Answers
ANSWER:
The displacement is 11.7 km
STEP-BY-STEP EXPLANATION:
The displacement is the vector sum from the start point to the end point. Vector addition is applying the formula of the distance between two points.. We will use this formula:
[tex]d=\sqrt[]{(x_2-x^{^{}}_1)^2+(y_2-y_1)^2^{}}[/tex]To better understand the exercise, we will draw a picture of the situation, it would look like this:
Replacing the points (-4, -11) and (0, 0)
[tex]\begin{gathered} d=\sqrt[]{(-4-0^{}^{}_{})^2+(-11_{}-0_{})^2} \\ d=\sqrt[]{16+121^{}} \\ d=\sqrt[]{137} \\ d=11.7 \end{gathered}[/tex]
Related Questions
What are the units for buoyant force?
Answers
Answer Unit of Buoyant Force The unit of the buoyant force is the Newton (N). = Here, F= buoyant force
Explanation:
i hope this helpes
A roller coaster car begins its roll from the top of the tracks at a speed of2 meters per second. When it reaches the bottom of the 200-meter drop four seconds later, its speed is 22 meters per second. What was the averagespeed of the roller coaster ride in meters per second over the 200-meter drop
Answers
The speed of the car from the top of the track is,
[tex]u=2ms^{-1}[/tex]The distance traveled by the car is,
[tex]d=200\text{ m}[/tex]The speed of the car after 4 seconds is,
[tex]v=22ms^{-1}[/tex]Thus, the average speed of the car is,
[tex]v_{av}=\frac{u+v}{2}[/tex][tex]\begin{gathered} v_{av}=\frac{2+22}{2} \\ v_{av}=12ms^{-1} \end{gathered}[/tex]Thus, the average speed of the roller coaster car is 12 meter per second.
What is the density of a 45.87 g golf ball with a diameter of 4.287 cm?
Answers
We are asked to determine the density of a gulf ball given its mass and volume. To do that, we will use the formula for density:
[tex]D=\frac{m}{V}[/tex]Where:
[tex]\begin{gathered} D=\text{ density} \\ m=\text{ mass} \\ V=\text{ volume} \end{gathered}[/tex]To determine the volume we will use the fact that the gulf ball can be approximated to a sphere and the volume of a sphere is given by:
[tex]V=\frac{4}{3}\pi r^3[/tex]Where:
[tex]r=\text{ radius}[/tex]We are given the diameter. We know that the diameter is twice the radius, therefore:
[tex]r=\frac{D}{2}[/tex]Substituting the value of the diameter we get:
[tex]r=\frac{4.287\operatorname{cm}}{2}[/tex]Solving the operations:
[tex]r=2.144\operatorname{cm}[/tex]Now, we substitute the value of the radius in the formula of the volume:
[tex]V=\frac{4}{3}\pi(2.144\operatorname{cm})^3[/tex]Solving the operation we get:
[tex]V=41.282\operatorname{cm}^3[/tex]Now, we substitute the value of the volume and the mass in the formula for density:
[tex]D=\frac{45.87g}{41.282\operatorname{cm}^3}[/tex]Solving the operation:
[tex]D=1.11\frac{g}{\operatorname{cm}^3}[/tex]Therefore, the density of the ball is 1.11 g/cm^3.
What is the momentum of a 934 kg car moving 10 m/s?
Answers
ANSWER:
9340 kg*m/s
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 934 kg
Speed (v) = 10 m/s
The formula to calculate the momentum is as follows:
[tex]\begin{gathered} p=m\cdot v \\ \text{ we replacing} \\ p=934\cdot10 \\ p=9340\text{ kg*m/s} \end{gathered}[/tex]The momentum of the car is 9340 kg*m/s.
A blink of an eye is a time interval of about 150ms for an average adult. The closure portion of the blink takes only about 55ms. Let us model the closure of the upper eyelid as uniform angular acceleration through an angular displacement of 16.6 degree. What is the value of the angular acceleration the eyelid undergoes while closing 2. What is the tangential acceleration of the edge of the eyelid while closing if the radius of the eyeball is 1.25 cm?
