Answer:
301.08 cm^3
Explanation:
v=m×d
156g×1.93g/cm^3
Answer:
The answer is 301.08
Explanation
I hope this helps! I know this is the right answer I took the test! Can I get brainliest?
If 1.75 g of titanium metal reacts with 1.25 g of oxygen gas to form titanium (IV) oxide, what is the theoretical yield of the product?
Answer:
Theoretical yield is 2.92g TiO₂
Explanation:
The reaction of Ti with O₂ to produce TiO₂ is:
Ti + O₂ → TiO₂
First, we need to find moles of titanium and oxygen. As the reaction is 1:1, we can determine directly the limiting reactant, the theoretical moles of TiO₂ and thus, theoretical yield:
Moles Ti (molar mass: 47.867g/mol):
1.75g * (1mol / 47.867g) = 0.03656 moles Ti
Moles O₂ (molar mass: 32g/mol):
1.25g * (1mol / 32g) = 0.0390 moles O₂
That means only 0.03656 moles of Ti will react withe 0.03656 moles of O₂ producing 0.03656 moles of TiO₂
As molar mass of TiO₂ is 79.866g/mol, the theoretical yield of the product is:
0.03656 moles TiO₂ * (79.866g / mol) = 2.92g TiO₂
Theoretical yield is 2.92g TiO₂The theoretical yield of the reaction of titanium and oxygen has been 2.92 grams.
The balanced reaction for the reaction of Titanium with oxygen can be given as:
[tex]\rm Ti\;+\;O_2\;\rightarrow\;TiO_2[/tex]
According to the balanced equation, 1 mole of Ti gives 1 mole of Titanium oxide.
The moles of Ti can be given as:
Moles = [tex]\rm \dfrac{mass}{molecular\;mass}[/tex]
The molecular mass of Ti has been 47.867 grams.
Moles of Ti has been:
Moles of Ti = [tex]\rm \dfrac{1.75}{47.867}[/tex]
Moles of Ti = 0.036 mol.
Moles of Oxygen has been:
Moles of oxygen = [tex]\rm \dfrac{1.25}{32}[/tex]
Moles of oxygen = 0.0390 mol.
The moles of Ti has been less than the required moles of Ti for the complete utilization of oxygen, thus titanium has been the limiting reactant.
1 mole of Titanium = 1 mole of titanium oxide
0.036 mol of Titanium = 0.036 mol of titanium oxide
The mass of 0.036 mol titanium oxide has been:
Mass = moles × molecular weight
Mass of titanium oxide = 0.036 mol × 79.866 g/mol
Mass of titanium oxide = 2.92 grams.
The theoretical yield of the reaction of titanium and oxygen has been 2.92 grams.
For more information about the theoretical yield, refer to the link:
https://brainly.com/question/7786567
what happens during the dissolution of wax in kerosene
Answer:
The wax will totally dissolve in the kerosene.
Explanation:
Hello.
In this case, since wax is more specifically known as paraffin wax which is a heavy-highly nonpolar organic compound which is largely insoluble in water due to its nonpolar nature, when dissolved in kerosene which is a highly nonpolar organic solvent we can infer that the dissolution process will rapidly undergo even at normal conditions due to the intermolecular forces joining them.
Therefore, when wax is dissolved in kerosene a complete dissolution is evidenced due to their common nature.
Best regards.
Need Help ASAP
Thanks you
Beryllium-9
Neutrons:
Protons:
Electrons:
Answer:
Neutrons - 5
Protons - 4
Electrons - 4
Explanation:
Beryllium (Be) is the 4th element on the Periodic Table.
It has 4 protons and 4 electrons (neutral charge)
Atomic Mass = # of Protons + # of Neutrons
9 = 4 + x
x = 5 Neutrons
(1.7 x 10-5 m) x (3.72 x 10-4 m) *
Answer:
The answer will be 1992/5 or 398.4
please help i’ll give brainliest
28 mL
it counts by 2 from 20
Answer:
28 ml
Explanation:
28 ml
my aunt told me
How many electrons would Magnesium with a -1 charge have?
The lungs are connected to the trachea by _____. bronchi windpipes alveoli capillaries
Answer:
Bronchi
Explanation:
The trachea divides into air tubes called the bronchi, which connects it to the lungs.
