Answer:
-$0.05
Explanation:
The expected value can be calculated as the sum of each possible prize multiplied by its probability. You will buy a ticket for $1 and there is a probability of 1/1000 to win the $500, a probability of 1/1000 to win $300, and a probability of 1/1000 to win $150, then the expected alue is
[tex]\begin{gathered} E=-1+500(\frac{1}{1000})+300(\frac{1}{1000})+150(\frac{1}{1000}) \\ E=-1+0.5+0.3+0.15 \\ E=-0.05 \end{gathered}[/tex]Therefore, the expected value is -$0.05.
Find all the factors of 99.
The factors of 99 are: 1, 3, 9, 11, 33 and 99.
The number of chaperones on a field trip must include 1 teacher for every 4 students, plus 2 parents total. The function describing the number of chaperones for a trip of x students is f(x) = 1/4x + 2.
a. How will the graph change if the number of parents is reduced to 0?
b. How will the graph change if the number of teachers is raised to 1 for every 3 students?
Number of chaperones for a trip defined by function f(x) = (1/4)x+2 then,
a. If the parents is reduced to 0 then the graph passes through origin (0,0).
b. If the number of teachers is raised to 1 for every 3 students then line cut x-axis at (-6,0) .
As given in the question,
Given conditions:
Field trip must include 1 teacher for every 4 students and add 2 parents in total.
Number of chaperones for a trip defined by function f(x) = (1/4)x+2
a. If the parents is reduced to 0 then the changes seen in the graph are as follow:
f(x) = (1/4)x+2 passes through the point (0,2)
when parents changes to 0 then graph passes through (0,0).
b. If the number of teachers is raised to 1 for every 3 students then the changes seen in the graph are as follow:
For f(x) = (1/4)x+2 the graph cut axis at (-8,0)
When for every 1 teacher there are 3 students then graph cut x-axis at (-6,0).
Therefore, number of chaperones for a trip defined by function f(x) = (1/4)x+2 then,
a. If the parents is reduced to 0 then the graph passes through origin (0,0).
b. If the number of teachers is raised to 1 for every 3 students then line cut x-axis at (-6,0) .
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Triangle A is rotated 90° about the origin. Which triangle shows the image?
Rotation 90° about the origin.
First, choose a point from triangle A.
For example: (-2,2)
For any point (x,y) rotated 90° =(-y,x)
So:
(-2,2) becames = (-2,-2)
Triangle D
Sketch the vectors u and w with angle θ between them and sketch the resultant.|u|=45, |w|= 25, θ=30°
Step 1
Find the resultant of the vectors
[tex]undefined[/tex]Benjamin & Associates, a real estate developer, recently built 194 condominiums in McCall, Idaho. The condos were either two-bedroom units or three-bedroom units. If the total number of rooms in the entire complex is 494, how many two-bedroom units are there? How many three-bedroom units are there
x = number of 2 bedrooms units
y= number of 3 bedroom units
194 condominiums
x+y = 194 (a)
the total number of rooms in the entire complex is 494
2x + 3y = 494 (b)
We have the system of equations:
x+y = 194 (a)
2x + 3y = 494 (b)
Solve (a) for x
x = 194-y
Replace x on (b) and solve for y
2 (194-y ) + 3 y = 494
388 - 2y +3 y = 494
-2y+3y = 494-388
y= 106
Replace y on (a) and solve for x
x + 106 = 194
x = 194-106
x= 88
2-bedroom units = 88
3- bedrooms units = 106
I have a question about how to solve graphing a system of inequalities and about how to do the (0,0)
The given system of inequality is
[tex]\begin{gathered} 2x-3y>-12 \\ x+y\ge-2 \end{gathered}[/tex]At first, we must draw the lines to represent these inequalities
[tex]2x-3y=-12[/tex]Let x = 0, then find y
[tex]\begin{gathered} 2(0)-3(y)=-12 \\ 0-3y=-12 \\ -3y=-12 \\ \frac{-3y}{-3}=\frac{-12}{-3} \\ y=4 \end{gathered}[/tex]The first point is (0, 4)
