Kara's original financial plan required that she save $220 amonth for two years in order to have $5,280 for the downpayment on a car. However, after one year she has onlymanaged to save $2,300. How much will Kara have to save each month in the second year in order to reach her original goal of $5,280?

Kara's Original Financial Plan Required That She Save $220 Amonth For Two Years In Order To Have $5,280

Answers

Answer 1

given data:

the amount needed to pay the downpayment of the car = $5280.

original financial plan = $220 per month.

The amount kara saved after 1 year = $2300.

the balance amount she needed to save

[tex]\begin{gathered} =5280-2300 \\ =2980 \end{gathered}[/tex]

now, divide the balance amount by 12, because 1 year =12 months.

[tex]\begin{gathered} =\frac{2980}{12} \\ =248.3 \end{gathered}[/tex]

Thus, kara needs to save 248 dollors each month in order to have 5280 dollors after a year.


Related Questions

Point B is on line segment AC. Given BC = 10 and AB = 5, determine the lengthAC.Answer: AC= Anyone know how to solve these???

Answers

3

1) Let's sketch that, to better understand this:

2) Considering the Segment Addition Postulate, we can write that:

DF = DE + EF Plug into that the given values

9 = 6 + EF

9-6 = 6-6 + EF

3 = EF

EF =3

3) Hence, the line segment EF is 3 units long

The polynomial expression x(3x^2+25)(10x^2+4x+6), where x is in inches, can be used to mod the number of cubic inches of cement that will be needed for a new porch. The cement contractor used 2 for the value of x.

Answers

[tex]x(3x^2+25)(10x^2+4x+6)[/tex]

Since x is given in cubic inches, let's split the expression like this:

[tex]\begin{gathered} h=height=x \\ w=width=(3x^2+25) \\ l=length=(10x^2+4x+6) \end{gathered}[/tex]

For x = 2:

[tex]\begin{gathered} h=2in \\ w=3(2)^2+25=37in \\ l=10(2)^2+4(2)+6=54in \end{gathered}[/tex]

What is the area of the real object that the scale drawing models?Scale factor: 1:3Area =6 square cmScale drawingOA. 54 square cmOB. 2 square cmO C. 18 square cmD. 6 square cmReal object

Answers

We have a drawing object with an area of 6 square centimeters. Since we have a scale factor of 1 : 3, it means that the real object is 3 times greater than the drawing object.

Therefore, if the drawing object has an area of 6 square centimeters, then the real object will have:

[tex]6cm^2*3=18cm^2[/tex]

The real object will be 3 times greater than the one in the drawing.

Therefore, in summary, the real object will have 18 square centimeters (.

you want to buy one pair of pants, one t-shirt, and several pairs of socks. the pants cost $24.95, the t-shirt cost $22.50 and the socks are $5.95 per pair. how many pairs of socks can you buy if you have $80 to spend?*for this question you have to write and inequality solve it and answer the question in words*

Answers

ANSWER

5 pairs

EXPLANATION

We have that:

- one pair of pants cost $24.95

- one t-shirt costs $22.50

- one pair of socks cost $5.95

You want to buy one pair of pants, one t-shirt and several pairs of socks and you don't want to spend more than $80.

This means that everything you spend must be less than or equal to $80.

Let the number of pairs of socks you can buy be x.

This therefore means that:

[tex]\begin{gathered} 24.95+22.50+(5.95\cdot x)\text{ }\leq80 \\ \Rightarrow\text{ }24.95\text{ + 22.50 + 5.95x }\leq80 \\ \text{Find x:} \\ 47.45\text{ + 5.95x }\leq80 \\ \Rightarrow\text{ 5.95x }\leq80\text{ - 47.45} \\ 5.95x\text{ }\leq32.55 \\ x\text{ }\leq\frac{32.55}{5.95} \\ x\leq5.47 \end{gathered}[/tex]

Because we know that the number of pairs of socks must be a whole number, we have to approximiate to whole number, which will be:

x = 5

Therefore, you can buy at most 5 pairs of socks.

The problem is below, we know the man weighs 60, the cat weighs 10 but we’re having a hard time explaining how

Answers

Given data:

The weight of man and daughter = 90

The weight of man and cat is = 70

The weight of cat and daughter = 40 .

