Need to graph and then mark length of stay (in days) on the bottom of the graph. Need 4 points on graph and 4 number on bottom of graph
Answers
given the data
13,9,5,11,6,3,12,10,11,7,3,2,2,2,10,10,12,12,12,8,8
sort data
s= 2, 2, 2, 3, 3, 5, 6, 7, 8, 8, 9, 10, 10, 10, 11, 11, 12, 12, 12, 12, 13
then we have
2 ---- 3
3 ----- 2
5----- 1
6 ---- 1
7 -----1
8------2
9 ------1
10-----3
11-------2
12------4
13-------1
Related Questions
Find the negative member of the solution set for |2x -4| =6
Answers
The negative solution of the absolute value function is x = - 1.
What is the negative solution of an absolute value set?In this problem we need to solve for x in an absolute value function, whose procedure is done by the use of algebra properties:
Step 1 - Initial condition:
|2 · x - 4| = 6
Step 2 - By definition of absolute value:
2 · x - 4 = 6 or - 2 · x + 4 = 6
Step 3 - By compatibility with addition, existence of additive inverse, associative, commutative and modulative properties:
2 · x = 10 or - 2 · x = 2
Step 4 - By compatibility with multiplication, existence of multiplicative inverse, associative, commutative and modulative properties we get this result:
x = 5 or x = - 1
The negative solution of the function is x = - 1.
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Please assist me in understanding how to solve number 4
Answers
Solution:
Given that;
y varies directly with the square of x
[tex]y\propto x^2[/tex]This expression above becomes
[tex]\begin{gathered} y=kx^2 \\ Where\text{ k is the constant} \end{gathered}[/tex]When
[tex]y=10\text{ and x}=5[/tex]Substitute the values for x and y into the expression above to find k
[tex]\begin{gathered} y=kx^2 \\ 10=k(5)^2 \\ 10=k(25) \\ 10=25k \\ Divide\text{ both sides 25} \\ \frac{25k}{25}=\frac{10}{25} \\ k=\frac{2}{5} \end{gathered}[/tex]The expression becomes
[tex]\begin{gathered} y=kx^2 \\ y=\frac{2}{5}x^2 \end{gathered}[/tex]a) The value of y when x = 20
[tex]\begin{gathered} y=\frac{2}{5}x^2 \\ y=\frac{2}{5}(20)^2 \\ y=\frac{2}{5}(400) \\ y=160 \end{gathered}[/tex]Hence, the value of y is 160
b) The value of x when y = 40
[tex]\begin{gathered} y=\frac{2}{5}x^2 \\ 40=\frac{2}{5}x^2 \\ Crossmultiply \\ 40(5)=2x^2 \\ 200=2x^2 \\ Divide\text{ both sides by 2} \\ \frac{200}{2}=\frac{2x^2}{2} \\ 100=x^2 \\ x^2=100 \\ Square\text{ root of both sides} \\ \sqrt{x^2}=\sqrt{100} \\ x=10 \end{gathered}[/tex]Hence, the value of x is 10
Given that A = {1, 2,2 3} and B = {4, 6}, then find B×A
Answers
The solution for set B × A is {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}
Given,
The sets,
A = {1, 2, 3}
B = {4, 6}
We have to find B × A.
Here,
Consider the Cartesian product:
The set of all ordered pairs (x, y) such that x belongs to A and y belongs to B is referred to as the Cartesian Product of sets A and B in mathematics. For instance, the Cartesian Product of A and B is (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), and (2, 5) if A = [1, 2] and B = [3, 4, 5].
The Cartesian product of B × A = {(b, a) | b € B, a € A}
So,
B × A = {4, 6} × {1, 2, 3}
B × A = {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}
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Identify the type of polar graph for the equation: r = 3-5cos θ aLimacon with inner loop bCardioid cDimpled limacon dConvex limacon eRose Curve fCircle gLemniscate
Answers
Given the equation:
[tex]r=3-5\cos \theta[/tex]Let's identify the type of polar graph for the equation.
