\ \\ C=-2 \end{gathered}[/tex]And we find that C = -2. Tip: You can also suppose that it's -1 and use -9 = 7 + C, the result will be the same.
Finding k:
Now we will use the asymptotes, we have two consecutive asymptotes at x = 0 and x = 2π, it means that the sin(kx) is zero at x = 0 and the next zero is at x = 2π, we know that sin(x) is zero every time it's a multiple of π, which gives us
[tex]\begin{gathered} \sin (0)=0\Rightarrow\sin (k\cdot0)=0\text{ (first zero | first asymptote)} \\ \sin (\pi)=0\Rightarrow\sin (2k\pi)=0\Rightarrow k=\frac{1}{2}\text{ (second zero | second asymptote)} \end{gathered}[/tex]Therefore, k = 1/2
[tex]f(x)=7\csc (\frac{x}{2}+\theta)-2[/tex]Finding θ:
It's the easiest one, since we have a zero at x = 0 it implies that θ = 0
Therefore our function is
[tex]f(x)=7\csc (\frac{x}{2})-2[/tex]Final answer:
[tex]f(x)=7\csc \mleft(\frac{x}{2}\mright)-2[/tex]
The sum of three consecutive integers is -39. What are the three numbers? Enter your answer as three numbers separated by a comma.
Answer:
-12, -13, and -14
Explanation:
x, y, and z are the three consecutive numbers and they sum -39, so we can write the following equation
x + y + z = -39
Since these numbers are consecutives, we get
y = x + 1
z = x + 2
So, replacing these equation on the first one and solving for x, we get
x + y + z = -39
x + (x + 1) + (x + 2) = -39
x + x + 1 + x + 2 = -39
3x + 3 = -39
3x + 3 - 3 = -39 -3
3x = -42
3x/3 = -42/3
x = -14
Then, y and z are
y = -14 + 1 = -13
z = -14 + 2 = -12
Therefore, the consecutive numbers are
-12, -13, and -14
what is the domain and range of {(1,0), (2,0), (3,0) (4,0), (5,0)}
We have the following:
The domain is the input values or the values of x and the range is the output values or the values of y
Therefore:
[tex]\begin{gathered} D=\mleft\lbrace{}1,2,3,4,5\mright\rbrace \\ R=\mleft\lbrace0\mright\rbrace \end{gathered}[/tex]Sketch the vectors u and w with angle θ between them and sketch the resultant.
Given:
Two vectors (u) and (w) and the angle between them θ
[tex]\begin{gathered} |u|=50 \\ |w|=12 \\ \theta=35\degree \end{gathered}[/tex]the sketch of the vectors will be as shown in the following figure:
As shown, the resultant vector is the blue line segment
The vector R has a magnitude = 60.22
And the angle between u and R = 5.56°