The man weights 60 kg.

then daughter weight = 90-60 = 30.

Thus the daughter weight is 30kg.

therefore the cat weight iwith daughter, 40-30 = 10 .

also with father, 70-60 = 10 .

Thus, the father weight is 60 kg.

The daughter weight is 30 kg and

The cat weight is 10 kg.

which equation represents a line having a slope of 5/2 and a y intercept of (0,-4)

Answers

First you must know the standard equation of a line and this is expressed as:

[tex]y\text{ = mx+c}[/tex]

where:

m is the slope of the line

c is the intercept

Given

Slope m = 5/2

Next is to get the intercept c:

To do that, you will substitute m = 5/2 and the coordinate (0, -4) into the equation above as shown:

[tex]\begin{gathered} -4\text{ = 5/2(0)+c} \\ -4\text{ = 0+c} \\ c\text{ = -4} \end{gathered}[/tex]

Next is to get the required equation by substituting m = 5/2 and c = -4 into the equation above as shown:

[tex]\begin{gathered} y\text{ = mx + c} \\ y\text{ = }\frac{5}{2}x\text{ +(-4)} \\ y\text{ = }\frac{5}{2}x\text{ - 4} \end{gathered}[/tex]

Hence the required equation is espressed as:

[tex]y\text{ = }\frac{5}{2}x-4[/tex]

Finding a final amount in a word problem on exponential growth or decay

Answers

Answer:

19g

Explanation:

Given the starting amount as 155grams, the below amount will be left after the 1st half life;

[tex]\frac{155g}{2}=77.5g[/tex]

After the 2nd half-life, the below amount will remain;

[tex]\frac{77.5g}{2}=38.75g[/tex]

After the 3rd half-life, the below amount will remain;

[tex]\begin{gathered} \frac{38.75}{2}=19.375g\approx19g\text{ (rounding to the nearest gram)} \\ \end{gathered}[/tex]

The formula k=5/9(f-32)+273.15 converts temperature of the object in a laboratory is cooled to 1.5 kelvin. What is the temperature of the object in degrees fahrenheit?

Answers

[tex]\begin{gathered} k=\frac{5}{9}(f-32)+273.15 \\ k=1.5 \\ 1.5=\frac{5}{9}(f-32)+273.15 \\ \text{Subtract 273.15 from both sides} \\ 1.5-273.15=\frac{5}{9}f-\frac{160}{9}\Rightarrow\frac{5}{9}f=1.5-273.15+\frac{160}{9} \\ \frac{5}{9}f=-253.872 \\ MultiplyBothSideBy,\frac{9}{5} \\ f=\frac{9}{5}\cdot(-253.872) \\ f=-456.97^{\circ} \end{gathered}[/tex]

The temperature of the object is -456.97 degrees

find the values of x y and z.The answers are in degrees.

Answers

Answer

x = 35°

y = 145°

z = 25°

Explanation

We are told to solve for x, y and z.

Considering the first triangle with angles 55°, x° and the right angle (90°).

The sum of angles in a triangle is 180°.

So,

x° + 55° + 90° = 180° (Sum of angles in a triangle is 180°)

x° + 145° = 180°

x = 180° - 145° = 35°

Then, we can solve for y. Angles x and y are on the same straight line, and the sum of angles on a straight line is 180°

x° + y° = 180°

35° + y° = 180°

y° = 180° - 35°

y° = 145°

We can then solve for z°. The big triangle has angles (55° + 10°), z° and the right angle (90°).

The sum of angles in a triangle is 180°.

So,

55° + 10° + z° + 90° = 180°

z° + 155° = 180°

z = 180° - 155°

z° = 25°

Hope this Helps!!!

