Answer: At least 100 billion stars, including our Sun, make up the Milky Way, a spiral galaxy with a diameter of around 100,000 light-years. In the Milky Way, where are we located? The Orion Arm, also known as the Orion Spur, is a short, incomplete arm between the Sagittarius and Perseus arms that is close to where our Sun is positioned.
Explanation:
Paul exerts a force of 375 N to pull a rope 4.20 m. The rope is attached to a block and tackle (A system of multiple pulleys) which lifts a 1345 N weight to a height of 0.975 M above the floor.
A: How much work does Paul do?
B: What is the work done on the object by the block and tackle
C: What is the mechanical advantage of the block and tackle
D: How efficient is the system?
(a) The work done by Paul is 1,575 J.
(b) The work done on the object by the block and tackle is 1,311.38 J.
(c) The mechanical advantage of the block and tackle is 3.59.
(d) The efficiency of the system is 83.26%.
What is the work done by Paul?The work done by Paul is calculated as follows;
W = F x d
where;
F is the force applied by Pauld is the distance travelled by the effortW = ( 375 N ) x ( 4.2 m )
W = 1,575 J
The work done on the object by the block and tackle is calculated as follows;
W = L x d
where;
L is the loadd is the distance travelled by the loadW = ( 1345 N ) x ( 0.975 m )
W = 1,311.38 J
The mechanical advantage of the block and tackle is calculated as follows;
M.A = Load / effort
M.A = ( 1345 N ) / ( 375 N )
M.A = 3.59
The efficiency of the system is calculated as follows;
E = ( output work / input work ) x 100%
E = ( 1,311.38 J / 1,575 J ) x 100 %
E = 83.26 %
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In which of the following cases does there exist a nonzero magnetic field that can be conveniently determined by using Ampere's law?
a. Outside a point charge that is at rest Inside stationary cylinder carrying uniformly distributed charge b. Inside a very long current-carrying solenoid c. At the center of current-carrying loop of wire d. Outside square current-carrying loop of wire
Answer:
(C) Has the symmetry for a direct application of Ampere's Law:
B * 2 π * a = μ0 * I
You know the radius a of the loop and I the current in the loop.
how did the charm quark get its name?
The charm quark got its name because it was the third type of quark discovered, after the up and down quarks. The naming convention for quarks is that they are named based on the order in which they were discovered. The first quark to be discovered was the up quark, followed by the down quark, and then the charm quark. The "charm" name was chosen as a playful reference to the way the particle was discovered, as well as its role in the symmetry of the strong nuclear force.
What is a nuclear force?The nuclear force is the force that holds the protons and neutrons in the nucleus of an atom together. It is a very strong force, much stronger than the electromagnetic force that holds the electrons in their orbits around the nucleus. The nuclear force is responsible for the stability of atomic nuclei and for the energy released in nuclear reactions. It is a short-range force, acting only over distances of about 1 to 2 femtometers (10^-15 meters).
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the amount or length of a vector is called its what
A. scalar
B. Direction
C.Magnitude
D.Vector
Answer:
C.Magnitude
Explanation:
Because Vector means that a thing have direction and magnitude.
How much work is done in accelerating a 2000 kg car from rest to a speed of 30 m/s?
Total work done is 900KJ.
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Work and energy are closely related to each other. Work can also be defined as the transfer of energy. In Physics, for two objects, the work done is defined as the transfer of energy from the first object to the second object. Also, energy is defined as the capacity to do work.Work Energy Principle: The change in kinetic energy of a body is equivalent to the net work done on the body.Here, Kinetic energy of car at rest is 0.
When it accelerates from rest to a speed of 30 m/s, it's kinetic energy is :
K.E = 1/2mv^2
Given, m = 2000Kg and v = 30 m/s
Putting these values in above equation, we get: K.E = 900000J = 900 KJ
We know that Work done is change in Kinetic energy.