To identify the type of polar graph, use the formula below to get the Cartesian form:
[tex](x^2_{}+y^2)=r(\cos \theta,\sin \theta)[/tex]Thus, we have:
[tex](x^2+y^2)=3\sqrt[]{x^2+y^2}-5x[/tex]We have the graph of the equation below:
We can see the graph forms a Limacon with an inner loop.
Therefore, the type of polar graph for the given equation is a limacon with inner loop.
ANSWER:
relation and functionFunction OperationComposition of functionsymmetryfunction Inversesrate of change scartterplotsMINIMUM STEPS PLEASE!
Answers
In order to find f(2) we just have to replace x by 2 in its equation:
f(x) = 3x - 1
↓
f(2) = 3 · 2 - 1
f(2) = 6 - 1
f(2) = 5
Finding g(x) = f(2)Since g(x) = f(2) is
g(x) = 5
using the equation of g, we have that
2x - 3 = 5
In order to find x we just solve the previous equation
2x - 3 = 5
↓ adding 3 both sides of the equation
2x - 3 + 3 = 5 + 3
2x = 8
↓ dividing by 2 both sides of the equation
2x/2 = 8/2
x = 4
Answer- D: x = 4
What would -5/6 be when turned into a decimal?
Answers
Answer:
answer is -0.8333
round about -0.834
Step-by-step explanation: I hope this helps.
Answer:
Find the common difference and the recursive formula. 22,19,16,13
Answers
The common difference between each term is -3.
19 - 22 = -3
16 - 19 = -3
13 - 16 = -3
The recursive formula of an arithmetic sequence follows the pattern below:
[tex]a_n=a_{n-1}+d,n\ge2[/tex]where d = common difference and number of terms "n" must be more than or equal to two.
To be able to get the recursive formula, we will plug in the common difference assuming that first term a₁ = 22. Therefore, the recursive formula is:
[tex]a_n=a_{n-1}-3,for\text{ n}\ge2[/tex]Determine the common ratio for each of the following geometric series and determine which one(s) have an infinite sum.
I. 4+5+25/4+…
II. -7+7/4-7/9+…
III. 1/2-1+2…
IV. 4- ++...
A. III only
B. II, IV only
C. I, Ill only
D. I, II, IV only
Answers
The correct answer is Option A ( III Only). I . -16 sum cannot be negative, II. Not a G.P, III. Sum = 1/4, and IV. Not a G.P.
Solution:Given geometric series,
I. 4 +5 +25 /4 ….
The common ratio(r) is (5/1)/(4/1) = 5/4.
S∞ = a / ( 1 - r)
= 4 / ( 1 - 5/4)
= 4 / -1/4
S∞ = -16.
Since sum cannot be negative.
II . -7 + 7/3 - 7/9+ ....
Here common ratio = -7 / (7/3) = -1/3
but - 7/9 / 7 /3 = 7/9
Here there is no common ratio so this not a G.P.
iii. 1/2 -1 + 2.....
Common ratio = -1 / (1/2) = -2
S∞ = a / ( 1 - r)
= 1/2 / (1 -(-2))
S∞ = 1/4.
iv 4 - 8/5 +16/5.....
Here there is no common ratio.
So this is not a G.P.
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currently, Yamir is twice as old as pato. in three years, the sum of their ages will be 30. if pathos current age is represented by a, what equation correctly solves for a?
Answers
The given situation can be written in an algebraic way.
If pathos age is a, and Yamir age is b. You have:
Yamir is twice as old as pato:
b = 2a
in three years, the sum of their ages will be 30:
(b + 3) + (a + 3) = 30
replace the b = 2a into the last equation, and solve for a, just as follow:
2a + 3 + a + 3 = 30 simplify like terms left side
3a + 6 = 30 subtract 6 both sides
3a = 30 - 6
3a = 24 divide by 3 both sides
a = 24/3
a = 8
Hence, the age of Pato is 8 years old.
f(x) = square root of x - 5. find f^-1 (x) and it’s domain
Answers
Given:
f(x) = root x - 5
Rewrite the function using y,
[tex]y=\sqrt[]{x}-5[/tex]Now, interchange the position of x and y in the function,
[tex]x=\sqrt[]{y}-5[/tex]Isolate the dependent variable
[tex]\begin{gathered} \sqrt[]{y}=x+5 \\ y=(x+5)^2 \end{gathered}[/tex]Therefore,
[tex]f^{-1}(x)=(x+5)^2[/tex]And the domain is minus infinity to infinity
[tex]\begin{gathered} f^{-1}(x)=(x+5)^2 \\ \text{Domain}=(-\infty,\infty) \end{gathered}[/tex]could you help me no other tutor will help and its heartbreaking so please try your hardest
Answers
The triangle has sides
a=8
b=14
c=19
You need to determine the measure of x
To determine the value of x you have to use the Law of Cosines that states that:
[tex]a^2+b^2-ab\cos \theta=c^2[/tex]Where a, b, and c are the sides of the triangle, and theta represents the angle we are looking for.
So first step is to replace the formula with the given data and solve the exponents
[tex]\begin{gathered} 8^2+14^2-8\cdot14\cos thetha=19^2 \\ 64+196-112\cos \theta=361 \\ 260-112\cos \theta=361 \end{gathered}[/tex]Next solve for the cosine of theta:
[tex]\begin{gathered} -112\cos \theta=361-260 \\ -112\cos \theta=101 \\ \cos \theta=\frac{101}{-112} \\ \cos \theta=-\frac{101}{112} \end{gathered}[/tex]And calculate the inverse cosine to determine the measure of the angle
[tex]\begin{gathered} \theta=\cos ^{-1}(-\frac{101}{112}) \\ \theta=154.39 \end{gathered}[/tex]determine the domain and range of the piecewise function graphed below
Answers
The domain is all the possible input values, and the range is all the possible output values.
So according to this function (Given in the question).
The domain is [-3, 5] and the range is [-5, 4]
That is all to this question.
I need help pls 1. Is this graph sine or cosine 2. What’s the amplitude of graph 3. What’s the equation of the midline 4. Whats the period of the function Whats the equation of the function Whats the domain and range?
Answers
As per given by the question,
There are given that a graph.
Now,
1. The given graph is cosine graph.
2. The aplitute of the given graph is,
From the graph, it is lie between -2 to 2.
So,
The amplitude of the given graph is 2.
Now,
3. The equation of the midline is,
[tex]y=-2[/tex]Now,
4.The period of the fumction is,
[tex]P=\frac{2\pi}{3}[/tex]Now,
The equation of the function.
First the general form of cosine graph function is,
[tex]y=A\cos (bx+c)+d[/tex]Then,
[tex]y=2\cos (3x+c)+d[/tex]Now,
[tex]y=2\cos (3x-1)+3[/tex]Where, D is vertical shift.
Hence, the equation of the function is,
[tex]y=2\cos (3x-1)+3[/tex]What is the product of 11/12 and its reciprocal?
Answers
Answer:
The product of 11/12 is 0.916.This as as a fraction would be 0.916/1.00. This means it's reciprocal is 1.
Step-by-step explanation:
The reciprocal is basically the bottom part, denominator, of the fraction, being siwtched to on top of the fraction (numerator, and vice versa. The fraction would be 0.916/ 1.00 because the closest whole number to 0.916 is 1, meaning the fraction would be 0.916 out of 1. DO NOT MISTAKE THIS FOR 100. When you do the final step, finding the recirprocal of 0.916/1.00, we siwtch the numerator and denominators position, making out answer:
The product of 11/12 is 0.916 which is 0.916/1.00 in fraction form. The reciprocal of this is 1.00/0.916. Hope this helped!
please help :(Find the coordinates of the midpoint of HXH(4 1/2, -4 1/4) , X(2 3/4, -2 1/4)
Answers
To find the coordinates of the midpoint of HX, we would apply the midpoint formula which is expressed as
[tex]\text{Midpoint = }\lbrack\frac{(x1\text{ + x2)}}{2},\text{ }\frac{(y1\text{ + y2)}}{2}\rbrack[/tex]From the information given,
[tex]\begin{gathered} x1\text{ = 4}\frac{1}{2}\text{ = 4.5, x2 = 2}\frac{3}{4}=\text{ 2.75} \\ y1\text{ = -4}\frac{1}{2}=-4.5,\text{ }y2=-2\frac{1}{4}=\text{ - 2.25} \\ \text{Midpoint = }\lbrack\frac{(4.5\text{ + 2.75)}}{2},\text{ }\frac{(-4.5\text{ - 2.25)}}{2}\rbrack \\ \text{Midpoint = (3.625, - 3.375)} \end{gathered}[/tex]well I'm stuck on this homework question and need help please thank you
Answers
Find the value of z such that 0.04 of the area lies to the right of z. Round your answer toTwo decimal places.