Let y = 0
[tex]\begin{gathered} 2x-3(0)=-12 \\ 2x-0=-12 \\ 2x=-12 \\ \frac{2x}{2}=\frac{-12}{2} \\ x=-6 \end{gathered}[/tex]The second point is (-6, 0)
We will do the same with the second line
Let x = 0
[tex]\begin{gathered} 0+y=-2 \\ y=-2 \end{gathered}[/tex]The first point is (0, -2)
Let y = 0
[tex]\begin{gathered} x+0=-2 \\ x=-2 \end{gathered}[/tex]The second point is (-2, 0)
Since the sign of the first inequality is >, then the line will be dashed
Since the sign of the second inequality is >=, then the line will be solid
Let us substitute x, y by the origin point (0,0) in both inequalities to find the shaded part of each one
[tex]\begin{gathered} 2(0)-3(0)>-12 \\ 0-0>-12 \\ 0>-12 \end{gathered}[/tex]Since the inequality is true then the point (0, 0) lies on the shaded area
[tex]\begin{gathered} 0+0\ge-2 \\ 0\ge-2 \end{gathered}[/tex]Since the inequality is true, then point (0, 0) lies in the shaded area
Let us draw the graph
The red line represents the first inequality
The blue line represents the second inequality
The area of two colors is the area of the solution
Point (0, 0) lies in this area, then it is a solution for the given system of inequalities
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19. Translate the following statement into an algebraic statement: "Two more than seven times a number is fifteen" I
2+7x=15
Explanation
Step 1
Let
x represents the number
seven times a number = 7x
two more = +2 or 2+, you need to add 2
is = "="
Step 2
replace,
"Two more than seven times a number is fifteen"
[tex]2+7x=15[/tex]I hope this helps you
Use the words to complete the sentences :1) Downards,2) 15,3) Ascending,4) does,5) upwards,6) Positive,7) Does not,8) Negative,9) Descending,10) 16,11) 3, 12) 3.51) The Graph a plane -----. 2) The line is slanting ------- and therefore has a ------ slope.3) It takes the plane ------ seconds to touch the ground.4) The plane starts at ------- kilometers in the sky .5) Graph ------ touch the origin (0, 0) .
According to the given graph, we have the following:
1) The graph represents a plane descending.
2) The line is slanting downwards and therefore has a negative slope.
3) It takes the plane 15 seconds to touch the ground.
4) The plane starts at 3 kilometers in the sky.
5) Graph does not touch the origin (0,0).
The given graph shows a decreasing line, starting at y = 3, and reaching y = 0 when x = 15.
The previous tutor helped me with solution but we got cut off before we could graph I need help with graphing please
We want to graph the following inequality system
[tex]\begin{gathered} x+8\ge9 \\ \text{and} \\ \frac{x}{7}\le1 \end{gathered}[/tex]First, we need to solve both inequalities. To solve the first one, we subtract 8 from both sides
[tex]\begin{gathered} x+8-8\ge9-8 \\ x\ge1 \end{gathered}[/tex]To solve the second one, we multiply both sides by 7.
[tex]\begin{gathered} 7\cdot\frac{x}{7}\le1\cdot7 \\ x\le7 \end{gathered}[/tex]Now, our system is
[tex]\begin{gathered} x\ge1 \\ \text{and} \\ x\le7 \end{gathered}[/tex]We can combine those inequalities into one.
[tex]1\le x\le7[/tex]The number x is inside the interval between 1 and 7. Graphically, this is the region between those numbers(including them).
-Quadratic Equations- Solve each by factoring, write each equation in standard form first.
Answer
The solutions to the quadratic equations are
[tex]\begin{gathered} a^2-4a-45 \\ \text{Solution: }a=-5\text{ or }9 \\ \\ 5y^2+4y=0 \\ \text{Solution: }y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]SOLUTION
Problem Statement
The question gives us 2 quadratic equations and we are required to solve them by factoring, first writing them in their standard forms.