The two angles shown are supplementary.162°Which equation can be solved to find the value of x, and what is the value of x?A.162° + Xo = 90°; x = 72B.162° + x° = 180°; x = 18C.162° + x = 360°; x= 198D.162° + x = 180°; x = 242

Answers

Supplementary angles are two angles whose sum is exactly 180, therefore:

162 + x = 180

Solving for x:

subtract 162 from both sides:

x = 180 - 162

x = 18

Given the points (3, -2) and (4, -1) find the slope

Answers

Slope is

[tex]\text{slope}=\frac{y2-y1}{x2-x1}[/tex]

Then:

[tex]\text{slope}=\frac{-1-(-2)}{4-3}=\frac{-1+2}{1}=\frac{1}{1}=1[/tex]

Answer: slope = 1

The ages of 12 selected participants in a Students’ Congress are:

16, 24, 23, 20, 12, 27, 19, 25, 21, 23, 14, 13

What is the mean age of the participants?

Answers

The mean age of the 12 participants in a student congress is 19.75.

given 16,24,23,20,12,27,19,25,21,23,14,13
Mean generally means average. The formula of Mean is as follows

Mean = The sum  of the numbers divided by total values in set
MEAN = SUM OF ALL VALUES
               TOTAL VALUES IN SET

Add the given numbers 16+24+23+20+21+27+19+25+21+23+14+13 = 237
Divide the total number by the number of participants that is
237/12 = 19.75

The mean age of the participants = 19.75

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Which will hold more cake batter; the rectangular pan or two round pans? The volume of the rectangle pan is 234 in 3rd power. Find the volume of the two round pans and choose your decision. Round your answer to the nearest tenth if necessary.

Answers

Solution

Given a rectangular pan and two round pans

The volume, V, of the rectangular pan is 234 in³

A round pan is in the form of a cylinder

To find the volume, V, of the a round pan, the formula is

[tex]V=\pi r^2h[/tex]

Where

[tex]\begin{gathered} d=8in \\ r=\frac{d}{2}=\frac{8}{2}=4in \\ r=4in \\ h=2in \end{gathered}[/tex]

Substitute the variables into the formula above

[tex]\begin{gathered} V=\pi\left(4\right)^2\left(2\right)=100.53in^3\text{ \lparen two decimal places\rparen} \\ V=100.53in^3\text{ \lparen two decimal places\rparen} \end{gathered}[/tex]

Since, there are two round pans, the volume of the two round pans will be

[tex]2\times100.53=201.06in^3[/tex]

nce, the volume of the two round pans is 201.06 i³.

Since the volume of the two round pans (201.06in³) is less than the volume of the rectangular pan (234in³), the rectangular pan will hold more.

Hence, the answer is rectangular pan (option a)


Determine whether the statement is true or false.
2E{x|XEN and x is odd}
Is the statement true or false?
O True
O False

Answers

The given statement exists as false. An expression, rule, or law in mathematics establishes the link between an independent variable and a dependent variable.

What is meant by function?

An expression, rule, or law in mathematics establishes the link between an independent variable and a dependent variable (the dependent variable).

The characteristic that every input is associated with exactly one output defines a function as a relationship between a set of inputs and a set of allowable outputs.

A relation between a collection of inputs and outputs is known as a function. A function exists, to put it simply, a relationship between inputs in which each input exists connected to precisely one output.

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Which expressions are equivalent to z + (z + 6)? Choose all answers that apply: A (2 + 2) + (2 + 6) 00 (z + 6 + 6 © 2(z + 3)

Answers

ANSWER:

[tex]2\cdot(z+3)[/tex]

STEP-BY-STEP EXPLANATION:

We have the following expression

[tex]z+(z+6)[/tex]

We operate and we have

[tex]z+z+6=2z+6=2\cdot(z+3)[/tex]

23 – 4u < 11 what is the answer

Answers

23 - 4u < 11

23 is adding on the left, then it will subtract on the right

-4u < 11 - 23

-4u < -12

-4 is multiplying on the left, then it will divide on the right. Remember that dividing by a negative number changes the sign.

u > (-12)/(-4)

u > 3

A person chooses a number in a set containing the first 5 cubic numbers. Find the set representing the event E of choosing a number that can be evenly divided by 2. Give your answer as a set, e.g. {1,2,3}, using the cubed number (not the base number) and do not include E= in your answer.