Answer:
bronchi
Explanation:
A 90-m3 basement in a residence is found to be contaminated with radon coming from the ground through the floor drains. The concentration of radon in the room is 1.5 Bq · L−1 (becquerels per liter) under steadystate conditions. The room behaves as a CMFR, and the decay of radon is a first-order reaction with a decay rate constant of 2.09 × 10−6 s−1. If the source of radon is closed off and the room is vented with radon-free air at a rate of 0.14 m3 · s−1, how long will it take to lower the radon concentration to an acceptable level of 0.15 Bq · L−1?
Answer: it will take 24.6467 min to lower the radon concentration to an acceptable level of 0.15Bq.L^-1
Explanation:
To calculate the required time, we make use of the formula
Cout = Coexp [ - ( 1/θ + k ) t ] .........lets call this equation 1
where Co is the concentration of radon( 1.5Bq.L^-1 ), Cout id the allowable radon concentration( 0.15Bq.L^-1), k is the radon decay rate constant( 2.09 * 10^-6 s^-1 ), θ is the theoretical detention time and t is the time required to lower the radon concentration.
first we find θ which is the theoretical detention time using the expression
θ = _V / Q
_V is the volume of basement (90 m^3) and Q is the rate of free air (0.14 m^3.s^-1)
so we substitute
θ = 90 / 0.14
θ = 642.857 s
Now we substitute all our values into equation 1
Cout = Coexp [ - ( 1/θ + k ) t ]
0.15 = 1.5exp [ - ( 1/642.857 + (2.09 * 10^-6) ) t ]
divide both LHS and RHS by 1.5
0.15/1.5 = exp [ - ( 0.001555 + 0.00000209)t ]
0.1 = exp[ - ( 0.001557)t ]
next we take the natural log of both sides
In 0.1 = In [ exp( -0.001557t )]
-2.3025 = - 0.001557t
t = 2.3025 / 0.001557
t = 1478.8053 sec
so we convert to minutes
t = 1478.8053 / 60
t = 24.6467 min
therefore it will take 24.6467 min to lower the radon concentration to an acceptable level of 0.15Bq.L^-1
Both elements and compounds are considered to be
Answer:
Pure Substances.
Explanation:
Elements and compounds are both examples of pure substances. A substance that cannot be broken down into chemically simpler components is an element.
Prions are proteins with the ability to generate more prions by causing other proteins to misfold into a similar shape. Since prions are proteins, they have a genetic sequence associated with them and their ability to create more prions allows them to reproduce. Why aren’t prions considered alive?
While 1 gram of fat provides 9 calories, 1 gram of glucose provides 4 calories. Why is that?
Answer:
fat always has more calories than glucose does
Explanation:
hope hope this helps!
Fat contains more chemical bonds than glucose.
The chemical energy stored in food substances is released when the chemical bonds in those food substances are broken down during digestion.
The more the number of chemical bonds in a food substance, the greater the energy released when 1g of that substance is is broken down.
We must recall that glucose contains only six carbon atoms while fat is composed of triglycerides having several carbon atoms. The breakdown of these many chemical bonds surely releases more energy.
Hence, 1 gram of fat provides 9 calories while 1 gram of glucose provides 4 calories.
https://brainly.com/question/857310
What is the wavelength of radiation that has a frequency of 5.9×1011 s−1 ?
Answer:
frequency = velocity of light /wavelength
wavelength = velocity / frequency
=3 x10^8 / 5.9 x 10^11
=0.508 x 10^-3.
.....m..........m.....mm...