The quadratic equations given are:
[tex]\begin{gathered} a^2-4a-45=0 \\ 5y^2+4y=0 \end{gathered}[/tex]Method
To solve the questions, we need to follow these steps:
(We will represent the independent variable as x for this explanation. We know they are "a" and "y" in the questions given)
The steps outlined below are known as the method of Completing the Square.
Step 1: Find the square of the half of the coefficient of x.
Step 2: Add and subtract the result from step 1.
Step 3: Re-write the Equation. This will be the standard form of the equation
Step 4. Solve for x
We will apply these steps to solve both questions.
Implementation
Question 1:
[tex]\begin{gathered} a^2-4a-45=0 \\ \text{Step 1: Find the square of the half of the coefficient of }a \\ (-\frac{4}{2})^2=(-2)^2=4 \\ \\ \text{Step 2: Add and subtract 4 to the equation} \\ a^2-4a-45+4-4=0 \\ \\ \text{Step 3: Rewrite the Equation} \\ a^2-4a+4-45-4=0 \\ (a^2-4a+4)-49=0 \\ (a^2-4a+4)=(a-2)^2 \\ \therefore(a-2)^2-49=0 \\ \text{ In standard form, we have:} \\ (a-2)^2=49 \\ \\ \text{Step 4: Solve for }a \\ (a-2)^2=49 \\ \text{ Find the square root of both sides} \\ \sqrt[]{(a-2)^2}=\pm\sqrt[]{49} \\ a-2=\pm7 \\ \text{Add 2 to both sides} \\ \therefore a=2\pm7 \\ \\ \therefore a=-5\text{ or }9 \end{gathered}[/tex]Question 2:
[tex]\begin{gathered} 5y^2+4y=0 \\ \text{ Before we begin solving, we should factorize out 5} \\ 5(y^2+\frac{4}{5}y)=0 \\ \\ \text{Step 1: Find the square of the coefficient of the half of y} \\ (\frac{4}{5}\times\frac{1}{2})^2=(\frac{2}{5})^2=\frac{4}{25} \\ \\ \text{Step 2: Add and subtract }\frac{4}{25}\text{ to the equation} \\ \\ 5(y^2+\frac{4}{5}y+\frac{4}{25}-\frac{4}{25})=0 \\ \\ \\ \text{Step 3: Rewrite the Equation} \\ 5((y^2+\frac{4}{5}y+\frac{4}{25})-\frac{4}{25})=0 \\ 5(y^2+\frac{4}{5}y+\frac{4}{25})-5(\frac{4}{25})=0 \\ 5(y^2+\frac{4}{5}y+\frac{4}{25})-\frac{4}{5}=0 \\ \\ (y^2+\frac{4}{5}y+\frac{4}{25})=(y+\frac{2}{5})^2 \\ \\ \therefore5(y+\frac{2}{5})^2-\frac{4}{5}=0 \\ \\ \text{ In standard form, the Equation becomes} \\ 5(y+\frac{2}{5})^2=\frac{4}{5} \\ \\ \\ \text{Step 4: Solve for }y \\ 5(y+\frac{2}{5})^2=\frac{4}{5} \\ \text{ Divide both sides by 5} \\ \frac{5}{5}(y+\frac{2}{5})^2=\frac{4}{5}\times\frac{1}{5} \\ (y+\frac{2}{5})^2=\frac{4}{25} \\ \\ \text{ Find the square root of both sides} \\ \sqrt[]{(y+\frac{2}{5})^2}=\pm\sqrt[]{\frac{4}{25}} \\ \\ y+\frac{2}{5}=\pm\frac{2}{5} \\ \\ \text{Subtract }\frac{2}{5}\text{ from both sides} \\ \\ y=-\frac{2}{5}\pm\frac{2}{5} \\ \\ \therefore y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]Final Answer
The solutions to the quadratic equations are
[tex]\begin{gathered} a^2-4a-45 \\ \text{Solution: }a=-5\text{ or }9 \\ \\ 5y^2+4y=0 \\ \text{Solution: }y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]Which is the image of vertex K after the parallelogram is rotated 180degrees about the origin?