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
The first thing is to convert the time into a second, just like this:
[tex]t=55\text{ ms}\cdot\frac{1\text{ s}}{1000\text{ ms}}=0.055\text{ s}[/tex]Now, convert the angular displacement of the eyelid from degrees to rad:
[tex]\partial\theta=16.6\text{\degree}\cdot\frac{2\pi\text{ rad}}{360\text{\degree}}=0.29\text{ rad}[/tex]We can calculate the angular velocity, dividing the angular momentum by the time, like this:
[tex]w=\frac{0.29}{0.055}=5.27\text{ rad/s}[/tex]The angular acceleration is calculated by means of the quotient of the difference in angular velocity and time, like this:
[tex]a_w=\frac{\delta w}{\delta t}=\frac{5.27-0}{0.15-0.055}=55.47\text{ rad/s}^2[/tex]the tangential acceleration would be:
What do you diagram to analyze orbital motion ?
Answers
The diagram to analyze the orbital motion can be shown as,
Here, a is the acceleration of moon and v is the speed.
The above diagram indicates the orbital motion of the moon around the earth. The moon is more towards the earth than the sun due to larger gravity of earth and at the same time the moon has its velocity that tends moon to move. Therefore, the moon has balanced gravitational and centripetal force to keep in an uniform orbital motion.
When you step off a bus moving at 2 m/s, your horizontal speed when you meet the ground isA) zero.B) less than 2 m/s but greater than zero.C) about 2 m/s.D) greater than 2 m/s.
Answers
ANSWER:
C) about 2 m/s.
STEP-BY-STEP EXPLANATION:
While step off the bus, it acquires a vertical component of velocity, but it still has the initial horizontal component of velocity due to the movement of the bus.
Which means that the velocity is either 2 m/s or about 2 m/s
What is the shortest distance in which you can stop, after the brakes are applied, without the groceries sliding off the seat? The static and kinetic coefficients of friction are, respectively, 0.65 and 0.45. Assume that the surface of the seat is horizontal.
Answers
The shortest distance in which you can stop, after the breaks are applied is 80.38 m.
What is the shortest distance you can stop?The shortest distance in which you can stop is calculated by applying the principle of conservation of energy and work energy principle.
K.E = ¹/₂mv²
where;
K.E is your kinetic energy
m is your mass
v is your speed
The work done by force of friction before you stop is calculated as follows;
W = Ffx
where;
Ff is the frictional forcex is the shortest distance you can stopW = (μmg)x
where;
μ is coefficient of kinetic frictionW = K.E
(μmg)x = ¹/₂mv²
(μg)x = ¹/₂v²
x = (v²) / (2μg)
x = (32²) / (2 x 0.65 x 9.8)
x = 80.38 m
Thus, the shortest distance in which you can stop, after the breaks are applied is determined by applying the principle of conservation of energy.
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The complete question is below:
Your are driving at 32 m/s, what is the shortest distance in which you can stop, after the brakes are applied, without the groceries sliding off the seat? The static and kinetic coefficients of friction are, respectively, 0.65 and 0.45. Assume that the surface of the seat is horizontal.
Peter is trying to ignite the hotplate by turning the gas knob. Suppose thatthe minimum moment of couple about the center of the gas knob requiredto ignite the hotplate is 0.3 N m. Calculate the minimum force (F, and F2)that required to exert. Given that the diameter of gas knob is 5 cm.
Answers
the minimum force is 6 Newtons
Explanation
A moment of a force, or a torque, is a measure of a force's tendency to cause a body to rotate. The moment depends on both the force, and on the position at which the force acts, it is given by the expression
[tex]M=F\cdot d\text{ }[/tex]where F is the exerted force and d is the distance
Step 1
then, let
[tex]\begin{gathered} M=\text{0}.3\text{ Nm} \\ F=F \\ \text{distance}=\text{ 5 cm= }\frac{5}{100}m=0.05\text{ m} \\ \end{gathered}[/tex]now, replace in the formula
[tex]\begin{gathered} M=F\cdot d\text{ } \\ 0.3\text{ Nm=F}\cdot0.05\text{ m} \\ \text{divide both sides by 0.05 m} \\ \frac{0.3\text{ Nm}}{0.05\text{ m}}\text{=}\frac{\text{F}\cdot0.05\text{ m}}{0.05\text{ m}} \\ 6N=F \end{gathered}[/tex]therefore, the minimum force is 6 Newtons
I hope this helps you
a cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00s. wht is its acceleration?
Answers
The given value of the speed of cheetah is,
[tex]v=30ms^{-1}[/tex]The time during the speed v is,
[tex]t=7\text{ s}[/tex]The relation between the acceleration, speed and time is,
[tex]a=\frac{v}{t}[/tex]Substituting the known values,
[tex]\begin{gathered} a=\frac{30}{7} \\ a=4.3ms^{-2} \end{gathered}[/tex]Thus, the value of the acceleration is 4.3 meter per second squared.
Answer:
30×7=210m it is easyokok
If a bus is traveling at 12m/s and a passenger on the bus is walking to the back of the bus at a velocity of 5m/s, what is the relative velocity of the passenger relative to the ground?
Answers
The relative velocity is 17m/s.
The relative velocity of the passenger relative to the ground can be found by applying the concept of relative motion.
speed of bus (vb)=12m/s
speed of passenger inside the bus(vp)= 5m/s opposite to the speed of bus
speed of passenger relative to the ground = v
v= vb+vp
v= 12+(-5), since passenger is traveling in opposite direction
v=7m/
Therefore, the velocity of passenger relative to the ground is 7m/s.
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How much potential energy due to gravity would a person have if they were standing on top of a building that is 36.2 m high? Assume that they have a mass of 79.2 kg.
Answers
Given:
The mass of thee person is
[tex]m=79.2\text{ kg}[/tex]The height at which person standing is
[tex]h=36.2\text{ m}[/tex]Required: calculate the potential energy of the person
Explanation:
when anybody of mass m is at a distance h from the earth's surface then it has potential energy that is given as
[tex]P.E=mgh[/tex]where g is the acceleration due to gravity whose value is
[tex]9.8\text{ m/s}^2[/tex]Plugging all the values in the above relation, we get;
[tex]\begin{gathered} P.E=79.2\text{ kg}\times9.8\text{ m/s}^2\times36.2\text{ m} \\ P.E=28096.992\text{ J} \end{gathered}[/tex]Thus, the potential energy is
[tex]28096.992[/tex]The total mechanical energy of the roller coaster cart below at Point A is 180,000 J. The speed of the cart at Point B is +20 m/s. Assume no energy is lost due to dissipative forces such as friction. A) What is the mass (in kg) of the roller coaster cart? B) What is the potential energy at Point A? C) What is the kinetic energy at Point A?
Answers
Mechanical energy (ME) = Potential energy(PE) + kinetic energy (KE)
PE = mgh
m= mass
g= gravity
h= height
KE= 1/2 m v^2
v= speed
Point B
ME = KE + PE
PE = 0 (height = 0 )
KE = 1/2 (m) v^2
180,000 = 1/2 (m) (20)^2
m = 180,000 / (1/2 (20)^2 )
m= 900 kg
Point A.
ME = 180,000 J = PEa + KE a
PEa = m g h = 900 (9.8) (20) = 176,400J
MEa = PEa + KEa
KEa = MEa - PEa = 180,000 - 176,400 J = 3,600 J
A) mass = 900 kg
B) 176,400 J
C) 3,600 J
A string with both ends fixed is vibrating in its second harmonic. The waves have a speed of 36m/s and a frequency of 60Hz. The amplitude of the standing wave at an antinode is 0.6cm. calculate the amplitude of the motion of points on the string a distance of 30cm,15cmand 7.5cm on the left hand end of the string.