So, W = 900KJ
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5.1 5.2 5.3 QUESTION 5 (Start on a new page.) A skier of mass 60 kg skies from rest down a slope inclined at an angle of 15°. The length of the incline is 75 in. He reaches the end of the clined at a velocity of 15 m-s¹. A constant frictional force acts on the skier on his way down. 15:... 75 m Write down an expression for the magnitude of the normal force acting on the skier and then calculate its magnitude. Draw a labelled free-body diagram showing ALL the forces acting on the skier as he skies down the slope. Calculate the average frictional force acting on the skier during his motion down the incline. (2) (3) (7) [12]
The frictional force that is acting on the object is 91N
What is a free body diagram?The normal force can be obtained from the equation mgcosθ. The magnitude of the normal force is;
F = 60 * 9.8 * cos 15
F = 568 N
To obtain the moving force, we must get the acceleration from;
v^2 = u^2 - 2as
Since v = 0
u^2 = 2as
a = u^2/as
a = (15)^2/2 * 75
a = 1.5 m/s^2
Then F = ma
F = 60 * 1.5 = 90 N
The coefficient of friction is 90 N/568N
= 0.16
Frictional force = μmgcosθ
Frictional force = 0.16 * 568
= 91 N
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A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 1.8×106 m/s .
Part A
What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units
Incorrect; Try Again; 4 attempts remaining Enter your answer using dimensions of velocity.
The proton's speed as it passes through point P is Vp = 1.72 × 10^6 m/s
What is a proton?A proton is described as a stable subatomic particle, symbol p , H⁺, or ¹H⁺ with a positive electric charge of +1 e elementary charge.
From the question have the following parameters
A fixed charge, Q = -10 nC
Initial position of charge particle, proton (q), ro = 3mm
Final position of charge particle, proton (q),
rp = 4mm
Initial velocity of charged particle,
vo =2.8 x 10^6 m/s
Let
vp be the final speed of proton
We then Apply conservation of Energy:
Initial (Potential + kinetic) Energy = Final (Potential + kinetic) Energy
kQq ro + 1/2mVo² = kQq rp + 1/2mVp²
m = 1.67 x 10^-27
Substituting the values and converting from mm to meters, we have that)
Vp = 1.72 × 10^6 m/s
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Where are simple sugars and amino acids absorbed into blood capillaries? Where are lipids absorbed into lacteals?
Simple sugars and amino acids are absorbed into the blood capillaries of the small intestine. Lipids, on the other hand, are absorbed into the lacteals of the small intestine. The lacteals are small, specialized tubes that are part of the lymphatic system and are responsible for transporting absorbed lipids away from the small intestine and into the bloodstream.
Answer:
small intestine
Explanation:
After digestion, absorption of amino acid takes place in the small intestine which is a principal organ for the absorption of nutrients. The capillaries of villi collect the amino acid and sugars taken up by the villi into the bloodstream through diffusion. Villi are meant for absorption in the small intestine.
A car starts from rest and accelerates at a rate of 5 m/s^2 for 10 seconds. how far does the car travel during this time?
A. 10 sec
B. 12 sec C. 15 sec
D. 18 sec
The distance that the car travel during each time is:
A. 10 sec = 250 meters.B. 12 sec = 300 meters.C. 15 sec = 375 meters.D. 18 sec = 450 meters.During this time, the car will travel a total distance of 250 meters.
This can be calculated by using the equation for displacement: displacement = initial velocity x time + 0.5 x acceleration x time^2.
Therefore, the displacement of the car after 10 seconds is:
D= (0 x 10 + 0.5 x 5 x 10^2) = 250 meters.
t= 12 sec
D= (0 x 12 + 0.5 x 5 x 12^2) = 300 meters.
t= 15 sec
D= (0 x 15 + 0.5 x 5 x 15^2) = 375 meters.
t= 18 sec
D= (0 x 18 + 0.5 x 5 x 18^2) = 450 meters.