Answer:
The image of vertex K is (3,-2)
Step-by-step explanation:
Rotated 180 degrees about the origin means that the value of x will not change, while y will have the same distance from the origin, but in a different direction.
Vertex K:
Value of x: x = 3
Value of y: y = 2
Distance from the origin: 2 - 0 = 2
Rotated, new coordinate: 0 - 2 = -2
The image of vertex K is (3,-2)
An integer is chosen at random from 1 to 50. find the probability that the chosen integer is not divisible by 2, 7 or 9a)13/50b)16/25c)9/25
There are a total of 50 numbers that are between 1 and 50. Halft of these numbers are even (divisible by 2 ) and half of then odd.
There are 25 integers that are not even and in total there are 50 integers; thereofre, the probablity of finding an even integer is
25/50 = 1/2
O GRAPHS AND FUNCTIONSFinding inputs and outputs of a two-step function that models a...
Given the function:
[tex]A(t)=256-16t[/tex]Where A is the amount of money (in dollars) Diane has left in her account after t trips on the toll roads.
(a)
After 8 trips on the toll roads (t = 8):
[tex]\begin{gathered} A(8)=256-16(8)=256-128 \\ \\ \therefore A(8)=\$128 \end{gathered}[/tex](b)
If her account is empty:
[tex]\begin{gathered} A(t)=0 \\ \\ \Rightarrow256-16t=0 \end{gathered}[/tex]Solving the equation for t:
[tex]\begin{gathered} 256=16t \\ \\ \therefore t=16\text{ trips} \end{gathered}[/tex]Find the interval in the line below. Use correct symbols to indicate in interval notation. If number is no an integer then round to the nearest hundredth.
we can see the interval is between -2 and 1. but the -2 isn't included (you can notice by the white circle) and the 1 is included, so in interval notation you get:
(-2,1]
if you run 5/6 of a mile in 1/12 of how hour how much is that
The entire miles that the person runs in 1 hour is 10 miles
What is a fraction?A fraction simply means the numbers that's expressed as a/b where a = numerator and b = denominator.
In this case, the person runs 5/6 of a mile in 1/12 of an hour.
The number of miles for the entire run will be the division of the fractions given. This will be illustrated as:
= 5/6 ÷ 1/12
= 5/6 × 12
= 5 × 2
= 10 miles
The entire race is 10 miles.
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What is the slope and y-intercept of the equation y = -2/3x + 1Group of answer choicesSlope = 2/3; y-intercept = 0Slope = 1; y-intercept = -2/3Slope = -2; y-intercept = 3Slope = -2/3; y-intercept = 1
The form of the linear equation is
[tex]y=mx+b[/tex]m is the slope
b is the y-intercept
The given equation is
[tex]y=-\frac{2}{3}x+1[/tex]Let us compare the given equation with the form above, then
[tex]m=-\frac{2}{3}[/tex]and the value of b is
[tex]b=1[/tex]The slope of the line is the coefficient of x
The y-intercept is the numerical term
The slope = -2/3
The y-intercept = 1
The right answer is D the last answer
In any question like that, put the equation in the form
y = m x + b
m is the slope
b is the y-intercept
A triangle has vertices on a coordinate grid at D(-10, -1), E(-10,6), and F(2,6). What is the length, in units, of DE?
A triangle has vertices on a coordinate grid at D(-10, -1), E(-10,6), and F(2,6). What is the length, in units, of DE?
we know that
The formula to calculate the distance between two points is equal to
[tex]d=\sqrt[]{(y2-y1)^2+(x2-x1)^2}[/tex]we have
D(-10, -1), E(-10,6)
substitute the given values in the formula
[tex]\begin{gathered} d=\sqrt[]{(6+1)^2+(-10+10)^2} \\ d=\sqrt[]{(7)^2+(0)^2} \\ d=\sqrt[]{49} \\ d=7\text{ units} \end{gathered}[/tex]therefore
the distance DE is 7 unitsHome Liquidators marks up its merchandise 35% on cost. What is the company’s equivalent markup on selling price?