Answers
The amplitude of the motion of points on the string a distance of 30cm,15cmand 7.5cm is 0.0547m, 0.027m and 0.0137m respectively.
Amplitude is the maximum range of vibration or oscillation, measured from the equilibrium position
According to the equation of the second harmonic motion
A = sin (kx)
A = Amplitude
k = [tex]\frac{2\pi f}{v}[/tex] = [tex]\frac{2*\pi * 60}{36}[/tex] = 10.467
x = distance of the point
For x = 30 cm = 0.3 m
A = sin (kx)
A = Sin (10.467 * 0.3)
A = 0.0547 m
For x = 15 cm = 0.15 m
A = sin (kx)
A = Sin (10.467 * 0.15)
A = 0.027 m
For x = 7.5 cm = 0.075 m
A = sin (kx)
A = Sin (10.467 * 0.075)
A = 0.0137 m
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Can you help me match these with the correct word
Answers
When an object is thrown up into the air the time up is equal to the time down.
When an object is thrown up into the air and reacher the apex, the velocity of the object is zero.
If you throw an object straight up the air the velocity of the object is decreasing on its way up.
Which of the following water molecules have the greatest kinetic energy?Select one:a. Cool water.b. Warm water.c. Boiling water.d. They all have the same kinetic energy.
Answers
Since all the molecules in the boiling water will have more energy introduced by heat, then the molecules with the greatest kinetic energy are the ones from the boiling water.
If a space ship traveling at a 1000 miles per hour enters and area free of Gravitational forces,it’s engine must run at some minimum level in order to maintain the ships velocity. is this statement true or false
Answers
The given statement is false.
If a spaceship traveling at 1,000 miles per hour enters an area free of gravitational forces, its engine must run at some maximum level in order to maintain the ship’s velocity
I need help with this question There is 4 answersa)b)c)d)
Answers
Given,
The velocity of the joggers, v=-3.50 m/s
The mass of Jim, M=100 kg
The mass of Tom, m=59 kg
(a) The kinetic energy of the system is given by,
[tex]\begin{gathered} E_a=\frac{1}{2}mv^2+\frac{1}{2}Mv^2 \\ =\frac{1}{2}v^2(m+M) \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} E_a=\frac{1}{2}\times3.50^2(59.0+100) \\ =973.88\text{ J} \end{gathered}[/tex]Thus the kinetic energy of the system is 973.88 J
(b)
The total momentum of the system is given by,
[tex]\begin{gathered} p_b=mv+Mv \\ =(m+M)v \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} p_b=(59+100)\times3.50 \\ =556.5\text{ kg}\cdot\text{ m/s} \end{gathered}[/tex]Thus the total momentum of the system is 556.5 kg m/s
(c)
Given that the velocity of Tom is -v
The total kinetic energy of the system is given by,
[tex]\begin{gathered} E_c=\frac{1}{2}Mv^2+\frac{1}{2}m(-v)^2 \\ =\frac{1}{2}(Mv^2+m(-v)^2) \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} E_c=\frac{1}{2}(100\times3.50^2+59\times(-3.50)^2) \\ =973.88\text{ J} \end{gathered}[/tex]Thus the total kinetic energy of the system, in this case, is 973.88 J
(d)
The total momentum of the system is given by,
[tex]\begin{gathered} p_d=Mv+m(-v) \\ =v(M-m) \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} p_d=3.50(100-59) \\ =143.5\text{ kg}\cdot\text{ m/s} \end{gathered}[/tex]Thus the total momentum of the system, in this case, is 143.5 kg m/s
You place a box weighing 276 N on an inclined plane that makes a 44.5° angle with the horizontal.
Compute the component of the gravitational force acting down the inclined plane.
Answer in units of N.
