PLEASE ASAPPPPP I NEED ITTTT

Answer: 3.33

Step-by-step explanation:

6x-2= 20

    +2= +2

Add two to both sides

6x=22

÷ 6= ÷6

Divide both sides by 6

x= 3.33 OR x= 22/6 simplified = 11/3

What you do to one side you do to the other to make the equation balanced.

Answer:

Step-by-step explanation:

6x - 2 = 20

Add 2 to both sides

6x - 2 + 2 = 20 + 2

          6x = 22

Divide both sides by 6

         [tex]\dfrac{6x}{6}=\dfrac{22}{6}\\\\\\x =\dfrac{11}{3}\\\\\\x = 3\dfrac{2}{3}[/tex]

Answer:

prop they're constant inchangeb

Step-by-step explanation:

W=130

Step-by-step explanation:

the question giving says_W=130and if minus is crossing to the other side it becomes+

12% is the percent decrease

95,920 is 88% of 109,000.
x/100 = 95,920/109,000

95,920 x 100 = 9,592,000

9,592,000 / 109,000 = 88

100 - 88 = 12

Since it is 88% of it, it decreased by 12%

Answer:

12%decrese

Step-by-step explanation:

percentage decrease=13080/109000 ×100

=12% decrease

Mark me brainliest.

Answer:

324 people

Step-by-step explanation:

We can take 54% of 600 to find the answer to our problem.

54% becomes 0.54

600 * 0.54 = 324 people

The solution is Option B.

The two right scalene triangles can be formed from the parallelogram B

A scalene triangle is a type of triangle with three different length sides and three interior angles that add up to 180 degrees. Scalene triangles have no equal of parallel sides , hence there is no line of symmetry. The interior angles of a scalene triangle can be acute , right or obtuse angles.

Given data ,

Let the parallelogram be represented as ABCD

Now , the figure ABCD represents a rectangle

So , the measures of angles ∠ABC = measure of angle ∠DCB = 90°

Let the diagonal of the rectangle be AC

The base of the rectangle = BC

The height of the rectangle = AB

So , the diagonal cuts the rectangle into two triangles each having different lengths and angles

And , the two triangles are ΔABC and ΔADC

Now , the triangles ΔABC and ΔADC are right scalene triangles

Hence , the triangles are scalene triangles

To learn more about scalene triangles click :

https://brainly.com/question/10651823

#SPJ2

Let her daily allowance be RMy.

0.25y x 14 = 28

0.25y=2

y=8

Therefore, her daily allowance is RM8.

Answer:

[tex]x=8[/tex]

Step-by-step explanation: [tex]25[/tex]%[tex]\times14\times[/tex][tex]x=28[/tex]

Solve the equation

[tex]0.25\times14x=28[/tex]

Multiply the monomials

[tex]3.5x=28[/tex]

Divide both sides of the equation by the coefficient of variable

[tex]x=\frac{28}{3.5}[/tex]

Multiply both the numerator and denominator with the same integer

[tex]x=\frac{280}{35}[/tex]

Cross out the common factor

[tex]x=8[/tex]

I hope this helps you

:)

Answer:

There are 10,560 yards in 3 mile or miles in 3 yard. Both yards and miles are units of length in the US customary and imperial systems of measurement.

Answer:The equation of a line is written as ​y=mx​+​b​, where the constant ​m​ is the slope of the line, and the ​b​ is the ​y​-intercept.

Step-by-step explanation:

Answer:

8 hours

Step-by-step explanation:

First, you must subtract $32 from $125. You end up with $93.

Usually, you would do 93 divided by 12, but 93 is not a multiple of 12.

96, which is 12 times 8, is the closest to 93, so 8 hours is the correct answer.

Answer:

Kayla

Step-by-step explanation:

To find who spend the least amount of time on homework per hour, divide the number of hours by the amount of homework

Kayla: 3.2 ÷ 4 = 0.8

Karen: 5 ÷ 6 = 0.833

Since Kayla's number is lower, that means she spent fewer hours per homework than Karen. This means Karen spent the least amount of time in hours per homework.