Answer:
Nuclear Regulatory Commission
A student wants to burn a 1.25 mL sample of ethanol (C2H5OH, d = 0.789 g/mL) in a jar containing dry air. Assuming the air in the jar is at standard atmospheric pressure and room temperature (22 °C), what volume will the jar need to be in order to hold enough oxygen for complete combustion? Hint: Refer to the composition of dry air in the previous question. (a) Write a balanced chemical reaction for the combustion of ethanol. (b) Calculate the moles of oxygen needed to completely combust the ethanol. (c) Calculate the partial pressure of oxygen in the jar. (d) Calculate the volume of oxygen (in L) needed in t
Answer:
The volume of the jar needed in order to hold enough oxygen for complete combustion is 24.2 L
(a) C₂H₅OH + 2O₂ -------> 2CO₂ + 3H₂O
(b) The moles of oxygen needed to completely combust the ethanol is 0.0429 moles
(c) The Partial pressure of oxygen is 4346.84 Pa
(d) the volume of oxygen (in L) needed in the jar is 1.038 L
Explanation:
Given;
volume of ethanol, V = 1.25 mL
density of ethanol, ρ = 0.789 g/mL
mass of ethanol, m = ρV = (1.25 mL) x (0.789 g/mL) = 0.986g
The volume of the dry air is calculated as;
[tex]P_d = \rho _d R_d T\\\\P_d = (\frac{M_d}{V_d} )R_d T\\\\V_d = (\frac{M_d}{P_d} )R_d T\\\\V_d = (\frac{0.02897 \ (kg)}{101325 \ (Pa)} )*287 \ (J/K.kg)* 295\ (K)\\\\V_d = 0.0242 \ m^3\\\\V_d = 24.2 \ L[/tex]
(a) a balanced chemical reaction for the combustion of ethanol
C₂H₅OH + 2O₂ -------> 2CO₂ + 3H₂O
(b) The moles of oxygen needed to completely combust the ethanol.
[tex]=0.986 g \ C_2H_5OH *(\frac{1 \ mol \ C_2H_5OH}{46g \ C_2H_5OH} )*(\frac{2 \ Mol \ O_2}{1 \ mol \ C_2H_5OH} )\\\\ = 0.0429 \ mols.[/tex]
(c) the partial pressure of oxygen in the jar
Total pressure of air in the jar, Pt = 101,325 Pa
Partial pressure of oxygen = nPt
= 0.0429 x 101,325 Pa = 4346.84 Pa
(d) the volume of oxygen (in L) needed in the jar
Total volume of air in the jar = 24.2 L
The fraction of this volume by oxygen = 0.0429 mols x 24.2 L = 1.038 L
Dry air is composed of many molecules and compounds. The major quantity of molecules present in the dry air is Nitrogen, followed by oxygen, argon, carbon dioxide and many more. Dry air also has some amount of water vapor in it.
The volume of the jar needed to hold enough oxygen for complete combustion can be calculated by:
Volume of ethanol= 1.25 mlDensity of ethanol = 0.789 g/mlMass of ethanol can be calculated by:= density × volume
= 1.25 ml x 0.789 g/ml
= 0.986 g
The volume of the dry air is calculated by the following:
[tex]\text{P}_d &= \rho_d \text{R}_d \text{T}[/tex]
[tex]\text{P}_d &= \dfrac{{\text M}_d}{\text{V}_d}} \text{R}_d \text{T}[/tex]
[tex]\text{V}_d &= \dfrac{{\text M}_d}{\text{V}_d}} \text{R}_d \text{T}[/tex]
[tex]\text{V}_d &= 0.0242\; m^{3}[/tex]
[tex]\text{V}_d &= 24.2\;\text L[/tex]
Hence, the volume of the dry air is 24.2 L.
a. Balanced chemical equation for the combustion of ethanol can be written as:
C₂H₅OH + 2 O₂ -------> 2 CO₂ + 3H₂O
One molecule of ethanol reacts with two molecules of oxygen to produce two molecules of carbon dioxide and three water molecules.
b. To calculate the moles of oxygen needed for complete combustion of ethanol can be calculated as:
[tex]\begin{aligned}&=0.986g\;\text{C}_2\text{H}_5\text{OH}\times\left(\frac{1\;\text{mol}\;\text{C}_2\text{H}_5\text{OH}}{46\;g\;\text{C}_2\text{H}_5\text{OH}} \right )\times\left(\frac{2\;\text{Mol\;O}_2}{1\;\text{mol}\text{C}_2\text{H}_5\text{OH}} \right )\\&=0.0429\text{mols} \end{aligned}[/tex]
Hence, 0.0429 moles of oxygen will be needed to completely burn ethanol.
c. The partial pressure of the oxygen in the jar can be calculated by the following formula:
Given,
Total pressure of air in the jar (Pt) = 101,325 PaThe partial pressure of oxygen:= nPt
= 0.0429 x 101,325 Pa
= 4346.84 Pa
Hence, the partial pressure of oxygen will be 4346.84 Pa.
d. The volume of oxygen (in L) needed in the jar can be calculated using the volume of the jar.
The total volume of air in the jar = 24.2 LThe fraction of this volume by oxygen:= 0.0429 moles x 24.2 L
= 1.038 L
Therefore, the volume of the jar needed to hold enough oxygen for complete combustion is 24.2 L.