Answers

The first 5 cubic numbers are:

[tex]\lbrace1,8,27,64,125\rbrace[/tex]

To find the set that represents event E we have to choose the numbers from the set above that are evenly divided by 2; this means that we have to choose the numbers that are multiple of 2. We notice that this numbers are 8 and 64, therefore the set that represents event E is:

[tex]\lbrace8,64\rbrace[/tex]

the volume v of a fixed amount of a gas variety directly as the temperature T and inversely as the pressure P. suppose that V =42cm3 when T=84 kelvin and P=8kg/cm2 find the temperature when V =74cm3 and P=10 kg/cm2

Answers

ok

I'll use the law of gases to solve this problem

V1 = 42 cm^3

T1 = 84 °K

P = 8 Kg/cm^2

T2 = x

V2 = 74 cm^3

P2 = 10 kg/cm^2

Equation

P1V1/T1 = P2V2/T2

Solve for T2

T2 = P2V2T1 / P1V1

Substitution

T2 = (10*74*84) / (8*42)

Simplification

T2 = 62160 / 336

Result

T2 = 185°K

What is the area of the blue shape?

Pls help :(

Answers

Answer:

38.5 sq units

Step-by-step explanation:

Hello!

We can split the shape into two rectangles.

The small rectangle at the top has an area of 14 sq units (2 * 7).

The middle rectangle has an area of 49 sq units ( 7*7).

Since the blue part in the middle rectangle is half of the whole rectangle, the area of the blue part there is 24.5 sq units.

Adding that to 14 sq units will give us 38.5 sq units.

Which of the following are maximum and minimum points of the function y = 2 cos x -1?

Answers

The graph of the function is shown below

From the options provided

Option A is correct because the maximum and minimum values are satisfied

Solve the following and give the interval notation of the solution and show the solution on a number line. 6x-12(3-x) is less than or equal to 9(x-4)+9x

Answers

The Solution:

The given inequality is

[tex]6x-12(3-x)\leq9(x-4)+9x[/tex]

Clearing the brackets, we get

[tex]6x-36+12x\leq9x-36+9x[/tex]

Collecting the like terms, we get

[tex]\begin{gathered} 6x+12x-9x-9x\leq-36+36 \\ \end{gathered}[/tex][tex]\begin{gathered} 18x-18x\leq0 \\ 0\leq0 \end{gathered}[/tex]

So, the solution is true for all real values of x.

The interval notation of the solution is

[tex](-\infty,\infty)[/tex]

Is the following sequence arithmetic, geometric, or neither?1, 5, 25, 125, 625

Answers

This is a geometric sequence

This is because we can find the common ratio and not common difference

difference between managerial and financial accounting?

Answers

The main difference between managerial accounting and financial accounting is who the statement is being prepared for.

What differentiates managerial and financial accounting?

There are several things that differentiate managerial accounting from financial accounting but the main one is the target of the financial statements.

Financial accounting is used for financial statements for those outside the company such as investors, customers, and the government. As such, it has to abide by certain standards.

Managerial accounting on the other hand, is for managers and decision makers in the company. It is less restrictive as the main goal is to provide information for managers and not those outside.

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- A chemist mixes 2,362 milliliters of a solution. The solution must be divided equally among 8 beakers. How much solution should be poured into each beaker?

Answers

Answer:

295.25mm

Explanation:

If the chemist mixes 2362mm of a solution and needs to divide it equally into 8 breakers, to determine how much solution should be poured into each breaker, we have to divide 2362mm divide 8;

[tex]\frac{2362}{8}=295.25\operatorname{mm}[/tex]

PLEASE HELP I REALLY NEED AN ANSWER ALSO ONLY ANSWER IF YOUR GOING TO GIVE A STEP BY STEP SOLUTION

Answers

The answer of the given expression is 80.

Exponents

Exponent is defined as the method of expressing large numbers in terms of powers. That means, exponent refers to how many times a number multiplied by itself.

For example:-

[tex]5^4[/tex] can be written as 5*5*5*5.

Here 4 is the exponent or power and 5 is the base.

There are some laws of exponents which we use while calculating the answer to such expressions.

Given expression:-

[tex]\frac{12^7*30^5}{25^2*8^5*27^4}[/tex]

We have to simplify the given solution using the laws of exponents.

First we will divide them in their prime factors.

