The face of a cuboid box have 4 right angles.
What is mean by Cuboid?
A cuboid is the solid shape or three-dimensional shape. A convex polyhedron which is bounded by six rectangular faces with eight vertices and twelve edges is called cuboid.
Given that;
Mari pushed a cube- shaped box to explore force.
And, She examined the attributes of the box.
Now,
In the cube shape, faces are all squares.
And, A square is a quadrilateral in which all angles are 90 degree.
Thus, The face of a cuboid box have 4 right angles.
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marie invested 10000 in a savings account that pays 2 interest quartarly 4 times a yesr. how much money will she have in her account in 7 years?
Okey, here we have the following:
Capital: 10000
Interest: 2%
Time: 7 Years= 7*4=28 quarters of year
Using the compound interest formula, we get:
[tex]C_f=10000(1+\frac{0.02}{4})^{4\cdot7}=1000(1+\frac{0.02}{4})^{28}[/tex]Working we get:
[tex]C_f\approx11.498.73[/tex]She will have aproximately $11,498.73 in her account after 7 years.
Find the zero for the polynomial function and give the multiplicity for each zero. State whether the graph crosses to x axis or touch the x axis and turn around, at each zero.
we have the function
f(x)=2(x-6)(x-7)^2
REmember that the zeros of the function are the values of x when the value of the function is equal to zero
In this problem
the zeros of the function are
x=6 -------> multiplicity 1 (the graph crosses to x axis)
x=7 ----- multiplicity 2 (touch the x axis and turn around)
see the attached figure to better understand the problem
A straight line l1 with equation 5x - 7 = 0 cuts the x axis at point A. Straight line l2 is perpendicular to straight line l1 and passes through point A. What is the coordinates of point A and the equation of the straight line l2?
Point A has a coordinate of (7/5, 0) while the straight line l2 is represented by the equation y = 0
The coordinates of point AThe equation of line l1 is given as
5x - 7 = 0
It cuts the x-axis at point A
This means that
5A - 7 = 0
Solve for A
5A = 7
So, we have
A = 7/5
Rewrite as
A = (7/5, 0)
The equation of the straight line l2From the question, we have
Lines l1 and l2 are perpendicular lines
The equation 5x - 7 = 0 has no y variable
So, the slope is undefined
The slopes of perpendicular lines are represented as follows
Slope 1 * Slope 2 = -1
So, we have
Slope 2 = -1/Slope 1
This gives
Slope 2 = -1/undefined
Evaluate
Slope 2 = 0
This means that l2 has a slope of 0
The equation of l2 is calculated as
y = m(x - x₁) + y₁
In this case,
A = x₁ and y₁ = 0
So, we have
y = m(x - A)
This gives
y = 0 * (x - 7/5)
Evaluate
y = 0
Hence, the equation of the straight line l2 is y = 0
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name the three congruent parts shown by the marks on each drawing
In this case the aswer is very simple. .
The congruent parts are the equal parts in the 2 triangles.
Therefore, the congruent parts would be:
1. side AB and side XY
2. ∠ A and ∠ X
3. side AC and side XZ
That is the solution. .
is the number 6.35 a whole number and a integer
Natural numbers are all numbers 1, 2, 3, 4… They are the numbers you usually count and they will continue on into infinity. This includes all numbers that can be written as a decimal.
Hence, 6.35 is a natural number. It is natural number, whole number, integer, and rational number.
3. What is the slope of a line that is parallel to the line that contains these
two points: (-2,5) and (-3,1).
Answer:
4
Step-by-step explanation:
The slope of the line through the points is
[tex]\frac{1-5}{-3-(-2)}=4[/tex]
Parallel lines have the same slope, so the answer is 4.
