PART 1Select Introduction, and for the following unbalanced reactions found in the sim provide the missing coefficients.CoefficientReactant1CoefficientReactant2CoefficientProduct1CoefficientProduct2N2+H2HONH3H2O2COz

PART 1Select Introduction, And For The Following Unbalanced Reactions Found In The Sim Provide The Missing

Answers

Answer 1

They give us the reactions with their respective products and reactants. To balance a reaction we must bear in mind that matter is neither created nor destroyed, it only transforms. So the mass that we have in the reactants must be the same in the products. We verify this by counting the atoms of each element on each side of the reaction.

In the first reaction we have nitrogen and hydrogen. We have 2 nitrogens and 2 hydrogens in the reactants. We start off-balanced in nitrogen, so we place coefficient 2 in the NH3 molecule to get 2NH3. Now that we have 2 nitrogens and 6 hydrogens in the products, we must balance the hydrogen in the reactants. For that, we place the coefficient 3 in the H2 in such a way that there will be 6 hydrogen atoms in the reactants. The equation is balanced and will be:

[tex]N_2+3H_2\rightarrow2NH_3[/tex]

We do this same procedure for the other two equations. We count the atoms, we put the coefficients so that the number of atoms is conserved and we count again until the number of atoms of each element is the same on each side of the reaction. For the other two reactions we have:

[tex]2H_2O\rightarrow2H_2+O_2[/tex][tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]


Related Questions

16.Solid carbon dioxide (dry ice) passes directly into the gaseous state. The name for this process is...Select one:a. boiling.b. evaporation.c. melting.d. sublimation.

Answers

Answer:

[tex]D[/tex]

Explanation:

Here, we want to select the correct option

We evaluate each of the options as follows:

a) Boiling

It is a state that occurs when the vapor pressure equals atmospheric pressure for liquid substances

b) Evaporation

Evaporation occurs when liquid substances change directly into the gaseous state

c) Melting is the change from the solid state to the liquid state

d) Sublimation is the direct change of a substance from the solid to the vapor state. We can see this in iodine and naphthalene

CanvasX &Question 16Consider the reaction: 4Na(s) + O2(8) → 2Na2O(s)

Answers

ANSWER

The mass of Na2O in grams is 123.49 grams

EXPLANATION:

Given information

The mass of sodium is 91 grams

The mass of oxygen is 34.0 grams

To find the amount of Na2O produced, follow the steps below

Step 1: Write the balanced equation of the reaction

[tex]\text{ 4Na}_{(s)}\text{ + O}_{2(g)}\rightarrow\text{ 2Na}_2O_{(S)}[/tex]

Step 2: Find the number of moles of sodium and oxygen using the formula below

[tex]\text{ Mole = }\frac{\text{ mass}}{molar\text{ mass}}[/tex]

Recall, that the molar mass of Na is 22.989 g/mol, and the molar mass of oxygen atom is 32 g/mol

For Na

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ Mole = }\frac{91.6}{22.989} \\ \text{ Mole = 3.985 moles} \end{gathered}[/tex]

For O2

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ } \\ \text{ Mole = }\frac{34}{32} \\ \text{ Mole = 1.0625 moles} \end{gathered}[/tex]

Step 3: Find the limiting reactant of the reaction

The limiting reactant is the reactant that has the least number of moles after dividing it by the coefficient of the reactant

From the reaction above, you will see that 4 moles of sodium react with one mole of oxygen to give 2 moles of sodium oxide.

For Na

[tex]\begin{gathered} \text{ Na = }\frac{\text{ number of moles}}{\text{ coefficient}} \\ \text{ Na = }\frac{3.985}{4} \\ \text{ Na = 0.99625 mole/wt} \\ \\ \text{ For O}_2 \\ \text{ O}_2\text{ = }\frac{1.0625}{1} \\ \text{ O}_2\text{ = 1.0625 moles/wt} \end{gathered}[/tex]

From the above calculations, you will see that Na has the least number of moles, hence, Na is the limiting reactant

Step 4: Find the number of moles of Na2O

The Na2O can be determined using a stoichiometric ratio

Let x represents the number of moles

[tex]\begin{gathered} \text{ 4 moles of Na }\rightarrow\text{ 2 moles of Na}_2O \\ 3.985\text{ moles of Na }\rightarrow\text{ x moles of Na}_2O \\ \text{ cross multiply} \\ \text{ 4 moles of Na }\times\text{ x moles of Na}_2O\text{ = 2 moles of Na}_2O\times3.985\text{ moles of Na} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\cancel{moles\text{ of Na}_2}O\times3.985\cancel{moles\text{ of Na}}}{4\cancel{moles\text{ of Na}}} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\times\text{ 3.985}}{4} \\ \text{ X moles of Na}_2O\text{ = 1.9925 moles} \end{gathered}[/tex]

Hence, the number of moles of Na2O is 1.9925 moles

Step 5: Find the mass of Na2O

[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]

Recall, that the molar mass of Na2O is 61.9789 g/mol

[tex]\begin{gathered} \text{ 1.9925 = }\frac{\text{ mass}}{61.978} \\ \text{ Cross multiply} \\ \text{ Mass = 1.9925}\times61.978 \\ \text{ Mass = 123.49 grams} \end{gathered}[/tex]

Hence, the mass of Na2O in grams is 123.49 grams

A chemical reaction has the equation 2AgNO3 (aq) + Zn (s) → 2Ag (s) + Zn(NO3)2 (aq). What type of reaction occurs between AgNO3 and Zn?Question 17 options:A) Single displacementB) DecompositionC) SynthesisD) Double displacement

Answers

Combination (also called synthesis): Where two elements or one compound and one element will bond and form a new compound as a product, the representation for this reaction is:

A + B -> AB

Decomposition: The opposite from Combination, now one compound will decompose and form 2 new elements or compounds as the product:

AB -> A + B

Single Replacement: One element will take the place of another element in already existing compound:

A + BC -> AB + C

Double Replacement: Now we have two compounds switching elements and forming two new compounds:

AB + CD -> AC + BD

Combustion: Reactions that involve oxygen as reactant and we have CO2 and H2O as products:

X + O2 -> CO2 + H2O

According to the explanation, what we have in this reaction is a Single Displacement reaction, letter A

Recall the postulates of kinetic-molecular theory. Read the list and check all the statements that apply to the behavior of an ideal gas:1. gas particles behave like hard spheres2. gas particles travel randomly3. gas particles are attracted to each other4. energy is lost when gas particles collide 5. average kinetic energy of a collection of gas particles depends on the temperature6. gas particles occupy most of the space within a container7. gas particles have mass and volume

Answers

Answer:

Chemistry - States of matter - Kinetic Molecular Theory

This is the theory that explains the states of the matter and is based on the idea that matter is composed of tiny particles that are always on motion.

Part 1: Check all the statements that apply to the behavior of an ideal gas

The behaviors that apply are:

1.Gas paarticles behave like hard sphares.

2.Gas particles travel randomly.

5. Average kinetic energy of a collection of gas particles depends on the temperature.

Part 2: According to kinetic-molecular theory the one that would not be considered an ideal gas is:

A gas with highly polar molecules that have very strong intermolecular forces.

This is because the theory consideres thhat there are no forces of attraction of repultion between gas particles.

If you add 8 g of salicylic acid to 84 g of an ointment base, what is the final concentration (w/w) of the product? Round to the nearest hundredths (w/w).Question 3 options:Answer will be in % nothing else! ACTIVE INGREDIENT will always be your numerator.NUMERATOR (ACTIVE INGREDIENT)--------------------------------DENOMINATOR (TOTAL) Numerator means the top part of your fractionThe (w/w) is telling you to divideSTEPS: Add 8 + 84 this will be your denominator totalthen multiply by 100 to add the % sign in #----- Divide = then multiply by 100 for the percent sign. What is your answer?#FINISH THE MATH FOR THE CORRECT ANSWER

Answers

Answer

Concentration = (8/92)*100 = 8.7%

Explanation

Given:

mass of salicylic acid (active ingredient) = 8 g

mass of an ointment base = 84 g

Required: concentration (w/w) of the product?

Solution:

Total mass of the mixture = 8 + 84 = 92 g

Concentration = (8/92)*100 = 8.7%

The______of photosynthesis are the____of cellular respirationmeaning their equation are the ame but_____of each other.

Answers

Answer:

reactants /products, products / reactants, opposite / inverse

I can't exactly tell how many underscores there are.

Explanation:

This is biology, but it does contain chemistry.

Which of the following statements is one of the postulates in Dalton’s atomic theory?1. Atoms of different elements can physically mix together.2. Atoms of one element can be changed into atoms of another element through a chemical reaction.3. All compounds are composed of multiple elements combined together.4. Atoms of one element cannot be changed into another element through a chemical reaction.

Answers

Answer:

All atoms of a specific element are identical in mass, size, and other properties. However, atoms of different element exhibit different properties and vary in mass and size. Atoms can neither be created nor destroyed. Furthermore, atoms cannot be divided into smaller particles.

How much heat is released when 245 g of steam cools from 106.0°C to -4.5°C

Answers

ANSWER

The amount of heat released is -54, 957.175J

EXPLANATION

Given that;

[tex]\begin{gathered} \text{ The mass of the steam is 245g} \\ \text{ The final temperature of the steam is -4.5}\degree C \\ \text{ The initial temperature of the steam is 106.0}\degree C \end{gathered}[/tex]

To find the amount of energy released, then apply the below formula

[tex]\text{ q = mc \lparen}\theta2\text{ - }\theta1)[/tex]

Recall, that the specific heat capacity of steam (c) is 2.03 J/g degrees Celcius

[tex]\begin{gathered} \text{ q = 245 }\times\text{ 2.03 \lparen-4.5 - 106\rparen} \\ \text{ q = 245 }\times\text{ 2.03 \lparen -110.5\rparen} \\ \text{ q = -54,957.175J} \end{gathered}[/tex]

Therefore, the amount of heat released is -54, 957.175J

need help with this pleaseeeeeeeeeeeeeeWhat trends do you see in the organisms of the ecosystem if youdecrease sunlight A. Increase in energy storage moleculesB. Decrease in H2OC. Decrease in energy storage moleculesD. Increase in CO2

Answers

Answer:

Explanations:

Answer:

Explanations:

What is the final concentration when 288mL of water is added to 239mL of a 0.274M solution?

Answers

Answer:

0.124 M.

Explanation:

What is given?

Volume 1 (V1) = 239 mL,

Concentration 1 (C1) = 0.274 M,

Volume 2 (V2) = 239 mL + 288 mL = 527 mL.

What do we need? Concentration 2 (C2).

Step-by-step solution:

To solve this problem, we have to use the following formula:

[tex]C_1V_1=C_2V_2.[/tex]

Where the initial concentration (C) and volume (V) are represented with subindex 1, and the final concentration and volume are represented with subindex 2.

The problem is telling us that we are adding 288 mL of water to 239 mL, so the final volume is the sum of these two volumes, i.e., 527 mL.

As we want to find the final concentration, C2, we just have to solve for this unknown value and replace the values that we have, like this:

[tex]\begin{gathered} C_2=\frac{C_1V_1}{V_2}, \\ \\ C_2=\frac{0.274\text{ M}\cdot239\text{ mL}}{527\text{ mL}}, \\ \\ C_2=0.124\text{ M.} \end{gathered}[/tex]

The answer would be that the final concentration of the solution is 0.124 M.

After centrifugation of the sample, the student was not careful and some of the solid was transferred to the Erlenmeyer flask along with the liquid (supernatant). How is this mistake expected to affect the mass of the limiting reactant in the unknown mixture used?

Answers

The fact that some of the solid was transferred would decrease the mass of the limiting reactant.

What is the limiting reactant?

We know that in a chemical reaction, there are at least two substances that are combined in order to give the product of the reaction. We also know that the product that we obtain must be in accordance to the stoichiometry of the reaction.

It is common to see that one of the reactants would be present in a very large amount while the other reactant would be present only in quite a small amount. The reactant that is present in a small amount is said to be the limiting reactant while the one that is present in the large amount is said to be the reactant that is in excess.

Having said this, we know that the mass of the limiting reactant can be obtained from the mass of the solid that is obtained after the reaction.

If we do not take out all of the solid from the centrifuge, the mass would not be accurately weighed and the mass of the limiting reactant would not be accurately determined.

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Name three different forms of mixture

Answers

Answer:

Mixtures can be classified on the basis of particle size into three different types: solutions, suspensions and colloids. The components of a mixture retain their own physical properties.

Sorry for the bad English, love from Vanuatu!

Explanation:

According to Bronsted-Lowry Theory, a base is.....Group of answer choicesa H+ donora H+ acceptora OH- donorwater

Answers

answer and explanation

a bronsted-lowry basic is a H+ donor

Limestone is a sedimentary rock composed largely of the mineral calcite, (calcium carbonate) CaCO3. To test the purity of the calcium carbonate, a sample of the mineral is reacted with hydrochloric acid to produce calcium chloride, carbon dioxide and water If a 15.70 g sample of calcite is reacted with excess hydrochloric acid and 16.89 g of calcium chloride are produced, what is the percent by mass of the calcium carbonate in the limestone? A) 69.4% B)93.0 % C) 96.94% D)98,22 %

Answers

Answer:

[tex]C\text{ : 96.94 \%}[/tex]

Explanation:

Here, we want to get the percentage by mass of calcium carbonate in the limestone

We start by writing an equation of chemical reaction

The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water

We have the equation as follows:

[tex]\text{CaCO}_{3(s)\text{ }}+2HCl_{(aq)}\rightarrow CaCl_{2(aq)\text{ }}+CO_{2(g)\text{ }}+H_2O_{(l)}[/tex]

Now, let us work with the extra information

16.89 g of calcium chloride are produced

Let us get the number of moles of calcium chloride produced

We can get that by dividing the mass by the molar mass of calcium chloride

The molar mass of calcium chloride is 111 g/mol

So, the number of moles will be:

[tex]\frac{16.89}{111}\text{ = 0.1522 mole}[/tex]

From the equation,

1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite

To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite

The molar mass of calcite is 100 g/mol

That means the mass of calcite that produced the calcium chloride will be:

[tex]0.1522\text{ }\times\text{ 100 = 15.22 g}[/tex]

What this mean is that 15.22 g of calcite produced the given mass of calcium chloride

The percentage by mass of calcite in the limestone will be:

[tex]\frac{15.22}{15.70}\times\text{ 100\% = 96.94 \%}[/tex]

how did democritus model change throughout history write a paragraph using other theories about atoms.

Answers

Democritus proposed the idea that atoms were unique to the substance they were found .

How has the atomic model evolved through time?

Model of Bohr (1913)

Niels Bohr made Rutherford's model better. He demonstrated, using mathematical concepts, that electrons reside in energy levels or shells surrounding the nucleus. Due to the discovery of subatomic particles, the Dalton model has evolved over time.

The importance of the atomic theory

Astonishing scientific advancements in fields like contemporary chemistry and nuclear energy resulted from the finding that all matter is composed of microscopic particles, which was made possible by the atomic theory.

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The sheet of gold foil Rutherford used was 304 mm wide and 0.016 mm thick. What maximum length of gold foil could be made from 1.10 x 103 g of gold?

Answers

The maximum length of gold foil could be 1171.7 cm made from 1.10 x 10³ g of gold.

What is the density?

The density of an object can be described as the mass per unit volume. The average density is equal to the total mass divided by its total volume.

The mathematical formula of the density of the material can be expressed as follows:

Density = Mass/Volume

The density of a substance is an intrinsic property as it doesn't depend on its size and the S.I. unit of the density is Kg/m³.

Given the width of the gold foil, w = 304 mm = 30.4 cm

The height or thickness of the foil, h = 0.016 mm = 0.0016 cm

The density of the gold foil, d = 19.3 g/cm³

The mass of the gold given, m = 1100 g

The volume of the foil = m/d = 1100/ 19.3 = 56.99 g/cm³

As we know that the volume of  gold foil , V = l × w × h

l = V/(w × h)

l = 56.99/(30.4 × 0.0016)

l =1171.7 cm

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how many molecules are there in 2.13 moles of sodium bromide

Answers

Answer:

121 I think not sure tbh......

How much water needs to be added to a 8.6317 M NaCl solution to obtain a 1.0421 M solution, if you start with 4.7869 liters of solution?

Answers

The amount of water needed to be added to a 8.6317 M NaCl solution to obtain a 1.0421 M solution starting with 4.7869 liters of solution would be 34.8629 L.

Dilution

The problem here has to do with dilution. The dilution principle states that the number of moles of solute in a solution is constant before and after dilution.

In other words, the dilution principle can be mathematically expressed as:

[tex]m_1v_1[/tex] = [tex]m_2v_2[/tex].

Where [tex]m_1[/tex] and [tex]m_2[/tex] are molarities before and after dilution; [tex]v_1[/tex] and [tex]v_2[/tex] are volumes before and after dilution.

In this case:  [tex]m_1[/tex] = 8.6317 M,  [tex]m_2[/tex]= 1.0421 M,  [tex]v_1[/tex]= 4.7869 L. We are to determine v2.

[tex]v_2[/tex] = [tex]m_1v_1[/tex]/ [tex]m_2[/tex]

    = 8.6317x4.7869/1.0421

    = 39.6498 L

If the final volume of the solution is 39.6498 L and the starting volume is 4.7869, then the amount of water needed can be calculated as:

39.6498 - 4.7869 = 34.8629 L

Thus, the amount of water that will be added to the original solution in order to arrive at the diluted solution is 34.8629 L.

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Initially a sample of nitrogen gas is found in a pressure of 4.62 atm under the temperature of 27.0°C

Answers

The change in the temperature of the gas, given that the volume is held constant is 63 °C

How to determine the change in temperature

Let's begin by obtaining the new temperature of the gas. This can be obtained as follow:

Initial pressure (P₁) = 4.62 atm Initial temperature (T₁) = 27 °C = 27 + 273 = 300 KNew pressure (P₂) = 5.59 atm New temperature (T₂) =?

P₁ / T₁ = P₂ / T₂

4.62 / 300 = 5.59 / T₂

Cross multiply

4.62 × T₂ = 300 × 5.59

Divide both side by 4.62

T₂ = (300 × 5.59) / 4.62

T₂ = 363 K

Subtract 273 to obtain answer in °C

T₂ = 363 – 273 K

T₂ = 90 °C

Finally, we shall determine the change in the temperature. This is illustrated below:

Initial temperature (T₁) = 27 °CNewl temperature (T₂) = 90 °CChange in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 90 – 27

ΔT = 63 °C

The, the change in the temperature is 63 °C

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A mixture of nitrogen and hydrogen gas is compressed from a volume of 90.0L to a volume of 89.0L, while the pressure is held constant at 44.0atm. Calculate the work done on the gas mixture. Round your answer to 2 significant digits, and be sure it has the correct sign (positive or negative).

Answers

The PV work formula is:

w = -Pexternal * ΔV

w = -44.0 atm * (89.0 - 90.0)

w = -44.0 atm * -1 L

w = 44.0 L atm

For each L atm, we will have 101.325 Joules, therefore

44.0 L atm * 101.325 J

w = 4458.3 J or 4.4 kJ

A redox reaction:A. is a reaction where oxygen is returned it its natural state.B. is a reduction reaction where oxygen is removed.C. is comprised of two half reactions, a reduction and an oxidation.D. is a reaction where oxygen is added to a compound.

Answers

In this question, we have to classify what is a redox reaction, and as the name suggests, we have a reduction and an oxidation reaction occurring in this type of reaction, where one element will lose electrons, or will be oxidized, and another element will gain electrons or will be reduced. Therefore the best answer will be letter C

A balloon has a volume of 1785 mL at 25°C, if the volume of balloon changes to 1.25 L, what is the new temperature in degree Celcius atconstant pressure and amount?

Answers

We work here with Charles' Law. The equation used here is:

V1/T1 = V2/T2 (1)

(pressure and amount constant)

V is for volume and T for temperature

V1 = 1785 mL

1 L = 1000 mL ==> V1 = 1.785 L

T1 = 25 °C = 25 °C + 273 = 298 K

V2 = 1.25 L

T2 = unknown

From (1) we clear T2:

T2 = V2 x T1/V1 = 1.25 L x 298 K/1.785 L = 209 K approx.

T2 = 209 K - 273 = -64 °C

Answer: T2 = -64 °C

i need to put 5 grams of hydrogen through two sets of chemical reactions, one resulting in a covalent outcome, the other resulting in an ionic outcome. I also need to balance the equations used during this process as well as calculate the number of molecules produced by the covalent compound, and the mass of the ionic product.This is a big project in my chemistry class and I've chosen Hydrogen as my element to use throughout these chemical reactions. I will provide the assignment outline and the work I've done so far :)thank you so very much for the help!

Answers

1.For a covalent bond , we will use the equation below:

2H2(g) +O2(g) → 2H2O(g)

Mass = 5 g : :

Moles = 4.96 : : 4.96

1.1 number of moles for hydrogen :

moles = mass /Molecular mass

= 5g/1,00784

=4.96 moles

1.2 Determine molar ratio in oder to get the moles for product 2H2O

we see that :

2 moles of Hydrogen produces: 2 moles of water

so, 4.96 moles of hydrogen will produce : x = 4.96*2 /2 = 4.96

This means that moles for water = 4.96

1.3 Calculating molecules of the product

n = 4.96moles

Molecules of H2O = 4.96 mol * 6.022×10^23molecules/1mol

=2.99x10^24 molecules

Place these Types of Decay in Order from the LOWEST Energy to the HIGHEST energy.

Answers

Answer:

[tex]\begin{gathered} Alpha\text{ Decay} \\ Beta\text{ Decay} \\ Gamma\text{ Decay} \end{gathered}[/tex]

Explanation:

Here, we want to order the radiations in terms of energy

There is a proportional relationship between the mass and the energy

It is established that the radiation with a higher mass would have the lesser energy

Alpha decay has the highest mass and thus, the lowest energy. This is followed by beta decay, and finally, gamma decay

How many moles of ammonium nitrate (NH4NO3) are present in 0.085 L of a 0.23 M ammonium nitrate (NH4NO3) solution?

Answers

Answer:

No. of moles [tex]\approx[/tex] 0.020

Explanation:

To calculate the number of moles of a substance in a solution given its concentration and volume, we use the following formula:

[tex]\boxed{\mathrm{No. \ of \ moles = Concentration \times Volume}}[/tex],

where concentration is in mol/dm³ (or M) and volume is in L.

In the question, we are told that the volume of the solution is 0.085 L and that its concentration is 0.23 M. Substituting these values into the formula above, we get:

No. of moles = 0.23 × 0.085

                     = 0.01955

                     [tex]\approx[/tex] 0.020 mol  (3 s.f.)

Therefore, there are 0.020 moles of NH₄NO₃ in the solution.

What volume of Cl2 gas, measured at 688 torr and 36 °C, is required to form 22 g of NaCl?Express your answer using two significant figures.

Answers

ANSWER

Volume of the gas 5.3L

EXPLANATION;

Given that

The pressure of the chlorine gas is 688 torr

The temperature of the chlorine gas is 36 degrees Celcius

The mass of NaCl is 22 grams

Follow the steps below to find the volume of chlorine gas

Step 1; Write a balanced equation for the reaction

[tex]\text{ 2Na + Cl}_2\text{ }\rightarrow\text{ 2NaCl}[/tex]

In the above reaction, 2 moles of Na react with 1 mole of chlorine to form 2 moles of NaCl

Step 2; Find the number of moles of NaCl using the below formula

[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]

Recall, that the molar mass of NaCl is 58.44 g/mol

[tex]\begin{gathered} \text{ mole = }\frac{22}{\text{ 58.44}} \\ \text{ moles = 0.376 mole} \end{gathered}[/tex]

Step 3; Find the number of moles of Cl2 using a stoichiometry ratio

Let x represents the number of moles of Cl2

[tex]\begin{gathered} 1\text{ mole Cl}_2\text{ }\rightarrow\text{ 2 moles NaCl} \\ \text{ x moles Cl}_2\rightarrow\text{ 0.376 moles NaCl} \\ \text{ cross multiply} \\ \text{ x moles Cl}_2\text{ }\times2\text{ moles NaCl }=\text{ 1 mole Cl}_2\text{ }\times\text{ 0.376 mole NaCl} \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 1 mole Cl}_2\times0.376moles\cancel{NaCl}}{2moles\cancel{NaCl}} \\ \\ \text{ x = }\frac{1\text{ }\times\text{ 0.376}}{2} \\ x\text{ = }\frac{0.376}{2} \\ \text{ x = 0.188 mol} \end{gathered}[/tex]

The number of moles of Cl2 is 0.188 mol

Step 4; Find the volume of the gas using the ideal gas equation

[tex]\text{ PV = nRT}[/tex]

Convert the temperature to degree kelvin

[tex]\begin{gathered} \text{ t = 36}\degree C \\ \text{ T = 36 + 273.15} \\ \text{ T = 309.15 K} \end{gathered}[/tex]

Step 5; Find the volume of the gas

[tex]\begin{gathered} \text{ PV = nRT} \\ \text{ Recall, that R = 62.363 L. torr mol}^{-1}K^{-1} \\ \text{ 688}\times\text{ V =}^{\text{ }}0.188\text{ x 62.636 }\times\text{ 309.15} \\ \text{ 688 V = 3624. 500} \\ V\text{ = }\frac{\text{ 3645, 500}}{688} \\ \text{ v = 5.3 L} \end{gathered}[/tex]

Therefore, volume of the gas 5.3L

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How do the masses of the hottest main sequence stars compare to the masses of the coolest main sequence stars?

Answers

Answer:

the more hotter the star, the more brightly it burns

Explanation:

someone just deleted my answer ugh sorry....ill write it again

so, te main sequence is a sequence in mass (and not a sequence in time).

The most massive stars are located at the the top left (since they are the brightest and hottest/bluest). The lowest mass stars are are located at the bottom left ( since they dimmer and cooler/redder).

Following the main sequence from the top left to the bottom right is thus a sequence from high to low mass.

If the mercury in a barometer raises 22.8 centimeters due to a change in ambient pressure, what is the corresponding change in pressure in atm?

Answers

If the mercury in a barometer raises 22.8 centimeters due to a change in ambient pressure, then the corresponding change in pressure would be 0.3 atm.

What is pressure?

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied

As given in the problem If the mercury in a barometer raises 22.8 centimeters due to a change in ambient pressure, then we have to find out the corresponding change in pressure in atm,

760 mm of Hg = 1 atm

76 cm of Hg = 1 atm

1 cm of Hg = 1 / 76 atm

22.8 cm of Hg = 22.8 / 76 atm

                        = 0.3 atm

Thus ,  the corresponding change in pressure in atm would be 0.3 atm .

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Which is a property of all acids?OA. They increase the OH concentration in solution.OB. They increase the H* concentration in solution.OC. They contain OH ions.OD. They contain H3O+ ions.

Answers

Answer

B - They increase the H+ concentration in solution.

Explanation

All acids contain H+ for example, HCl contributes H+ ions into the solution, which decreases the pH of the solution. for example, a base, NaOH increases the concentration of OH⁻ ions and decreases the concentration of H⁺ ions. Therefore all acids increase the H+ concentration in solution.

Add 43.8lbs and 56.8923lbs. What is the answer in the correct significant figures?

Answers

The answer in correct significant figures of the addition of the two numbers mentioned is 100.70.

What are significant figures?

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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