Answers
The total area under the normal distribution curve is 1. z-scores are indicated in the horizontal axis below this curve. This means that the sum of areas under the curve at the left and at the right of a certain z-score must be equal to 1.
Then if the area at the right of the z-score that we are looking for is 0.04 the area at its left must be equal to 1-0.04=0.96. The area at the left of z is important because z-score tables usually show the areas at the left of several z-scores. Then the only thing that we have to do is look for the z-score associated with 0.96 in one of these tables. In your case the table that you should use is the one named "Normal Table -∞ to z". That table should look like this one:
As you can see the value 0.96 is associated with the row 1.7 and the column .05 which means that the z-score that meets that the area under the curve at its right is 0.04 is z=1.7+0.05=1.75.
AnswerThen the answer is 1.75
Find the length of line segment MN. Round to the nearest hundredths place.
Answers
First, look th the graph and set the coordinate of the points:
M = (mx,my)= (-1,2)
N = (nx,ny)= (4,0)
Now, apply the distance formula:
[tex]\text{Distance =}\sqrt[]{(mx-nx)^2+(my-ny)^2}[/tex]Replace with the coordinates:
[tex]D\text{ =}\sqrt[]{(-1-4)^2+(2-0)^2}[/tex][tex]D=\sqrt[]{(-5)^2+2^2}=\sqrt[]{25+4}=\sqrt[]{29}\text{ =5.3}9[/tex]Distance: 5.39
In one us city the taxi cost is 2$ plus .50c per mile . If you are traveling from the airport there is an additional charge of 3.50$ for tolls how far can i travel for 33$
Answers
Let the number of miles I can travel for $33 be x;
The total cost of taxi ride from the airport is;
Flat fee + Tolls fee + Charge/Mile = Total cost
Flat fee = $2.00
Toll fee = $3.50
Charge per mile = 0.50x
Total cost = $33.00
Thus, we have;
[tex]\begin{gathered} 2.00+3.50+0.50x=33.00 \\ 0.50x=33.00-5.50 \\ 0.50x=27.50 \\ x=\frac{27.50}{0.50} \\ x=55 \end{gathered}[/tex]Thus, the number of miles
please help me and answer quick because my brainly keeps crashing before i can see the answer
Answers
The surface area of a sphere is given by the formula
[tex]SA=4*pi*r^2[/tex]we have
r=24/2=12 ft ----> the radius is half the diameter
substitute
[tex]\begin{gathered} SA=4*pi*12^2 \\ SA=576pi\text{ ft}^2 \end{gathered}[/tex]What's the divisor, dividend, Quotient, and reminder in a long divison problem
Answers
In a long division problem, say 8/5:
[tex]\frac{8}{5}\text{ is the quotient}[/tex]• 8 is the divisor
,• 5 is the dividend
[tex]\frac{8}{5}=1\frac{3}{5}[/tex]• 3 is the remainder.
A decrease in smoking in the United States has resulted in lower death rates caused bylung cancer. The number of death rates per 100,000 people y can be expressed byy = - 26x2 - .55x + 91.81, where x represents the number of year after 2000.
Answers
Given the equation:
[tex]y=-0.26x^2-0.55x+91.81[/tex]Where x represents the number of years after 2000.
Let's solve for the following:
a.) Calculate the number of deaths per 100,000 for 2015 and 2017.
• For 2015, we have:
Number of years between 2015 and 2000 = 2015 - 2000 = 15
Substitute 15 for x and solve for y:
[tex]\begin{gathered} y=-0.26(15)^2-0.55(15)+91.81 \\ \\ y=-0.26(225)-8.25+91.81 \\ \\ y=-58.5-8.25+91.81 \\ \\ y=25.06\approx25 \end{gathered}[/tex]The number of deaths per 100,000 for 2015 is 25.
• For 2017:
Number of years between 2017 and 2000 = 2017 - 2000 = 17 years
Subustitute 17 for x and solve for y:
[tex]\begin{gathered} y=-0.25(17)^2-0.55(17)+91.81 \\ \\ y=7.32\approx7 \end{gathered}[/tex]The number of deaths oer 100,000 for 2017 is 7.
• b.) Let's solve for x when y = 50 using the quadratic formula.
Apply the quadratic formula:
[tex]x=\frac{-b\pm\sqrt[]{(b^2-4ac)}}{2a}[/tex]Now, subsitute 50 for y and equate to zero:
[tex]50=-0.26x^2-0.55x+91.81[/tex]Subtract 50 from both sides:
[tex]\begin{gathered} 50-50=-0.26x^2-0.55x+91.81-50 \\ \\ 0=-0.26x^2-0.55+41.81 \\ \\ -0.26x^2-0.55+41.81=0 \end{gathered}[/tex]Apply the general quadractic equation to get the values of a, b and c:
[tex]\begin{gathered} ax^2+bx+c=0 \\ \\ -0.26x^2-0.55+41.81=0 \end{gathered}[/tex]Hence, we have:
a = -0.26
b = -0.55
c = 41.81
Thus, we have:
[tex]\begin{gathered} x=\frac{-(-0.55)\pm\sqrt[]{-0.55^2-4(-0.26\ast41.81)}}{2(-0.26)} \\ \\ x=\frac{0.55\pm\sqrt[]{0.3025+43.4824}}{-0.52} \\ \\ x=\frac{0.55\pm6.617}{-0.52} \\ \\ x=-13.78,\text{ 11.}67 \end{gathered}[/tex]Since the number of years cannot be a negative value, let's take the positive value 11.67
Therefore, the value of x is 11.67 when y = 50.
HELP PLS (question in image)
Answers
Answer:
[tex]106-19\sqrt{x} 10[/tex]
Step-by-step explanation:
Evaluate.C15 3 It says I need to evaluate 15^C 3
Answers
Explanation
We are required to determine the value of the following:
[tex]_{15}C_3[/tex]This is achieved thus:
We know that the combination formula is given as:
Therefore, we have:
[tex]\begin{gathered} _{15}C_3=\frac{15!}{3!(15-3)!} \\ _{15}C_3=\frac{15!}{3!12!} \\ _{15}C_3=\frac{15\cdot14\cdot13\cdot12!}{3!12!} \\ _{15}C_3=\frac{15\cdot14\cdot13}{3!}=\frac{15\cdot14\cdot13}{3\cdot2\cdot1} \\ _{15}C_3=5\cdot7\cdot13 \\ _{15}C_3=455 \end{gathered}[/tex]Hence, the answer is:
[tex]455[/tex]Convert the numeral in base ten. (Explanation please)
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Converting the given expression which is [tex]43_{8}[/tex] to base ten gives 35 in base ten.
How to convert a number in base eight to base tenConversion of bases is achieved based on how the conversion to be done are are basically of two methods which are
conversion from other bases to base tenconversion from base ten to other basesThe question is about converting other bases (base eight) to base ten. The steps required are as follows:
For other bases, the number 8 as used is replaced by the number required to be convertedThe exponents starts from zero and increases from left to right as seen belowThe given data is a number in base eight
[tex]43_{eight}[/tex]
[tex]43_{eight}=4*8^{1}+3*8^0[/tex]
[tex]43_{eight}=4*8+3*1[/tex]
[tex]43_{eight}=32+3[/tex]
[tex]43_{eight}=35[/tex]
The number 35 is now in base ten and can be written as [tex]35_{10}[/tex]
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Nayeli bought Jamba juice smoothies for herself and Evelyn after school one day. The smoothies cost $4.95 each plus 8.5% tax. how much change did she receive from a $20 bill
Answers
Explanation
Step 1
remember
[tex]8.5\text{ \%}\Rightarrow\frac{8.5}{100}=0.085[/tex]then, to find the value of the tax, multiply 4.95 0 0.085
[tex]\text{tax}=4.95\cdot0.085=0.42075\text{ per smoothie}[/tex]so, the total cost is
total =2 smoothies +(taxes for 2 smoothies)
total=(2*4.95)+(2*0.42075)
total=9.9+0.8415
total=10.7415
so, Nayebi paid $10.7415
Event A, Event B, and Event Care provided. Event A and Event B aremutually exclusive. Event A and Event C are not mutually exclusive.P(A) = 0.45P(B) = 0.30P(C) = 0.25What is the probability of the union of A and B?