Julie is 6 feet tall if she stands 15 feet from the flagpole and holds a cardboard square the edges of the square light up with the top and bottom of the flagpole approximate the height of the flagpole
Using tangent function:
[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{adjacent} \\ \frac{6}{15}=\frac{15}{x-6} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 6(x-6)=15^2 \\ 6x-36=225 \\ 6x=225+36 \\ 6x=261 \\ x=\frac{261}{6} \\ x=43.5ft \end{gathered}[/tex]When point A'(-2,4) is reflected over they-axis, where is the image A"?(2,-4)(2,4)(4,-2)
Answer:
Explanation
Given a coordinate (x, y), If this coordinate reflected over y axis, the resulting coordinate will be expressed as (-x, y). Note that only the sign of the x coordinate axis was
a storage container for oil is in the shape of a cylinder with a diameter of 10ft and a height of 17ft. what is the volume if the storage container in cubic feet?
To calculate the volume, w will use the formula:
[tex]V=\pi r^2h[/tex]where r is the radius and h is the height
From the question,
diameter = 10
This implies that; r=d/2 = 10/2 = 5
h = 17
susbtitute the values into the formula
[tex]V=\pi\times5^2\times17[/tex][tex]=425\pi\text{ cubic feet}[/tex]If we substitute the value of pie= 22/7
[tex]V=\frac{22}{7}\times425[/tex][tex]\approx1335.71\text{ cubic f}eet[/tex]Which inference about the man is best supported by the events in the text?
factor bofe problems using synthetic division and list All zeros
Given:
[tex]f(x)=x^3-7x^2+2x+40;\text{ x -5}[/tex]Let's factor using synthetic division.
Equate the divisor to zero:
x - 5 = 0
x = 5
List all terms of the polynomial: 1, -7, 2, 40
Palce the numbers representing the divisor and dividend into a long division-like configuration
To factor using synthetic division, we have:
Therefore, the factored expression is:
[tex]\begin{gathered} 1x^2-2x-8 \\ \\ =x^2-2x-8 \\ \\ =(x-4)(x+2) \end{gathered}[/tex]The zeros are also the roots of the polynomial.
The zeros of a polynomial are all the x-values that makes the polynomial equal to zero,
To find the zeros, equate each afctor to zero:
(x - 4) = 0
x = 4
(x + 2) = 0
x = -2
Thus, the zeros are:
x = 4, -2
ANSWER:
[tex]\begin{gathered} (x-4)(x+2) \\ \\ \text{Zeros: 4, and -2} \end{gathered}[/tex]Lucky's Market purchased a new freezer for the store.When the freezer door stays open, the temperatureinside rises. The table shows how much thetemperature rises every 15 minutes. Find the unit rate.temperature (°F) =10number of minutes =15(answer) °F per minute
Notice that the information in the table can be modeled using a linear function. To find the slope (rate of change) given two points, use the formula below
[tex]\begin{gathered} (x_1,y_1),(x_2,y_2) \\ \Rightarrow slope=m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]Therefore, in our case,
[tex]\begin{gathered} (15,10),(30,20) \\ \Rightarrow slope=\frac{20-10}{30-15}=\frac{10}{15}=\frac{2}{3} \end{gathered}[/tex]find the slope of the line passing through the points (-5,4) and (3,-3)
P1 = (-5, 4)
P2 = (3, -3)
Formula
[tex]\text{slope = }\frac{(y2\text{ - y1)}}{(x2\text{ - x1)}}[/tex]Substitution
[tex]\begin{gathered} \text{ slope = }\frac{(-3-4)}{(3\text{ + 5)}} \\ \text{ slope = }\frac{-7}{8} \end{gathered}[/tex]Result
[tex]\text{ slope = }\frac{-7}{8}[/tex]Sketch the graph and circle the points that are solutions. (0-0)(2,5)(-3,-5)(-3,2)
(-3,-5)
1) Let's plot both inequalities to solve that geometrically at first.
y ≤ -1/3x -2
y< 2/3x +1
2) Since the possible solutions to that Linear system of Inequalities are within the darker and common region, after examining those options we can write:
The only (-3,-5) of those is a possible solution to that System.
3) Hence the only possible solution between them is (-3,-5).
Find the simple interest owed for the following loan. Principal = 2775 Rate = 7.5% Time = 5 1/2 years
We would apply the simple interest formula which is xpressed as
I = PRT/100
Where
I represents interest
P represents principal or amount borrowed
T represents time in years
R represents rate.
