Let f(t) = 3 + 2, g(x) = -x^2?, andhe) = (x - 2)/5. Find the indicated value:24. h (g(5))
Answers
The Solution to Question 24:
Given the function below:
[tex]\begin{gathered} g(x)=-x^2 \\ h(x)=\frac{x-2}{5} \end{gathered}[/tex]We are asked to find the value of h(g(5)).
Step 1:
We shall find g(5) by substituting 5 for x in g(x).
[tex]g(5)=-5^2=-25[/tex]So that:
[tex]h(g(5))=h(-25)[/tex]Similarly, we shall find h(-25) by substituting -25 for x in h(x).
[tex]h(-25)=\frac{-25-2}{5}=\frac{-27}{5}[/tex]Therefore, the correct answer is
[tex]\frac{-27}{5}[/tex]Related Questions
Evaluate : g(x) = x^2 + 4x ; find g(2)
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Given the function
[tex]g(x)=x^2+4x[/tex]We want to evaluate this function at x = 2.
When we evaluate a function at a given value, we just need to substitute the terms with a variable by the given value.
[tex]g(2)=(2)^2+4\cdot(2)=4+8=12[/tex]9×6 can u help me with this
Answers
You have to multiply the numbers:
9x6 =54
Multiply is the same as adding the number 6 times
9+9+9+9+9+9 =54
The illustration below shows the graph of y as afunction of xComplete the following sentences based on thegraph of the function.(Enter the x-intercepts from least to greatest.)* This is the graph of a (nonlinear, linear orconstant) function.* The y-intercept of the graph is the function value y = ___.The x-intercepts of the graph (in order from leastto greatest) are located at x = ___ and x = ___.* The greatest value of y is y = ___ and it occurswhen x = ___.* For x between x = 2 and x = 6, the function value y (<, 2, or =) 0.
Answers
* This is the graph of a (nonlinear, linear or constant) function.
Answer:
This is the graph of a nonlinear function (In this case it is a quadratic function).
--------------------------------------------------------------------------------------
The y-intercept of the graph is the function value y =
Answer:
From the graph we can conclude that, the y-intercept is:
[tex]y=-6[/tex]----------------------------------------------------------------------------
The x-intercepts of the graph (in order from least to greatest) are located at x = ___ and x = ___.
Answer:
From the graph, we can conclude that the x-intercepts are located at:
[tex]\begin{gathered} x=2 \\ and \\ x=6 \end{gathered}[/tex]----------------------------------------------------------------------
The greatest value of y is y = ___ and it occurs
Answer:
From the graph, we can see that the vertex of the function is:
[tex]\begin{gathered} y=2 \\ when \\ x=4 \end{gathered}[/tex]----------------------------------------------------------------
For x between x = 2 and x = 6, the function value y is.
Answer:
For those values, y is always greater than or equal to 0, so:
[tex]2\le x\le6\to y\ge0[/tex]if Dixon is 6 ft tall,, how tall is ariadne?
Answers
Notice that the triangles formed by the shadows are similar, therefore:
[tex]\frac{x}{6}=\frac{15}{18},[/tex]where x is Adriadne's height. ( We will omit the units to simplify the calculations).
Solving the above equation for x, we get:
[tex]x=\frac{15}{18}*6.[/tex]Simplifying the above result, we get:
[tex]x=5ft.[/tex]Answer:[tex]5ft.[/tex]
lineal or no?1) 2x+y=52) y= x + 6 --- 2thanks
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1) 2x+y=5 ...... It is a linear equation
2) y= x + 6 ....... It is a linear equation
Because they are of first degree and they contain x and y (equations of a line)
You want to put a 4 inch thick layer of topsoil for a new 23 ft by 31 ft garden. The dirt store sells by the cubicyards. How many cubic yards will you need to order? The store only sells in increments of 1/4 cubic yards.