We are given with a limit and we need to find it's value so let's start !!!!

[tex]{\quad \qquad \blacktriangleright \blacktriangleright \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}}[/tex]

But , before starting , let's recall an identity which is the main key to answer this question

Consider The limit ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}}[/tex]

Now as directly putting the limit will lead to indeterminate form 0/0. So , Rationalizing the numerator i.e multiplying both numerator and denominator by the conjugate of numerator

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}\times \dfrac{\sqrt{x}+\sqrt{3\sqrt{x}-2}}{\sqrt{x}+\sqrt{3\sqrt{x}-2}}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-\sqrt{3\sqrt{x}-2})(\sqrt{x}+\sqrt{3\sqrt{x}-2})}{(x^{2}-4^{2})(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Using the above algebraic identity ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x})^{2}-(\sqrt{3\sqrt{x}-2})^{2}}{(x-4)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-(3\sqrt{x}-2)}{(x-4)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}+2}{\{(\sqrt{x})^{2}-2^{2}\}(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}-2}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Now , here we need to eliminate (√x-2) from the denominator somehow , or the limit will again be indeterminate ,so if you think carefully as I thought after seeing the question i.e what if we add 4 and subtract 4 in numerator ? So let's try !

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}-2+4-4}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(x-4)+2+4-3\sqrt{x}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Now , using the same above identity ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)+6-3\sqrt{x}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)+3(2-\sqrt{x})}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Now , take minus sign common in numerator from 2nd term , so that we can take (√x-2) common from both terms

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)-3(\sqrt{x}-2)}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Now , take (√x-2) common in numerator ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)\{(\sqrt{x}+2)-3\}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Cancelling the radical that makes our limit again and again indeterminate ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\cancel{(\sqrt{x}-2)}\{(\sqrt{x}+2)-3\}}{\cancel{(\sqrt{x}-2)}(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}+2-3)}{(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-1)}{(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}[/tex]

Now , putting the limit ;

[tex]{:\implies \quad \sf \dfrac{\sqrt{4}-1}{(\sqrt{4}+2)(4+4)(\sqrt{4}+\sqrt{3\sqrt{4}-2})}}[/tex]

[tex]{:\implies \quad \sf \dfrac{2-1}{(2+2)(4+4)(2+\sqrt{3\times 2-2})}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{(4)(8)(2+\sqrt{6-2})}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{(4)(8)(2+\sqrt{4})}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{(4)(8)(2+2)}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{(4)(8)(4)}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{128}}[/tex]

[tex]{:\implies \quad \bf \therefore \underline{\underline{\displaystyle \bf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}=\dfrac{1}{128}}}}[/tex]

We can transform the limand into a proper rational expression by substitution.

Let y = √x. Then as x approaches 4, y will approach √4 = 2. So

[tex]\displaystyle \lim_{x\to4}\frac{\sqrt x - \sqrt{3 \sqrt x - 2}}{x^2 - 16} = \lim_{y\to2} \frac{y - \sqrt{3y-2}}{y^4 - 16}[/tex]

Now let z = √(3y - 2). Then as y approaches 2, z will approach √(3•2 - 2) = 2 as well. It follows that y = (z² + 2)/3, so that

[tex]\displaystyle \lim_{y\to2} \frac{y - \sqrt{3y-2}}{y^4-16} = \lim_{z\to2} \frac{\frac{z^2+2}3 - z}{\frac{(z^2+2)^4}{81}-16} \\\\ = \lim_{z\to2} \frac{27(z^2+2)-81z}{(z^2+2)^4 - 1296} \\\\ = 27 \lim_{z\to2} \frac{z^2 - 3z + 2}{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280}[/tex]

Plugging z = 2 into the denominator returns a value of 0, which means z - 2 divides z⁸ + 8z⁶ + 24z⁴ + 32z² - 1280 exactly. Polynomial division shows that