Answers
Given data:
The probability of A is P(A)=0.45.
The probability of B is P(B)=0.30.
The expression for the mutually exclusive events is,
[tex]P(A\cap B)=0[/tex]The expression for the probability of A union B is,
[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =0.45+0.30-0 \\ =0.75 \end{gathered}[/tex]Thus, the probability of (AUB) is 0.75.
What are the solutions to the equation ? e^1/4x = (4x) [tex]e^1/4x =abs( 4x)[/tex](Round to the nearest hundredth). The solutions are about x = and
Answers
The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.
What is the equation?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
A formula known as an equation uses the same sign to denote the equality of two expressions.
As per the given expression,
e^(x/4) = |4x|
The function e^(x/4) is an exponential function and the plot of this function has been plotted below.
The mode function |4x| has also been plotted below.
The point of intersection is the point where both will be the same or the solution meets.
The first point of intersection is (0.267,1.0691) so x = 0.267 ≈ 0.27
The second point of intersection (-0.2357,0.9428) so x = -0.2357 ≈ -0.24
Hence " The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.".
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11 gallons Blue Car 2 of gas 35.4 miles A gallons 27 miles Silver Car 5 14. You are running a fuel economy study. You want to find out which car can travel a greater distance on 1'gallon of gas. a. What is the gas mileage, in miles per gallon, for the blue car? b. What is the gas mileage, in miles per gallon, for the silver car? c. Which car could travel the greater distance on 1 gallon of gas?
Answers
Answer:
a) 23.67 miles per gallon
b) 34 miles per gallon
c) The silver car could travel a greater distance.
Step-by-step explanation:
a)
Conversion of the mixed numbers to fractions:
[tex]1\frac{1}{2}=\frac{1\ast2+1}{2}=\frac{2+1}{2}=\frac{3}{2}[/tex][tex]35\frac{1}{2}=\frac{35\ast2+1}{2}=\frac{70+1}{2}=\frac{71}{2}[/tex]Gas mileage:
3/2 gallons - 71/2 miles
1 gallons - x miles
Simplifying the top line by 2.
3 gallons - 71 miles
1 gallon - x miles
3x = 71
x = 71/3
x = 23.67 miles per gallon
b)
Conversion of the mixed number to fraction:
[tex]27\frac{1}{5}=\frac{27\ast5+1}{5}=\frac{135+1}{5}=\frac{136}{5}[/tex]Mileage:
4/5 gallons - 136/5 miles
1 gallon - x miles
Simplifying the top line by 5
4 gallons - 136 miles
1 gallon - x miles
4x = 136
x = 136/4
x = 34 miles per gallon
c)
Blue car: 23.67 miles per gallon
Silver car: 34 miles per gallon
Silver car could travel a greater distance.
Find the slope of the line that passes through (54, -61) and (8, -56).
Answers
Answer:
The slope m of the line that passes through the two given points is;
[tex]m=-\frac{5}{46}[/tex]Explanation:
We want to calculate the slope of the line that passes through the given point;
[tex](54,-61)\text{ and }(8,-56)[/tex]Recall that the slope formula can be written as;
[tex]m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]substituting the given points;
[tex]\begin{gathered} (x_1,y_1)=(54,-61) \\ (x_2,y_2)=(8,-56) \end{gathered}[/tex]We have;
[tex]\begin{gathered} m=\frac{-56-(-61)}{8-54}=\frac{5}{-46} \\ m=-\frac{5}{46} \end{gathered}[/tex]Therefore, the slope m of the line that passes through the two given points is;
[tex]m=-\frac{5}{46}[/tex]
