Need help I have been stuck on this for a while

Answer:

0.56

Step-by-step explanation:

edu 2022

Answer:

B

Step-by-step explanation:

there are 30 buildings...

Considering the median, the missing value of the data-set is of 31.

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

In this problem, since the set has even cardinality, the median is the mean of the middle elements, which are 23 and x. Since it is of 27, we have that:

(23 + x)/2 = 27

23 + x = 54

x = 31

Hence, the missing value of the data-set is of 31.

More can be learned about the median of a data-set at https://brainly.com/question/24732674

In the history of Nepal, Rana Regime is known as Dark Age as it lacked freedom, public sovereignty, and public literacy.  

I would do the opposite of the things listed.

Answer:

The replicas will have a surface area of 3 m2, 2.4 m2 and 2 m2.

Step-by-step explanation:

You would have to multiply:

24 x 1/8 = 3

24 x 1/10 = 2.4

24 x 1/12 = 2

Answer: Answer is 4.25

Step-by-step explanation: Jus take you first number (2 over 8.50) and divide. You get 4.25. Now try to multiply or add for other numbers, and you find multiplying 4.25 by X will get you the answer of Y.

Answer: y = 9x - 14

Step-by-step explanation:

The equation of a line is y = mx + b

We know the slope is 9 so so far the equation we have is y = 9x + b.

Since we know (1,-5) is a point on the line, we can plug in the x and y values into the equation and we get:

-5 = 1*9 + b

-5 = 9 + b

b = -14.

Therefore, the equation of the line is y = 9x - 14

Hello.

Here we have a point that the line passes through: (1, -5)

We also have the line's slope: 9

Now, we have enough information to write the line's equation in Point-Slope Form:

[tex]\mathrm{y-y1=m(x-x1)}[/tex]

Plug in the values and solve:

[tex]\mathrm{y-(-5)=9(x-1)}[/tex]

[tex]\mathrm{y+5+9(x-1)}[/tex]

[tex]\mathrm{y+5=9x-9}[/tex]

[tex]\mathrm{y=9x-9-5}[/tex]

[tex]\mathrm{y=9x-14}[/tex]

Therefore, the answer is

[tex]\mathrm{y=9x-14}[/tex]

I hope it helps.

Have a nice day.

[tex]\boxed{imperturbability}[/tex]

Answer:

80 + 9x + 4 + 16x - 4 =180

25x = 180 - 80 + 4 - 4

25x = 100

x = 4

I can't see the question on the image...so not sure about final answer

Answer:

8.2 cm x 6.5 cm = an area of 53.3 cm

Answer:

53.3

Step-by-step explanation:

Multiply: 8.2cm*6.5cm

Answer: 53.3

Answer:

[tex] \displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8} }[/tex]

Convert the mixed fractions into improper fractions.

[tex]\displaystyle{ \frac{8 \times 4 + 3}{4} \div \frac{8 \times 2 + 7}{8} }[/tex]

[tex]\displaystyle{ \frac{32 + 3}{4} \div \frac{16 + 7}{8} }[/tex]

[tex]\displaystyle{ \frac{35}{4} \div \frac{23}{8} }[/tex]

[tex]\displaystyle{ \frac{35}{4} \times \frac{8}{23} }[/tex]

[tex]\displaystyle{ \frac{35}{ \cancel4} \times \frac{ \cancel8 {}^{2} }{23} }[/tex]

[tex] \displaystyle{ \frac{35 \times 2}{23} }[/tex]

[tex] \displaystyle{ \frac{70}{23} }[/tex]

[tex] \displaystyle{3 \frac{1}{23} }[/tex]

Answer:

8

Step-by-step explanation:

10 percent of 80 is 8

80 x 0.1 = 8

4 is 16 percent of 25

25/4 = 0.16

0.16 = 16%

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 80}}{\left( \cfrac{10}{100} \right)80}\implies 8 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{4\% of 25}}{\left( \cfrac{4}{100} \right)25}\implies 1[/tex]

Answer: 3

Step-by-step explanation:

Triangle DCB is similar to Triangle ECA by AAA.

Since EA and DB are parallel lines, that makes Angle CDB = Angle CEA and Angle CBD = Angle CAE because they are corresponding angles.

Since the two triangles are parallel, we can set up a ratio.

[tex]\frac{CD}{CE} = \frac{CB}{CA}[/tex]

Now we plug in the numbers given.

[tex]\frac{6}{8} = \frac{9}{CA}[/tex]

Now we can cross multiply

6CA = 72

Therefore, CA = 12.

