metres> -21,23Sup10f3: Wandere first rareAnswerTeir wiced data prosto w will be whermerson is us. There will stand er is danfromGoethe type of boundary lineDashedEnter two points on the boundary lineSelect the repon you wish to be shaded:

Metres> -21,23Sup10f3: Wandere First RareAnswerTeir Wiced Data Prosto W Will Be Whermerson Is Us.

Answers

Answer 1

Given

[tex]\begin{gathered} x>-2 \\ y\ge3 \end{gathered}[/tex]

The graph

[tex]\begin{gathered} x>-3\text{ the pink colour} \\ y\ge3\text{ the blue colour} \end{gathered}[/tex]

Two boundary points

[tex]\begin{gathered} \lparen-2,3) \\ \lparen-2,0) \end{gathered}[/tex]

Metres> -21,23Sup10f3: Wandere First RareAnswerTeir Wiced Data Prosto W Will Be Whermerson Is Us.
Metres> -21,23Sup10f3: Wandere First RareAnswerTeir Wiced Data Prosto W Will Be Whermerson Is Us.

Related Questions

How do I know which score is the highest frequency? how do I figure the scores had a frequency of 2?

Answers

To determine the score which presents the highest frequency, we need to check the last column, the frequency one, and find the highest value among them. The score which is in the same row that this value will be the score with the highest frequency.

In the present problem, there are values of frequency equal to 1, 2, 3, and 4. The one with frequency 4 is the one with the highest frequency. (8th row). And the Score related to it is Score 8.

Once we check the frequency column once again, we see that the 2nd, the 4th, and the 7th rows have a frequency equal to 2.

Checking the Scores of the related rows, we are able to say that the scores with frequency 2 are: 2, 4, and 7.

how can you obtain the points for the log below from its inverse?

Answers

Answer

Check Explanation

Explanation

The laws of logarithms will come in handy in helping to obtain the points for the log from its inverse.

Before we commence, the two laws of logarithms that we will be using is that

log₄ 4ᶜ = c (log₄ 4)

And

log₄ 4 = 1

So, no matter the value of inverse given, a simple mathematical evaluation will give the log points.

when x = 1

f(x) = log₄ x

f(1) = log₄ 1 = log₄ 4⁰ = 0 log₄ 4 = 0 × 1 = 0

when x = 4

f(x) = log₄ x

f(4) = log₄ 4 = log₄ 4¹ = 1 (log₄ 4) = 1 × 1 = 1

when x = 16

f(x) = log₄ x

f(16) = log₄ 16 = log₄ 4² = 2 (log₄ 4) = 2 × 1 = 2

when x = 64

f(x) = log₄ x

f(64) = log₄ 64 = log₄ 4³ = 3 (log₄ 4) = 3 × 1 = 3

Hope this Helps!!!

make a table of values then graph the following quadratic functions, label atleast 5 points

Answers

Given the function below:

[tex]f(x)=\frac{-4(x-3)^2}{9}+4[/tex]

Substituting each value of x in the table in the function above, we get

[tex]\begin{gathered} f(0)=\frac{-4(0-3)^2}{9}+4\text{ = }\frac{-4(-3)^2}{9}+4 \\ \\ f(0)=\frac{-4\times9}{9}+4\text{ =-4+4 = 0} \end{gathered}[/tex][tex]f(1)=\frac{-4(1-3)^2}{9}+4\text{ =}\frac{-4\times4}{9}+4=\frac{-16}{9}+4=\frac{20}{9}[/tex][tex]f(6)=\frac{-4(6-3)^2}{9}+4\text{ = }\frac{-4(3^2)}{9}+4\text{ =-4+4 = 0}[/tex]

A triangle has two sides of length 13 and 17. What is the largest possible whole numberlength for the third side?

Answers

Given two sides of a triangle, x, and z, such that

[tex]x\le z[/tex]

then the third side y must satisfy the following condition

[tex]z-xIn our case,

x =13, and z = 17

Then, the third side y

lies in

17-13 < x < 17 +13

4 < x < 30

Hence the largest possible whole number of the third side is 29

Which of the following is a proportion?8/10=6/83/4=12/154/6=9/126/9=8/12

Answers

To be able to determine which among the choices is a proportion, you check if each side has the same common ratio.

A. 8/10 = 6/8

Ratio: 0.80 = 0.75 (Not Proportional)

B. 3/4 = 12/15

Ratio: 0.75 = 0.80 (Not Proportional)

C. 4/6 = 9/12

Ratio: 0.67 = 0.75 (Not Proportional)

D. 6/9 = 8/12

Ratio: 0.67 = 0.67 (Proportional)

Since the ratio of each side of letter D is equal, Letter D is the one that is in Proportion.

The percentage of students in the school that attended the talent show for the years 2008 to 2013 are shown.This Year, the school had a total of 360 students. How many students do you expect to attend the talent show this year? Explain.

Answers

Considering this year as the last year in the table which is 2013

[tex]\text{the total number of students in 2013=360}[/tex][tex]\text{The percentage of students attendance in 2013=95\%}[/tex]

Therefore,

The number of students to attend this year's talent show will be calculated by

[tex]A\text{ttendance}=\text{percentage of students}\times total\text{ number of students}[/tex][tex]\begin{gathered} \text{Attendance}=95\text{ \%}\times360 \\ \text{Attendance}=\frac{95}{100}\times360 \\ \text{Attendance}=\frac{34200}{100} \\ \text{Attendance}=342\text{ students} \end{gathered}[/tex]

Hence.

The attendance for this year is 342 students

Answer the statistical measures and create a box and whiskers plot for the following set of data.

Answers

Solution

The picture below is the solution to the problem

Brief explanantion

From the data given, It is obvious that:

Minimum = 2

Maximum =

The total number of the data is 3, so the number 7th term is the median

Thus,

Median = 8

To find Q1

[tex]\begin{gathered} Q_1=\frac{1}{4}(n+1)th\text{ term} \\ Q_1=\frac{1}{4}(13+1)=\frac{14}{4}=3.5 \end{gathered}[/tex]

Q1 is between the third and fourth term

Therefore, Q1 is

[tex]Q_1=0.5(4)+0.5(6)=5[/tex]

Similarly, to find Q3

[tex]\begin{gathered} Q_3=\frac{3}{4}(n+1)th\text{ term} \\ Q_3=\frac{3}{4}(13+1)=3\times\frac{14}{4}=3\times3.5=10.5 \end{gathered}[/tex]

Q3 is between the tenth and the eleventh term

Therefore, Q3 is

[tex]Q_3=0.5(11)+0.5(11)=11[/tex]

r is the midpoint of op and qr is perpendicular to op in the diagram below find the the length of qr

Answers

Given:

OP = 20 in

QP = 26 in

Since R is the midpoint of OP, then, OR = RP

Thus

[tex]OR=RP=\frac{OP}{2}=\frac{20}{2}=10\text{ in}[/tex]

To find the length of QR, use pythagoras theorem below:

[tex]\begin{gathered} a^2+b^2=c^2 \\ \\ RP^2+QR^2=PQ^2 \end{gathered}[/tex]

Input values into the formula:

[tex]10^2+QR^2=26^2[/tex]

Subtract 10² from both sides:

[tex]\begin{gathered} 10^2-10^2+QR^2=26^2-10^2 \\ \\ QR^2=26^2-10^2 \end{gathered}[/tex]

Take the square root of both sides:

[tex]\begin{gathered} \sqrt[]{QR^2}=\sqrt[]{26^2-10^2} \\ \\ QR=\sqrt[]{676-100} \\ \\ QR=\sqrt[]{576} \\ \\ QR=24 \end{gathered}[/tex]

Therefore, the length of QR is 24 in

i need help with this too

Answers

a The value of (2.3 × 10⁴) × (1.5 × 10^-2) is 3.45 × 10^2

b. The value of (3.6 × 10^-5) ÷ (1.8 × 10^2) is 2 × 10^-3. This illustrates the concept of standard form.

What is standard form?

The standard form is simply used in Mathematics to illustrate the numbers that are either too large or too small.

It's important to note that the multiplication of exponents is an addition and the division of the power is subtraction.

Therefore, (2.3 × 10⁴) × (1.5 × 10^-2) will be:

= (2.3 × 1.5) × (10^(4-2)

= 3.45 × 10^2

Also, (3.6 × 10^-5) ÷ (1.8 × 10^2) will be:

= (3.6 ÷ 1.8) × 10^(-5 + 2)

= 2 × 10^-3.