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2. You are kite-surfing and your kite is pulling
you upwards at an angle of 60° with respect to
the ocean, with a force of 1200 Newtons. What
component of that force is up? How much of it
is sideways, parallel to the water?
The upward component of that force is 1039.23 N.
The parallel component of that force is 600N.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body.
The magnitude of force = 1200 Newtons.
Angle with respect to the ocean = 60°.
The upward component of that force is = F sin60° = 1200×sin60° N = 1039.23 N.
The parallel component of that force is = F cos60° = 1200× cos60° N = 600N.
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The position
Of a body is described by S= t^3-2t + 5 find v in m/s when t=3s
An 80 N box of clothes is pulled 20m up a 30° ramp by a force of 115 N that points along the ramp. If the
The box's kinetic energy is 845.2J when an 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N if the coefficient of kinetic friction between the box and the ramp is 0.22.
We know that,
the theorem states the relationship between work and energy. This theorem states that the change in kinetic energy is equal to the work
W = ΔKE = Force × displacement
Now given that,
Weight of the box, w = 80N
Length of the ramp, l = 20m
Angle, θ = 30⁰
Applied force on the box, F = 115N and
coefficient of the kinetic friction, μ = 0.22
first, we find the net force acting on the box
ΣF = Fsinθ - f
here, f is the frictional force
ΣF = Fsinθ - μwcosθ
or ΣF = 115(sin30°) - 0.22(80)cos30° = 115(0.5) - 17.6(0.86)
or ΣF = 42.26N
Now, by applying the work-energy theorem
W = ΣF×d = (42.26N)(20m) = 845.2J
Kinetic energy = 845.2J
Therefore, The box's kinetic energy is 845.2J when an 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N if the coefficient of kinetic friction between the box and the ramp is 0.22.
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The complete question is:
An 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N. If the coefficient of kinetic friction between the box and the ramp is 0.22, what is the box's kinetic energy?
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated. One complete wave passes a putrefying pile of poached pickerel in 0.50 seconds. The piled pickerel protrude 20 cm along the beach. Calculate its velocity. _____ cm/s 5.0 20. 10. 40.
Answer: 40 cm/s.
Explanation:
To solve this problem, we need to use the formula for velocity, which is velocity = distance/time.
We are given the time it takes for one wave to pass the pile of pickerel as 0.50 seconds and the distance that the pickerel protrude along the beach as 20 cm. Plugging these values into the formula gives us:
velocity = distance/time
= 20 cm / 0.50 s
= 40 cm/s
Since we are given the value of g with two significant digits, we should round our answer to the nearest whole number, giving us 40 cm/s.
3. What is the net force experienced by a box of mass 50 kg moving down a
frictionless plane inclined at a 60 degree angle?
Imagine two charged objects on the y-axis. The first object has charge Q = + 3 μC and is located at y = 6 cm. The second object is located at y = 3.0 cm. If the force on the second object is 32.16 N and points in the positive y direction, what is the charge on the second object (in microcoulombs)?
(round to nearest hundredth)
Two charged objects are on the y axis. The first object has a charge of Q = + 3 μC and is located at y = 6 cm, and the second object is located at y = 3.0 cm, so the charge on the object is 0.36 μC or 0.40 μC.
What is the significance of the charge on the object?The charge on the object is dependent upon many factors, and to calculate the charge, Coulomb's Law is applied, which is F=kQq2/[tex]{r}^2[/tex], as here the r = 3 cm, Q = 3 μC, F = 32.16 N, k= 9×[tex]{10}^9[/tex] [tex]{Nm}^2/{c}^2[/tex] . So the q2 is derived from this and that is the charge.
Hence, two charged objects are on the y axis. The first object has a charge of Q = + 3 μC and is located at y = 6 cm, and the second object is located at y = 3.0 cm, so the charge on the object is 0.36 μC.
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Why might some abolitionists have been against supporting women's rights?