[tex]\dfrac{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280}{z-2} \\\\ = z^7+2z^6+12z^5+24z^4+72z^3+144z^2+320z+640[/tex]

and it's easy to see that the numerator is also divisible by z - 2, since

[tex]z^2 - 3z + 2 = (z - 1) (z - 2)[/tex]

So, we can eliminate the factor of z - 2 and we're left with

[tex]\displaystyle 27 \lim_{z\to2} \frac{z^2 - 3z + 2}{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280} = 27 \lim_{z\to2}\frac{z-1}{z^7+\cdots+640}[/tex]

The remaining limand is continuous at z = 2, so we can evaluate the limit by direct substitution:

[tex]\displaystyle 27 \lim_{z\to2}\frac{z-1}{z^7+\cdots+640} = \frac{27}{3456} = \boxed{\frac1{128}}[/tex]

Answer:

x = e^12/100

Step-by-step explanation:

Solve for x over the real numbers:

10 ln(100 x) - 3 = 117

Add 3 to both sides:

10 ln(100 x) = 120

Divide both sides by 10:

ln(100 x) = 12

Cancel logarithms by taking exp of both sides:

100 x = e^12

Divide both sides by 100:

Answer:  x = e^12/100

Answer:

-8

Step-by-step explanation:

-32^3/5

Fifth root of 32 is 2.

Thus, 2^3 is 8, but -8 instead due to making 32 positive

Hope this helps!

Answer:  Annie sold 50 calendars

Step-by-step explanation:

45 * $1.20    = $54

34 * $1.50    = $51

$54 + $ 51   = $105

$150 - $105 = $45

$45 / $0.9   = 50       Therefore ,Annie sold 50 calendars

y= 7- ( the length of candle decreased for 30 min)x

gallon = pint *0.125

gallon = pint / 8
0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+

0.125+0.125+0.125+0.125+0.125 = 2

16 would be the answer I believe, maybe I'm wrong, double check.

Answer:

5 1/3 pints

Step-by-step explanation:

1 pint is 1/8gal and u need to find how many pints in 2/3 gal so it'll be 2/3 ÷ 1/8 which is 5 1/3

Answer:

C. 22/5

Step-by-step explanation:

4x5=20

20+2=22

Answer:

C. 22/5

When making an improper fraction you must first multiply the denominator with the whole number in this case that would be 4 and 5

4*5=20

Then just add the numerator

20+2=22

And bring it back over the denominator

22/5

There you go your improper fraction.

Step-by-step explanation:

Answer: 30° and 110°

55° and 85°

70° and 70°

The sum of angles in a triangle is 180°. Therefore, since an angle has been given as 40°, the remaining angles will be:

= 180° - 40°

= 140°

Therefore,

30° + 110° = 140°

55° + 85° = 140°

70° + 70° = 140°

Answer:

(-2,-6) on point

Step-by-step explanation:

Mark me brainliest!!

Answer:

(2,-2)

Explanation:

vertex after translation:

original position + translation unit

( 2 , -6 ) + ( 0 , 4 )

( 2 , -2 )

note: vertically means only up and down, there is will change in y not x.

For the lines to be parallel the two angles need to be equal to each other:

128-x = x

Add 1x to both sides

128 = 2x

Divide both sides by 2:

X = 128/2

X = 64

Answer: x = 64

Answer:

the perimeter is 58 inches

Step-by-step explanation:

15+8+9+14+12= 58

Answer:

150 people

Step-by-step explanation:

20/50 = 40%
So 40% are wearing hats and 60% aren't

0.6=60%

250x0.6= 150

Answer:

60 degrees

Step-by-step explanation:

It measures 60 degrees

Tip: the wider the angle, the bigger the degree.

Hope this helps!

Answer:

34

Step-by-step explanation:

Answer:

A, C D

Step-by-step explanation:

sorry if wrong

Answer:

51

Step-by-step explanation:

3n means 3 × n

substitute n = 17 into the expression

3n = 3 × 17 = 51