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the math club has 18 members and 50% are sixth graders.The science club has 25 members and 40% are sixth graders. The principal wants to know which club has more sixth graders.

Answers

The science club had more sixth graders.

How to calculate the value?

The math club has 18 members and 50% are sixth graders. The number of sixth graders will be:

= Percentage × Number of members

= 50% × 18

= 0.5 × 18

= 9

The science club has 25 members and 40% are sixth graders. The number of sixth graders will be:

= Percentage × Number of members

= 40% × 25

= 0.4 × 25

= 10

Since 10 is more than 5, the science class has higher number.

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A coin is tossed nine times what is the probability of getting all tails express your answer as a simplified fraction or decimal rounded to four decimal places

Answers

The probability of getting a tail on each toss is:

[tex]\frac{1}{2}[/tex]

Since there is only one way of getting all tails, it follows that the required probability is given by:

[tex](\frac{1}{2})^9\approx0.0020[/tex]

Hence, the required probability is approximately 0.0020

Determine a third pair of congruent parts to establish congruence between the triangles. Give the congruence postulate involved

Answers

In this problem, we have that

mYO ≅ XO

The third pair of congruent parts is

m by vertical angles

therefore

triangle YOT ≅ triangle XOB ----> by ASA congruence postulate

Graph the linear equation.
x=-2/12/12
X=
Use the graphing tool to graph the linear equation.
Click to
enlarge
graph
3
10
8
6
2
d
4
6
8
40

Answers

The graph of (3, 2) is located 3 units to the right of the y-axis and 2 units above the x-axis, while the graphs of (-3, 2), (-3, -2) and (3, -2) are located 3 units to the left of the y-axis and 2 units below the x-axis, 3 units to the right of the y-axis, and 3 units to the bottom of the x-axis, respectively.

What is linear equations?

The ordinate of the point is the distance from the x-axis that it is placed at, and the abscissa of the point is the distance from the y-axis that it is located at. An algebraic equation of the type known as a linear equation.

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Write a mathematical sentence that expresses the information given below. Use b as your variable name. If necessary:

type < = to mean

or > = to mean .

If you need to show multiplication, do not use the letter x. Use the asterisk ( * ) symbol instead, or simplify your answer.

Emily has 300 books. If Frank were to double the number of books that he now owns, he would still have fewer than Emily has.

Answers

The number of books owned by frank is represented as b < 150

What is inequality?

Inequality represents the form of writing expressions where the left hand side of the expression is not exactly equal to the right hand side of the expression

How to represent the required expression

Information gotten from the data include

Emily has 300 books

Frank were to double the number of books that he now owns, he would still have fewer than Emily has.

Let the number of books owned by frank be b and from the information we have that:

2b < 300

b < 150

hence the number of books owned by frank, b less than 150

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a turtle swims 15 kilometers in 9 hours how long does it take the turtle to swim 18 kilometers?

Answers

Answer:

10.8 hours or 648 minutes

Step-by-step explanation:

1. Find a factor of 15 and 18 kilometers. A similar factor is 3.

2. Find how long it will take the turtle to swim 3 kilometers.

3. Divide 9 by 5 which is how long it takes to swim three hours. (Keep it in a fraction for now)

4.Multiply 9/5 by 6 to get 18 hours; which is 10.8 hours.

Pep Boys Automotive paid $208.50 for a pickup truck bed liner. The original selling price was $291.90, but this was marked down 35%. If operating expenses are 28% of the cost, find the absolute loss

Answers

Step 1: State the given in the question

THe following were given:

[tex]\begin{gathered} \text{Amount Paid (}A_{\text{paid}})=208.50 \\ (Originalsellingprice)SP_{ORIGINAL}=291.90 \\ \text{Marked Percentage=35\%} \\ \text{Operating expenses=28\%} \end{gathered}[/tex]

Step 2: State what is to be found

We are to find the absolute loss

Step 3: Calculate the selling price

Please note that the selling price is the marked down price

The marked down price would be

[tex]\begin{gathered} P_{\text{MARKED DOWN}}=(100-35)\text{ \% of original selling price} \\ P_{\text{MARKED DOWN}}=65\text{ \% of }SP_{ORIGINAL} \\ P_{\text{MARKED DOWN}}=\frac{65}{100}\times291.90=189.74 \end{gathered}[/tex]

