Metal panels that are designed to act as stressed-skin panels are attached directly to the structural frame of the building with
a. bags
b. straps
c. clips
d, mats

The spring 2 has more stored elastic potential energy due to its greater extension.

The energy stored in a spring is known as elastic potential energy. This energy increases with increase in the extension of the spring.

Mathematically, the energy stored in an elastic spring is given by the following formula.

U = ¹/₂kx²

where;

From the formula given above, the energy stored in the spring increases with increase in the extension of the spring.

Thus, for two identical springs, that is two springs with the same spring constant, the energy stored in each spring depends on the extension of the spring.

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A 25° ramp must be  174.4 m long to slow to a momentary stop a runaway truck moving along.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction.

Initial velocity: u = 85 mile/hour = 85 × 0.45 m/s = 38.0 m/s

Acceleration due to gravity: g = 9.8 m/s²

As the ramp is 25° inclined, the deceleration: a = g sinα = 9.8×sin25° m/s² = 4.14 m/s².

Hence, required distance = u²/2a = 38.0²/(2×4.14) = 174.4 m.

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The convection currents will be due to the attraction of gravity that exists between the moon and the sun.

This is going to be due to the forces of attraction that exist between the earth with the sun and the moon. It will have a difference in position of the sun with respect to the earth. It will also influence the changes that the position of the earth has with respect to the orbit of the sun.

This will also vary as the earth is not stable in one part of its orbit but will move, which may give heat to different parts of the earth but there are still differences in heat in different sectors.

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From Hooke's law F=k×Δx, the force constant of springk= 1032 N/m. If object with m of 630g is hung on spring then force of the object acting on the spring is 6.17 N. A greater spring constant implies a tougher spring.

According to Hooke's law, the amount of force used to stretch an elastic item is proportional to that force. The object won't return if it is stretched very far, though.

The spring constant K is a constant that is always positive. As seen by the negative sign, the restoring force is acting in the opposite direction to that of the applied force.

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The core (nucleus) of an atom is made up of protons and neutrons. Protons have a charge, whereas neutrons have no charge. A cloud of charged particles known as electrons surrounds the nucleus. Electrons have a charge that is diametrically opposed to the charge on the

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The forces that act are;

b)950 Kg

c) 522.5 N

d) 9,500 N

e) 4015 N

f) 9,500 N

g)3444 N

When we talk about the free body diagram, we want to show the diagram that is incorporating all the forces that do act on the object as it is moving down the plane in the object.

b) The mass of the box is; Weight/ acceleration due to gravity = 9500 N/10 m/s^2

= 950 Kg

c) The net force is obtained as mass * acceleration = 950 Kg * 0.55 m/s^2

= 522.5 N

d) The normal force is the weight of the object which is 9,500 N

e) The applied force is obtained as mgsinθ = 950 * 10 * sin 25

= 4015 N

f) The force of gravity is the weight of the box = 9,500 N

e) The frictional force is; μmg cosθ = 0.4 * 950 * 10 * cos 25

=3444 N

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These filters each have a different purpose and can be used according to the requirement.

A low-pass filter is a filter that allows signals with frequencies lower than a certain cutoff frequency to pass while attenuating signals with frequencies greater than the cutoff frequency. The frequency response of the filter is determined by its design. Low-pass filters are used in audio amplifiers, equalizers, and speakers and have applications such as anti-aliasing, reconstruction, and speech processing.

A high-pass filter is an electrical filter that allows signals with frequencies higher than a specific cutoff frequency to pass while attenuating sounds with frequencies lower than the cutoff frequency. The degree of attenuation for each frequency is determined by the filter design. A high pass filter is used to eliminate undesirable noises at the bottom of the audible range.

A band-pass filter, is a device that passes frequencies within a specific range while rejecting frequencies outside of that range. Band-pass filter functions are employed when it is intended to transmit signals within a specific frequency band while blocking signals at lower and higher frequencies. This is what "tuning" a desired frequency, such as a radio or television transmission, entails.

A band-stop filter, also known as a band-rejection filter, is a signal processing filter that passes most frequencies unmodified while attenuating those in a certain frequency range to very low levels. It's the inverse of a band-pass filter. A band stop filter is commonly used in audio signal processing to remove a specified range of undesired frequencies of sound, such as noise or hum, without attenuating the remainder.