Based on the fact that Home Liquidators marked up their merchandise by 35% on cost, the company equivalent markup on selling price is 26%.
How to find the equivalent markup?The equivalent markup by Home Liquidators on the selling price can be found by the formula:
= Percentage markup / Percentage selling price x 100%
The percentage markup = 35%
Percentage selling price = (100% + 35%) = 135%
The equivalent markup by Home Liquidators is therefore:
= 35% / 135% x 100%
= 26%
In conclusion, the Home Liquidators has an equivalent markup of 26% on selling price.
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in the inequality 6a+4b>10, what could be the possible value of a if b=2?
We are given the following inequality:
[tex]6a+4b>10[/tex]If we replace b = 2, we get:
[tex]\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}[/tex]Now we solve for "a" first by subtracting 8 on both sides:
[tex]\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}[/tex]Now we divide both sides by 6
[tex]\frac{6a}{6}>\frac{2}{6}[/tex]Simplifying:
[tex]a>\frac{1}{3}[/tex]Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3
Given f <-2, 3> and g <1, -5> find f + 2g
Here are the steps in adding vector f and vector 2g.
1. First, multiply vector G by 2. To do this, simply multiply each component of g by 2.
[tex]<2(1),2(-5)>\Rightarrow<2,-10>[/tex]2. Add the result in step 1 to vector f.
To add, simply add each component of vector f to its corresponding component of vector g.
[tex]\begin{gathered} <-2,3>+<2,-10> \\ <-2+2,3+(-10)> \\ <0,-7> \end{gathered}[/tex]The result is <0, -7>.
Hence, f + 2g = <0, -7>. (Option 3)
Hence, f + 2g = <0, -7>. (Option 3)
how far a hawk can fly in 15 days
Answer : 1500 miles
According to the distance time relationship
Distance = Rate x time
From the figure given, the hawk flies 500 miles in 5 days
We can find our rate using the above parameters
Since, distance = rate x time
Rate = distance / time
Rate = 500 / 5
Rate = 100 miles / day
Since, the rate remains constant
How far the hawk can fly in 15 days can be calculated as follows
Time = 15 days
Rate = 100
Distance = ?
Disatnce = rate x time
Distance = 100 x 15
Distance = 1500 miles
The Hawk can fly 1500 miles in 15 days
Derrick's football team needs to raise at least $1,000 for new uniforms they have collected 480 so far which inequality represents the amount of money,m, the team still needs to raise A. m>$480 B. m<$480 C.m<$520 D.m>$520
The inequality representing the amount of money, m. Derrick's football team needs to raise is D. m>$520
What is inequality?In mathematics, Inequality is part of equations solved with the use of the some special type of equality signs. The signs used inequality calculations are
greater thanless thangreater than or equal toless than or equal toGiven that:
Derrick's football team needs to raise at least $1,000
The team collected 480
To solve the given problem we have the inequality in the form
at least $1,000 ≡ greater than or equal to 1000
m > $1000
having collected $480 so far. The amount collected is subtracted from the $1000
m > $1000 - $480
m > $520
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I need help with this question
A person who watches TV 11.5 hours can do 36 sit-ups.
Define Regression Analysis
Regression analysis is a mathematical measure of the average relationship between two or more variables in terms of the original units of the data
Given,
y = ax +b
a = -1.073
b = 27.069
r² = 0.434281
r = -0.659
No. of hours TV watched = 11.5 hours
we have , y = ax + b
where, a = 1.073 , b = 27.069 and x = 11.5 hours
put this value in given equation,
y = 1.073 * 11.5 + 27.069
After calculating, we get
y = 39.4085 or 39
Therefore, a person who watches TV 11.5 hours can do 36 sit-ups.
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A 39 -ft ladder leans against a building so that the angle between the ground and the ladder is 85∘
How high does the ladder reach the building? __________ ft
The height of the building is 38.85 ft.
Given;
length of the ladder, x = 39 ft
the angle between the ground and the ladder, θ = 85°
let the height of the building be h.
Construct this triangle, the ladder forms the hypotenuse side of the right angle triangle, the height of the triangle is the opposite side of the triangle while the base of the triangle is the adjacent side of the triangle.