O They thought they had a better chance of abolishing slavery if it was not tied to women's suffrage.
O They thought women did not have the temperament to be able to govern themselves.
O They were jealous of the attention that the women's marches were getting.
O They were afraid that if women received the vote, they would not support abolition.
Answer: I think it’s b
Explanation:
question 1 - A certain type of glass is used in making flat-panel computer monitors. For light with a wavelength in air of 656.3 nm, the refractive index of the glass is nA = 1.5160. For light with a wavelength in air of 435.8 nm, nB = 1.5290. Determine the difference, lA - lB, in their wavelengths inside the glass.
The difference in the wavelength of the lights in the glass is 147.88 nm.
What is the difference in their wavelengths inside the glass?The difference in their wavelengths inside the glass is calculated by applying the following formula as shown below.
The wavelength of light A inside the glass is calculated as;
nA = ( 656.3 nm ) / ( 1.516 )
nA = 432.9 nm
The wavelength of light B inside the glass is calculated as;
nB = ( 435.8 nm ) / ( 1.529 )
nB = 285.02 nm
difference in wavelength = 432.9 nm - 285.02 nm = 147.88 nm
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The energy transfer diagram shows energy transfers in an MP3 player. Useful energy is transferred away from the MP3 player by light and... what else?
Useful energy is transferred away from the MP3 player by light and sound.
What is the law of conservation of energy?
The law of conservation of energy states energy can neither be created nor destroyed but can be transformed from one form to another.
This implies that energy can be converted from one form to another such as;
kinetic energy to potential energypotential energy to kinetic energyelectrical energy to mechanical energy chemical energy to electrical energymechanical energy to electrical energylight energy to heat energyelectrical energy to lightelectrical energy to sound energylight energy to heat energysolar energy to light energyhydro energy to electrical energy, etcThe MP3 player uses the energy from electricity supplied to it to play music. The basic energy conversion process that occurs to achieve this include;
electricity → light energy → sound energy → heat energy.
Thus, MP3 player conserves energy by converting the energy supplied to it into useful energy.
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38. Which of the following is true about all or non-rule?
A) Can be applied on whole heart.
B) Minimal stimulus produces minimal response.
C) A minimal stimulus produces a maximal response.
D) The nerve trunk either responc maximally or not respond at all.
E) The response in a single nerve fiber increases with increase intensity of
stimulus.
The nerve trunk either response maximally or not respond at all. - this is true about all or non-rule. Option (D) is correct.
What is all-or-non law?
The all-or-none law in physiology states that a single nerve fiber will always respond maximally to stimulation and generate an electrical impulse with a single amplitude.
The height of the impulse will remain constant even if the stimulus's intensity or duration are raised. The nerve fiber either responds fully or not at all.
Thus, either the nerve trunk responds fully or not at all.
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Please help!!
What is the impulse needed to completely stop a 1300 kg car that's driving at 18
m/h?
Impulse needed to stop the 1300 kg car driving at a speed of 18 km/h or 5 m/s is 6500 kg m/s.
What is impulse?Impulse of a moving body is the change in its momentum. The ability to make the applied force increasing the displacement of a body is called its momentum. It is the product of mass and velocity of the body.
Impulse is the product of force and time. Here, the impulse we need to calculate is required to stop the car. Hence the final momentum is zero.
Given = 1300 kg
velocity = 18 km/h = 5 m/s
then initial momentum = 1300 kg × 5 m/s = 6500 kg m/s.
Final momentum = 0
thus, impulse = 6500 kg m/s - 0 = 6500 kg m/s
Therefore, the impulse of the car needed to stop it is 6500 kg m/s against the momentum.
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C=59(F−32)The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
A. temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 59 degree Celsius.
B. temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
C. temperature increase of 59 degree Fahrenheit is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
As a result, claim I is accurate. According to this formula, a temperature increase of 1 degree Celsius is comparable to a temperature increase of 9/5 degrees Fahrenheit.