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Answer:

emmm

I really think that the answer to the whole thing will be

S2 +O4+113

The virtual focus of a person is -2m and the power of bi focal spectacles for a person who can see between 50cm and 2m is -0.5D

The true focus is the location of the actual convergence, while the virtual focus is the location from which the diverging rays appear to arise as they are stretched backward. In the case of a convex lens, real focus is attained, and in the case of a concave lens, virtual focus is attained.

Visible object distance (u)= 2m

Image distance (v) = infinity

Focal length (f) formula => 1/v - 1/u = 1/f

                                      => 1/infinity - 1/2 = 1/f

                                      => f = -2m

The relation between power (P) and focal length (f) => P = 1/f

                                                                     P = 1/-(2) => -0.5D

The ciliary muscles gradually become less flexible and the eye lens becomes less flexible, which leads to presbyopia. A bifocal lens is used to repair the problem in eyes that have both myopia and hypermetropia.

Visible object distance (u)= 2m

Image distance (v) = infinity

Focal length (f) formula => 1/v - 1/u = 1/f

                                      => 1/infinity - 1/2 = 1/f

                                      => f = -2m

The relation between power (P) and focal length (f) => P = 1/f

                                                                     P = 1/-(2) => -0.5D

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No, the given data of runners speed is not a precise data as this variation is not possible for a runner.

Measurements are called as precise when we measure the same item multiple times and the values of each measurement are close to each other. However, the precision tells us nothing about whether the measured values are near to the correct value or not. Measurements that  are made can be close to each other but far from the proper value of the measurement.

In order to get the most reliable results in a scientific inquiry or measurement, it is important to minimize the bias and error in experiment, as well as to be precise and accurate in the collection of data.

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Your question is incomplete, most probably the complete question is:

The following data was collected for a runners speed: 4 mi/hr, 3 mi/hr, 6.9 mi/hr, and 7 mi, hr. Is this data precise? Explain

The resistance of the cylinder is 50 ohms.

The cylinder's resistance is calculated by applying Ohm's law as shown below;

Mathematically, the formula for Ohm's law is given as;

R = Δ V / ΔI

where;

The resistance of the cylinder is calculated as follows;

R = ( 100 V - 0 V ) / ( 2 A - 0 A)

R = ( 100 V ) / ( 2 A )

R = 50 ohms

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The output light frequency of material used before doubling will be 0.056 Hz.

The term frequency refers to the number of repetitions that there will be for a certain unit of time. Frequency is usually measured in hertz (Hz). The hertz is going to tell us the number of frequencies per second, which would then be a cycle per second.

The frequency can be calculated by counting the number of occurrences within a time interval and dividing by the time that elapsed in that period. So the calculation will be:

                                                  1 Hz=[tex]\frac{1}{s}[/tex]

A term that is related to the frequency and that is reciprocal to it is the period, which refers to the duration of time of a cycle in an event that is going to be repeated.

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The force acting on the 0.10 kg apple with a velocity of  -5.88 m/s and time of 0.6 sec is 0.98 Newton.

Any action that has the ability to alter, maintain, or modify a body's motion is considered a force in mechanics. Isaac Newton's Principia Mathematica has three laws of motion that are usually used to explain the concept of force (1687).

A body at rest or consistently moving in a straight path is said to remain in that state until a force is applied to it, according to Newton's first law. A body will accelerate (change in velocity), in accordance with the second rule, in the direction of any external force acting on it.

Calculate the change in velocity as shown below,

V = -6.86 - (-0.98)

V = -5.88

The time for this change in velocity,

T = 0.70 - 0.10

T = 0.6

Calculate the force as shown below,

Force = 0.10 × (-5.88) / 0.6

Force = -0.588 / 0.6

Force = -0.98 N

Thus, the force acting on the apple is 0.98 Newton.

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What is significant about John Michell’s contribution to the study of black holes is that he was the first to mention black holes in his writings.

The correct option is A.

A black hole is an area of spacetime with a gravitational pull so intense that nothing, not even light or other electromagnetic waves, can travel beyond its event horizon.

A sufficiently compact mass can distort spacetime to create a black hole, according to the general relativity theory.

The idea of "black stars," or objects that, if compressed to a sufficiently small size, would have an escape velocity that exceeded even the speed of light, was initially put forth by John Michell in 1783.