Answers
Remember that
1 ft=12 in
1 yd =36 in
so
The garden is 23 ft by 31 ft
Convert to inches
23 ft=23*12=276 in
31 ft=31*12=372 in
Find out the volume
V=(276)*(372)*(4)
V=410,688 in3
Convert to cubic yards
410,688 in3=410,688*(1/36)^3=8.80 cubic yards
Remember that
The store only sells in increments of 1/4 cubic yards
so
The volume is 9 cubic yardswrite the equation of the polynomial with the following zeros in standard form
Answers
Answer:
x² - (5 + √7)x + 5√7
Explanation:
A polynomial with zeros at x = a and x = b can be written as:
(x - a)(x - b)
So, if the roots are x = √7 and x = 5, we can write the equation for the polynomial as follows:
(x - √7)(x - 5)
Then, to write it in standard form, we need to apply the distributive property, so:
[tex]\begin{gathered} (x-\sqrt[]{7})(x-5)=x\cdot x+x(-5)-\sqrt[]{7}x-\sqrt[]{7}(-5) \\ (x-\sqrt[]{7})(x-5)=x^2-5x-\sqrt[]{7}x+5\sqrt[]{7} \\ (x-\sqrt[]{7})(x-5)=x^2-(5+\sqrt[]{7})_{}x+5\sqrt[]{7} \end{gathered}[/tex]Therefore, the answer is:
x² - (5 + √7)x + 5√7
What are the coordinates of M', the image of M (2,4), after a counterclockwiserotation of 90° about the origin?
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If M(h,k) is rotated 90° counterclockwise about the origin, the new position would be M'(k, -h)
M(2, 4)-> M'(4, -2)
what is polynomial define on the basis of degree and terms
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Detailed Answer :-
Based on the Degree :
• A polynomial having degree 0 is called a constant polynomial.
• A polynomial having degree 1 is called a linear polynomial.
• A polynomial having degree 2 is called a quadratic polynomial.
• A polynomial having degree 3 is called a cubic polynomial.
• A polynomial having degree 4 is called a bi-quadratic polynomial.
Based on the Number of Terms :
• One term - Monomial
• Two terms - Binomial
• Three terms - Trinomial
• Four terms - Quadrinomial
All of these are generally called POLYNOMIALS.
Identify the inverse g(x) of the given relation f(x). f(x)={(8,3),(0,-1),(-4,-3)}
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The function is given as.
f(x)={(8,3),(4,1),(0,-1),(-4,-3) }
The inverse function is determined as a function, which can reverse into another function.
Therefore the inverse function g(x) is obtained as
[tex]g(x)=\lbrace(3,8),(1,4),(-1,0),(-3,-4)\rbrace[/tex]Hence the correct option is D.
The area of a rectangular garden is 1,432 meters. If the length of the garden is 40 meters,
what is the width of the garden?
Answers
Answer: 35.8
Step-by-step explanation: 40x?=1432
40x35.8=1432
QuestionFind the equation of a line that contains the points (-6, 3) and (5,-8). Write the equation in slope-intercept form.
Answers
ANSWER
y = -x - 3
STEP BY STEP EXPLANATION
Step 1: The given points are:
(-6, 3) and (5, -8)
Step 2: The slope-intercept form is
[tex]y\text{ = mx + c}[/tex]where m is the slope and c is the intercept
Step 3: Find the slope m
[tex]\begin{gathered} \text{slope (m) = }\frac{y_2-y_1}{x_2-x_1} \\ \text{m = }\frac{-8_{}-\text{ 3}}{5\text{ - (-6)}} \\ m\text{ = }\frac{-11}{11}\text{ = -1} \end{gathered}[/tex]Step 4: Solve for intercept c using either of the points
[tex]\begin{gathered} y\text{ = mx + c} \\ c\text{ = y - mx} \\ c\text{ = 3 - (-1)(-6)} \\ c\text{ = 3 - 6} \\ c\text{ = -3} \end{gathered}[/tex]Step 5: Re-writing the slope-intercept form to include the values of m and c
[tex]\begin{gathered} y\text{ = mx + c} \\ y\text{ = -x - 3} \end{gathered}[/tex]Hence, the equation of the line in slope-intercept form is y = -x - 3
6. Line 1 passes through the points (1,4) and (-2,5). Line 2 passes through the points (1,0) and (0,3). What is true about Line 1 and Line 2? (2 points) (A) (B) They are perpendicular. They are parallel. They both decrease. They both increase. (C) (D)
Answers
First, calculate the slope (m) of both lines.
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Line 1:
Point 1 = (x1,y1) = (1,4)
Point 2 = (x2,y2) = (-2,5)
Replacing:
[tex]m=\frac{5-4}{-2-1}=\frac{1}{-3}=-\frac{1}{3}[/tex]Line 2:
Point 1 = (x1,y1) = (1,0)
Point 2 = (x2,y2) = (0,3)
[tex]m=\frac{3-0}{0-1}=\frac{3}{-1}=-3[/tex]Lines to be parallel must have the same slope, and to be perpendicular, they must have negative reciprocal slope.
None of the slopes are equal or negative reciprocal. SO, A and B are false-
Now, for the increase/ decrease
We can see that both lines have a negative slope, so they both decrease.