Answers
Answer:
this is the answer
Explanation:
hope it helps
Which of the following is true for an isolated system? I. Matter is able to freely enter or exit the system.II. Heat is able to freely enter or exit the system.III. Work is able to freely enter or exit the system.II onlyNone of the aboveI or II onlyI only
Answers
Note that, an isolated system does not allow:
• the exchange of energy
,• the exchange of matter
Therefore, in an isolated system, neither
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A student fires a cannonball vertically upwards. The cannonball returns to the ground after a 3.80s flight. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. Use regular metric units (ie. meters).How long did the cannonball rise? What was the cannonball's initial speed? What was the cannonball's maximum height?
Answers
The time taken by ball to rise is given as,
[tex]t=3.80\text{ s}[/tex]Therefore, the total time taken to move the ball in the upward direction is calculated as,
[tex]\begin{gathered} t_0=\frac{3.80\text{ s}}{2} \\ =1.90\text{ s} \end{gathered}[/tex]Therefore, the ball rise for 1.90 s.
The final speed of the ball can be given as,
[tex]v=u+gt[/tex]At the maximum height the final speed of ball is zero.
Substitute the known values,
[tex]\begin{gathered} 0m/s=u+(9.8m/s^2)(1.90\text{ s)} \\ u=-(9.8m/s^2)(1.90\text{ s)} \\ =-18.62\text{ m/s} \end{gathered}[/tex]Therefore, the initial speed of the ball is -18.62 m/s where negative sign indicates the direction of ball.
The final speed of the ball can be given as,
[tex]v^2=u^2-2gh_m[/tex]At the maximum height the final speed is zero. Substitute the known values,
[tex]\begin{gathered} (0m/s)^2=(-18.62m/s)^2-2(9.8m/s^2)h_m \\ h_m=\frac{(-18.62m/s)^2}{2(9.8m/s)^2} \\ =17.7\text{ m} \end{gathered}[/tex]Therefore, the maximum height of the canon is 17.7 m.
true or false? a liter is a metric unit for area
Answers
A iter is defined as 1 cubic decimeter. It is the volume that fits inside a cube whose side measures 10 centimeters:
Therefore, the statement is false because a liter is a metric unit for volume.
Need help 82x2682 please
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
We have the following multiplication:
[tex]undefined[/tex]Calculate the kinetic energy of a 3.15 kg bowling ball rolling down the lane at 2.5 m/s. Include the units.
Answers
Given:
The mass of the ball is: m = 3.15 kg
The velocity of the ball is: v = 2.5 m/s
To find:
The kinetic energy of the ball.
Explanation:
The kinetic energy is the energy that a particle has when is is in motion. For the particle of mass m moving with velocity v, the kinetic energy KE is given as:
[tex]KE=\frac{1}{2}mv^2[/tex]Substitute the values in the above expression, we get:
[tex]\begin{gathered} KE=\frac{1}{2}\times3.15\text{ kg}\times(2.5\text{ m/s\rparen}^2 \\ \\ KE=\frac{1}{2}\times3.15\text{ kg}\times6.25\text{ m}^2\text{/s}^2 \\ \\ KE=9.84\text{ kg.m}^2\text{/s}^2 \\ \\ KE=9.84\text{ J} \end{gathered}[/tex]Final answer:
The kinetic energy of the ball is 9.84 J.
3 Fig. 2.1 is a head-on view of an airliner flying at constant speed in a circular horizontal path. The centre of the circle is to the left of the diagram. Fig. 2.1 II (a) On Fig. 2.1, draw the resultant force acting on the airliner. Explain your answer.
Answers
Answer:
Part (a)
The airliner is moving at a constant speed in a circular path, so it follows a circular motion where the net force is the centripetal force that points to the center of the circle. So, we can draw the resultant force as
Part (b)
The weight and aerodynamic lift force is represented in the following free body diagram
Then, we can calculate the net vertical force and the net horizontal force.