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The figure (E) is the great free diagram, showing the forces operating on the blocks at period t = 0.05 seconds, according to the provided statement.

Vehicle operation on a surface- Whenever an vehicle is still being driven, the engine exerts a force on the wheel that propels the vehicle forward. The car can't move ahead because of the friction between wheels and indeed the ground. Consequently, the car keeps from skidding.

Although friction is assumed to be created by the reactions here between microscopic bumps on surfaces when they rub against one other, scientists are not quite clear what causes it. It is challenging to for surfaces to slide over one another because the peaks on each face flex and exert stress on one another.

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The complete question is-

A block on a level horizontal surface of negligible friction is initially traveling at 20 m/s to the left. A horizontal force F is exerted to the right on the block for the time interval 0 <1 <0.10 s. The magnitude of the force is given as a function of time I by the equation F = at. where a = 240 N/s and t is in seconds.

Which of the following free-body diagrams best shows the forces acting on the block at time t= 0.05 s?

False, When anything is amplified, it is made larger; in the case of sound, this increases the loudness of the sound. Although it is not the only one, sound frequency is a significant factor in how we interpret sounds.

Wavelength, time period, amplitude, frequency, and speed are the five properties of a sound wave. A sound wave's frequency determines its pitch, while its amplitude determines how loud it sounds. The aspect of sound that most influences pitch is frequency. The range of frequencies that people can hear is considerably influenced by their environment, although the commonly acknowledged standard range of audible frequencies for humans is 20 to 20,000 Hz. When you magnify anything, you make it bigger; in the case of sound, this raises the volume.

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When something is amplified, it becomes smaller; in the case of sound, this reduces the volume of the sound. This claim is untrue.

Any sound that has been amplified by a man-made device is one that has been made louder. Bullhorns, speakers, drums, and sound systems all make sound louder. You will likely exceed the typical noise decibel limitations if you plan to have a band, stereo, or speaker on a microphone or bullhorn, in which case you will require a noise variance.

The teacher's voice in the classroom is amplified by a Sound Amplication System (SAS). It operates by dispersing an enhanced signal in a portion of the classroom where speakers are located.

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1) The displacement is 0 mi. Option A

2) The average speed is 20 mi/hr. Option C

3) The average velocity is 0 mi/hr. option A

We know that when we talk about the speed, we would look at the ratio of the average distance to the average time that is taken and this would span the entire journey not only a section of the journey.

We must note that the displacement is a vector quantity and as such, we have to look at the direction of the motion of the object.

Displacement = 5 miles - 5 miles = 0 miles

Average speed = Total distance/ Time = 5 miles + 5 miles/ 0.5 hr = 20 mi/hr

Average velocity = Displacement/Time = 0 miles// 0.5 hr =  0 mi/hr

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We can conclude that due to large difference in the charges between two positive charges, positive charges are displaced at opposite end and object B get concentrated with negative charges that allows ball to move towards Object B.

Positive charge is described as a charge that exists in a body that has fewer electrons than protons.

It is a known rule that unlike charges attract each other and like charges repel each other but it happens in a very rare case when like charges attract each other. It is so due to charge difference between the objects.

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Complete question:

Two positively charged objects (Object A and Object B) are 8 inches apart. When a positively charged ball is hung at an equal distance between the two positively charged objects, the ball moves toward object B (see figure).

What can you conclude about the relative amount of positive charge on Object A and Object B?

(a) At time, t = 1 s, the net force on the object  is 10.8 N.

(b) At time, t = 4 s, the net force on the object is 8.1 N.

(c) At time, t = 7 s, the net force on the object is 3.1 N.

The net force acting on the object is calculated by applying Newton's second law of motion.

F = ma

where;

F = mv/t

where;

At time, t = 1 s, the net force on the object is calculated as;

F = ( 2.7 x 4 ) / 1

F = 10.8 N

At time, t = 4 s, the net force on the object is calculated as;

F = ( 2.7 x 12 ) / 4

F = 8.1 N

At time, t = 7 s, the net force on the object is calculated as;

F = ( 2.7 x 8 ) / ( 7 )

F = 3.1 N

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The magnitude of the acceleration of a proton at rest at point c and d is  1.53 x 10⁶ m/s².

The centripetal acceleration of the proton is calculated by applying the formula for magnetic force and centripetal force as shown below.