From the information given,
P = 2775
R = 7.5
T = 5 1/2 = 5.5
I = (2775 * 7.5 * 5.5)/100
I = 1144.6875
Rounding to the nearest cent,
I = 1144.69
Using the Rational Roots Theorem which of the values shown are potential roots of ) = 32-132-3x + 457 Select all that apply. +1/3 +5 +5/3 +9 +1 +15 +3 +45
To solve this problem, you find the value of x that will make the function to be = 0 by substituting the likely values from the option into the eqaution and checking if after the simplification the value is 0
so checking
[tex]\begin{gathered} \text{The factors betwe}en\text{ }3\text{ and 45 are } \\ 1,3,5,9,15,45 \\ \text{factors of 3 are 1,3} \end{gathered}[/tex]we have
[tex]\begin{gathered} =3x^{^3}-13x^2-3x\text{ +45} \\ \pm1,\text{ 3, 5,9, 15,45} \\ \pm\frac{1}{3},\text{ 1, 5/3, 3, 5 , 15} \\ \text{values that apply are +3 twice and -5/3} \end{gathered}[/tex]2) A humane society claims that 30% of U.S. households own a cat. In a random sample of 210 U.S. households, 80 say they own a cat. Is there enough evidence to show this percent has changed? Use a level of significance of 0.05.
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
please help me work through this homework problem! thank you!
Given:
Given the function
[tex]y=3+\frac{3}{x}+\frac{2}{x^2}[/tex]and a point x = 3.
Required: Equation of the line tangent to y at x = 3.
Explanation:
The derivative of a function is he slope of the tangent line of the function at a given point. So, finding the derivative gives the slope of the tangent line.
[tex]y^{\prime}=-\frac{3}{x^2}-\frac{4}{x^3}[/tex]Substitute 3 for x into the derivative.
[tex]\begin{gathered} y^{\prime}|_{x=3}=-\frac{3}{3^2}-\frac{4}{3^3} \\ =-\frac{31}{27} \end{gathered}[/tex]Therefore, the slope of the tangent line is -31/27.
Substitute 3 for x into y.
[tex]\begin{gathered} y|_{x=3}=3+\frac{3}{3}+\frac{2}{3^2} \\ =3+1+\frac{2}{9} \\ =4+\frac{2}{9} \\ =\frac{38}{9} \end{gathered}[/tex](3, 38/9) is the only point on the tangent line where it intersects the original graph.
Plug these coordinates along with slope into the general point-slope form to find the equation.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-\frac{38}{9}=-\frac{31}{27}(x-3) \end{gathered}[/tex]Solving for y will give the equation in slope-intercept form.
[tex]\begin{gathered} y=-\frac{31}{27}(x-3)+\frac{38}{9} \\ =-\frac{31}{27}x+\frac{69}{9} \end{gathered}[/tex]Final Answer: The equation of the tangent line is
[tex]y=-\frac{31}{27}x+\frac{69}{9}[/tex]
If a,b ,and c represent the set of all values of x that satisly the equation below, what is the value(A+ b+ c) + (abc)?X^3-20x = x^2(A) -1(B) 0(C) 1(D) 9
First, we need to find the solutions a, b, and c of the equation:
[tex]x^3-20x=x^2[/tex]We can rewrite it as:
[tex]\begin{gathered} x^3-x^{2}-20x=0 \\ \\ x(x^{2}-x-20)=0 \\ \\ x=0\text{ or }x^{2}-x-20=0 \end{gathered}[/tex]Thus, one of the solutions is a = 0.
To find the other solutions, we can use the quadratic formula. We obtain:
[tex]\begin{gathered} x=\frac{-(-1)\pm\sqrt[]{(-1)^{2}-4(1)(-20)}}{2(1)} \\ \\ x=\frac{1\pm\sqrt[]{1+80}}{2} \\ \\ x=\frac{1\pm\sqrt[]{81}}{2} \\ \\ x=\frac{1\pm9}{2} \\ \\ b=\frac{1-9}{2}=-4 \\ \\ c=\frac{1+9}{2}=5 \end{gathered}[/tex]Now, we need to find the value of the expression:
[tex]\mleft(a+b+c\mright)+abc[/tex]Using the previous solutions, we obtain:
[tex]\mleft(0-4+5\mright)+0(-4)(5)=1+0=1[/tex]Therefore, the answer is 1.
a) Reflection, then translationb) Rotation, then translationc) Reflection, then rotationd) Rotation, then reflection
We have the following:
Therefore we can conclude that from step 1 to step 2, it is a rotation because it moves on its own axis and from step 2 to 3, it is a reflection
2/3 divided 17/28 equals what?
A train travels at 100 mph any equation can be written that compares the time with the distance to find the domain and range
ok
speed = distance / time
time = distance/speed
[tex]\text{ time = }\frac{dis\tan ce\text{ }}{speed}[/tex][tex]\text{ time = }\frac{dis\tan ce\text{ }}{100}[/tex]or
[tex]\text{ distance = 100 x time}[/tex]Given f(x), find g(x) and h(x) such that f(x)= g(h(x)) and neither g(x) nor h(x) is solely x.
Given:
[tex]\begin{gathered} f(x)=g(h(x)) \\ f(x)=\sqrt[]{-4x^2-3}+2 \end{gathered}[/tex]Solve :
[tex]g(h(x)=\sqrt[]{-4x^2-3}+2[/tex]The function g(x) convert then x is equal to h(x) then:
[tex]\begin{gathered} h(x)=-4x^2 \\ g(x)=\sqrt[]{x-3}+2 \end{gathered}[/tex]I need some help solving this It’s from my ACT prep guide
We can convert a measure from radians to degrees by taking into account that π radians is equivalent to 180°.
Then, we can convert a measure in radians into degrees by multiplying by 180°/π.
We can convert 7π/11 into degrees as:
[tex]\frac{7\pi}{11}\cdot\frac{180\degree}{\pi}=\frac{7\cdot180\degree}{11}\approx114.55\degree[/tex]Answer: 114.55°
mputing and Using a Least-Squares Regression LineVehiclesight (tons) Gas mileage (mpg)1.6291.6451.75261.952221821211822.32.5The table shows the weight and gas mileage of severalvehicles.What is the equation of the least-squares regressionline, where ŷ is the predicted gas mileage and x is theweight?ŷ=V+According to the regression equation, a car that weighs1.8 tons would have a gas mileage of aboutmiles per gallon.
From the table, we have the following points:
(x, y) ==> (1.6, 29), (1.6, 45), (1.75, 26), (1.95, 22), (2, 18), (2, 21), (2.3, 21), (2.5, 18)
Let's find the regression line.
Apply the slope-intercept form:
y = mx + b
Where m is the slope and b is the y-intercept.
To find the slope, apply the formula:
[tex]m=\frac{n(\Sigma xy)-\Sigma x\Sigma y}{n(\Sigma x^2)-(\Sigma x)^2}[/tex]Where:
• ∑x = 1.6 + 1.6 + 1.75 + 1.95 + 2 + 2 + 2.3 + 2.5 = 15.7
• ∑y = 29 + 45 + 26 + 22 + 18 + 21 + 21 + 18 = 200
• ∑xy = 1.6⋅29 + 1.6⋅45 + 1.75⋅26 + 1.95⋅22 + 2⋅18 +2⋅21 +2.3⋅21 + 2.5⋅18 = 378.1
• ∑x² = 1.6² + 1.6² + 1.75² + 1.95² + 2² + 2² + 2.3² + 2.5² = 31.525
,• n is the number of data = 8
Now, plug in values into the equation and solve for m:
[tex]\begin{gathered} m=\frac{8(378.1)-15.7*200}{8(31.525)-(15.7)^2} \\ \\ m=-20.175\approx20.2 \end{gathered}[/tex]The slope, m = -20.2
To find the y-intercept, b, apply the formula:
[tex]\begin{gathered} b=\frac{(\Sigma y)(\Sigma x^2)-\Sigma x\Sigma xy}{n(\Sigma x^2)-(\Sigma x)^2} \\ \\ b=\frac{200(31.525)-15.7*200}{8(31.525)-15.7^2} \\ \\ b=64.594\approx64.6 \end{gathered}[/tex]Therefore, the regression equation is:
y = 64.6 + (-20.2)x
(b). Substitute 1.8 for x in the equation and solve for y:
y = -20.2(1.8) + 64.6
y = 28.24 = 28.