Correct option: C
Find the missing side of this righttriangle.x816x= V[?]=Enter the number that belongs in the green box.Enter
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As gien by the question
There are given that the right angle triangle.
Now,
To find the value of x, use Pythagoras theorem:
So,
From the Pythagoras theorem;
[tex]\begin{gathered} x^2+8^2=16^2 \\ x^2+64=256 \\ x^2=256-64 \\ x=\sqrt[]{192} \end{gathered}[/tex]Hence, the value of x is shown below:
[tex]x=\sqrt[]{192}[/tex]Translate to an equation and solve W divided by 6 is equal to 36 w=
Answers
Answer:
[tex]w\text{ = 216}[/tex]Explanation:
Here, we want to translate it into an equation and solve
W divided by 6 equal to 36:
[tex]\begin{gathered} \frac{w}{6}\text{ = 36} \\ \\ w\text{ = 6}\times36 \\ w\text{ = 216} \end{gathered}[/tex]49x^2 + 16y^2 - 392x +160y + 400 = 01. give the coordinates of the upper vertex2. give the coordinates of the lower vertex3. give the coordinates of the upper focus(round to the nearest hundredths)4. give the coordinates of the lower focus(round to the nearest hundredths)5. give the eccentricity
Answers
we have
49x^2 + 16y^2 - 392x +160y + 400 = 0
Complete the square
Group terms
[tex](49x^2-392x)+(16y^2+160y)=-400[/tex]Factor 49 and 16
[tex]49(x^2-8x)+16(y^2+10y)=-400[/tex][tex]49(x^2-8x+16)+16(y^2+10y+25)=-400+16(49)+25(16)[/tex][tex]\begin{gathered} 49(x^2-8x+16)+16(y^2+10y+25)=784 \\ 49(x^{}-4)^2+16(y+5)^2=784 \end{gathered}[/tex]Divide by 784 both sides
[tex]\begin{gathered} 49(x^{}-4)^2+16(y+5)^2=784 \\ \frac{49(x^{}-4)^2}{784}+\frac{16(y+5)^2}{784}=1 \end{gathered}[/tex]simplify
[tex]\frac{(x^{}-4)^2}{16}+\frac{(y+5)^2}{49}=1[/tex]we have a vertical elipse
the center is the point (4,-5)
major semi axis is 7
we have
a^2=16 --------> a=4
b^2=49 ------> b=7
Find the value of c
[tex]\begin{gathered} c=\sqrt[]{b^2-a^2} \\ c=\sqrt[]{33} \end{gathered}[/tex]see the attached figure to better understand the problem
Find all real and imaginary solutions to the equation. Please help me tyy
Answers
Real solutions = 4/5 and 3
Imaginary solutions = 3i
Define real and imaginary solutions.The quadratic equation x² + 1 = 0 has a solution in the imaginary unit or unit imaginary number I Although there isn't a real number associated with this attribute, addition and multiplication can be employed to expand real numbers to so-called complex numbers. A real number is the real root of an equation. A complex root is a fictitious root that is represented by complex numbers in an equation. Imaginary numbers are "real" in the sense that they exist and are used in mathematics, even though they are not real numbers because they cannot be defined on a number line. Complex numbers, often known as imaginary numbers, are used in quadratic equations and in real-world applications like electricity.
Given,
Equation
4x³ + 5x² + 36x + 45 = 0
x²(4x + 5) + 9( 4x + 5) = 0
x² + 9 + (4x +5) = 0
(x - 3 ) (x +3) + (4x+5) = 0
x = 3i
x = [tex]\frac{4}{5}[/tex] and 3
Real solutions = 4/5 and 3
Imaginary solutions = 3i
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the bears have won 7 and tied 2 of their last 13 games. the not forfeited any games . which ratio correctly campares their to losses
Answers
Explanation:
Number of games won = 7
Number of games drawn = 2
Total number of games = 13
Number of games lost = Total number of games - (Number of games won + Number of games drawn)
Number of games lost = 13 - (7 + 2) = 13 - 9
Number of games lost = 7
The ratio of
If 260 is decreased by 65%, what is the new amount?
Answers
To find the new amount, substract the percent of the original amount to the original amount, this way:
[tex]260-0.65\cdot260=91[/tex]The new amount is 91.
Rapheal is traveling in a straight line at a constant speed from point A to point B. His distance from point B in miles is -20t + 45, where t is the number of hours he has been traveling. What is his speed in miles per hour?
Answers
Rapheal is traveling in a straight line. Its speed in miles per hour is 20 miles per hour.
A and B are the two points of a straight line.Distance between two points is given as :d₀ = -20t + 45 miles
t = the number of hours of travelling.The starting time = 0
i.e. the initial position = 0
Then
we put t=0
At t=0
d₀ = -20(0) + 45
= 0 + 45
= 45 miles
the distance travel after starting first hour is :
T= d₁ & d₀
than we put t = 1
At t = 1;
d₁ = -20(1) + 45
= -20 + 45
= 25 miles
now
Difference between d₁ & d₀ is
d = d₁ - d₀
45 - 25 = 20 miles
Total distance covered = 20 miles
To find the speed we use formula:
Speed = distance/time
Speed=20/1
Speed = 20 miles/hour
Rapheal is traveling in a straight line. Its speed in miles per hour is 20 miles per hour.
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I need help A. -3 B. 3 C. -2D. -10
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The average rate of change can be calculated as the division of the output of the function on the interest interval by the size of the interval. To do that we have to find the value of "y" at the end of the interval and subtract it by the value of "y" at the beggining. This is shown as an expression below:
[tex]\text{average rate of change=}\frac{y_{\text{ final}}-y_{\text{ initial}}}{x_{\text{ final}}-x_{\text{ initial}}}[/tex]For this function the values of x are:
[tex]\begin{gathered} x_{\text{ initial}}=0 \\ x_{\text{ initial}}=3 \end{gathered}[/tex]The values for y are:
[tex]\begin{gathered} y_{\text{ initial}}=10 \\ y_{\text{ final}}=1 \end{gathered}[/tex]Using these values we can calculate the average rate of change:
[tex]\text{average rate of change=}\frac{1-10}{3-0}=\frac{-9}{3}=-3[/tex]The average rate of change for this function is approximately -3 for the given interval. The correct answer is A.
Describe the relationship between average velocity of a car in motion versus the instantaneous velocity of the same car in motion. Which one matters more if you get pulled over on the freeway for speeding and why?
Answers
Answer:
During a typical trip to school, your car will undergo a series of changes in its speed. If you were to inspect the speedometer readings at regular intervals, you would notice that it changes often. The speedometer of a car reveals information about the instantaneous speed of your car. It shows your speed at a particular instant in time.
Step-by-step explanation:
The instantaneous speed of an object is not to be confused with the average speed. Average speed is a measure of the distance traveled in a given period of time; it is sometimes referred to as the distance per time ratio. Suppose that during your trip to school, you traveled a distance of 5 miles and the trip lasted 0.2 hours (12 minutes). The average speed of your car could be determined as
On the average, your car was moving with a speed of 25 miles per hour. During your trip, there may have been times that you were stopped and other times that your speedometer was reading 50 miles per hour. Yet, on average, you were moving with a speed of 25 miles per hour.
hope this helps might not be the answer your looking for but a better explanation on how too figure it out :))
Brainliest and 20 points please solve
Answers
Answer:
part a: x = 5
part b: no
Step-by-step explanation:
part a : 8x + 3 = 9x - 2, subtract 8x from both sides which leaves you with 1x or just x. add 2 to both sides which gives you 5. 5 is equal to 1x.
part b: a complementary angle is 2 angles whos sum equals 90 degrees. m<ABC = 43 & m<DBE = 43 & they both equal 86 not 90.
Answer/Step-by-step explanation:
A C
\ (8x + 3) /
\ /
\ /
\ /
B
/ \
/ \
/ \
/ (9x - 2) \
D E
A. Solve for x.
m∠ABC = m∠DBE
(8x + 3) = (9x - 2)
8x + 3 = 9x - 2
-9x -9x
------------------------
-x + 3 = -2
-3 -3
--------------------
-x = -5
÷-1 ÷-1
----------------
x = 5
B. Are vertical angles also complementary angles?
No, vertical angles are angles that are congruent to each other or in other words, equal. In the equation above (8x + 3) = (9x - 2). If I were to plug 5 into the equation I would get
(8(5) + 3) = (9(5) - 2)
(40 + 3) = (45 - 2)
43 = 43
Complementary angles equal to 90°. It wouldn't make sense to add these numbers together because I would end up with a fraction if I set the equation equal to 90°
I hope this helps!
For f(x) = 2x+1 and g(x) = x² − 7, find (f+ g)(x).