The selling price is the marked down price which is $189.74

Step 4: Calcualte the operating expenses

Please note that the cost price is amount paid. Therefore, the operating expenses would be as calculated below:

[tex]\begin{gathered} E_{\text{OPEARATING}}=28\text{ \% of Amount Paid} \\ E_{\text{OPERATING}}=28\text{ \% of }A_{\text{paid}}=\frac{28}{100}\times208.50 \\ E_{\text{OPERATING}}=0.28\times208.50=58.38 \end{gathered}[/tex]

Hence, the operating expenses is $58.38

Step 5: Calculate the total cost price

The total cost price is the addition of the cost price and the operating expenses. This is as calculated below:

[tex]\begin{gathered} C_{\text{TOTAL COST PRICE}}=E_{OPERATING}+A_{PAID} \\ C_{\text{TOTAL COST PRICE}}=58.38+208.50=266.88 \end{gathered}[/tex]

Hence, the total cost price is $266.88

Step 6: Calculate the absolute loss

The absolute loss is the difference between the total cost price and the marked down price (or the actual selling price). This is as calculated below:

[tex]\begin{gathered} L_{\text{ABSOLUTE LOSS}}=C_{TOTAL\text{ COST PRICE}}-P_{MARKED\text{ DOWN}} \\ L_{\text{ABSOLUTE LOSS}}=266.88-189.74=77.14 \end{gathered}[/tex]

Hence, the absolute loss is $77.14

name each angle pair as corresponding, alternate interior, alternate exterior, consecutive interior angle, or no relationship. identify the transversal that connects each angle pair.

Answers

[tex]\begin{gathered} \text{Alternate interior angles} \\ 10,5\text{ transversal l} \\ 4,15\text{ transversal m} \\ 13,2\text{ transversal }l\text{ } \\ 7,12\text{ transversal }m \\ \text{Alternate exterior angles} \\ 1,14\text{ transversal l} \\ 9,6\text{ transversal l} \\ 11,8\text{ transversal }m \\ 3,6\text{ transversal }m \\ \end{gathered}[/tex]

Nikki and four friends had lunch at their favorite restaurant. The total bill was $29.00, and they wanted to leave a 15% tip. Which amount of money is closest to the 15% tip? A $3.00 B $3.50C $4.00D $4.50

Answers

Total bill = $29

Tip left = 15%

The valu of the tip = 15% of $29

[tex]\begin{gathered} \frac{15}{100}\text{ x 29} \\ \\ =\text{ \$4.35} \end{gathered}[/tex]

The value of the tip = $4.35

Let us consider the options given

$4.35 - $3 = $1.35

$4.35 - $3.5 = $0.85

$4.35 - $4 = $0.35

$4.5 - $4.35 = $0.15

Looking t the deviation from the real value of the tip ($4.35), the least deviation is $0.15. Hence, we can conclude that $4.5 is the closest to the tip.

The answer is option D ($4.50)

Olivia goes out to lunch. The bill, before tax and tip, was $13.90. A sales tax of 6% was added on. Olivia tipped 23% on the amount after the sales tax was added. How much was the sales tax? Round to the nearest cent.

Answers

According to the information given in the exercise, the bill before the tax and tip was $13.90 and the sales tax of 6% was added to that amount.

By definition, you can write 6% as a Decimal number by dividing it by 100. Then, this is:

[tex]\frac{6}{100}=0.06[/tex]

Let be "t" the amount (in dollars) of the sales tax.

To find the value of "t", you can set up the following equation:

[tex]t=(13.90)(0.06)[/tex]

Finally, evaluating, you get that this is:

[tex]t=0.834[/tex]

Rounded to the nearest cent, this is:

[tex]t\approx0.83[/tex]

The answer is: $0.83

There is a 40% chance that it will be cloudy tomorrow.

If it is cloudy, there is a 79% chance that it will rain.

What is the probability that it will rain?

Answers

Answer:

3.16%

Step-by-step explanation:

a*(79/100)*40/100

3.16a/100

3.16%

Answer:

O. 316

Step-by-step explanation:

40/100 × 79/100 =0.316

Find x when the f(x) = 350 - 125x ; when f(x) = 0.

Answers

ANSWER

x = 2.8

EXPLANATION

The function given is:

f(x) = 350 - 125x

We want to find the value of x when f(x) = 0.

This means that:

[tex]\begin{gathered} f(x)\text{ = 350 - 125x} \\ \Rightarrow\text{ 0 = 350 - 125x} \\ \Rightarrow\text{ 125x = 350} \\ \frac{125x}{125}\text{ = }\frac{350}{125} \\ x\text{ = 2.8} \end{gathered}[/tex]

That is the value of x

Please help:What are the zeros of the quadratic function?f (z )= 3z^2 − 11z − 4Enter your answers, as simplified fractions if necessary, in the boxes.The zeros of f (z) are __ and __.

Answers

We need to find the zeros for the next function:

[tex]f(z)=3z^2−11z−4[/tex]

We can find those zeros using the quadratic formula given by:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Use the form ax²+bx+x.

Where a=3

b= -11

c=-4

Replacing :

[tex]\begin{gathered} x=\frac{-(-11)\pm\sqrt{(-11)^2-4(3)(-4)}}{2(3)} \\ Simplify \\ x=\frac{11\pm\sqrt{169}}{2\ast3} \\ x=\frac{11\pm13}{2\ast3} \\ Therefore: \\ x_1=\frac{11-13}{6}=\frac{-2}{6}=-\frac{1}{3} \\ x_2=\frac{11+13}{6}=\frac{24}{6}=4 \end{gathered}[/tex]

Therefore, the zeros of f (z) are -1/3 and 4.

5x^2+2x-3 and x+4 how do I find the area

Answers

You have a rectangle with the followinf expressions for its sides:

w: width = 5x² + 2x - 3

h: height = x + 4

In order to calculate the area of the rectangle, you use the following formula for the area:

A = w*h

By replacing w and h by the given algebraic expressions you have:

A = (5x² + 2x - 3)(x + 4) use distribution property

A = 5x²(x) + 5x²(4) + 2x(x) + 2x(4) - 3(x) - 3(4) simplify

A = 5x³ + 20x² + 2x² + 8x - 3x - 12 simplify similar terms

A = 5x³ + 22x² + 5x - 12

Hence, the total area of the figure is 5x³ + 22x² + 5x - 12

Simplify the following: (4x + 3) -2(4x - 7) - 3(x +7)

Answers

Simplify: (4x + 3) -2(4x - 7) - 3(x +7)

Explanation:

[tex]\begin{gathered} (4x+3)-2(4x-7)-3(x+7) \\ =4x+3-8x+14-3x-21 \\ =4x-11x+17-21 \\ =-7x-4 \end{gathered}[/tex]

Final answer: -7x-4 is required simplify form .

What is the solution to 4x-8=12 please explain

Answers

Given the equation 4x-8=12 you need to clear the value of x.

First step is to leave the value of x in one side of the equation and the integers in the other side, to do so you have to add 8 to both sides of the equation

[tex]\begin{gathered} 4x-8=12 \\ 4x-8+8=12+8 \\ 4x=20 \end{gathered}[/tex]

Next you have to divide both terms of the equation by 4 to get the value of x

[tex]\begin{gathered} 4x=20 \\ \frac{4x}{4}=\frac{20}{4} \\ x=5 \end{gathered}[/tex]

The value of x=5

In 1980 approximately 4,825 million metric tons of carbon dioxide emissions were recorded for the United States. That number rose to approximately 6,000 million metric tons in the year 2005. Here you have measurements of carbon dioxide emissions for two moments in time. If you treat this information as two ordered pairs (x, y), you can use those two points to create a linear equation that helps you make predictions about the future of carbon dioxide emissions!A) Organize the measurements into ordered pairs. B) Find the slope,C) Set up an equation in point-slope form,D) Show the equation in slope-intercept form,E) Predict emissions for the year 2020,

Answers

ANSWER and EXPLANATION

A) To organize the measurements in ordered pairs implies that we want to put them in the form:

[tex](x_1,y_1);(x_2,y_2)[/tex]

Therefore, the measurements in ordered pairs are:

[tex]\begin{gathered} (1980,4825) \\ (2005,6000) \end{gathered}[/tex]

Note: 4825 and 6000 are in millions (10⁶) of metric tons

B) To find the slope, apply the formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, the slope is:

[tex]\begin{gathered} m=\frac{6000-4825}{2005-1980} \\ m=\frac{1175}{25} \\ m=47\text{ million metric tons per year} \end{gathered}[/tex]

C) To find the in point-slope form, we apply the formula:

[tex]y-y_1=m(x-x_1)_{}[/tex]

Therefore, we have:

[tex]y-4825=47(x-1980)[/tex]

Note: the unit is in million metric tons

D) To show the equation in point-slope form, we have to put it in the form:

[tex]y=mx+b[/tex]

To do that, simplify the point-slope form of the equation:

[tex]\begin{gathered} y-4825=47(x-1980) \\ y=47x-93060+4825 \\ y=47x-88235 \end{gathered}[/tex]

E) To predict the emissions for the year 2020, substitute 2020 for x in the equation above:

[tex]\begin{gathered} y=47(2020)-88235 \\ y=94940-88235 \\ y=6705\text{ million metric tons} \end{gathered}[/tex]

That is the prediction for the year 2020.

A portion of $ 100,000 (x) is invested with a 3% after one year. The rest of the investment (and) obtained a return of 1%. The total return on investment was $ 1,800. 1) What equation shows the return on investment? 2) What equation shows how the $ 100,000 was divided?3) how much money was invested at a 3% rate of return?4) how much money was invested at a rate of return of 1%

Answers

We can write a system of equations that describe our problem.

Since we don't know how the original $100,000 was divided, we call the two parts X and Y

So we know that X + Y = 100000

Then we know the Combined Interest coming from the accounts.

We use the Interest formula for return on investment:

I = P * r * t

were P is the principal, r is the percent rate (in decimal form), and t is the number of years (in our case 1)

Then the interest from the 3% account (let's call it I1) (if X amount of money was deposited there) is:

I1 = X * 0.03 * 1 = 0.03 X

Similarly, the interest I2 coming from the 1% account (if Y amount of money was deposited there) is given by:

I2 = Y * 0.01 * 1 = 0.01 Y

Then, the addition of these two interest is our total return of $1800:

0.03 X + 0.01 Y = 1800

Then our system of equations is:

X + Y = 100000

0.03 X + 0.01 Y = 1800

which we solve by substituting for example for Y in the first equation:

Y = 100000 - X

and replacing the Y by this expression in our second equation:

0.03 X + 0.01 (100000 - X) = 1800

use distributive property to eliminate parenthesis:

0.03 X + 1000 - 0.01 X = 1800

combine like terms

0.02 X + 1000 = 1800

subtract 1000 from both sides

0.02 X = 800

divide both sides by 0.02 to completely isolate X:

X = 800 / 0.02

X = $40000

This is the amount deposited on the 3% account

Then we easily calculate the amount deposited in the other account by replacing x with $40000 in the equation we use for substitution:

Y = $100000 - $40000 = $60000

Then, the amount deposited in the 1% account was $60000

and the amount deposited in the 3% account was $40000.

Question 2 (7 points)Match the fractions and decimals to the corrects percentage.

Answers

we can change a fraction to a percentage multiplying the fraction by 100

also, we can change a decimal number to a percentage multiplying by 100

for example

1. 1/5

[tex]\frac{1}{5}\cdot100=20[/tex]

In this case, 1/5 represent 20%

4. .625

[tex]0.625\cdot100=62.5[/tex]

In this case, 0.625 represent 62.5%

If we do the same process to all the next numbers we will obtain the next solutions.

1. 1/5 ------ a. 20%

2. 8/10 ------ f. 80%

3. 0.08 ------ d. 8%

4. .625 ---- g. 62.5%

5. 32/100 ---- b. 32%

6. 1/2 ------ c. 50%

7. 1.25 ---- e. 125%

How else can you write 6p in mathematic terms?

Answers

In mathematic terms, the expression 6p is written as 6 times p.

Mathematic terms

Mathematic terms means a single mathematical expression. The terms may be a single number, a single variable, several variables multiplied but never added or subtracted. Some of the terms contain variables with a number in front of them.  Those number in front of a term is called a coefficient.

Given,

Here we have the expression 6p.

Now, we have to write it as a mathematic term.

While we looking into the expression 6p.

The only operation word in this expression is p which is multiplied with the constant that is the number 6.

So, in the verbal phrase it can be written as 6 times p.

Here p take any valid number in the real numbers.

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I need help with this problem. Quick answer is fine

Answers

[tex]a^{\frac{-m}{n}}=\frac{1}{a\frac{m}{n}}=\frac{1}{\sqrt[n]{a^m}}[/tex]

Other Questions
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