ANSWER:
(A). y = 64.6 + (-20.2)x
(B). 28
Answer:
here's your answer :)
Step-by-step explanation:
help meeeee pleaseeeee!!!
thank you
The value of x is -2.
We are given a graph of a function f(x).
We have to find the value of x when the value of f(x) is -3.
We know that x- axis represents x and the y-axis shows f(x).
Hence, the x and y coordinates of a point on the line will be (x, f(x)).
To find the value of x , I will check the coordinates of the point (x, -3) because it is given that f(x) is -3.
Using the graph, we found the coordinates of that point to be (-2,-3).
Hence, we can say that,
x = -2
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An example of an experiment that leads to a uniform probability distribution is...Choose one answer. 1. the sum of rolling two dice 2. measuring the heights of all the students in a school 3. tossing a coin ten times and recording the number of heads 4. selecting a card from a deck of 52 cards
Solution
A probability distribution in which all of the values of the random variable occur with equal probability is called a uniform probability distribution. Describe an example of an experiment that would produce a uniform distribution. Then find the theoretical probabilities that would result from this experiment. Include a table and graph of the distribution.
Answer:
The theoretical probability experiment of rolling a die would result in a uniform distribution because the probabilities of rolling a 1,2,3,4,5,6 are all equally likely to occur.
Therefore the sum of rolling two dice is an option
Hence the correct answer is
Option 1
Identify the property of real numbers illustrated in the following equation.(+6) + [y? • (-4)] = [y2 • (-4)] + (-6)
Given
[tex]\mleft(+6\mright)+\mleft[y^2•(-4)\mright]=\mleft[y^2•(-4)\mright]+(-6)[/tex]Answer
Commutative property of addition
Identify each of the following statements as true or false in relation to confidence intervals (CIs).
Let's analyze each sentence to check if it is true or false:
First:
This sentence is true, the confidence interval is an interval where the true mean is likely to be.
Second:
This sentence is true, with a sample size smaller than 30, it is better to use the t-distribution instead of the normal distribution.
Third:
This sentence is true, the confidence interval is not a 100% guarantee that the true mean will be inside it.
Fourth:
Ti s sentence is true, this theorem states that when getting a large enough sample of a distribution with mean and standard deviation, the sample will be approximately normally distributed.
Fifth:
This sentence is false, because the number of degrees of freedom is 1 less than the sample size, so it would be 10.
Therefore the answer is:
True, True, True, True, False.
In a nearby park, a field has been marked off for the neighborhood Pop Warner football team. If the field has a perimeter of 310 yd and an area of 4950 yd', what are the dimensions of the field?
Answer:
The dimension of the field is ( 110 x 45)
Exolanations:
Perimeter of the field, P = 310 yd
Area of the field, A = 4950 yd²
Note that the shape of a field is rectangular:
Perimeter of a rectangle, P = 2(L + B)
Area of a rectangle, A = L x B
Substituting the values of the perimeter, P, and the Area, A into the formulae above:
310 = 2(L + B)
310 / 2 = L + B
155 = L + B
L + B = 155...............................................(1)
4950 = L x B...............(2)
From equation (1), make L the subject of the formula:
L = 155 - B...................(3)
Substitute equation (3) into equation (2)
4950 = (155 - B) B
4950 = 155B - B²
B² - 155B + 4950 = 0
Solving the quadratic equation above:
B² - 110B - 45B + 4950 = 0
B (B - 110) - 45(B - 110) = 0
(B - 110) ( B - 45) = 0
B - 110 = 0
B = 110
B - 45 = 0
B = 45
Substitute the value of B into equation (3)
L = 155 - B
L = 155 - 45
L = 110
The dimension of the field is ( 110 x 45)