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Given the functions:
[tex]\begin{gathered} f(x)=2x+1 \\ \\ g(x)=x^2-7 \end{gathered}[/tex]By definition, (f+g)(x) is equivalent to:
[tex](f+g)(x)=f(x)+g(x)[/tex]Finally, using the expressions for f and g:
[tex]\begin{gathered} f(x)+g(x)=2x+1+x^2-7 \\ \\ \therefore(f+g)(x)=x^2+2x-6 \end{gathered}[/tex]-87, -70, -27, -36,...a(n)= 17n - 10432nd term
Answers
We have the arithmetic progression given by
[tex]a_n=17n-104[/tex]if n = 1 we have the first term, n = 2 the second one and, so on, to find the 32nd term we just do n = 32, therefore
[tex]\begin{gathered} a_{32}=17\cdot32-104 \\ \\ a_{32}=544-104 \\ \\ a_{32}=440 \end{gathered}[/tex]The 32nd term is 440.
Company operates stores under multiple banners in 13 states in the United States
Answers
Given:
Banners in 13 states in united states:
Total states in united state is 50.
(A)
Do not have store is:
[tex]\begin{gathered} =50-13 \\ =37 \end{gathered}[/tex]So in 37 states Company not operates any store.
(B)
Fraction do not have a store operates :
[tex]\begin{gathered} =\frac{37}{50} \\ =0.75 \end{gathered}[/tex]y - 32 = -2(x-48)what is y
Answers
y - 32 = -2( x - 48)
y - 32 = -2x + 96
y = -2x + 96 + 32
y = -2x + 128
you are given the point Q(-2,-5). A identify a point (x,y) that along with point Q defines a line with a positive slope.
Answers
Answer:
[tex] \sqrt{29} [/tex]
Suppose medical records indicate that the length of newborn babies (in inches) is normally distributed with a mean of 20 and a standard deviation of 2.6. Find the probability that a given infant is longer than 20 inches. [? ]%
Answers
To find the probability we need to use the z score formula, given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]where x is the value we like, mu is the median and sigma is the standard deviation.
Then the z score is:
[tex]z=\frac{20-20}{2.6}=0[/tex]Then we have to look for the proability:
[tex]P(z>0)=0.5[/tex]Therefore the probability that a given infant is longer than 20 inches is 0.5 or 50%.
Which of the following could be an example of a function with a domain (-0,) and a range (-0,2)? Check all that apply. A. V= - (0.25)* - 2 - B. v= -(3)*-2 O c. v= -(3)*+2 1 v= - (0.25)*+2 D.
Answers
It is desired that the domain and range of the function should, respectively, be
[tex]\begin{gathered} \text{Domain}=(-\infty,\infty) \\ \text{Range}=(-\infty,2) \end{gathered}[/tex]Observe the given choices of function.
It is evident that all the functions are exponential functions, so their domain must be the set of all real numbers,
[tex](-\infty,\infty)[/tex]Now, we have to check the range of each of the 4 given functions.
Option A:
The function is given as,
[tex]y=-(0.25)^x-2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(0.25)^x\rightarrow0\Rightarrow-(0.25)^x-2\rightarrow-2\Rightarrow y\rightarrow-2 \\ x\rightarrow-\infty\Rightarrow-(0.25)^x\rightarrow-\infty\Rightarrow-(0.25)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,-2)[/tex]Since this does not match with the desired range. This is not a correct choice.
Option B:
The function is given as,
[tex]y=-(3)^x-2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(3)^x\rightarrow-\infty\Rightarrow-(3)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \\ x\rightarrow-\infty\Rightarrow-(3)^x\rightarrow0\Rightarrow-(3)^x-2\rightarrow-2\Rightarrow y\rightarrow-2 \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,-2)[/tex]Since this does not match with the desired range. This is not a correct choice.
Option C:
The function is given as,
[tex]y=-(3)^x+2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(3)^x\rightarrow-\infty\Rightarrow-(3)^x+2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \\ x\rightarrow-\infty\Rightarrow-(3)^x\rightarrow0\Rightarrow-(3)^x+2\rightarrow2\Rightarrow y\rightarrow2 \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,2)[/tex]Since this exactly matches with the desired range. This is a correct choice.
Option D:
The function is given as,
[tex]y=-(0.25)^x+2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(0.25)^x\rightarrow0\Rightarrow-(0.25)^x+2\rightarrow2\Rightarrow y\rightarrow2 \\ x\rightarrow-\infty\Rightarrow-(0.25)^x\rightarrow-\infty\Rightarrow-(0.25)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,2)[/tex]Since this exactly matches with the desired range. This is also a correct choice.
Thus, the we see that the functions in option C and D possess the desired domain and range.
Therefore, option C and option D are t