To learn more about combustion reaction follow the given link:
https://brainly.com/question/25092860
Nutrients are added to soil with the help of?
A: decomposers
B: herbivores
C: predators
D: prey
Answer:
Decomposers
Explanation:
Decomposers, well as in the name, ingest decomposing things and or droppings, and turn it into nutrients.
What is the pH in a 1.5 M solution of hydrofluoric acid?
[tex]HF \rightleftharpoons H^{+} + F^{-}\\[/tex]
We have 1.5 M HF in the beginning and 0 M [tex]H^{+}[/tex] and [tex]F^{-}[/tex]
We know that there's gonna be a decrease of x M on [tex]HF[/tex] and an increase of x M on [tex]H^{+}[/tex] and [tex]F^{-}[/tex].
We also find in chemistry tables that [tex]K_{a}(HF) = 6.8 \cdot 10^{-4}[/tex]
[tex]K_a = \frac{[H^+] \cdot [F^-]}{[HF]}\\6.8 \cdot 10^{-4} = \frac{x \cdot x}{1.5 - x} \\6.8 \cdot 10^{-4} = \frac{x^2}{1.5}\\6.8 \cdot 10^{-4} \cdot 1.5 = x^2\\x^2 = 1.02 \cdot 10^{-3}\\x = 0.0319\\pH = -\log{0.0319}\\pH = 1.5[/tex]
Lithium-4 and Lithium-5 can be defined as:
A: isotopes
B: different elements
C: ions
D: average atomic masses
Answer:
A: isotopes
Explanation:
Hello.
In this case, since isotopes are defined as atoms of the same element with the same atomic number (number of protons and electrons) but different mass number (atomic mass) we can represent them via the symbol of the element followed by a dash indicating the atomic mass of the occurring isotope, for instance, for carbon, we may find C-12, C-13 and even C-14 which is useful in dating techniques.
Therefore, Lithium-4 or Li-4 and Lithium-5 or Li-5 can be defined as isotopes.
Best regards.
Atoms are generally held together by attraction between neutrons and protons (the strong interaction) and stabilized by electrons. As atoms increase in mass, it becomes easier for them to have too many or too few neutrons, leading to radioactive isotopes of certain elements. What factors might allow this to happen?
Answer:
im pretty sure the answer is: alpha decay, beta decay, and gamma decay.
Explanation:
The arrows in the chart below represent phase transitions.
Solid
Liquid
16
Gas
Which arrows represent the phase transitions in which heat energy is gained?
1, 2, and 3
2,3, and 5
3, 4, and 5
4,5, and 6
Answer:
A: 1, 2, and 3
Explanation:
mY ANSWER GOT DELETED ITS WHAT I SAID BEFORE ITS ON EDGE2020
Answer:
A. 1, 2, and 3
Explanation:
Correct on Edge 2022!!!
Good luck everyone, you got this! Have a great day!
What is the pH of 0.10 M HNO2 solution? (Ka= 4.0 x 10-4)|
Answer:
The answer is 2.2Explanation:
Since the above substance is a weak acid it's pH can be found by using the formula
[tex]pH = \frac{1}{2} ( - log(Ka ) - log(c) )[/tex]
where
Ka is the acid dissociation constant
c is the concentration of the acid
From the question
Ka = 4.0 × 10-⁴
c = 0.1 M
So we have
[tex]pH = \frac{1}{2} ( - log(4.0 \times {10}^{ - 4} ) - log(0.1) ) \\ = \frac{1}{2} (3.4 + 1) \\ = \frac{1}{2}(4.4) \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
2.2Hope this helps you
A 2 mL sample of concentration 0.0043 M is measured out with a volumetric pipet and diluted to 100.0 mL. What is the concentration (in M) for this solution? Give your numerical answer to three significant figures and leave off the unit label.
Answer:
Explanation:
The dilution formula is
s₁ v₁ = s₂ v₂
s₁ = .0043
v₁= 2 mL
v₂ = 100 mL
s₂ = ?
putting the values
.0043 x 2 = s₂ x 100
s₂ = .000086 = 86.0 x 10⁻⁶
Which Bohr model shows the correct # of electrons for a neutral sodium atom
that has 11 protons and 12 neutrons? *
Answer:
3 option........