0F and 0C stand for what?The Celsius scale, sometimes known as the centigrade scale, is a temperature scale based on the water's freezing point at 0°C and boiling point at 100°C. A temperature scale called the Fahrenheit scale is based on the fact that water freezes at 32°F and boils at 212°F.
Why convert 95 degrees Celsius to degrees Fahrenheit?The relationship between Celsius and Fahrenheit is inversely proportional. The temperature on the Fahrenheit scale rises as the temperature does on the Celsius scale, and vice versa. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C.
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Obviously, most of Ms. Kontos’s students have not learned what she thought she had taught them about human vision.
Explain why many students believe the opposite of what Ms. Kontos has taught them. Base your response on contemporary principles and theories of learning and cognition.
Describe two different ways in which you might improve on this lesson to help students gain a more accurate understanding of human vision. Base your strategies on contemporary principles and theories of learning and cognition.
It is possible that students may have misunderstood the information taught by Ms. Kontos about human vision due to various factors such as prior knowledge, attention, motivation, and the way the information was presented.
How to improve on learning accuracy?To improve on this lesson and help students gain a more accurate understanding of human vision, two strategies based on contemporary principles and theories of learning and cognition are:
Incorporating visual aids and hands-on activities: By using visual aids such as diagrams, videos, and animations, students can better understand the complex processes involved in human vision. Hands-on activities such as creating simple models or simulations of the eye can also help students connect what they have learned to real-life situations.
Encouraging metacognition: Encouraging students to think about their own thinking processes, or metacognition, can help them understand their own learning style and identify areas where they need further clarification. By encouraging students to ask questions, discuss what they have learned, and reflect on their own understanding, they can build a more accurate understanding of the topic.
These strategies can help students gain a deeper and more accurate understanding of human vision and improve their learning outcomes.
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A motorboat going downstream overcame a raft at a point A; Ï„=60min later it turned back and after some time the raft is at a distance l=6.0km from the point A. Find the flow velocity in km/h assuming the duty of the engine to be constant.
The flow velocity in km/h is 3 km/hr if the engine duty remains constant.
What is velocity?The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.
Here,
Now, let's assume the velocity of boat to be v in still water.
While going down stream its velocity will be v + u
Velocity of boat relative to raft => v + u - u = + v after 1 hr distance between them will be v km.
In 1 hr raft moved by u× 1 = u km
Now while coming back
vb = -(v - u)
vr = + u
vb/r = - (v - u) - u = - v
So we see here that the relative velocity of boat with respect to raft is same as while going downstream or upstream both.
distance between them = v km.
So time in which they meet =
v/v=1 hr
So in next 1 hr they meet at some point,which will be 6 km away from A
Also in next 1 hr the raft would have traveled another u km. so total distance of meeting point from A in 2u = 6 ⇒ u = 3 km/hr
Flow velocity = speed of raft = 3 km/hr
The flow velocity in km/h assuming the duty of the engine to be constant is 3 km.
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A resistor and a capacitor are connected in series to an ideal battery of constant terminal voltage. At the moment contact is made with the battery, the voltage across the capacitor is:
a. greater than the battery's terminal voltage.
b. less than the battery's terminal voltage, but greater than zero.
c. zero.
d. equal to the battery's terminal voltage.
When contact is made with the battery, the voltage across the capacitor is zero.
The true choice is C.
The voltage across the capacitor is given by the formula V = Q/C. Voltages of other elements can be found using Kirchoff's first law. The current through the capacitor must always decrease and end at zero because the charge cannot continue to flow through the capacitor.
An RC circuit is one in which a resistor and capacitor are connected in series with a voltage source such as a battery. Like all purely resistive circuits, this RC circuit allows electric current to flow with one change. Batteries connected in series with a resistor produce a constant current.
So, the voltage on the resistor and capacitor connected in series which has the same value will produce a zero-voltage value.