The net vertical force is
Fnety = (1.39 x 10⁶ N)cos(30) - (1.20 x 10⁶ N)
Fnety = 1.20 x 10⁶ N - 1.20 x 10⁶ N
Fnety = 0
The net horizontal force
Fnetx = (1.39 x 10⁶ N)sin(30)
Fnetx = 6.95 x 10⁵ N to the left.
Therefore, the net force has a component only in the horizontal direction which is equivalent to the direction shown in part (a)
Part (c)
By the second law of Newton, if there is a net force, there is acceleration. So, there is a change in the velocity. In this case, the speed is constant but the velocity is changing constantly because the airliner is changing its direction to follow the circular path.
some more disconnectiob
Answers
let the student report the tutor and check
answer is updated
answer is updated olalalala
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I need help with this question.The answer choices for each one is eitherAB C D E Any type of help will be appreciated even if it’s just a hint!
Answers
Conductor that carries electrons:
From the pic we can conclude that the conductor is the wire, in this case it would be A.
Load that transforms energy:
From the pic, it is the bulb which transform the electric energy into light and heat, so it would be B
Insulation that prevents electrons from flowing:
It is the cable sheath, from the pic it is C
Area of low potential energy for electrons:
It is the negative part of the battery, from the pic it is E
Area of high potential energy for electrons:
It is the positive part of the battery, it is D
Two plastic blocks of the same plastic material have the following characteristics:
Block A: Mass 10 g, Volume 25 mL, and
Block B: Mass 20 g, Volume 50 mL.
Which of the statements below is true? (Density of water is 1g/mL at room temperature.)
Group of answer choices
Both blocks will sink equally under water.
Block A will sink deeper under water.
Both blocks will float equally over water.
Block B will float more than Block A over water.
Answers
The true statement, given the data from the question is: Both blocks will float equally over water.
How to determine the true statementTo know which statement is true, we shall obtain the density of each blocks. Details below
For block A:
Mass of block A = 10 gramsVolume of block A = 25 mL Density of block A = ?Density = mass / volume
Density of block A = 10 / 25
Density of block A = 0.4 g/mL
For block B:
Mass of block B = 20 gramsVolume of block B = 50 mL Density of block B = ?Density = mass / volume
Density of block B = 20 / 50
Density of block B = 0.4 g/mL
From the above calculation, we can see that the two blocks have the same density.
Thus, we can conclude that the true statement is both blocks will float equally over water.
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Calculate the potential energy of a roller coaster when the coaster is at the top of a 107.1 meter high hill and has a mass of 2,078.1 kg when fully loaded with passengers.
Answers
Given:
The mass when fully loaded with passengers is m =2078.1 kg
The height is h = 107.1 m
To find the potential energy of the roller coaster.
Explanation:
The potential energy of the roller coaster is given by the formula
[tex]P\mathrm{}E\text{. =mgh}[/tex]Here, g= 9.8 m/s^2 is the acceleration due to gravity.
Substituting the values, the potential energy of the roller coaster will be
[tex]\begin{gathered} P\mathrm{}E\text{. = 2078.1}\times9.8\times107.1 \\ =2181132.198\text{ N} \end{gathered}[/tex]Final Answer: The potential energy of the roller coaster is 2181132.198 N
What is the wavelength of the sound produced by a bat if the frequency of the sound is 90 kHz on a night when the air temperature is 22°C?
Answers
We know that the wavelength is related to the speed of the wave by:
[tex]v=\lambda f[/tex]where f is the frequency.
The speed of sound on air at a given temperature is given by:
[tex]v=331\sqrt[]{1+\frac{T}{273}}[/tex]so in this case the speed is:
[tex]v=331\sqrt[]{1+\frac{22}{273}}=344.08[/tex]Plugging this and the frequency in the first expression above we have:
[tex]\begin{gathered} 344.08=90\times10^3\lambda \\ \lambda=\frac{344.08}{90\times10^3} \\ \lambda=3.82\times10^{-3} \end{gathered}[/tex]Therefore the wavelength is:
[tex]3.82\times10^{-3}\text{ m}[/tex]