We know that,

[tex](x^a)^b=x^{ab}[/tex]

We can write,

[tex]12^7 = (2^2)^7*3^7=2^{14}*3^7[/tex]

[tex]30^5=2^5*3^5*5^5[/tex]

[tex]25^2=(5^2)^2=5^4[/tex]

[tex]8^5=(2^3)^5=2^{15}[/tex]

[tex]27^4=(3^3)^4=3^{12}[/tex]

Hence, we can write the given expression as follows,

[tex]\frac{2^{14}*3^7*2^5*3^5*5^5}{5^4*2^{15}*3^{12}}[/tex]

Also, we know that,

[tex]x^a*x^b=x^{a+b}\\x^a/x^b=x^{a-b}[/tex]

We can write,

[tex]{2^{(14+5-15)}*3^{(7+5-12)}*5^{(5-4)}}[/tex]

[tex]2^4*3^0*5^1[/tex] = 16*1*5 = 80

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What is the standard form of the complex number that point A represents?

Answers

Answer

-3 + 4i

Explanation

The standard form for a complex number is given by:

[tex]\begin{gathered} Z=a+bi \\ \text{Where:} \\ a\text{ is the real part,} \\ b\text{ is the imaginary part} \end{gathered}[/tex]

From the graph, the coordinates of A corresponding to the real axis and imaginary axis is traced in blue color in the graph below:

Hence, the standard form of the complex number that a represents is: -3 + 4i

A half-marathon has 53 runners. A first-, second-, and third-place trophy will be awarded. Howmany different ways can the trophies be awarded?

Answers

Let's use the combination formula:

[tex]\begin{gathered} C(n,k)=nCk=\frac{n!}{k!(n-k)!} \\ n=53 \\ k=3 \\ C(53,3)=53C3=\frac{53!}{3!(50)!}=23426 \end{gathered}[/tex]

What is the max/min of the quadratic equation in factored form: f(x) = 0.5(x +3)(x-7)

Answers

F(x) = 1/2(x+3)(X-7)

Step 1 ; expand the function

F(x)= 1/2(x²-7x+3x-21)

F(x) = 1/2(x² - 4x-21)

F(x) = 1/2x² - 2x-21/2

Step 2 : Take the second derivative of F(x)

This means you are to differentiate F(X) twice

[tex]\begin{gathered} F(x)=\frac{1}{2}x^2-2x-\frac{21}{2} \\ \text{First derivative is} \\ F^!(x)\text{=x-2} \\ F^{!!}(x)=1 \\ \text{the second derivative =1} \end{gathered}[/tex]

The second derivative is greater than 0, so it is a minimum point

Put x=1 in F(x) to find the value

[tex]\begin{gathered} f(x)=\frac{1}{2}(1)^2_{}-\text{ 2(1)-}\frac{21}{2} \\ f(x)=\frac{1}{2}-2-\frac{21}{2} \\ f(x)=-2-\frac{20}{2} \\ f(x)\text{ =-12} \end{gathered}[/tex]

The minimum of the quadratic equation is -12

Rewrite the following equation in slope-intercept form.
HELP I WILL GIVE BRAINLY FOR RIGHT ANSWER SOLVE FOR Y
11x + 19y = 8


Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answers

Answer:

y = - (11/19)x + 8/19

==============================

Given

Line 11x + 19y = 8

To find

Convert the equation into slope-intercept form

Solution

The slope-intercept form is:

y = mx + b

Convert the given equation to the above form.

11x + 19y = 8                               ⇔     Given equation19y = - 11x + 8                             ⇔     Make y the subject19y/19 = - 11x/19 + 8/19               ⇔     Divide all terms by 19y = - (11/19)x + 8/19                      ⇔     Answer

Which equation is set up for direct use of the zero-factor property? A. 3x2 - 19x - 14 = 0 C.X2 + x = 42 B. (7x + 9)2 = 3 D. (3x - 2)(- 2) = 0

Answers

Explanation:

The zero-factor property states that if ab=0, then either a = 0 or b = 0 (or both). A product of factors is zero if and only if one or more factors is zero.

From these options only B and D have factors, but B equals to 3. In D we have that (3x-2) = 0 or the other factor is zero (or both)

Answer:

The correct answer is option D

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