Explanation:
i think
Acetone is produced from 2-propanol in the presence of dioxygen and the photocatalyst TiO2 when the reactor is irradiated with ultraviolet light. For a reaction carried out at room temperature in 1.0 mol of liquid 2-propanol containing 0.125 g of catalyst the following product concentrations were measured as a function of irradiation time. Calculate the first order rate constant.
Reaction Time min 20 40 60 80 100 120 140 160 180
Acetone Produced 1.9 3.9 5.0 6.2 8.2 10 11.5 13.2 14.0
Answer:
20 30 40 50 is the answer to that one day
Determine whether each statement is a description of a physical property or a chemical property. Please check the box that applies.
Copper conducts heat well.
physical
chemical
Alcohol has a sweet odor.
physical
chemical
Answer:
Copper conducts heat well- physical
Alcohol has a sweet door- physical
Explanation:
Answer:
a, a
Explanation:
The air pressure inside a balloon is 0.78 atm. What is this
pressure in mmHg?
mmHg
Your answer should be rounded to 2 significant figures. Do not include units in
Answer:
The pressure in mmHg is 59.
Explanation:
Given data:
Pressure of air inside balloon = 0.78 atm
Pressure in mmHg = ?
Solution:
mmHg:
mmHg is referred as manometric unit of pressure. It is define as the pressure exerted by mercury column at height of one millimeter.
Symbol:
"mmHg"
Atmosphere (atm)
atm is unit of pressure. It is used as a standard unit. It is equal to the 101325 Pa.
1 atm = 760 mmHg
Inorder to convert the atm into mmHg we will multiply the given atm value with 760.
0.78 atm × 760 mmHg / 1 atm = 592.8 mmHg
59 mmHg or 59
Torque can be calculated by multiplying the force (N) applied at 90∘ to the lever arm at a distance (m) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅m. If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?
Answer:
F=15 N
Moment arm=2 m
torque=Fl=15x2=30 Nm
Explanation:
Phosphoric acid (H3PO4) is an important industrial chemical used in fertilizers, detergents, and in the food industry. It is produced by two different methods. In the electric furnace method, elemental phosphorus (P4) is burned in air to form P4O10, which is then reacted with water to give H3PO4. In the wet process, the mineral phosphate rock [Ca5(PO4)3F] is reacted with sulfuric acid to give H3PO4 (and HF and CaSO4). (a) Write the balanced equations for the electric furnace method. Include the phase abbreviations.
Answer:
P₄(s) + 5 O₂(g) ⇒ P₄O₁₀(s)
P₄O₁₀(s) + 6 H₂O(l) ⇒ 4 H₃PO₄(aq)
P₄(s) + 5 O₂(g) + 6 H₂O(l) ⇒ 4 H₃PO₄(aq)
Explanation:
The electric furnace method for the synthesis of phosphoric acid has 2 steps. In the first step, elemental phosphorus (P₄) is burned in air to form P₄O₁₀. The balanced reaction is:
P₄(s) + 5 O₂(g) ⇒ P₄O₁₀(s)
In the second step, P₄O₁₀ reacts with water to give phosphoric acid.
P₄O₁₀(s) + 6 H₂O(l) ⇒ 4 H₃PO₄(aq)
If we add both steps, we get the global reaction.
P₄(s) + 5 O₂(g) + 6 H₂O(l) ⇒ 4 H₃PO₄(aq)
Why are nutrient molecules important?
A nutrient is a substance used by an organism to survive, grow, and reproduce. The requirement for dietary nutrient intake applies to animals, plants, fungi, and protists. Nutrients can be incorporated into cells for metabolic purposes or excreted by cells to create non-cellular structures, such as hair, scales, feathers, or exoskeletons. Some nutrients can be metabolically converted to smaller molecules in the process of releasing energy, such as for carbohydrates, lipids, proteins, and fermentation products (ethanol or vinegar), leading to end-products of water and carbon dioxide. All organisms require water. Essential nutrients for animals are the energy sources, some of the amino acids that are combined to create proteins, a subset of fatty acids, vitamins and certain minerals. Plants require more diverse minerals absorbed through roots, plus carbon dioxide and oxygen absorbed through leaves. Fungi live on dead or living organic matter and meet nutrient needs from their host.
determine the molarity of 3.72 moles of NaBr in 575 ml of solution
Answer:
6.47 M (3 s.f.)
Explanation:
Please see the attached picture for the full solution.