AB = CA - CB

So AB = 12 - 9

AB = 3

[tex] \qquad \qquad \huge \underline{\boxed{ \sf {Answer}}}[/tex]

Let's solve ~

The given equations are :

[tex] \qquad \dashrightarrow \bf \: 3x + 4y = 36 \sf \: \: \: \: \: \: \: \: \: \: (1)[/tex]

and

[tex] \qquad \dashrightarrow \sf \:y = - \frac{1}{2} x + 8[/tex]

[ multiply each sides by 2 ]

[tex] \qquad \dashrightarrow \sf \: 2y = - x + 16[/tex]

[tex] \qquad \dashrightarrow \sf \:x + 2y = 16[/tex]

[ multiply both sides by 2 ]

[tex] \qquad \dashrightarrow \bf \: 2x + 4y = 32 \: \: \: \: \: \: \: \: \: \: \: \sf(2)[/tex]

Now, subtract equation (2) from (1)

[tex] \qquad \dashrightarrow \sf \: 3x + 4y - (2x + 4y) = 36 - 32[/tex]

[tex] \qquad \dashrightarrow \sf \: 3x + \cancel{4y }- 2x - \cancel{4y }= 4[/tex]

[tex] \qquad \dashrightarrow \bf \: x = 4[/tex]

Now, as we got the value of x, let's solve for y :

[tex] \qquad \dashrightarrow \sf \: y = - \dfrac{1}{2} x+ 8[/tex]

[tex] \qquad \dashrightarrow \sf \: y = -\dfrac{1}{2} (4)+8[/tex]

[tex] \qquad \dashrightarrow \sf \: y = - 2 + 8[/tex]

[tex] \qquad \dashrightarrow \bf \: y = 6[/tex]

Answer:

no clue but thanks for the points!

Step-by-step explanation:

Answer:

 (a)  A and B are similar but not congruent

Step-by-step explanation:

All of the rectangles have sides in the ratio of 2:1, so are all similar. Only the rectangles that are the same size are congruent: A and C.

 A and B are similar, but not congruent.

Answer:

Declare h. We can declare it as any number, so let's say 2.

h - 13 = 11 ↓

because h = 2.

Answer:

4

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST

Answer:

Ali is about 5-6 due to him having a larger stomach capacity.

Step-by-step explanation:

5-6 year olds would definitely eat about 4 cookies if somebody held 5, since they are open to sugary things, and they would eat possibly anything.

PLEASE MARK ME AS THE BRAINLIEST.

Answer:

Yes

Step-by-step explanation:

6/12 is 1/2 when you simplify

7/10 is more than 5/10 (one half of ten)
Please mark brainlest

Answer : Yes

Explanation : 6/12 Is 1/2 When You Simplify

7/10 Is More Than 5/10 (One Half Of Ten)

5/10 Is The Same As 1/2 Btw

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◊ YusuCr ◊

Answer:

[tex]\left|a\right|[/tex]

Step-by-step explanation:

Write the distance formula

[tex]\left|x_2-x_1\right|[/tex]

Find the distance

Find the distance between [tex]None(-1,a) and ():[/tex] [tex]\left|a\right|[/tex]

I hope this helps you

:)

Answer:

The distance between the pair of numbers is the absolute value of [tex]a[/tex], or [tex]|a|[/tex].

Step-by-step explanation:

Use the distance formula: [tex]d=|x_2-x_1|[/tex]. The [tex]x[/tex]s represent points one and two. Point one is [tex]-a[/tex], and point two is 0. Plug these into the equation, then solve:

[tex]d=|x_2-x_1|\\d=|(0)-(-a)|\\d=|a|[/tex]

Therefore, the distance between the pair of numbers is the absolute value of [tex]a[/tex], or [tex]|a|[/tex].

Label the points A,B,C

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

[tex]A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\[/tex]

Segment AB is exactly [tex]3\sqrt{2}[/tex] units long.

Now let's find the distance from B to C

[tex]B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\[/tex]

Segment BC is exactly [tex]4\sqrt{2}[/tex] units long.

Adding these segments gives

[tex]AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}[/tex]

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

[tex]A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\[/tex]

AC is exactly [tex]7\sqrt{2}[/tex] units long.

Therefore, we've shown that AB+BC = AC is a true equation.

This proves that A,B,C are collinear.

For more information, check out the segment addition postulate.

Answer:

h=78.4

Step-by-step explanation:

2/1.25 = h/49

Cross multiplication

1.25h = 2x49

1.25h=98

h= 78.4

                   CHECK:

         2/1.25 = 1.6

        78.4/49=1.6

Answer: 2.5 and 87.5 degrees

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

2+5=7
7*4=28

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15x + 17y = 31

17x + 15y = 21

- - -

───────

-2x + 2y = 10

→ -2 (x -y) = 10

→ x - y = -5

Value of (x - y) is -5

In this exercise we have to use the knowledge of equation to find the value, so:

[tex]x-y=-5[/tex]

The solution of a linear system is every ordered and finite set that satisfies all the equations of the system at the same time. The number of elements in the solution set is always equal to the number of unknowns in the system.

So we have:

[tex]15x + 17y = 31\\17x + 15y = 21\\-2x + 2y = 10\\-2 (x -y) = 10\\x - y = -5[/tex]

See more about system at brainly.com/question/9061107

#1

Just follow the naming

#2

Note the adjacent angles of JK

Answer:

-4, -1, 3, 5, 6

Step-by-step explanation:

-4, -1, 3, 5, 6

Answer:

Least to greatest would be:

-4, -1, 3, 5, and then 6.

Answer:

i think its a or d

Step-by-step explanation: