Part 1: Factorial! 3. What are the pros and cons to using the factorial function on your calculator in terms of understanding and/or thecalculation itself?

Part 1: Factorial! 3. What Are The Pros And Cons To Using The Factorial Function On Your Calculator In

Answers

Answer 1

Explanation

We are required to determine the pros and cons of using the factorial function on the calculator.

Hence, the answers are:

- Pros

• It makes calculation easier.

,

• It makes calculations to be done in an efficient manner.

,

• It helps students to solve complicated questions seamlessly.

- Cons

• It cannot help with large numbers as the calculator has limited space for answer preview.

,

• It does not help to understand better how the calculation is done.


Related Questions

Today's previewYou can solve this by rearranging to create asituation to use the method from the previouslesson, or you can solve this by thinking a littledifferently about how the variables below mightalso be described.... so solve it.y = 2x + 4x + y = 7

Answers

[tex]\begin{gathered} y-2x=4 \\ y+x=7 \\ -2x-x=4-7 \\ -3x=-3 \\ x=3 \\ \\ y+x=7 \\ y=7-3 \\ y=4 \end{gathered}[/tex]

Choose SSS, SAS, or neither to comparethese two triangles.A) SSSB) SASC) neither

Answers

Answer:

C. Neither

Explanation:

The SSS Congruence Rule states that if the three sides of a triangle are equal to the three sides of another triangle, then the two triangles are congruent.

The SAS Congruence Rule states that if the two sides and the included angle of one triangle are equal to the two sides and the included angle of another triangle, then the two triangles are congruent.

Notice that in the given triangles, there are two congruent sides and a non-included angle, since this does not satisfy any of the rules stated above, SSS Congruence rule or SAS Congruence rule, we'll choose "neither" as the correct answer.

Consider the two polynomials p(x), q(x) in Z[x] by p(x) = 1+2x+3x2, q(x) = 4+5x+7x3. Then p(x) + q(x) is

Answers

The solution for polynomials p(x) + q(x) is 7x³ + 3x² + 7x + 5

Given,

The polynomials

p(x) = 1 + 2x + 3x²

q(x) = 4 + 5x + 7x³

We have to find the solution for p(x) + q(x)

Then,

p(x) + q(x) = (1 + 2x + 3x²) + ( 4 + 5x + 7x³)

p(x) + q(x) = 7x³ + 3x² + 2x + 5x + 1 + 5

p(x) + q(x) = 7x³ + 3x² + 7x + 5

That is,

The solution for polynomials p(x) + q(x) is 7x³ + 3x² + 7x + 5

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PLEASE ITS URGENT I NEED HELP!!! I BEG YOU GUYS PLEEAASEEE THANKS..

Answers

[tex]b,c\text{ and d}[/tex]

Explanation

remember some properties of the exponents

[tex]\begin{gathered} a^m\cdot a^n=a^{m+n} \\ (a^m)^n=a^{m\cdot n} \\ a^{-m}=\frac{1}{a^m} \end{gathered}[/tex]

then, to solve this solve each option and compare

Step 1

[tex]6^{-5}\cdot6^2[/tex]

solve

[tex]\begin{gathered} 6^{-5}\cdot6^2=6^{-5+2}=6^{-3} \\ \end{gathered}[/tex]

so, this is not an answer

Step 2

[tex](\frac{1}{6^2})^5[/tex]

solve

[tex]\begin{gathered} (\frac{1}{6^2})^5=(6^{-2})^5=6^{(-2\cdot5)}=6^{-10} \\ \end{gathered}[/tex]

so, this is an answer

Step 3

[tex]\begin{gathered} (6^{-5})^2 \\ \text{solve} \\ (6^{-5})^2=6^{-5\cdot2}=6^{-10} \end{gathered}[/tex]

so, this is an answer

Step 4

[tex]\begin{gathered} \frac{6^{-3}}{6^7} \\ \text{solve} \\ \frac{6^{-3}}{6^7}=\frac{1}{6^3\cdot6^7}=\frac{1}{6^{3+7}}=\frac{1}{6^{10}}=6^{-10} \end{gathered}[/tex]

so, this is an answer

Step 5

[tex]\begin{gathered} \frac{6^5\cdot6^{-3}}{6^{-8}} \\ \text{solve} \\ \frac{6^5\cdot6^{-3}}{6^{-8}}=\frac{6^{5-3}}{6^{-8}}=\frac{6^2}{6^{-8}}=6^2\cdot\frac{1}{6^{-8}}=6^2\cdot6^8=6^{10} \end{gathered}[/tex]

so, this is not an answer

I hope this helps you

find the first term when the 31st 32nd and 33rd are 1.40, 1.55, and 1.70

Answers

jadeymae06, this is the solution:

This is an arithmetic sequence, where d (common difference) = 0.15

(1.70 - 1.55) or (1.55 - 1.40)

,

• a + 30d = 1.40

,

• a + 30(0.15) = 1.4

,

• a + 4.5 = 1.4

,

• a = 1.4 - 4.5

,

• a = -3.1

Jade, the first term is -3.1

2) A seat has a speed of 15 mph in seicher travels downstream from Greentown to Glenevon in 2/5 of an hour. It then goes back upstream from Glenevon to Colombia, which is 2 miles downstream, in 3/5 of an hour. Find the rate of the current.

Answers

Answer:

Rate of the current = 5 mph

Explanations:

The time taken to travel downstream from Greentown to Glenevon = 2/5 hours

The time taken to travel upstream from Glenevon to Columbia = 3/5 hours

Rate = Distance /time

Let the distance traveled = y miles

Rate of the downstream travel:

Rate = y ÷ 2/5

Rate = y x 5/2

Rate = 5y / 2

Rate of the upstream travel

Since the travel upstream from Glenevon to Columbia is 2 meters downstream:

Distance = y - 2

Rate = (y-2) ÷ 3/5

Rate = (y-2) x 5/3

Rate = 5(y-2)/3

Let the current rate be represented by k

The rate of the downstream travel will be:

15 + k = 5y/2...........(1)

The rate of the upstream movement will be:

15 - k = 5(y-2)/3............(2)

Add equations (1) and (2)

(15 + k) + (15 - k) = [5y/3] + [5(y-2)/3]

[tex]\begin{gathered} 30\text{ = }\frac{5y}{2}+\text{ }\frac{5y-10}{3} \\ 30\text{ = }\frac{15y+10y-20}{6} \\ 30(6)\text{ = 15y + 10y - 20} \\ 180\text{ = 25y - 20} \\ 180\text{ + 20 = 25y} \\ 25y\text{ = 200} \\ y\text{ = 200/25} \\ y\text{ = 8} \end{gathered}[/tex]

Substitute the value of y into equation (1)

[tex]\begin{gathered} 15\text{ + k = }\frac{5y}{2} \\ 15\text{ + k = }\frac{5(8)}{2} \\ 15\text{ + k = }\frac{40}{2} \\ 15\text{ + k = 20} \\ k\text{ = 20 - 15} \\ k\text{ = 5} \end{gathered}[/tex]

The rate of the current = 5 mph

For each set of three side lengths in the table, determine how many unique triangles can be formed. Select the appropriate circle in each row.

Answers

The first one the 3 sides are equal to 1, this mean that it is a equilater triangle, so it is possible to made exactly one unique triangle.

now for the other triangles we will add the two shortest sides of the triangle, and if they are more than the greater side of the triangle, then it will be a unique triangle, if not there will be more than one triangle

for the second one:

[tex]3+4=7>5[/tex]

so the second one have exactly one unique triangle.

for the number 3:

[tex]5+10=15=15[/tex]

So in this case there is none unique triangles.

for the number 4:

[tex]6+16=22<26[/tex]

So in this case there is none unique triangles.

and for the number 5:

[tex]10+50=60>55[/tex]

So we hace exactly one unique triangle.

What are the domain and range of y = cot x? Select onechoice for domain and one for range.

Answers

ANSWER:

A. Domain: x ≠ n

D. Range: All real numbers

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]y=\cot\left(x\right)[/tex]

The domain of a function is the interval of input values, that is, the interval of x while the range is the interval of output values, that is, the interval of y.

In the cotangent function, x cannot take the value of radians (nor its multiples), since it is not defined, while the range is continuous on all real numbers.

That means the correct options are:

A. Domain: x ≠ n

D. Range: All real numbers

I wills send you a picture

Answers

Draw the tank

we can use the formula of the volume of a cylinder

[tex]V=\pi\times r^2\times h[/tex]

we can repalce the value of the volume (320pi) and the height

[tex]\begin{gathered} 320\pi=\pi\times r^2\times20 \\ 320\pi=20r^2\pi \end{gathered}[/tex]

now solve for r^2 dividing 20pi on both sides

[tex]\begin{gathered} \frac{320\pi}{20\pi}=r^2 \\ \\ r^2=16 \\ \end{gathered}[/tex]

and solve for r using roots

[tex]\begin{gathered} r=\sqrt[]{16} \\ \\ r=4 \end{gathered}[/tex]

the value of the radious is 4ft and the diameter double, then

[tex]\begin{gathered} d=2\times4 \\ d=8 \end{gathered}[/tex]

diameter of the cylinder is 8 ft then rigth option is C

what is the simplified ratio of 32:24

Answers

Answer:

4/3

Step-by-step explanation:

The simplest form of

32: 24

is 43

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 32 and 24 is 8

Divide both the numerator and denominator by the GCD

32 ÷ 8

24 ÷ 8

Reduced fraction:

4/3

Therefore, 32/24 simplified to lowest terms is 4/3.

Nov 28,Quadrilateral ABCD is dilated by a scale factor of to form quadrilateral A'B'C'D'.What is the measure of side DA?Dal1515301B2162А

Answers

The quadrilateral ABCD was dilated by a scale factor of 3/4 to form the quadrilateral A'B'C'D'

This means that each side of the quadrilateral was multiplied by 3/4 to make the dilation.

You know that the scale factor is 3/4 and the length of D'A' is equal to 30 units, then:

[tex]\begin{gathered} D^{\prime}A^{\prime}=\frac{3}{4}DA \\ 30=\frac{3}{4}DA \end{gathered}[/tex]

Multiply both sides by the reciprocal of 3/4

[tex]\begin{gathered} 30\cdot\frac{4}{3}=(\frac{4}{3}\cdot\frac{3}{4})DA \\ 40=DA \end{gathered}[/tex]

The length of side DA is 40 units.

Please help with this practice question

Answers

They are both 0

Explanation below:

Evaluate theexpression belowwhen x = = 3.<54 : 2.3 - 22Enter your answer inthe box below.

Answers

The given expression is

[tex]54\frac{.}{.}2\times3-x^2[/tex]

where x=3

the dot in the expression means multiplication

substitute into the expression above we have

[tex]\begin{gathered} 54\frac{.}{.}2\times3-3^2 \\ \end{gathered}[/tex]

Applying BODMAS

[tex]27\times3-3^2[/tex][tex]\begin{gathered} 81-3^2 \\ 81-9 \\ 72 \end{gathered}[/tex]

Therefore the value of the expression is 72

Angie added a stone border 2 feet in width on all sides of her garden making her harder 12 by 6 feet. What is the area, in square feet, of the portion of the garden that excludes the border?

A. 4
B. 16
C. 40
D. 56
E. 72

Answers

The area, in square feet, of the portion of the garden that excludes the border is 40.

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

We have been given that Angie added a stone border of 2 feet in width on all sides of her garden making her harder 12 by 6 feet.

Length = 12 ft

Width = 6 ft

The dimension of the garden  that excludes the border of 2 feet are;

Length = 12 ft- 2 = 10 ft

Width = 6 ft - 2= 4 ft

Thus, Area  =  length × Width

Area = 10 x 4

Area = 40 square feet

Hence, the area, in square feet, of the portion of the garden that excludes the border is 40.

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True or false? Based only on the given information, it is guaranteed thatAD EBDADGiven: ADI ACDBICBAC = BCBCDO A. TrueB. FalseSUBMIT

Answers

According to the information given, we can assure:

For both triangles, two interior angles and the side between them have the same measure and length, respectively. This is consistent with the ALA triangle congruence criterion.

ANSWER:

True.

11. Jarrod's favorite movie is now on video at 15% off the originalprice. If he pays $17, what was the original price?

Answers

original price = x

discount = 15%

price after discount = $17

Write an equation:

x (1-15/100) = 17

x (1-0.15 ) = 17

0.85x = 17

Solve for x:

x = 17/0.85

x = $20

A ball is thrown from an initial height of 6 feet with an initial upward velocity of 21 ft/s. The ball's heighth (in feet) after t seconds is given by the following,6+21 167Find all values of t for which the ball's height is 12 feet.Round your answer(s) to the hearest hundredth(If there is more than one answer, use the "or" button.)

Answers

The given expression in the question is

[tex]h=6+21t-16t^2[/tex]

with the value of h given as

[tex]h=12ft[/tex]

By equating both equations, we will have

[tex]\begin{gathered} 12=6+21t-16t^2 \\ 12-6-21t+16t^2=0 \\ 6-21t+16t^2=0 \\ 16t^2-21t+6=0 \end{gathered}[/tex]

To find the value of t we will use the quadratic formula of

[tex]ax^2+bx+c=0[/tex]

which is

[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where} \\ a=16 \\ b=-21 \\ c=6 \end{gathered}[/tex]

By substitution, we will have

[tex]\begin{gathered} t=\frac{-(-21)\pm\sqrt[]{(-21)^2-4\times16\times6}}{2\times16} \\ t=\frac{21\pm\sqrt[]{441-384}}{32} \\ t=\frac{21\pm\sqrt[]{57}}{32} \\ t=\frac{21\pm7.5498}{32} \\ t=\frac{21+7.5498}{32}\text{ or t=}\frac{21-7.5498}{32} \\ t=\frac{28.5498}{32\text{ }}\text{ or }t=\frac{13.4502}{32\text{ }} \\ t=0.89\text{ or t=0.42} \end{gathered}[/tex]

Alternatively, Solving the equation graphically we will have

Therefore,

The values of t( to the nearest hundredth) t= 0.89sec or 0.42sec

Can you please help me out with a question

Answers

right. the lateral area of a hemisfere is the curved area, wich is half the area of a complete sphere

area of a sphere:

4πr²

So, half the area is 1/2(4πr²)= 2πr²

Now, the total surface is the lateral area plus the area of the base. the base is a circle, so the area is equal to πr²

And the volume of a hemisfere is equal to half the volume of a sphere:

[tex](\frac{4}{3}\pi r^3)\cdot\frac{1}{2}\text{ =}\frac{2}{3}\pi r^3[/tex]

So, the anwsers are:

[tex]2\pi r^{2}\text{ = }2\pi(24ft)^{2}\text{ = 1152}\pi ft^2[/tex][tex]\pi r^{2}\text{ = }\pi(24ft)^2\text{ = 576}\pi ft^2[/tex][tex]\frac{2}{3}\pi r^3\text{ = }\frac{2}{3}\pi(24ft)^3\text{ = 9216}\pi ft^3[/tex]

The answers are in order

Hi there, I need help with this question. Thank you in advance!

Answers

For the data given, we have 24 entries in all.

They are :

75, 36, 80, 49, 24, 61, 34, 39, 30, 76, 44, 44, 40, 35, 21, 89, 34, 70, 79, 65, 66, 53, 99, 11

(1) Minimum refers to the lowest data in the table. we can see out of all the data in the table, the lowest is 11. Therefore,

Min = 11

(2) Maximum refers to the highest data in the table.

The highest is 99.

Therefore,

Max = 99

(3) Range is defined as highest data minus lowest data

Range = 99 - 11

Range = 88

(4) Mean:

[tex]\begin{gathered} \text{ Mean =}\frac{\text{ sum of the data}}{total\text{ count}} \\ \operatorname{mean}\text{ = }\frac{75+36+80+49+24+61+34+39+30+76+44+44+40+35+21+89+34+70+79+65+66+53+99+11}{24} \\ \\ \text{Mean = }\frac{1254}{24} \\ =52.25 \end{gathered}[/tex]

Therefore,

Mean = 52.25

(5) Standard deviation:

The steps to calculate the standard deviation in shown in the picture below.

The standard deviation = 22.8386..

To 2 decimal places, we have 22.84

Therefore,

Standard deviation = 22.84

The table represents the amount of money in a bank account each month. Month Balance ($) 1 2,215.25 2 2,089.75 3 1,964.25 4 1,838.75 5 1,713.25 What type of function represents the bank account as a function of time? Justify your answer.

Answers

The form of function that represents the bank account as a function of time is a linear function.

How to determine the type of function?

The table of values is given as illustrated:

Month Balance ($)

1           2,215.25

2          2,089.75

3           1,964.25

4            1,838.75

5            1,713.25

From the above table of values, we can see that the balance in the bank account reduces each month by $125.5

So, we have

Difference = 1,838.75 - 1713.25 =125.5

Difference = 1,964.25 - 1,838.75 =125.5

Difference = 2,089.75 - 1,964.25 =125.5

Difference = 2,215.25  - 2,089.75 =125.5

This shows a linear function.

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The graphs of the functions g and h are shown below. For each graph, find the absolute maximum and absolute minimum. If no such value exists, click on "None".

Assume that the dashed line shown is a vertical asymptote that the graph does not cross.

Answers

For the graph g, the absolute maximum is 2 and the absolute minimum is -4.

Similarly, for graph h, the absolute maximum is 3 and the absolute minimum is -5.

Absolute Maximum of a Graph:

The absolute maximum of a graph is the point on the graph with the highest y-value. There can only be one absolute maximum of a graph.

Absolute Minimum of a Graph:

The absolute minimum of a graph is the point on the graph with the lowest y-value. There can only be one absolute minimum of a graph.

Given,

Here we have the two graph called g and h.

Now, we need to find the absolute maximum and minimum from it.

AS per the given definition, we know that,

For graph g,

The absolute maximum is 2 and the absolute minimum is -4.

Similarly, for graph h, the absolute maximum is 3 and the absolute minimum is -5.

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For the function f(x)=3x2−4x−4,a. Calculate the discriminant.b. Determine whether there are 0, 1, or 2 real solutions to f(x)=0.

Answers

Answer:

a) Using the formula for the discriminant we get:

[tex]\begin{gathered} \Delta=(-4)^2-4(3)(-4), \\ \Delta=16+48, \\ \Delta=64. \end{gathered}[/tex]

The discriminant is 64.

b) Based on the above result we know that the f(x)=0 has 2 real solutions,

What is the distance from 7 to 0? O A. 7, because 171 = 7 Jurid O B. 7, because 171 = 7 O c. 7, because |-71 = -7 O D. -7, because [7] = -7

Answers

The distance from 7 to 0 is 7 because the absolute value of 7 is 7.

Correct Answer: A

Hey I need help with my homework help me find the points on the graph too please Thankyouu

Answers

Given the function:

g(x) = 3^x + 1

we are asked to plot the graph of the function.

Using the table:

x y

-2 10/9

-1 4/3

0 2

1 4

2 10

The graph:

The expomential functions have a horizontal asymptote.

The equation of the horizontal asymptote is y = 1

Horizontal Asymptote: y = 1

To find the domain is finding where the question is defined.

The range is the set of values that correspond with the domain.

Domain: (-infinity, infinity), {x|x E R}

Range: (1, infinity0, {y|y > 1}.

Write the equation of the circle centered at (−4,−2) that passes through (−15,19)

Answers

In this problem, we are going to find the formula for a circle from the center and a point on the circle. Let's begin by reviewing the standard form of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

The values of h and k give us the center of the circle, (h,k). The value r is the radius. We can begin by substituting the values of h and k into our formula.

Since the center is at (-4, -2), we have:

[tex]\begin{gathered} (x-(-4))^2+(y-(-2))^2=r^2 \\ (x+4)^2+(y+2)^2=r^2 \end{gathered}[/tex]

Next, we can use the center and the given point on the circle to find the radius.

Recall that the radius is the distance from the center of a circle to a point on that circle. So, we can use the distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Let

[tex](x_1,y_1)=(-4,-2)[/tex]

and let

[tex](x_2,y_2)=(-15,19)[/tex]

Now we can substitute those values into the distance formula and simplify.

[tex]\begin{gathered} r=\sqrt{(-15-(-4))^2+(19-(-2))^2} \\ r=\sqrt{(-11)^2+(21)^2} \\ r=\sqrt{562} \end{gathered}[/tex]

Adding that to our equation, we have:

[tex]\begin{gathered} (x+4)^2+(y+2)^2=(\sqrt{562})^2 \\ (x+4)^2+(y+2)^2=562 \end{gathered}[/tex]

What is the answer to 3/8 + 7 5/8

Answers

Given the Addition:

[tex]\frac{3}{8}+7\frac{5}{8}[/tex]

You can find the sum as follows:

1. Covert the Mixed Number to an Improper Fraction:

- Multiply the Whole Number part by the denominator of the fraction.

- Add the result to the numerator.

- The denominator does not change.

Then:

[tex]7\frac{5}{8}=\frac{5+(7\cdot8)}{8}=\frac{5+56}{8}=\frac{61}{8}[/tex]

2. Rewrite the Addition:

[tex]=\frac{3}{8}+\frac{61}{8}[/tex]

3. Since the denominators are equal, you only need to add the numerators:

[tex]=\frac{3+61}{8}=\frac{64}{8}[/tex]

4. Simplifying the fraction, you get:

[tex]=8[/tex]

Hence, the answer is:

[tex]=8[/tex]

Find the surface area. Do not round please Formula: SA= p * h + 2 * b

Answers

The shape in the question has two hexagonal faces,

The Area of each of the heaxagonal faces is

[tex]=42\text{ square units}[/tex]

The shape also has 6 rectangular faces with dimensions of

[tex]8.2\times4[/tex]

The area of a rectangle is gotten with the formula below

[tex]\text{Area}=l\times b[/tex]

By substituting the values, we will have

[tex]\begin{gathered} \text{Area}=l\times b \\ \text{Area}=8.2\times4 \\ \text{Area}=32.8\text{square units} \end{gathered}[/tex]

To calculate The total surface area of the shape, we will add up the areas of the hexagonal faces and the rectangular faces

[tex]\text{Surface area=}2\times(area\text{ of hexagonal faces)+ 6(area of rectangular faces)}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} \text{Surface area=}2\times(area\text{ of hexagonal faces)+ 6(area of rectangular faces)} \\ \text{Surface area}=(2\times42)+(6\times32.8) \\ \text{Surface area}=84+196.8 \\ \text{Surface area}=280.8\text{ square units} \end{gathered}[/tex]

Hence,

The Surface Area is = 280.8 square units

4) Using the number line to help you, decide which fraction is larger or if they are equal: one/twos or three/fifths. Label each fraction on the number line.

Answers

Explanation:

The number line is between 0 to 1. There are 10 smaller lines in between

Each of the small lines represent 1/10 or 0.1

one/twos is the same as 1/2 = 0.5

three/fifths is the same as 3/5 = 0.6

From the above, 0.6 is greater than 0.5

Showing both numbers on the number line:

The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?

Answers

The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?​

we have that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube.

so

Find the scale factor

ratio volumes=40.5/12=3.375

3.375=(scale factor)^3

[tex]\text{scale factor=}\sqrt[3]{3.375}[/tex]

scale factor=1.5

To find out the diameter of the larger balloon multiply the scale factor by the diameter of the smaller balloon

so

1.5*(10)=15 inches

the answer is 15 inches

please help me I dont understand A number is less than or equal to - 7 or greater than 12.

Answers

To translate the sentence as an inequality, we have:

[tex]x\leq-7,x>12[/tex]

Since the number is less or equal ( < = ) we use this symbol to represent it as inequality, and greater than using the symbol ( > ).

Then, we can answer the question as:

x < = -7 or x > 12.

Other Questions
5.4 The Progressive Era DBQ Essay100 points!!Historical Context:During the late 1800s and early 1900s, Progressive reformers worked to improve the social, political, and economic problems in American society.Task:Using information from the documents and your knowledge of United States history and government complete the following tasks:- Discuss three specific problems or injustices that were present in American life during the 1800s and early 1900s.- Explain how reforms proposed during the Progressive Era attempted to address these problems.Essay Guidelines:- Address all aspects of the task.- Support the theme with relevant facts, examples, and details.- Use a logical and clear plan of organization.- Introduce the theme by establishing a framework that is beyond a simple restatement of the task and conclude with a summation of the theme. In Emily's physics class, she had to solve the equation 9 = 12at2 + ut for u. Each step of her work is shown below.Use the drop-down menus to explain each step. meeting planning is a growing profession because select one: a. the profession involves practically all corporations b. it is mainly used by associations c. the convention market is growing d. all of the above e. none of the above explain two ways to evulate 32(16-6) Match each expression with its translation.1. 3 na number increased by three2. a +3the quotient of three and a number3. Y-3three times a number4. 3 = xthree subtracted from a number What is the product of 0.976 and 1.2 You had $21 to spend on five notebooks after buying them u had $6 dollars how much did each notebook cost. In Mr. Pattersons class, the average score among students who studied for an exam was 78. The average among students who did not study was 54. The overall class average was 70. What portion of the class did not study? Express your answer as a common fraction. under which conditions will an investor demand a larger return (yield) on a bond? multiple choice the bond issue is upgraded from a to aa. the bond issue is downgraded from a to bbb. interest rates decrease due to decline in inflation. none of the conditions will cause an increase in the bond's yield. what or who caused the plague in idm-al -wardi A website recorded the number of referrals it received from social media websites over a 10-year period. The results can be modeled by g = 2500(150), where is the year and SSRinterpret the values of a and & in this situation.a represents the number of referrals after 9 years, represents the growth factor of the number of referrals each yeara represents the number of referrals it received at the start of the model; &represents the decay factor of the number of referralsa represents the number of referrals after 9 years; b represents the decay factor of the number of referrals sach yeara represents the number of referrals it received at the start of the model & represents the growth factor of the number offWhat is the annual percent increase?The annual percent increase is %. Determine whether the arc is a minor arc, a major arc, or a semicircle of R. Questions 25 nd 27 2/3x - 8 when x = 12 Simply the equation 3(6+x)=-18 For the rhombus below, find the measures I just need help with question 1 for exercise 3! the actions a person takes in purchasing and using products and services, including the mental and social processes that come before and after these actions, are referred to as the amount of work actually done in a process costing center for the period includes all units started and completed during the period. in addition, other work is included in the quantification of the work done during the period. what other work is included? Users in motion, wireless connectivity, and a cloud-based resource are the elements in a ________ system. how would you explain the bubonic plague creatively and descriptively?