F = ma = qvB

a = qvB / m

where;

a = q(r/t)B / m

a = ( qrB ) / ( mt )

a = ( qr / m) (B/t)

where;

The acceleration of the proton is calculated as follows;

a = ( 1.6 x 10⁻¹⁹ x 0.02 x 0.8 ) / ( 1.67 x 10⁻²⁷ )

a = 1.53 x 10⁶ m/s²

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An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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Explanation:

u=0

v=100

T=1min that 60 second

a=?

Formula

=

V=U+AT

100=0+a×60

100=60a

a=100/60 =1.66

To find Distance

S=ut+1/2at×t

s=0×60+1/2×1.66×60×60

s=0+1/2×1.66×3600

s=0.83×3600

s=2988

Answer:

hydro-energy

Explanation:

hydro-energy is cheap unlimited, successful, and a renewable resource:)

Answer:a i think

Explanation:

When a longitudinal wave passes through air, the instantaneous acceleration of the particle is proportional to its displacement. Hence, option (B) is correct.

Simple harmonic motion is a specific sort of periodic motion of a body that arises from a dynamic equilibrium between an inertial force in mechanics and physics (often referred to as SHM).

It operates as a restoring force on the moving object that is directly proportional to the size of the object's displacement and acts in the direction of the object's equilibrium position. It is proportional to the acceleration of the body away from the static equilibrium position.

When a longitudinal wave passes through air, the particles of the air posses simple harmonic motion. Hence,  the instantaneous acceleration of the particle is proportional to its displacement.

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Answer:

1.

Explanation:

The direction of (gravitational) acceleration is toward the Earth (1.) at every point of the trajectory, including the R point too.

Answer: 4167 turns

Explanation: Given turns in Primary coil(Np) = 200 Turns

Voltage provided(Vp) =120V..........    (Primary Voltage)

Required Voltage(Vs) = 25,000V .............(Secondary Voltage)

Turns in Secondary Coil (Ns) =?

As we know Ns/Np=Vs/Vp

so     Ns/200=25,000/120

120*Ns= 50,00,000

Ns = 4167 Turns

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Answer:

Yes, the driver traveled far enough to reach the office.

Explanation:

We can use the formula

[tex]v=\frac{x}{t}[/tex]

We are given

[tex]x=30[/tex] KM

[tex]t=45[/tex] min

[tex]v=50[/tex] KM/H

Lets convert minutes to hours.

To convert minutes to hours divide the speed by 60.

[tex]\frac{45}{60} =\frac{3}{4} =0.75[/tex]

Now we have

[tex]x=30[/tex] KM

[tex]t=0.75[/tex] H

[tex]v=50[/tex] KM/H

[tex]v=\frac{x}{t}[/tex]

Solve for x.

[tex]x=vt[/tex]

Lets substitute our values into the equation.

[tex]x=50*0.75[/tex]

[tex]x=37.5[/tex]

[tex]37.5 > 30[/tex] So the answer is yes;  the driver traveled far enough to reach the office.

The driver has to travel 35 km to reach the office. The distance he covered with a speed of 50 km/h within 45 minutes or 0.75 hour is 37.5 km. Hence, he travelled enough to reach the office.

Velocity of a moving body is the measure of distance it covered within unit time. The velocity is a vector quantity and have a magnitude and direction. The units of velocity are km/h, m/s etc.

Velocity is the ratio of change in distance to the change in time. Hence, distance can be calculated by multiplying the velocity with time.

Given that, velocity of the driver = 50 Km/h

time taken = 45 minutes = 45/60 =0.75 hr

Therefore, the distance = 0.75 hr × 50 km/h = 37.5 km

The distance to the office is 30 km. Therefore, the driver traveled far enough to reach the office.

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Because the focus of a convex mirror is on the right side and behind the mirror, it has a positive focal length.

Conventionally, distances along the central axis are measured as positive from the mirror toward the object and negative away from the object. As a result, the focal length and radius of curvature are positive for concave mirrors and negative for convex mirrors.

The focal length is always positive for converging lenses and always negative for divergent lenses. This is done according to sign convention in ray optics.

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Answer:

200,821.6 J

Explanation:

GPE = mgh = (436 kg)(9.8 m/s²)(47 m) = 200,821.6 J