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A bowling ball and a tennis ball are dropped separately in such a way that both have the same kinetic energy when they hit the ground. Were they dropped from the same height or a different height? If the latter, which one was dropped from a higher point ?
Answer:Combust Methane
Reaction
Explanation:Seperate
Please help!!
What is the average force if the car takes 3.0 seconds to stop?
The correct answer would be that the force on the car to stop the car will be 7333 N.
What is force?The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Force is used to describe a body's tendency to alter or change its condition as a result of an external cause. When force is applied, the body may also alter its size, shape, and direction. kicking a ball, pushing and tugging on the door, or kneading bread are a few examples.
We have specified that the automobile weighs m = 1000 kg.
initial vehicle speed, 22m/sec
The vehicle's ultimate velocity is v = 0 m/sec
when it comes to a stop. Given as t = 3 sec, the time is.
According to the first equation of motion, v = u+at.
So, a= v-u/t = 0-22/3 = -22/3 = -7.33m/sec
Force F = ma, according to Newton's Second Law.
so force, F= 1000 x 7.333= 7333N
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Vector A has a magnitude of 3 newtons and points in the positive direction vector B has a magnitude of 10 newtons and points in the negative direction. What is the resultant
Answer: 7 newtons in the negative direction
Explanation:
If the directions measured are only negative and positive then the resultant should just be the addition of the two vectors.
Adding the vectors we have (+3N) + (-10N)
This gives us a final answer of (-7N) or 7 newtons in the negative direction
A small air compressor operates on a 2.8 hp
(horsepower) electric motor for 8 hours a day.
How much energy is consumed by the motor
daily? 1 hp equals about 750 watts.
Answer in units of J.
The energy consumed by the motor is 1008000 J.
What is energy?Energy is the ability of the capacity to perform work.
To calculate the energy consumed by the electric motor daily, we use the formula below.
E = Pt.......................... Equation 1Where:
E = Energy consumed by the electric motor dailyP = Power of the air compressor = 2.8 hp = (2.8×750) = 2100 Jt = Time = 8 hours = 8×60 = 480 secondsSubstitute these values into equation 1
E = 2100×480E = 1008000 JHence, the energy is 1008000 J.
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1.
The temperature of the melting point of ice and that of boiling point of water
at normal atmospheric pressure are marked 40 and 200
respectively on a
certain thermometer. What is
a.
b.
the temperature
the thermometer
on this thermometer
is 80.
temperature is 60°C. Ans: 25°C, 136
in °C when the reading
reading when the
Answer:
I believe this is what you was asking for.
Explanation:
A. The temperature in °C when the reading on the thermometer is 80 is 60°C.
B. The reading when the temperature is 60°C on this thermometer is 136.
If the orbit of a rocket is a circle around the earth with a radius r
= 8 x 106 m, and the mass of the earth is 5.97 x 1024 kg while
that of the rocket is 0.5 x 106 kg, then what is the speed of the
rocket under uniform circular motion (in m/s, G = 6.67 × 10-11 N
(m/kg) 2)?
a 2.04 x 10-
b 7.06 × 10³
c 2.04 x 10-3
d 7.06 x 10°
e 7.06 x 105
Answer:
The speed of an object in uniform circular motion can be calculated using the formula:
v = (G * M / r)^0.5
Where:
v is the speed of the object
G is the gravitational constant (6.67 × 10^-11 N*m^2/kg^2)
M is the mass of the central object (in this case, the Earth)
r is the distance between the object and the center of the circular orbit (in this case, the distance between the rocket and the Earth)
Plugging in the given values, we have:
v = (6.67 × 10^-11 Nm^2/kg^2 * 5.97 × 10^24 kg / 8 × 10^6 m)^0.5
= (3.96 × 10^-5 Nm/kg)^0.5
= 1.99 × 10^-2 m/s
Therefore, the speed of the rocket under uniform circular motion is approximately 0.0199 m/s, which is answer C: 2.04 x 10-3.
Explanation:
