The ball experiences an equal and opposing force from the wall as a result of Newton's third law .Therefore, in a perfect world, the ball would return at the same speed it originally did, preserving momentum.
explain magnitude of the loss in the Kinetic energy?
An object's mass times its velocity change equals the change in momentum of that object.Δp=m⋅(Δv)=m⋅(vf−vi) Pi=m1v1 will be the system's initial momentum.Therefore, the difference between the initial and final kinetic energies is non-zero, demonstrating that kinetic energy is always lost in inelastic collisions. The magnitude of this loss is Loss=12m1v12[m2m1+m2]. The ball is severely deformed as it is struck due to the bat's tremendous force.The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. By multiplying the magnitudes of two forces acting in the same direction along a straight line, you can quickly calculate the combined force.To learn more about magnitude refer
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A car with a weight of 6996 N is subjected to a net force of 1.74e4. The cars acceleration will be
Answer: 24.37 m/s/s [forward] = a
Explanation:
First, find mass with the Fgrav formula.
Fgrav=mg
6996=m(9.8)
713.88 kg
Then, plug the answer into Newton's second law formula.
Fnet = ma
1.74e4 = (713.88)a
(1.74e4)/(713.88) = a
24.37 m/s^2 = a
. is a major factor in dictating how much energy the vehicle can absorb to protect the occupants. a. frictional energy b. angle of attack c. speed d. all of the above
The correct answer is option c, speed.
Speed is the rate at which someone or something moves or operate. It is measured by the velocity and time.
Velocity is the total distance in total time taken.
Speed tells the amount of energy absorbed by the vehicle. The energy is used in the movement of the vehicle and it also helps the vehicle to move accordingly.
Speed is the major factor that helps to protect the occupants.
It is speed only that we can adjust a according to the situation. This also keeps the vehicle in control. It is the main factor in any vehicle that causes the vehicle to move and also it helps to keep it in control as well. Other controls are the supporting factors that helps to keep the speed in control.
Be it the weather, the climate, roads or traffic, it is speed that helps to keep the occupants safe.
Therefore, Speed is a major factor in dictating how much energy the vehicle can absorb to protect the occupants
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To program a digital turtle to trace the outline of a hexagon, what code should be used?
A.
forward 50
B.
repeat 6 [forward 50 right 60]
C.
repeat 3 [forward 50 right 90]
D.
repeat 4 [forward 50 right 60]
To program a digital turtle to trace the outline of a hexagon, the code that should be used is repeat 6 [forward 50 and right 60]. Hence, option B is correct.
What is a program?A computer utilizes a program, which is a collection of instructions, to carry out a particular task. A program is like a computer's recipe, to use an analogy. It has a list of components (known as variables, which can stand for text, graphics, or numeric data) and a list of instructions (known as statements), which instruct the computer on how to carry out a certain operation.
Programming languages with particular syntax, like C++, Python, and Ruby, are used to develop programs. These high-level programming languages are written and readable by humans.
According to the question, the hexagon has six sides so the turtle has to repeat 6 times. Hence, option B is correct.
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Question 6:A particle of mass 0.2 kg is moving in a straight line at speed 2.5ms, a constant force of magnitude FN is applied to it in the direction in which it is moving. The speed of the particle 5 seconds later is 4.5ms Find the value of F, magnitude of the force applied.
First, let's calculate the particle acceleration, using the formula below:
[tex]\begin{gathered} V=V_0+a\cdot t \\ 4.5=2.5+a\cdot5 \\ 5a=4.5-2.5 \\ 5a=2 \\ a=\frac{2}{5}=0.4\text{ m/s}^2 \end{gathered}[/tex]Now, to find the force applied, let's use the second law of Newton:
[tex]\begin{gathered} F=m\cdot a \\ F=0.2\cdot0.4 \\ F=0.08\text{ N} \end{gathered}[/tex]Therefore the value of F is 0.08 N.
a car is travelling at a velocity of 2.0m/s. it accelerates at a constant 0.20m/s^2 for 2.5 min what is the final velocity of the car
The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue.
The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.
V = u + a*t
V = 2 + 0.20 * (2.5*60)
V = 32 m/s
The rate at which the speed and direction of a moving object change over time is known as acceleration. Something is said to be accelerating when it starts to move faster or slower. Motion on a circle accelerates even while the speed is constant because the direction is always changing. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.
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True or false? The period of an AC supply is equal to the time between an adjacent peak and trough on an oscilloscope trace.
Answer:
false
Explanation:
the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.
jim leaves his house and begins walking to his car in a straight line. he goes 2.0 m then returns to his house to get his keys. next, he leaves his house and travels 6.0 m to his car. what is jim's displacement?
Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m
Δx = x2 - x1
Δx = Displacement
x2 = Final position
x1 = Initial position
Considering the house as origin,
Final position = 6 m
Initial position = 0
Δx = 6 - 0
Δx = 6 m
Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.
Therefore, Jim's displacement is 6 m
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thermal energy 1. causes the mass of a body to increase. 2. decreases as the temperature of a body increases. 3. is characterized by the random motion of molecules. 4. is the only form of energy that can be transformed into work with 100% efficiency.
Thermal energy 3. is characterized by the random motion of molecules.
In the field of physics, thermal energy can be described as the internal energy present inside an object or system.
The thermal energy present in the molecules of an object causes the molecules to move randomly. It is the energy that causes random motion in atoms.
If the thermal energy keeps on increasing, the movement of molecules also keeps on increasing.
For example, the molecules in water have lower thermal energy initially due to which they show lesser random motion. As we increase heat, the thermal energy increases causing the random motion to increase and water turns into steam as we keep on increasing the thermal energy.
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A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :
a) 5 N/C
b) 800 N/C
c) 0.02 N/C
d) 50 N/C
(d) 50N/C
The magnitude of the electric field at point 'P' is 50N/C.
It is derived from the basic concepts of Electrostatics. Coulomb's Law is the basis of relations in Electrostatics. It resembles Newton's Law of Gravitation.
Using the relation between Electric force, charge, and Electric field:
F = qE
F = 200N; q = 4C200 = (4)E
E = 50N/C
It is widely used in the calculation of Electric Force and Electric Field. The S.I. Unit of the Electric Force is Newton. The S.I. Unit of the Electric Field is N/C. The S.I. Unit of charge is Coulomb.
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two circuits present the same resistance to the cu rrent. in one circuit the battery causing the flow of current has a voltage of 9.0 v, and the current is 3.0 a. in the other circuit the battery has a voltage of 1.5 v. what is the current in this other circu it?
The current in this other circuit while the time remains constant, the current is doubled and the resistance is cut in half.
According to Ohm's law, the resistance (R) in a circuit has an inverse relationship to the electrical current (I), which is proportional to the voltage (V) (R). Therefore, if the voltage is raised, the current will rise as long as the circuit's resistance remains constant. Ohm's Law describes the relationship between current, voltage, and resistance. This states that, provided the temperature stays constant, the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the circuit resistance. As long as the resistance is kept constant, an increase in voltage will therefore result in an increase in current.
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Victor is using his Geiger-counter to record the amount of radiation that is leaking into the soil from a nearby nuclear disposal site. This radiation decreases by the square of the distance from the source. If he starts measurements 100 m from the disposal site how close will he need to stand if he hopes to measure soil with 4 times the radiation?
According to inverse square proportionality, measuring 4 times more radiation will require Victor to _____ his distance. Victor will need to stand _____ m from the disposal site.
If Victor starts measurements 100 m from the disposal site, he needs to stand 50 m from the source if he hopes to measure soil with 4 times the radiation.
I = 1 / r²
I = Intensity
r = Distance
At a distance of 100 m from the source,
I = 1 / 100²
I = 1 / 10000
I = [tex]10^{-4}[/tex] J / m² s
Four times this radiation will have an intensity of,
I = 4 * [tex]10^{-4}[/tex] J / m² s
4 * [tex]10^{-4}[/tex] = 1 / d²
d² = 1 / 4 * [tex]10^{-4}[/tex]
d² = 0.25 * [tex]10^{4}[/tex]
d = √ 25 * 10²
d = 5 * 10
d = 50 m
Therefore, he needs to stand 50 m from the source
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If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)
Given:
The mass of the system is m' =m/2
The net force acting on it is F' = 2F
To find the acceleration.
Explanation:
The acceleration will be
[tex]\begin{gathered} a^{\prime}=\frac{F^{\prime}}{m^{\prime}} \\ =\frac{2F}{\frac{m}{2}} \\ =\frac{4F}{m} \\ a^{\prime}=4a \end{gathered}[/tex]Thus, the acceleration would be quadrupled(x4).
The concept of inertia forms the basis for Newton's Third Law of Motion True False
Given
The concept of inertia forms the basis for Newton's Third Law of Motion
To find
The given statement is true or false
Explanation
The third law of motion states that every action has a equal and opposite reaction
Inertia is the property by virtue of which an object at rest tends to be at rest and object at motion tends to be at motion
Thus both the concept are not similar
Conclusion
The given statement is false
a car carrying a 80-kgkg test dummy crashes into a wall at 28 m/sm/s and is brought to rest in 0.10 ss. part a what is the magnitude of the average force exerted by the seat belt on the dummy? express your answer to two significant figures and include the appropriate units
The magnitude of the average force exerted by the seat belt on the dummy is 224N .
What is an average force ?The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.
Briefing:mass of the dummy (m) = 80kg
velocity of the dummy (v) = 28 m/s
time (t) = 10 seconds
Average force exerted (F)
To calculate the average force;
According to the formula;
F = (m × v) ÷ t
Where;
F represents the force exerted
m represents the mass of the dummy
v represents the velocity
t represents the time
F = m * v/t
F = 80 *28/10
F = 224
F = 224 N
The force exerted by the seat belt on the dummy is 224N .
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Show how you got the answer, please
Question:
A wave with a frequency of 14 Hz has a wavelength of 3 meters. At what speed with this wave travel?
Answer:
42m/s
Explanation:
v= λf
Frequency of wave: f= 14Hz
the wavelength of the wave: λ=3m
speed of wave: s=?
speed = frequency * wavelength
s = 14 * 3 = 42 m/s.
a rocket started at rest.after initiating the launch,it had an acceleration of 90m/s2.how long did it take to reach a speed of 2430 m/s2
The time taken for the rocket to reach a speed of 2430m/s from rest is 27.0 seconds.
What is the time taken for the rocket to reach a speed of 2430m/s?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Since it starts from rest, Initial velocity u = 0m/sFinal velocity v = 2430m/sAcceleration a = 90m/s²Elapsed time t = ?To determine the time, substitute the given values into the formula above and solve for t.
v = u + at
2430m/s = 0 + ( 90m/s² × t )
2430m/s = 90m/s² × t
t = 2430m/s / 90m/s²
t = 27.0s
Therefore, the elapsed time is 27.0 seconds.
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A rocket launched with an acceleration of 90 m/s², and a final speed of 2430 m/s. So the time required to reach the final speed is 27 seconds.
What is acceleration?The ratio of change in velocity to time is referred to as acceleration. It has a SI unit m/s² with dimension formula MLT⁻².
According to the question, the given values are,
Final velocity, v = 2430 m/s
Initial velocity, u = 0 m/s
The acceleration is given as, a = 90 m/s².
Use the equation of motion to find the time required to reach the final speed,
v = u + at
2430 = 0 + ( 90 × t )
2430 = 90 × t
t = 2430 / 90
t = 27.0 seconds.
Hence, the time taken to reach the final speed is 27 seconds.
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A box measures 3 centimeters on each side and has a mass of 47 grams , what is the density
Answer:
[tex]3 \times 47 = [/tex]
141
what is the velocity (in m/s) of a 925 kg car initially moving at 29.5 m/s, just after it hits a 145 kg deer initially running at 12.5 m/s in the same direction? assume the deer remains on the car. (enter the magnitude.)
The velocity after the collision is 27.19 m/s
What is the law of conservation of momentum?For a collision between Object 1 and Object 2 in an isolated system, the total momentum of the two objects before collision equals the total momentum of the two objects after collision. That is, the momentum lost from object 1 is equal to the momentum gained from object 2 (a constant or unchanging value). It can be stated by following equation:
Pₙ = mₙvₙ
mₙvₙ = m₁v₁ + m₂v₂
Where, Pₙ = final momentum
mₙ = total mass of the system
vₙ = final velocity of the system
For the given case,
Since, mₙvₙ = m₁v₁ + m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
(925 + 145)vₙ = (925 × 29.5) + (145 × 12.5)
1070 vₙ = 27287.5 + 1812.5
1070 vₙ = 29100
vₙ = [tex]\frac{29100}{1070}[/tex]
vₙ = 27.19 m/s
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1. a circular coil 0.0500 m in radius, with 30 turns of wire, lies in a horizontal plane. it carries a counterclockwise (as viewed from above) current of 5.00 a. the coil is in a uniform 1.20 t magnetic field directed toward the right. find the magnitudes of the magnetic moment and the torque on the coil.
Magnetic moment of the given coil is 1.178 Am²
Torque of the given coil is 1.414 TAm²
Radius of the coil = 0.05 m
Number of turns in the coil = 30 turns
Current passing through the coil = 5 A
Magnetic field in the coil = 1.2 T
The current flows in counterclockwise direction. Therefore by thumbs rule, the magnetic field flows towards right side.
The magnetic moment of the coil
M = N x I x A
where N is the number of turns in the coil
I is the current passing through the coil
A is the area of the coil
Let us substitute the known values in the above equation,
M = 30 x 5 x πr²
= 30 x 5 x 3.14 x (0.05)²
= 471 x 0.0025
= 1.178
The magnetic moment of the given coil is 1.178 Am²
The torque of the coil can be found using
τ = M x B
where M is the magnetic moment and
B is the magnetic field produced due to the coil.
τ = 1.178 x 1.20
= 1.414 TAm²
Therefore , the torque of the coil is 1.414 TAm²
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a 2 900-kg truck moving at 11.0 m/s strikes a car waiting at a traffic light, hooking bumpers. the two continue to move together at 7.00 m/s. what was the mass of the struck car?
The mass of the car that was stuck is 1657 Kg.
What is the mass of the struck car?We know that we have to use the laws of the conservation of the linear momentum here. It is known that the momentum before collision must be equal to the total momentum that we have after collision.
In this case, we have;
m1u1 + m2u2 = m1v1 + m2v2
m1 = mass of the truck
m2 = mass of the car
u1 and v1 = the initial and final velocities of the truck
u2 and v2 = initial and final velocities of the car
Again we are told that the two continue to move together hence v1 + v2 = v
m1u1 + m2u2 = (m1 + m2) v
(2900 * 11.0) + 0 = (2900 + m2) 7
31900 = 20300 + 7m2
31900 - 20300 = 7m2
m2 = 31900 - 20300 /7
m2 = 1657 Kg
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a cat slides down a slippery slanted roof at an acceleration of 2.2 m/s2 (it won't get hurt because it has nine lives). if it started at the top with zero initial speed, how far will the cat have slipped after 3 seconds? answer in meters and include two digits after the decimal point.
The cat will have slipped till the distance of 9.90 seconds in 3 seconds.
The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.
Now, using equation of motion,
S = Ut + 1/2at²
Where,
U is initial velocity of the body,
t is the time period of the body,
S is the displacement of the body,
a is the acceleration of the body.
Putting all the values,
S = 1/2at²
S = 1/2(2.2)(3)²
S = 9.90 meters.
The distance to which the cat will fall is 9.90 meters.
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PLEASE ANSWERRRRRRRRRRRRRR
Law of Reflection :
The law of reflection states that when light rays strike a smooth surface, the angle of reflection equals the angle of incidence, and the incident ray, reflected ray, and normal to the surface all lie in the same plane.
Here, let us consider, the ray A as the normal , as it is perpendicular to the surface of the plane mirror. When the incident ray hits the plane mirror at an angle say, θ with the normal ( here, incident ray A) , then, θ will be the angle of reflection.
Now if we consider all the incident rays A, B, C and D. Among them, let the ray C make an angle Θ, with the normal ( here, incident ray A).
Therefore, from the image given, clearly, θ = Θ, hence Θ is the angle of reflection, thus ray C best represents the reflected ray.
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6. Force is being applied to a rotating disk at an angle of 90 degrees to itsradial line. How does the torque change if...
Torque Formula:
T = d * F * sin angle
a) if the force is doubled, torque is doubled ( directly proportional)
For example, if force is 2 N, and distance is 2 m ,
T= 2*2* sin 90 = 4 Nm
If force is doubled:
T= 2*4 * sin90 = 8 Nm
b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")
c) If angle decreases 45° (90 - 45 = 45 )
T= 2*2*sin45 = 2.82 Nm
Torque also decreases
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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24) A 0.042-kg pet lab mouse sits on a 0.35 kg air-track cart. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of u1=0.88m/s. What is the speed v2 of the mouse and the 0.25-kg cart? |
The mass of the mouse, m₁=0.042 kg
The mass of the 1st cart, m₂=0.35 kg
The mass of the second cart, m₃=0.25 kg
The speed of the 1st car after the jump, u₁=0.88 m/s
From the law of conservation of momentum, the momentum of a system should always remain the same.
Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.
Thus after the mouse jumps, the total momentum of the system should be equal to zero.
Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.
Thus,
[tex]m_2u_1=(m_1+m_3)v_2[/tex]On substituting the known values,
[tex]\begin{gathered} 0.35\times0.88=(0.042+0.25)v_2 \\ \Rightarrow v_2=\frac{0.35\times0.88}{(0.042+0.25)} \\ =1.05\text{ m/s} \end{gathered}[/tex]Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s
a baseball player exerts a force of 100n on a ball for a distance of 0.5m as he throws it. if the ball has a mass of 0.15kg, what is its velocity as it leaves his hand?
now assume that the crate is sliding along the floor with constant velocity. what is the magnitude fp of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?
The magnitude[tex]F_{P}[/tex] of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity is 437.5N.
How friction force can be calculated?The Normal Force (in a horizontal plane, it is comparable to the mass by gravity) and the Kinetic Coefficient of Friction must be multiplied in order to obtain the Friction Force, which must be used in order to solve this problem.
Given that the sentence does not specify the value of the coefficient of friction, I will ascribe a value of 0.5 between the crate and the ground. If a different value has been specified for this coefficient, the below equation will simply need to be changed to reflect it.
[tex]F_{P}[/tex] = µK N
µK = Friction coefficient
Normal Force is N.
Replacing,
[tex]F_{P}[/tex] = 0.5 × 875
[tex]F_{P}[/tex] = 437.5N.
Consequently, the crate is subject to a friction force of 437.5N.
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Complete question is "Suppose you have to move a heavy crate of weight 875 {\rm N} by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 {\rm N}, but friction prevents the crate from sliding. Now assume that the crate is sliding along the floor with constant velocity. What is the magnitude F_p of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?"
An atmospheric layer of a specific gas provides shielding from harmful ultraviolet light from the sun, allowing life to thrive on earth. What gas makes up this layer?.
Since stratospheric ozone shields life on Earth from harmful ultraviolet (UV) radiation, it is frequently referred to as "good" ozone.
How does the atmosphere safeguard life on Earth?It not only has the oxygen we require to survive, but it also shields us from dangerous UV sun radiation. It generates the pressure necessary for liquid water to exist on the surface of our planet. Additionally, it heats our planet and maintains conditions that allow life to exist on Earth.
The ozone layer, located higher up in the stratosphere, absorbs solar ultraviolet radiation and modulates the amount of heat that is returned to space from the Sun. Overexposure to UV radiation may cause sunburn, skin cancer, and eye damage. The ozone layer protects humans from these negative consequences.
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a circuit consists of a 10.0-volt battery, its internal resistor of 2.00 ohms, a resistor of 4.00 ohms, and an ammeter. the battery and the resistors are connected in series in a closed loop. the ammeter is parallel to the battery and its internal resistor. part a find the reading of the ammeter.
The ammeter will read the current as 1.67 A.
An ammeter is a device that measures the current through the conductor. The reading of the ammeter depends on the resistance and voltage. Resistance can be defined as the ratio of the voltage applied to the current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
From the question above, we know that
V = 10 V
r = 2 Ω
R = 4 Ω
Find the current by substituting the given parameters
V = I . ( R + r )
10 = I ( 4 + 2 )
10 = 6 I
I = 10 / 6
I = 1.67 A
Hence, the ammeter will read the following current.
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Find the total translational kinetic energy of0.5 L of oxygen gas held at a temperature of3◦C and a pressure of 1.5 atm.Answer in units of J.
Given
Volume of the oxygen gas is
[tex]V=0.5L=0.0005m^3[/tex]The temperature is
[tex]T=3^oC[/tex]Pressure is
[tex]\begin{gathered} P=1.5atm \\ \Rightarrow P=1.5\times101325=151,987.5Pa \end{gathered}[/tex]To find
The translational kinetic energy
Explanation
The translational kinetic energy is given by
[tex]K=\frac{3}{2}nRT[/tex]For ideal gas,
[tex]PV=nRT[/tex]Thus,
[tex]\begin{gathered} K=\frac{3}{2}PV \\ \Rightarrow K=\frac{3}{2}\times151987.5\times0.0005 \\ \Rightarrow K=113.99J \end{gathered}[/tex]Conclusion
The translational kinetic energy is 113.99J