Apply the following trig ratio to determine the height of the triangle;
sin(θ) = opposite/hypotenuse
sin(85°) = h/39
h = 39sin(85°)
h = 38.85 ft
Therefore, the height of the building is 38.85 ft (approx.).
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If an account is compounded annually at 9%, how much interest will a principal of $12,300 earn in 16 months? Round your answer tothe nearest cent. Note: Assume 365 days in a year and 30 days in a month.
From the question, we have the given information.
[tex]\begin{gathered} \text{Principal =\$12300} \\ \text{rate}=9\text{\%} \\ \text{number of times compounded =1} \\ \text{Time =16 months =}\frac{4}{3}years \end{gathered}[/tex]We will use the formula below to solve the question
[tex]\text{Amount =P(}1+\frac{r}{n})^{nt}[/tex]Therefore;
[tex]\begin{gathered} \text{Amount}=12300(1+\frac{9}{100})^{\frac{4}{3}} \\ =12300(\frac{109}{100})^{\frac{4}{3}} \\ =13797.71 \end{gathered}[/tex]Since the Amount = 13797.71, we can get the interest by using the formula below.
[tex]\begin{gathered} \text{Interest= Amount- Principal} \\ =13797.71-12300 \\ =1497.71 \end{gathered}[/tex]Answer: Interest =$1497.71
Graph the inequality and give interval notation for the solution. Use two o's (as in octopus) forinifinity and a U for union as needed.-- 5x + 4 >I 19 OR – 22 - 15 – 3-8 -7 -6 -5-4-3-2-] 022345678Clear All Draw:Interval notation for the above inequality and graph is
- 5x + 4 > 19
1st step let us move 4 to the other side by subtracting both sides by 4
- 5x + 4 - 4 > 19 - 4
- 5x > 15
2nd step is move - 5 to the other side by dividing both sides by -5, BUT when we divide the sides of an inequality by a negative number we must reverse the sign of inequality
[tex]\frac{-5x}{-5}<\frac{15}{-5}[/tex]x < -3
The solution is all values smaller than -3
On the number, line draw an empty circle at -3 then draw from it an arrow pointing to the left ( - ve infinity)
The solution is {x : x < -3} or (-00, -3)
Given these points please solve this problme.
The point that belongs to the solution set is A( 4, 4)
What are inequalities?Inequalities are defined as mathematical relations involving an unequal comparison between two numbers, elements or other arithmetic expressions.
They are mostly used to compare two numbers on the number line on the basis of their sizes.
Given the inequalities;
x + y > 63x - 5y ≤ 2Make 'x' the subject from equation 1, we have;
x > 6 - y
substitute the value into equation 2, we have;
3( 6 - y) - 5y ≤ 2
expand the bracket
18 - 3y - 5y ≤ 2
collect like terms
- 8y ≤ 2 - 18
- 8y ≤ -16
Make 'y' the subject of formula
y ≤ 2
Substitute the value in equation 3
x > 6 - 2
x > 4
Hence, the point is A( 4, 4)
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Let E be the event where the sum of two rolled dice is less than 9. List the outcomes in E^c
The Solution:
Let the outcomes when two dice are tossed be as summarized in the picture attached below:
The composition of functions
Answer: g(f(5)) = 352
Step-by-step explanation:
The question being asked is the same as finding g(f(5)).
What this means is to find f(5), and then plug that value into g(x) as x and solve.
f(5) = 4(5) + 1 = 20 + 1 = 21
g(f(5)) = g(21) = 21^2 - 4(21) - 5 = 441 - 84 - 5 = 357 - 5 = 352
Note: You could also find g(f(x)), and then plug 5 in as x and solve.
Start by plugging f(x) into g(x) such that you get g(x = f(x))
g(f(x)) = (4x + 1)^2 - 4(4x + 1) - 5
Now, replace x with 5 and solve to get g(f(5)).
g(f(5)) = (4(5) + 1)^2 - 4(4(5) + 1) - 5 = 352
